# Selina Concise Mathematics Class 6 ICSE Solutions Chapter 14 Fractions

## Selina Concise Mathematics Class 6 ICSE Solutions Chapter 14 Fractions

Selina Publishers Concise Mathematics Class 6 ICSE Solutions Chapter 14 Fractions

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### Fractions Exercise 14A – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
For each expression, given below, write a fraction :
(i) 2 out of 7 = ………..
(ii) 5 out of 17 = ………..
(iii) three-fifths = ………
Solution:
(i) 2 out of 7 = $$\frac { 2 }{ 7 }$$
(ii) 5 out of 17 = $$\frac { 5 }{ 17 }$$
(iii) three-fifths = $$\frac { 3 }{ 5 }$$

Question 2.
Fill in the blanks :

Solution:
(i) Proper
(ii) Improper
(iii) Improper
(iv) 1
(v) -1
(vi) Mixed
(vii) Like
(viii) Unlike fraction
(ix) Equal fraction
(x) Like

Question 3.
From the following fractions, separate :
(i) Proper fractions
(ii)Improper fractions :

Solution:
We know that proper fraction is a fraction whose numerator is less than its denominator and improper fraction is the fraction whose numerator is greater them its denominator :

Question 4.
Change the following mixed fractions to improper fractions :

Solution:

Question 5.
Change the following improper fractions to mixed fractions :

Solution:

Question 6.
Change the following groups of fractions to like fractions :

Solution:

### Fractions Exercise 14B – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
Reduce the given fractions to their lowest terms :

Solution:

Question 2.
State, whether true or false ?

Solution:

Question 3.
Which fraction is greater ?

Solution:

Question 4.
Which fraction is smaller ?

Solution:

Question 5.
Arrange the given fractions in descending order of magnitude :

Solution:

Question 6.
Arrange the given fractions in ascending order of magnitude :

Solution:

Question 7.
I bought one dozen bananas and ate five of them. What fraction of the total number of bananas was left ?
Solution:
Number of bananas bought = 1
Dozen = 12
Number of bananas eaten by me = 5
Number of bananas left = 12 – 5 = 7
Fraction = $$\frac { 7 }{ 12 }$$

Question 8.
Insert the symbol ‘=’ or ‘>’ or ‘<’ between each of the pairs of fractions, given below :

Solution:

Question 9.
Out of 50 identical articles, 36 are broken. Find the fraction of :
(i) The total number of articles and the articles broken.
(ii) The remaining articles and total number of articles.
Solution:
Total number of articles = 50
Number of articles broken = 36
Remaining articles = 50 – 36 = 14
Now (i) the fraction of the total number of articles and articles broken = $$\frac { 50 }{ 36 }$$

Question 1.

Solution:

Question 2.
Simplify :

Solution:

### Fractions Exercise 14D – Selina Concise Mathematics Class 6 ICSE Solutions

Point to Remember :
BODMAS :- While simplifying an expressions we can involve six operation in following orders.
B Stands for “BRACKET”
O Stands for “OF”
D Stands for “DIVISION”
M Stands for “MULTIPLICATION”
S Stands for “SUBTRACTION”

Question 1.
Simplify :

Solution:

Question 2.
Simplify :

Solution:

Question 3.
Simplify :

Solution:

Question 4.
Simplify :

Solution:

Question 5.
Simplify :

Solution:

### Fractions Exercise 14E – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
From a rope of 10$$\frac { 1 }{ 2 }$$ m long, 4$$\frac { 5 }{ 8 }$$ m is cut off. Find the length of the remaining rope.
Solution:

Question 2.
A piece of cloth is 5 metre long. After washing, it shrinks by $$\frac { 1 }{ 25 }$$ of its length. What is the length of the cloth after washing ?
Solution:

Question 3.
I bought wheat worth Rs. 12$$\frac { 1 }{ 2 }$$, rice worth Rs. 25$$\frac { 3 }{ 4 }$$ and vegetables worth
Rs. 10$$\frac { 1 }{ 4 }$$. If I gave a hundred-rupee note to the shopkeeper ; how much did he return to me
Solution:

Question 4.
Out of 500 oranges in a box, $$\frac { 3 }{ 25 }$$ are rotten and $$\frac { 1 }{ 5 }$$ are kept for some guests. How many oranges are left in the box?
Solution:

Question 5.
An ornament piece is made of gold and copper. Its total weight is 96g. If $$\frac { 1 }{ 12 }$$ of the ornament hi copper, find the weight of gold in it.
Solution:

Question 6.
A girl did half of some work on Monday and one-third of it on Tuesday. How much will she have to do on Wednesday in order to complete the work ?
Solution:

Question 7.
A man spends $$\frac { 3 }{ 8 }$$ of his money and 8 still has Rs. 720 left with him. How much money did he have at first ?
Solution:

Question 8.
In a school, $$\frac { 4 }{ 5 }$$ of the students are boys, and the number of girls is 100. Find the number of boys.
Solution:

Question 9.
After finishing $$\frac { 3 }{ 4 }$$ of my journey, I find that 12 km of my journey is covered. How much distance is still left to be covered ?
Solution:

Question 10.
When Ajit travelled 15 km, he found that one-fourth of his journey was still left. What was the full length of the journey ?
Solution:

Question 11.
In a particular month, a man earns Rs. 7,200. Out of this income, he spends $$\frac { 3 }{ 10 }$$ on food, $$\frac { 1 }{ 4 }$$ on house rent, $$\frac { 1 }{ 10 }$$ on insurance and $$\frac { 2 }{ 25 }$$ on holidays. How much did he save in that month ?
Solution:

### Fractions Revision Exercise – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.

Solution:

Question 2.

Solution:

Question 3.
Evaluate :

Solution:

Question 4.
Mr. Mehra gave one-third of his money to his son, one-fifth of his money to his daughter and the remaining amount to his wife. If his wife got Rs. 91,000, how much money did Mr. Mehra have originally?
Solution:

Question 5.
A sum of Rs. 84,000 is divided among three persons A, B and C. If A gets one-fourth of it and B gets one-fifth of it; how much did C get ?
Solution:

= Rs. 84,000 – (37,800) = Rs. 46,200

Question 6.
In one hour Rohit walks 3$$\frac { 2 }{ 5 }$$ km. How much distance will he cover in 2$$\frac { 1 }{ 2 }$$ hours?
Solution:

Question 7.
An 84 m long string is cut into pieces each of length 5$$\frac { 1 }{ 4 }$$ m. How many pieces are obtained ?
Solution:

Question 8.
In buying a ready made shirt-two-fifths of my pocket money is spent If Rs. 540 is still left with me, find :
(i) The money I had before I bought the shirt.
(ii) The emit of the shirt
Solution:

Question 9.
Mohan leaves Rs. 1,20,000 to his wife and three children such that two-fifths of this money is given to his wife and the remaining is distributed equally among the children. Find, how much each child gets ?
Solution:
Total amount = Rs. 12,0,000
Amount given to his wife = $$\frac { 2}{ 5 }$$ of Rs. 1,20,000
= Rs. 2 x 24,000 = Rs. 48,000
Remaining amount = Rs. 120000 – Rs. 48000 = Rs. 72000
This amount is distributed among three children equally.
Each’s share = Rs. 72,000 x $$\frac { 1 }{ 3 }$$ = Rs. 24,000

Question 10.
Simplify :

Solution: