Selina Concise Physics Class 7 ICSE Solutions – Energy

Selina Concise Physics Class 7 ICSE Solutions – Energy

ICSE SolutionsSelina ICSE SolutionsML Aggarwal Solutions

APlusTopper.com provides step by step solutions for Selina Concise ICSE Solutions for Class 7 Physics. You can download the Selina Concise Physics ICSE Solutions for Class 7 with Free PDF download option. Selina Publishers Concise Physics for Class 7 ICSE Solutions all questions are solved and explained by expert teachers as per ICSE board guidelines.

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Selina Concise ICSE Solutions for Class 7 Physics Chapter 3 Energy

  • Points to Remember
  •  Work is said to be done if the applied force on the body moves it. If no motion takes place, no work is said to be done.
  •  The amount of work done depends on two factors : (i) on the magnitude of the force applied (greater the force applied, greater is the work done), and (ii) on the distance moved in the direction of force (greater the distance moved, greater is the work done).
  •  The work done by a force on a body is equal to the product of the force and the distance moved by the body in the direction of force, i.e. Work done = Force × distance moved in the direction of force Or W = F × d
  •  The S.I. unit of work is joule (J), where 1 joule (J) = 1 newton (N) × 1 metre (m)
  •  The energy of a body is its capacity (or ability) to do work. The energy of a body in a state is equal to the work done on the body to bring it to that state.
  •  The S.I. unit of energy is joule (J).
  •  Kinetic energy of a body is the energy possessed by it due to its motion. It is the energy stored when work is done to bring the body in motion.
  •  Kinetic energy of a moving body depends on two factors :
    (i) on the mass of the body (greater the mass of the body, greater is its kinetic energy), and (iii) on the speed of the body (more the speed of the body, higher is its kinetic energy).
  •  The potential energy changes into the kinetic energy when it is put to use.
  •  In transformation of energy, the total sum of useful and non-useful energy obtained after conversion is equal to the energy converted, i.e. the total energy remains conserved.
  •  According to the conservation of mechanical energy, if friction is neglected, the total sum of potential energy and kinetic energy remains constant. Examples are : motion of roller coaster, free vertical fall of a body etc.
  •  The electricity obtained from the energy possessed by the flowing water is called the hydro-electricity.

Test Yourself

A. Objective Questions 

1. Write true or false for each statement

(a) A man going up has potential energy and kinetic energy both.
Answer. True.

(b) A gum bottle lying on a table has no energy.
Answer. False.
Correct — A gum bottle lying on a table has energy.

(c) In an electric fan, electrical energy changes into the mechanical energy.
Answer. True.

(d) Potential energy changes into kinetic energy when it is put to use.
Answer. True.

(e) One form of energy cannot be converted into another form.
Answer. False.
Correct — One form of energy can be converted into the other form.

(f) There is always some loss of energy in conversion from one form of energy to another form, so the total energy is not conserved.
Answer. False.
Correct — There is always some loss of energy in conversion from one form of energy to the other form, so the total energy is conserved.

(g) The energy of flowing water can be converted into electric energy (electricity).
Answer. True.

2. Fill in the blanks

(a) An electric fan converts electrical energy into mechanical energy.
(b) Cooking gas converts chemical energy into heat energy.
(c) Energy possessed by a compressed spring is potential energy.
(d) The ability to do work is called energy
(e) The energy possessed by a body due to its position is called potential energy.
(f) The energy possessed by a body due to its motion is called kinetic energy.
(g) Green plants convert light energy into chemical energy.
(h) The S.I.unit of energy is joule
(i) An object falling freely from the roof of a multistory building has potential energy and kinetic energy when halfway down the building.

3. Match the following columns

Selina Concise Physics Class 7 ICSE Solutions Chapter 3 Energy 1

Selina Concise Physics Class 7 ICSE Solutions Chapter 3 Energy 2

4. Select the correct alternatives 

(a) When we rub our hands

  1.  kinetic energy changes into potential energy
  2.  mechanical energy changes into heat energy
  3.  potential energy changes into kinetic energy
  4.  heat energy changes into mechanical energy.

(b) A ball rolling on the ground possesses

  1.  kinetic energy
  2.  potential energy
  3.  no energy
  4.  heat energy

(c) The energy stored in an electric cell is

  1.  chemical energy
  2.  electrical energy
  3.  heat energy
  4.  mechanical energy.

(d) When a bulb lights up on passing current, the change of energy is

  1.  from electrical energy to heat energy
  2.  from electrical energy to light energy
  3.  from electrical energy to heat and light energy
  4.  from electrical energy to mechanical energy.

(e) The correct statement is

  1.  Both work and energy have the same units
  2.  Potential energy of a body is due to its motion
  3.  Kinetic energy of a body is due to its position or state
  4.  Kinetic energy can change into potential energy, but potential energy cannot change into kinetic energy.

(f) According to law of conservation of energy, energy changes from one form to another form, but the total energy of that system

  1.  increases
  2.  decreases
  3.  alternates
  4.  remains the same

B. Short/Long Answer Questions

Question 1.
Define the term energy.
Answer:
Energy is the capacity of doing work.

Question 2.
State the unit of energy and define it.
Answer:
The energy is measured in the same unit as work. Therefore the S.I. unit of energy is joule (symbol J).
A body is said to possess an energy of one joule if a force of 1 newton moves the body by a distance of 1 metre in the direction of force.
Another unit of energy is calorie (symbol cal) where 1 cal = 4.2 J. A bigger unit is kilo-calorie (symbol kcal) where 1 kcal = 1000 cal.

Question 3.
Name five different forms of energy.
Answer:
The different forms of energy are :
(i) Mechanical energy
(ii) Heat energy
(iii) Light energy
(iv) Chemical energy
(v) Sound energy
(vi) Magnetic energy
(vii) Electrical energy and
(viii) Atomic energy or nuclear energy.

Question 4.
What are the two kinds of mechanical energy.
Answer:
The mechanical energy is found in two forms namely :
(a) The potential energy, and (b) The kinetic energy.

Question 5.
What is potential energy ? State its unit.
Answer:
The energy of a body at rest is called the potential energy. It is defined as follows :
Potential energy of a body is the energy possessed by it due to its state of rest or position. Actually, it is the work spent in bringing the body to that state of rest or position.
It is written as P.E. or U.
The S.I. unit of potential energy is Joules.

Question 6.
Give one example of a body that has potential energy, in each of the following : (i) due to its position, (ii) due to its state.
Answer:
(i) Potential energy of a body is the energy possessed by it due to its state of rest or position. It is the energy stored when work is done on the body to bring it to that state or position.
(ii) Potential energy of a body in the raised (or lifted) position depends on two factors : (1) the mass of the body greater the mass of the body, greater is the potential energy of the body), and (2) the height of the body above the ground (greater the height of the body, greater is its potential energy.)

Question 7.
State two factors on which the potential energy of a body at a certain height above the ground depends.
Answer:
The potential energy of a body in the raised position depends upon the following two factors :
(a) The mass of the body: Greater the mass of the body, greater is the potential energy of the body.
(b) Its height above the ground : Higher the height of the body, greater is its potential.

Question 8.
Two bodies A and B of masses 10 kg and 20 kg respectively are at the same height above the ground. Which of the two has the greater potential energy ?
Answer:
The body B having mass 20 kg has the greater potential energy. This can be explained as follows :
P.E. = mgh .
For both the bodies gravity and height are same so the body with greater mass possesses greater potential energy.

Question 9.
A bucket full of water .is on the first floor of your house and another identical bucket with same quantity of water is kept on the second floor. Which of the two has greater potential energy ?
Answer:
A bucket full of water kept on second floor has the greater potential energy. This can be explained as follows :
P.E. = mgh
Mass of both bucket and the gravitational force are same, so the body at greater height will possess more potential energy.

Question 10.
Define the term kinetic energy. Give one example of a body which possesses kinetic energy.
Answer:
The energy of a body in motion is called its kinetic energy. It is defined as follows :
Kinetic energy of a body is the energy possessed by it due to its state of motion.
Actually, it is the work done on the body bringing it to the state of motion. In short form it is written as K.E. or K.
Example : In a swinging pendulum moving to and fro, the bob has the kinetic energy.

Selina Concise Physics Class 7 ICSE Solutions Chapter 3 Energy 3

Question 11.
State two factors on which the kinetic energy of a moving body depends.
Answer:
The kinetic energy of a moving body depends on the following two factors :
(a) The mass of the body — Greater the mass of the body, higher is its kinetic energy.
(b) The speed of the body — More the speed of the body, higher is its kinetic energy.

Question 12.
Two toy-cars A and B of masses 500 g and 200 g respectively are moving with the same speed. Which of the two has the greater kinetic energy?
Answer:
The toy car ‘A’ of mass ‘500 gm’ has the greater kinetic energy. This can be explained as :
K.E. = 1 / 2 Mv2
Here, both the cars are moving with same speed. So the car with greater mass will possess greater kinetic energy.

Question 13.
A cyclist doubles his speed. How will his kinetic energy change: increase, decrease or remain same ?
Answer:
When a cyclist doubles his speed. His kinetic energy increases four times.
K.E. = 1 / 2 Mv2
When v = doubles the K.E. quadriples

Question 14.
Name the form of energy which a wound up watch spring possess.
Answer:
A wound up watch spring has the potential energy because of its wound up state. As the spring unwinds itself, the potential energy changes into the kinetic energy. This kinetic energy does work in moving the arms of the watch

Question 15.
Can a body possess energy even when it is not in motion ? Explain your answer with an example.
Answer:
Yes, a body possesses energy even when it is not in motion ;
Consider a body raised to a certain height say h. It its velocity is zero. Kinetic energy will be zero but the body will have.
P.E. = mgh
Thus, a body may possess energy even though it is not in motion.

Question 16.
Name the type of energy (kinetic or potential) possessed by the following :
(i) A moving cricket ball.
(ii) A stone at rest on the top of a building.
(iii) A compressed spring.
(iv) A moving bus.
(v) A bullet fired from a gun.
(vi) Water flowing in a river.
(vii) A stretched rubber band.
Answer:
(i) Kinetic energy.
(ii) Potential energy.
(iii) Potential energy.
(iv) Kinetic energy.
(v) Kinetic energy.
(vi) Potential energy.
(vii) Potential energy.

Question 17.
Give one example to show the conversion of potential energy to kinetic energy when put in use.
Answer:
The example to show the conversion of potential energy to kinetic energy when put in use is :
A stone at a height has the potential energy due to its lifted or raised position. In the figure below when the stone is dropped from that position, it begins to fall. The falling stone has the kinetic energy. Thus, the potential energy stored in the stone in its raised position changes into the kinetic energy when the stone is falling. This kinetic energy does work on the nail as the stone strikes the nail arid makes the nail to move into the wood.

Selina Concise Physics Class 7 ICSE Solutions Chapter 3 Energy 4
Similarly, in the figure below the potential energy possessed by the stone at a height changes into its kinetic energy when it falls, The kinetic energy of the falling stone does work in raising the weight upwards.

Selina Concise Physics Class 7 ICSE Solutions Chapter 3 Energy 5

Question 18.
State the energy changes that occur in the following :
(i) The unwinding of a watch spring.
(ii) Burning coal while operating a steam engine.
(iii) Lighting of a torch bulb.
(iv) An electric generator (or dynamo).
Answer:
(i) Potential energy to kinetic energy.
(ii) Chemical energy of coal changes to heat energy of the steam. Heat energy changes into mechanical energy.
(iii) Chemical energy into light and heat energy.
(iv) Electrical energy change into mechanical energy.

Question 19.
Energy can exist in several forms and may change from one form to another. Give two examples to show the conversion of energy from one form to another.
Answer:
The examples that show the conversion of energy from one form to another are :
(1) In a steam engine, the chemical energy of the coal first changes into the heat energy of the steam. Then heat jenergy of steam changes into the mechanical energy which makes the train to move.
(2) In an electric motor (or in fan), the electrical energy changes into the mechanical energy. This energy rotates the axle of motor (or the blades of the fan).

Question 20.
Give one relevant example for each of the following transformation of energy :
(i) Electrical energy to heat energy.
(ii) Electrical energy to mechanical energy.
(iii) Electrical energy to light energy.
(iv) Chemical energy to heat energy.
(v) Chemical energy to light energy.
Answer:
(i) In an electric heater, oven, geyser, toaster etc., the electrical energy changes into heat energy.
(ii) An electric generator.
(iii) Tube eight of bulbs.
(iv) Burning of wood, coal etc.
(v) Fire crackers burst

Question 21.
What do you mean by conservation of mechanical energy? State the condition when does it hold.
Answer:
This means “The total MECHANICAL ENERGY (P.E + K.E) of an isolated system at any instant is equal to the sum of kinetic ENERGY and the potential ENERGY.”
Condition : Condition under which the mechanical energy is conserved is “WHEN THERE ARE NO FRICTIONAL FORCES.” In other words the mechanical energy is conserved strictly in vacuum where friction due to air is absent.

Selina Concise Physics Class 7 ICSE Solutions Chapter 3 Energy 6

Question 22.
Give one example to show that the sum of potential energy and kinetic energy remains constant if friction is ignored.
Answer:
During the vertical fall of ball, if friction due to air is neglected, the total sum of potential energy and kinetic energy at each point of its path remains same.

Question 23.
A ball is made to fall freely from a height. State the kind/ kinds of energy possessed by the ball when it is
(a) at the highest point
(b) just in the middle
(c) at the ground.
Answer:
(a) Potential energy.
(b) Potential energy + Kinetic energy.
(c) Kinetic energy.

Question 24.
State the changes in form of energy while producing hydro electricity.
Answer:
The water in motion in a river or sea has the kinetic energy. The energy possessed by the flowing water is called the hydro energy. The most important use of hydro energy is to produce electricity from it.

Selina Concise Physics Class 7 ICSE Solutions Chapter 3 Energy 7
Figure shows the principle of a hydroelectric power plant. The flowing water of river is collected in a dam at a high altitude. The water stored in the dam has the potential energy. When water from dam falls on the water turbine, the potential energy of the water stored in dam changes into its kinetic energy and this kinetic energy of water is transferred to the blades of turbine as the kinetic energy which rotates the turbine. As the turbine rotates, it rotates the armature of the generator (or dynamo) to produce electricity.

 

 

Selina Concise Physics Class 7 ICSE Solutions – Sound

Selina Concise Physics Class 7 ICSE Solutions – Sound

ICSE SolutionsSelina ICSE SolutionsML Aggarwal Solutions

APlusTopper.com provides step by step solutions for Selina Concise ICSE Solutions for Class 7 Physics. You can download the Selina Concise Physics ICSE Solutions for Class 7 with Free PDF download option. Selina Publishers Concise Physics for Class 7 ICSE Solutions all questions are solved and explained by expert teachers as per ICSE board guidelines.

Selina Class 7 Physics ICSE SolutionsChemistryBiologyMathsGeographyHistory & Civics

Selina Concise ICSE Solutions for Class 7 Physics Chapter 6 Sound

  • Points to Remember
  •  Sound is a form of energy which produces the sensation of hearing.
  •  Sound requires a medium to travel. It cannot travel in vacuum.
  •  Sound travels in all directions. Sound can travel through solids, liquids and gases.
  •  Sound travels faster in solids than in liquids and gases.
  •  The loudness of sound is measured on a special scale called the decibel scale.
  •  Sound is classified into two groups. (i) Musical sound, (ii) Noise.
  •  Musical sound is produced by periodic vibrations.
  •  Noise is produced by non-periodic motions.
  •  What the sound gets repeated after reflection from a distant body, is called an echo.
  •  Multiple echoes are called reverberations.
  •  Sonar is method used to measure the depth of a sea and is based on the principle of echo.
  •  Music is pleasent to hear and is caused by periodic vibrations.
  •  Noise is irritating and is produced by an irregular pattern of waves.
  •  The three characteristics of sound are loudness, pitch, quality or timbre.
  •  Loudness depends upon many factors, e.g. amplitude, distance, waves of vibrating body, humidity, pressure, wind velocity etc.
  •  Pitch depends on the frequency of sound. Higher is the pitch, shriller is the sound.
  •  Loudness is merely a sensation.

Test Yourself

A. Objective Questions 

1. Write true or false for each statement

(a) Sound can travel in vacuum.
Answer. False.
Correct — Sound requires medium to travel.

(b) Sound is a form of energy.
Answer. True.

(c) Sound can only be produced by vibrating bodies.
Answer. True.

(d) Larger is the amplitude, feeble is the sound.
Answer.False.
Correct — Larger the amplitude, greater is the sound.

(e) The frequency is measured in hertz.
Answer. True.

(f) Loudness depends on frequency.
Answer. False.
Correct — Loudness depends on the amplitude.

(g) Waveforms of two different stringed instruments can be the same.
Answer. False.
Correct—Waveforms of two different stringed instruments cannot be the same.

(h) Female voice is shriller than the male voice.
Answer. True.

(i) A ticking clock sound is heard late when heard through a metal.
Answer. False.
Correct—A ticking clock sounds is heard early when heard through a metal.

2. Fill in the blanks

(a) Sound is produced when a body vibrates.
(b) The number of times a body vibrates in one second is called its frequency.
(c) The pitch of a sound depends on its frequency.
(d) Sound can travel in a medium solid, liquid or gas.
(e) We can hear sounds of frequency in the range of 20 Hz to 20,000 Hz.
(f) Sound requires a medium for propagation.
(g) Sound travels faster in solids than in liquids.
(h) The sound heard after reflection is echo.
(i) Sound produces sensation in ears.

3. Match the following

Selina Concise Physics Class 7 ICSE Solutions Chapter 6 Sound 1

4. Select the correct alternative 

(a) We can distinguish a shrill sound from a flat sound by its

  1.  amplitude
  2.  loudness
  3.  pitch
  4.  none of the above.

(b) We can hear sound of frequency

  1.  10 Hz
  2.  500 Hz
  3.  100,000 Hz
  4.  50,000 Hz

(c) Sound cannot travel in

  1.  gases
  2.  liquids
  3.  solids
  4.  vacuum

(d) The minimum distance required between the source and the reflector so as to hear the echo in air is

  1.  10 m
  2. 17 m
  3.  34 m
  4.  50 m

(e) Wavelength is measured in

  1.  kg
  2.  second
  3.  litre
  4. metre

(f) The speed of sound in water is

  1.  332 m
  2. 1500 m
  3.  5000 m s
  4.  1000 m s

(g) Sound travels the fastest in

  1.  liquids
  2.  solids
  3.  gases
  4.  vacuum

B. Short/Long Answer Questions

Question 1.
What do you mean by a vibratory motion ?
Answer:
The oscillatory motion in which the body assumes a new shape during its motion, is called the vibratory motion.

Question 2.
What is sound ?
Answer:
Sound is a form of energy which produces the sensation of hearing.

Question 3.
How is sound produced ?
Answer:
Sound is produced by vibrating bodies.

Question 4.
Describe an experiment to show that each source of sound is a vibrating body.
Answer:
Sound is produced when a body vibrates. In other words, each source of sound is a vibrating body. This can be demonstrated by the following experiment.
Take a ruler. Press its one end on the table with the left hand as shown in figure. Pull down the other end of the ruler with the right hand and then leave it.
You will notice that the ruler vibrates i.e., the ruler moves to and fro and a humming sound is heard.
After some time, the ruler stops vibrating. No sound is then heard.

Selina Concise Physics Class 7 ICSE Solutions Chapter 6 Sound 2
This shows that the humming sound is produced only because of the vibrations of the ruler.

Question 5.
Name two sources of sound.
Answer:
Each vibrating body is a source of sound. We, the human beings, produce sound when our vocal cords vibrate on blowing air through them by our lungs. Some animals like birds, frogs etc., also produce sound due to vibration of their vocal cords. But bees do not have the voice-boxes. They produce sound by moving their wings up and down very fast.

Question 6.
How do we produce sound ?
Answer:
Our throat has a larynx. The voice is produced in the larynx. Larynx is also called the voice box. It is designed to produce voice. It is a box like structure with walls of tough tissues. Inside two folds of the tissue, there is a gap. They are the vocal cords. When we breathe, the vocal cords become loose and the gap between them increases. When we talk, shout or sing, the cords become tight and hence they vibrate, thus produce sound. Given figure shows the part of the body which vibrates to produce sound.

Selina Concise Physics Class 7 ICSE Solutions Chapter 6 Sound 3

Question 7.
The bees do not have voice-boxes. How do they produce sound ?
Answer:
The bees do not have the voice-boxes. Still they produce sound.
This happens by the vibrations produced by the quick movement of their wings. Bees buzz while flying and depositing pollen among flowers.

Question 8.
Can sound travel through a vacuum ? Describe an experiment to explain your answer.
Answer:
Experiment — Arrange an electric bell, a glass bell jar, a vacuum pump, a battery and a switch as shown in the figure. When the circuit is closed by pressing the switch, the bell starts ringing and sound can be heard. Now remove the air from the jar with the help of vacuum pump. The loudness of the sound gradually decreases and a stage comes when no sound is heard. Sound requires a medium to travel but cannot travel in vacuum.

Selina Concise Physics Class 7 ICSE Solutions Chapter 6 Sound 4
Connect the bell to a battery through a switch. On pressing the switch, the bell starts ringing and a sound is heard. The sound reaches us through the air in the jar.
Now start the vacuum pump. It withdraws the air from the jar. You will notice that as the jar is evacuated, the sound becomes feeble and feeble. After some time when no air is left within the jar, no sound is heard. However, the hammer of the electric bell can be still seen striking the gong. The reason is that when no air is left in the jar, the sound does not reach us, although the bell is still ringing (or vibrating).
Thus, sound cannot travel through a vacuum.

Question 9.
Describe an experiment to show that sound can travel in water.
Answer:
Take a tub filled with water. Hold a bell in one hand and dip it in water. Keep one of your ears gently on the surface of water without letting water into the ear. Now ring the bell inside water. You will be able to hear the sound clearly. This shows that sound can travel through liquids.

Question 10.
Describe an experiment to show that sound can travel in a solid.
Answer:
Take two empty ice-cream cups. Make a small hole at the bottom of each cup and pass a long thread (about 20 m long) through them. Tie a knot or match-stick at each end of the thread so that the thread does not slip out through the holes. This makes a toy – telephone

Selina Concise Physics Class 7 ICSE Solutions Chapter 6 Sound 5
Now use the toy-telephone as shown in figure and talk to your friend. You will be able to hear the sound of your friend. This shows that sound travels through the thread and reaches your ear. Thus, sound can travel through a solid.

Question 11.
Can two person hear each other on moon’s surface ? Give reason to support your answer.
Answer:
No, we cannot hear each other since sound requires medium for transmission. It cannot travel through vacuum.

Question 12.
What is a longitudinal wave ?
Answer:
In a longitudinal wave, the particles of air vibrate to and fro about their mean positions in the direction of travel of sound.

Question 13.
Define the following terms :
Amplitude, Time period, Frequency.
Answer:

Selina Concise Physics Class 7 ICSE Solutions Chapter 6 Sound 6
(a) Amplitude (A) : The maximum displacement of a wave on either side of its mean position is called Amplitude. A = XY is amplitude.
(b) Time Period (T) : Time taken to complete one vibration is called Time Period, i.e. from A to B

Selina Concise Physics Class 7 ICSE Solutions Chapter 6 Sound 7
(c) Frequency (f) or u
Number of oscillations made by a wave in one second is known as its frequency.

Question 14.
Write the audible range of frequency for the normal human ear.
Answer:
The range of frequency from 20 Hz to 20,000 Hz is called the audible range for the normal human ear.

Question 15.
What are ultrasonics ? Can you hear the ultrasonic sound ?
Answer:
Sounds of frequency higher than 20,000 Hz are called the ultrasonics. We cannot hear the ultrasonic sounds.

Question 16.
What are infrasonics ? Can you hear them ?
Answer:
Sounds of frequency lower than 20 Hz are called the infrasonics. We cannot hear the infrasonic sounds.

Question 17.
How does a bat make use of ultrasonics waves to find its way?
Answer:
Use of ultrasonics by bats : Bats have no eyes. But they easily move about without colliding with any object (or obstacle). The reason is that they produce ultrasonic sound as they fly. When this ultrasonic sound comes back after reflection from any object (or obstacle) in their way, they hear it and thus they detect the presence of the object (or obstacle).

Question 18.
Name the two characteristics of sound which differentiate two sounds from each other.
Answer:
A sound wave is characterized by its amplitude and frequency. Depending upon the (amplitude and frequency of the sound wave, the following two characteristics of sound :
(1) Loudness, and (2) Pitch.

Question 19.
On what factor does the loudness of a sound depend ?
Answer:
The loudness of a sound depends on the amplitude of vibration of the vibrating body producing the sound.

Question 20.
How does the loudness of sound produced depend on the vibrating area of the body ?
Answer:
The loudness of sound also depends on the area of the vibrating body. Greater the area of the vibrating body, louder is the sound produced.
If you take two drums, one small and the other big, and beat both of them to produce vibrations in them, We will notice that the sound produced from the big drum is louder than that produced from the small drum. In temples, you must have noticed that the bell with a big case produces a louder sound than that with a small case.

Question 21.
The outer case of the bell in a temple is made big. Give a reason.
Answer:
The outer case of the bell in a temple is made big. So that there is multiple reflection of sound and the sound can be amplified.

Question 22.
State the factors on which the pitch of a sound depends.
Answer:
The pitch of a sound depends on its frequency (i.c., on the frequency of the vibrating body).

Question 23.
Differentiate between a high pitch sound and a low pitch sound.
Answer:
Higher the pitch, the shriller is the sound. Lower the pitch, the flat (or grave) is the sound.

Question 24.
How does a man’s voice differ from a woman’s voice ?
Answer:
A female voice is shriller than a male voice because of higher frequency. Higher is the frequency, shriller is the sound. Female has higher frequency.

Question 25.
Name the characteristic which differentiates two sounds of the same pitch and same loudness.
Answer:
The quality is the characteristic of sound which distinguishes the two sounds of the same pitch and same loudness.

Question 26.
You recognize your friend by hearing his voice on a telephone. Explain.
Answer:
We can recognize our friend by hearing his voice on a telephone due to quality of sound and pitch of sound.

Question 27.
A musician recognizes the musical instrument by hearing the sound produced by it, even without seeing the instrument. Which characteristic of sound makes this possible ?
Answer:
It is the pitch and quality that helps a musician recognize the musical instrument by hearing the sound produced by it, even without seeing the instrument.

Question 28.
Describe an experiment to show the production of sound having low and high pitch.
Answer:
Take few rubber bands some thicker and longer, few thinner and of shorter length. Cut and stretch these rubber bands by holding one end of the string in your mouth under the teeth and the other end in your hand. Now pluck these rubber bands one by one. The rubber bands thicker and longer will produce sound with a lower pitch. The rubber bands thinner and shorter will produce sound with a higher pitch.

Question 29.
How does a musician playing on a flute change the pitch of sound produced by it ?
Answer:
In musical instruments like flute and clarinet, the pitch of sound is changed by changing the length of vibrating air column when different holes in it are closed.

Question 30.
Why are musical instruments provided with more than one string ?
Answer:
The stringed instruments are provided with a number of strings of different thickness and under different tensions so that each string produces sound of a different pitch.

Question 31.
How can the pitch of sound produced in a piano be changed ?
Answer:
In a piano, the string is struck to make the string vibrate and produce sound. The pitch of sound produced can be changed by stretching or loosening the strings of piano.

Question 32.
Explain why you can predict the arrival of a train by placing your ear on the rails without seeing it.
Answer:
The sound produced by the moving wheels of train travels much faster through the track than through the air. Therefore they hear through the track much before it is heard through the – air.

Question 33.
Write the approximate speed of sound in (i) air, (ii) water and (iii) steel.
Answer:

Selina Concise Physics Class 7 ICSE Solutions Chapter 6 Sound 8

Question 34.
During a thunderstorm, the sound of a thunder is heard after the lightning is seen. Why ?
Answer:
The velocity of light is 3 × 10m/s whereas velocity of sound is 332 m/s. First we see the flash of light and then we hear the thunder.

Question 35.
Describe an experiment to estimate the speed of sound in air.
Answer:
To estimate the speed of sound in air suppose we choose two  hills A and B about a kilometer apart. A person at the hill A fires  a gun. Another person at the hill B starts a stop watch as he sees the flash of the fire and stops it on hearing the sound. Thus, he measures the time interval between the seeing of flash and hearing of the sound. Let it be t second. Then measure the distance between the hills A and B. Let it be S metre.

Selina Concise Physics Class 7 ICSE Solutions Chapter 6 Sound 9
Experimentally, it is found that the speed of sound in air is nearly 330 m s-1

Question 36.
Can sound travel through solids and liquids ? In which of these two does it travel faster ?
Answer:
Sound travels with highest speed in — solids.
and Sound travels with lowest speed in — gases.

Question 37.
What do you mean by reflection of sound ?
Answer:
Reflection of Sound— When a sound wave strikes a rigid surface, it retraces from its path is called reflection of sound.

Question 38.
State one use of reflection of sound.
Answer:
The reflection of sound is used in making the speaking tube (or megaphone), sound board and trumpet.

Question 39.
What is echo ?
Answer:
Echo is the sound heard after reflection from a rigid surface such as a cliff, a hillside, the wall of a building etc.

Question 40.
What minimum distance is required between the source of sound and the reflecting surface to hear an echo ? Give reason.
Answer:
Since sound has to travel an equal distance in going up to the reflecting surface and in coming back from the reflecting surface, therefore it must travel nearly 33/2 = 16.5 m either way. Thus, to hear the echo clearly in air, the reflecting surface should be at a minimum distance of 16.5 m from the source of sound.

Question 41.
List four substances which are good absorbers of sound.
Answer:
When sound falls on sofa, fluffs and light substances such as clothes, papers, thermocol, coating of plaster of paris, carpets, curtains, furniture, wood etc., they absorb the sound to a good extent. These are called good absorbers of sound.

Question 42.
List the measures that you will take when designing a sound-proof room.
Answer:
In order to design such a sound proof room we take the following measures
(1) The roof of the enclosure must be covered by plaster of paris after putting the sheets of thermocol.
(2) The walls of the enclosure should be covered by the wooden strips.
(3) The floor must be laid down by thick carpets.
(4) The machine parts of all the electrical equipments such as fan, air conditioner etc. must be placed outside the enclosure.
(5) Thick curtains should be used to cover the doors and keep them closed.
(6) Thick stripping must be used to cover the openings of doors and windows.

C. Numericals

Question 1.
A boy fires a gun and another boy at a distance of 1020 m hears the sound of firing the gun 3 s after seeing its smoke. Find the speed of sound.
Answer:

Selina Concise Physics Class 7 ICSE Solutions Chapter 6 Sound 10

Question 2.
A boy on a hill A fires a gun. The other boy on hill B hears the sound after 4 s. If the speed of sound is 330 ms-1, find the distance between the two hills.
Answer:
Speed, v = 330 ms-1
t = 4s
Distances = v × t
= 330 × 4s = 1320 m Ans.

Selina Concise Chemistry Class 7 ICSE Solutions – Language of Chemistry

Selina Concise Chemistry Class 7 ICSE Solutions – Language of Chemistry

ICSE SolutionsSelina ICSE SolutionsML Aggarwal Solutions

APlusTopper.com provides step by step solutions for Selina Concise ICSE Solutions for Class 7 Chemistry. You can download the Selina Concise Chemistry ICSE Solutions for Class 7 with Free PDF download option. Selina Publishers Concise Chemistry for Class 7 ICSE Solutions all questions are solved and explained by expert teachers as per ICSE board guidelines.

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Selina Concise ICSE Solutions for Class 7 Chemistry Chapter 5 Language of Chemistry

Points to Remember :

  1. A chemical reaction involves the transformation of original substance into an altogether new substance(s).
  2. A chemical reaction can be represented with the help of the symbols or the formulae of the elements and the compounds taking part in that reaction. This gives a chemical equation.
  3. Certain necessary conditions for a chemical reaction to happen are  close contact, solution form, heat, light and catalyst.
  4. Characteristics of chemical reactions are change of colour, evolution of a gas, formation of a precipitate, change of state, change of smell and evolution/absorption of heat.
  5. A complete chemical equation symbolically represents the reactants, products and their physical states.
  6. The substances that react with each other are called reactants and they are represented on the left hand side of the equation. The substances that are formed as a result of the reaction are called products. They are represented on the right hand side of the equation.
  7. A chemical equation needs to be balanced to make it follow the law of the conservation of mass.
  8. The law of conservation of mass states that mass can be neither created nor destroyed, it can only be transformed from one form to another.
  9. A chemical equation gives both qualitative and quantitative information about the reactants and products.

EXERCISE

Question 1.
(a) Define chemical reaction.
(b) What is a chemical equation?
(c) Why do we need to balance chemical equations?
Answer:
(a) Chemical reaction : Any chemical change in matter which involves its transformation into one or more new substances is called a chemical reaction.
(b) Chemical equation : A chemical equation is the symbolic representation of a chemical reaction using the symbols and the formula of the substances involved in the reaction.
(c) A chemical equation needs to be balanced so as to make the number of the atoms of the reactants equal to the number of the atoms of the products.

Question 2.
State four conditions necessary for chemical reactions to take place.
Answer:
Conditions necessary for chemical reactions :

  1. Close contact
  2. Solution form
  3. Heat
  4. Light
  5. Catalyst

3. Differentiate between :
(a) Reactants and products.

ReactantsProducts
  1. The substances that react with one another are called reactants.
  2. Reactants are written on the left hand side of equation.
  1. The new substances formed are called products.
  2. Products are written on the right hand side of equation.

(b) Chemical reaction and chemical equation.

Chemical reactionChemical Equation
Any chemical change in matter which involves its transformation into one or more new substances is called a chemical reaction.A chemical equation is the symbolic representation of a chemical reaction using the symbols and the formula of the substances involved in the reaction.

(c) A balanced and a skeletal chemical equation.

Balanced Equation

Skeletal Equation

A balanced chemical equation is one in which the number of atoms each element on the reactant side is equal to the number of atoms of that element on the product side.

In a skeletal equation the number of atoms on reactant side are not equal to number of atoms of product side.

Question 4.
Write word equations for the following skeletal equations:
(a) KClO3  KCl + O2
(b) Zn + HCl → ZnCl2 + H2
(c)FeCl2 + Cl2 → FeCl3
(d) CO + O2 → CO2
(e) Ca + O2 → CaO
(f) Na + O2 →  Na2O
(g) NaOH + H2SO4 → Na2SO4 + H2O
(h) AgBr →  Ag + Br2
(i) KNO2 →   KNO2 + O2

Answer:
(a) 2KClO3    2KCl+ 3O2
(b) Zn + 2HCl    →   ZnCl2 + H2
(c) 2FeCl2 + Cl →  2FeCl3
(d) 2CO + O2      2CO2
(e) 2Ca + O2   2CaO
(f) 4Na + O2    2Na2O
(g) 2NaOH + H2SO4    Na2SO4 + 2H2O
(h) 2AgBr      2Ag + Br2
(i) 2KNO3    2KN02 + O2

Question 5.
Balance the following chemical equations :
(a) FeS + HCl   FeCl2 + H2S
(b) Na2CO3 + HCl  →  NaCI + H2O + CO2
(c) H2 + O2   →  H2O
(d) Na20 + H2  NaOH
Answer:
(a) FeS + 2HCl      FeCl2 + H2S
(b) Na2CO3 + 2HCl    2NaCl + H2O + CO2
(c) 2H2+ O2        2H2O
(d) Na2O + H2O      2NaOH

Question 6.
What information do you get from the equation H2+ Cl2  →  2HCl ?
Answer:
(a)Hydrogen and chlorine molecules are the reactants.
(b)They are in gaseous form.
(c)The product is hydrogen chloride gas.
(d)Two molecules of hydrogen chloride are formed.

Question 7.
Write your observations for the following chemical reactions and name the products formed :
(a) When sugar is heated.
(b) When manganese dioxide is added to potassium chlorate and heated.
(c) When dilute acetic acid is poured on baking soda.
(d) When an aqueous solution of sodium chloride is mixed with an aqueous solution of silver nitrate.
(e) When ammonium chloride is heated with sodium hydroxide.
(f) When water is added to quick lime?

Answer:
(a) Black solid mass (charcoal) is formed along with water vapours.
(b) Manganese dioxide acts as a catalyst for the decomposition of potassium chlorate into potassium chloride and oxygen at a lower temperature.
(c) Sodium acetate, COand water is formed.
(d) A white insoluble solid precipitate of silver chloride is formed along with Sodium nitrate.
(e) When solid ammonium chloride is heated with sodium hydroxide solution, a gas ammonia is evolved which is recognised by its strong pungent smell.
Selina Concise Chemistry Class 7 ICSE Solutions - Language of Chemistry-7
(f) When water is added to quick lime, a large amount of heat energy is evolved.
Selina Concise Chemistry Class 7 ICSE Solutions - Language of Chemistry-7f
Question 8.
Write symbolic representation for the following word equations and balance them :
(a) Calcium carbonate → Calcium oxide + Carbon dioxide
(b) Carbon + Oxygen → Carbon dioxide
(c) Calcium oxide + Water → Calcium hydroxide
(d) Aluminium + Chlorine → Aluminium chloride
(e) Iron + Sulphur → Iron sulphide

Answer:

Selina Concise Chemistry Class 7 ICSE Solutions - Language of Chemistry-8

OBJECTIVE TYPE QUESTIONS

1. Fill in the blanks:
(a) The substances which undergo chemical change are called reactants.
(b)
The substances formed as a result of a chemical reaction are called products.
(c)
During a chemical reaction transfer of energy takes place.
(d) The basic conditions necessary for a chemical reaction is close contact.
(e)
In some chemical reactions an insoluble precipitate is formed when two solutions are mixed.

2. Write ‘true’ or ‘false’ for the following statements :
(a) No new substance is formed during a chemical reaction : True
(b)
Hydrogen sulphide has rotten egg smell : True
(c)
When potassium iodide solution is added to lead acetate solution a red precipitate is formed : False
(d)
A black residue is formed when sugar is heated : True
(e)
When iron and sulphur are heated together a grey mass is formed which is attracted by a magnet : False
(f)
A chemical equation gives only qualitative information of a chemical reaction : False

MULTIPLE CHOICE QUESTIONS

1. A chemical equation is a statement that describes a chemical change in terms of
(a) symbols and formulae
(b) energy
(c) number of atoms
(d) colours

2. Balancing a chemical equation is based on
(a) Law of conservation of mass
(b) Mass of reactants and products
(c) Symbols and formulae
(d) None of the above

3. Copper carbonate when heated, it turns :
(a) Blue
(b) Green
(c) Black
(d) Yellow

 

Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions

Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions (Decimals)

Selina Publishers Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions(Decimals)

ICSE SolutionsSelina ICSE SolutionsML Aggarwal Solutions

APlusTopper.com provides step by step solutions for Selina Concise ICSE Solutions for Class 7 Mathematics. You can download the Selina Concise Mathematics ICSE Solutions for Class 7 with Free PDF download option. Selina Publishers Concise Mathematics for Class 7 ICSE Solutions all questions are solved and explained by expert mathematic teachers as per ICSE board guidelines.

Selina Class 7 Maths ICSE SolutionsPhysicsChemistryBiologyGeographyHistory & Civics

POINTS TO REMEMBER

  1. Decimal fraction (or a decimal number)
    A decimal fraction is a fraction whose denominator is 10 or a higher power of 10.
    In order to express a given decimal fraction in shorter form, the denominator is not written but its absence is shown by a dot which is called a decimal point inserted in a proper place.
    Note :
    (i) When there is no number is the left of the decimal point, generally, a zero is written.
    (ii) Generally, a decimal fraction has two parts, the first part which is on the right ox the decimal point is called decimal part and the part on the left side of the decimal point, is called integeral part.
    (iii) The decimal part is always less than 1.
  2. Reading Decimal Numbers
    The integral part is read according to its value and the decimal part is read by naming each digit, in order, separately
  3. Converting a decimal number into a vulgar fraction :
    Remove the decimal point from the decimal number and write in its denominator with as many zeros as the number of digits are in the decimal parts to the right of 1.
    In the decimal number, the name of each place is given as under is the place value chart:

    ThousandsHundredsTensUnitsTenthsHundredthsThousandth
        Decimal point  and so on
  4. Converting a given fraction in to a decimal fraction :
    (a) When the denominator in given fraction is 10. 100, 1000 etc., then count from extreme right to left, mark decimal point after as many digits of the numerator as there are zeroes in the denominator.
    (b) When the denominator of the given number is other then 10 or higher power of 10, then divide in an ordinary way and mark the decimal point in the quotient just after the division of unit digit is completed. After this, any number of zeroes can be borrowed to.complete the division.
    Note : The number of figures that follow the decimal part is called the number of decimal places.
  5. Addition and Subtraction of decimal numbers.
    (a) Addition : Write the given decimal numbers in such a way, that the decimal points of all the numbers fall in the same vertical line. Digits with the same place value are placed one below the other units are written below units, tens below tens and so on.
    Addition is started from the right side, as done in the usual addition (empty places may be filled up by zeroes). In the result (total), the decimal point is placed under decimal points of the numbers added.
    (b) Subtraction : In subtraction also, the numbers are written in such a way that their decimals are in ihe same vertical line. Digits with the same place value are placed one below the other (empty places may be filled by zeroes).
    Subtraction is started from the right side, as in the case of normal subtraction. In the result, decimal point is placed just under the other decimal points.
  6. Multiplication of decimal numbers :
    (1) Multiplication by 10,100, 1000 etc. shift the decimal point, in the multiplicand, to the right by as many digits as there are zeroes in the multiplier.
    (2) Multiplication by a whole number : Multiply in an ordinary way, without considering the decimal point. In the product, the decimal point should be fixed by counting as many digits from the right as there are decimal places in the multiplicand.
    Thus, (i) 0.3 x 6 = 1.8 (ii) 0.26 x 18 = 4.68 and so on.
    (3) Multiplication of a decimal number by another decimal number :
    Multiply the two numbers in a normal way, ignoring their decimals. In the product, decimal point is fixed counting from right, the digits equal to the sum of decimal places in the multiplicand and the multiplier.
    Thus, 32.5 x ().()7 = 2.275
    Since, the multiplicand (32.5) has one decimal place and multiplier (0.07) has two decimal places, their product will have 1+2 = 3 decimal places.
  7. Division of decimal numbers :
    (1) Division by 10, 100, 1000 etc : Shift the decimal points to the left as many digits as there are
    zeroes in the divisor. .
    (2) Division by a whole number : Divide in the normal manner, ignoring the decimal, and mark tire decimal point; in the quotient, while just crossing over the decimal point in the dividend.
  8. Recurring Decimals :
    On performing a division, sometimes we find that the same remainder is left, no matter how long we continue the division process. For this reason, the same digit appeares again and again in the quotient. This fact is shown by puting a dot as a bar over the repeating digits.
  9. Rounding off of decimal numbers :
    (i) If the answer required is correct to two decimal places, we retain digits upto three decimal places.
    (ii) If the digit in the third decimal place is five or more than five, then the digit in the second decimal place is increased by one and, if the digit in the third decimal place is less than five, then the digit in the second decimal place is not altered.
    (iii)The third digit which was retained is now omitted.
    Thus, for getting 8.4813 correct to two decimal places.
    Write the given number upto three decimal places i.e. 8.481.
    Since, the digit in the third decimal place is 1 which is less than 5.
    ∴The digit in the second decimal place is not altered.
    And, so 8.4813 = 8.48, correct to two decimal places.
    In the same way, to get 3.946824 correct to nearest thousandths i.e., correct to three decimal places, first write it as 3.9468.
    Then according to the rule, the digit in the third place changes from 6 to 7.
    3.9468 = 3.947, correct to three decimal places.

Decimal Fractions Exercise 4A – Selina Concise Mathematics Class 7 ICSE Solutions

Question 1.
Convert the following into fractions in their lowest terms :
(i) 3.75
(ii) 0.5
(iii) 2.04
(iv) 0.65
(v) 2.405
(vi) 0.085
(vii) 8.025

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 1

Question 2.
Convert into decimal fractions
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 2

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 4
Question 3.
Write the number of decimal places in :
(i) 0.4762
(ii) 7.00349
(iii) 8235.403
(iv) 35.4
(v) 2.608
(vi) 0.000879

Answer:
(i) In 0.4762, there are four places.
(ii) In 7.00349, there are five places.
(iii) In 8235.403, there are three places.
(iv) In 35.4, there is one place.
(v) In 2.608, there are three places.
(vi) In 0.000879, there are six places.

Question 4.
Write the following decimals as word statements :
(i) 0.4,0.9,0.1
(ii) 1.9, 4.4, 7.5
(iii) 0.02, 0.56, 13.06
(iv) 0.005,0.207, 111.519
(v) 0.8, 0.08, 0.008, 0.0008
(vi)256.1, 10.22, 0.634

Answer:
(i) 0.4 = zero point four, 0.9 = zero point nine, 0.1 = zero point one.
(ii) 1 .9 = one point nine, 4.4 = four point four, 7.5 = seven point five.
(iii) 0.02 = zero point zero two, 0.56 = zero point five six, 13.06 = thirteen point zero six.
(iv) 0.005 = zero point zero zero five, 0.207 = zero point two zero seven, 111.519 = one hundred eleven point five one nine.
(v) 0.8 = zero point eight, 0.08 = zero point zero eight, 0.008 = zero point zero zero eight, 0.0008 = zero point zero zero zero eight
(vi) 256.1 = Two hundred fifty six point one, 10.22 = Ten point two two, 0.634 = zero point six three four.

Question 5.
Convert the given fractions into like fractions:
(i) 0.5,3.62,43.987 and 232.0037
(ii) 215.78, 33.0006, 530.3 and 0.03569

Answer:
(i) 0.5, 3.62, 43.987 and 232.0037
In these decimals, the greatest places of decimal is 4
∴0.5 = 0.5000
3.62 = 3.6200
43.987 = 43.9870
232.0037 = 232.0037

(ii) 215.78, 33.0006, 530.3 and 0.03569
In these decimals, the greatest places of decimal is 5
∴215.78 = 215.78000
33.0006 = 33.00060
530.3 = 530.30000
0.03569 = 0.03569

Decimal Fractions Exercise 4B – Selina Concise Mathematics Class 7 ICSE Solutions

Question 1.
Add:
(i) 0.5 and 0.37 (ii) 3.8 and 8.7
(iii) 0.02, 0.008 and 0.309
(iv) 0. 4136, 0. 3195 and 0.52
(v) 9.25, 3.4 and 6.666
(vi) 3.007, 0.587 and 18.341
(vii) 0.2, 0.02 and 2.0002
(viii) 6. 08, 60.8, 0.608 and 0.0608
(ix) 29.03, 0.0003, 0.3 and 7.2
(x) 3.4, 2.025, 9.36 and 3.6221

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 5
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 6
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 7

Question 2.
Subtract the first! number from the second :
(i) 5.4, 9.8
(ii) 0.16, 4.3
(iii) 0.82, 8.6
(v) 2.237, 9.425
(vi) 41 .03, 59.46
(vii) 3.92. 26.86
(viii) 4.73, 8.5
(ix) 12.63, 36.2
(x) 0.845, 3.71

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 8
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 9

Question 3.
Simplify :
(i) 28.796 -13.42 – 2.555
(ii) 93.354 – 62.82 – 13.045
(iii) 36 – 18.59 – 3.2
(iv) 86 + 16.95 – 3.0042
(v) 32.8 – 13 – 10.725 +3.517
(vi) 4000 – 30.51 – 753.101 – 69.43
(vii) 0.1835 + 163.2005 – 25.9 – 100
(viii) 38.00 – 30 + 200.200 – 0.230
(ix) 555.555 + 55.555 – 5.55 – 0.555

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 10
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 11
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 12
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 13

Question 4.
Find the difference between 6.85 and 0.685.
Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 14

Question 5.
Take out the sum of 19.38 and 56.025 then subtract it from 200. 111.
Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 15

Question 6.
Add 13.95 and 1.003 ; and from the result, subtract the sum of 2.794 and 6.2.
Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 16
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 17

Question 7.
What should be added to 39.587 to give 80.375 ?

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 18

Question 8.
What should be subtracted from 100 to give 19.29?
Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 19

Question 9.
What is the excess of 584.29 over 213.95 ?
Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 20

Question 10.
Evaluate:
(i) (5.4 – 0.8) + (2.97 -1.462)
(ii) (6.25 + 0.36) -(17.2 – 8.97)
(iii) 9.004 + (3 -2.462)
(iv) 879.4 – (87.94 – 8 .794)

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 21

Question 11.
What is the excess of 75 over 48.29?
Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 22

Question 12.
If A = 237.98 and B = 83.47.
Find :
(i) A – B
(ii) B – A.
Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 23

Question 13.
The cost of one kg of sugar increases from ?28.47 to T32.65. Find the increase in cost.

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 24

Decimal Fractions Exercise 4C – Selina Concise Mathematics Class 7 ICSE Solutions

Question 1.
Multiply:
(i) 0.87 by 10
(ii) 2.948 by 100
(iii) 6.4 by 1000
(iv) 5.8 by 4
(v) 16.32 by 28
(vi) 5. 037 by 8
(vi) 4.6 by 2.1
(viii) 0.568 by 6.4

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 25

Question 2.
Multiply each number by 10, 100, 1000 :
(i) 0.5
(ii) 0.112
(iii) 4.8
(iv) 0.0359
(v) 16.27
(vi) 234.8

Answer:
(i) 0.5 x 10 = 5,0.5 x 100 = 50,
0.5 x 1000 = 500
(ii) 0.112 x 10= 1.12,0.112 x 100
= 11.2, 0.112 x 1000= 112
(iii) 4.8 x 10 = 48, 4.8 x 100 = 480,
4.8 x 1000 = 4800
(iv) 0.0359 x 10 = 0.359,0.0359 x 100 = 3.59, 0.0359 x 1000 = 35-9
(v) 16.27 x 10 = 162.7, 16.27 x 100 = 1627, 16.27 x 1000= 16270
(vi) 234.8 x 10 = 2348, 234.8 x 100 = 23480, 234.8 x 1000 = 234800

Question 3.
Evaluate:
(i) 5.897 x 2.3
(ii) 0.894 x 87
(iii) 0.01 x 0.001
(iv) 0.84 x 2.2 x 4
(v) 4.75 x 0.08 x 3
(vi) 2.4 x 3.5 x 4.8
(vii) 0.8 x 1.2 x 0.25
(viii) 0.3 x 0.03 x 0.003
(ix) 12.003 x (0.2)5

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 26
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 27

Question 4.
Divide :
(i) 54.9 by 10
(ii) 7.8 by 100
(iii) 324.76 by 1000
(iv) 12.8 by 4
(v) 27.918 by 9
(vi) 4.672 by 8
(vii) 4.32 by 1.2
(viii) 7.644 by 1.4
(ix) 4.8432 by 0.08

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 28
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 29
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 30

Question 5.
Divide each of the given numbers by 10, 100, 1000 and 10000
(i) 2.1
(ii) 8.64
(iii) 5-01
(iv) 0.0906
(v) 0.125
(vi) 111.11
(vii) 0.848 x 3
(viii)4.906 x (0.2) ²
(ix) (1.2)² x(0.9)²

Answer:

(i) 2.1 ÷ 10 = 0.21, 2.1 ÷ 100 = 0.021,
2.1 ÷ 1000 = 0.0021
and 2.1 ÷10000 = 0.00021

(ii) 8.64 ÷ 10 = 0-864, 8.64 ÷ 100 = 0-0864,
8.64 ÷ 1000 = 0-00864
and 8.64 ÷ 10000 = 0.000864

(iii)5.01 ÷ 10 = 0.501,
5.01 ÷ 100 = 0.0501,
5.01 ÷1000 = 0.00501,
5.01 ÷ 10000 = 0.000501

(iv) 0.0906 ÷ 10 = 0.00906,
0.0906 ÷ 100 = 0.000906,
0.0906 ÷ 1000 = 0.0090906,
0.0906 ÷ 10000 = 0.00000906

(v) 0.125
Now 0.125 + 10 = 0.0125,
0.125 ÷ 100 = 0-00125,
0.125 ÷1000 = 0.000125,
0.125 ÷ 10000 = 0.0000125

(vi) 111.11÷ 10= 11.111,
111.11÷ 100 = 1.1111,
111.11 ÷ 1000 = 0.11111,
111.11 ÷ 10000 = 0.011111

(vii) 0.848 x 3 = 2.544 ,
Now 2.544 ÷ 10 = 0.2544,
2.544 ÷ 100 = 0-02544,
2-544 ÷ 1000 = 0-002544,
2-544 ÷ 10000 = 0-0002544

(viii) 4.906 x (0.2)² = 4.906 x 0.2 x 0.2
= 4.906 x 0.04 = 0.19624
Now 0.19624 + 10 = 0.019624,
0.19624 + 100 = 0.0019624,
0.19624 + 1000 = 0.00019624,
0.19624 + 10000 = 0.000019624

(ix) (1.2)² x (0.9)² = 1.2 x 1.2 x 0.9 x 0.9 = 1.44 x 0.81 = 1.1664
Now 1 .1664 + 10 = 0.11664,
1.1664 ÷ 100 = 0.011664,
1.1664 ÷ 1000 = 0.0011664,
1.1664 ÷ 10000 = 0.00011664

Question 6.
Evaluate :
(i) 9.75 + 5
(ii) 4.4064 + 4
(iii) 27.69 + 30
(iv) 19.25 + 25
(v) 20.64+ 16
(vi) 3.204 + 9
(vii) 0.125 + 25
(viii) 0.14616 + 72
(ix) 0.6227+ 1300
(x) 257.894+ 0-169
(xi) 6.3 + (0.3)²

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 31
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 32
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 33
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 34

Question 7.
Evaluate:
(i) 4.3 x 0.52 x 0.3
(ii) 3.2 x 2.5 x 0.7
(iii) 0.8 x 1.5 x 0.6
(iv) 0.3 x 0.3 x 0.3
(v) 1.2 x 1.2 x 0.4
(vi) 0.4 x 0.04 x 0.004
(vii) 0.5 x 0.6 x 0.7
(Viii) 0.5 x 0.06 x 0.007

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 35
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 36
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 37
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 38
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 39
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 40

Question 8.
Evaluate:
(i) (0.9)²
(ii) (0.6)² x 0.5
(iii) 0.3 x (0.5)²
(iv) (0.4)³
(v) (0.2)3 x 5
(vi) (0.2)3 x 0.05

Answer:

(i) (0.9)2
⇒ 0.9 x 0.9 = 0.81
(Sum of decimal places 1 + 1=2)

(ii) (0.6)2 x 0.5
⇒ 0.6 x 0.6 x 0.5
⇒ 0.36 x 0.5 = 0.180 or 0.18
(Sum of decimal places = 1 + 1 + 1 = 3)

(iii) 0.3 x (0.5)2
⇒ 0.3 x 0.5 x 0.5
⇒ 0.3 x 0.25 = 0.075
(Sum of decimal places 1 + 1 + 1 = 3)
(iv) (0.4)3
⇒ 0.4 x 0.4 x 0.4
⇒ 0.16 x 0.4 = 0.064
(Sum of decimal places 1 + 1 + 1 = 3)

(v) (0.2)3 x 5
⇒ 0.2 x 0.2 x 0.2 x 5
⇒ 0.08 x 5 = 0.40 or 0.4
(Sum of decimal places 1 + 1 + 1 = 3)

(vi) (0.2)3 x 0.05
⇒ 0.2 x 0.2 x 0.2 x 0.05
⇒ 0.008 x 0.05 = 0.00040
(Sum of decimal places = 5)

 Question 9.
Find the cost of 36.75 kg wheat at the rate of ₹12.80 per kg.
Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 41

Question 10.
The cost of a pen is ₹56.15. Find the cost of 16 such pens.
Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 42

Question 11.
Evaluate:
(i) 0.0072 ÷ 0.06
(ii) 0.621 ÷ 0.3
(iii) 0.0532 ÷ 0.005
(iv) 0.01162 ÷ 0.14
(v) (7.5 x 40.4) ÷ 25
(vi) 2.1 ÷ (0.1 x 0.1)

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 43
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 44

Question 12.
Fifteen indentical articles weigh 31.50 kg. Find the weight of each article.
Answer:
Weight of 15 articles = 31.50 kg
∴ Weight of one article
= 31.50- 15 = 2.1 kg

Question 13.
The product of two numbers is 211.2. If one of these two numbers is 16.5, find the other number.
Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 45

Question 14.
One dozen identical articles cost ₹45.96. Find the cost of each article.
Answer:
∴ Weight of one dozen articles = ₹45.96
One dozen = 12
∴ Cost of one article = 45.96 + 12 = ₹3.83

Decimal Fractions Exercise 4D – Selina Concise Mathematics Class 7 ICSE Solutions

Question 1.
Find whether the given division forms a terminating decimal or a non-terminating decimal:
(i) 3 ÷ 8
(ii)8 ÷ 3
(iii) 6÷ 5
(iv) 5 ÷ 6
(v) 12.5 ÷ 4
(vi) 23 ÷ 0.7
(vii) 42 ÷ 9
(viii) 0.56÷ 0.11

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 46
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 47
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 48
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 49
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 50

Question 2.
Express as recurring decimals :
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 51

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 52
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 53
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 54
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 55
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 56
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 57

Question 3.
Convert into vulgar fraction :
(i) 0.\(\bar { 3 }\)
(ii) 0.\(\bar { 8 }\)
(iii) 4.\(\bar { 4 }\)
(iv) 23.\(\bar { 7 }\)

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 58
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 59

Question 4.
Convert into vulgar fraction :
(i) 0.\(\bar { 35 }\)
(ii) 2.\(\bar { 23 }\)
(iii) 1.\(\bar { 28 }\)
(iv) 5.\(\bar { 234 }\)

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 60

Question 5.
Convert into vulgar fraction :
(i) 0 0.3\(\bar { 7 }\)
(ii) 0.2\(\bar { 45 }\)
(iii) 0.68\(\bar { 5 }\)
(iv) 0.4\(\bar { 42 }\)

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 61
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 62

Decimal Fractions Exercise 4E – Selina Concise Mathematics Class 7 ICSE Solutions

Question 1.
Round off:
(i) 0 .07, 0.112, 3.59, 9.489 to the nearest tenths.
(ii) 0.627, 100.479, 0 065 and 0.024 to the nearest hundredths.
(iii) 4.83,0.86,451 .943 and 9.08 to the nearest whole number.

Answer:
(i) 0.07 = 0.1,
0.112 = 0.1
3 . 59 = 3.6, 9.489 = 9.5
(ii) 0.627 = 0.63,
100.479 = 100.48
0.065 = 0.07,
0.024 = 0.02
(iii) 4.83 = 5,
0.86= 1,
451.943 = 452
9.08 = 9

Question 2.
Simplify, and write your answers correct to the nearest hundredths :
(i) 18 .35 x 1.2
(ii) 62.89 x 0.02

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 63

Question 3.
Write the number of significant figures (digits) in:
(i) 35.06
(ii) 0.35
(iii) 7.0068
(iv) 19 .0
(v) 0.0062
(vi) 0 4.2 x 0.6
(vii) 0.08 x 25
(viii) 3.6 ÷ 0.12 .

Answer:
(i) 35.06 : In this significant figures i.e. digits are 4
(ii) In 0.35, significant figures are 2
(iii) In 7.0068, significant figures are 5
(iv) In 19.0, significant figures are 3
(v) In 0.0062, significant figures are 2
(vi) In 4.2 x 0.6 = 2.52, significant figure are 3
(vii) In 008 x 25 = 2.00 = 2 significant figure is 1
(viii) In 3.6 ÷0 .12 or 360 ÷ 12 = 30, significant figure are 2.

Question 4.
Write :
(i) 35.869,0 008426,4.952 and 382.7, correct lo three significant figures.
(ii) 60.974. 2.8753, 0.001789 and 400.04, correct to four significant figures.
(iii) 14.29462, 19.2, 46356.82 and 69, correct to five significant figures.

Answer:
(i) Correct to three significant figures are
35.869 → 35.9
0.008426 →0.00843
4. 952→ 4.95
382.7 →383
(ii) Correct to four significant figures
60.974 →60.97
2. 8753 → 2.875
0.001789 → 0.001789
400.04 → 400.0
(iii) Correct to five significant figures
14.29462→ 14.295
19.2 → 19.200
46356.82 →46357
69 → 69.000

Decimal Fractions Exercise 4F – Selina Concise Mathematics Class 7 ICSE Solutions

Question 1.
The weight of an object is 3 .06 kg. Find the total weight of 48 similar objects.
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 64

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 65

Question 2.
Find die cost of 17.5 m cloth at the rate of Rs. 112.50 per metre.

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 66

Question 3.
One kilogramme of oil costs Rs. 73.40. Find the cost of 9.75 kilogramme of the oil.

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 67

Question 4.
Total weight of 8 identical objects is 51.2 kg. Find the weight of each object.
Answer:
Weight of 8 objects = 51-2 kg
∴ Weight of 1 object = 51 -2 + 8 kg = 6-4 kg Ans.

Question 5.
18.5 m of cloth costs Rs. 666. Find the cost of 3.8 m cloth.

Answer:
Cost of 18.5 m cloth = Rs. 666
Cost of 1 m cloth = Rs. 666 ÷18.5 and cost of 3.8 m cloth
= Rs. (666 ÷18.5) x 3-8 = Rs. (6660 ÷ 185) x 3.8 = Rs. 36 x 3.8 = Rs. 136.80
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 68

Question 6.
Find die value of:
(i) 0.5 of Rs. 7.60 + 1.62 of Rs. 30
(ii) 2.3 of 7.3 kg + 0.9 of 0.48 kg
(iii) 6.25 of 8.4 – 4.7 of 3.24
(iv) 0.98 of 235 – 0 .09 of 3.2

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 69

Question 7.
Evaluate:
(i) 5.6 – 1 .5 of 3.4
(ii) 4.8 ÷ 0.04 of 5
(iii) 0.72 of 80 + 0.2
(iv) 0.72 ÷ 80 of 0.2
(v) 6.45 + (3.9 – 1.75)
(vi) 0.12 of(0.104 – 0.02)+ 0.36 x 0.5

Answer:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 4 Decimal Fractions image - 70

 

Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers

Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers

Selina Publishers Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers

ICSE SolutionsSelina ICSE SolutionsML Aggarwal Solutions

APlusTopper.com provides step by step solutions for Selina Concise ICSE Solutions for Class 7 Mathematics. You can download the Selina Concise Mathematics ICSE Solutions for Class 7 with Free PDF download option. Selina Publishers Concise Mathematics for Class 7 ICSE Solutions all questions are solved and explained by expert mathematic teachers as per ICSE board guidelines.

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EXERCISE 2 (A)

Question 1.
Write down a rational number whose numerator is the largest number of two digits and denominator is the smallest number of four digits.

Solution:
Largest two digit = 99
Smallest, number of four digit = 1000 Now numerator = 99 and denominator = 1000
∴ Rational number = \(\frac { 99 }{ 1000 }\)

Question 2.
Write the numerator of each of the following rational numbers:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 1

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 2
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 3

Question 3.
Write the denominator of each of the following rational numbers:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 4

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 5

Question 4.
Write down a rational number numerator (-5) x (-4) and denominator (28 – 27) x (8 – 5).

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 6

Question 5.
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 7

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 8

Question 6.
Separate positive and negative rational numbers from the following :
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 9
Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 10
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 11

Question 7.
Find three rational numbers equivalent to
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 12

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 13
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 14

Question 8.
Which of the following are not rational numbers :
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 15

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 16

Question 9.
Express each of the following integers as a rational number with denominator 7 :
(i) 5
(ii) -8
(iii) 0
(iv) -16
(v) 7

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 17
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 18

Question 10.
Express \(\frac { 3 }{ 5 }\) as a rational number with denominator:

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 19

Question 11.
Express \(\frac { 4 }{ 7 }\) as a rational number with numerator :

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 20

Question 12.
Find x, such that:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 21

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 22
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 23
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 24
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 25

Question 13.
Express each of the following rational numbers to the lowest terms :
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 26

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 27
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 28

Question 14.
Express each of the following rational numbers in the standard form.
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 29

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 30
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 31

EXERCISE 2 (B)

Question 1.
Mark the following pairs of rational numbers on the separate number lines :
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 32

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 33
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 34

Question 2.
Compare:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 35

Solution:

Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 37
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 38
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 39

Question 3.
Compare:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 40

Solution:
v
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 42
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 43
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 44

Question 4.
Arrange the given rational numbers in ascending order :
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 45

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 46
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 47

Question 5.
Arrange the given rational numbers in descending order:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 48

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 49
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 50

Question 6.
Fill in the blanks :
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 51

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 52
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 53

EXERCISE 2 (C)

Question 1.
Add:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 54

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 55
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 56

Question 2.
Add:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 57

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 58
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 59
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 60
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 61
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 62
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 63

Question 3.
Evaluate:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 64

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 65
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 66
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 67

Question 4.
Evaluate:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 68

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 69
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 70
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 71

Question 5.
Subtract :
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 72

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 73
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 74

Question 6.
Subtract :
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 75

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 76
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 77
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 78
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 79

Question 7.
The sum of two rational numbers is \(\frac { 11 }{ 24 }\). If one of them is \(\frac { 3 }{ 8 }\), find the other.

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 80

Question 8.
The sum of two rational numbers is \(\frac { -7 }{ 11 }\). If one of them is \(\frac { 13 }{ 24 }\), find the other.

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 81

Question 9.
The sum of two rational numbers is -4. If one of them is \(-\frac { 13 }{ 12 }\) , find the other.

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 82

Question 10.
What should be added to \(-\frac { 3 }{ 6 }\) to get \(-\frac { 11 }{ 24 }\) ?

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 83
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 84

Question 11.
What should be added to \(\frac { -3 }{ 5 }\) to get 2?

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 85

Question 12.
What should be subtracted from \(\frac { -4 }{ 5 }\) to get 1?

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 86
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 87

Question 13.
The sum of two numbers is \(-\frac { 6 }{ 5 }\). If one of them is -2, find the other.

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 88

Question 14.
What should be added to \(\frac { -7 }{ 12 }\) to get \(\frac { 3 }{ 8 }\)?

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 89

Question 15.
What should be subtracted from \(\frac { 5 }{ 9 }\)to get \(\frac { 9 }{ 5 }\) ?

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 90

EXERCISE 2 (D)

Question 1.
Evaluate:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 91

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 92
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 93
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 94

Question 2.
Multiply:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 95

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 96
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 97
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 98
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 99

Question 3.
Evaluate:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 100
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 101

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 102
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 103
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 104
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 105
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 106

Question 4.
Find the cost of 3 \(\frac { 1 }{ 2 }\) m cloth, if one metre cloth costs ₹325 \(\frac { 1 }{ 2 }\).

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 107

Question 5.
A bus is moving with a speed of 65 \(\frac { 1 }{ 2 }\) km per hour. How much distance will it cover in 1 \(\frac { 1 }{ 3 }\) hours.

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 108

Question 6.
Divide:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 109

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 110
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 111

Question 7.
Evaluate:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 112

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 113
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 114
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 115

Question 8.
The product of two numbers is 14. If one of the numbers is \(\frac { -8 }{ 7 }\), find the other.

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 116

Question 9.
The cost of 11 pens is ₹3 \(\frac { 2 }{ 3 }\). Find the cost of one pen.

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 117

Question 10.
If 6 identical articles can be bought for ₹2 \(\frac { 6 }{ 17 }\). Find the cost of each article.

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 118

Question 11.
By what number should \(\frac { -3 }{ 8 }\) be multiplied so that the product is \(\frac { -9 }{ 16 }\) ?

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 119

Question 12.
By what number should \(\frac { -5 }{ 7 }\) be divided so -15 that the result is\(\frac { -15 }{ 28 }\) ?

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 120

Question 13.
Evaluate :
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 121

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 122

Question 14.
Seven equal piece are made out of a rope 5 of 21 \(\frac { 5 }{ 7 }\) m. Find the length of each piece.

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 123

EXERCISE 2 (E)

Question 1.
Evaluate:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 124

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 125
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 126
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 127
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 128
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 129
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 131
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 132
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 133

Question 2.
The sum of two rational numbers is \(\frac { -3 }{ 8 }\). If one of them is \(\frac { 3 }{ 16 }\), find the other,

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 134

Question 3.
The sum of two rational numbers is -5. If one of them is \(\frac { -52 }{ 25 }\) , find the other.

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 135

Question 4.
What rational number should be added to \(-\frac { 3 }{ 16 }\) to get \(\frac { 11 }{ 24 }\)

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 136
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 137

Question 5.
What rational number should be added to \(-\frac { 3 }{ 5 }\) to get 2?

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 138

Question 6.
What rational number should be subtracted from \(-\frac { 5 }{ 12 }\)to get \(\frac { 5 }{ 24 }\)

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 139

Question 7.
What rational number should be subtracted from \(\frac { 5 }{ 8 }\) to get \(\frac { 8 }{ 5 }\) ?

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 140

Question 8.
Evaluate:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 141

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 142
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 143
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 144
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 145
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 146

Question 9.
The product of two rational numbers is 24. If one of them is \(-\frac { 36}{ 11 }\), find the other.

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 147

Question 10.
By what rational number should we multiply \(\frac { 20 }{ -9 }\) ,so that the product may be \(\frac { -5 }{ 9 }\) ?

Solution:
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 2 Rational Numbers image - 148