Selina Concise Mathematics Class 9 ICSE Solutions Statistics

Selina Concise Mathematics Class 9 ICSE Solutions Statistics

ICSE SolutionsSelina ICSE Solutions

APlusTopper.com provides step by step solutions for Selina Concise Mathematics Class 9 ICSE Solutions Chapter 18 Statistics. You can download the Selina Concise Mathematics ICSE Solutions for Class 9 with Free PDF download option. Selina Publishers Concise Mathematics for Class 9 ICSE Solutions all questions are solved and explained by expert mathematic teachers as per ICSE board guidelines.

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Selina ICSE Solutions for Class 9 Maths Chapter 18 Statistics

Exercise 18(A)

Solution 1:
(a) Discrete variable.
(b) Continuous variable.
(c) Discrete variable.
(d) Continuous variable.
(e) Discrete variable.

Solution 2:
Selina Concise Mathematics Class 9 ICSE Solutions Statistics image - 1

Solution 3:
Selina Concise Mathematics Class 9 ICSE Solutions Statistics image - 2
In this frequency distribution, the marks 30 are in the class of interval 30 – 40 and not in 20 – 30. Similarly, marks 40 are in the class of interval 40 – 50 and not in 30 – 40.

Solution 4:
Selina Concise Mathematics Class 9 ICSE Solutions Statistics image - 3

Solution 5:
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Solution 6:
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Solution 7:
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Solution 8:
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Solution 9:
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Solution 10:
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Solution 11:
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Solution 12:
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Solution 13:
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Exercise 18(B)

Solution 1:
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Solution 2:
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Solution 3:
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Solution 4:
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Solution 5(i):
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Solution 5(ii):
Selina Concise Mathematics Class 9 ICSE Solutions Statistics image - 20
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Selina Concise Mathematics Class 9 ICSE Solutions Statistics image - 22

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ICSE Solutions for Class 10 Mathematics – Statistics

ICSE Solutions for Class 10 Mathematics – Statistics

ICSE SolutionsSelina ICSE Solutions

Get ICSE Solutions for Class 10 Mathematics Chapter 19 Statistics for ICSE Board Examinations on APlusTopper.com. We provide step by step Solutions for ICSE Mathematics Class 10 Solutions Pdf. You can download the Class 10 Maths ICSE Textbook Solutions with Free PDF download option.

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Formulae

  1. Mean:
    icse-solutions-class-10-mathematics-33
    icse-solutions-class-10-mathematics-34
  2. Median:
    icse-solutions-class-10-mathematics-35
  3. Quartiles:
    icse-solutions-class-10-mathematics-36

Formulae Based Questions

Question 1. There are 45 students in a class, in which 15 are girls. The average weight of 15 girls is 45 kg and 30 boys is 52 kg. Find the mean weight in kg of the entire class.
icse-solutions-class-10-mathematics-70

Question 2. A school has 4 sections of Chemistry in class X having 40, 35, 45 and 42 students. The mean marks obtained in Chemistry test are 50, 60, 55 and 45 respectively for the 4 sections. Determine the overall average of marks per student.
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Question 3. Find the mean of 4, 7, 12, 8, 11, 9, 13, 15, 2, 7.
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Question 4. Find the mean of first five natural numbers.
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Question 5. In X standard, there are three sections A, B and C with 25, 40 and 35 students respectively. The average marks of section A is 70%, section B is 65% and of section C is 50%. Find the average marks of the entire X standard.
icse-solutions-class-10-mathematics-74

Question 6. The average score of boys in an examination of a school is 71 and of girls is 73. The averages score of school in that examination is 71.8. Find the ratio of the number of boys between number of girls appeared in the examination.
icse-solutions-class-10-mathematics-75

Question 7. There are 50 students in a class in which 40 are boys and rest are girls. The average weight of the class is 44 kgs and the average weight of the girls is 40 kgs. Find the average weight of the boys.
icse-solutions-class-10-mathematics-76

Question 8. From the following numbers find the median:
10, 75, 3, 81, 17, 27, 4, 48, 12, 47, 9, 15.
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Question 9. The median of the following observation 11, 12, 14, 18, (x + 4), 30, 32, 35, 41 arranged in ascending order is 24. Find x.
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Question 10. The median of the following observations arranged in ascending order is 24. Find x:
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Question 11. Find the mean, median and mode of the following distribution:
8,10, 7, 6,10,11, 6,13,10
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Question 12. Find the median of the following values:
37, 31, 42, 43, 46, 25, 39, 45, 32.
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Question 13. Find the mode from the following data:
110,120,130,120,110,140,130,120,140,120.
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Question 14. Find the mode for the following series:
2.5, 2.3, 2.2, 2.2, 2.4, 2.7, 2.7, 2.5, 2.3, 2.2, 2.6, 2.2.
icse-solutions-class-10-mathematics-84

Question 15. Find out the mode from the following data:
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Data Based Questions

Question 1. The contents of 100 match box were checked to determine the number of match sticks they contained.
icse-solutions-class-10-mathematics-35
(i) Calculate correct to one decimal place, the mean number of match sticks per box.
(ii) Determine how many matchsticks would have to be added. To the total contents of the 100 boxes to bring the mean up exactly 39 match sticks.
Solution:
icse-solutions-class-10-mathematics-36

Question 2. Find the mean of the following distribution:
icse-solutions-class-10-mathematics-37
icse-solutions-class-10-mathematics-38

Question 3. The mean of the following distribution is 6. Find the value at P:
icse-solutions-class-10-mathematics-39

Question 4. If the mean of the following distribution is 7.5, find the missing frequency ‘f’:
icse-solutions-class-10-mathematics-40

Question 5. Marks obtained by 40 students in a short assessment is given below; where a and b are two missing data.
icse-solutions-class-10-mathematics-41
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Question 6. Find the mean of the following distribution:
icse-solutions-class-10-mathematics-43
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Question 7. Find the mean of the following distribution:
icse-solutions-class-10-mathematics-45

Question 8. Find the mean of the following frequency distribution:
icse-solutions-class-10-mathematics-46

Question 9. Find the Median of the following data:
(i) 12,17, 3,14, 6, 9,8,15,20
(ii) 2,10,9,9,5,2,3,7,11,15.
icse-solutions-class-10-mathematics-47

Question 10Find the Median of the following distribution:
icse-solutions-class-10-mathematics-48
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Question 11. Find the mode and median of the following frequency distribution:
icse-solutions-class-10-mathematics-50

Question 12. Calculate the median of the following distribution:
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Solution: The given variates (weights of students) are already in ascending order. We construct the cumulative frequency table as under:
icse-solutions-class-10-mathematics-52
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Question 13. Obtain the median for the following frequency distribution:
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Question 14. Calculate the median of the following distribution:
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Question 15. The following table gives the wages of worker in a factory:
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Question 16. The following table shows the weight of 12 students:
icse-solutions-class-10-mathematics-57

Question 17. Find the mean wage of a worker from the following data:
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Question 18. The marks obtained by a set of students in an examination all given below:
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icse-solutions-class-10-mathematics-60

Question 19. Find the mean of the following distribution by step deviation method:
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Question 20. Helping the step deviation method find the arithmetic mean of the distribution:
icse-solutions-class-10-mathematics-62
icse-solutions-class-10-mathematics-63

Question 21. The weights of 50 apples were recorded as given below. Calculate the mean weight, to the nearest gram. by the Step Deviation Method.
icse-solutions-class-10-mathematics-64
Solution:
icse-solutions-class-10-mathematics-65

Question 22. A frequency distribution of the life times of 400 T.V., picture tubes leased in tube company is given below. Find the average life of tube:
icse-solutions-class-10-mathematics-66
Solution: Here, the class-intervals are formed by exclusive method. If we make the series an inclusive one the mid-values remain same. So, there is no need to convert the series.
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Question 23. (i) Using step-deviation method, calculate the mean marks of the following distribution, (ii) State the modal class.
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Question 24. Calculate the mean of the distribution given below using the short cut method.
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Question 25. A study of the yield of 150 tomato plants, resulted in the record:
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Question 26. For the following frequency distribution find:
(i) Lower quartile
(ii) Upper quartile
(iii) Inter quartile range
(iv) Semi-inter quartile range.
icse-solutions-class-10-mathematics-71
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Prove the Following 

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Graphical Depiction

statistics-icse-solutions-class-10-mathematics-1
Draw an ogive for the given distribution taking 2 cm = 10 marks on one axis and 2 cm = 20 students on the other axis. Using the graph, determine:
(i) The median marks
(ii) The number of students who failed if minimum marks required to pass is 40.
(iii) If scoring 85 and more marks is considered as grade one, find the number of students who secured grade one in the examination.
statistics-icse-solutions-class-10-mathematics-2
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Question 2. Draw a histogram from the following frequency distribution and find the mode from the graph:
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Question 3. The marks obtained by 200 students in an examination are given below:
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Using a graph paper, draw an Ogive for the above distribution. Use your Ogive to estimate:
(i) the median; (ii) the lower quartile;
(iii) the number of students who obtained more than 80% marks in the examination and
(iv) the number of students who did not pass, if the pass percentage was 35.
Use the scale as 2 cm = 10 marks on one axis and 2 cm = 20 students on the other axis.
statistics-icse-solutions-class-10-mathematics-6
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Question 4. The following table give the marks scored by students in an examination:
statistics-icse-solutions-class-10-mathematics-9
Solution: (i) 15 – 20 is the modal group.
(ii) The group 35 – 40 has the least frequency.

Questions 5. The monthly income of a group of 320 employees in a company is given below:
statistics-icse-solutions-class-10-mathematics-10
Draw an ogive of the given distribution on a graph sheet taking 2 cm = Rs. 1000 on one axis and 2 cm = 50 employees on the other axis. From the graph determine:
(i) the median wage
(ii) the number of employees whose income is below Rs. 8,500.
(iii) If the salary of a senior employee is above Rs. 11,500, find the number of senior employees in the company.
(iv) the upper quartile.
statistics-icse-solutions-class-10-mathematics-11
statistics-icse-solutions-class-10-mathematics-12

Question 6. Attempt this question on graph paper. Marks obtained by 200 students in examination are given below:
statistics-icse-solutions-class-10-mathematics-13
Draw an ogive for the given distribution taking 2 cm = 10 makrs on one axis and 2 cm = 20 students on the other axis.
From the graph find:
(i) the median
(ii) the upper quartile
(iii) number of student scoring above 65 marks.
(iv) If to students qualify for merit scholarship, find the minimum marks required to qualify.
statistics-icse-solutions-class-10-mathematics-14
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Question 8. Use graph paper for this question.
The table given below shows the monthly wages of some factory workers.
statistics-icse-solutions-class-10-mathematics-22
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Question 9. Following table present educational level (middle stage) of females in Arunachal pradesh according to 1981 census:
statistics-icse-solutions-class-10-mathematics-25
statistics-icse-solutions-class-10-mathematics-26

Question 10. Distribution of height in cm of 100 people is given below:
statistics-icse-solutions-class-10-mathematics-27
statistics-icse-solutions-class-10-mathematics-28

Question 11. The time taken, in seconds, to solve a problem for each of 25 persons is as follows:
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Question 12. Using a graph paper, drawn an Ogive for the following distribution which shows a record of the weight in kilograms of 200 students.
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Question 13. Draw a histogram and frequency polygon to represent the following data (on the same scale) which shows the monthly cost of living index of a city in a period of 2 years:
statistics-icse-solutions-class-10-mathematics-39
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Question 14. Draw the histogram for the following frequency distribution and hence estimate the mode for the distribution.
statistics-icse-solutions-class-10-mathematics-41

Question. 15. The frequency distribution of scores obtained by 230 candidates in a medical entrance test is as ahead:
statistics-icse-solutions-class-10-mathematics-42
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Question 16. Draw a histogram to represent the following data:
statistics-icse-solutions-class-10-mathematics-44
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Question 17. Use graph paper for this question. The following table shows the weights in gm of a sample of 100 potatoes taken from a large consignment:
statistics-icse-solutions-class-10-mathematics-46
statistics-icse-solutions-class-10-mathematics-47
statistics-icse-solutions-class-10-mathematics-48

Question 18. Attempt this question on a graph paper. The table shows the distribution of marks gained by a group of 400 students in an examination:
statistics-icse-solutions-class-10-mathematics-49
statistics-icse-solutions-class-10-mathematics-50
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Question 19. A Mathematics aptitude test of 50 students was recorded as follows:
statistics-icse-solutions-class-10-mathematics-52
statistics-icse-solutions-class-10-mathematics-53

Question 20. The daily wages of 160 workers in a building project are given below:
statistics-icse-solutions-class-10-mathematics-54
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Question 21. The marks obtained by 120 students in a test are given below:
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Question 22. (Use a graph paper for this question.) The daily pocket expenses of 200 students in a school are given below:
statistics-icse-solutions-class-10-mathematics-60
Draw a histogram representing the above distribution and estimate the mode from the graph.
Solution: Histogram on the graph paper.
statistics-icse-solutions-class-10-mathematics-61

Question 23. The marks obtained by 100 students in a Mathematics test are given below:
statistics-icse-solutions-class-10-mathematics-62
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Concept Based Questions

Question 1. The median of the following observations 11, 12, 14, (x – 2), (x + 4), (x + 9), 32, 38, 47 arranged in ascending order is 24. Find the value of x and hence find the mean.
statistics-icse-solutions-class-10-mathematics-1

Question 2. The mean of 16 numbers is 8. If 2 is added to every number, what will be the new mean ?
statistics-icse-solutions-class-10-mathematics-2
statistics-icse-solutions-class-10-mathematics-3

Question 3. The mean monthly salary of 10 members of a group is Rs.1,445, one more member whose monthly salary is Rs.1,500 has joined the group. Find the mean monthly salary of 11 members of the group.
statistics-icse-solutions-class-10-mathematics-4

Question 4. The mean of 40 observations was 160. It was detected on rechecking that the value of 165 was wrongly copied as 125 for computation of mean. Find the correct mean.
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statistics-icse-solutions-class-10-mathematics-6

Question 5. The mean of 100 items was found to be 30. If at the time of calculation two items were wrongly taken as 32 and 12 instead of 23 and 11, find the correct mean.
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statistics-icse-solutions-class-10-mathematics-8
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Question 7. The average score of girls in class X examination in school is 67 and that of boys is 63. The average score for the whole class is 64.5. Find the percentage of girls and boys in the class.
statistics-icse-solutions-class-10-mathematics-10
statistics-icse-solutions-class-10-mathematics-11

Question 8. The mean weight of 150 students in a certain class is 60 kgs. The mean weight of boys in the class is 70 kg and that of girls is 55 kgs. Find the number of boys and the number of girls in the class.
statistics-icse-solutions-class-10-mathematics-12

Question 9. The numbers 6, 8, 10, 12, 13, and x are arranged in an ascending order. If the mean of the observations is equal to the median, find the value of x.
statistics-icse-solutions-class-10-mathematics-13
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For More Resources

How do you Calculate the Median

How do you Calculate the Median

Median of a distribution is the value of the variable which divides the distribution into two equal parts i.e. it is the value of the variable such that the number of observations above it is equal to the number of observations below it.
If the values xi in the raw data. are arranged in order of increasing or decreasing magnitude, then the middle, most value in the arrangement is called the median.
Algorithm :
Step I : Arrange the observations (values of the variate) in ascending or descending order of magnitude.
Step II  : Determine the total number of observations, say, n.
Step III  : If n is odd, then
Median = value of \({\left( {\frac{{n + 1}}{2}} \right)^{th}}\) observation
If n is even, then
Median = \(\frac{{Value\;of\;{{\left( {\frac{n}{2}} \right)}^{th}}observation + \;Value\;of\,{{\left( {\frac{n}{2} + 1} \right)}^{th}}observation}}{2}\)

The median can be calculated graphically while mean cannot be.
The sum of the absolute deviations taken from the median is less than the sum of the absolute deviations taken from any other observation in the data.
Median is not affected by extreme values.

Median Example Problems with Solutions

Example 1:    Find the median of the following data :
25, 34, 31, 23, 22, 26, 35, 28, 20, 32
Solution:    Arranging the data in ascending order, we get20, 22, 23, 25, 26, 28, 31, 32, 34, 35
Here, the number of observations n = 10 (even).
∴ Median = \(\frac{{Value\;of\;{{\left( {\frac{10}{2}} \right)}^{th}}observation + \;Value\;of\,{{\left( {\frac{10}{2} + 1} \right)}^{th}}observation}}{2}\)
⇒ Median = \(\frac{{Value\;of\;{5^{th}}observation\; + Value\;of\;{6^{th}}observation}}{2}\)
∴  Median = \(\frac{{26 + 28}}{2}\) = 27
Hence, median of the given data is 27.

Example 2:    Find the median of the following values :
37, 31, 42, 43, 46, 25, 39, 45, 32
Solution:    Arranging the data in ascending order, we have 25, 31, 32, 37, 39, 42, 43, 45, 46
Here, the number of observations n = 9 (odd)
∴ Median = Value of \({\left( {\frac{{9 + 1}}{2}} \right)^{th}}\) observation
= Value of 5th observation = 39.

Example 3:    The median of the observations 11, 12, 14, 18, x + 2, x + 4, 30, 32, 35, 41 arranged in ascending order is 24. Find the value of x.
Solution:    Here, the number of observations n = 10. Since n is even, therefore
Median =  \(\frac{{{{\left( {\frac{n}{2}} \right)}^{th}}observation\; + {{\left( {\frac{n}{2} + 1} \right)}^{th}}observation}}{2}\)
⇒   24 =  \(\frac{{{5^{th}}observation + {6^{th}}observation}}{2}\)
⇒   24 =  \(\frac{{(x + 2) + (x + 4)}}{2}\)
⇒   24 =  \(\frac{{2x + 6}}{2}\)
⇒   24 = x + 3   ⇒ x = 21.
Hence,  x = 21.

Example 4:    Find the median of the following data : 19, 25, 59, 48, 35, 31, 30, 32, 51. If 25 is replaced by 52, what will be the new median.
Solution:    Arranging the given data in ascending order, we have 19, 25, 30, 31, 32, 35, 48, 51, 59
Here, the number of observations n = 9 (odd)
Since the number of observations is odd. Therefore.
Median = Value of \({\left( {\frac{{9 + 1}}{2}} \right)^{th}}\) observations
⇒   Median = value of 5th observation = 32.
Hence, Median = 32
If 25 is replaced by 52, then the new observations arranged in ascending order are :
19, 30, 31, 32, 35, 48, 51, 52, 59
∴ New median = Value of 5th observation = 35.

Example 5:    Calculate the median for the following  distribution.

Weight  (in kg)Number of students
463
472
484
496
505
512
521

Solution:    The cumulative frequency table is constructed as shown below :

Weight  (xi)Number of students (fiCumulative frequency
4633
4725
4849
49615
50520
51222
52123

Here, n = 23, which is odd
Median  = \({t_{\frac{{23 + 1}}{2}}}\) = t12 = 49
(i.e. weight of the 12th student when the weights have been arranged in order)

Example 6:    The following data have been arranged in desending orders of magnitude 75, 70, 68, x + 2, x – 2, 50, 45, 40
If the median of the data is 60, find the value of x.
Solution:    The number of observations are 8, the median will be the average of 4th and 5th number
⇒   Median = \(\frac{{(x + 2) + (x-2)}}{2}\)
⇒   60 = \(\frac{{2x}}{2}\)  ⇒ x = 60

Example 7:    Find the median of the following data
(i)   17, 27, 37, 13, 18, 25, 32, 34, 23
(ii)  24, 37, 19, 41, 28, 32, 29, 31, 33, 21
Solution:    (i)   The scores when arranged in ascending order are
13, 17, 18, 23, 25, 27, 32, 34, 37
Here, the number of scores n = 9 (odd)
∴    Median = \({t_{\frac{{9 + 1}}{2}}}\) = t5 = 25
(ii)  The scores when arraged in ascending order are
19, 21, 24, 28, 29, 31, 33, 34, 37, 41.
Total number of scores = 10, which is even. So there will be two middle-terms which are t5 = 29 and t6 = 31.
∴  Median = \(\frac{{{t_5} + {t_6}}}{2} = \frac{{29 + 31}}{2}\) = 30

Example 8:    Find the median of the following data :
(i)   8, 10, 5, 7, 12, 15, 11
(ii)  12, 14, 10, 7, 15, 16
Solution:    (i)   8, 10, 5, 7, 12, 15, 11
These numbers are arranged in an order
5, 7, 8, 10, 11, 12, 15
The number of observations = 7 (odd)
⇒   Median = \(\frac{7+1}{2}\) = 4th term
⇒   Median = 10
(ii)  12, 14, 10, 7, 15, 16
These numbers are arranged in an order
7, 10, 12, 14, 15, 16
The number of observations = 6 (even)
The medians will be mean of  = 3rd and 4th terms i.e., 12 and 14
⇒  The median = \(\frac{12+14}{2}\) = 13

Example 9:    The following data have been arranged in desending orders of magnitude 75, 70, 68, x + 2, x – 2, 50, 45, 40
If the median of the data is 60, find the value of x.
Solution:    The number of observations are 8, the median will be the average of 4th and 5th number
⇒   Median = \(\frac{{(x + 2) + (x–2)}}{2}\)
⇒   60 = \(\frac{2x}{2}\)
⇒  x = 60

Example 10:    Find the median of 6, 8, 9, 10, 11, 12 and 13.
Solution:    Total number of terms = 7
The middle terms = \(\frac{1}{2}\) (7 + 1) = 4th
Median = Value of the 4th term = 10.
Hence, the median of the given series is 10.

Example 11:    Find the median of 21, 22, 23, 24, 25, 26, 27 and 28.
Solution:    Total number of terms = 8
Median
= Value of \(\frac{1}{2}\left[ {\frac{8}{2}th\,\,term + \,\left( {\frac{8}{2} + 1} \right)th\,term} \right]\)
= Value of \(\frac{1}{2}\) [4th term + 5th term]
= \(\frac{1}{2}\) [24 + 25] = \(\frac{49}{2}\) = 24.5

Example 12:    The number of runs scored by 11 players of a cricket team of school are 5, 19, 42, 11, 50, 30, 21, 0, 52, 36, 27. Find the median.
Solution:    Let us arrange the value in ascending order
0, 5, 11, 19, 21, 27, 30, 36, 42, 50, 52
∴  Median M = \({\left( {\frac{{n + 1}}{2}} \right)^{th}}\) value
= \({\left( {\frac{{11 + 1}}{2}} \right)^{th}}\) value = 6th value
Now 6th value in data is 27
∴        Median = 27 runs.

What is Cumulative Frequency in statistics

What is Cumulative Frequency in statistics

  • If the frequency of first class interval is added to the frequency of second class and this sum is added to third class and so on then frequencies so obtained are known as Cumulative Frequency (c.f.).
  • There are two types of cumulative frequencies (a) less than, (b) greater than    
  • A table which displays the manner in which cumulative frequencies are distributed over various classes is called a cumulative frequency distribution or cumulative frequency table.
  • There are two types of cumulative frequency.
    (1)  Less than type
    (2) Greater than type

Read  More:

Cumulative Frequency Table Example Problems with Solutions

Example 1:    The marks obtained by 35 students in a class are given below. Construct the cumulative frequency table :

Marks obtainedNumber of students
01
12
24
34
43
55
64
76
83
92
101

Solution:
What is Cumulative Frequency in statistics 1

Example 2:    The distribution of ages (in years) of 40 persons in a colony is given below.

Age (in years)Number of Persons
20-257
25-3010
30-358
35-406
40-454
45-505

(a) Determine the class mark of each class
(b) What is the upper class limit of 4th class
(c) Determine the class size
Solution:    (a) Class marks are
What is Cumulative Frequency in statistics 2
= 22.5, 27.5, 32.5, 37.5, 42.5, 47.5
(b)  The fourth class interval is 35–40. Its upper limit is 40
(c)  The class size is 25 – 20 = 5

Example 3:    Following is the distribution of marks of 40 students in a class. Construct a cumulative frequency distribution table.

MarksNumber of Students
0-103
10-208
20-309
30-4015
40-505

Solution:
What is Cumulative Frequency in statistics 3

Example 4:    The class marks of a distribution are 25, 35, 45, 55, 65 and 75. Determine the class size and class limit.
Solution:    Class size = The difference between the class marks of two adjacent classes.
= 35 – 25
= 10
We need classes of size 10 with class marks as 25, 35, 45, 55, 65, 75
The class limits for the first class are
25 –  \(\frac { 10 }{ 2 }\) and 25 + \(\frac { 10 }{ 2 }\)
i.e. 20 and 30
First class is, therefore, 20–30
Similarly, the other classes are 30 – 40, 40 – 50, 50 – 60, 60 – 70, 70 – 80.

Example 5:   Given below is the cumulative frequency distribution table showing the marks secured by 40 students.

MarksNumber of Students
Below 205
Below 4010
Below 6025
Below 8032
Below 10040

Show in the class and their frequency form.
Solution:

MarksCumulative frequencyFrequency
0-2055
20-40105 ( = 10 -5)
40-602515 ( = 25 – 10)
60-80327 ( = 32 – 25)
80-100408 (= 40 – 32)

Example 6:    Write down less than type cumulative frequency and greater than type cumulative frequency.

Height  (in cm)Frequency
140 – 14510
145 – 15012
150 – 15518
155 – 16035
160 – 16545
165 – 17038
170 – 17522
175 – 18020

Solution:    We have

Height           (in cm)140–145145–150150–155155–160160–165165–170170–175175–180
Frequency1012183545382220
Height     Less than type145150155160165170175180
Cumulative  frequency10224075120158180200
Height Greater than type140145150155160165170175
Cumulative  frequency200190178160125804220

Example 7:    The distances (in km) covered by 24 cars in 2 hours are given below :
125, 140, 128, 108, 96, 149, 136, 112, 84, 123, 130, 120, 103, 89, 65, 103, 145, 97, 102, 87, 67, 78, 98, 126
Represent them as a cumulative frequency table using 60 as the lower limit of the first group and all the classes having the class size of 15.
Solution:    We have, Class size = 15
Maximum distance covered = 149 km.
Minimum distance covered = 65 km.
Range = (149 – 65) km = 84 km.
So, number of classes = 6 (since \(\frac { 84 }{ 15 }  \) = 5.6
Thus, the class intervals are 60-75, 75-90,90-105, 105-120, 120-135, 135-50.
The cumulative frequency distribution is as given below :
What is Cumulative Frequency in statistics 4

Example 8:    The following table gives the marks scored by 378 students in an entrance examination :
What is Cumulative Frequency in statistics 5
From this table form (i) the less than series, and (ii) the more than series.
Solution:    (i)   Less than cumulative frequency table
What is Cumulative Frequency in statistics 6
 (ii) More than cumulative frequency table
What is Cumulative Frequency in statistics 7

Example 9:    Convert the given simple frequency series into a:
(i)   Less than cumulative frequency series.
(ii)  More than cumulative frequency series.

MarksNo. of students
0-103
10-207
20-3012
30-408
40-505

Solution:    (i)  Less than cumulative frequency series
What is Cumulative Frequency in statistics 8
(ii)  More than cumulative frequency series
What is Cumulative Frequency in statistics 9

Example 10:    Convert the following more than cumulative frequency series into simple frequency series.
What is Cumulative Frequency in statistics 10
Solution:    Simple frequency distribution table
What is Cumulative Frequency in statistics 11

Example 11:    Drawn ogive for the following frequency distribution by less than method  

Marks0-1010-2020-3030-4040-5050-60
No. of Students710235163

Solution:    We first prepare the cumulative frequency distribution table by less than method as given below :

Marks0-1010-2020-3030-4040-5050-60
No. of Students710235162
Marks less than102030405060
Cumulativefrequency717409197100

Other than the given class intervals, we assume a class – 10-0 before the first class interval 0-10 with zero frequency.
Now, we mark the upper class limits (including the imagined class) along X-axis on a suitable scale and the cumulative frequencies along Y-axis on a suitable scale.
Thus, we plot the points
(0, 0), (10, 7), (20, 17), (30, 40), (40, 91), (50,97), and (60, 100)
What is Cumulative Frequency in statistics 12
Now, we join the plotted points by a free hand curve to obtain the required ogive.

Example 12:    Draw a cumulative frequency curve for the following frequency distribution by less than method

    Age (in years)0-910-1920-2930-3940-4950-5960-69
   No. of persons:515202317119

Solution:    The given frequency distribution is not continuous. So, we first make it continuous and prepare the cumulative frequency distribution as under :

Age (in years) FrequencyAge less thanCumulative frequency 
0.5 – 9.559.55
9.5 – 19.51519.520
19.5 – 29.52029.540
29.5 – 39.52339.563
39.5 – 49.51749.580
49.5 – 59.51159.591
59.5 – 69.5969.5100

Now, we plot points (9.5, 5), (19.5, 20), (29.5,40), (39.5, 63), (49.5, 80), (59.5, 91) and (69.5, 100) and join them by a free hand smooth curve to obtain the required ogive as shown in Fig.
What is Cumulative Frequency in statistics 13

Example 13:    The temperature of a patient, admitted in a hospital with typhoid fever, taken at different times of the day are given below. Draw the temperature-time graph to reprents the data:

  Time (in hours)6:008:0010:0012:0014:0016:0018:00
Temperature  (in °F)1021009910310010299

Solution:    In order to draw the temperature-time graph, we represent time (in hours) on the x-axis and the temperature in ºF on the y-axis. We first plot the ordered pairs (6, 102), (8, 100),      (10, 99), (12, 103), (14, 100), (16, 102) and (18, 99) as points and then join them by line segments as shown in Fig.
What is Cumulative Frequency in statistics 14

Example 14:    The graph shown in Fig. exhibits the rate of interest on fixed deposite upto one year announced by the reserve bank of india in different years. Read the graph and find.
(i)   In which period was the rate of interest maximum?
(ii)  In which period was the rate of interest minimum ?
What is Cumulative Frequency in statistics 15
Solution:    In the graph, we find that years are represented on x-axis and the rate of interest per annum is along y-axis. From the graph, we find that
(i)   The rate of interest was maximum (12%) in 1996.
(ii)  The minimum rate of interest was 6.5% in the year 2002.

Example 15:    The following data represents the wages of 25 workers of a certain factory :

Wages (in rupees) No. of workers
30-405
40-508
50-6012
60-707
70-804
80-902

Solution:    The cumulative frequency table is constructed as follows :

Wages (in rupees)No. of workersCumulative frequency
30-4055
40-50813
50-601225
60-70732
70-80436
80-90238

The cumulative frequency curve is shown below:
What is Cumulative Frequency in statistics 16

Example 16:    Draw the Time-Temperature graph from the following table

Time (in hour)Temperature (in °C)
10-0021
11-0023
12-0025
13-0027
14-0028
15-0026

From the graph estimate the temperature at 11-30 a.m.
Solution:    Time in hours is denoted along the X-axis and temperature (in °C) is inidicated along the Y-axis. The points are joined by drawing a freehand curve. From the graph, the temperature at 11-30 a.m. is found to be 24.0°C.
What is Cumulative Frequency in statistics 17

What is a Bar Graph in Statistics

What is a Bar Graph in Statistics

Graphical representation of data
The graphical representations such as bar graphs, histograms, frequency polygons, etc.  

Bar graph (diagram) of a data
A bar graph (diagram) is a pictorial representation of the data by a series of bars or rectangles of uniform width standing on the same horizontal (or vertical) base line with equal spacing between the bars. Each rectangle or bar represents only one numerical value of the data. The height (or length in case the base is on a vertical line) of each bar is proportional to the numerical values of the data.
For example, we are given a data about the household expenditure of a family as below :

Heads of expenditure

Expenditure 
(in thousand rupees)

Rent

5
Grocery

2

Education

3
Transport

2

Miscellaneous

4

We draw the bar graph for the above data as below:
What is a Bar Graph in Statistics 1
The horizontal axis is generally called x-axis and the vertical axis as the y-axis.

  1. Each bar of a bar diagram has same width.
  2. Space between two consecutive bars is same throughout.

Bar Graph in Statistics Example Problems with Solutions

Example 1:    In figure, the bar diagram presents the expenditure (in proportionate figures) on five different sports. If the total expenditure incurred on all the sports in a particular year be 2,00,000, then find the amount spent
(i) on hockey
(ii) on cricket
What is a Bar Graph in Statistics 2Solution:    Proportionate amount spent on Football, Hockey, Cricket, Basketball, and volleyball are in the ratio 3 : 4 : 6 : 2 : 5 respectively. Total amount spent = RS. 2,00,000.
Now,    3 + 4 + 6 + 2 + 5 = 20.
Amount spent on hockey
= 2,00,000 ×  \(\frac { 4 }{ 20 }\)
= 40,000
Amount spent on cricket
= 2,00,000 ×  \(\frac { 6 }{ 20 }\)
= Rs. 60,000

Example 2:   Compare the academic standard of two classes A and B each of 40 students on the basis of the following data by making bar diagram.   

Marks :

0-1010-3030-6060-100

No. of students in A :

5

1020

5

No. of students in B : 101510

5

Solution:    
What is a Bar Graph in Statistics 3

Example 3:   Read the bar graph in figure and answer the following :
What is a Bar Graph in Statistics 4
(i)   What information is given by the bar graph ?
(ii)  What was the quantity of rice production in the year 1980-81.
(iii) What is the difference between the maximum and minimum production of rice in the time span of 1978-1983.

Solution:    (i)  The bar graph, represents production of rice in the period 1978-1983 (year-wise).
(ii) The bar for 1980-81 has length = 55.
Therefore, the production of rice in the year 1980-81 is 55 lakh tons.
(iii) In the year 1981-82, the production of rice is maximum and is equal to 65 lakh tons. In the year 1979-80, the production of rice is minimum and is equal to 25 lakh tons.
The difference between the maximum and the minimum production
= 65 lakh tons – 25 lakh tons
= 40 lakh tons