Selina ICSE Mathematics Class 6 Textbook Solutions Archives

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 13 Unitary Method

November 10, 2023May 19, 2022 by Raju

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 13 Unitary Method

Selina Publishers Concise Mathematics Class 6 ICSE Solutions Chapter 13 Unitary Method

ICSE Solutions Selina ICSE Solutions ML Aggarwal Solutions

APlusTopper.com provides step by step solutions for Selina Concise ICSE Solutions for Class 6 Mathematics. You can download the Selina Concise Mathematics ICSE Solutions for Class 6 with Free PDF download option. Selina Publishers Concise Mathematics for Class 6 ICSE Solutions all questions are solved and explained by expert mathematic teachers as per ICSE board guidelines.

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Unitary Method Exercise 13A – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
The price of 25 identical articles is ₹ 1,750. Find the price of :
(i) one article
(ii) 13 articles
Solution:
The price of 25 articles = ₹ 1,750
(i) Price of one article = ₹ \(\frac { 1750 }{ 25 }\) = ₹ 70
(ii) Now, Price of 13 articles = 13 x ₹ 70 = ₹ 910

Question 2.
A motorbike travels 330 km in 5 litres of petrol. How much distance will it cover in :
(i) one litre of petrol ?
(ii) 2.5 litres of petrol ?
Solution:
(i) Consuming 5 litres petrol in 30 km
Consuming 1 litre petrol, motorbike covers = \(\frac { 330 }{ 5 }\) km = 66 km
(ii) Consuming 2.5 litres petrol = 66 x 2.5 = 165 km

Question 3.
If the cost of a dozen soaps is ₹ 460.80, what will the cost of:
(i) each soap ?
(ii) 15 soaps ?
(iii) 3 dozen soaps ?
Solution:
(i) Cost of one dozen soap = ₹ 460.80
In one dozen = 12 soaps
Cost of each soap = ₹ \(\frac { 460.80 }{ 12 }\) = ₹ 38.4
(ii) Cost of 15 soaps = 15 x ₹ 38.4 = ₹ 576
(iii) Cost of 3 dozen soaps = (12 x 3 = 36) = 36 x ₹ 38.4 = ₹ 1382.4

Question 4.
The cost of 35 envelops is ₹ 105. How many envelops can be bought for ₹ 90 ?
Solution:
Envelops purchased by ₹ 105 = 35
Envelopes purchased by ₹ 1 = \(\frac { 35 }{ 105 }\)
In ₹ 90, the envelop will be bought = \(\frac { 35 }{ 105 }\) x 90 = 30

Question 5.
If the cost of 8 cans of juice is ₹ 280, then what will be the cost of 6 cans of juice ?
Solution:
Cost of 8 cans of juice = ₹ 280
Cost of 1 can of juice = \(\frac { 280 }{ 8 }\) = ₹ 35
then, cost of 6 cans of juice = 6 x ₹ 35 = ₹ 210

Question 6.
For ₹ 378, 9 cans of juice can be bought, then how many cans of juice can be bought for ₹ 504?
Solution:
In ₹ 378, the juice can bought = 9 cans
In ₹ 504, the cans of juice will be bought = \(\frac { 9 }{ 378 }\)
12 cans of juice can be bought in ₹ 504.

Question 7.
A motorbike travels 425 km in 5 hours. How much distance will be covered by it in 3.2 hours?
Solution:
Distance covered by motorbike = 425 km
Time taken = 5 hours
Distance covered by motorbike in 1 hour = \(\frac { 425 }{ 5 }\) km/hr = 85 km/hr
Then, distance covered in 3.2 hours = 85 x 3.2 = 272 km/hr

Question 8.
If the cost of a dozen identical articles is ₹ 672, what will be the cost of 18 such articles?
Solution:
Cost of one dozen articles = ₹ 672
Cost of one article = ₹ \(\frac { 672 }{ 12 }\) = ₹ 56
Cost of 18 articles = ₹ 56 x 18 = ₹ 1008

Question 9.
A car covers a distance of 180 km in 5 hours.
(i) How much distance will the car cover in 3 hours with the same speed ?
(ii) How much time will the car take to cover 54 km with the same speed?
Solution:
Distance covered by car 180 km in 5 hours
(i) Distance covered in 1 hour = \(\frac { 180 }{ 5 }\) = 36 km
Distance covered in 3 hours = 3 x 36 = 108 km
(ii) To cover a distance of 180 km, time taken = 5 hours
To cover a distance of 1 km, time taken = \(\frac { 5 }{ 180 }\)
To cover a distance of 54 km, time taken = \(\frac { 5 }{ 180}\) x 54 = 1.5 hours

Question 10.
If it has rained 276 cm in the last 3 days, how many cm of rain will fall in one week (7 days) ?
Assume that the rain continues to fall at the same rate.
Solution:
Rate of rainfall in 3 days = 276 cm
Rainfall in one day = \(\frac { 276 }{ 3 }\) = 92 cm
Rainfall in one week = 92 x 7 = 644 cm

Question 11.
Cost of 10 kg of wheat is ₹ 180.
(i) What is the cost of 18 kg of wheat ?
(ii) What quantity of wheat can be purchased in ₹ 432 ?
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 13 Unitary Method image - 1

Question 12.
Rohit buys 10 pens for ₹ 150 and Manoj buys 14 pens for ₹ 168. Who got the pens cheaper?
Solution:
Rohit buys 10 pens = ₹ 150
Cost of one pen = \(\frac { 150 }{ 10 }\) = ₹ 15
Manoj buys 14 pens = ₹ 168
Cost of one pen = \(\frac { 168 }{ 14 }\) = ₹ 12
Manoj buys cheaper pen.

Question 13.
A tree 24 m high casts a shadow of 15 m. At the same time, the length of the shadow casted by some other tree is 6 m. Find the height of the tree.
Solution:
Height of a tree which casts a shadow of 15 m = 24 m
Height of a tree which casts a shadow 24 of 1 m = \(\frac { 24 }{ 15 }\) m
Height of a tree which casts a shadow of 6 m = \(\frac { 24 }{ 15 }\) x 6 = 9.6 m

Question 14.
A loaded truck travels 18 km in 25 minutes. If the speed remains the same, how far can it travel in 5 hours?
Solution:
A loaded truck travels in 25 minutes a distance of = 18 km
A loaded truck travels in 1 min a distance of = \(\frac { 18 }{ 25 }\) km
A loaded truck travels in shows or 300 minutes, a distance of = \(\frac { 18 }{ 25 }\) x 300 = 216 km

Unitary Method Exercise 13B – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
Weight of 15 books is 6 kg. What is the weight of 45 such books?
Solution:
Weight of 15 books = 6 kg
Weight of 1 book = \(\frac { 6 }{ 15 }\) kg
Weight of 45 such books = \(\frac { 15 }{ 6 }\) x 45 = 112.5 kg

Question 2.
A made 84 runs in 6 overs and B made 126 runs in 7 overs. Who made more runs per over?
Solution:
Runs scored by A in 6 overs = 84 runs
Runs scored by A in one over = \(\frac { 84 }{ 6 }\) = 14 runs
Runs scored by B in 7 overs = 126 runs
Runs scored by B in one over = \(\frac { 126 }{ 7 }\) = 18 runs
B score more runs per over than A.

Question 3.
Geeta types 108 words in 6 minutes. How many words would she type in half an hour?
Solution:
Words typed by Geeta in 6 minutes = 108
Words typed by Geeta in 1 minute = \(\frac { 108 }{ 6 }\)
Words typed by Geeta in half hour or 30 minutes = \(\frac { 108 }{ 6 }\) x 30 = 540 words

Question 4.
The temperature dropped 18 degree Celsius in the last 24 days. If the rate of temperature drop remains the same, how many degrees will the temperature drop in the next 18 days?
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 13 Unitary Method image - 2

Question 5.
Mr. Chopra pays ₹ 12,000 as rent for 3 months. How much does he has to pay for a year if the rent per month remains same?
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 13 Unitary Method image - 3

Question 6.
A truck requires 108 litres of diesel for covering a distance of 1188 km. How much diesel will be required by the truck to cover a distance of 3300 km?
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 13 Unitary Method image - 4

Question 7.
If a deposit of ₹ 2,000 earns an interest of ₹ 500 in 3 years, how much interest would a deposit of ₹ 36,000 earn in 3 years with the same rate of simple interest?
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 13 Unitary Method image - 5

Question 8.
If John walks 250 steps to cover a distance of 200 metres, find the distance covered by him in 350 steps.
Solution:
Distance covered with 250 steps = 200 m
Distance covered with 1 step = \(\frac { 200 }{ 250 }\) m
Distance covered with 350 steps = \(\frac { 200 }{ 250 }\) x 350 = 280 m

Question 9.
25 metres of cloth costs ₹ 1,012.50.
(i) What will be the cost of 20 metres of cloth of the same type?
(ii) How many metres of the same kind can be bought for ₹ 1,620?
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 13 Unitary Method image - 6

Question 10.
In a particular week, a man works for 48 hours and earns ₹ 4,320. But in the next week he worked 6 hours less, how much has he earned in this week?
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 13 Unitary Method image - 7

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Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion

November 10, 2023May 19, 2022 by Raju

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion (Including Word Problems)

Selina Publishers Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion (Including Word Problems)

ICSE Solutions Selina ICSE Solutions ML Aggarwal Solutions

Selina Class 6 Maths ICSE Solutions Physics Chemistry Biology Geography History & Civics

Proportion Exercise 12A – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
In each of the following, check whether or not the given ratios form a proportion :
(i) 8 : 16 and 12 : 15
(ii) 16 : 28 and 24 : 42
(iii) 12 ÷ 3 and 8 ÷ 2
(iv) 25 : 40 and 20 : 32
(v) \(\frac { 15 }{ 18 } and \frac { 10 }{ 12 }\)
(vi) \(\frac { 7 }{ 8 }\) and 14 : 16
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 1

Question 2.
Find the value of x in .each of the following proportions :
(i) x : 4 = 6 : 8
(ii) 14 : x = 7 : 9
(iii) 4 : 6 = x : 18
(iv) 8 : 10 = x : 25
(v) 5 : 15 = 4 : x
(vi) 16 : 24 = 6 : x
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 3

Question 3.
Find the value of x so that the given four numbers are in proportion :
(i) x, 6, 10 and 15
(ii) x, 4, 15 and 30
(iii) 2, x, 10 and 25
(iv) 4, x, 6 and 18
(v) 9, 12, x and 8
(vi) 4, 10, 36 and x
(vii) 7, 21, x and 45
(viii) 6, 8, 12 and x.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 5

Question 4.
The first, second and the fourth terms of a proportion are 6, 18 and 75, respectively. Find its third term.
Solution:
Let the third term = x
6 : 18 : : x : 75
= 18 x x = 6 x 75
x = \(\frac { 6\times 75 }{ 18 } =\frac { 75 }{ 3 }\) = 25
The third term of proportion is 25

Question 5.
Find the second term of the proportion whose first, third and fourth terms are 9, 8 and 24 respectively.
Solution:
Let the second term = x
9 : x : : 8 : 24
=> x x 8 = 24 x 9
x = \(\frac { 24\times 9 }{ 8 }\) = 3 x 9 = 27
The second term of proportion = 27

Question 6.
Find the fourth term of the proportion whose first, second and third terms are 18, 27, and 32 respectively.
Solution:
Let the fourth term = x
18 : 27 : : 32 : x
=> 18 x x = 27 x 32
=> x = \(\frac { 27\times 32 }{ 18 }\) = 3 x 16 = 48
Fourth term = 48

Question 7.
The ratio of the length and the width of a school ground is 5 : 2. Find the length, if the width is 40 metres.
Solution:
Let the length = x m,
width = 40 m
The ratio of length to width = x : 40
as per given statement 5 : 2 = x : 40
=> 2 x x = 40 x 5
x = \(\frac { 40\times 5 }{ 2 }\) = 20 x 5 = 100 m

Question 8.
The ratio of the sale of eggs on a Sunday and that of the whole week at a grocery shop was 2 : 9. If the total value of the sale of eggs in the same week was Rs 360, find the value of the sale of eggs that Sunday.
Solution:
Let, the sale of eggs on Sunday = x
Sale in week = Rs 360
According to question, 2 : 9 = x : 360
=> 9 x x = 360 x 2
x = \(\frac { 360\times 2 }{ 9 }\) = Rs 80
Sale on Sunday = Rs 80

Question 9.
The ratio of copper and zinc in an alloy is 9 : 8. If the weight of zinc, in the alloy, is 9.6 kg ; find the weight of copper in the alloy.
Solution:
Let the weight of copper = x kg
Weight of zinc = 9.6 kg.
According to question,
9 : 8 = x : 9.6
=> 8 x x = 9 x 9.6
=> x = \(\frac { 9\times 9.6 }{ 8 }\) = 9 x 1.2 = 10.8 kg.
Weight of cooper in alloy = 10.8

Question 10.
The ratio of the number of girls to the number of boys in a school is 2 : 5. If the number of boys is 225 ; find:
(i) the number of girls in the school.
(ii) the number of students in the school.
Solution:
Let, the number of girls in school = x
Number of boys in school = 225
According to question 2 : 5 = x : 225
=> 5 x x = 2 x 225
x = \(\frac { 2\times 225 }{ 5 }\) = 2 x 45 = 90
Number of girls in school = 90
Total number of student in the school = (number of boys + number of girls) = (225 + 90) = 315

Question 11.
In a class, one out of every 5 students pass. If there are 225 students in all the sections of a class, find how many pass ?
Solution:
Total number of students in all sections = 225
Given, One of every five students pass
Total students pass = 225 x \(\frac { 1 }{ 5 }\) = 45 studetns

Question 12.
Make set of all possible proportions from the numbers 15, 18, 35 and 42.
Solution:
The possible proportions that can be made from the numbers 15, 18, 35 and 42 are
(i) 15 : 35 :: 18 : 42
(ii) 42 : 18 :: 35 : 15
(iii) 42 : 35 :: 18 : 15
(iv) 15 : 18 :: 35 : 42

Proportion Exercise 12B – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
If x, y and z are in continued proportion, then which of the following is true :
(i) x : y = x : z
(ii) x : x = z : y
(iii) x : y = y : z
(iv) y : x = y : z
Solution:
(iii) x : y = y : z

Question 2.
Which of the following numbers are in continued proportion :
(i) 3, 6 and 15
(ii) 15, 45 and 48
(iii) 6, 12 and 24
(iv) 12, 18 and 27
Solution:
(iii) and (iv)

Question 3.
Find the mean proportion between
(i) 3 and 27
(ii) 0.06 and 0.96
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 7

Question 4.
Find the third proportional to :
(i) 36, 18
(ii) 5.25, 7
(iii) ₹ 1.60, ₹ 0.40
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 8

=> x = 0.1

Question 5.
The ratio between 7 and 5 is same as the ratio between ₹ x and ₹ 20.50 ; find the value of x.
Solution:
Since, It is given that the ratio between 7 and 5 is same as the ratio between ₹ x and ₹ 20.50
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 10

Question 6.
If (4x + 3y) : (3x + 5y) = 6 : 7, find :
(i) x : y
(ii) x, if y = 10
(iii) y, if x = 27
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 11

Question 7.
If \(\frac { 2y+5x }{ 3y-5x } =2\frac { 1 }{ 2 }\), find:
(i) x : y
(ii) x, if y = 70
(iii) y, if x = 33
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 13

Proportion Exercise 12C – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
Are the following numbers in proportion:
(i) 32, 40, 48 and 60 ?
(ii) 12,15,18 and 20 ?
Solution:
(i) 32, 40, 48 and 60 are in proportion
if 32 : 40 = 48 : 60
if 32 x 60 = 40 x 48
\(\left\{ \frac { a }{ b } =\frac { c }{ d } \Longrightarrow \quad ad=bc \right\}\)
if 1920 = 1920
Which is true.
32, 40, 48 and 60 are in proportion
(ii) 12, 15, 18 and 20 are in proportion
if 12 : 15 = 18 : 20
if 12 x 20 = 15 x 18 {ad = bc}
if 240 = 270
which is not true.
12, 15, 18 and 20 are not in proportion.

Question 2.
Find the value of x in each of the following such that the given numbers are in proportion.
(i) 14, 42, x and 75
(ii) 45, 135, 90 and x
Solution:
14, 42, x and 75 are in proportion
\(\frac { 14 }{ 42 } =\frac { x }{ 75 }\)
=> 14 x 75 =x x 42
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 16

Question 3.
The costs of two articles are in the ratio 7 : 4. If the cost of the first article is Rs. 2,800 ; find the cost of the second article.
Solution:
Ratio in the cost of two articles = 7 : 4
Cost of first article = Rs. 2800
Let cost of the second article = x
7 : 4 = 2800 : x
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 17

Question 4.
The ratio of the length and the width of a rectangular sheet of paper is 8 : 5. If the width of the sheet is 17.5 cm; find the length.
Solution:
Let length of sheet = x cm
Ratio in length and breadth = 8 : 5
and width = 17.5 cm
8 : 5 = x : 17.5
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 18
Length of sheet = 28 cm

Question 5.
The ages of A and B are in the ratio 6 : 5. If A’s age is 18 years, find the age of B.
Solution:
Ratio in the ages of A and B = 6 : 5
A’s age = 18 years
Let B’s age = x years
6 : 5 = 18 : x
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 19

Question 6.
A sum of Rs. 10, 500 is divided among A, B and C in the ratio 5 : 6 : 4. Find the share of each.
Solution:
Total amount = Rs. 10, 500
Ratio in A, B, and C = 5 : 6 : 4
Sum of ratio = 5 + 6 + 4 = 15
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 20

Question 7.
Do the ratios 15 cm to 2 m and 10 sec to 3 minutes form a proportion ?
Solution:
15 cm : 2 m : : 10 sec : 3 min
15 cm : 2 x 100 cm :: 10 sec : 30 x 60 sec
15 : 200 :: 10 : 1800
3 : 40 :: 1 : 180
No, they donot form a proportion

Question 8.
Do the ratios 2 kg : 80 kg and 25 g : 625 g form a proportion ?
Solution:
2 kg : 80 kg : : 25 g : 625 g
2 : 80 :: 25 : 625
1 : 40 :: 1 : 25
No, they donot form a proportion.

Question 9.
10 kg sugar cost ₹ 350. If x kg sugar of the same kind costs ₹ 175, find the value of x
Solution:
10 kg of sugar costs = ₹ 350
and x kg of sugar cost = ₹ 175
A.T.Q.
10 kg : x kg :: 350 : 175
=> 10 x 175 = 350 x x
=> 350x= 1750
=> x = \(\frac { 1750 }{ 350 }\) = 5
Hence, 5 kg of sugar costs ₹ 175

Question 10.
The length of two ropes are in the ratio 7 : 5. Find the length of:
(i) shorter rope, if the longer one is 22.5 ni
(ii) longer rope, if the shorter is 9.8 m.
Solution:
Length of the ropes are in the ratio = 7 : 5
(i) Let the length of shorter rope = x
Length of longer rope = 22.5 m
A.T.Q.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 12 Proportion image - 21

Question 11.
If 4, x and 9 are in continued proportion, find the value of x.
Solution:
4, x and 9 are in continued proportion
=> 4 : x = x : 9
=> x² = 9 x 4
=> x = √36
x = 6

Question 12.
If 25, 35 and x are in continued proportion, find the value of x.
Solution:
25, 35 and x are in continued proportion
=> 25 : 35 = 35 : x
=> 25 x x = 35 x 35
=> x = \(\frac { 35\times 35 }{ 25 }\)
=> x = 49

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Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time

November 10, 2023May 19, 2022 by Raju

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time

Selina Publishers Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time

ICSE Solutions Selina ICSE Solutions ML Aggarwal Solutions

Selina Class 6 Maths ICSE Solutions Physics Chemistry Biology Geography History & Civics

Idea of Speed, Distance and Time Exercise 17A – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
A train covers 51 km in 3 hours. Calculate its speed. How far does the train go in 30 minutes?
Solution:
Given : Distance = 51 km
Time = 3 hours
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 1

Question 2.
A motorist travelled the distance between two towns, which is 65 km, in 2 hours and 10 minutes. Find his speed in metre per minute.
Solution:
Distance between two towns = 65 km
Time taken = 2 hr 10 min
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 2

Question 3.
A train travels 700 metres in 35 seconds. What is its speed in km/h?
Solution:
Distance = 700 m
Time taken = 35 sec
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 4

Question 4.
A racing car covered 600 km in 3 hours 20 minutes. Find its speed in metre per second. How much distance will the car cover in 50 sec?
Solution:
Distance covered = 600 km
Time taken = 3 hr 20 min
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 5
= Speed x Time
= 50 x 50 m = 2500 m or 2.50 km

Question 5.
Rohit goes 350 km in 5 hours. Find :
(i) his speed
(ii) the distance covered by Rohit in 6.2 hours
(iii) the time taken by him to cover 210 km.
Solution:
Distance covered = 350 km
Time taken = 5 hours
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 6

Question 6.
A boy drives his scooter with a uniform speed of 45 km/h. Find :
(i) the distance covered by him in 1 hour 20 min.
(ii) the time taken by him to cover 108 km.
(iii) the time taken to cover 900 m.
Solution:
Speed of the scooter = 45 km/h
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 7

Question 7.
I travel a distance of 10 km and come back in 2\(\frac { 1 }{ 2 }\) hours. What is my speed?
Solution:
Total distance covered = 10 km + 10 km = 20 km
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 9

Question 8.
A man walks a distance of 5 km in 2 hours. Then he goes in a bus to a nearby town, which is 40 km, in further 2 hours. From there, he goes to his office in an autorickshaw, a distance of 5 km, in \(\frac { 1 }{ 2 }\) hour. What was his average speed during the whole journey?
Solution:
Distance of 5 km travelled on foot in 2 hours
Distance of 40 km travelled by bus in 2 hours
Distance of 5 km travelled by Rickshaw in \(\frac { 1 }{ 2 }\) hour
Total distance covered = 5 + 40 + 5 = 50 km
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 10

Question 9.
Jagan went to another town such that he covered 240 km by a car going at 60 kmh^-1. Then he covered 80 km by a train, going at 100 kmh^-1 and the rest 200 km, he covered by a bus, going at 50 kmh^-1. What was his average speed during the whole journey?
Solution:
Distance covered 240 km by car with speed 60 km/h
Distance covered 80 km by train with speed 100 km/h
and rest distance covered 200 km by bus with speed 50 km/h
Total distance covered = (240 + 80 + 200) km = 520 km
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 11

Question 10.
The speed of sound in air is about 330 ms^-1. Express this speed in kmh^-1. How long will the sound take to travel 99 km?
Solution:
Speed of sound in air = 330 m/sec
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 13

Idea of Speed, Distance and Time Exercise 17B – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
A train 180 m long is running at a speed of 90 km/h. How long will it take to pass a railway signal?
Solution:
Distance = 180 m
Speed = 90 km/h
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 14

Question 2.
A train whose length is 150 m, passes a telegraph pole in 10 sec. Find the speed of the train in km/h.
Solution:
Distance = 150 m
Time taken = 10 sec
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 15

Question 3.
A train 120 m long passes a railway platform 160 m long in 14 sec. How long will it take to pass another platform which is 100 m long?
Solution:
Distance covered = 120 m + 160 m = 280 m
Time taken = 14 seconds
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 16

Question 4.
Mr. Amit can walk 8 km in 1 hour 20 minutes.
(a) How far does he go in :
(i) 10 minutes ?
(ii) 30 seconds ?
(b) How long will it take him to walk :
(i) 2500 m ?
(ii) 6.5 km ?
Solution:
Amit walks 8 km in 1 hour 20 min
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 17

Question 5.
Which is greater : a speed of 45 km/h or a speed of 12.25 m/sec?
How much is the distance travelled by each in 2 seconds?
Solution:
First speed = 45 km/h
Second = 12.25 m/sec
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 19

Question 6.
A and B start from the same point and at the same time with speeds 15 km/h and 12 km/h respectively, find the distance between A and B after 6 hours if both move in :
(i) same direction
(ii) the opposite directions.
Solution:
A’s speed = 15 km/h
B’s speed = 12 km/h
Distance covered by A in 6 hours = 15 x 6 = 90 km
and Distance covered by B in 6 hours = 12 x 6 = 72 km
(i) Distance between A and B when they move in the same direction = 90 – 72 = 18 km
(ii) Distance between A and B, when they move in the opposite directions = 90 + 72 = 162 km

Question 7.
A and B start from the same place, in the same direction and at the same time with speeds 6 km/h and 2 m/sec respectively. After 5 hours who will be ahead and by how much?
Solution:
A’s speed = 6 km/h
B’s speed = 2 m/sec
Distance covered by A in 5 hours = 6 x 5 = 30 km
and distance covered by B in 5 hours = 5 x 60 x 60 x 2 m = 36000 m
= \(\frac { 3600 }{ 1000 }\) = 36 km
B will be ahead and 36 – 30 = 6 km ahead.

Question 8.
Mohit covers a certain distance in 6 hrs by his scooter at a speed of 40 kmh^-1.
(i) Find the time taken by Manjoor to cover the same distance by his car at the speed of 60 kmh^-1.
(ii) Find the speed of Joseph, if he takes 8 hrs to complete the same distance.
Solution:
Mohit’s speed = 40 km/h or kmh^-1
Distance covered in = 6 hours
Distance = 40 x 6 = 240 km
(i) Manjoor car’s speed = 60 kmh^-1
He will cover the distance of 240 km in = \(\frac { 240 }{ 60 }\) = 4 hours
(ii) Joseph covered that distance in 8 hours
His speed = \(\frac { 240 }{ 8 }\) = 30 kmh^-1

Question 9.
A boy swims 200 m in still water and then returns back to the point of start in total 10 minutes. Find the speed of his swim in
(i) ms^-1
(ii) kmh^-1.
Solution:
Distance swimed by a boys of 200 m + 200 m = 400 m
Time taken = 10 minutes
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 20

Question 10.
A distance of 14.4 km is covered in 2 horus 40 minutes. Find the speed in ms^-1. With this speed Sakshi goes to her school, 240 m away from her house and then returns back. How much time, in all, will Sakshi take?
Solution:
Distance = 14.4 km
Time taken to cover = 2 hrs 40 min
= \(2\frac { 2 }{ 3 } =\frac { 8 }{ 3 }\) hrs
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 17 Idea of Speed, Distance and Time image - 21

Selina Class 6 Maths ICSE Solutions Physics Chemistry Biology Geography History & Civics

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System

November 10, 2023May 18, 2022 by Raju

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System (Consolidating the Sense of Numberness)

Selina Publishers Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System (Consolidating the Sense of Numberness)

ICSE Solutions Selina ICSE Solutions ML Aggarwal Solutions

Selina Class 6 Maths ICSE Solutions Physics Chemistry Biology Geography History & Civics

IMPORTANT POINTS

Place-Value (Local Value) : The place value (Local-value) of a digit depends upon the position, it occupies in the number:
For example :
In the number 6453
the place value of 6 is 6 thousand = 6 x 1000 = 6000
the place value of 4 is 4 hundred = 4 x 100 = 400
the place value of 5 is 5 ten = 5 x 10 = 50
the place value of 3 is 3 one = 3 x 1 = 3
Face-Value (True-Value) : Each digit in a number has a fixed value, regardless to its position in the number
For Example :
In the above number 6453
Face value of 6 is 6, 4 is 4, 5 is 5 and 3 is 3
An Abstract Number : Which does not refer to any particular unit e.g., 3, 5, 9.
A Concrete Number : Which refers to particular unit e.g., 3 boys, 5 girls, 9 rooms etc.
The smallest (least) one digit Number is 1.
The largest (greatest) one digit number is 9.

Number System Exercise 1A – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
Which is greater ?
(i) 537 or 98
(ii) 2428 or 529
(iii) 2, 59, 467 or 10, 35, 729
Solution:
(i) 537 or 98
Since 537 is three digit number and 98 is two digit number.
Hence 537 > 98 and 537 is greater
(ii) 2428 or 529
Since 2498 is four digit number and 529 is three digit number.
2498 > 529 ; 2498 is greater
(iii) 2, 59, 467 or 10, 35, 729
Since 10, 35, 729 is seven digit number and 2, 59, 467 is six digit number
10, 35, 729 > 2, 59, 467 ; 10, 35, 729 is greater

Question 2.
Which is smaller ?
(i) 428 or 437
(ii) 2497 or 2597
(iii) 3297 or 3596
Solution:
(i) 428 or 437
We observe that both the numbers are of three-digits.
And at the leftmost, both the number have same digit i.e. 4. But at the second place from the left, the first, number has 2 and the second number has 3.
Since 2 < 3
437 is greater
(ii) 2497 or 2597
We observe that both the numbers are of four digits.
And at the leftmost, both the numbers have same digit i.e. 2. But at the second place from the left, the first number has 4 and the second number has 5.
Since 4 < 5
2597 is greater
(iii) 3297 or 3596
We observe that both the numbers are of four digits.
And at the leftmost, both the numbers have same digit i.e. 2. But at the second place from the left, the first number has 4 and the second number has 5.
Since 4 < 5
3596 is greater

Question 3.
Which is greater ?
(i) 45293 or 45427
(ii) 380362 or 381007
(iii) 63520 or 63250
Solution:
(i) 45293 or 45427
We observe that both the numbers are of 5-digits.
And at the digits at leftmost and second place from the left are same.
But the digits at the third place from the left are different, the first number has 2 and the second number has 4.
Since 2 < 4
45427 is greater
(ii) 380362 or 381007
We observe that both the numbers are of 6-digits.
And at the digits at leftmost and second place from the left are same.
But the digits at the third place from the left are different, the first number has 0 and the second number has 1.
Since 0 < 1
381007 is greater
(iii) 63520 or 63250
We observe that both the numbers are of 5-digits.
And at the digits at leftmost and second place from the left are same.
But the digits at the third place from the left are different, the first number has 5 and the second number has 2.
Since 5 < 2
63520 is greater

Question 4.
By making a suitable chart, compare:
(i) 540276 and 369998
(ii) 6983245 and 6893254
Solution:
(i) 540276 and 369998

5	4	0	2	7	6
3	6	9	9	9	8

Clearly, both the numbers have equal number of digits i.e. 6
And at the leftmost, the first number has 5 and the second number has 3.
Since 5 > 3
540276 is greater.
(ii) 6983245 and 6893254

6	9	8	3	2	4	5
6	8	9	3	2	5	4

Clearly, both the numbers have equal number of digits i.e. 7
And at the leftmost, both have the same digit i.e. 6
And at the second place from the left, the first number has 9 and the second number has 8.
Since 9 > 8
6983245 is greater.

Question 5.
Compare the numbers written in the following table by writing them in ascending order:

	5	4	3	2	9	7	2
2	3	1	0	6	2	9	3
	5	2	2	3	7	9	1
2	3	1	8	2	6	3	4
5	4	3	4	4	7	8	2

Solution:
The given number in ascending order are as :
54344782 > 243182634 > 23106293 > 5432972> 5223791

5	4	3	4	4	7	8	2
2	3	1	8	2	6	3	4
2	3	1	0	6	2	9	3
	5	4	3	2	9	7	2
	5	2	2	3	7	9	1

Question 6.
Use table form to compare the numbers in descending order : 5,43,287; 54,82,900; 27,32,940; 43,877 ; 78,396 and 4,999
Solution:
The given numbers in descending order are as :

			4	9	9	9
		4	3	8	7	7
		7	8	3	9	6
	5	4	3	2	8	7
2	7	3	2	9	4	0
5	4	8	2	9	0	0

4, 999 < 43, 877 < 78, 396 < 5, 43, 287 < 27, 32, 940 < 54, 82, 900

Question 7.
Find the smallest and the greatest numbers in each case given below:
(i) 983, 5754, 84 and 5942
(ii) 32849, 53628, 5499 and 54909.
Solution:
(i) 983, 5754, 84 ahd 5942
Since 84 has the least number of digits.
84 is the least smallest whereas 5754 and 5942 have the maximum number of digits.
Out of 5754 and 5942, 5942 is greater.
5942 is the greatest and 84 is the smallest.
(ii) 32849, 53628, 5499 and 54909.
Since 5499 has the least number of digits.
5499 is the smallest
Whereas 54909 and 53628 have the maximum number of digits. Out of 54909 and 53628, 54909 is greater.
54909 is the greatest and 5499 is the smallest

Question 8.
Form the greatest and the smallest 4 digit numbers using the given digits without repetition
(i) 3, 7, 2 and 5
(ii) 6, 1, 4 and 9
(iii) 7, 0, 4 and 2
(iv) 1, 8, 5 and 3
(v) 9, 6, 0 and 7
Solution:
(i) The given digits are 3, 7, 2 and 5
(a) The greatest 4-digit number = 7532
(b) and the smallest 4-digit number = 2357
(ii) The digits are given : 6, 1, 4 and 9
(a) The greatest 4-digit number = 9641
(b) and the smallest 4-digit number = 1469
(iii) The digits are given 7, 0, 4 and 2
(a) The greatest 4-digit number = 7420
(b) The smallest 4-digit number = 2047
(iv) the digits are given 1, 8, 5 and 3
(a) The greatest 4-digit number = 8531
(b) and the smallest 4-digit number =1358
(v) The digits are given 9, 6, 0 and 7
(a) The greatest 4-digit number = 9760
(b) and the smallest 4-digit number = 6079

Question 9.
Form the greatest and the smallest 3-digit numbers using any three different digits with the condition that digit 6 is always at the unit (one’s) place.
Solution:
The condition for 3-digit number of three different digits is that 6 is at the ones place
The greatest 3-digit number will be 986 and the smallest 3-digit number will be 106

Question 10.
Form the greatest and the smallest 4-digit number using any four different digits with the condition that digit 5 is always at ten’s place.
Solution:
The condition for 4-digit number of four different digits is that 5 is always at its tens place
The greatest 4-digit number will be 9857 and the smallest 4-digit number will be 1052

Question 11.
Fill in the blanks :
(i) The largest number of 5-digit is …………… and the smallest number of 6-digit is …………….
(ii) The difference between the smallest number of four digits and the largest number of three digits = …………. – ………….. = …………..
(iii) The sum (addition) of the smallest number of three digit and the largest number of two digit = ………… + …………= ………….
(iv) On adding one to the largest five digit number, we get ……………. which is the smallest ……………… digit number.
(v) On subtracting one from the smallest four digit number, we get ……………… which is the ……………. three digit number.
Solution:
(i) The largest number of 5-digit is 99999 and the smallest number of 6-digit is 100000
(ii) The difference between the smallest number of four digits and the largest number of three digits = 1000 – 999 = 1
(iii) The sum (addition) of the smallest number of three digit and the largest number of two digit = 100 + 99 = 199
(iv) On adding one to the largest five digit number, we get 100000 which is the smallest six digit number.
(v) On subtracting one from the smallest four digit number, we get 999 which is the greatest three digit number.

Question 12.
Form the largest number with the digits 2, 3, 5, 9, 6 and 0 without repetition of digits.
Solution:
Largest number = 9, 65, 320.

Question 13.
Write the smallest and the greatest numbers of 4 digits without repetition of any digit.
Solution:
Smallest 4 digits number = 1023
Greatest number of 4 digits = 9876

Question 14.
Find the greatest and the smallest five digit numbers with 8 in hundred’s place and with all the digits different.
Solution:
Greatest 5-digit number = 97865 and smallest 5-digit number = 10823

Question 15.
Find the sum of the largest and the smallest four-digit numbers:
Solution:
Largest four-digits number = 9,999
Smallest four digits number = 1,000
Sum of the above = 9, 999 + 1,000 = 10,999.

Question 16.
Find the difference between the smallest and the greatest six-digits numbers.
Solution:
Greatest six-digits number = 9, 99, 999
Smallest six-digits number = 1,00,000
Difference between greatest and smallest = 9, 99, 999 – 1, 00, 000 = 8, 99, 999

Question 17.
(i) How many four digit numbers are there between 999 and 3000 ?
(ii) How many four digit numbers are there between 99 and 3000 ?
Solution:
(i) Four digit numbers between 999 and 3000 = 2999 – 999 = 2000
(ii) Four digit numbers between 99 and 3000 = 2999 – 999 = 2000

Question 18.
How many four digit numbers are there between 500 and 3000 ?
Solution:
Four digits numbers between 99 and 3000 = 2999 – 999 = 2000

Question 19.
Write all the possible three digit numbers using the digits 3, 6 and 8 only; if the repetition of digits is not allowed.
Solution:
All the three digits number using 3, 6, and 8 when repetition is not allowed, can be :
368, 386, 638, 683, 836, 863.

Question 20.
Make the greatest and the smallest 4-digit numbers using the digits 5, 4, 7 and 9 (without repeating the digits) and with the condition that:
(i) 7 is at unit’s place.
(ii) 9 is at ten’s place
(iii) 4 is at hundred’s place
Solution:
(i) 7 is at unit’s place
The smallest 4-digit number using the digits 5, 4, 7 and 9, and keeping 7 at unit’s place = 4597
The greatest 4-digit number using the digits 5, 4, 7 and 9 and keeping 7 at unit’s place = 9547
(ii) 9 is at ten’s place
The smallest 4-digit number using the digits 5, 4, 7 and 9 and keeping 9 at ten’s place = 4597
The greatest 4-digit number using the digits 5, 4, 7 and 9 and keeping 9 at ten’s place = 7594
(iii) 4 is at hundred’s place
The smallest 4-digit number using the digits 5, 4, 7 and 9 and keeping 4 at hundred’s place = 5479
The greatest 4-digit number using the digits 5, 4, 7 and 9 and keeping 4 at hundred’s place = 9475

Number System Exercise 1B – Selina Concise Mathematics Class 8 ICSE Solutions

Question 1.
Population of a city was 3, 54, 976 in the year 2014. In the year 2015, it was found to be increased by 68, 438. What was the population of the city at the end of the year 2015?
Solution:
Population of a city in 2014 = 3,54, 976
Population increased in 2015 = 68, 438
Total population at the end of the year 2015 = 3, 54, 976 + 68, 438 = 423414
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 1

Question 2.
A = 7,43,000 and B = 8,00,100. Which is greater A or B ? And, by how much?
Solution:
A = 7,43,000
B = 8,00,100
B is greater than A. (B > A)
Because = B – A
Since A = 7, 43, 000 and B = 800,100 and both the numbers have 6 digits.
And at the leftmost, the first number has 7 and the second number has 8.
Since 8 > 7
800, 600 > 7,43,000 (B > A)
B is greater than A by = 800, 100 – 7, 43, 000 = 57, 100
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 2

Question 3.
A small and thin notebook has 56 pages. How many total number of pages will 5326 such note-books have?
Solution:
Number of pages in one notebook = 56 pages
Number of pages in 5326 notebooks = 5326 x 56 = 298256 pages
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 3

Question 4.
The number of sheets of paper available for making notebooks is 75,000. Each sheet makes 8 pages of a notebook. Each notebook contains 200 pages. How many notebooks can be made from the available paper ?
Solution:
Number of sheets available = 75, 000
Number of pages obtained from one sheet = 8
Total number of pages obtained = 8 x 75, 000 = 6, 00, 000
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 4

Question 5.
Add 1, 76, 209; 4, 50, 923 and 44, 83, 947
Solution:
1, 76, 209 + 4, 50, 923 + 44, 83, 947
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 5
Adding these values, we get = 51, 11, 079

Question 6.
A cricket player has so far scored 7, 849 runs in test matches. He wishes to complete 10, 000 runs ; how many more runs does he need ?
Solution:
Score of cricket player = 7, 849 runs
Total scores he wish to complete = 10,000
Runs required = 10, 000 – 7, 849 = 2151
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 6

Question 7.
In an election two candidates A and B are the only contestants. If candidate A scored 9, 32, 567 votes and candidates B scored 9, 00, 235 votes, by how much margin did A win or loose the election ?
Solution:
Scores of candidate A = 9,32,567
Scores of candidate B = 9,00,235
Candidate A win the election By margin = 9,32,567 – 9,00,235 = 32,332 scores
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 7

Question 8.
Find the difference between the largest and the smallest number that can be written using the digits 5, 1, 6,3 and 2 without repeating any digit.
Solution:
The digits given are = 5, 1, 6, 3 and 2
The largest 5-digit number that can be formed using the digits 5, 1, 6, 3 and 2 = 65321
The smallest 5-digit number that can be formed using the digits 5, 1,6, 37and 2 =12356
Difference between 65321 and 12356
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 8
= 65321 – 12356 = 52,965

Question 9.
A machine manufactures 5,782 screws every day. How many screws will it manufacture in the month of April ?
Solution:
Number of screws in one day = 5, 782
Number of days in April = 30 days
Number of screws in April = 5, 782 x 30 = 1,73,460
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 9

Question 10.
A man had ₹ 1, 57, 184 with him. He placed an order for purchasing 80 articles at 125 each. How much money will remain with him after the purchase ?
Solution:
Money in hand = ₹ 1, 57, 184
Number of articles purchased = 80
Cost of one article = ₹ 125
Cost of 80 articles = ₹ 80 x 125 = ₹ 10,000
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 10

Question 11.
A student multiplied 8,035 by 87 instead of multiplying by 78. By how much was his answer greater than or less than the correct answer ?
Solution:
Correct answer = 8,035 x 87 = 6,99,045
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 11

Question 12.
Mohani has 30 m cloth and she wants to make some shirts for her son. If each shirt requires 2 m 30 cm cloth, how many shirts, in all, can be made and how much length of cloth will be lefft ?
Solution:
Total length of cloth available = 30 m or 30 x 100 = 3000 cm
Shirt made by using 2m 30cm (230 cm) cloth = 1
Shirts made by using 30 m cloth = \(\frac { 1 }{ 230 }\) x 3000 = 13.04 = 13 shirts
Cloth required to make 13 shirts = 230 x 13 = 2990 cm or 29 m 90 cm
Hence, remaining cloth = 30 m – 29 m = 1m

Question 13.
The weight of a box is 4 kg 800 gm. What is the total weight of 150 boxes?>
Solution:
Weight of one box = 4 kg 800 gm
Total weight of 150 boxes = 4 kg 800 g x 150 = 720 kg
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 12

Question 14.
The distance between two places A and B is 3 km 760 m. A boy travels A to B and then B to A every day. How much distance does he travel in 8 days?
Solution:
Distance between two places = 3 km 760 m 3760 m
Distance among A to B and B to A = 2 x 3760 m = 7520 m
In 8 days he travelled = 7520 x 8 = 60160 m or 60 km 160 m

Question 15.
An oil-tin contains 6 litre 60 ml oil. How many identical bottles can the oil fill, if capacity of each bottle is 30 ml ?
Solution:
Oil contained in a tin = 6 litre 60 ml = 6 x 1000 + 60 = 6060 ml
Capacity of each bottle = 30 ml
No. of bottled can be filled with 30 ml oil = 6060 ÷ 30 = 202 bottles
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 13

Question 16.
The scale receipt of a company in a certain year was ₹ 83, 73, 540. In the following year, it was decreased by ₹ 7, 84, 670.
(i) What was the sale receipt of the company during second year?
(ii) What was the total sale receipt of the company during these two years?
Solution:
Sale receipt of the company during first year = ₹ 83,73,540
Sale decreased in second year = ₹ 7,84,670
(i) The sale receipt of the company during second year = ₹ 83,73,540 – ₹ 7,84,670
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 1 Number System image - 14
(ii) Total sale receipt of the company during these two years = ₹ 83, 73, 540 + ₹ 75, 88, 870 = ₹ 1, 59, 62, 410

Question 17.
A number exceeds 8, 59, 470 by 3, 00, 999. What is the number?
Solution:
First number = 8, 59, 470
Difference between second and first number = 3, 00, 999
Second number = 8, 59, 470 + 3, 00, 999 = 11, 60, 469

Selina Class 6 Maths ICSE Solutions Physics Chemistry Biology Geography History & Civics

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 4 Place Value

November 10, 2023May 18, 2022 by Raju

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 4 Place Value

Selina Publishers Concise Mathematics Class 6 ICSE Solutions Chapter 4 Place Value

ICSE Solutions Selina ICSE Solutions ML Aggarwal Solutions

Selina Class 6 Maths ICSE Solutions Physics Chemistry Biology Geography History & Civics

Place Value Exercise 4A – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
Fill in the blanks :
(i) In 20 kg, the unit is ………….., which is taken …………. times.
(ii) In 80 m, the unit is …………., which is taken …………. times.
(iii) If a unit cm (centimetre) is taken 5 times, the corresponding quantity is …………….
(iv) If a unit km (kilometre) is taken 24 times, the corresponding quantity is ……………
(v)

Number	Numeral	Numeration
53	………….	……….
………	9	…………
240	…………..	………..

Solution:
(i) In 20 kg, the unit is kg, which is taken 20 times.
(ii) In 80 m, the unit is m, which is taken 80 times.
(iii) If a unit cm (centi metre) is taken 5 times, the corresponding quantity is 5 cm.
(iv) If a unit km (kilo metre) is taken 24 times, the corresponding quantity is 24 km.
(v)

Number	Numeral	Numeration
53	53	fifty three
9	9	Nine
240	240	two hundred forty

Question 2.
Fill in the blanks :
(i) In 24,673 ; the place value of 6 is ………..
(ii) In 8,039 ; the place value of 8 is …………..
(iii) In 3,25,648; the local value of 5 is ……………
(iv) In 6,439 ; the local value of 6 is ……….
Solution:
(i) In 24,673 ; the place value of 6 is 6 x 100 = 600.
(ii) In 8, 039 ; the place value of 8 is 8 x 1000 = 8000.
(iii) In 3, 25, 648 ; the local value of 5 is 5 x 1000 = 5000.
(iv) In 6, 439 ; the local value of 6 is 6 x 1000 = 6000.

Question 3.
Find the difference between the place values of 3 and 5 in the number 3945.
Solution:
Place values of 3 in 3945 is 3000 and 5 is 5
Difference between them = 3000 – 5 = 2995

Question 4.
In the number 40562
(i) the local value of 5 = …………..
(ii) the place value of 6 = ………..
(iii) the sum of the place value of 5 and the place value of 6 = …………
Solution:
(i) the local value of 5 = 500 and its local value is 5.
(ii) the place value of 6 = 60
(iii) the sum of the place value of 5 and the place value of 6 = 500 + 60 = 560

Question 5.
Read and write the following numbers in words and also in expanded form :
(i) 35,000 = …………
(ii) 76,000 = ……………
(iii) 6,23,000 = ………….
(iv) 40,075 = …………….
(v) 50,004 = ………..
Solution:
(i) 35,000 = Thirty five thousands = 3 x 10000 + 5 x 1000
(ii) 76,000 = Seventy six thousands = 7 x 10000 + 6 x 1000
(iii) 6,23,000 = Six lakhs twenty three thousands = 6 x 100000 + 23 x 1000
(iv) 40,075 = Forty thousands seventy five = 4 x 10000 + 75 x 10 + 5
(v) 50,004 = Fifty thousands four = 5 x 10000 + 4

Question 6.
Find the difference in the place values of two sevens in the number 8, 72, 574.
Solution:
In 8,72,574, the first 7 occurs at ten thousand place.
=> Its place value = 70000
=> The second 7 occurs at ten’s place.
Its place value = 70
The difference of the two place values of 7 = 70000 – 70 = 69930

Place Value Exercise 4B – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
Fill in the blanks :
(i) 999 + 1 = …………
(ii) 10,000 – 1 = …………
(iii) 10 coins – one coin = …………
(iv) ₹ 99 + ₹ 1 = ………..
(v) 10,000 boys – 1 boy = ………..
(vi) 1000 toys – 1 toy = ……….
Solution:
(i) 999 + 1 = 1,000
(ii) 10,000 – 1 =9,999
(iii) 10 coins – one coin = 9 coins
(iv) ₹ 99 + ₹ 1 = ₹ 100
(v) 10,000 boys – 1 boy = 9,999 boys
(vi) 1000 toys – 1 toy = 999 toys

Question 2.
Would the number of students in your school be a 3-digit number or a 4-digit number or a 5-digit number ?
Solution:
Note : This answer will vary from school to school.
Since, the total strength of M.G.N. Public school is 5410.
Hence, It is a 4-digit number.

Question 3.
Write the smallest number which is just more than 9, 99, 999.
Solution:
Given number = 9, 99, 999
Smallest number which is more than 1 is = 9, 99, 999 + 1 = 10, 00, 000

Question 4.
Starting from the greatest 5-digit number, write the previous five numbers in descending order.
Solution:
Greatest digit number = 99, 999
Next four numbers in descending order
99, 999 > 99998 > 99997 > 99996 > 99995

Question 5.
Starting from the smallest 7-digit number, write the next four numbers in ascending order.
Solution:
Smallest 7-digit number = 10, 00, 000
Next four numbers in ascending order
10,00,001 < 1000002 < 1000003 < 1000004 <1000005

Question 6.
How many numbers lie between the largest 3-digit number and the smallest 4-digit number ?
Solution:
Largest 3-digit number = 999
Smallest 4-digit number = 1000
Required number = (1000 – 999) = 1

Question 7.
How many 5-digit numbers are there in all?
Solution:
Largest number of 5-digits = 99999 Largest number of 4-digits = 9999
Required number=99999 – 9999 = 90,000
So, 90,000 numbers are there in all.

Selina Class 6 Maths ICSE Solutions Physics Chemistry Biology Geography History & Civics