What are Laws of Exponents?

What are Laws of Exponents?

Laws of Exponents

Law-1:
If a is any non-zero integer and m and n are whole numbers, then

am × an = am + n

Eg :
What are Laws of Exponents 1
Therefore, in general, we write,
What are Laws of Exponents 2

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Law-2:
If a and b are non-zero integers and m is a positive integer, then

am × bm = (a × b)m

Eg :
53 × 33 = (5 × 5 × 5) × (3 × 3 × 3)
= (5 × 3) × (5 × 3) × (5 × 3)
= 15 × 15 × 15 = (15)3
So, 53 × 33 = (5 × 3)3 = (15)3
Here, we find that 15 is the product of bases 5 and 3.
Also, if a and b are non-zero integers, then
a5 × b5 = (a × a × a × a × a) × (b × b × b × b × b)
= (a × b) (a × b) (a × b) (a × b) (a × b) = (ab)5

Law-3:
If a is a non-zero integer and m and n are two whole numbers such that m > n, then
What are Laws of Exponents 3What are Laws of Exponents 4When an exponential form is divided by another exponential form whose bases are same, then the resultant is an exponential form with same base but the exponent is the difference of the exponent of the divisor from the exponent of the dividend.

Law-4:
Division of exponential forms with the same exponents and different base:
If a and b are any two non-zero integers, have same exponent m then for am ÷ bm, we write
What are Laws of Exponents 5
Law-5:
If ‘a’ be any non-zero integer and m and n any two positive integers then

[(a)m]n = amn

Eg :
(22)3 = 22 × 22 × 22 = 22 + 2 +2 = 26 = 22 × 3
(27)2 = 27 × 27 = 27 +7 = 214 = 27 × 2

Law-6:
Law of zero Exponent:
We know that
What are Laws of Exponents 6
By using Law-3 of exponents, we have
26 ÷ 26 = 26–6 = 20
Thus, 20 = 1
In general am ÷ am = am – m = a0 and also
What are Laws of Exponents 7
Hence, a= 1
Any non-zero integer raised to the power 0 always results into 1.

Use Of Exponents In Expressing Large Numbers

We know that
100 = 10 × 10 = 102,
1000 = 10 × 10 × 10 = 103,
10000 = 10 × 10 × 10 × 10 = 104
We can write a number followed by large number of zeroes in powers of 10.
For example, we can write the speed of light in vacuum = 300,000,000 m/s
= 3 × 1,00,000,000 m/s = 3 × 108 m/s
= 30 × 107 m/s = 300 × 106 m/s
Similarly,
the age of universe = 8,000,000,000 years (app.)
= 8 × 109 years (app.)
We can also express the age of universe as
80 × 108 years or 800 × 107 years, etc.
But generally the number which preceded the power of 10 should be less than 10. Such a notation is called standard or scientific notation.
So 8 × 109 years is the standard form of the age of the universe.
Similarly, the standard form of the speed of light is 3 × 108 m/s.

Eg: Write the following numbers in standard form :
(i) 4340000
(ii) 173000
(iii) 140000
Solution:
(i)   It is clear that 4340000 = 434 × 10000
Also, 4340000 = 4.34 × 106
∵  434 = 4.34 × 100 = 4.34 × 102
(ii) Also, 173000 = 1.73 × 105
(iii) Also, 140000 = 1.4 × 105

Laws of Exponents Problems with Solutions

1. Write in exponential form :
(i)   (5 × 7)            (ii)   (–7n)5
Solution:
(i) (5 × 7)6
= (5 × 7) (5 × 7) (5 × 7) (5 × 7)  (5 × 7) (5 × 7)
= (5 × 5 × 5 × 5 × 5 ×  5) ( 7 × 7 × 7 × 7 × 7 × 7) =  56 × 76
Hence, (5 × 7)6 = 56 × 76
(ii) (–7n)5 = (–7n) (–7n) (–7n) (–7n) (–7n)
= (–7 × – 7 × – 7 × – 7 × –7) (n × n × n × n × n)
= (–7)5 × (n)5

2. Write the following in expanded form :
What are Laws of Exponents 8
Solution:
What are Laws of Exponents 9

3. Find the value of :
(i) (30 – 20) × 50
(ii) 20 × 30 × 40
(iii) (60 – 20) × (60 + 20)
Solution:
(i) We have, (30 – 20) × 50
Therefore, (1 – 1) × 1 = 0 × 1 = 0
[Since 30 =1 , 20 = 1]
(ii) We have, 20 × 30 × 40 = (1 × 1 × 1) = 1
(iii) We have, (60 – 20) × (60 + 20)
= (1 – 1) × (1 + 1)
= 0 × 2 = 0.

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