Frank ICSE Class 9 Solutions Archives

Frank ICSE Solutions for Class 9 Physics – Light: Spherical Mirrors

November 10, 2023May 19, 2022 by Veerendra

Frank ICSE Solutions for Class 9 Physics – Light: Spherical Mirrors

PAGE NO: 258
Solution 1:
A spherical mirror is a part of a hollow glass sphere silvered on one side.

Solution 2:
Frank ICSE Solutions for Class 9 Physics - Light Spherical Mirrors 1

Solution 3:
Focal length = 1/2 of radius of curvature
= 1/2 x 30 = 15cm.

Solution 4:
Focal point is the principal focus of the mirror where a parallel beam of light meets(or appear to meet) after reflection from the mirror.

Solution 5:
Frank ICSE Solutions for Class 9 Physics - Light Spherical Mirrors 2

Solution 6:

Pole is the centre of the reflecting surface, in this case spherical mirror.
Centre of curvature is the centre of the imaginary sphere to which the mirror belongs
Aperture is the distance between the extreme points on the periphery of the mirror.
Principal axis is the straight line passing through the pole and the centre of curvature.
The principle focus of a spherical mirror may be defined as a point on its principle axis where a beam of light parallel to the principle axis converges to or appears to diverge from after reflection from the spherical mirror.

Solution 7:
Convex mirror has a wider field of view.

Solution 8:
Concave mirrors are used in reflecting microscope, in shaving and make up glasses and in ophthalmoscope.

Solution 9:
Convex mirrors are used as a rear view mirror in automobiles as it provides a wider view of following traffic.

Solution 10:
Convex mirror is used in vehicles to see the traffic following it.

Solution 11:
The relationship between the focal length, f and radius of curvature, r is
f = 1/2 x r.

Solution 12:
Frank ICSE Solutions for Class 9 Physics - Light Spherical Mirrors 3

Solution 13:
Frank ICSE Solutions for Class 9 Physics - Light Spherical Mirrors 4

Solution 14:
Concave mirror can produce real and diminished image of the object.

Solution 15:
The focal length of plane mirror is infinity.

Solution 16:
The object should be placed between F and P to obtain its magnified and erect image.

Solution 17:
Frank ICSE Solutions for Class 9 Physics - Light Spherical Mirrors 5

Solution 18:
Linear magnification is defined as the ratio of the height of the image to the height of the object. It is taken to be positive for an image to be virtual and erect and negative when image is real and inverted.
Magnification = height of image / height of object.

Solution 19:
SI unit of focal length is meter.

Solution 20:
The top mirror is convex mirror, the middle mirror is concave mirror and bottom mirror is a plane mirror.

Solution 21:
The mirror having +15 cm as its focal length is a convex mirror because focal length is taken positive only in case of convex mirror.

Solution 22:
The mirror having -20 cm as its focal length is a concave mirror because focal length is taken negative only in case of concave mirror.

Solution 23:
When we look into a plane mirror, the image of our face is virtual because the image cannot be obtained on a screen.

Solution 24:
When an object is brought towards the concave mirror, the position of the image moves away from the mirror and the size increases and it remains inverted but at object position between F and P, the image is virtual, magnified and erect.

Solution 25:
Frank ICSE Solutions for Class 9 Physics - Light Spherical Mirrors 6

PAGE NO : 259
Solution 26:
Frank ICSE Solutions for Class 9 Physics - Light Spherical Mirrors 7

Solution 27:
Frank ICSE Solutions for Class 9 Physics - Light Spherical Mirrors 8

Solution 28:
Frank ICSE Solutions for Class 9 Physics - Light Spherical Mirrors 9

Solution 29:
Frank ICSE Solutions for Class 9 Physics - Light Spherical Mirrors 10

Solution 30:
Frank ICSE Solutions for Class 9 Physics - Light Spherical Mirrors 11

Physics Chemistry Biology Maths

Frank ICSE Solutions for Class 9 Biology – Pollination and Fertilization

November 10, 2023May 19, 2022 by Veerendra

Frank ICSE Solutions for Class 9 Biology – Pollination and Fertilization

PAGE NO: 72

Solution 1:
Pollination is the transfer of pollen grains from the anther to the stigma of the same or another flower.
The male gametes are produced inside pollen grains located in the anthers of androecium whereas the female gametes are produced in the ovules located in the ovary of gynoecium. For forming zygote, the male gametes need to be transferred to the gynoecium for fusing with the female gametes. This is achieved through pollination. Pollination occurs through insects, wind or other agents.
There are two types of pollination – Self pollination and cross pollination.

Solution 2:
The two modes of pollination are:

(i) Self-pollination – It is the transfer of pollens produced within the anther of a flower to the stigma of the same flower or to the stigma of another flower of the same plant. In such flowers, pollination is ensured since the flowers bear similar genetic characters. Self pollination can occur in bisexual or monoecious flowers. Examples of plants showing self pollination are Mirabilis, Arachis etc.
(ii) Cross pollination – It is the transfer of pollen grains from the anthers of a flower of one plant to the stigma of a flower of another plant. Cross pollination occurs in unisexual or dioecious flowers such as papaya, maize, jasmine, rose etc.

Solution 3:
Frank ICSE Solutions for Class 9 Biology - Pollination and Fertilization 1

Solution 4:
Adaptations required by self pollinated plants are:

Bisexuality – Self pollination occurs only in bisexual flowers.
Homogamy – Both anther and stigma need to mature at the same time.
Cleistogamy – Flowers which are bisexual and never open are called cleistogamous flowers. They are small, colourless, odourless and without nectar. The pollen grains fall on the stigma inside the closed flower. Example – Arachis

Adaptations required by cross pollinated plants are:

Unisexuality – The stamens and carpels are found in different flowers. The male and female flowers may be borne on the same or different plants.
Dichogamy – In bisexual flowers, stamens and carpels mature at different times.

It is of two kinds:

Protandry wherein stamens mature before carpels. E.g – jasmine
Protogyny wherein carpels mature before stamens. E.g. – Rose

Heterostyly – Here the style is either longer or shorter, thereby preventing self pollination.
Herkogamy – Stigma and stamen mature at the same time, but some type of barrier prevents self pollination. E.g. – In caryophyllaceous flower, the stigma projects beyond the stamens so that pollens cannot fall on it.
Self-sterility – Pollen of one flower cannot fertilize the female gametes of the same flower.

Solution 5:
Frank ICSE Solutions for Class 9 Biology - Pollination and Fertilization 2

Solution 6:
Fertilisation is defined as the fusion of the male and female gametes.

Solution 7:
Frank ICSE Solutions for Class 9 Biology - Pollination and Fertilization 4

Solution 8:
In angiosperms, during fertilization, one male gamete fuses with the egg cell and forms diploid zygote in a process called syngamy. The other male gamete fuses with the two polar nuclei to form a triploid nucleus called primary endosperm nucleus. This process is called triple fusion. Since fertilization takes place twice here, so this process is called double fertilization.
Significance – Due to double fertilization, triploid nucleus develops into endosperm which serves as nutrition for embryo.

Solution 9:
Fruit is a ripened ovary containing one or more seeds.

Solution 10:
After fertilization, ovary undergoes two important changes:

The ovules develop into seeds
The ovary walls thicken and ripen into pericarp or fruit wall.

Solution 11:
Yes, fruits are important for the plant since the seeds mature inside it. Fruits are colourful and tasty and hence eaten by animals. This helps in far and wide dispersal of the seeds.

Solution 12:
(i) (c) entomophily
(ii) (a) bats
(iii) (a) ornithophily
(iv) (a) syngamy
(v) (c) pomology
(vi) (b) true fruits
Biology Chemistry Physics Maths

Frank ICSE Solutions for Class 9 Biology – Interaction Between Biotic and Abiotic Factors in an Ecosystem

November 10, 2023May 18, 2022 by Veerendra

Frank ICSE Solutions for Class 9 Biology – Interaction Between Biotic and Abiotic Factors in an Ecosystem

PAGE NO: 99

Solution 1:
Producers

Solution 2:
Consumers

Solution 3:
The climatic factors affecting ecosystem are sunlight, temperature, humidity, rainfall and wind.

Solution 4:
Low and high temperatures restrict the growth of plants and existence of animal species. Changes in temperature patterns will impact plant life which in turn will influence the animal life, since animals depend directly or indirectly on it for food. During extreme cold and hot conditions, animals either migrate to favourable places, some may hibernate or some may aestivate.

Solution 5:
Consumers which eat only plants are called consumers of the first order. Consumers that eat herbivores like deer, goats, grasshoppers, etc. are called consumers of the second order.

Solution 6:
Deserts have scanty water, either because there is little rainfall, or because the water evaporates very fast in deserts. Desert species are adapted to less amounts of water and they are capable of surviving for long periods of time in the scarcity of water. The growth of plants and animals and their vital functions are dependent on water intake. Hence water is a vital limiting factor in deserts due to the scant availability of this important resource.

Solution 7:
Frank ICSE Solutions for Class 9 Biology - Interaction Between Biotic and Abiotic Factors in an Ecosystem 1

Solution 8:
Frank ICSE Solutions for Class 9 Biology - Interaction Between Biotic and Abiotic Factors in an Ecosystem 2

Solution 9:
Vital atmospheric gases are oxygen, carbon dioxide and nitrogen.
Oxygen availability seldom becomes a limiting factor for land animals unless they live in soil or invade high altitudes. Plants release oxygen into the air which is used by animals for respiration. During respiration, animals release carbon dioxide which is required by plants for photosynthesis. Nitrogen is an essential gas which is vital for the growth and sustenance of organisms.

Solution 10:
In a natural ecosystem, green plants capture solar energy and convert it into chemical forms. The energy is then passed onto herbivores when they feed on green plants. From herbivores, the energy moves into carnivores that eat them. Some animals like lion and vultures are not eaten by other organisms. All the organisms ultimately pass on energy to the decomposers. Energy thus flows continuously through the ecosystem from plant to animals and from prey to predator.

Solution 11:
Energy passes through the ecosystem in a one-way path. Energy goes through each trophic level, one at a time. As it goes from one level to another, it is lost due to metabolism and in the form of heat. For example – The energy ingested by producers is used by the producers for carrying out various life activities and some amount of energy is lost as heat, so that the entire energy does not pass completely to the consumers. The energy lost as heat cannot be used anymore.

Solution 12:
The transfer of energy from autotrophs through a series of organisms that consume and are consumed is known as a food chain.

Solution 13:
The types of food chain are:

Grazing food chain
Detritus food chain
Auxiliary food chain
(Write any two)

Solution 14:
Individual food chains interconnected in a complex way is called food web.

Solution 15:
An energy pyramid is a graphical representation of the flow of energy from the producers through the various consumers. It shows the amount of energy available and the loss of useful energy at each step of the food chain in an ecosystem.

Solution 16:
As the energy gets transferred from lower trophic level to the higher one, there is a loss of large amount of energy due to metabolism and as heat. As a result very little energy (i.e. 10%) gets transferred to the next level. So the trophic level at the base has maximum energy and that at the top has the least amount of energy. Hence energy pyramid is broader at the base and narrower at the top.

Solution 17:
(i)(a) unidirectional
(ii)(d) producers and consumers
(iii)(d) all the above
(iv)(a) photosynthesis
(v)(b) herbivores
(vi)(b) bacteria, fungi, etc.
(vii)(b) Communities and their physical environment
(viii)(d) solar energy
(ix)(d) biotic and abiotic
(x)(d) high temperature and high rain
Biology Chemistry Physics Maths

Frank ICSE Solutions for Class 9 Physics – Light

November 10, 2023May 17, 2022 by Veerendra

Frank ICSE Solutions for Class 9 Physics – Light

PAGE NO: 261
Solution 1:
Convex mirror has a wider field of view.

Solution 2:
Convex mirror always produces an erect image of the object.

Solution 3:
Convex mirror is used in vehicles to see the traffic on rear side.

Solution 4:
We will use convex mirror to see an enlarged image of our face.

Solution 5:
Image of object placed at a long distance in front of a convex mirror is formed at principal focus. Radius of curvature of convex mirror is 20 cm.
Focal length of convex mirror = radius of curvature/2.
Focal length of convex mirror = 20/2 = 10 cm.
So image will form at principal focus 10 cm away from pole.

Solution 6:
Concave mirror can produce real and diminished image of the object.

Solution 7:
The distance of the principal focus from the pole of the mirror is called the focal length of the mirror.

Solution 8:
The mirror having +20 cm as its focal length is a convex mirror because focal length is taken positive only in case of convex mirror.

Solution 9:
The focal length of plane mirror is infinity.

Solution 10:
The mirror having -15 cm as its focal length is a concave mirror because focal length is taken negative only in case of concave mirror.

Solution 11:
Principal axis is the straight line passing through the pole and the centre of curvature.

Solution 12:
Linear magnification is defined as the ratio of the height of the image to the height of the object. It is taken to be positive for an image to be virtual and erect and negative when image is real and inverted.
Magnification = height of image / height of object.

Solution 13:
Pole is the centre of the reflecting surface, in this case spherical mirror.

Solution 14:
Centre of curvature is the centre of the imaginary sphere to which the mirror belongs.

Solution 15:
Three characteristics of light are:-

Light waves can travel through vacuum.
Light waves are transverse waves.
The velocity of light in vacuum is 3 x 10⁸ m/s.

Solution 16:
Three distinctions between light and sound waves are

Light waves can travel through vacuum while sound waves cannot.
Light waves are transverse waves while sound waves are longitudinal waves.
The velocity of light in air is 3 x 10⁸ m/s while the speed of light in air is just about 330 m/s.

Solution 17:

When position of object is at infinity, concave mirror forms a point and Real image at Focus point.
When position of object is beyond C, concave mirror forms a Diminished, Real and inverted image between F and C.
When position of object is at C, concave mirror forms a Magnified, Real and inverted image at C.

Solution 18:
Image formed by a convex mirror is always Diminished, Virtual and Erect.

Solution 19:
Concave mirrors are used in reflecting microscope, in shaving and make up glasses and in ophthalmoscope.

Solution 20:

The distance from the pole in the direction of incident ray is taken positive.
The distance from the pole in the direction opposite to the incident ray is taken negative.

Solution 21:
Mirror formula is the relation between the focal length f of the mirror, the distance u of the object from the pole of the mirror, and the distance v of the image from the pole.
Mirror formula is
1/v +1/u = 1/f.
Linear magnification is defined as the ratio of the height of the image to the height of the object. It is taken to be positive for an image to be virtual and erect and negative when image is real and inverted.
Magnification = height of image / height of object.

Solution 22:
Mirror formula is the relation between the focal length f of the mirror, the distance u of the object from the pole of the mirror, and the distance v of the image from the pole.
Mirror formula is
1/v +1/u = 1/f.
Size of body = 1.5 m.
Magnification of body = 1.5.
Magnification = height of image / height of object.
Height of image = magnification x height of object.
Height of image = 1.5 x 1.5= 2.25 m.

Solution 23:
Linear magnification is defined as the ratio of the height of the image to the height of the object. It is taken to be positive for an image to be virtual and erect and negative when image is real and inverted.
Magnification produced by concave mirror is:
Magnification = height of image / height of object.
It is a pure ratio and does not have any units.

Solution 24:
Frank ICSE Solutions for Class 9 Physics - Light 1

Solution 25:
A smooth and polished surface causes regular reflection while a rough and unpolished surface causes irregular reflection.

Solution 26:
When rays of light fall on a surface, they are turned back into the same medium in accordance with some definite laws. This process is known as reflection.
Reflection obeys following two laws

The incident ray, the reflected ray, and the normal at the point of incidence, all lie in the same plane.
The angle of incidence and the angle of reflection are always equal.

Solution 27:
You can distinguish between plane mirror, a concave mirror, and a convex mirror without touching them. When you look into these mirrors by bringing your face close to each mirror, they will produce an image of your face of different types.

A plane mirror will produce an image of the same size as your face.
A concave mirror will produce a magnified image of your face.
A convex mirror will produce Diminished image of your face.

Solution 28:
You can distinguish between a concave mirror and a convex mirror without touching them. When you look into these mirrors by bringing your face close to each mirror, they will produce an image of your face of different types.

A concave mirror will produce a magnified image of your face.
A convex mirror will produce Diminished image of your face.

PAGE NO : 262
Solution 29:
Frank ICSE Solutions for Class 9 Physics - Light 2

Solution 30:
Uses of concave mirror:

Concave mirrors are used in reflecting microscope
Concave mirrors are used in shaving and make up glasses.
Uses of convex mirror: Convex mirrors are used as a rear view mirror in automobiles as it provides a wider view of following traffic.

Solution 31:
We can see the reflection of our face on a polished table top because a regular reflection occurs in case of a polished surface while on a unpolished table top irregular reflection occurs which make image of our face unclear.

Solution 32:

The angle of incidence is the angle made by the incident ray with the plane mirror. {FALSE}
Correct statement is the angle of incidence is the angle made by the incident ray with the normal to the surface of plane mirror.
If a ray of light incident on a plane mirror is such that it makes an angle of 30° with the normal, then the angle of reflection is 60°.{FALSE}
Correct statement is if a ray of light incident on a plane mirror is such that it makes an angle of 30° with the normal, then the angle of reflection is 30°.
If the incident ray makes an angle of X° with the normal, then the angle between the incident ray and reflected ray is 2X°. {TRUE}
The image formed in a plane mirror is real, erect and same size as that of the object. {FALSE}
Correct statement is the image formed in a plane mirror is virtual, erect and same size as that of the object.

Solution 33:
Frank ICSE Solutions for Class 9 Physics - Light 3

Solution 34:
Frank ICSE Solutions for Class 9 Physics - Light 4

Solution 35:
The image formed by a plane mirror is erect and virtual. It is a laterally inverted image. The image formed is of the same size as that of the object. Also, the image and the object are equidistant from the mirror.

Solution 36:
Frank ICSE Solutions for Class 9 Physics - Light 5

Solution 37:
Given, distance of boy from the mirror = 3 m

Distance of image from mirror = distance of boy from the mirror = 3 m
Distance between boy and his image = distance of boy from the mirror + distance of image from mirror = 3+3 = 6 m
Now, distance of boy from the mirror = 4 m
Distance of image from mirror = 4 m
Distance between boy and his image = distance of boy from the mirror + distance of image from mirror = 4+4 = 8m.

Solution 38:
Periscope is used to see over the top of an obstacle. It is also used in submarines for observing for movement of ships. It can be used from the trenches for observing the movement on the surface of earth.

PAGE NO : 263
Solution 39:
Frank ICSE Solutions for Class 9 Physics - Light 6

Solution 40:

Pole is the centre of the reflecting surface, in this case spherical mirror.
Centre of curvature is the centre of the imaginary sphere to which the mirror belongs
Principal focus of a spherical mirror is a point on the principal axis of the mirror, where all the rays travelling parallel to the principal axis and close to it after reflection from the mirror, converge to or appear to diverge from.
Principal axis is the straight line passing through the pole and the centre of curvature.
Focus of a concave mirror is a point on the principal axis of the mirror, where all the rays travelling parallel to the principal axis and close to it after reflection from the mirror converge to that point.
Normal to the surface of a mirror at any point is the straight line at right angle to the tangent drawn at that point.

Solution 41:
Frank ICSE Solutions for Class 9 Physics - Light 7

Solution 42:
Frank ICSE Solutions for Class 9 Physics - Light 8

Solution 43:
Frank ICSE Solutions for Class 9 Physics - Light 9

Solution 44:
Frank ICSE Solutions for Class 9 Physics - Light 10

Solution 45:
Frank ICSE Solutions for Class 9 Physics - Light 11

Solution 46:
Frank ICSE Solutions for Class 9 Physics - Light 12

PAGE NO : 264
Solution 47:
Frank ICSE Solutions for Class 9 Physics - Light 13

Solution 48:
Frank ICSE Solutions for Class 9 Physics - Light 14

Solution 49:
Frank ICSE Solutions for Class 9 Physics - Light 15

Solution 50:
Frank ICSE Solutions for Class 9 Physics - Light 16

Physics Chemistry Biology Maths

Frank ICSE Solutions for Class 9 Biology – Diversity of Life and Classification

November 10, 2023May 17, 2022 by Veerendra

Frank ICSE Solutions for Class 9 Biology – Diversity of Life and Classification

PAGE NO:117

Solution 1:
Diversity refers to the variety of living organisms found within a given ecosystem, biome, or on an entire planet.

Solution 2:
The method of arranging organisms into series of groups on the basis of similarities and differences is called classification.
Classification is important in the following ways:

It makes the study of a wide variety of organisms easy.
It gives us an overall picture of all the life-forms.
It helps us to understand the interrelationships among different groups of organisms.
It forms a base for the development of other biological sciences.

Solution 3:
Frank ICSE Solutions for Class 9 Biology - Diversity of Life and Classification 1

Solution 4:
Taxonomy is the study of the theory, practice and rules of classification of living and extinct organisms.

Solution 5:
The five kingdom system of classification was proposed by R. H. Whittaker in 1969. This classification is based on the following four facts:

Complexity of cell structure
Methods of nutrition (autotrophic or heterotrophic)
Complexity of body organization.
Phylogenetic relationships.

The five kingdoms in this system are:

Monera – It includes all the prokaryotes like bacteria and cyanobacteria. They are important decomposers.
Protista – It includes the aquatic, eukaryotic, acellular organisms like protozoans.
Fungi – This kingdom includes moulds, mushrooms and yeasts.
Plantae – It includes all the coloured, multicellular, eukaryotes with cell walls.
Animalia – These are multicellular eukaryotes lacking cell wall and showing heterotrophic nutrition.

Solution 6:
Important characters of five kingdom are:
Characters of kingdom Monera are:

It contains acellular organisms, ranging in size between 0.15 to 2.0 .
They are prokaryotes, lacking a well-defined nucleus .
They usually lack chlorophyll and hence are parasites or saprophytes.
Reproduction occurs by binary fission or budding in bacteria.
Example – Actinomycetes, bacteria, cyanobacteria.

Characters of kingdom Protista are:

They are aquatic, unicellular organisms.
They have eukaryotic cells with well-defined nucleus and organelles.
They show autotrophic or heterotrophic mode of nutrition.
Some protists are parasites and few are decomposers too.
Example – Euglena, Ameoba, Paramoecium.

Characters of kingdom Fungi:

They may be unicellular or multicellular.
They have heterotrophic nutrition and mostly they are saprophytes.
Their body is made up of mycelium, a filament of which is called hypha.
Their cell wall is made up of chitin.
Example – Aspergillus, Agaricus, Penicillium.

Characters of kingdom Plantae:

They are multicellular, eukaryotic organisms.
The cell membrane is surrounded by a thick cell wall of cellulose.
Except a few aquatic life forms, plants are non-motile.
They have different modes of nutrition: autotrophic, parasitic even
insectivorous.
Example – Mango, Cycas, Fern, Moss.

Characters of kingdom Animalia:

They are multicellular, eukaryotic organisms without cell wall.
They show heterotrophic mode of nutrition.
They can retract or expand with the help of muscles.
They are consumers in-between producers and decomposers.
Example – Fish, Frog, Earthworm, Man.

Solution 7:
The kingdom Plantae has been divided into following groups:
Thallophyta

They are consists of red, green and brown algae.
Algae are of universal occurrence.
Their body ranges from unicellular to multicellular colonies, filaments or sheets of cells.
Vascular tissues are absent.
Nutrition is generally autotrophic (through photosynthesis).
Reproduction is vegetative or sexual.

Bryophyta

It consists of liverworts and mosses.
They are terrestrial, found in damp, shady places.
Their life cycle has a long gametophytic phase and a short sporophytic phase.
Liverworts have prostrate thalloid gametophytic body, but mosses have erect body.
True roots are absent, but rhizoids presents.
Vascular tissues are absent.
Nutrition is generally autotrophic (through photosynthesis).
Reproduction is vegetative or sexual.

Pteridophyta

They include ferns, horse-tails and club mosses.
They occur mainly in cool, shady and moist places.
They are mostly terrestrial.
They are perennial herbs with stem in the form of rhizome.
Fibrous roots present.
Their life cycle has a gametophytic phase and a short sporophytic phase.
Vascular tissues are present.
Nutrition is generally autotrophic (through photosynthesis).
Reproduction is vegetative or sexual.

Spermatophyta

They are the most successful terrestrial plants having seeds.
They produce seeds (fertilized ovules).
They are divided into two groups –

Gymnosperms -They bear naked seeds and lack flowers.
Examples: Pine, Cycas
Angiosperms – They produce seeds enclosed in ovary and flowers
are present.
Examples: Rose, Grass

Solution 8:
Frank ICSE Solutions for Class 9 Biology - Diversity of Life and Classification 2
Solution 9:

Solution 10:
The various classes of Chordata are:

Pisces – Labeo (Rohu), Scoliodon (Dog fish)
Amphibia – Rana (Frog), Hyla (Tree frog )
Reptilia – Kanchuga (Tortoise), Naja naja ( Cobra)
Aves – Columba (Pigeon), Pavo (Peacock)
Mammalia – Elephas ( Elephant), Funambulas (Squirrel)

Solution 11:
Frank ICSE Solutions for Class 9 Biology - Diversity of Life and Classification 4

Solution 12:
Characters of mammals are:

The females of this class are provided with mammary glands which produces milk to feed the young one.
Body usually covered with hair, spines, scales, nail, hoof or horn.
External ear or pinna is well-developed.
They are warm-blooded.

PAGE NO:118

Solution 13:
(a) Starfish belongs to phylum Echinodermata.
Two characters of starfish are:

Spines found on the body which is covered by calcareous plates.
Body is star shaped with five radiating areas called ambulacra with inter-ambulacra in between.

(b) Whale belongs to phylum Chordata.
Two characters of whale are:

They are warm blooded marine animals.
Heart is completely four-chambered.

(c) Jelly fish belongs to phylum Coelenterata.
Two characters of jelly fish are:

Body diploblastic having outer epidermis and inner gastrodermis with gelatinous mesoglea.
Tentacles are present around the mouth.

(d) Cockroach belongs to phylum Arthropoda.
Two characters of cockroach are:

They have jointed legs.
Their exoskeleton is made up of chitinous cuticle which is shed from time to time.

Solution 14:
Frank ICSE Solutions for Class 9 Biology - Diversity of Life and Classification 5

Solution 15:
Bryophyta – Liverwort and Moss.
Pteridophyta – Fern and Horsetail.

Solution 16:
Antedon (Sea lily) and Asterias (Star fish ).

Solution 17:
Whale

Solution 18:
Cockroach, crab

Solution 19:
Frog

Solution 20:
Echidna

Solution 21:
Earthworm – Pheretima posthuma and
Roundworm – Ascaris

Solution 22:
Frank ICSE Solutions for Class 9 Biology - Diversity of Life and Classification 6

Solution 23:
(a) Arthropoda
(b) Porifera
(c) Mollusca

Solution 24:
(a) Protozoa
(b) Mollusca
(c) Annelida

Solution 25:
(a) Asterias (Star fish ), Echinus (Sea-urchin)
(b) Scoliodon (Dog fish), Labeo (Rohu)
(c) Fasciola ( Liver fluke), Taenia solium (Tapeworm)
(d) Ascaris ( Roundworm), Wuchereria (Filarial worm )
(e) Pheretima (Earthworm), Hirudinaria ( Leech )
(f) Palemon (Prawn), Periplaneta (Cockroach)

Solution 26:
(a) Annelida
(b) Coelenterata
(c) Arthropoda
(d) Echinodermata

Solution 27:
(a) Flame cells
(b) Nemathelminthes
(c) Annelida
(d) Porifera
(e) Chordata

Solution 28:

(a) three pairs of legs are present.
(a) coelentrata
(c) octopus
(c) paramoecium
(c) hippocampus
(a) Scorpion
(b) for five kingdom classification
(a) prokaryotic and multicellular eukaryotic cell
(d) plant
(d) C. Linnaeus
(c) Carolus Linnaeus

Biology Chemistry Physics Maths