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Frank ICSE Solutions for Class 9 Chemistry – The Periodic Table

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Frank ICSE Solutions for Class 9 Chemistry – The Periodic Table

PAGE NO :132
Solution 1:
The present form of periodic table has eighteen vertical columns called ‘groups’. These groups are numbered from 1 to 18.

Solution 2:
Seven horizontal rows in periodic table are called periods.These are numbered as 1, 2, 3, 4, 5, 6 and 7 from top to bottom.

Solution 3:
Certain chemically similar elements are arranged into set of three elements are called triads. When these elements are arranged in order of their atomic mass, the atomic mass of the middle element is approximately average of the atomic masses of the other two.
For Example – Lithium, Sodium, Potassium

Solution 4:
Frank ICSE Solutions for Class 9 Chemistry - The Periodic Table 1

Solution 5:

  1. (a) When elements are arranged in increasing order of their atomic masses, the eighth element resembles the first in physical and chemical properties just like the eighth note on a musical scale resembles the first note.
  2. (b) It is based on the notes of the musical scale.
  3. (c) No, the law of octaves was not valid beyond calcium i.e. not valid for heavier elements having atomic no. greater than ’40’.
  4. (d) There are 6 elements in between A and B.

Solution 6:
Important conclusions of Newland’s law of octaves are-

  1. It was the first logical attempt to classify elements on the basis of atomic masses.
  2. Periodicity of elements was recognized for the first time.

Solution 7:
The physical and chemical properties of elements are the periodic functions of their atomic masses.

Solution 8:

  1. It helps to understand that the properties of elements are related with some fundamental unit of all elements.
  2. It simplifies and systemizes the study of the properties of various elements and their compounds.
  3. It helps to understand  the relationship between the different types of elements.
  4. It helps to understand the cause of gradual change in properties from one element to another.

Solution 9:
The number of elements in various periods are-
Period 1 – 2
Period 2 – 8
Period 3 – 8

Solution 10:
Hydrogen and Helium are the elements of period 1.

Solution 11:
At the end of the period 2 and period 3 the outer shell of the elements are fully filled i.e. they have complete octet.

Solution 12:
The element of group II (2) is likely to be metallic in character.

Solution 13:
Metallic character increases on moving down the group. Therefore, the element that is placed at the end of the group will have the greatest metallic character.

Solution 14:

  1. (a) Two alkali metals and their groups and period are-
    Lithium – First group and second period.
    Sodium – First group and third period.
  2. (b) Two alkaline earth metals with their groups and periods are-
    Beryllium – Second group and Second period
    Magnesium – Second group and Third period
  3. (c) Halogens belong to Group 17.
  4. (d) Elements of groups from 3 to 12 are called as transition elements.
  5. (e) Helium gas has duplet arrangement of electrons.
  6. (f) Germanium is a metalloid of group 14.
  7. (g) The bond formed between the atoms of an element of group 2 and group 16 is called as electrovalent or  ionic bond.
  8. (h) The bond formed between the atoms an element of group 14 and group 17 is called as covalent bond.
  9. (i) Lithium and Magnesium are the elements which are showing a diagonal relationship.
  10. (j) In Group 18 all elements are gases.

PAGE NO :133
Solution 15:

  1. (a) Newland, Newland law of Octaves
  2. (b) atomic masses
  3. (c) 18, 7
  4. (d) unstable
  5. (e) Atomic number, Moseley
  6. (f) similar outer electronic configuration at certain regular intervals
  7. (g) decreases
  8. (h) 2 electrons
  9. (i) different

Solution 16:

  1. (a) False
  2. (b) True
  3. (c) True
  4. (d) False
  5. (e) False
  6. (f) False
  7. (g) False

Solution 17:

  1. (a) A – 2, 1
    B – 2, 3
    C – 2, 8, 2
    D – 2, 8, 8
    E – 2, 8, 8, 2
  2. (b) B is placed right to A.
  3. (c) C and E belongs to same group.
  4. (d) The formula for sulphate of C is CSO4.
  5. (e) C has a smaller size atom.
  6. (f) Sodium is placed below A.
  7. (g) Helium is the first element of the group to which D belongs.
  8. (h) The formula for chloride of B is BCl3.
  9. (i) A2O is the formula of oxide of A.
  10. (j) Fluorine  is the non-metallic element which belongs to the same period as A.

Solution 18:

  1. (a) Properties of Germanium i.e. also called as eka-silicon were predicted on the basis of its position in Mendeleev’s periodic table.
  2. (b) Beryllium and Gold are the two elements whose atomic weights were corrected on the basis of their positions in Mendeleev’s periodic table.
  3. (c) There were 63 elements known at the time of Mendeleev’s classification of elements.

PAGE NO :134
Solution 19:
Merits of Mendeleev’s classification of elements are:-

  1. Systematic study of the element: Elements could now be studied as groups or families rather than individuals. The Mendeleev’s  periodic table simplified and systemized the study of the elements and their compounds.
  2. Prediction of new elements: While arranging the elements, in increasing order of atomic mass, Mendeleev left some blanks for the elements that were not discovered at that time. Though unknown, he was able to predict their properties more or less accurately.He named 3 of such elements as eka-boron, eka-aluminium, eka-silicon. He named them, as they were below boron,aluminium and silicon in the respective sub-groups.Eka-boron was later named as scandium, eka-aluminium as gallium and eka-silicon as germanium.
  3. Correction of atomic masses: The Mendeleev’s periodic table helped in correcting the atomic masses of elements based on their position in periodic table. Example-Atomic masses of Be was corrected from 13.5 to 9.

Solution 20:
Mendeleev left some gaps in his periodic table of elements for the elements that were not discovered at that time. Though they were unknown, he was able to predict their properties more or less accurately at that time.
Example – He named eka-boron, eka- aluminium and eka-silicon to some elements as they were just below boron, aluminium and silicon in the respective sub-groups. Eka-boron was later named as scandium, eka-aluminium as gallium and eka-silicon as germanium.

Solution 21:
The main characteristic of the last elements in the periodic table are-

  1. Their octet is attained.
  2. They are inert in nature.

The general name of such elements is noble gas or inert elements.

Solution 22:

  1. (a) The physical and chemical properties of elements are the periodic functions of their atomic numbers.
  2. (b) There are 7 periods and 18 groups  in the long form of the periodic table.
  3. (c) The number of elements in each period is-
    1 period-2
    2 period-8
    3 period-8
    4 period-18
    5 period-18
    6 period-32
    7 period-Incomplete

Solution 23:

  1. (a) X belongs to 17th group.
  2. (b) The period number of X is 3.
  3. (c) In atom of X there are 7 valence electrons.
  4. (d) Valency of X is 1.
  5. (e) It is non-metal.
  6. (f) The element right to it is Argon and the element left to it is Sulphur.
  7. (g) The atomic number of the elements above to it is 9 and below to it is 35 in the periodic table.

Solution 24:

  1. (a) The nature of bond will be ionic in the compound XY.
  2. (b)
    1. Y and Z will form covalent bond.
    2. X and Z will form ionic compound.

Solution 25:

  1. (a) There would be 2 electrons in the outermost shell of the element X.
  2. (b) Element X belong to second group of the periodic table.
  3. (c) When X reacts with chlorine, the compound formed of the formula XCl2.

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Frank ICSE Solutions for Class 9 Chemistry – Study of the First Element – Hydrogen

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Frank ICSE Solutions for Class 9 Chemistry – Study of the First Element – Hydrogen

PAGE NO :146
Solution 1:

  1. (a) Symbol of hydrogen is ‘H’ and its molecular formula is H2.
  2. (b) 2 H means 2 atoms of hydrogen while H2 means one molecule of hydrogen.
  3. (c) Lavoisier gave “Hydrogen” its name because it means water product.

Solution 2:
Hydrogen is found in free state as well as in combined  state.

  1. In free state, it is found in traces in the earth’s crust and atmosphere. On the sun and bright stars, hydrogen is very abundant.It is suggested that the source of sun’s energy is fusion of hydrogen to helium.
  2. In combined state it is found in the compounds like water, acids, organic materials and minerals. Natural gas coming out from oil wells, coal mines and volcanoes invariably contains this gas.

Solution 3:
Hydrogen resembles the alkali in following manner-

  1. Electronic configuration – Hydrogen as well as alkali metals have one electron in their valence shell.
    H (1) = 1      ; Li(3)= 2, 1   ; Na(11) =2, 8, 1
  2. Ion formation – Hydrogen loses one electron to form H+ ion like the alkali metals which form Li+, Na+, K+ etc.
  3. Valency electrons – Like alkali metals, hydrogen exhibit valency of one in its compounds , as it has only one electron in its outermost shell.
  4. Combination with non-metals – Like alkali metals, hydrogen combines with non-metals such as oxygen, chlorine and sulphur forming their oxides, chlorides and sulphides respectively.
  5. Reducing action – Like alkali metals, hydrogen is also a very good reducing agent.

Solution 4:
Hydrogen resembles the alkali in following manner-

  1. Electronic configuration – All the halogens have seven electrons in their outermost shell and need just one more electron to attain stable inert gas configuration. Similarly, hydrogen with one electron in its outermost shell requires one electron to attain a stable inert gas(Helium) configuration.
  2. Valency – Hydrogen and halogen both show a valency of one.
  3. Non-metals – Hydrogen is non-metallic like halogen.
  4. Atomicity – Hydrogen as well as halogens are diatomic gases, e.g.H2,Cl2.Br2 etc.
  5. Ion formation – Halogens have a strong tendency to gain an electron to form halide ions.In similar way, hydrogen shows tendency to gain one electron to form hydride ion (H–).

Solution 5:
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 1

Solution 6:
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 2

Solution 7:
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 3

Solution 8:
Hydrogen gas  obtained in the laboratory by dilute H2SO4 and granulated zinc have following impurities-

  1. Hydrogen sulphide (H2S),
  2. Sulphur dioxide (SO2),
  3. Oxides of nitrogen,
  4. Phosphine (PH3),
  5. Arsine (AsH3),
  6. Carbon dioxide, Nitrogen oxides,
  7. Water vapour
    They are removed by passing through-

    1. Lead nitrate solution-It absorbs H2S.
    2. Silver nitrate solution (AgNO3)-It absorbs PH3, AsH3
    3. Caustic potash (solid KOH)-It absorbs CO2, SO2, oxides of nitrogen
    4. Anhydrous calcium chloride or P2O5-It absorbs moisture.

Solution 9:
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 4

Solution 10:
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 5
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 6

PAGE NO :147
Solution 11:
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 7

Solution 12:
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 8

Solution 13:

  1. (a) Nickel, hydrogen
  2. (b) above, dilute mineral
  3. (c) covalent, electronegative
  4. (d) CuO, hydrogen, water
  5. (e) CO, H2
  6. (f) alkali
  7. (g) nascent hydrogen
  8. (h) water

Solution 14:

  1. (a) False
  2. (b) False
  3. (c) True
  4. (d) True
  5. (e) True
  6. (f) True
  7. (g) True
  8. (h) False

Solution 15:
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 9
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 10

PAGE NO :148
Solution 16:
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 11

Solution 17:
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 12

Solution 18:
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 14

Solution 19:
Some pieces of zinc granules are placed in Woulfe’s bottle and the apparatus is made in air tight. Now dilute sulphuric acid is poured through the thistle funnel.
Observation: The reaction takes place at room temperature even without heating. A brisk effervescence with the evolution of gas is seen inside the bottle.
If burning candle is brought near the bubbles of hydrogen gas, they explode.This proves that bubbles were full of hydrogen gas and they move up in the air because they are lighter than air.

Solution 20:

  1. (a) Meteorological balloons – The low density and high lifting power of hydrogen made it useful in meteorological balloons used for studying air currents and weather conditions. However, due to its highly inflammable nature it has been replaced by helium which has a lifting only slightly less than that of hydrogen.
  2. (b) In metallurgy – Hydrogen acts as a very good reducing agent. It is used to obtain metals by reducing their oxides.
  3. (c) In fuel – Hydrogen has very high heat of combustions, therefore it is used as fuel  in the form of coal gas, water gas and liquid hydrogen(for rocket propulsion).
  4. (d) In making fertilizers – A large quantity of hydrogen is used in the manufacture of ammonia by Haber process. Ammonia is used in manufacture of HCl and methyl alcohol.

Solution 21:
Frank ICSE Solutions for Class 9 Chemistry - Study of the First Element - Hydrogen 15

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Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2

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Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2

Download Formulae Handbook For ICSE Class 9 and 10

Frank ICSE Solutions for Class 9 Maths Chapter 1 Irrational Numbers Ex 1.2

Answer 1A.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 1
Answer 1B.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 2
Answer 1C.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 3
Answer 1D.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 4
Answer 2A.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 5
Answer 2B.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 6
Answer 2C.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 7
Answer 2D.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 8
Answer 3.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 9
Answer 4.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 10
Answer 5A.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 11
Answer 5B.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 12
Answer 5C.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 13
Answer 5D.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 14
Answer 5E.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 15
Answer 5F.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 16
Answer 6A.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 17
Answer 6B.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 18
Answer 7A.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 19
Answer 7B.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 20
Answer 7C.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 21
Answer 7D.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 22
Answer 8A.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 24
Answer 8B.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 25
Answer 8C.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 27
Answer 9.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 28
Answer 10.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 29
Answer 11.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 30
Answer 12.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 31
Answer 13A.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 32
Answer 13B.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 33
Answer 13C.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 34
Answer 13D.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 35
Answer 13E.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 36
Answer 13F.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 37
Answer 14.
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 38
Frank ICSE Solutions for Class 9 Maths Irrational Numbers Ex 1.2 39

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Frank ICSE Solutions for Class 10 Chemistry – Electrolysis

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Frank ICSE Solutions for Class 10 Chemistry – Electrolysis

PAGE NO : 131
Solution 1:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 1

Solution 2:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 2

Solution 3:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 3

Solution 4:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 4

Solution 5:
Three appilications of electrolysis are:

  1. Electro plating with metals
  2. Electrofining of metals
  3. Extraction of metals

Solution 6:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 6
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 7

Solution 7:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 8

Solution 8:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 9

Solution 9:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 10

PAGE NO : 132

Solution 10:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 11

Solution 11:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 12

Solution 12:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 13

Solution 13:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 14

Solution 14:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 15

Solution 15:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 16

Solution 16:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 17

Solution 17:
The main appilications of electrolysis are:

  1. Electro plating with metals
  2. Electrofining of metals
  3. Extraction of metals

Solution 18:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 18

Solution 19:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 19

Solution 20:

  1. Na2CO3
  2. NH3
  3. Graphite, Cu electrode
  4. NH4+
  5. Graphite

PAGE NO : 133
Solution 1994-1:

  1. The article to be plated must be made Cathode.
  2. The ions of the metal which is to be electroplated must be present in the electrolyte.
  3. The metal to be plated on the article must be made anode. It needs to be periodically replaced.

Solution 1994-2:
The passage of electricity through an electrolyte occurs through ions furnished by the electrolyte where as the passage of electricity through a copper wire occurs through electrons.

Solution 1995-1:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 20

Solution 1995-2:
It is the process of decomposition of an electrolyte in the molten or aqueous state by discharge of ions at the electrodes on the passage of an electric current.

Solution 1995-3:
Pure water does not conduct electricity because the degree of ionization is low. Thus to make it a good conductor of electricity acid is added to it which will increase the degree of ionization.

Solution 1996-1:
Substance which contain

  1. Ions only:- HCl
  2. Molecules only:- Petrol
  3. Both ions and molecules:- CH3COOH

Solution 1996-2:

  1. Electrolyte is a compound which either in aqueous solution or in molten state allows an electric current to pass through it and is accompanied by discharge of ions and finally into neutral atoms at the two electrodes.
  2. Non- electrolyte are substances which do not conduct electricity in fused or aqueous state. They contain only molecules and do not ionize. For example: petrol, alcohol.
  3. If the electrolyte is described as ‘strong electrolyte’ it means it completely dissociates into its constituting ions in aqueous solution.

Solution 1996-3:

  1. As for every copper ion discharged at the cathode, an ion of copper is formed at the anode which goes into the solution .Since atoms of copper are deposited at the cathode, the cathode becomesthicker and as the atoms of copper from the anode change into ions of copper, the anode becomes thinner.
  2. When platinum rods are used as electrodes, then x the blue colour of copper sulphate solution fades and sulphuric acid is formed. This is because oxygen is liberated at anode and copper metal is deposited at cathode
  3. Practical application of electrolysis of copper sulphate solution: This is the basis for purification of copper.
    Other metals like Zinc, Nickel, Silver .Lead can also be purified.

Solution 1997-1:
Lead Bromide should be in the molten state if it has to conduct electricity.

Solution 1997-2:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 21

Solution 1997-3:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 22

Solution 1998-1:

  1. Electrolyte
  2. Nickel
  3. Cathode
  4. Anode
  5. Cations

PAGE NO : 134
Solution 1999-1:
The electrolysis of lead bromide liberates lead at cathode and bromine at anode.

Solution 1999-2:
When a fused metallic chloride is electrolyzed, the metal is obtained at cathode.

Solution 2000-1:

  1. Strong electrolytes – dilute hydrochloric acid, dilute sulphuric acid, Ammonium chloride
  2. Weak electrolyte – Acetic acid, Ammonium hydroxide
  3. Non-electrolytes – Carbon tetrachloride

Solution 2002-3:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 23

Solution 2002-1:

  1. molecules.
  2. will not

Solution 2002-2:

  1. When sulphuric acid is added to water it becomes good conductor as addition of sulphuric acid causes dissociation of water molecules into H+ and OH– ions which are then responsible for conduction of electricity by pure water. The water thus obtained is called acidified water.
  2. Cathode, Anode

Solution 2003-1:
electricity, chemical

Solution 2004-2

  1. Molecules are found in a liquid compound which is a non-electrolyte.
  2. Non ionized molecules;
  3. H+ and X– particles will be present in dilute solution.
  4. Loss, Gain
  5. The ions of the metal which is to be electroplated on the article must be present in a solution.
  6. Redox reaction is one in which oxidation and reduction occurs simultaneously.
  7. Similarly in case of electrolysis:
    • At cathode: The cations gain electron and become neutral. As the electrons are gained the ion is said to be reduced.
    • At anode: The anions lose electron to form neutral atoms. As the electrons are lost the ion is said to be oxidized.
      Hence in electrolysis also the oxidation and reduction occurs hence it is an example of Redox reaction.

Solution 2004-1:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 24

PAGE NO : 135
Solution 2005-1:

  1. Copper metal is solid and has no mobile ions whereas an electrolyte should dissociate into oppositely charged ions to conduct the electric current.
  2. Hydrogen is released at the cathode when acidulated water is electrolyzed.
  3. In sodium chloride, Na+ and Cl– ions are not free to carry the electric current.
  4. (a) Reduced
    (b) Higher

Solution 2006-1:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 25

Solution 2006-2:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 26

Solution 2007-1:

  1. Molten ionic compound – Strong electrolyte
  2. Carbon tetrachloride- Non-electrolyte
  3. An aluminium wire- Metallic conductor
  4. A solution containing solvent molecules, solute molecules and ions formed by the dissociation of solute molecules- weak electrolyte
  5. A sugar solution with sugar molecules and water molecules- Non-electrolyte

Solution 2007-2:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 27

PAGE NO : 136
Solution 2008-1:
(d) Lead is deposited at the cathode

Solution 2008-2:
Frank ICSE Solutions for Class 10 Chemistry - Electrolysis 28

Solution 2009–2:
Mg (OH)2 as it is basic while rest are amphoteric.

Solution 2009–3:
Molten Lead bromide conducts electricity.

Solution 2009-4:

  1. Nickel ions move towards cathode.
  2. Nickel ions.

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Frank ICSE Solutions for Class 10 Chemistry – Mole Concept And Stoichiometry

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Frank ICSE Solutions for Class 10 Chemistry – Mole Concept And Stoichiometry

PAGE NO : 103
Solution 1:

  1. Gay-Lussac’s law: It states that ‘when gases react, they do so in volumes which bear a simple ratio to one another, and also to the volume of the gaseous product, provided all the volumes are measured at the same temperature and pressure’.
  2. Avogadro’s law : It states that ‘Under the same conditions of temperature and pressure, equal volumes of all gases contain the same number of molecules’.

Solution 2:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 1

Solution 3:
When stating the volume of a gas, the pressure and temperature should also be given because the volume of a gas is highly susceptible to slight change in pressure and temperature of the gas.

Solution 4:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 2

Solution 5:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 3

Solution 6:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 4

Solution 7:

  1. Gram atom: “The quantity of the element which weighs equal to its gram atomic mass is called one gram atom of that element”.
    For example: The gram atomic mass of hydrogen is 1g. So, 1g of hydrogen is 1 gram atom of hydrogen.
  2. Gram mole: “A sample of substance with its mass equal to its gram molecular mass is called one gram molecule of this substance or one gram mole”.
    For example: Gram molecular mass of oxygen is 32 g. So One gram mole of oxygen is 32g.

Solution 8:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 5

Solution 9:
Empirical formula:“Empirical formula of a compound is the formula which gives the number of atoms of different elements present in one molecule of the compound, in the simplest numerical ratio”.
Molecular formula: “Molecular formula of a compound denotes the actual number of atoms of different elements present in one molecule of the compound”.

Solution 10:

  1. The empirical formula of C6H6 is: CH
  2. The empirical formula of C6H12O6 is: CH2O.
  3. The empirical formula of C2H2 is: CH
  4. The empirical formula of CH3COOH is: CH2O.

Solution 11:
Three pieces of information conveyed by the formula H2O is that:

  1. It shows that there are 2 hydrogen atoms and 1oxygen atoms present in H2O.
  2. The hydrogen and oxygen atoms are present in simplest whole number ratio of 2:1.
  3. It represents one molecule of compound water.

Solution 12:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 6

Solution 13:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 7

PAGE NO : 104

Solution 14:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 8

Solution 15:

  1. Na2SO4.10H2O.
  2. C6H12O6.

Solution 16:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 9

Solution 17:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 10

Solution 18:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 11

Solution 19:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 12

Solution 20:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 13

Solution 21:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 14

Solution 22:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 15

Solution 23:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 16

Solution 24:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 17

PAGE NO : 105
Solution 25:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 18

Solution 26:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 19

Solution 27:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 20

Solution 28:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 21

Solution 29:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 22

Solution 30:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 23

Solution 31:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 24

Solution 1996-1:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 25

Solution 1996-2:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 26

Solution 1996-3:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 27

Solution 1996-4:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 28

PAGE NO : 106
Solution 1997-1:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 29

Solution 1997-2:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 30

Solution 1997-3:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 31

Solution 1997-4:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 32

Solution 1998-1:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 33

Solution 1998-2:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 34

Solution 1999-1:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 35

PAGE NO : 107

Solution 1999-2:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 36

Solution 1999-3:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 37

Solution 2000-2:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 38

Solution 2000-1:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 39

Solution 2000-1:
Gay – Lussac proposed this law.

Solution 2001-2:
Molecular mass of ethane = 30
According to Gay-Lussac’s law:
2 vol. of C2H6 requires= 7 vol. of oxygen
Vol. of C2H6 = 2 vol. = 100 L
Vol. of oxygen required = 7 vol. =350 L

Solution 2001-3:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 40

PAGE NO : 108
Solution 2001-4:
The term is vapour density.

Solution 2001-5:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 41

Solution 2001-6:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 42

Solution 2001-7:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 43

Solution 2002-1:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 44

Solution 2002-2:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 45

Solution 2002-3:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 46

Solution 2003-1:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 47

Solution 2004-1:

Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 48

PAGE NO : 109
Solution 2004-2:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 49

Solution 2005-1:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 50

Solution 2006-1:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 51

Solution 2006-2:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 52

PAGE NO : 110
Solution 2006-3:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 53

Solution 2006-4:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 54

Solution 2007-1:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 55

Solution 2007-2:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 56

Solution 2008-1:
The gas laws which relates the volume of a gas to the number of molecules of the gas is avogadro’s law

PAGE NO : 111
Solution 2008-2:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 57

Solution 2008-3:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 58
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 59

Solution 2009-2:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 60

Solution 2009-3:
The correct statement is that equal volumes of all gases under identical conditions contain the same number of molecules.

Solution 2009-4:
Frank ICSE Solutions for Class 10 Chemistry - Mole Concept And Stoichiometry 61

Solution 2009-1:
The relative molecular mass of the gas is 10.

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