Mastering Physics Solutions Chapter 13 Oscillations About Equilibrium

Mastering Physics Solutions Chapter 13 Oscillations About Equilibrium

Mastering Physics Solutions

Chapter 13 Oscillations About Equilibrium Q.1CQ
A basketball player dribbles a ball with a steady period of T seconds. Is the motion of the ball periodic? Is it simple harmonic? Explain.
Solution:
The motion of a particle, which is repeated in position and phase after a certain interval of time. is defined as periodic motion The periodic motion, in which a particle moves to and fr0 about a fixed point such that its acceleration is always directly proportional to its displacement from its mean position. is defined as simple harmonic motion. Since the player dribbles the ball with constant period, the motion is periodic. On the other hand. the position and velocity of the ball do not vary sinusoidally with time, instead it varies linearly. So the motion is not a simple harmonic motion.

Chapter 13 Oscillations About Equilibrium Q.1P
A small cart on a 5.0-m-long air track moves with a speed of 0.85 m/s. Bumpers at either end of the track cause the cart to reverse direction and maintain the same speed. Find the period and frequency of this motion.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium1ps

Chapter 13 Oscillations About Equilibrium Q.2CQ
A person rides on a Ferris wheel that rotates with constant angular speed If the Sun is directly overhead. does the person’s shadow on the ground undergo periodic motion? Does it undergo simple harmonic motion? Explain.
Solution:
The persons shadow undergoes periodic motioni with the same period as the period of the Ferris wheel’s rotation In fact, if we take into account the connection between uniform circular motion and simple harmonic motion, we can say that the shadow exhibits simple harmonic motion as it moves back and forth on the ground

Chapter 13 Oscillations About Equilibrium Q.2P
A person in a rocking chair completes 12 cycles in 21 s. What are the period and frequency of the rocking?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium2ps

Chapter 13 Oscillations About Equilibrium Q.3CQ
An air-track cart bounces back and forth between the two ends of an air track. Is this motion periodic? Is it simple harmonic? Explain.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium3cqs

Chapter 13 Oscillations About Equilibrium Q.3P
While fishing for catfish, a fisherman suddenly notices that the bobber (a floating device) attached to his line is bobbing up and down with a frequency of 2.6 Hz. What is the period of the bobber’s motion?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium3ps

Chapter 13 Oscillations About Equilibrium Q.4CQ
If a mass m and a mass 2m oscillate on identical springs with identical amplitudes, they both have the same maximum kinetic energy. How can this be? Shouldn’t the larger mass have more kinetic energy? Explain.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium4cqs

Chapter 13 Oscillations About Equilibrium Q.4P
If you dribble a basketball with a frequency of 1.77 Hz, how long does it take for you to complete 12 dribbles?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium4ps

Chapter 13 Oscillations About Equilibrium Q.5CQ
An object oscillating with simple harmonic motion completes a cycle in a time T. If the object’s amplitude is doubled, the time required for one cycle is still T, even though the object covers twice the distance. How can this be? Explain.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium5cqs

Chapter 13 Oscillations About Equilibrium Q.5P
You take your pulse and observe 74 heartbeats in a minute. What are the period and frequency of your heartbeat?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium5ps

Chapter 13 Oscillations About Equilibrium Q.6CQ
The position of an object undergoing simple harmonic motion is given by x =A cos(Bt). Explain the physical significance of the constants A and B. What is the frequency of this object’s motion?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium6cqs

Chapter 13 Oscillations About Equilibrium Q.6P
(a) Your heart beats wi th a frequency of 1.45 Hz. How many beats occur in a minute? (b) If the frequency of your heartbeat increases, will the number of beats in a minute increase, decrease, or stay the same? (c) How many beats occur in a minute if the frequency increases to 1.55 Hz?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium6ps

Chapter 13 Oscillations About Equilibrium Q.7CQ
The velocity of an object undergoing simple harmonic motion is given by v = −C sin(Dt). Explain the physical significance of the constants C and D. What are the amplitude and period of this object’s motion?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium7cqs

Chapter 13 Oscillations About Equilibrium Q.7P
You rev your car’s engine to 2700 rpm (rev/min). (a) What are the period and frequency of the engine? (b) If you change the period of the engine to 0.044 s, how many rpms is it doing?
Solution:
Frequency is number of cycles (or revolution) per second. Time is period is the time take to complete one cycle.
Given that
Frequency of car’s engine = 2700 rpm
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium7ps

Chapter 13 Oscillations About Equilibrium Q.8CQ
The pendulum bob in Figure leaks sand onto the strip chart. What effect does this loss of sand have on the period of the pendulum? Explain.
Solution:
The period of a pendulum is independent of the mass of its bob. Therefore, the period should be unaffected.

Chapter 13 Oscillations About Equilibrium Q.8P
A mass moves back and forth in simple harmonic motion with amplitude A and period T.(a) In terms of A,through what distance does the mass move in the time T? (b) Through what distance does it move in the time 5T/2?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium8ps

Chapter 13 Oscillations About Equilibrium Q.9CQ
Soldiers on the march are often ordered to break cadence in their step when crossing a bridge. Why is this a good idea?
Solution:
The soldiers are marching on the bridge. If the natural frequency of the bridge is equal to the frequency of the soldiers, then the bridge vibrates with greater amplitude because of resonance. This may cause the bridge to collapse at once. Because of this, all soldiers are ordered to break cadence in their steps when crossing a bridge.

Chapter 13 Oscillations About Equilibrium Q.9P
A mass moves back and forth in simple harmonic motion with amplitude A and period T. (a) In terms of T, how long does it take for the mass to move through a total distance of 2A? (b) How long does it take for the mass to move through a total distance of 3A?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium9ps

Chapter 13 Oscillations About Equilibrium Q.10P
The position of a mass oscillating on a spring is given by x = (3.2 cm) cos[2πt/(0.58 s)]. (a) What is the period of this motion? (b) What is the first time the mass is at the position x = 0?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium10ps

Chapter 13 Oscillations About Equilibrium Q.11P
The position of a mass oscillating on a spring is given by x = (7.8 cm) cos[2πt/(0.68 s)] (a) What is the frequency of this motion? (b) When is the mass first at the position x = –7.8 cm?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium11ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium11ps1

Chapter 13 Oscillations About Equilibrium Q.12
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium12p
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium12ps
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Chapter 13 Oscillations About Equilibrium Q.13P
Amass on a spring osculates with simple harmonic motion of amplitude A about the equilibrium position x = 0. Its maximum speed is vmax and its maximum acceleration is amax. (a) What is the speed of the mass at x =0? (b) What is the acceleration of the mass at x =0? (c) What is the speed of the mass at x = A? (d) What is the acceleration of the mass at x = A?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium13ps

Chapter 13 Oscillations About Equilibrium Q.14P
A mass oscillates on a spring with a period of 0.73 s and an amplitude of 5.4 cm. Write an equation giving x as a function of time, assuming the mass starts at x = A at time t = 0.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium14ps

Chapter 13 Oscillations About Equilibrium Q.15P
An atom in a molecule oscillates about its equilibrium position with a frequency of 2.00 × 1014 Hz and a maximum displacement of 3.50 nm. (a) Write an expression giving x as a function of time for this atom, assuming that x = A at t = 0. (b) If, instead, we assume that x = 0 at t =0, would your expression for position versus time use a sine function or a cosine function? Explain.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium15ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium15ps1

Chapter 13 Oscillations About Equilibrium Q.16P
A mass oscillates on a spring with a period T and an amplitude 0.48 cm. The mass is at the equilibrium position x = 0 at t = 0, and is moving in the positive direction. Where is the mass at the times (a) t = T/8, (b) t = T/4, (c) t = T/2and (d) t = 3T/4? (e) Plot your results for parts (a) through (d) with the vertical axis representing position and the horizontal axis representing time.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium16ps
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mastering-physics-solutions-chapter-13-oscillations-about-equilibrium16ps2
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Chapter 13 Oscillations About Equilibrium Q.17P
The position of a mass on a spring is given by x = (6.5 cm) cos[2πt/(0.88 s)]. (a) What is the period, T, of this motion? (b) Where is the mass at t = 0.25 s? (c) Show that the mass is at the same location at 0.25 s + T seconds as it is at 0.25 s.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium17ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium17ps1

Chapter 13 Oscillations About Equilibrium Q.18P
A mass attached to a spring oscillates with a period of 3.35 s. (a) If the mass starts from rest at x = 0.0440 m and time t = 0, where is it at time t = 6.37 s? (b) Is the mass moving in the positive or negative x direction at t =6.37 s? Explain.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium18ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium18ps1

Chapter 13 Oscillations About Equilibrium Q.19P
An object moves with simple harmonic motion of period T and amplitude A. During one complete cycle, for what length of time is the position of the object greater than A/2?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium19ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium19ps1

Chapter 13 Oscillations About Equilibrium Q.20P
An object moves with simple harmonic motion of period T and amplitude A. During one complete cycle, for what length of time is the speed of the object greater than vmax/2?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium20ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium20ps1

Chapter 13 Oscillations About Equilibrium Q.21P
An object executing simple harmonic motion has a maximum speed vmax and a maximum acceleration amax. Find (a) the amplitude and (b) the period of this motion. Express your answers in terms of vmax and amax.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium21ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium21ps1

Chapter 13 Oscillations About Equilibrium Q.22P
A ball rolls on a circular track of radius 0.62 m with a constant angular speed of 1.3 rad/s inthe counterclockwise direction. If the angular position of the ball at t = 0 is θ = 0, find the x component of the ball’s position at the times 2.5 s, 5.0 s, and 7.5 s. Let θ = 0 correspond to the positive x direction.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium22ps
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Chapter 13 Oscillations About Equilibrium Q.23P
An object executing simple harmonic motion has a maximum speed of 4.3 m/s and a maximum acceleration of 0.65 m/s2. Find (a) the amplitude and (b) the period of this motion.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium23ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium23ps1

Chapter 13 Oscillations About Equilibrium Q.24P
A child rocks back and forth on a porch swing with an amplitude of 0.204 m and a period of 2.80 s. Assuming the motion is approximately simple harmonic, find the child’s maximum speed.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium24ps

Chapter 13 Oscillations About Equilibrium Q.25P
A 30.0-g goldfinch lands on a slender branch, where it oscillates up and down with simple harmonic motion of amplitude 0.0335 m and period 1.65 s. (a) What is the maximum acceleration of the finch? Express your answer as a fraction of the acceleration of gravity, g. (b)What is the maximum speed of the goldfinch? (c) At the time when the goldfinch experiences its maximum acceleration, is its speed a maximum or a minimum? Explain.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium25ps
c) For the maximum acceleration, the velocity in a simple harmonic motion becomes zero.

Chapter 13 Oscillations About Equilibrium Q.26P
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium26p
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium26ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium26ps1

Chapter 13 Oscillations About Equilibrium Q.27P
A vibrating structural beam in a spacecraft can cause problems if the frequency of vibration is fairly high. Even if the amplitude of vibration is only a fraction of a millimeter, the acceleration of the beam can be several times greater than the acceleration due to gravity. As an example, find the maximum acceleration of a beam that vibrates with an amplitude of 0.25 mm at the rate of 110 vibrations per second. Give your answer as a multiple of g.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium27ps

Chapter 13 Oscillations About Equilibrium Q.28P
A peg on a turntable moves with a constant tangential speed of 0.77 m/s in a circle of radius 0.23 m. The peg casts a shadow on a wall. Find the following quantities related to the motion of the shadow: (a) the period, (b) the amplitude, (c) the maximum speed, and (d) the maximum magnitude of the acceleration.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium28ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium28ps1

Chapter 13 Oscillations About Equilibrium Q.29P
The pistons in an internal combustion engine undergo a motion that is approximately simple harmonic. If the amplitude of motion is 3.5 cm, and the engine runs at 1700 rev/min, find (a) the maximum acceleration of the pistons and (b) their maximum speed.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium29ps

Chapter 13 Oscillations About Equilibrium Q.30P
A 0.84-kg air cartis attached to a spring and allowed to oscillate. If the displacement of the air cart from equilibrium is x = (10.0 cm) cos[(2.00 s−1)t + π], find (a) the maximum kinetic energy of the cart and (b) the maximum force exerted on it by the spring.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium30ps

Chapter 13 Oscillations About Equilibrium Q.31P
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium31p
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium31ps

Chapter 13 Oscillations About Equilibrium Q.32P
If a mass m is attached to a given spring,. its period of oscillation is T. If two such springs are connected end to end and the same mass m is attached, (a) is the resulting period of oscillation greater than, less than, or equal to T? (b) Choose the best explanation from among the following:
I. Connecting two springs together makes the spring suffer, which means that less time is required for an oscillation.
II. The period of oscillation does not depend on the length of a spring, only on its force constant and the mass attached to it.
III. The longer spring stretches more easily, and hence takes longer to complete an oscillation.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium32ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium32ps1
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium32ps2

Chapter 13 Oscillations About Equilibrium Q.33P
An old car with worn-out shock absorbers oscillates with a given frequency when it hits a speed bump. If the driver adds a couple of passengers to the car and hits another speed bump, (a) is the car’s frequency of oscillation greater than, less than, or equal to what it was before? (b) Choose the best explanation from among the following:
I. Increasing the mass on a spring increases its period, and hence decreases its frequency.
II. The frequency depends on the force constant of the spring but is independent of the mass.
III. Adding mass makes the spring oscillate more rapidly, which increases the frequency.
Solution:
a) The car’s frequency of oscillation is less than to what it was before.
b) Increase in mass increases its period of oscillation of the car and hence frequency decreases. Option I is correct.

Chapter 13 Oscillations About Equilibrium Q.34P
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium34p
Solution:
a) When both the blocks are set into oscillation, the period of the block 1 is equal to the period of block 2.
b) The two blocks experience the same restoring force for a given displacement from the equilibrium and hence they have equal periods of oscillation.

Chapter 13 Oscillations About Equilibrium Q.35P
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium35p
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium35ps

Chapter 13 Oscillations About Equilibrium Q.36P
A 0.46-kg mass attached to a spring undergoes simple harmonic motion with a period of 0.77 s. What is the force constant of the spring?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium36ps

Chapter 13 Oscillations About Equilibrium Q.37P
System A consists of a mass m attached to a spring with a force constant k;system B has a mass 2m attached to a spring with a force constant k;system C has a mass 3m attached to a spring with a force constant 6k; and system D has a mass m attached to a spring with a force constant 4k. Rank these systems in order of Increasing period of oscillation.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium37ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium37ps1

Chapter 13 Oscillations About Equilibrium Q.38P
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium38p
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium38ps

Chapter 13 Oscillations About Equilibrium Q.39P
When a 0.50-kg mass is attached to a vertical spring, the spring stretches by 15 cm. How much mass must be attached to the spring to result in a 0.75-s period of oscillation?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium39ps

Chapter 13 Oscillations About Equilibrium Q.40P
A spring with a force constant of 69 N/m is attached to a 0.57-kg mass. Assuming that the amplitude of motion is 3.1 cm, determine the following quantities for this system: (a) ω, (b) vmax, (c) T.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium40ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium40ps1

Chapter 13 Oscillations About Equilibrium Q.41P
Two people with a combined mass of 125 kg hop into an old car with worn-out shock absorbers. This causes the springs to compress by 8.00 cm. When the car hits a bump in the road, it oscillates up and down with a period of 1.65 s. Find (a) the total load supported by the springs and (b) the mass of the car.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium41ps

Chapter 13 Oscillations About Equilibrium Q.42P
A 0.85-kg mass attached to a vertical spring of force constant 150 N/m oscillates with a maximum speed of 0.35 m/s. Find the following quantities related to the motion of the mass: (a) the period, (b) the amplitude, (c) the maximum magnitude of the acceleration.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium42ps

Chapter 13 Oscillations About Equilibrium Q.43P
When a 0.213-kg mass is attached to a vertical spring, it causes the spring to stretch a distance d. If the mass is now displaced slightly from equilibrium, it is found to make 102 oscillations in 56.7 s. Find the stretch distance, d.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium43ps

Chapter 13 Oscillations About Equilibrium Q.44P
The springs of a 511-kg motorcycle have an effective force constant of 9130 N/m. (a) If a person sits on the motorcycle, does its period of oscillation increase, decrease, or stay the same? (b) By what percent and in what direction does the period of oscillation change when a 112-kg person rides the motorcycle?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium44ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium44ps1

Chapter 13 Oscillations About Equilibrium Q.45P
If a mass m is attached to a given spring, its period of oscillation is T. If two such springs are connected end to end, and the same mass m is attached, (a) is its period greater than, less than, or the same as with a single spring? (b) Verify your answer to part (a) by calculating the new period, T’,in terms of the old period T.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium45ps

Chapter 13 Oscillations About Equilibrium Q.46P
How much work is required to stretch a spring 0.133 m if its force constant is 9.17 N/m?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium46ps

Chapter 13 Oscillations About Equilibrium Q.47P
A 0.321-kg mass is attached to a spring with a force constant of 13.3 N/m. If the mass is displaced 0.256 m from equilibrium and released, what is its speed when it is 0.128 m from equilibrium?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium47ps

Chapter 13 Oscillations About Equilibrium Q.48P
Find the total mechanical energy of the system described in the previous problem.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium48ps

Chapter 13 Oscillations About Equilibrium Q.49P
A 1.8-kg mass attached to aspring oscillates with an amplitude of 7.1 cm and a frequency of 2.6 Hz. What is its energy of motion?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium49ps

Chapter 13 Oscillations About Equilibrium Q.50P
A 0.40-kg mass is attached to a spring with a force constant of 26 N/m and released from rest a distance of 3.2 cm from the equilibrium position of the spring. (a) Give a strategy that allows you to find the speed of the mass when it is halfway to the equilibrium position. (b) Use your strategy to find this speed.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium50ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium50ps1

Chapter 13 Oscillations About Equilibrium Q.51P
(a) What is the maximum speed of the mass in the previous problem? (b) How far is the mass from the equilibrium position when its speed is half the maximum speed?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium51ps
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mastering-physics-solutions-chapter-13-oscillations-about-equilibrium51ps2
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Chapter 13 Oscillations About Equilibrium Q.52P
A bunch of grapes is placed in a spring scale at a supermarket. The grapes oscillate up and down with a period of 0.48 s, and the spring in the scale has a force constant of 650 N/m. What are (a) the mass and (b) the weight of the grapes?
Solution:
a) The time period of a spring mass system is directly proportional to the square root of mass and inversely proportional to the square root of force constant of the spring. The time period is given by relation
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium52ps

Chapter 13 Oscillations About Equilibrium Q.53P
What is the maximum speed of the grapes in the previous problem if their amplitude of oscillation is 2.3 cm?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium53ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium53ps1

Chapter 13 Oscillations About Equilibrium Q.54P
A 0.505-kg block slides on a frictionless horizontal surface with a speed of 1.18 m/s. The block encounters an unstretched spring and compresses it 23.2 cm before coming to rest. (a) What is the force constant of this spring? (b) For what length of time is the block in contact with the spring before it comes to rest? (c) If the force constant of the spring is increased, docs the time required to stop the block increase, decrease, or stay the same? Explain.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium54ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium54ps1

Chapter 13 Oscillations About Equilibrium Q.55P
A 2.25-g bullet embeds itself in a 1.50-kg block, which is attached to a spring of force constant 785 N/m. If the maximum compression of the spring is 5.88 cm, find (a) the initialspeed of the bullet and (b) the time for the bullet-block system to come to rest.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium55ps
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Chapter 13 Oscillations About Equilibrium Q.56P
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium56p
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium56ps

Chapter 13 Oscillations About Equilibrium Q.57P
A grandfather clock keeps correct time at sea level. If the clock is taken to the top of a nearby mountain, (a) would you expect it to keep correct time, run slow, or run fast? (b) Choose the best explanation from among the following:
I. Gravity is weaker at the top of the mountain, leading to a greater period oi oscillation.
II. The length of the pendulum is unchanged, and therefore its period remains the same.
III. The extra gravity from the mountain causes the period to decrease.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium57ps

Chapter 13 Oscillations About Equilibrium Q.58P
A pendulum of length L has a period T. How long must the pendulum be if its period is to be 2T?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium58ps

Chapter 13 Oscillations About Equilibrium Q.59P
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium59p
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium59ps

Chapter 13 Oscillations About Equilibrium Q.60P
A simple pendulum of length 2.5 m makes 5.0 complete swings in 16 s. What is the acceleration of gravity at the location of the pendulum?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium60ps

Chapter 13 Oscillations About Equilibrium Q.61P
A large pendulum with a 200-lb gold-plated bob 12 inches in diameter is on display in the lobby of the United Nations building. The penduliun has a length of 75 ft. It is used to show the rotation of the Earth—for this reason it is referred to as a Foucault pendulum, What is the least amount of time it takes for the bob to swing from a position of maximum displacement to the equilibrium position of the pendulum? (Assume that the acceleration due to gravity is g = 9.81 m /s2 at the UN building.)
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium61ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium61ps1

Chapter 13 Oscillations About Equilibrium Q.62P
Find the length of a simple pendulum that has a period oi 1.00 s. Assume that the acceleration of gravity is g = 9.81 m/s2.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium62ps

Chapter 13 Oscillations About Equilibrium Q.63P
If the pendulum in the previous problem were to be taken to the Moon, where the acceleration of gravity is g/6, (a) would its period increase, decrease, or stay the same? (b) Check your result in part (a) by calculating the period of the pendulum on the Moon.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium63ps

Chapter 13 Oscillations About Equilibrium Q.64P
A hula hoop hangs from a peg. Find the period of the hoop as it gently rocks back and forth on the peg. (For a hoop with axis at the rim I = 2mR2, where R is the radius of the hoop.)
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium64ps

Chapter 13 Oscillations About Equilibrium Q.65P
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium65p
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium65ps

Chapter 13 Oscillations About Equilibrium Q.66P
Consider a meterstick that oscillates back and forth about a pivot point at one of its ends. (a) Is the period of a simple pendulum of length L =1.00 m greater than, less than, or the same as the period of the meterstick? Explain. (b) Find the length L of a simple pendulum that has a period equal to the period of the meterstick.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium66ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium66ps1

Chapter 13 Oscillations About Equilibrium Q.67P
On the construction site for a new skyscraper, a uniform beam of steel is suspended from one end. If the beam swings back and forth with a period of 2.00 s, what is its length?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium67ps

Chapter 13 Oscillations About Equilibrium Q.68P
(a) Find the period of a child’s leg as it swings about the hip joint. Assume the leg is 0.55 m long and can be treated as a uniform rod. (b) Estimate the child’s walking speed.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium68ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium68ps1

Chapter 13 Oscillations About Equilibrium Q.69P
Suspended from the ceiling of an elevator is a simple pendulum of length L. What is the period of this pendulum if the elevator (a) accelerates upward with an acceleration a, or (b) accelerates downward with an acceleration whose magnitude is greater than zero but less than g? Give your answer in terms of L, g,and a.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium69ps

Chapter 13 Oscillations About Equilibrium Q.70GP
An object undergoes simple harmonicmotion with a period T. In the time 3T/2 the object moves through a total distance of 12D. In terms of D, what is the object’s amplitude of motion?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium70ps

Chapter 13 Oscillations About Equilibrium Q.71GP
A mass on a string moves with simple harmonic motion. If the period of motion is doubled, with the force constant and the amplitude remaining the same, by what multiplicative factor do the following quantities change: (a) angular frequency, (b) frequency, (c) maximum speed, (d) maximum acceleration, (e) total mechanical energy?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium71ps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium71ps1
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium71ps2

Chapter 13 Oscillations About Equilibrium Q.72GP
If the amplitude of a simple harmonic oscillator is doubled, by what multiplicative factor do the following quantities change: (a) angular frequency, (b) frequency, (c) period, (d) maximum. speed, (e) maximum acceleration, (f) total mechanical energy?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium72gps

Chapter 13 Oscillations About Equilibrium Q.73GP
A mass m is suspended from the ceiling of an elevator by a spring of force constant k. When the elevator is at rest, the period of the mass is T. Does the period increase, decrease, or remain the same when the elevator (a) moves upward with constant speed or (b) moves upward with constant acceleration?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium73gps

Chapter 13 Oscillations About Equilibrium Q.74GP
A pendulum of length L is suspended from the ceiling of an elevator. When the elevator is at rest, the period of the pendulum is T. Does the period increase, decrease, or remain the same when the elevator (a) moves upward with constant speed or (b) moves upward with constant acceleration?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium74gps

Chapter 13 Oscillations About Equilibrium Q.75GP
A 1.8-kg mass is attached to a spring with a force constant of 59 N/m. If the mass is released with a speed of 0.25 m/s at a distance of 8.4 cm from the equilibrium position of the spring, what is its speed when it is halfway to the equilibrium position?
Solution:
We can find the speed of the mass attached to the spring at any point using conservation of energy. Initially the mass has both potential energy as well as kinetic energy. Now our interest is to know the speed of the block when it is halfway from its equilibrium point.
According to conservation of energy
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium75gps

Chapter 13 Oscillations About Equilibrium Q.76GP
An astronaut uses a Body Mass Measurement Device (BMMD) to determine her mass. What is the astronaut’s mass, given that the force constant of the BMMD is 2600 N/m and the period of oscillation is 0.85 s? (See the discussion on page 427 for more details on the BMMD.)
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium76gps

Chapter 13 Oscillations About Equilibrium Q.77GP
A typical atom in a solid might oscillate with a frequency of 1012 Hz andan amplitude of 0.10 angstrom (10−11 m). Find the maximum acceleration of the atom and compare it with the acceleration of gravity.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium77gps

Chapter 13 Oscillations About Equilibrium Q.78GP
Sunspots vary in number as a function of time, exhibiting an approximately 11-year cycle. Galileo made the first European observations of sunspots in 1610, and daily observations were begun in Zurich in 1749. At the present time we are well into the 23rd observed cycle. What is the frequency of the sunspot cycle? Give your answer in Hz.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium78gps

Chapter 13 Oscillations About Equilibrium Q.79GP
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium79gp
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium79gps

Chapter 13 Oscillations About Equilibrium Q.80GP
An object undergoing simple harmonic motion with a period T is at the position x = 0 at the time t =0. At the time t = 0.25T the position of the object is positive. State whether x is positive, negative, or zero at the following times: (a) t = 1.5T, (b) t = 2T, (c) t = 2.25T, and (d) t = 6.75T.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium80gps

Chapter 13 Oscillations About Equilibrium Q.81GP
The maximum speed of a 3.1-kg mass attached to aspring is 0.68 m/s, and the maximum force exerted on the mass is 11 N. (a) Whatis the amplitude of motion for this mass? (b) What is the force constant of the spring? (c) What is the frequency of this system?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium81gps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium81gps1
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium81gps2

Chapter 13 Oscillations About Equilibrium Q.82GP
The acceleration of a block attached to a spring is given by a = −(0.302 m/s2) cos([2.41 rad/s]t). (a) What isthe frequency of the block’s motion? (b) What is the maximum, speed of the block? (c) What is the amplitude of the block’s motion?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium82gps

Chapter 13 Oscillations About Equilibrium Q.83GP
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium83gp
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium83gps

Chapter 13 Oscillations About Equilibrium Q.84GP
A 9.50-g bullet, moving horizontally with an initial speed v0, embeds itself in a 1.45-kg pendulum bob that is initially at rest. The length of the pendulum is L = 0.745 m. After the collision, the pendulum swings to one side and comes to rest when it has gained a vertical height of 12.4 cm. (a) Is the kinetic energy of the bullet-bob system immediately after the collision greater than, less than, or the same as the kinetic energy of the system just before the collision? Explain. (b) Find the initial speed of the bullet. (c) How long does it take for the bullet-bob system to come to rest for the first time?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium84gps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium84gps1

Chapter 13 Oscillations About Equilibrium Q.85GP
A 1.44-g spider oscillates on its web, which has a damping constant of 3.30 × 10−5 kg/s. How long does it take for the spider’s amplitude of osculation to decrease by 10.0 percent?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium85gps

Chapter 13 Oscillations About Equilibrium Q.86GP
An object undergoes simple harmonic motion with a period T and amplitude A. In terms of T, how long does it take the object to travel from x = A to x = A/2?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium86gps

Chapter 13 Oscillations About Equilibrium Q.87GP
Find the period of oscillation of a disk of mass 0.32 kg and radius 0.15 m if it is pivoted about a small hole drilled near its rim.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium87gps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium87gps1

Chapter 13 Oscillations About Equilibrium Q.88GP
Calculate the ratio of the kinetic energy to the potential energy of a simple harmonic oscillator when its displacement is half its amplitude.
Solution:
Let an object of mass m be oscillating under simple harmonic motion with amplitude A. When it is displaced, half of the amplitude at this position speed of the object is
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium88gps

Chapter 13 Oscillations About Equilibrium Q.89GP
A 0.363-kg mass slides on a frictionless floor with a speed of 1.24 m/s. The mass strikes and compresses a spring with a force constant of 44.5 N/m. (a) How far docs the mass travel after contacting the spring before it comes to rest? (b) How long does it take for the spring to stop the mass?
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium89gps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium89gps1

Chapter 13 Oscillations About Equilibrium Q.90GP
A large rectangular barge floating on a lake oscillates up and down with a period of 4.5 s. Find the damping constant for the barge, given that its mass is 2.44 × 105 kg and that its amplitude of oscillation decreases by a factor of 2.0 in 5.0 minutes.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium90gps

Chapter 13 Oscillations About Equilibrium Q.91GP
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium91gp
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium91gps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium91gps1

Chapter 13 Oscillations About Equilibrium Q.92GP
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium92gp
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium92gps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium92gps1
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium92gps2
3.31N

Chapter 13 Oscillations About Equilibrium Q.93GP
A 0.45-kg crow lands on a slender branch and bobs up and down with a period of 1.5 s. An eagle flies up to the same branch, scaring the crow away, and lands. The eagle now bobs up and down with a period of 4.8 s. Treating the branch as an ideal spring, find (a) the effective force constant of the branch and (b) the mass of the eagle.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium93gps

Chapter 13 Oscillations About Equilibrium Q.94GP
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium94gp
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium94gps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium94gps1
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium94gps2

Chapter 13 Oscillations About Equilibrium Q.95GP
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium95gp
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium95gps

Chapter 13 Oscillations About Equilibrium Q.96GP
When a mass m is attached to a vertical spring with a force constant k,it stretches the spring by the amount L. Calculate (a) the period of this mass and (b) the period of a simple pendulum of length L.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium96gps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium96gps1
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium96gps2
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium96gps3

Chapter 13 Oscillations About Equilibrium Q.97GP
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium97gp
Solution:
The total mechanical energy of an object in simple harmonic motion is equal to the sum of kinetic and potential energies.
For a mass undergoing simple harmonic motion to a spring with force constant(k)
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium97gps

Chapter 13 Oscillations About Equilibrium Q.98GP
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium98gp
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium98gps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium98gps1
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium98gps2

Chapter 13 Oscillations About Equilibrium Q.99GP
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium99gp
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium99gps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium99gps1

Chapter 13 Oscillations About Equilibrium Q.100PP
Insects are ectothermic, which means their body temperature is largely determined by the temperature of their surroundings. This can have a number of interesting consequences. For example, the wing coloration in some butterfly species is determined by the ambient temperature, as is the body color of several species of dragonfly. In addition, the wing beat frequency of beetles taking flight varies with temperature due to changes in the resonant frequency of their thorax.
The origin of such temperature effects can be traced back to the fact that molecules have higher speeds and greater energy as temperature is increased (see Chapters 16 and 17). Thus, for example, molecules that collide and react as part of the metabolic process will do so more rapidly when the reactions are occurring at a higher temperature. As a result, development rates, heart rates, wing beats, and other processes all occur more rapidly.
One of the most interesting thermal effects is the temperature dependence of chirp rate in certain insects. This behavior has been observed in cone-headed grasshoppers, as well as several types of cricket. A particularly accurate connection between chirp rate and temperature is found in the snowy tree cricket (Oecanthus fultoni Walker), which chirps at a rate that follows the expression N = T − 39, where N is the number of chirps in 13 seconds, and T is the numerical value of the temperature in degrees Fahrenheit. This formula, which is known as Dolbear’s law, is plotted in Figure (green line) along with data points (blue dots) for the snowy tree cricket.
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium100gp
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium100gps

Chapter 13 Oscillations About Equilibrium Q.101PP
Insects are ectothermic, which means their body temperature is largely determined by the temperature of their surroundings. This can have a number of interesting consequences. For example, the wing coloration in some butterfly species is determined by the ambient temperature, as is the body color of several species of dragonfly. In addition, the wing beat frequency of beetles taking flight varies with temperature due to changes in the resonant frequency of their thorax.
The origin of such temperature effects can be traced back to the fact that molecules have higher speeds and greater energy as temperature is increased (see Chapters 16 and 17). Thus, for example, molecules that collide and react as part of the metabolic process will do so more rapidly when the reactions are occurring at a higher temperature. As a result, development rates, heart rates, wing beats, and other processes all occur more rapidly.
One of the most interesting thermal effects is the temperature dependence of chirp rate in certain insects. This behavior has been observed in cone-headed grasshoppers, as well as several types of cricket. A particularly accurate connection between chirp rate and temperature is found in the snowy tree cricket (Oecanthus fultoni Walker), which chirps at a rate that follows the expression N = T − 39, where N is the number of chirps in 13 seconds, and T is the numerical value of the temperature in degrees Fahrenheit. This formula, which is known as Dolbear’s law, is plotted in Figure (green line) along with data points (blue dots) for the snowy tree cricket.
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium101gp
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium101gps

Chapter 13 Oscillations About Equilibrium Q.102PP
Insects are ectothermic, which means their body temperature is largely determined by the temperature of their surroundings. This can have a number of interesting consequences. For example, the wing coloration in some butterfly species is determined by the ambient temperature, as is the body color of several species of dragonfly. In addition, the wing beat frequency of beetles taking flight varies with temperature due to changes in the resonant frequency of their thorax.
The origin of such temperature effects can be traced back to the fact that molecules have higher speeds and greater energy as temperature is increased (see Chapters 16 and 17). Thus, for example, molecules that collide and react as part of the metabolic process will do so more rapidly when the reactions are occurring at a higher temperature. As a result, development rates, heart rates, wing beats, and other processes all occur more rapidly.
One of the most interesting thermal effects is the temperature dependence of chirp rate in certain insects. This behavior has been observed in cone-headed grasshoppers, as well as several types of cricket. A particularly accurate connection between chirp rate and temperature is found in the snowy tree cricket (Oecanthus fultoni Walker), which chirps at a rate that follows the expression N = T − 39, where N is the number of chirps in 13 seconds, and T is the numerical value of the temperature in degrees Fahrenheit. This formula, which is known as Dolbear’s law, is plotted in Figure (green line) along with data points (blue dots) for the snowy tree cricket.
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium102gp
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium102gps

Chapter 13 Oscillations About Equilibrium Q.103PP
Insects are ectothermic, which means their body temperature is largely determined by the temperature of their surroundings. This can have a number of interesting consequences. For example, the wing coloration in some butterfly species is determined by the ambient temperature, as is the body color of several species of dragonfly. In addition, the wing beat frequency of beetles taking flight varies with temperature due to changes in the resonant frequency of their thorax.
The origin of such temperature effects can be traced back to the fact that molecules have higher speeds and greater energy as temperature is increased (see Chapters 16 and 17). Thus, for example, molecules that collide and react as part of the metabolic process will do so more rapidly when the reactions are occurring at a higher temperature. As a result, development rates, heart rates, wing beats, and other processes all occur more rapidly.
One of the most interesting thermal effects is the temperature dependence of chirp rate in certain insects. This behavior has been observed in cone-headed grasshoppers, as well as several types of cricket. A particularly accurate connection between chirp rate and temperature is found in the snowy tree cricket (Oecanthus fultoni Walker), which chirps at a rate that follows the expression N = T − 39, where N is the number of chirps in 13 seconds, and T is the numerical value of the temperature in degrees Fahrenheit. This formula, which is known as Dolbear’s law, is plotted in Figure (green line) along with data points (blue dots) for the snowy tree cricket.
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium103gp
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium103gps
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium103gps1

Chapter 13 Oscillations About Equilibrium Q.104IP
Suppose we can change the plane’s period of oscillation, while keeping its amplitude of motion equal to 30.0 m. (a) If we want to reduce the maximum acceleration of the plane, should we increase or decrease the period? Explain. (b) Find the period that results in a maximum acceleration of 1.0g.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium104ips
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium104ips1

Chapter 13 Oscillations About Equilibrium Q.105IP
Suppose the force constant of the spring is doubled, but the mass and speed of the block are still 0.980 kg and 1.32 m/s, respectively. (a) By what multiplicative factor do you expect the maximum compression of the spring to change? Explain. (b) Find the new maximum compression of the spring. (c) Find the time required for the mass to come to rest after contacting the spring.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium105ips
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium105ips1

Chapter 13 Oscillations About Equilibrium Q.106IP
If the block’s initial speed is increased, does the total time the block is in contact wi th the spring increase, decrease, or stay the same? (b) Find the total time of contact for v0 = 1.65 m/s, m = 0.980 kg, and k = 245 N/m.
Solution:
mastering-physics-solutions-chapter-13-oscillations-about-equilibrium106ips

Mastering Physics Solutions Chapter 12 Gravity

Mastering Physics Solutions Chapter 12 Gravity

Mastering Physics Solutions

Chapter 12 Gravity Q.1CQ
It is often said that astronauts in orbit experience weightlessness because they are beyond the pull of Earth’s gravity. Is this statement correct? Explain.
Solution:
No The force of Earth’s gravity is practically as strong in orbit as it is on the surface of Earth The astronauts experience weightlessness because they are in constant free fall.

Chapter 12 Gravity Q.1P
CE System A has masses m and m separated by a distance r; system B has masses m and 2m separated by a distance 2r; system C has masses 2m and 3m separated by a distance 2r, and system D has masses 4m and 5m separated by a distance 3r. Rank these systems in order of increasing gravitational force. Indicate ties where appropriate.
Solution:
Mastering Physics Solutions Chapter 12 Gravity1ps

Chapter 12 Gravity Q.2CQ
When a person passes you on the street, you do not feel a gravitational tug. Explain.
Solution:
Mastering Physics Solutions Chapter 12 Gravity2cqs

Chapter 12 Gravity Q.2P
In each hand you hold a 0.16-kg apple. What is the gravitational force exerted by each apple on the other when their separation is (a) 0.25 m and (b) 0.50 m?
Solution:
Mastering Physics Solutions Chapter 12 Gravity2ps
Mastering Physics Solutions Chapter 12 Gravity2ps1

Chapter 12 Gravity Q.3CQ
Two objects experience a gravitational attraction. Give a reason why the gravitational force between them does not depend on the sum of their masses.
Solution:
The force of gravity between two point masses m1 and m2, separated by a distance r, is attractive and of magnitude
Mastering Physics Solutions Chapter 12 Gravity3cqs
where G is the universal gravitational constant.
Gravity exerts an action-reaction pair of forces on m1 and m2. That is, the force exerted by gravity on m1 is equal in magnitude but opposite in direction to the force exerted on m2. It is dependent on the product of masses. If the gravitational force depended on the sum of the two masses, it would predict a non-zero force even when one of the masses is zero. That is, there would be a gravitational force between a mass and a point in empty space, which is certainly not what we observed.

Chapter 12 Gravity Q.3P
A 6.1-kg bowling ball and a 7.2-kg bowling ball rest on a rack 0.75 m apart. (a) What is the force of gravity exerted on each of the balls by the other ball? (b) At what separation is the force of gravity between the balls equal to 2.0 × 10?9N?
Solution:
Mastering Physics Solutions Chapter 12 Gravity3ps

Chapter 12 Gravity Q.4CQ
Imagine bringing the tips of your index fingers together. Each finger contains a certain finite mass, and the distance between them goes to zero as they come into contact. From the force law F = Gm1m2/r2 one might conclude that the attractive force between the fingers is infinite, and, therefore, that your fingers must remain forever stuck together. What is wrong with this argument?
Solution:
As the tips of the fingers approach one another, we can think of them as being two small spheres that touch each other. Even though the two spheres touch each other, the distance between the centers is not zero. This is always a finite number. Therefore, the force between the spheres is always finite, even they touch each other. As such, the two fingers simply experience the finite force of two point masses separated by a finite distance.

Chapter 12 Gravity Q.4P
A communications satellite with a mass of 480 kg is in a circular orbit about the Earth. The radius of the orbit is 35,000 km as measured from the center of the Earth. Calculate (a) the weight of the satellite on the surface of the Earth and (b) the gravitational force exerted on the satellite by the Earth when it is in orbit.
Solution:
Mastering Physics Solutions Chapter 12 Gravity4ps
Mastering Physics Solutions Chapter 12 Gravity4ps1

Chapter 12 Gravity Q.5CQ
Does the radius vector of Mars sweep out the same amount of area per time as that of the Earth? Why or why not?
Solution:
No. The amount of area swept out per time varies from planet to planet because the linear speeds of planets are different.

Chapter 12 Gravity Q.5P
The Attraction of Ceres Ceres, the largest asteroid known, has a mass of roughly 8.7 × 1020 kg. If Ceres passes within 14,000 km. of the spaceship in which you are traveling, what force does it exert on you? (Use an approximate value for your mass, and treat yourself and the asteroid as point objects.)
Solution:
Mastering Physics Solutions Chapter 12 Gravity5ps

Chapter 12 Gravity Q.6CQ
When a communications satellite is placed in a geosynchronous orbit above the equator. it remains fixed over a given point on the ground. Is it possible to put a satellite into an orbi t so that it remains fixed above the North Pole? Explain
Solution:
INot possiblel because a satellite will appear stationary only when it revolves in an orbit that is concentric and coplanar with the equatorial plane, has a period of revolution of 24 hours, and
has a sense of revolution from the west to the east of Earth. As the north pole is away from the equatorial plane. it will not be possible to put a geostationary satellite over the north pole.

Chapter 12 Gravity Q.6P
In one hand you hold a 0.11-kg apple, in the other hand a 0.24-kg orange. The apple and orange are separated by 0.85 m. What is the magnitude of the force of gravity that (a) the orange exerts on the apple and (b) the apple exerts on the orange?
Solution:
Mastering Physics Solutions Chapter 12 Gravity6ps

Chapter 12 Gravity Q.7CQ
The Mass of Pluto On June 22, 1978, James Christy made the first observation of a moon orbiting Pluto. Until that lime the mass of Pluto was not known, but with the discovery of its moon, Charon, its mass could be calculated with some accuracy. Explain.
Solution:
Mastering Physics Solutions Chapter 12 Gravity7cqs

Chapter 12 Gravity Q.7P
IP A spaceship of mass m travels from the Earth to the Moon along a line that passes through the center of the Earth and the center of the Moon. (a) At what distance from the center of the Earth is the force due to the Earth twice the magnitude of the force due to the Moon? (b) How does your answer to part (a) depend on the mass of the spaceship? Explain.
Solution:
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Chapter 12 Gravity Q.8CQ
Rockets arc launched into space from Cape Canaveral in an easterly direction Is there an advantage to launching to the east versus launching to the west? Explain
Solution:
Earth revolves from west to east (counterclockwise) about its polar axis. Therefore, all the particles on Earth have a velocity from west to east. This velocity is at a maximum along the
equatorial line, as y = Rw,where R is the radius of Earth and w is the angular velocity of Earth’s revolution about its polar axis.
ICape Canaveral is situated at the equator so when a rocket is launched from west to east in this place. the maximum linear velocity is added to the launching velocity of the rocket Because of this. launching becomes easied

Chapter 12 Gravity Q.8P
Mastering Physics Solutions Chapter 12 Gravity8p
Solution:
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Chapter 12 Gravity Q.9CQ
One day in the future you may take a pleasure cruise to the Moon While there you might climb a lunar mountain and throw a rock horizontally from its summit If. in principle, you could throw the rock fast enough, it might end up hitting you in the back Explain.
Solution:
Ion the Moon. where there is no atmosphere, a rock can orbit at any altitudel where it clears the mountains — as long as it has sufficient speed If we could give a rock enough speed. it would orbit the Moon and return to us from the other side (behind).

Chapter 12 Gravity Q.9P
Mastering Physics Solutions Chapter 12 Gravity9p
Solution:
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Chapter 12 Gravity Q.10CQ
Apollo astronauts orbiting the Moon at low altitude noticed occasional changes ¡n their orbit that they attributed to localized concentrations of mass below the lunar surface. Just what effect would such ‘Thascons” have on their orbit?
Solution:
As the astronauts approach a mass concentration, its increased gravitational attraction would increase the speed of the craft Similarly, as they pass the mass concentration, its ravitationaI attraction is in the backward direction, which decreases their speed I

Chapter 12 Gravity Q.10P
Mastering Physics Solutions Chapter 12 Gravity10p
Solution:
Mastering Physics Solutions Chapter 12 Gravity10ps
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Chapter 12 Gravity Q.11CQ
If you light a candle on the space shuttle—which would not be a good idea—would it burn the same as on the Earth? Explain
Solution:
No. In the weightless environment of the shuttle, there is no convection which is required to bring fresh oxygen to the flame. Without convection, a flame usually goes out very quickly. In carefully controlled experiments on the shuttle, however, small flames have been maintained for considerable times These “weightless” flames are spherical in shape. as opposed to the tear- shaped flames on Earth

Chapter 12 Gravity Q.11P
IP Three 6.75-kg masses are at the corners of an equilateral triangle and located in space far from any other masses. (a) If the sides of the triangle are 1.25 m long, find the magnitude of the net force exerted on each of the three masses. (b) How does your answer to part (a) change if the sides of the triangle are doubled in length?
Solution:
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Chapter 12 Gravity Q.12CQ
The force exerted by the Sun on the Moon is more than twice the force exerted by the Earth on the Moon. Should the Moon be thought of as orbiting the Earth or the Sun? Explain.
Solution:
Mastering Physics Solutions Chapter 12 Gravity12cqs

Chapter 12 Gravity Q.12
Mastering Physics Solutions Chapter 12 Gravity12p
Solution:
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Chapter 12 Gravity Q.13CQ
Mastering Physics Solutions Chapter 12 Gravity13cq
Solution:
The net force acting on the moon is always directed toward the Sun, never away from the Sun. Therefore, the Moon’s orbit must always curve toward the Sun. It curves sharply toward the Sun when Earth is between the Moon and the Sun, and curves only slightly toward the Sun when the Moon is between the Sun and Earth.

Chapter 12 Gravity Q.13P
Suppose that three astronomical objects (1, 2, and 3) are observed to lie on a line, and that the distance from object 1 to object 3 is D. Given that object 1. has four times the mass of object 3 and seven times the mass of object 2, find the distance between objects 1 and 2 for which the net force on object 2 is zero.
Solution:
Mastering Physics Solutions Chapter 12 Gravity13ps
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Chapter 12 Gravity Q.14P
Find the acceleration due to gravity on the surface of (a) Mercury and (b) Venus.
Solution:
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Chapter 12 Gravity Q.15P
At what altitude above the Earth’s surface is the acceleration due to gravity equal to g/2?
Solution:
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Chapter 12 Gravity Q.16P
Two 6-7-kg bowling balls, each with a radius of 0.11 m, are in contact with one another. What is the gravitational attraction between the bowling balls?
Solution:
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Chapter 12 Gravity Q.17P
What is the acceleration due to Earth’s gravity at a distance from the center of the Earth equal to the orbital radius of the Moon?
Solution:
Mastering Physics Solutions Chapter 12 Gravity17ps

Chapter 12 Gravity Q.18P
Gravity on Titan Titan is the larges t moon o f Saturn and the only moon in the solar system known to have a substantial atmosphere. Find the acceleration due to gravity on Titan’s surface, given that its mass is 1.35 × 1023 kg and its radius is 2570 km.
Solution:
Mastering Physics Solutions Chapter 12 Gravity18ps

Chapter 12 Gravity Q.19P
IP At a certain distance from the center of the Earth, a 4.6-kg object has a weight of 2.2 N. (a) Find this distance, (b) If the object is released at this location and allowed to falï toward the Earth, what is its initial acceleration? (c) If the object is now moved twice as far from the Earth, by what factor does its weight change? Explain, (d) By what factor does its initial acceleration change? Explain.
Solution:
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Chapter 12 Gravity Q.20P
Tine acceleration due to gravity on the Moon’s surface is known to be about one-sixth the acceleration due to gravity on the Earth. Given that the radius of the Moon is roughly one-quarter that of the Earth, find the mass of the Moon in terms of the mass of the Earth.
Solution:
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Chapter 12 Gravity Q.21P
IP An Extraterrestrial Volcano Several volcanoes have been observed erupting on the surface of Jupiter’s closest Galilean moon, lo. Suppose that material ejected from one of these volcanoes reaches a height of 5.00 km a fter being projected straight upward with an initial speed of 134 m/s. Given that the radius of lo is 1820 km, (a) outlinca strategy thatallows you to calculate the mass of To. (b) Use your strategy to calculate Io’s mass.
Solution:
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Chapter 12 Gravity Q.22P
IP Verne’s Trip to the Moon In his novel From the Earth to the Moon, Jules Verne imagined that astronauts inside a spaceship would walk on the floor of the cabin when the force exerted on the ship by the Earth was greater than the force exerted by the Moon. When the force exerted by the Moon was greater, he thought the astronauts would walk on the ceiling of the cabin, (a) At what distance from the center of the Earth would the forces exerted on the spaceship by the Earth and the Moon be equal? (b) Explain why Verne’s description of gravitational effects is incorrect.
Solution:
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Chapter 12 Gravity Q.23P
Consider an asteroid with a radius of 19 km and a mass of 3.35 X 1015 kg. Assume the asteroid is roughly spherical, (a) What is the acceleration due to gravity on the surface of the asteroid? (b) Suppose the asteroid spins about an axis through its center, like the Earth, with a rotational period T. What is the smallest value T can have before loose rocks on the asteroid’s equator begin to fly off the surface?
Solution:
Mastering Physics Solutions Chapter 12 Gravity23ps
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Chapter 12 Gravity Q.24P
CE Predict/Explain The Speed of the Earth The orbital speed of the Earth is greatest around January 4 and least around July 4. (a) Is the distance from the Earth to the Sun on January 4 greater than, less than, or equal to its distance from the Sun on July 4? (b) Choose the best explanation from among the following:
I. The Earth’s orbit is circular, with equal distance from, the Sun at all times.
II. The Earth sweeps out equal area in equal time, thus it must be closer to the Sun when it is moving faster.
III. The greater the speed of the Earth, the greater its distance from the Sun.
Solution:
a) The distance from the Earth to the Sun on January 4, is less than the distance from the Sun on July 4.
b) The Earth sweeps out equal area in equal time, thus it must be closer to the sun when it is moving faster.

Chapter 12 Gravity Q.25P
C E A satellite orbits the Earth in a circular orbit of radius r. At some point its rocket engine is fired in such a way that its speed increases rapidly by a small amount. As a result, do the (a) apogee distance and (b) perigee distance increase, decrease, or stay the same?
Solution:
Use the concept of orbital transfer to place the satellite into a new orbit.
(a)
The decelerating or accelerating rockets at some point in the circular orbit of the satellite would allow the satellite into a new orbit which is not a circle. The new orbit is an ellipse. The largest distance between the Earth and the satellite in an elliptical orbit is called the apogee distance. In the case of transfer of orbits, the apogee distance increases if the speed of the rocket increases a while in the original orbit.
(b)
The smallest distance between the Earth and the satellite in an elliptical orbit is nothing but the perigee distance. In case of transfer of orbits, the perigee distance doesn’t change and equal to the radius of the original circular orbit.

Chapter 12 Gravity Q.26P
g Repeat the previous problem., only this time with the rocket engine of the satellite fired in such a way as to slow the satellite.
Solution:
(A) The satellite drops into an elliptical orbit that brings it closer to Earth.
(B) The apogee distance remains unchanged.
(C) The perigee distance is reduced.

Chapter 12 Gravity Q.27P
CE Predict/Explain The Earth-Moon Distance Is Increasing Laser reflectors left on the surface of the Moon by the Apollo astronauts show that the average distance from the Earth to the Moon is increasing at the rate of 3.8 cm per year. (a) As a result, will the length of the month increase, decrease, or remain the same? (b) Choose the best expianation from among the following: I. The greater the radius of an orbit, the greater the period,
which implies a longer month.
II. The length of the month will remain the same due to conservation of angular momentum,
III. The speed of the Moon is greater with increasing radius; therefore, the length of the month will be less.
Solution:
a) If the average distance increases, then the length of the month also increases.
b) The period depends upon the radius. Greater the radius, greater will be the period. Option (1) is correct.

Chapter 12 Gravity Q.28P
Apollo Missions On Apollq missions to the Moon, the command module orbited at an altitude of 110 km above the lunar surface. How long did it take for the command module to complete one orbit?
Solution:
Mastering Physics Solutions Chapter 12 Gravity28ps

Chapter 12 Gravity Q.29P
Find the orbital speed of a satellite in a geosynchronous circular orbit 3.58 X 107 m above the surface of the Earth.
Solution:
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Chapter 12 Gravity Q.30P
An Extrasolar Planet In July of 1999 a planet was reported to be orbiting the Sun-like star Iota Horologii with a period of 320 days. Find the radius of the planet’s orbi t, assuming that iota Horologii has the same mass as the Sun. (This planet is presumably similar to Jupiter, but it may have large, rocky moons that enjoy a relatively pleasant climate.)
Solution:
Mastering Physics Solutions Chapter 12 Gravity30ps

Chapter 12 Gravity Q.31P
Phobos, one of the moons of Mars, orbits at a distance of 9378 km from the center of the red planet. What is the orbital period of Phobos?
Solution:
Mastering Physics Solutions Chapter 12 Gravity31ps

Chapter 12 Gravity Q.32P
· The largest moon in the solar system is Ganymede, a moon of Jupiter. Ganymede orbits at a distance of 1.07 X 109 m from the center of Jupiter with an orbital period of about 6.18 X 10′ s. Using this information, find the mass of Jupiter.
Solution:
Mastering Physics Solutions Chapter 12 Gravity32ps

Chapter 12 Gravity Q.33P
IP Am Asteroid with Its Own Moon The asteroid 243 Ida has its own small moon, Dactyl. (See the photo on p. 390) (a) Outline a strategy to find the mass of 243 Ida, given that the orbital radius of Dactyl is 89 km arid its period is 19 hr. (b) Use your strategy to calculate the mass of 243 Ida.
Solution:
Mastering Physics Solutions Chapter 12 Gravity33ps

Chapter 12 Gravity Q.34P
GPS Satellites GPS (Global Positioning System) satellites orbit at an altitude of 2.0 x 107 m. Find (a) the orbital period, and (b) the orbital speed of such a satellite.
Solution:
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Chapter 12 Gravity Q.35P
IP Two satellites orbit the Earth, with satellite 1 at a greater altitude than satellite 2. (a) Which satellite has the greater orbital speed? Explain, (b) Calculate the orbital speed of a satellite that orbits at an altitude of one Earth radius above the surface of the Earth, (c) Calculate the orbital speed of a satellite that orbits at an altitude of two Earth radii above the surface of the Earth.
Solution:
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Chapter 12 Gravity Q.36P
IP Calculate the orbital periods of satellites that orbit (a) one Earth radius above the surface of the Earth and (b) two Earth radii above the surface of the Earth, (c) How do your answers to parts (a) and (b) depend on the mass of the satellites? Explain, (d) How do your answers to parts (a) and (b) depend on the mass of the Earth? Explain.
Solution:
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Chapter 12 Gravity Q.37P
S P The Martian moon Deimos has an orbital period that is greater than the other Martian moon, Phobos. Both moons have approximately circular orbits, (a) Is Deimos closer to or farther from Mars than Phobos? Explain, (b) Calculate the distance from the center of Mars to Deimos given that its orbital period is 1.10 × 105 s.
Solution:
Mastering Physics Solutions Chapter 12 Gravity37ps

Chapter 12 Gravity Q.38P
Binary Stars Centauri A and Centauri B are binary stars with a separation of 3.45 × 1012 m and an orbital period of 2.52 × 109 s. Assuming the two stars are equally massive (which is approximately the case), determine their mass.
Solution:
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Chapter 12 Gravity Q.39P
Find the speed of Centauri A and Centauri B, using the information given in the previous problem.
Solution:
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Chapter 12 Gravity Q.40P
Sputnik The first artificial satellite to orbit the Earth was Sputnik I, Saunched October 4,1957. The mass of Sputnik 1 was 83.5 kg, and its distances from the center of the Earth at apogee and perigee were 7330 km-and 6610 km, respectively. Find the difference in gravitational potential energy for Sputnik I as it moved from apogee to perigee.
Solution:
Mastering Physics Solutions Chapter 12 Gravity40ps

Chapter 12 Gravity Q.41P
CE Predict/Explain (a) Is the amount of energy required to get a spacecraft from the Earth to the Moon greater than, less than, or equal to the energy required to get the same spacecraft from the Moon to the Earth? (b) Choose the best explanation from among the following:
I. The escape speed of the Moon is less than that of the Earth; therefore, less energy is required to leave the Moon.
II. The situation is symmetric, and hence the same amount of energy is required to travel in either direction.
III. It takes more energy to go from the Moon to the Earth because the Moon is orbiting the Earth.
Solution:
Use the concept of escape speed of the planet. The escape speed of the planet is the minimum speed at which the object frees from the gravitational attraction of the planet.
(a)
The escape speed of an object launched from the planet depends only on the mass and size of the planet, but not on the mass of the object. The escape speed of the Earth is much greater than that of the Moon. Since the kinetic energy is directly proportional to the square of the velocity, the more energy is required to launch the spacecraft from the Earth to the Moon than that required to launch the spacecraft from the Moon to the Earth.
(b)
The option (I) is correct.

Chapter 12 Gravity Q.42P
Mastering Physics Solutions Chapter 12 Gravity42p
Solution:
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Chapter 12 Gravity Q.43P
Calculate the gravitational potential energy of a 8.8-kg mass (a) on the surface of the Earth and (b) at an altitude of 350 km. (c) Take the difference between the results for parts (b) and (a), and compare with nigh, where h = 350 km.
Solution:
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Chapter 12 Gravity Q.44P
Two 0.59-kg basketballs, each with a radius of 12 cm, are just touching. How much energy is required to change the separation between the centers of the basketballs to (a) 1.0 m and (b) 10.0 m? (Ignore any other gravitational interactions.)
Solution:
Mastering Physics Solutions Chapter 12 Gravity44ps

Chapter 12 Gravity Q.45P
Find the minimum kinetic energy needed for a 39,000-kg rocket to escape (a) the Moon or (b) the Earth.
Solution:
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Chapter 12 Gravity Q.46P
CE Predict/Explain Suppose the Earth were to suddenly shrink to half its current diameter, with its mass remaining constant, (a) Would the escape speed of the Earth increase, decrease, or stay the same? (b) Choose the best explanation from among the following:
I. Since the radius of the Earth would be smaller, the escape speed would also be smaller.
II. The Earth would have the same amount of mass, and hence its escape speed would be unchanged.
III. The force of gravity would be much stronger on the surface of the compressed Earth, leading to a greater escape speed.
Solution:
a) The escape speed of the earth increases.
b) The force of gravity would be much stronger on the surface of compressed Earth, leading to a greater escape speed. Option (III) is correct.

Chapter 12 Gravity Q.47P
CE Is the energy required to launch a rocket vertically to a height h greater than, less than, or equal to the energy required to prit the same rocket into orbit at the height hi Explain.
Solution:
The energy required to launch a rocket vertically to a height h is equal to the potential energy of the rocket at that height. However, for a rocket to be put into orbit at a height h, both kinetic energy and potential energy are required. So the energy required for the rocket to be put into orbit is greater than the energy required to launch a rocket vertically to the same height.

Chapter 12 Gravity Q.48P
Suppose one of the Global Positioning System satellites has a speed of 4.46 km/s at perigee and a speed of 3.64 km/s at apogee. If the distance from the center of the Earth to the satellite at perigee is 2.00 × 104 lem, what is the corresponding distance at apogee?
Solution:
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Chapter 12 Gravity Q.49P
Mastering Physics Solutions Chapter 12 Gravity49p
Solution:
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Chapter 12 Gravity Q.50P
· Referring to Example 12-1, if the Millennium Eagle is at rest at point A, what is its speed at point B?
Solution:
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Chapter 12 Gravity Q.51P
What is the launch speed of a projectile that rises vertically above the Earth to an altitude equal to one Earth radius before coming to rest momentarily?
Solution:
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Chapter 12 Gravity Q.52P
A projectile launched vertically from the surface of the Moon? rises to an altitude of 365 km. What was the projectile’s initial speed?
Solution:
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Chapter 12 Gravity Q.53P
Find the escape velocity for (a) Mercury and (b) Ventis.
Solution:
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Chapter 12 Gravity Q.54P
IP Halley’s Comet Halley’s comet, which passes around the Sun every 76 years, has an elliptical orbit. When closest to the Sun (perihelion) it is at a distance of 8.823 x 1010 m and moves with a speed of 54.6 km/s. The greatest distance between Halley’s comet and the Sun (aphelion) is 6.152 x 1012 m. (a) Is the speed of Halley’s comet greater than or less than 54.6 km/s when it is at aphelion? Explain, (b) Calculate its speed ai aphelion.
Solution:
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Chapter 12 Gravity Q.55P
The End of the Lunar Module On Apollo Moon missions, the lunar module would blast off from the Moon’s surface and dock with the command module in lunar orbit. After docking, the lunar module would be jettisoned and allowed to crash back onto the lunar surface. Seismometers placed on the Moon’s surface by the astronauts would then pick up the resulting seismic waves. Find the impact speed of the lunar module, given that it is jettisoned from an orbit 110 km above the lunar surface moving with a speed of 1630 m/s.
Solution:
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Chapter 12 Gravity Q.56P
If a projectile is launched vertically from the Earth with a speed equal to the escape speed, how high above the Earth’s surface is it when its speed is half the escape speed?
Solution:
Mastering Physics Solutions Chapter 12 Gravity56ps

Chapter 12 Gravity Q.57P
Suppose a planet is discovered orbiting a distant star. If the mass of the planet is 10 times the mass of the Earth, and its radius is one-tenth the Earth’s radius, how does the escape speed of this planet compare with that of the Earth?
Solution:
Mastering Physics Solutions Chapter 12 Gravity57ps

Chapter 12 Gravity Q.58P
A projectile is launched vertically from the surface of the Moon with an initiaL speed of 1050 m/s. At what altitude is the projectile’s speed one-half its initial value?
Solution:
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Chapter 12 Gravity Q.59P
To what radius would the Sun have to be contracted for its escape speed to equal the speed of light? (Black holes have escape speeds greater than the speed of light; hence we see no light from them.)
Solution:
Mastering Physics Solutions Chapter 12 Gravity59ps

Chapter 12 Gravity Q.60P
IP Two baseballs, each with a mass of 0.148 kg, are separated by a distance of 395 m in outer space, far from any other objects. (a) If the balls are released from rest, what speed do they have when their separation has decreased to 145 m? (b) Suppose the mass of the balls is doubled. Would the speed found in part (a) increase, decrease, or stay the same? Explain.
Solution:
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Chapter 12 Gravity Q.61P
On Earth, a person can jump vertically and rise to a height h. What is the radius of the largest spherical asteroid from which this person could escape by jumping straight upward? Assume that each cubic meter of the asteroid has a mass of 3500 kg.
Solution:
Mastering Physics Solutions Chapter 12 Gravity61ps

Chapter 12 Gravity Q.62P
As will be shown in Problem 63, the magnitude of the tidal force exerted on an object of mass m and length a is approximately 4GmMa/r3. In this expression, M is the mass of the body causing the tidal force and r is the distance from the center of m to the center of M. Suppose you are 1 million miles away from a black hole whose mass is a million times that of the Sun. (a) Estimate the tidal force exerted on your body by the black hole. (b) At what distance will the tidal force be approximately 10 times greater than your weight?
Solution:
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Chapter 12 Gravity Q.63P
Mastering Physics Solutions Chapter 12 Gravity63p
Solution:
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Chapter 12 Gravity Q.64P
Mastering Physics Solutions Chapter 12 Gravity64p
Solution:
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Chapter 12 Gravity Q.65GP
CE You weigh yourself on a scale inside an airplane flying due east above the equator. If the airplane now turns around and heads due west with the same speed, will the reading on the scale increase, decrease, or stay the same? Explain.
Solution:
SOLUTION:
The reading on the scale is due to the force of gravity between the person on the plane and the Earth.
F = Gm1m2 / R2
Where R is the difference between the passenger on the plane and the center of the Earth. As the plane switches direction from East to West, the R value remains unchanged. Since the mass of the person and the mass of the Earth are both the same, the magnitude of gravitational force will be the same.

Chapter 12 Gravity Q.66GP
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Solution:
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Chapter 12 Gravity Q.67GP
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Solution:
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Thus the increasing order of gravitational force is given by
object C >object A >object B

Chapter 12 Gravity Q.68GP
Mastering Physics Solutions Chapter 12 Gravity68gp
Solution:
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Chapter 12 Gravity Q.69GP
CE A satellite goes through one complete orbit of the Earth. (a) Is the net work done on it by the Earth’s gravitational force positive, negative, or zero? Explain, (b) Does your answer to part (a) depend on whether the orbit is circular or elliptical?
Solution:
(A) When a satellite goes through one complete orbit, this means the satellite returns to
the initial point at which it started. The resulting net displacement is zero. So the net work done on it by Earth’s gravitational force is zero.
(B) No, the answer to part (A) is independent of the shape of the orbit (i.e., whether the orbit is circular or elliptical). It is dependent on the displacement by the satellite.

Chapter 12 Gravity Q.70GP
CE The Crash of Skylab Skylab, the largest spacecraft ever to fall back to the Earth, met its fiery end on July 11,1979, after flying directly over Everett, WA, on its last orbit. On the CBS Evening News the night before the crash, anchorman Walter Cronkite, in his rich baritone voice, made the following statement: “NASA says there is a little chance that Skylab will land in a populated area.” After the commercial, he immediately corrected himself by saying,”I meant to say ‘there is little chance’ Skylab will hita populated area.” In fact, it landed primarily in the Indian Ocean off the west coast of Australia, though several pieces were recovered near the town of Espérance, Australia, which later sent the U.S. State Department a $400 bill for littering. The cause of Skylab’s crash was the friction it experienced in the upper reaches of the Earth’s atmosphere. As the radius of Skylab’s orbit decreased, did its speed increase, decrease, or stay the same? Explain.
Solution:
The speed of the Skylab increases with decreasing radius. We might think that friction would slow Skylab just like other objects are slowed by friction – but by dropping Skylab to a lower orbit, friction is ultimately responsible for an increase in speed.

Chapter 12 Gravity Q.71GP
Consider a system consisting of three masses on the x axis. Mass m1 = 1.00 kg is at x = 1.00 m; mass m2 = 2.00 kg is at x = 2.00 m; and mass m3 = 3.00 kg is at x = 3.00 m. What is the total gravitational potential energy of this system?
Solution:
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Chapter 12 Gravity Q.72GP
An astronaut exploring a distant solar system lands on an unnamed planet with a radius of 3860 km. When the astronaut jumps upward with an initial speed of 3.10 m/s, she rises to a height of 0.580 m. What is the mass of the planet?
Solution:
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Mastering Physics Solutions Chapter 12 Gravity72gps1

Chapter 12 Gravity Q.73GP
IP When the Moon is in its third-quarter phase, the Earth, Moon, and Sun form a right triangle, as shown in Figure 12-22. Calculate the magnitude of the force exerted on the Moon by (a) the Earth and (b) the Sun. (c) Does it make more sense to think of the Moon as orbiting the Sun, with a small effect due to the Earth, or as orbiting the Earth, with a small effect due to the Sun?
Solution:
Mastering Physics Solutions Chapter 12 Gravity73gps
Mastering Physics Solutions Chapter 12 Gravity73gps1

Chapter 12 Gravity Q.74GP
Mastering Physics Solutions Chapter 12 Gravity74gp
Solution:
Mastering Physics Solutions Chapter 12 Gravity74gps
Mastering Physics Solutions Chapter 12 Gravity74gps1
Mastering Physics Solutions Chapter 12 Gravity74gps2

Chapter 12 Gravity Q.75GP
Mastering Physics Solutions Chapter 12 Gravity75gp
Solution:
Mastering Physics Solutions Chapter 12 Gravity75gps
Mastering Physics Solutions Chapter 12 Gravity75gps1
Mastering Physics Solutions Chapter 12 Gravity75gps2
Mastering Physics Solutions Chapter 12 Gravity75gps3

Chapter 12 Gravity Q.76GP
A Near Miss! In the early morning hours of June 14, 2002, the Earth had a remarkably close encounter with an asteroid the size of a small city. The previously unknown asteroid, now designated 2002 MN, remained undetected until three days after it had passed the Earth. At its closest approach, the asteroid was 73,600 miles from the center of the Earth?about a third of the distance to the Moon. (a) Find the speed of the asteroid at closest approach, assuming its speed at infinite distance to be zero and considering only its interaction with the Barth. (b) Observations indica te the asteroid to have a diameter of about 2.0 km. Estimate the kinetic energy of the asteroid at closest approach, assuming it has an average density of 3.33 g/cm3 (For comparison, a 1-megaton nuclear weapon releases about 5.6 × 1015J of energy.)
Solution:
Mastering Physics Solutions Chapter 12 Gravity76gps
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Mastering Physics Solutions Chapter 12 Gravity76gps2

Chapter 12 Gravity Q.77GP
IP Suppose a planet is discovered that has the same amount of mass in a given volume as the Earth, but has half its radius. (a) Is the acceleration due to gravity on this planet more than, less than, or the same as the acceleration due to gravity on the Earth? Explain. (b) Calculate the acceleration due to gravity on this planet.
Solution:
Mastering Physics Solutions Chapter 12 Gravity77gps

Chapter 12 Gravity Q.78GP
IP Suppose a planet is discovered that has the same total mass as the Earth, but half its radius. (a) Is the acceleration due to gravity on this planet more than, less than, or the same as the acceleration due to gravity on the Earth? Explain. (b) Calculate the acceleration due to gravity on this planet.
Solution:
Mastering Physics Solutions Chapter 12 Gravity78gps

Chapter 12 Gravity Q.79GP
Mastering Physics Solutions Chapter 12 Gravity79gp
Solution:
Mastering Physics Solutions Chapter 12 Gravity79gps
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Chapter 12 Gravity Q.80GP
Mastering Physics Solutions Chapter 12 Gravity80gp
Solution:
Mastering Physics Solutions Chapter 12 Gravity80gps
Mastering Physics Solutions Chapter 12 Gravity80gps1
Mastering Physics Solutions Chapter 12 Gravity80gps2

Chapter 12 Gravity Q.81GP
Mastering Physics Solutions Chapter 12 Gravity81gp
Solution:
Mastering Physics Solutions Chapter 12 Gravity81gps
Mastering Physics Solutions Chapter 12 Gravity81gps1

Chapter 12 Gravity Q.82GP
Using the results from Problem 54. find the angular momentum of Halley’s comet (a) at perihelion and (b) at aphelion (Take the mass of Halley’s comet to be 9.8 x 1014 kg.)
Solution:
Mastering Physics Solutions Chapter 12 Gravity82gps

Chapter 12 Gravity Q.83GP
Exploring Mars Inthe not-too-distant future astronauts will travel to Mars to carry out scientific explorations. As part of their mission, it is likely that a “geosynchronous” satellite will be placed above a given point on the Martian equator to facilitate communications. At what altitude above the surface of Mars should such a satellite orbit? (Note: The Martian “day” is 24.6229 hours, Other relevant information can be found in Appendix C.)
Solution:
Mastering Physics Solutions Chapter 12 Gravity83gps
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Chapter 12 Gravity Q.84GP
IP A satellite is placed in Earth orbit 1000 miles higher than the altitude of a geosynchronous satellite. Referringto Active Example 12-1, we see that the altitude of the satellite is 23,300 mi. (a) Is the period of this satellite greater than or less than 24 hours? (b) As viewed from the surface of the Earth, does the satellite move eastward or westward? Explain. (c) Find the orbital period of this satellite.
Solution:
Mastering Physics Solutions Chapter 12 Gravity84gps
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Chapter 12 Gravity Q.85GP
Find the speed of the Millennium Eagle at point A in Example 12-1 if its speed at point B is 0.905 m/s.
Solution:
Mastering Physics Solutions Chapter 12 Gravity85gps
Mastering Physics Solutions Chapter 12 Gravity85gps1
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Chapter 12 Gravity Q.86GP
Show that the force of gravity between the Moon and the Sun is always greater than the force of gravity between the Moon and the Earth.
Solution:
Mastering Physics Solutions Chapter 12 Gravity86gps
Mastering Physics Solutions Chapter 12 Gravity86gps1

Chapter 12 Gravity Q.87GP
Mastering Physics Solutions Chapter 12 Gravity87gp
Solution:
Mastering Physics Solutions Chapter 12 Gravity87gps

Chapter 12 Gravity Q.88GP
(a) Find the kinetic energy of a 1720-kg satellite in a circular orbit about the Earth, given that the radius of the orbit is 12,600 miles. (b) How much energy is required to move this satellite to a circular orbit with a radius of 25,200 miles?
Solution:
Mastering Physics Solutions Chapter 12 Gravity88gps
Mastering Physics Solutions Chapter 12 Gravity88gps1

Chapter 12 Gravity Q.89GP
IP Space Shuttle Orbit On a typical mission, the space shuttle (m = 2.00 × 106 kg) orbits at an altitude of 250 km above the Earth’s surface. (a) Does the orbital speed of the shuttle depend on its mass? Explain. (b) Find the speed of the shuttle in its orbit. (c) How long does it take for the shuttle to complete one orbit of the Earth?
Solution:
Mastering Physics Solutions Chapter 12 Gravity89gps
Mastering Physics Solutions Chapter 12 Gravity89gps1

Chapter 12 Gravity Q.90GP
IP Consider an object of mass m orbiting the Earth at a radius r. (a) Find the speed of the object. (b) Show that the total mechanical energy of this object is equal to (?1) times its kinetic energy. (c) Does the result of part (b) apply to an object orbiting the Sun? Explain.
Solution:
Mastering Physics Solutions Chapter 12 Gravity90gps
Mastering Physics Solutions Chapter 12 Gravity90gps1

Chapter 12 Gravity Q.91GP
In a binary star system two stars orbit about their common center of mass. Find the orbital period of such a system, given that the stars are separated by a distance d and have masses m and 2m.
Solution:
Mastering Physics Solutions Chapter 12 Gravity91gps
Mastering Physics Solutions Chapter 12 Gravity91gps1
Mastering Physics Solutions Chapter 12 Gravity91gps2

Chapter 12 Gravity Q.92GP
Mastering Physics Solutions Chapter 12 Gravity92gp
Solution:
Mastering Physics Solutions Chapter 12 Gravity92gps
Mastering Physics Solutions Chapter 12 Gravity92gps1
Mastering Physics Solutions Chapter 12 Gravity92gps2
Mastering Physics Solutions Chapter 12 Gravity92gps3
Mastering Physics Solutions Chapter 12 Gravity92gps4

Chapter 12 Gravity Q.93GP
Find an expression for the kinetic energy of a satellite of mass m in an orbit of radius r about a planet of mass M.
Solution:
Mastering Physics Solutions Chapter 12 Gravity93gps
Mastering Physics Solutions Chapter 12 Gravity93gps1

Chapter 12 Gravity Q.94GP
Referring to Example 12-1, find the x component of the net force acting on the Millennium Eagle as a function of x. Plot your result, showing both negative and positive values of x.
Solution:
Mastering Physics Solutions Chapter 12 Gravity94gps
Mastering Physics Solutions Chapter 12 Gravity94gps1

Chapter 12 Gravity Q.95GP
A satellite orbits the Earth in an elliptical orbit. At perigee its distance from the center of the Earth is 22,500 km and its speed is 4280 m/s. At apogee its distance from the center of the Earth is 24,100 km and its speed is 3990 m/s. Using this information, calculate the mass of the Earth.
Solution:
Mastering Physics Solutions Chapter 12 Gravity95gps
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Chapter 12 Gravity Q.96PP
Mastering Physics Solutions Chapter 12 Gravity96gp
Solution:
Mastering Physics Solutions Chapter 12 Gravity96gps
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Chapter 12 Gravity Q.97PP
Mastering Physics Solutions Chapter 12 Gravity97gp
Solution:
Mastering Physics Solutions Chapter 12 Gravity97gps
Mastering Physics Solutions Chapter 12 Gravity97gps1

Chapter 12 Gravity Q.98PP
Mastering Physics Solutions Chapter 12 Gravity98gp
Solution:
Mastering Physics Solutions Chapter 12 Gravity98gps

Chapter 12 Gravity Q.99PP
Mastering Physics Solutions Chapter 12 Gravity99pp
Solution:
Mastering Physics Solutions Chapter 12 Gravity99pps
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Chapter 12 Gravity Q.100IP
Find the orbital radius that corresponds to a “year” of 150 days.
Solution:
Mastering Physics Solutions Chapter 12 Gravity100ips

Chapter 12 Gravity Q.101IP
Suppose the mass of the Sun is suddenly doubled, but the Earth’s orbital radius remains the same. (a) Would the length of an Earth year increase, decrease, or stay the same? (b) Find the length of a year for the case of a Sun with twice the mass. (c) Suppose the Sun retains its present mass, but the mass of the Earth is doubled instead. Would the length of the year increase, decrease, or stay the same?
Solution:
Mastering Physics Solutions Chapter 12 Gravity101ips
Mastering Physics Solutions Chapter 12 Gravity101ips1

Chapter 12 Gravity Q.102IP
(a) If the mass of the Earth were doubled, would the escape speed of a rocket increase, decrease, or stay the same? (b) Calculate the escape speed of a rocket for the case of an Earth with twice its present mass. (c) If the mass of the Earth retains its present value, but the mass of the rocket is doubled, does the escape speed increase, decrease, or stay the same?
Solution:
Mastering Physics Solutions Chapter 12 Gravity102ips
The escape speed depends on the mass of Earth, radius of Earth, and the universal gravitational constant. However, it does not depend on the mass of the rocket.

Chapter 12 Gravity Q.103IP
Suppose the Earth is suddenly shrunk to half its present radius without losing any of its mass. (a) Would the escape speed of a rocket increase, decrease, or stay the same? (b) Find the escape speed for an Earth with half its present radius.
Solution:
Mastering Physics Solutions Chapter 12 Gravity103ips

Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium

Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium

Mastering Physics Solutions

Chapter 11 Rotational Dynamics and Static Equilibrium Q.1CQ
Two forces produce the same torque Does it follow that they have the same magnitude? Explain
Solution:
No, we know that the torque exerted by a tangential force a distance r from the axis of rotation
is t=rF
Here, the torque depends on both the magnitude of force and on the distance from the axis of rotation at which it is applied However because the forces are the same, the torque depends
on the axis of rotationS A small force can produce the same torque as a large force, if it is applied farther from the axis of rotation

Chapter 11 Rotational Dynamics and Static Equilibrium Q.1P
To tighten a spark plug, it is recommended that a torque of 15 N · m be applied. If a mechanic tightens the spark plug with a wrench that is 25 cm long, what is the minimum force necessary to create the desired torque?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium1ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.2CQ
A car pitches down in front when the brakes are applied sharply. Explain this observation in terms of torques.
Solution:
The torque is given by,t = rF
Here, r is the distance of the axis of rotation to the force and F is the tangential force.
When the brakes are applied, it causes the wheels to lock and then the friction plays the role to stop the car. The total force on the car acts on the center of mass but the friction does not be applied on the center of mass of the vehicle and it is applied to the tires. The friction force opposes the motion and its direction is negative and this causes negative torque to be applied to the vehicle which leads to the clockwise rotation of the center of the mass as given by the expression of the torque. This clockwise rotation of the center of the mass causes the front of the car to pitch downward.
The torque by gravity which is in the opposite direction to the torque by friction acts as the restoring torque because the first law of angular motion states that the body will maintain constant angular motion unless the outside torque is acted upon it. Hence, the car pitches down in front when the brakes are applied sharply.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.2P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium2p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium2ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.3CQ
A tightrope walker uses a long pole to aid in balancing. Why?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium3cqs

Chapter 11 Rotational Dynamics and Static Equilibrium Q.3P
A 1.61-kg bowling trophy is held at arm’s length, a distance of 0.605 m from the shoulder joint. What torque does the trophy exert about the shoulder if the arm is (a) horizontal, or (b) at an angle of 22.5° below the horizontal?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium3ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.4CQ
When a motorcycle accelerates rapidly from a stop it sometimes “pops a wheelie”; that is, its front wheel may lift off the ground. Explain this behavior in terms of torques.
Solution:
The moment of inertia is greatest when more mass is at a greater distance from the axis of rotation. Therefore, rotating the body about an axis through the hips results in the larger moment of inertia. This is true since the angular acceleration is inversely proportional to the moment of inertia. It follows that a given torque produces greater angular acceleration when the body rotates about an axis through the spine.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.4P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium4p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium4ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.5CQ
Give an example of a system in which the net torque is zero but the net force is nonzero.
Solution:
A force applied radially to a wheel produces zero torque, though the net force is not zero.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.5P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium5p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium5ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium5ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.6CQ
Give an example of a system in which the net force is zero but the net torqueis nonzero.
Solution:
Consider an airplane propeller or a ceiling fan that is just starting to rotate. In both these cases the net force is zero. Here, the center of mass is not accelerating, but the net torque is non-zero.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.6P
At the local playground, a 16-kg child sits on the end of a horizontal teeter-totter, 1.5 m from the pivot point. On the other side of the pivot an adult pushes straight down on the teeter-totter with a force of 95 N. Tn which direction does the teeter-totter rotate if the adult applies the force at a distance of (a) 3.0 m, (b) 2.5 m, or (c) 2.0 m from the pivot?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium6ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.7CQ
Is the normal force exerted by the ground the same for all four tires on yourcar? Explain.
Solution:
No, because the engine is situated in front in most of the cars. Thus, most of the car’s mass is located in the front of the car, and the center of mass of the car is not located at the center of the
car. It is closer to the front end. This means that more force is exerted on the front tires than on the back tires. Thus, the normal force applied is equal for all four tires.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.7P
Consider the pulley-block systems shown in Conceptual Checkpoint 11-1. (a) Is the tension in the string on the left-hand rotating system greater than, less than, or equal to the weight of the mass attached to that string? (b) Choose the best explanation from among the following:
I. The mass is in free fall once it is released.
II. The string rotates the pulley in addition to supporting the mass.
III. The mass accelerates downward.
Solution:
a) The mass moves in downward directions. So the tension in the string is less than the weight of the mass.
b) The best option is the mass accelerates downwards.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.8CQ
Give two everyday examples of objects that are not in static equilibrium.
Solution:
(i) A truck accelerating from rest is not in static equilibrium because its center of mass is accelerating.
(ii) An airplane propeller that is just starting up is not in static equilibrium because it has an angular acceleration.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.8P
Consider the pulley-block systems shown in Conceptual Checkpoint 11–1. (a) Is the tension in the string on the left-hand rotating system greater than, less than, or equal to the tension in the string on the right-hand rotating system? (b) Choose the best explanation from among the following:
I. The mass in the right-hand system has the greater downward acceleration.
II. The masses are equal.
III. The mass in the left-hand system has the greater downward acceleration.
Solution:
a) The mass in the left hand system drops with small acceleration than the mass in the right hand system. The tension in the left hand string is greater than the tension in the right hand string.
b) The mass in the left hand mass has smaller acceleration. Option (a) is correct.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.9CQ
Give two everyday examples of objects that are in static equilibrium.
Solution:
Conditions for static equilibrium
(i) The net force acting on the object must be zero.
(ii) The net torque acting on the object must be zero.
The examples that meet these conditions are
(1) A physics text book on the table
(2) A person sitting on the chair

Chapter 11 Rotational Dynamics and Static Equilibrium Q.9P
Suppose a torque rotates your body about one of three different axes of rotation: case A, an axis through your spine; case B, an axis through yorrr hips; and case C, an axis through your ankles. Rank these three axes of rotation in increasing order of the angular acceleration produced by the torque. Indicate ties where appropriate.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium9ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium9ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.10CQ
Can an object have zero translational acceleration and, at the same time, have nonzero angular acceleration? if your answer is no, explain why not. If your answer is yes, give a specific example.
Solution:
Yes, an object can have zero translational acceleration with nonzero angular acceleration. An example is a stationary exercise bike, here the wheels do not transport the user anywhere and translational acceleration of the wheels/bike is zero, but through the use of chemical energy the wheels can be rotated faster or slower due to a nonzero angular acceleration.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.10P
A torque of 0.97 N m is applied to a bicycle wheel of radius 35 cm and mass 0.75 kg. Treating the wheel as a hoop, find its angular acceleration.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium10ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.11CQ
Stars form when a large rotating cloud of gas collapses. What happens to the angular speed of the gas cloud as it collapses?
Solution:
When stars are forming, the rotating cloud of gas collapses.
Thus, the radius of rotation decreases.
Therefore, the moment of inertia also decreases. However, we have conservation of angular momentum (L)=lω = constant
Therefore, as I decreases, the angular velocity of the gas cloud increases.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.11P
When a ceiling fan rotating with an angular speed of 2.75 rad/s is turned off, a frictional torque of 0.120 N · m slows it to a stop in 22.5 s. What is the moment of inertia of the fan?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium11ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.12CQ
What purpose does the tail rotor on a helicopter serve?
Solution:
The tail rotor on a helicopter has a horizontal axis of rotationi, as opposed to the vertical axis of the main rotor, therefore, the tail rotor produces a horizontal thrust
that tends to rotate the helicopter about a vertical axis. As a result, if the angular speed of the main rotor is increased or decreased. The tail rotor can exert an opposing torque that prevents the entire helicopter from rotating in the opposite direction

Chapter 11 Rotational Dynamics and Static Equilibrium Q.12
When the play button is pressed, a CD accelerates uniformly from, rest to 450 rev/min in 3.0 revolutions. If the CD has a radius of 6.0 cm and a mass of 17 g, what is the torque exerted on it?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium12ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium12ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.13CQ
Is it possible to change the angular momentum of an object without changing its linear momentum? If your answer is no, explain why not. If your answer is yes, give a specific example.
Solution:
Yes, by keeping its velocity constant. If we change the distances from the axis of rotation r, then we change the angular momentum.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.13P
A person holds a ladder horizontally at its center. Treating the ladder as a uniform rod of length 3.15 m and mass 8.42 kg, find the torque the person must exert on the ladder to give it an angular acceleration of 0.302 rad/s2.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium13ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.14CQ
Suppose a diver springs into the air with no initial angular velocity. Can the diver begin to rotate by folding into atucked position? Explain.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium14cqs

Chapter 11 Rotational Dynamics and Static Equilibrium Q.14P
Awheel on a game show is given aninitiai angular speed of 1.22 rad/s. It comes to rest after rotating through 0.75 of a turn. (a) Find the average torque exerted on the wheel given that it is a disk of radius 0.71 m and mass 6.4 kg. (b) If the mass of the wheel is doubled and its radius is halved, will the angle through which it rotates before coming to rest increase, decrease, or stay the same? Explain. (Assume that the average torque exerted on the wheel is unchanged.)
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium14ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium14ps1
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Chapter 11 Rotational Dynamics and Static Equilibrium Q.15P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium15p
Solution:
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Chapter 11 Rotational Dynamics and Static Equilibrium Q.16P
The L-shaped object described in Problem 15 can be rotated in one of the following three ways: case A, about the x axis; case B, about the y axis; and case C, about the z axis (which passes through the origin perpendicular’ to the plane of the figure). If the same torque r is applied in the of these cases, rank them in increasing order of the resulting angular acceleration. Indicate ties where appropriate.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium16ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium16ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.17P
A motorcycle accelerates from rest, and both the front and rear- tires roll without slipping. (a) Is the force exerted by the ground on the rear tire in the forward or in the backward direction? Explain. (b) Is the force exerted by the ground on the front tire in the forward or in the backward direction? Explain. (c) If the moment of inertia of the front tire is increased, will the motorcycle’s acceleration increase, decrease, or stay the same? Explain.
Solution:
(a) The rear tire rolls forwards such that the force of static friction, opposing motion, points backwards. By Newton’s 3rd law, there is an equal and opposite force, exerted by the ground on the rear tire, pointing forward that counteracts this frictional force.
(b) The front tire rolls forwards such that the force of static friction, opposing motion upon ground contact, points backwards. By Newton’s 3rd law, there is an equal and opposite force, exerted by the ground on the front tire, pointing forward, that counteracts the frictional force.
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium17ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.18P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium18p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium18ps
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Chapter 11 Rotational Dynamics and Static Equilibrium Q.19P
A fish takes the bait and pulls on the line with a force of 2.2 N. The fishing reel, which rotates without friction, is a cylinder of radius 0.055 m and mass 0.99 kg. (a) What is the angular acceleration of the fishing reel? (b) How much line does the fish pull from the reel in 0.25 s?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium19ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium19ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.20P
Repeat the previous problem, only now assume the reel has a friction clutch that exerts a restraining torque of 0.047 N · m.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium20ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium20ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.21P
Suppose the person in Active Example 11-3 climbs higher on the ladder. (a) As a result, is the ladder more likely, less likely, or equally likely to slip? (b) Choose the best explanation from among the following:
I. The forces are the same regardless of the person’s position.
II. The magnitude of f 2 must increase as the person moves upward.
III. When the person is higher, the ladder presses down harder on the floor.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium21ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium21ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium21ps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.22P
A string that passes over a pulley has a 0.321-kg mass attached to one end and a 0.635-kg mass attached to the other end. The pulley, which is a disk of radius 9.40 cm, has friction in its axle. What is the magnitude of the frictional torque that must be exerted by the axle if the system is to be in static equilibrium?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium22ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.23P
To loosen the lid on a jar of jam 8.9 cm in diameter, a torque of 8.5 N · m must be applied to the circumference of the lid. If a jar wrench whose handle extends 15 cm from the center of the jar is attached to the lid, what is the minimum force required to open the jar?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium23ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.24P
Consider the system in Active Example 11-1, this time with the axis of rotation at the location of the child. Write out both the condition for zero net force and the condition for zero net torque. Solve for the two forces.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium24ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium24ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.25P
Referring to the person holding a baseball in Problem 5, suppose the biceps exert just enough upward force to keep the system in static equilibrium. (a) Is the force exerted by the biceps more than, less than, or equal to the combined weight of the forearm, hand, and baseball? Explain. (b) Determine the force exerted by the biceps.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium25ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium25ps1
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Chapter 11 Rotational Dynamics and Static Equilibrium Q.26P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium26ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium26p
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium26p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium26ps1
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Chapter 11 Rotational Dynamics and Static Equilibrium Q.27P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium27p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium27ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium27ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.28P
A schoolyard teeter-totter with a total length of 5.2 m and a mass of 38 kg is pivoted at its center. A 19-kg child sits on one end of the teeter-totter. (a) Where should a parent push vertically downward with a force of 210 N in order to hold the teeter-totter level? (b) Where should the parent push with a force of 310 N? (c) How would your answers to parts (a) and (b) change if the mass of the teeter-totter were doubled? Explain.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium28ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.29P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium29p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium29ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium29ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.30P
A 0.16-kg meterstick is held perpendicular to avertical wall by a 2.5-m string going from the wall to the far end of the stick. (a) Find the tension in the string. (b) If a shorter string is used, will its tension be greater than, less than, or the same as that found in part (a)? (c) Find the tension in a 2.0-m string.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium30ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium30ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium30ps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.31P
Repeat Example 11-4, this time with a uniform diving board that weighs 225 N.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium31ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium31ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium31ps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.32P
Babe Ruth steps to the plate and casually points to left center field to indicate the location of his next home run. The mighty Babe holds his bat across his shoulder, with one hand holding the small end of the bat. The bat is horizontal, and the distance from the small end of the bat to the shoulder is 22.5 cm. If the bat has a mass of 1.10 kg and has a center of mass that is 67.0 cm from the small end of the bat, find the magnitude and direction of the force exerted by (a) the hand and (b) the shoulder.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium32ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium32ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium32ps2
The force exerted by the shoulder on the bat is pointed to the upward direction.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.33P
A uniform metal rod, with a mass of 3.7 kg and a length of 1.2 m, is attached to a wall by a hinge at its base. A horizontal wire bolted to the wall 0.51 m above the base of the rod holds the rod at an angle of 25° above the horizontal. The wire is attached to the top of the rod. (a) Find the tension in the wire. Find (b) the horizontal and (c) the vertical components of the force exerted on the rod by the hinge.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium33ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium33ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.34P
In the previous problem, suppose the wire is shortened, so that the rod now makes an angle of 35° with the horizontal. The wire is horizontal, as before. (a) Do you expect the tension in the wire to increase, decrease, or stay the same as a result of its new length? Explain. (b) Calculate the tension in the wire.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium34ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.35P
Repeat Active Example 11-3, this time with a uniform 7.2-kg ladder that is 4.0 m long.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium35ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium35ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium35ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium35ps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.36P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium36p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium36ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium36ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium36ps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.37P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium37p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium37ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium37ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.38P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium38p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium38ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium38ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium38ps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium38ps3
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium38ps4

Chapter 11 Rotational Dynamics and Static Equilibrium Q.39P
A uniform crate with a mass of 16.2 kg rests on a floor with a coefficient of static friction equal to 0.571. The crate is a uniform cube with sides 1.21 m in length. (a) What horizontal force applied to the top of the crate will initiate tipping? (b) If the horizontal force is applied halfway to the top of the crate, it will begin to slip before it tips. Explain.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium39ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium39ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium39ps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium39ps3

Chapter 11 Rotational Dynamics and Static Equilibrium Q.40P
In the previous problem, (a) what is the minimum height where the force F can be applied so that the crate begins to tip before sliding? (b) What is the magnitude of the force in this case?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium40ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium40ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium40ps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.41P
A hand-held shopping basket 62.0 cm long has a 1.81-kg carton of milk at one end, and a 0.722-kg box of cereal at the other end. Where should a 1.80-kg container of orange juice be placed so that the basket balances at its center?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium41ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium41ps1
Hence, the orange juice container should be placed from center, on the side of cereal carton, at a distance of.18.5cm

Chapter 11 Rotational Dynamics and Static Equilibrium Q.42P
If the cat in Active Example 11-2 has a mass of 2.8 kg, how close to the right end of the two-by-four can it walle before the board begins to tip?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium42ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium42ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.43P
A0.34-kg meterstick balances at its center. If a necklace is suspended from one end of the stick, the balance point moves 9.5 cm toward that end. (a) Is the mass of the necklace more than, less than, or the same as that of the meterstick? Explain. (b) Find the mass of the necklace.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium43ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium43ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.44P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium44p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium44ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium44ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.45P
A baseball bat balances 71.1 cm from one end. If a 0, 560-kg glove is attached to that end, the balance point moves 24.7 cm toward the glove. Find the mass of the bat.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium45ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.46P
A 2.85-kg bucket is attached to a disk-shaped pulley of radius 0.121 m and mass 0.742 kg. If the bucket is allowed to fall, (a) what is its linear acceleration? (b) What is the angular acceleration of the pulley? (c) How far does the bucket drop in 1.50 s?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium46ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium46ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium46ps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.47P
In the previous problem, (a) is the tension in the rope greater than, less than, or equal to the weight of the bucket? Explain. (b) Calculate the tension in the rope.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium47ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium47ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.48P
A child exerts a tangential 42.2-N force on the rim of a disk-shaped merry-go-round with a radius of 2.40 m. If the merry-go-round starts at rest and acquires an angular speed of 0.0860 rev/s in 3.50 s, what is its mass?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium48ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium48ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.49P
You pull downward with a force of 28 N on a rope that passes over a disk-shaped pulley of mass 1.2 kg and radius 0.075 m. The other end of the rope is attached to a 0.67-kg mass. (a) Is the tension in the rope the same on both sides of the pulley? If not, which side has the largest tension? (b) Find the tension in the rope on both sides of the pulley.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium49ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium49ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.50P
Referring to the previous problem, find the linear acceleration of the 0.67-kg mass.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium50ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium50ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium50ps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium50ps3

Chapter 11 Rotational Dynamics and Static Equilibrium Q.51P
A uniform meterstick of mass M has an empty paint can of mass m hangingfrom one end. The meterstick and the can balance at a point 20.0 cm from the end of the stick where the can is attached. When the balanced stick-can system is suspended from a scale, the reading on the scale is 2.54 N. Find the mass of (a) the meterstick and (b) the paint can.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium51ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium51ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium51ps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.52P
Atwood’s Machine An Atwood’s machine consists of two masses, m\ and m-i, connected by a string that passes over a pulley. If the pulley is a disk of radius R and mass M, find the acceleration of the masses.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium52ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium52ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.53P
Calculate the angular momentum of the Earth about its own axis, due to its daily rotation. Assume that the Earth is a uniform sphere.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium53ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.54P
A 0.015-kg record with aradiusof!5 cm rotates with an angular speed of rpm. Find the angular momentum of the record.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium54ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.55P
Tn the previous problem, a 1.1-g fly lands on the rim of the record. What is the fly’s angular momentum?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium55ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium55ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.56P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium56p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium56ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium56ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.57P
Repeat the previous problem for the case of jogger 2, whose speed is 2.68 m/s and whose mass is 58.2 kg.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium57ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium57ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium57ps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.58P
Suppose jogger 3 in Figure 11-33 has a mass of 62.2 kg and a speed of 5.85 m/s. (a) Is the magnitude of the jogger’s angular momentum greater with respect to point A or point B? Explain. (b) Is the magnitude of the jogger’s angular momentum with respect to point B greater than, less than, or the same as it is with respect to the origin, O?Explain. (c) Calculate the magnitude of the jogger’s angular momentum with respect to points A, B, and O.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium58ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium58ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.59P
A torque of 0.12 N m is applied to an egg beater. (a) Tf the egg beater starts at rest, what is its angular momentum after 0.65 s? (b) Tf the moment of inertia of the egg beater is 2.5 × 10−3 kg · m2, what is its angular speed after 0.65 s?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium59ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium59ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.60P
A windmill has an initial angular momentum of 8500 kg · m2 /s. The wind picks up, and 5.86 s later the windmill’s angular momentum is 9700 kg · m2 /s. What was the torque acting on the windmill, assuming it was constant during this time?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium60ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.61P
Two gerbils run in place with a linear speed of 0.55 m/s on an exercise wheel that is shaped like a hoop. Find the angular momentum of the system if the gerbil has a mass of 0.22 kg and the exercise wheel has a radius of 9.5 cm and a mass of 5.0 g.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium61ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium61ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.62P
A student rotates on a frictionless piano stool with his arms outstretched, a heavy weight in the hand. Suddenly he lets go of the weights, and they fall to the floor. As a result, does the student’s angular speed increase, decrease, or stay the same? (b) Choose the best explanation from among the following:
I. The loss of angular momentum when the weights are dropped causes the student to rotate more slowly.
II. The student’s moment of inertia is decreased by dropping the weights.
III. Dropping the weights exerts no torque on the student, but the floor exerts a torque on the weights when they land.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium62ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.63P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium63p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium63ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.64P
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium64p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium64ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium64ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.65P
As an ice skater begins a spin, his angular speed is 3.17 rad/s. After pulling in Ms arms, his angular speed increases to 5.46 rad/s. Find the ratio of the skater’sfinalmoment of inertia to his initial moment of inertia.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium65ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.66P
Calculate both the initial and the final kinetic energies of the system described in Active Example 11-5.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium66ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium66ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.67P
A diver tucks her body in midnight, decreasing her moment of inertia by a factor of two. By what factor does her angular speed change?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium67ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.68P
In the previous problem, (a) does the diver’s kinetic energy increase, decrease, or stay the same? (b) Calculate the ratio of the final kinetic energy to the initial kinetic energy for the diver.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium68ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.69P
A disk-shaped merry-go-round of radius 2.63 m and mass 155 kg rotates freely with an angular speed of 0, 641 rev/s. A 59.4-kg person running tangential to the rim of the merry-go-round at 3.41 m/s jumps onto its rim and holds on. Before jumping on the merry-go-round, the person was moving in the same direction as the merry-go-round’s rim. What is the final angidar speed of the merry-go-round?
Solution:
Mass of the merry-go-round (M) = 155 kg
Radius of the merry-go-round (R) = 2.63 m
Initial angular speed of the merry-go-round
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium69ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.70P
In the previous problem, (a) does the kinetic energy of the system increase, decrease, or stay the same when the person jumps on the merry-go-round? (b) Calculate the initial and final kinetic energies for this system.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium70ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium70ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium70ps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium70ps3
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium70ps4

Chapter 11 Rotational Dynamics and Static Equilibrium Q.71P
A student sits at rest on a piano stool tha t can rotate without friction. The moment of inertia of the student-stool system is 4.1 kg · m2. A second student tosses a 1.5-kg mass with a speed of 2.7 m/s to the student on the stool, who catches it at a distance of 0.40 m from the axis of rotation. What is the resulting angular speed of the student and the stool?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium71ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.72P
Referring to the previous problem, (a) does the kinetic energy of the mass-student-stool system increase, decrease, or stay the same as the mass is caught? (b) Calculate the initial and final kinetic energies of the system.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium72ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium72ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.73P
A turntable with a moment of inertia of 5.4 × 10 −3 kg-m2 rotates freely with an angular speed of rpm. Riding on the rim of the turntable, 15 cm from the center, is a cute, 32-g mouse. (a) if the mouse walks to the center of the turntable, will the turntable rotate faster, slower, or at the same rate? Explain. (b) Calculate the angular speed of the turntable when the mouse rthees the center.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium73ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium73ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium73ps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.74P
A student on a piano stool rotates freely with an angular speed of 2.95 rev/s. The student holds a 1.25-kg mass in the outstretched arm, 0.759 m from the axis of rotation. The combined moment of inertia of the student and the stool, ignoring the two masses, is 5.43 kg -m2, a value that remains constant. (a) As the student pulls his arms inward, his angular speed increases to 3.54 rcv/s. How farare the masses from the axis of rotation at this time, considering the masses to be points? (b) Calculate the initial and final kinetic energies of the system.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium74ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium74ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.75P
A child of mass m tands at rest near the rim of a stationary merry-go-round of radius R and moment of inertia I. The child now begins to walk around the circumference of the merry-go-round with a tangential speed v with respect to the merry-go-round’s surface. (a) What is the child’s speed with respect to the ground? Check your results in the limits (b) I → 0 and (c) I →∞
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium75ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium75ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium75ps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.76P
Two spheres of equal mass and radius are rolling across the floor with the same speed. Sphere 1 is a uniform solid; sphere 2 is hollow. Is the work required to stop sphere 1 greater than, less than, or equal to the work required to stop sphere 2? (b) Choose the best explanation from among the following:
I. Sphere 2 has the greater moment of inertia and hence the greater rotational kinetic energy.
II. The spheres have equal mass and speed; therefore, they have the same kinetic energy.
III. The hollow sphere has less kinetic energy.
Solution:
The mass, radius and speed of the both balls are same. The kinetic energy of the hallow sphere is more than the kinetic energy of the sold sphere. According to work energy theorem, the work done would be greater for ball that posses more kinetic energy. So Work required to stop sphere1 is less than the work done to stop sphere2. The moment of inertia of the of the hallow ball is greater and hence the greater rotational kinetic energy.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.77P
How much work must be done to accelerate a baton from rest to an angular speed of 7.4 rad/s about its center? Consider the baton to be a uniform rod of length 0.53 m and mass 0.44 kg.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium77ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.78P
Turning a doorknob through. 0.25 of a revolution requires 0.14 J of work. What is the torque required to turn the doorknob?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium78ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.79P
A person exerts a tangential force of 36.1 N on the rim of a disk-shaped merry-go-round of radius 2.74 m and mass 167 kg. If the merry-go-round starts at rest, what is its angular speed after the person has rotated it through an angle of 32.5°?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium79ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium79ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium79ps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium79ps3

Chapter 11 Rotational Dynamics and Static Equilibrium Q.80P
To prepare homemade ice cream, a crank must be turned with a torque of 3.95 N· m. How much work is required for the complete turn of the crank?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium80ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.81P
A popular make of dental drill can operate at a speed of 42, 500 rpm while producing a torque of 3.68 oz · in. What is the power output of this drill? Give your answer in watts.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium81ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.82P
The L-shaped object in Figure 11-24 consists of three masses connected by light rods. Find the work that must be done on this object to accelerate it from rest to an angular speed of 2.35 rad/s about (a) the x axis, (b) the y axis, and (c) the z axis (which is through the origin and perpendicular to the page).
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium82ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium82ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium82ps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium82ps3

Chapter 11 Rotational Dynamics and Static Equilibrium Q.83P
The rectangular object in Figure 11-25 consists of four masses connected by light rods. What power must be applied to this object to accelerate it from rest to an angular speed of 2.5 rad/s in 6.4 s about (a) the x axis, (b) the y axis, and (c) the z axis (which is through the origin and perpendicular to the page)?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium83ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium83ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium83ps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium83ps3
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium83ps4
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium83ps5
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium83ps6

Chapter 11 Rotational Dynamics and Static Equilibrium Q.84P
A circular saw blade accelerates from rest to an angular speed of 3620 rpm in 6.30 revolutions. (a) Find the torque exerted on the saw blade, assuming it is a disk of radius 15.2 cm and mass 0.755 kg. (b) Is the angular speed of the saw blade after 3.15 revolutions greater than, less than, or equal to 1810 rpm? Explain. (c) Find the angular speed of the blade after 3.15 revolutions.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium84ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium84ps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium84ps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.85GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium85p
Solution:
a) From the given figure, if the paper is pulled horizontally to the right, then the disk rotates in a counterclockwise direction because the force is exerted to the right on the bottom of the disk.
b) The center of the disk moves toward the right because the paper is pulled to the right. This is the direction of the net force exerted on the disk.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.86GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium86p
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium86ps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.87GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium87p
Solution:
(a) When the block is allowed to fall, the block moves towards the left.
(b) The wheel has larger moment of inertia and smaller angular acceleration. Therefore the string unwinds from the wheel more slowly than the disk, and so the block moves to the left.
Option (II) is correct.

Chapter 11 Rotational Dynamics and Static Equilibrium Q.88GP
A beetle sits at the rim of a turntable that is at rest but is free to rotate about a vertical axis. Suppose the beetle now begins to walk around the perimeter of the turntable. Does the beetle move forward, backward, or does it remain in the same location relative to the ground? Answer for two different cases, (a) the turntable is much more massive than the beetle and (b) the turntable is massless.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium88ps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium88ps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.89GP
A beetle sits near the rim of a turntable that is rotating without friction about a vertical axis. The beetle now begins to walk toward the center of the turntable. As a result, does the angular speed of the turntable increase, decrease, or stay the same? Explain.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium89gps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.90GP
Suppose the Earth were to magically expand, doubling its radius while keeping its mass the same. Would the length of the day increase, decrease, or stay the same? Explain.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium90gps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.91GP
After getting a drink of water, a hamster jumps onto an exercise wheel for a run. A few seconds later the hamster is running in place with a speed of 1, 3 m/s. Find the work done by the hamster to get the exercise wheel moving, assuming it is a hoop of radius 0.13 m and mass 6.5 g.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium91gp

Chapter 11 Rotational Dynamics and Static Equilibrium Q.92GP
A 47.0-kg unif orm rod 4.25 m long is attached to a wall with a hinge at one end. The rod is held in a horizontal position by, a wire attached to its other end. The wire makes an angle of 30.0° with the horizontal, and is bolted to the wall directly above the hinge. If the wire can withstand a maximum tension of 1450 N before breaking, how far from the wall can a 68.0-kg person sit without breaking the wire?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium92gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium92gps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium92gps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium92gps3

Chapter 11 Rotational Dynamics and Static Equilibrium Q.93GP
A puck attached to a string moves in a circular path on a frictionless surface, as shown in Figure 11–34. Initially, the speed of the puck is v and the radius of the circle is r. If the string passes through ahole in the surface, and is pulled downward until the radius of the eircularpath is r /2, (a) does the speed of the puck increase, decrease, or stay the same? (b) Calculate the final speed of the puck.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium93gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium93gps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.94GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium94gp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium94gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium94gps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium94gps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium94gps3

Chapter 11 Rotational Dynamics and Static Equilibrium Q.95GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium95gp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium95gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium95gps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.96GP
Auto mechanics use the following formula to calculate the horsepower (HP) of a car engine: In this expression, Torque is the torque produced by the engine in ft · lb, RPM is the angular speed of the engine in revolutions per minute, and C is a dimensionless constant. (a) Find the numerical value of C. (b) The Shelby Series 1 engine is advertised to generate 320 hp at 6500 rpm. What is the corresponding torque produced by this engine? Give your answer in ft · lb.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium96gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium96gps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.97GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium97gp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium97gps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.98GP
You hold a uniform, 28-g pen horizontal with your thumb pushing down on one end and your index finger pushing upward 3.5 cm from, your thumb. The pen is 14 cm long. (a) Which of these two forces is greater in magnitude? (b) Find the two forces.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium98gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium98gps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.99GP
In Active Example 11-3, suppose the ladder is uniform, 4.0 m long, and weighs 60.0 N. Find the forces exerted on the ladder when the person is (a) halfway up the ladder and (b) three-fourths of the way up the ladder.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium99gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium99gps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium99gps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium99gps3
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium99gps4
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium99gps5

Chapter 11 Rotational Dynamics and Static Equilibrium Q.100GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium100gp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium100gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium100gps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.101GP
A 67, 0-kg person stands on a lightweight diving board supported by two pillars, one at the end of the board, the other 1.10 m away. The pillar at the end of the board exerts a downward force of 828 N. (a) How far from that pillar is the person standing? (b) Find the force exerted by the second pillar.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium101gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium101gps1
Therefore, the force exerted by the second pillar is.1.49KN

Chapter 11 Rotational Dynamics and Static Equilibrium Q.102GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium102gp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium102gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium102gps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.103GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium103gp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium103gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium103gps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium103gps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium103gps3
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium103gps4

Chapter 11 Rotational Dynamics and Static Equilibrium Q.104GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium104gp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium104gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium104gps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium104gps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.105GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium105gp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium105gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium105gps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium105gps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium105gps3
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium105gps4

Chapter 11 Rotational Dynamics and Static Equilibrium Q.106GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium106gp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium106gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium106gps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium106gps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.107GP
Suppose a fourth book, the same as the other three, is added to the stack of books shown in Figure 11-32. (a) What is the maximum overhang distance, d, in this case? (b) If the mass of the book is increased by the same amount, does your answer to part (a) increase, decrease, or stay the same? Explain.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium107gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium107gps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium107gps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.108GP
Suppose partial melting of the polar ice caps increases the moment of inertia of the Earth from 0.331 M E R E 2 to 0.332 M E R E 2. (a) Would the length of a day (the time required for the Earth to complete one revolution about its axis) increase or decrease? Explain. (b) Calculate the change in the length of a day. Give your answer in seconds.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium108gps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.109GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium109gp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium109gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium109gps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.110GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium110gp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium110gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium110gps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium110gps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.111GP
In Problem, assume that the rod has a mass of M and that its bottom end simply rests on the floor, held in place by static friction. If the coefficient of static friction is μs, find the maximum force F that can be applied to the rod at its midpoint before it slips.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium111gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium111gps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.112GP
In the previous problem, suppose the rod has a mass of 2.3 kg and the coefficient of static friction is 1/7. (a) Find the greatest force F that can be applied at the midpoint of the rod without causing it to slip. (b) Show that if F is applied 1/8 of the way down from the top of the rod, it will never slip at all, no matter how large the force F.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium112gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium112gps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium112gps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.113GP
A cylinder of mass m and radius r has a string wrapped around its circumference. The upper end of the string is held fixed, and the cylinder is allowed to fall. Show that its linear acceleration is (2/3)g.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium113gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium113gps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium113gps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.114GP
Repeat the previous problem, replacing the cylinder with a solid sphere. Show that its linear acceleration is (5/7)g.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium114gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium114gps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.115GP
A mass M is attached to a rope that passes over a disk-shaped pulley of mass m and radius r. The mass hangs to the left side of the pulley. On the right side of the pulley, the rope is pulled downward with a force F. Find (a) the acceleration of the mass, (b) the tension in the rope on the left side of the pulley, and (c) the tension in the rope on the right side of the pulley, (d) Check your results in the limits m → 0 and m →∞.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium115gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium115gps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.116GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium116gp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium116gps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium116gps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.117GP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium117pp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium117pps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium117pps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium117pps2

Chapter 11 Rotational Dynamics and Static Equilibrium Q.118PP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium118pp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium118pps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium118pps1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium118pps2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium118pps3

Chapter 11 Rotational Dynamics and Static Equilibrium Q.119PP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium119pp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium119pps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium119pps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.120PP
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium120pp
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium120pps

Chapter 11 Rotational Dynamics and Static Equilibrium Q.121IP
Suppose the mass of the pulley is doubled, to 0.160 kg, and that everything else in the system remains the same. (a) Do you expect the value of T 2 to increase, decrease, or stay the same? Explain, (b) Calculate the value of T 2 for this case.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium121pps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium121pps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.122IP
Suppose the mass of the cart is doubled, to 0.62 kg, and that everything else in the system remains the same. (a) Do you expect the value of T 2 to increase decrease, or stay the same? Explain. (b) Calculate the value of T 2 for this case.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium122pps
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium122pps1

Chapter 11 Rotational Dynamics and Static Equilibrium Q.123IP
Suppose the child runs with a different initial speed, but that everything else in the system remains the same. What initial speed does the child have if the angular speed of the system after the collision is 0.425 rad/s?
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium123ips

Chapter 11 Rotational Dynamics and Static Equilibrium Q.124IP
Suppose everything in the system is as described in Active Example 11-5 except that the child approaches the merry-go-round in a direction that is not tangential Find the angle θ between the direction of motion and the outward radial direction (as in Example 11-8) that is required if the final angular speed of the system is to be 0.272 rad/s.
Solution:
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium124ips
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium124ips1
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium124ips2
Mastering Physics Solutions Chapter 11 Rotational Dynamics and Static Equilibrium124ips3

Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy

Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy

Mastering Physics Solutions

Chapter 10 Rotational Kinematics and Energy Q.1CQ
A rigid object rotates about a fixed axis Do all points on the object have the same angular speed? Do all points on the object have the same linear speed? Explain
Solution:
Yes, all points on the rigid object have the same angular speed. but the linear speed is not the same at all points The linear speed near the point of the axis of rotation will be lower relative to
points further away from the axis of rotation Thus, it can be increased by increasing the distance away from the axis of rotation (v =r ω)

Chapter 10 Rotational Kinematics and Energy Q.1P
The following angles are given in degrees. Convert them to radians: 30°, 45°, 90°, 180°.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy1ps

Chapter 10 Rotational Kinematics and Energy Q.2CQ
Can you drive your car in such a way that your tangential acceleration is zero while at the same time your centripetal acceleration is nonzero? Give an example if your answer is yes. state why not if your answer is no.
Solution:
Yes Tangential acceleration is caused by a changing tangential speed. while centripetal acceleration is caused by a changing direction of motion. If you drive a car in a circular path with constant speed. tangential acceleration is zero while centripetal acceleration is non-zero

Chapter 10 Rotational Kinematics and Energy Q.2P
The following angles are given in radians. Convert them to degrees: π/6, 0.70π, 1.5π, 5π.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy2ps

Chapter 10 Rotational Kinematics and Energy Q.3CQ
Can you drive your car in such a way that your tangential acceleration is nonzero while at the same time your centripetal acceleration is zero? Give an example if your answer is yes. state why not if your answer is no.
Solution:
If you are traveling in a circular path. your centripetal acceleration is always non zero So it is not possible to have zero centripetal acceleration If you are traveling in a straight path. the centripetal acceleration does not arise at all So it is not relevant

Chapter 10 Rotational Kinematics and Energy Q.3P
Find the angular speed of (a) the minute hand and (b) the hour hand of the famous clock in London, England, that rings the bell known as Big Ben.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy3ps

Chapter 10 Rotational Kinematics and Energy Q.4CQ
The fact that the Earth rotates gives people in New York a linear speed of about 750 mi/hrn Where should you stand on the Earth to have the smallest possible linear speed?
Solution:
We should stand on Earth’s poles for the smallest possible linear speed (v) This is because Earth has a constant angular speed. and the distance from the axis of rotation at the poles is the smallest compared to other places on Earth (v =r ω)

Chapter 10 Rotational Kinematics and Energy Q.4P
Express the angular velocity of the second hand on a clock in trie following units: (a) rev/hr, (b) deg/min, and (c) rad/s.
Solution:
Time taken by the second hand to complete one revolution(T) = 60s=1min
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy4ps

Chapter 10 Rotational Kinematics and Energy Q.5CQ
At the local carnival you and a friend decide to take a ride on the Ferris wheel. As the wheel rotates with a constant angular speed, your friend poses the following questions: (a) is my linear velocity constant? (b) Is my linear speed constant? (c) is the magnitude of my centripetal acceleration constant? (d) Is the direction of my centripetal acceleration constant? What is your answer to each of these questions?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy5cqs

Chapter 10 Rotational Kinematics and Energy Q.5P
Rank the following inorder of increasing angular speed: an automobile tire rotating at 2.00 × 103 deg/s, an electric drill rotating at 400.0 rev/min, and an airplane propeller rotating at 40.0 rad/s.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy5ps

Chapter 10 Rotational Kinematics and Energy Q.6CQ
Why should changing the axis of rotation of an object change its moment of inertia, given that its shape and mass remain the same?
Solution:
We know that the moment of inertia of an object depends on its mass, shape. and siz4 By changing the axis of rotation, the size of the object will also change (distance from the axis of rotation) Therefore, the moment of inertia of the object changes

Chapter 10 Rotational Kinematics and Energy Q.6P
A spot of paint on a bicycle tire moves in a circular path of radius 0.33 m. When the spot has traveled a linear distance of 1.95 m, through what angle has the tire rotated? Give your answer in radians.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy6ps

Chapter 10 Rotational Kinematics and Energy Q.7CQ
Give a common, everyday example for each of the following: (a) An object that has zero rotational kinetic energy but nonzero translational kinetic energy. (b) An object that has zero translational kinetic energy but nonzero rotational kinetic energy. (c) An object that has nonzero rotational and translational kinetic energies.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy7cqps

Chapter 10 Rotational Kinematics and Energy Q.7P
What is the angular speed (in rev/min) of the Earth as it orbits about the Sun?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy7ps

Chapter 10 Rotational Kinematics and Energy Q.8CQ
Two spheres have identical radii and masses. How might you tell which of these spheres is hollow and which is solid?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy8cqs

Chapter 10 Rotational Kinematics and Energy Q.8P
Find the angular speed of the Earth as it spins about its axis. Give your result in rad/s.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy8ps

Chapter 10 Rotational Kinematics and Energy Q.9CQ
At the grocery store you pick up a can of beef broth and a can of chunky beef stew. The cans are identical in diameter and. weight. Rolling both of them down the aisle with the same initial speed, you notice that the can of chunky stew rolls much farther than the can of broth. Why?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy9cqs

Chapter 10 Rotational Kinematics and Energy Q.9P
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy9p
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy9ps

Chapter 10 Rotational Kinematics and Energy Q.10CQ
Suppose we change the race shown in Conceptual Checkpoint 10-4 so that a hoop of radius R and mass M races a hoop of radius R and mass 2M. (a) Does the hoop with mass M finish before, after, or at the same time as the hoop with mass 2M? Explain. (b) How would your answer to part (a) change if the hoops had different radii? Explain.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy10cqs

Chapter 10 Rotational Kinematics and Energy Q.10P
A 3.5-inch floppy disk in a computer rotates with a period of 2.00 × 10− 1 s. What are (a) the angular speed of the disk and (b) the linear speed of a point on the rim of the disk? (c) Does a point near the center of the disk have an angular speed that is greater than, less than, or the same as the angular speed found in part (a)? Explain. (Note: A 3.5-inch floppy disk is 3.5 inches in diameter.)
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy10ps

Chapter 10 Rotational Kinematics and Energy Q.11P
The angle an airplane propeller makes with the horizontal as a function of time is given by θ = (125 rad/s)t + (42.5 rad/s2)t 2. (a) Estimate the instantaneous angular velocity at t = 0.00 s by calculating the average angular velocity from t = 0.00 s to t = 0.010 s. (b) Estimate the instantaneous angular velocity at t − 1.000 s by calculating the average angular velocity from t = 1.000 s to t = 1.010 s. (c) Estimate the instantaneous angular velocity at t = 2.000 s by calculating the average angular velocity from t = 2.000 s to t = 2.010 s. (d) Based on your results from parts (a), (b), and (c), is the angular acceleration of the propeller positive, negative, or zero? Explain. (e) Calculate the average angular acceleration from t = 0.00 s to t − 1.00 s and from t = 1.00 s to t = 2.00 s.
SECTION 10-2 ROTATIONAL KINEMATICS
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy11ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy11ps1
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy11ps2
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy11ps3

Chapter 10 Rotational Kinematics and Energy Q.12
An object at rest begins to rotate with a constant angular acceleration. If this object rotates through an angle θ in the time t, through what angle did it rotate in the time t /2?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy12ps

Chapter 10 Rotational Kinematics and Energy Q.13P
An object at rest begins to rotate with a constant angular acceleration. If the angular speed of the object is w after the time t, what was its angular speed at the time t /2?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy13ps

Chapter 10 Rotational Kinematics and Energy Q.14P
In Active Example, how long does it take before the angular velocity of the pulley is equal to −5.0 rad/s?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy14ps

Chapter 10 Rotational Kinematics and Energy Q.15P
In Example, through what angle has the wheel turned when its angular speed is 2.45 rad/s?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy15ps

Chapter 10 Rotational Kinematics and Energy Q.16P
The angular speed of a propeller on a boat increases with constant acceleration from 12 rad/s to 26 rad/s in 2.5 revolutions. What is the acceleration of the propeller?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy16ps

Chapter 10 Rotational Kinematics and Energy Q.17P
The angular speed of a propeller on a boat increases with constant acceleration from 11 rad/s to 28 rad/s in 2.4 seconds. Through what angle did the propeller turn during this time?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy17ps

Chapter 10 Rotational Kinematics and Energy Q.18P
After fixing a flat tire on a bicycle you give the wheel a spin. (a) If its initial angular speed was 6.35 rad/s and it rotated 14.2 revolutions before coming to rest, what was its average angular acceleration? (b) For what length of time did the wheel rotate?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy18ps

Chapter 10 Rotational Kinematics and Energy Q.19P
A ceiling fan is rotating at 0.96 rev/s. When turned off, it slows uniformly to a stop in2.4 min. (a) How many revolutions does the fan make in this time? (b) Using the result from part (a), find the number of revolutions the fan must make for its speed to decrease from 0.96 rev/s to 0.48 rev/s.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy19ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy19ps1

Chapter 10 Rotational Kinematics and Energy Q.20P
A discus thrower starts from rest and begins to rotate with a constant angular acceleration of 2.2 rad/s2, (a) How many revolutions does it take for the discus thrower’s angular speed to rthe 6.3 rad/s? (b) How much time does this take?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy20ps

Chapter 10 Rotational Kinematics and Energy Q.21P
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy21p
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy21ps

Chapter 10 Rotational Kinematics and Energy Q.22P
A centrifuge is a common laboratory instrument that separates components of differing densities in solution. This is accomplished by spinning a sample around in a circle with a large angular speed. Suppose that after a centrifuge in a medical laboratory is turned off, it continues to rotate with a constant angular deceleration for 10.2 s before coming to rest. (a) If its initial angular speed was 3850 rpm, what is the magnitude of its angular deceleration? (b) How many revolutions did the centrifuge complete after being turned off?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy22ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy22ps1

Chapter 10 Rotational Kinematics and Energy Q.23P
The Earth’s rate of rotation is constantly decreasing, causing the day to increase in duration. In the year 2006 the Earth took about 0.840 s longer to complete 365 revolutions than it did in the year 1906. What was the average angular acceleration of the Earth during this time? Give your answer in rad/s.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy23ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy23ps1

Chapter 10 Rotational Kinematics and Energy Q.24P
A compact disk (CD) speeds up uniformly from rest to 310 rpm in 3.3 s. (a) Déscribe a strategy that allows you to calculate the number of revolutions the CD makes in this time. (b) Use your strategy to find the number of revolutions.
Solution:
a) The CD moves speeds up with uniform velocity. Initially we determine the angular acceleration to determine the angular displacement.
b) The angular acceleration of the compact disc which speeds up uniformly is given from the equation 10-8 is
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy24ps

Chapter 10 Rotational Kinematics and Energy Q.25P
When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4440 rpm to 0.00 rpm in 2.50 s. (a) What is the angular acceleration of the blade? (b) What is the distance traveled by a point on the rim of the blade during the deceleration? (c) What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy25ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy25ps1
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy25ps2

Chapter 10 Rotational Kinematics and Energy Q.26P
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy26p
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy26ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy26ps1

Chapter 10 Rotational Kinematics and Energy Q.27P
Two children, Jason and Betsy, ride on the same merry-go-round. Jason is a distance R from, the axis of rotation; Betsy is a distance 2R from the axis. Is the rotational period of Jason greater than, less than, or equal to the rotational period of Betsy? (b) Choose the best explanation from among the following:
I. The period is greater for Jason because he moves more slowly than Betsy.
II. The period is greater for Betsy since she must go around a circle with a larger circumference.
III. It takes the same amount of time for the merry-go-round to complete a revolution for all points on the merry-go-round.
Solution:
a) The rotational period of Jason is equal to the rotational period of Betsy.
b) The angular speed of the merry go round is constant and the period is constant for every point on it. So option III is correct explanation.

Chapter 10 Rotational Kinematics and Energy Q.28P
Referring to the previous problem, what are (a) the ratio of Jason’s angular speed to Betsy’s angular speed, (b) the ratio of Jason’s linear speed to Betsy’s linear speed, and (c) the ratio of Jason’s centripetal acceleration to Betsy’s centripetal acceleration?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy28ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy28ps1

Chapter 10 Rotational Kinematics and Energy Q.29P
The world’s tallest building is the Taipei 101 Tower in Taiwan, which rises to a height of 508 m (1667 ft). (a) When standing on the top floor of the building, is your angular speed due to the Earth’s rotation greater than, less than, or equal to your angular speed when you stand on the ground floor? (b) Choose the best explanation from among the following;
I. The angular speed is the same at all distances from the axis of rotation.
II. At the top of the building you are farther from the axis of rotation and hence you have a greater angular speed.
III. You are spinning faster when you are closer to the axis of rotation.
Solution:
a) The angular speed of the earth rotation is equal.
b) Our angular speed due to Earth’s rotation is same at every point on the earth irrespective of the elevation. So your angular speed due to earth’s rotation on the top floor of the building will be same as it is on the ground floor. Option I is correct.

Chapter 10 Rotational Kinematics and Energy Q.30P
The hour hand on a certain clock is 8.2 cm long, Find the tangential speed of the tip of this hand.
Solution:
The tangential speed in case of circular motion is, v =rω Here, r represents radius and ω represents angular velocity.
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy30ps

Chapter 10 Rotational Kinematics and Energy Q.31P
Two children ride on the merry-go-round shown in Conceptual Checkpoint 10-1. Child 1 is 2.0 m from the axis of rotation, and child 2 is 1.5 m from the axis. If the merry-go-round completes one revolution every 4.5 s, find (a) the angular speed and (b) the linear speed of the child,
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy31ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy31ps1

Chapter 10 Rotational Kinematics and Energy Q.32P
The outer edge of a rotating Frisbee with a diameter of 29 cm has a linear speed of 3.7 m/s. What is the angular speed of the Frisbee?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy32ps

Chapter 10 Rotational Kinematics and Energy Q.33P
A carousel at the local carnival rotates once every 45 seconds. (a) What is the linear speed of an outer horse on the carousel, which is 2.75 m from the axis of rotation? (b) What is the linear speed of an inner horse that is 1.75 m from the axis of rotation?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy33ps

Chapter 10 Rotational Kinematics and Energy Q.34P
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy34p
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy34ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy34ps1

Chapter 10 Rotational Kinematics and Energy Q.35P
Suppose, in Problem 34, that at some point inhis swing Jeff of the Jungle has an angular speed of 0.850 rad/s and an angular acceleration of 0.620 rad/s2. Find the magnitude of his centripetal, tangential, and total accelerations, and the angle his total acceleration makes with respect to the tangential direction of motion.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy35ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy35ps1

Chapter 10 Rotational Kinematics and Energy Q.36P
A compact disk, which has a diameter of 12.0 cm, speeds up uniformly from 0.00 to 4.00 rev/s in 3.00 s. What is the tangential acceleration of a point on the outer rim of the disk at the moment when its angular speed is (a) 2.00 rev/s and (b) 3.00 rev/s?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy36ps

Chapter 10 Rotational Kinematics and Energy Q.37P
When a compact disk with a 12.0-cm diameter is rotating at 5.05 rad/s, what are (a) the linear speed and (b) the centripetal acceleration of a point on its outer rim? (c) Consider a point on the CD that is halfway between its center and its outer rim. Without repeating all of the calculations required for parts (a) and (b), determine the linear speed and the centripetal acceleration of this point.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy37ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy37ps1

Chapter 10 Rotational Kinematics and Energy Q.38P
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy38p
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy38ps

Chapter 10 Rotational Kinematics and Energy Q.39P
A Ferris wheel with a radius of 9.5 rotates a constant rate, completing one revolution every 36 second. Find the direction and a passenger’s acceleration when (a) at the top and (b) at the bottom of the wheel.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy39ps
Chapter 10 Rotational Kinematics and Energy Q.40P
Suppose the Ferris wheel in the previous problem begins to decelerate at the rate of 0.22 rad/s2 when the passenger is at the top of the wheel. Find the direction and magnitude of the passenger’s acceleration at that time.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy40ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy40ps1

Chapter 10 Rotational Kinematics and Energy Q.41P
A person swings a 0.52-kg tether ball tied to a 4.5-m rope in an approximately horizontal circle. (a) If the maximum tension the rope can withstand before breaking is 11 N, what is the maximum angular speed of the ball? (b) If the rope is shortened, doea the maximum angular speed found in part (a) increase, decrease, or stay the same? Explain.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy41ps

Chapter 10 Rotational Kinematics and Energy Q.42P
To polish a filling, a dentist attaches a sanding disk with a radius of 3.20 mm to the drill. (a) When the drill is operated at 2.15 × 104 rad/s, what is the tangential speed of the rim of the disk? (b) What period of rotation must the disk have if the tangential speed of its rim is to be 275 m/s?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy42ps

Chapter 10 Rotational Kinematics and Energy Q.43P
In the previous problem, suppose the disk has an angular acceleration of 232 rad/s2 when its angular speed is 640 rad/s. Find both the tangential and centripetal accelerations of a point on the rim of the disk.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy43ps

Chapter 10 Rotational Kinematics and Energy Q.44P
The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proton. In the lowest-energy orbitthe distance from the proton to the electron is 5.29 × 10−11 m, and die linear speed of the electron is 2. 18 × 106 m/s. (a) What is the angular speed of the electron? (b) How many orbits about the proton does it make the second? (c) What is the electron’s centripetal acceleration?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy44ps

Chapter 10 Rotational Kinematics and Energy Q.45P
A wheel of radius R starts from rest and accelerates with a constant angular acceleration x about a fixed axis. At what time t will the centripetal and tangential accelerations of a point on the rim have the same magnitude?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy45ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy45ps1

Chapter 10 Rotational Kinematics and Energy Q.46P
As you drive down the highway, the top of your tires are moving with a speed v. What is the reading on your speedometer?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy46ps

Chapter 10 Rotational Kinematics and Energy Q.47P
The tires on a car have a radius of 31 cm. What is the angular speed of these tires when the car is driven at 15 m/s?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy47ps

Chapter 10 Rotational Kinematics and Energy Q.48P
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy48p
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy48ps

Chapter 10 Rotational Kinematics and Energy Q.49P
A soccer ball, which has a circumference of 70.0 cm, rolls 14.0 yards in 3.35 s. What was the average angular speed of the ball during this time?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy49ps

Chapter 10 Rotational Kinematics and Energy Q.50P
As you drive down the road at 17 m/s, you press on the gas pedal and speed up with a uniform acceleration of 1, 12 m/s2 for 0.65 s. if the tires on your car have a radius of 33 cm, what is their angular displacement during this period of acceleration?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy50ps

Chapter 10 Rotational Kinematics and Energy Q.51P
A bicycle coasts downhilland accelerates from rest to a linear speed of 8.90 m/s in 12.2 s. (a) If the bicyde’stires have a radius of 36.0 cm, what is theirangular accelerator? (b) If the radius of the tires had been smaller, would their angular acceleration be greater than or less than the result found in part (a)
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy51ps

Chapter 10 Rotational Kinematics and Energy Q.52P
The minute and hour hands of a clock have a common axis of rotation and equal mass. The minute hand is long, thin, and uniform; the hour hand is short, thick, and uniform. (a) Is the moment of inertia of the minute hand greater than, less than, or equal to the moment of inertia of the hour hand? (b) Choose the best explanation from among the following:
I. The hands have equal mass, and hence equal moments of inertia.
II. Having mass farther from the axis of rotation results in a greater moment of inertia.
III. The more compact hour hand concentrates its mass ared has the greater moment of inertia.
Solution:
a) The moment of inertia depends on mass and radius of the body. As the mass of the hour hand and minutes hand are same, the moment of inertia depends on the length of the hand. The length of the minutes hand is greater than the hour’s hand, so moment of inertia of minutes hand is greater than the hour hand.
b) The mass farther from the axis of rotation results in greater moment of inertia.

Chapter 10 Rotational Kinematics and Energy Q.53P
Tons of dust and small particles rain down onto the Earth from space every day. As a result, does the Earth’s moment of inertia increase, decrease, or stay the same? (b) Choose the best explanation from among the following:
I. The dust adds mass to the Earth and increases its radius slightly.
II. As the dust moves closer to the axis of rotation, the moment of inertia decreases.
III. The moment of inertia is a conserved quantity and cannot change.
Solution:
a) Moment of inertia depends upon the mass and radius of the earth. As dust and small particles add up with increase in radius, moment of inertia increases.
b) The moment of inertia of earth, increase because both the mass and radius of earth increased.(I α mr2) Option I is correct.

Chapter 10 Rotational Kinematics and Energy Q.54P
Suppose a bicycle wheel is rotated about an axis through its rim and parallel to its axle. (a) Is its moment of inertia about this axis greater than, less than, or equal to its moment of inertia about its axle? (b) Choose the best explanation from among the following:
I. The moment of inertia is greatest when an object is rotated about its center.
II. The mass and shape of the wheel remain the same.
III. Mass is farther from the axis when the wheel is rotated about the rim.
Solution:
a) Moment of inertia about the rim of the wheel is greater than the moment of inertia about the axle.
b) Moment of inertia is greater when the mass is farther from the axis when the wheel is rotating about the rim.

Chapter 10 Rotational Kinematics and Energy Q.55P
The moment of inertia of a 0.98-kg bicycle wheel rotating about its center is 0.13 kg · m 2. What is the radius of this wheel, assuming the weight of the spokes can be ignored?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy55ps

Chapter 10 Rotational Kinematics and Energy Q.56P
What is the kinetic energy of the grindstone inExample 10-4 if it completes one revolution every 4.20 s?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy56ps

Chapter 10 Rotational Kinematics and Energy Q.57P
An electric fan spinning with an angular speed of 13 rad/s has a kinetic energy of 4.6 J. What is the moment of inertia of the fan?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy57ps

Chapter 10 Rotational Kinematics and Energy Q.58P
Repeat Example 10-5 for the case of a rolling hoop of the same mass and radius.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy58ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy58ps1

Chapter 10 Rotational Kinematics and Energy Q.59P
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy59p
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy59ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy59ps1

Chapter 10 Rotational Kinematics and Energy Q.60P
A 12-g CD with a radius of 6.0 cm rotates with an angular speed of 34 rad/s. (a) What is its kinetic energy? (b) What angularspeed must the CD have if its kinetic energy is to be doubled?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy60ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy60ps1

Chapter 10 Rotational Kinematics and Energy Q.61P
When a pitcher throws a curve ball, the ball is given a fairly rapid spin. If a 0.15-kg baseball with a radius of 3.7 cm is thrown with a linear speed of 48 m/s and an angular speed of 42 rad/s, how much of its kinetic energy is translational and how much is rotational? Assume the ball is a uniform, solid sphere.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy61ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy61ps1

Chapter 10 Rotational Kinematics and Energy Q.62P
A basketball rolls along the floor with a constant linear speed v. (a) Find the fraction of its total kinetic energy that is in the form of rotational kinetic energy about the center of the ball. (b) If the linear speed of the ball is doubled to 2v, does your answer to part (a) increase, decrease, or stay the same? Explain.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy62ps

Chapter 10 Rotational Kinematics and Energy Q.63P
Find the rate at which the rotational kinetic energy of the Earth is decreasing. The Earth has a moment of inertia of 0.331M e R e 2 where R E = 6.38 × 106 m and M E = 5.97 × 1024 kg, and its rotational period increases by 2.3 ms with the passing century. Give your answer in watts.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy63ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy63ps1

Chapter 10 Rotational Kinematics and Energy Q.64P
A lawn mower has a flat, rod-shaped steel blade that rotates about its center. The mass of the blade is 0.65 kg and its length is 0.55 m. (a) What is the rotational energy of the blade at its operating angular speed of 3500 rpm? (b) If all of the rotational kinetic energy of the blade could be converted to gravitational potential energy, to what height would the blade rise?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy64ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy64ps1

Chapter 10 Rotational Kinematics and Energy Q.65P
Consider the physical situation shown in Conceptual Checkpoint 10-5. Suppose this time a ball is released from rest on the frictionless surface. When the ball comes to rest on the no-slip surface, is its height greater than, less than, or equal to the height from which it was released?
Solution:
Assuming the ball starts spinning immediately upon encountering the non-slip surface, with no loss of energy, it will rise to the same height from which it was released. However, in a real system, some energy will be lost when the ball begins to spin. Therefore, the ball should reach a height slightly less than the height at which it was released.

Chapter 10 Rotational Kinematics and Energy Q.66P
Suppose the block in Example 10-6 has a mass of 2.1 kg and an initial upward speed of 0.33 m/s. Find the moment of inertia of the wheel if its radius is 8.0 cm and the block rises to a height of 7.4 cm before momentarily coming to rest.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy66ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy65ps1

Chapter 10 Rotational Kinematics and Energy Q.67P
Through what height must the yo-yo in Active Example 10-3 fall for its linear speed to be 0.65 m/s?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy67ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy67ps1
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy67ps2

Chapter 10 Rotational Kinematics and Energy Q.68P
Suppose we change the race shown in Conceptual Checkpoint 10-4 to a race between three different disks. Let disk 1 have a mass M and a radius R, disk 2 have a mass M and a radius 2R, and disk 3 have a mass 2M and a radius R. Rank the three disks in the order in which they finish the race, indicate ties where appropriate.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy68ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy68ps1

Chapter 10 Rotational Kinematics and Energy Q.69P
Calculate the speeds of (a) the disk and (b) the hoop at the bottom of the inclined plane in Conceptual Checkpoint 10-4 if the height of the incline is 0.82 m.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy69ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy69ps1
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy69ps2
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy69ps3

Chapter 10 Rotational Kinematics and Energy Q.70P
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy70p
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy70ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy70ps1

Chapter 10 Rotational Kinematics and Energy Q.71P
In Conceptual Checkpoint 10-5, assume the ball is a solid sphere of radius 2.9 cm and mass 0.14 kg. If the ball is released from rest at a height of 0.78 m above the bottom of the track on the no-slip side, (a) what is its angular speed when it is on the
frictionless side of the track? (b) How high does the ball rise on the frictionless side?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy71ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy71ps1

Chapter 10 Rotational Kinematics and Energy Q.72P
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy72p
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy72ps

Chapter 10 Rotational Kinematics and Energy Q.73P
A 1.3-kg block is tied to a string that is wrapped around the rim of a pulley of radius 7.2 cm. The block is released from rest. (a) Assuming the pulley is a uniform disk with a mass of 0.31 kg, find the speed of the block after it has fallen through a height of 0.50 m. (b) If a small lead weight is attached near the rim of the pulley and this experiment is repeated, will the speed of the block increase, decrease, or stay the same? Explain.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy73ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy73ps1
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy73ps2
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy73ps3
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy73ps4

Chapter 10 Rotational Kinematics and Energy Q.74P
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy74p
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy74ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy74ps1

Chapter 10 Rotational Kinematics and Energy Q.75P
A 2.0-kg solid cylinder (radius = 0.10 m, length = 0.50 m) is released from rest at the top of a ramp and allowed to roll without slipping. The ramp is 0.75 m high and 5.0 m long. When the cylinder rthees the bottom of the ramp, what are
(a) Its total kinetic energy, (b) its rotational kinetic energy, and (c) its translational kinetic energy?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy75ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy75ps1
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy75ps2
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy75ps3

Chapter 10 Rotational Kinematics and Energy Q.76P
A2.5-kg solid sphere (radius = 0.10 m) is released from rest at the top of a ramp and allowed to roll without slipping. The ramp is 0.75 m high and 5.6 m long. When the sphere rthees the bottom of the ramp, what are (a) its total kinetic energy, (b) its rotational kinetic energy, and (c) its translational kinetic energy?
GENERAL PROBLEMS
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy76ps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy76ps1
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy76ps2

Chapter 10 Rotational Kinematics and Energy Q.77GP
When you stand on the observation deck of the Empire State Building in New York, is your linear speed due to the Earth’s rotation greater than, less than, or the same as when you were waiting for the elevators on the ground floor?
Solution:
Linear speed V=rw
When you stand on the top of the building, your distance (r) from the axis of rotation of Earth will be greater than it was on the ground. As a result, your linear speed at the top of the building is greater than when you were on the ground.

Chapter 10 Rotational Kinematics and Energy Q.78GP
One way to tell whether an egg is raw or hard boiled−without cracking it open−is to place it on a kitchen counter and give it a spin. If you do this to two eggs, one raw the other hard boiled, you will find that one spins considerably longer than the other. Is the raw egg the one that spins a long time, or the one that stops spinning in a short time?
Solution:
A hard-boiled egg spins for a longer time than a raw egg. A hard-boiled egg is rigid and spins with a uniform angular speed. However, the angular speed of a raw egg is not uniform because of its liquid inertia. The liquid inside tries to move away from the axis of rotation and increase its moment of inertia.

Chapter 10 Rotational Kinematics and Energy Q.79GP
When the Hoover Dam was completed and the reservoir behind it filled with water, did the moment of inertia of the Earth increase, decrease, or stay the same?
Solution:
The reservoir was filled by moving from a lower level to a higher level, moving this mass of water further from the axis of rotation. This slightly increases the moment of inertia of Earth.
l ∝r
As the distance from the axis of rotation (r) increases, I increases.

Chapter 10 Rotational Kinematics and Energy Q.80GP
In Quito, Ecuador, near the equator, you weigh about half a pound less than in Barrow, Alaska, near the pole. Find the rotational period of the Earth that would make you feel weightless at the equator. (With this rotational period, your centripetal acceleration would be equal to the acceleration due to gravity, g.)
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy80gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy80gps1

Chapter 10 Rotational Kinematics and Energy Q.81GP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy81gp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy81gps

Chapter 10 Rotational Kinematics and Energy Q.82GP
What linear speed must a 0.065-kg hula hoop have if its total kinetic energy is to be 0.12 J? Assume the hoop rolls an the ground without slipping.
Solution:
When the hoop rolls on the ground without slipping, the energy possessed is the sum of its rotational kinetic energy and translational kinetic energy. The translational kinetic energy is
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy82gps

Chapter 10 Rotational Kinematics and Energy Q.83GP
A pilot performing a horizontal turn will lose consciousness if she experiences a centripetal acceleration greater than 7.00 times the acceleration of gravity. What is the minimum radius turn she can make without losing consciousness if her plane is flying with a constant speed of 245 m/s?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy83gps

Chapter 10 Rotational Kinematics and Energy Q.84GP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy84gp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy84gps

The center of the outer quarter moves in a circle that has double the radius of a quarter. As a result, the linear distance covered by the center of the outer part of the quarter is twice the circumference of a quarter. Therefore, if the outer quarter rolls without slipping, it must complete . two revolutions

Chapter 10 Rotational Kinematics and Energy Q.85GP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy85gp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy85gps

Chapter 10 Rotational Kinematics and Energy Q.86GP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy86gp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy86gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy86gps1

Chapter 10 Rotational Kinematics and Energy Q.87GP
Referring to the previous problem, (a) estimate the linear speed of a point on the rim of the rotating disk. (b) By comparing the arc length between the two white lines to the distance covered by the BB, estimate the speed of the BB. (c) What radius must the disk have for the linear speed of a point on its rim to be the same as the speed of the BB? (d) Suppose a1.0-g lump of putty is stuck to the rim of the disk. What centripetal force is required to hold the putty in place?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy87gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy87gps1
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy87gps2

Chapter 10 Rotational Kinematics and Energy Q.88GP
A mathematically inclined friend e-mails you the following instructions: “Meet me in the cafeteria the first tune after 2:00 p.m. today that the hands of a clock point in the same direction.” (a) Is the desired meeting time before, after, or equal to 2:10 P.M.? Explain. (b) Is the desired meeting time before, after, or equal to 2:15 p.m.? Explain. (c) When should you meet your friend?
Solution:
Use the angle between the two vectors to know the first tune after 2.00 PM that the hands of a clock points in the same direction.
(a)
The hands of a clock are in same direction after 2.00 PM at 2.10 PM.
Hence, the desired time is equal to 2.10 PM.
(b)
The hands of a clock are in same direction after 2.00 PM at 2.10 PM.
Hence, the desired time is before 2.15 PM.
(c)
The hands of a clock are in same direction after 2.00 PM at 2.10 PM.
Hence, You meet your friend at . 2.10 PM.

Chapter 10 Rotational Kinematics and Energy Q.89GP
A diver runs horizontally off the end of a diving tower 3.0 m above the surface of the water with an initial speed of 2.6 m/s. During her fall she rotates with an average angular speed of 2.2 rad/s. (a) How many revolutions has she made when she hits the water? (b) How does your answer to part (a) depend on the diver’s initial speed? Explain.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy89gps

Chapter 10 Rotational Kinematics and Energy Q.90GP
A potter’s wheel of radius 6.8 cm rotates with a period of 0.52 s. What are (a) the linear speed and (b) the centripetal acceleration of a small lump of clay on the rim of the wheel? (c) How do your answers to parts (a) and (b) change if the period of rotation is doubled?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy90gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy90gps1

Chapter 10 Rotational Kinematics and Energy Q.91GP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy91gp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy91gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy91gps1

Chapter 10 Rotational Kinematics and Energy Q.92GP
Pigeons arc bred to display a number of interesting characteristics. One breed of pigeon, the “roiler, ” is remarkable for the fact that it does a number of backward somersaults as it drops straight down toward the ground. Suppose a roller pigeon drops from rest and free falls downward for a distance of 14 m. If the pigeon somersaults at the rate of 12 rad/s, how many revolutions has it completed by the end of its fall?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy92gps

Chapter 10 Rotational Kinematics and Energy Q.93GP
As a marble with a diameter of 1.6 cm roils down an incline, its center moveswith a linear acceleration of 3.3 m/s2. (a) What is the angular acceleration of the marble? (b) What is the angular speed of the marble after it rolls for 1.5 s from rest?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy93gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy93gps1

Chapter 10 Rotational Kinematics and Energy Q.94GP
A rubber ball with a radius of 3.2 cm rolls along the horizontal surface of a table with a constant linear speed v. When the ball rolls off the edge of the table, it falls 0.66 m to the floor below. If the ball completes 0.37 revolution during its fall, what was its lineal’ speed, v?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy94gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy94gps1

Chapter 10 Rotational Kinematics and Energy Q.95GP
Acollege campus features a large fountain surrounded by a circular pool. Two students start at the northernmost point of the pool and walk slowly around it in opposite directions. (a) If the angularspeed of the student walking in the clockwise direction (as viewed from above) is 0.045 rad/s and the angular speed of the other student is 0.023 rad/s, how long does it take before they meet? (b) A t what angle, measured clockwise from due north, do the students meet? (c) If the difference in linear speed between the students is 0, 23 m/s, what is the radius of the fountain?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy95gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy95gps1
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy95gps2

Chapter 10 Rotational Kinematics and Energy Q.96GP
A yo-yo moves downward until it rthees the end of its string, where it “sleeps.” As it sleeps−that is, spins in place−its angular speed decreases from 35 rad/s to 25 rad/s. During this time it completes 120 revolutions. (a) How long did it take for the yo-yo to slow from 35 rad/s to 25 rad/s? (b) How long does it take for the yo-yo to slow from 25 rad/s to 15 rad/s? Assume a constant angular acceleration as the yo-yo sleeps.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy96gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy96gps1

Chapter 10 Rotational Kinematics and Energy Q.97GP
(a) An automobile with tires of radius 32 cm accelerates from 0 to 45 mph in 9.1 s. Find the angular acceleration of the tires. (b) How does your answer to part (a) change if the radius of the tires is halved?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy97gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy97gps1

Chapter 10 Rotational Kinematics and Energy Q.98GP
In Problems 75 and 76 we considered a cylinder and a solid sphere, respectively, rolling down a ramp. (a) Which object do yon expect to have the greater speed at the bottom of the ramp? (b) Verify your answer to part (a) by calculating the speed of the cylinder and of the sphere when they rthe the bottom of the ramp.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy98gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy98gps1

Chapter 10 Rotational Kinematics and Energy Q.99GP
A centrifuge (Problem 22) with an angular speed of 6050 rpm produces a maximum centripetal acceleration equal to 6840 g (that is, 6840 times the acceleration of gravity). (a) What is the diameter of this centrifuge? (b) What force must the bottom of the sample holder exert on a 15.0-g sample under these conditions?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy99gps

Chapter 10 Rotational Kinematics and Energy Q.100GP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy100gp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy100gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy100gps1

Chapter 10 Rotational Kinematics and Energy Q.101GP
The rotor in a centrifuge has an initial angular speed of 430 rad/s. After 8.2 s of constant angular acceleration, its angular speed has increased to 550 rad/s. During this time, what were (a) the angular acceleration of the rotor and (b) the angle through which it turned?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy101gps

Chapter 10 Rotational Kinematics and Energy Q.102GP
A honey bee has two pairs of wings that can beat 250 times a second. Estimate (a) the maximum angular speed of the wings and (b) the maximum linear speed of a wing tip.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy102gps

Chapter 10 Rotational Kinematics and Energy Q.103GP
The Sun, with Earth in tow, orbits about the center of the Milky Way galaxy at a speed of 137 miles per second, completing one revolution every 240 million years. (a) Find the angular speed of the Sun relative to the center of the Milky Way. (b) Find the distance from the Sun to the center of the Milky Way.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy103gps

Chapter 10 Rotational Kinematics and Energy Q.104GP
A person walks into a room and switches on the ceiling fan. The fan accelerates with constant angular acceleration for 15 s until it rthees its operating angularspeed of 1.9 rotations/s− after that its speed remains constant as long as the switch is “on.” The person stays in the room for a short time; then, 5.5 minutes after turning the fan on, she switches it off again and leaves the room. The fan now decelerates with constant angular acceleration, taking 2.4 minutes to come to rest. What is the total number of revolutions made by the fan, from the time it was turned on until the time it stopped?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy104gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy104gps1

Chapter 10 Rotational Kinematics and Energy Q.105GP
When astronauts return from prolonged space flights, they often suffer from bone loss, resulting in brittle bones that may take weeks for their bodies to rebuild. One solution may be to expose astronauts to periods of substantiai”g forces” in a centrifuge carried aboard their spaceship. To test this approach, NASA conducted a study in which four people spent 22 hours the in a compartment attached to the end of a 28-foot arm that rotated with an angular speed of 10.0 rpm. (a) What centripetal acceleration did these volunteersexperience? Express your answer in terms of g. (b) What was their linear speed?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy105gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy105gps1

Chapter 10 Rotational Kinematics and Energy Q.106GP
The pulsar in the Crab nebula (Problem 9) was created by a supernova explosion that was observed on Earth in A.D. 1.054. Its current period of rotation (33.0 ms) is observed to be increasing by 1.26 × 10−5 seconds per year. (a) What is the angular acceleration of the pulsar in rad/s2? (b) Assuming the angular acceleration of the pulsar to be constant, how many years will it take for the pulsar to slow to a stop? (c) Under the same assumption, what was the period of the pulsar when it was created?
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy106gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy106gps1
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy106gps2
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Chapter 10 Rotational Kinematics and Energy Q.107GP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy107gp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy107gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy107gps1

Chapter 10 Rotational Kinematics and Energy Q.108GP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy108gp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy108gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy108gps2
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy108gps3
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy108gps4

Chapter 10 Rotational Kinematics and Energy Q.109GP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy109gp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy109gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy109gps1

Chapter 10 Rotational Kinematics and Energy Q.110GP
A person rides on a 12-m-diameter Ferris wheel that rotates at the constant rate of 8.1 rpm. Calculate the magnitude and direction of the force that the seat exerts on a 65-kg person when he is (a) at the top of the wheel, (b) at the bottom of the wheel, and (c) halfway up the wheel.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy110gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy110gps1
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Chapter 10 Rotational Kinematics and Energy Q.111GP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy111gp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy111gps
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy111gps1
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy111gps2
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Chapter 10 Rotational Kinematics and Energy Q.112PP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy112gp
Solution:
The centripetal acceleration is given as
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy112gps
From the graph, let us assume draw a line from 20rpm of x- axis such that all the curves cut these line. From that we can get the centripetal accelerations of the individual curve.
From the above equation greater the acceleration, greater will be the radius because radius is directly proportional to acceleration when angular speed is constant.
Curve 1 will have greater radius.
And the rank of the curves in the order of increasing radius is 4, 3, 2, 1

Chapter 10 Rotational Kinematics and Energy Q.113PP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy113gp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy113gps

Chapter 10 Rotational Kinematics and Energy Q.114PP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy114gp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy114gps

Chapter 10 Rotational Kinematics and Energy Q.115PP
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy115pp
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy115pps

Chapter 10 Rotational Kinematics and Energy Q.116IP
Suppose we race a disk and a hollow spherical, shell, like a basketball. The spherical shell has a mass M and a radius R; the disk has a mass 2M and a radius 2R. (a) Which object wins the race? If the two objects are released at rest, and the height of the ramp is h = 0.75 m, find the speed of (b) the disk and (c) the spherical shell when they rthe the bottom of the ramp.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy116ip
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy116ips
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy116ips1

Chapter 10 Rotational Kinematics and Energy Q.117IP
Consider a race between the following three objects: object 1, a disk; object 2, a solid sphere; and object 3, a hollow spherical shell. All objects have the same mass and radius. (a) Rank the three objects in the order in which they finish the race. Indicate a tie where appropriate. (b) Rank the objects in order of increasing kinetic energy at the bottom of the ramp. Indicate a tie where appropriate.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy117ips
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Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy117ips2
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy117ips3
b) The total kinetic energy of all objects remains same according to conservation of energy

Chapter 10 Rotational Kinematics and Energy Q.118IP
(a) Suppose the radius of the axle the string wraps around is increased. Does the speed of the yo-yo after falling through a given height increase, decrease, or stay the same? (b) Find the speed of the yo-yo after falling from rest through a height h = 0.50 m if the radius of the axle is 0.0075 m. Everything else in Active Example 10-3 remains the same.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy118ips

Chapter 10 Rotational Kinematics and Energy Q.119IP
Suppose we use a new yo-yo that has the same mass as the original yo-yo and an axle of the same radius. The new yo-yo has a different mass distribution−most of its mass is concentrated near the rim. (a) Is the moment of inertia of the new yo-yo greater than, less than, or the same as that of the original yo-yo? (b) Find the moment of inertia of the new yo-yo if its speed after dropping from rest through a height h = 0.50 m is v = 0.64 m/s.
Solution:
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy119ips
Mastering Physics Solutions Chapter 10 Rotational Kinematics and Energy119ips1

Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions

Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions

Mastering Physics Solutions

Chapter 9 Linear Momentum And Collisions Q.1CQ
If you drop your keys, their momentum increases as they fall. Why is the momentum of the keys not conserved? Does this mean that the momentum of the universe increases as the keys fail? Explain.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions1cqs
The momentum of the key is not conserved, because a net force acts on them. The momentum of the universe, however, is conserved because there are equal and opposite forces acting on Earth.

Chapter 9 Linear Momentum And Collisions Q.1P
Referring to Exercise 9-1, what speed must the baseball have if its momentum is to be equal in magnitude tothat of the car? Give your result in miles per hour.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions1ps

Chapter 9 Linear Momentum And Collisions Q.2CQ
By what factor does an object’s kinetic energy change if its speed is doubled? By what factor does its momentum change?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions2cqs

Chapter 9 Linear Momentum And Collisions Q.2P
Find the total momentum of the birds in Example 9-1 if the goose reverses direction.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions2ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions2ps1

Chapter 9 Linear Momentum And Collisions Q.3CQ
A system of particles is known to have zero kinetic energy. What can you say about the momentum of the system?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions3cqs

Chapter 9 Linear Momentum And Collisions Q.3P
· · A26.2-kg dog is running northward at 2.70 m/s, while a 5.30-kg cat is running eastward at 3.04 m/s. Their 74.0-kg owner has the same momentum as the two pets taken together. Find the direction and magnitude of the owner’s velocity.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions3ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions3ps1
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions3ps2

Chapter 9 Linear Momentum And Collisions Q.4CQ
A system of particles is known to have zero momentum. Does it follow that the kinetic energy of the system is also zero? Explain.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions4cqps

Chapter 9 Linear Momentum And Collisions Q.4P
IP Two air-track carts move toward one another on an air track. Cart 1 has a mass of 0.35 kg and a speed of 1.2 m/s. Cart 2 has a mass of 0.61 kg. (a) What speed must cart 2 have if
the total momentum of the system is to be zero? (b) Since the momentum of the system is zero, does it follow that the kinetic energy of the system is also zero? (c) Verify your answer to part (b) by calculating the system’s kinetic energy
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions4ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions4ps1

Chapter 9 Linear Momentum And Collisions Q.5CQ
On a calm day you connect an electric fan to a battery on your sailboat and generate a breeze. Can the wind produced by the fan be used to power the sailboat? Explain.
Solution:
Momentum is defined as the quantity of motion of the moving body, which is equal to the mass and its velocity. In other ward, momentum is the product of mass and velocity of the moving body. If the electric fan is connected to the battery on the sailboat, then electric fan generates the freeze that is winds. The winds generated by the fan which is faced the rear of the sailboat are used, and then winds pushed the sailboat and gives the momentum of the sailboat. So, sailboat moves in the same direction of the face of the sailboat. Therefore, the wind produced by the fan is used to power the sailboat. Hence, the wind is used to give the power to the sailboat.

Chapter 9 Linear Momentum And Collisions Q.5P
A 0.150-kg baseball is dropped from rest. If the magnitude of the baseball’s momentum is 0.780 kg · m/s just before it lands on the ground, from what height was it dropped?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions5ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions5ps1

Chapter 9 Linear Momentum And Collisions Q.6CQ
In the previous question, can you use the wind generated by the fan to move a boat that has no sail? Explain whyor why not.
Solution:
Answer:
Yes, just point the fan to the rear of the boat.
When the boat is not sailing, then the total momentum of the system is zero. If the fan is placed to the rear end of the boat, then the fan pushes the water backward. So, in order to conserve the momentum, the water should push the boat forward. Hence, the resulting thrust will make the boat sail.

Chapter 9 Linear Momentum And Collisions Q.6P
IP A 285-g ball falls vertically downward, hitting the floor with a speed of 2.5 m/s and rebounding upward with a speed of 2.0 m/s. (a) Find the magnitude of the change in the ball’s momentum. (b) Find the change in the magnitude of the ball’s momentum. (c) Which of the two quantities calculated in parts (a) and (b) ismore directly related to the net force acting on the ball during its collision with the floor? Explain.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions6ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions6ps1

Chapter 9 Linear Momentum And Collisions Q.7CQ
Crash statistics show that it is safer to be riding in a heavy car in an accident than in a light car. Explain in terms of physical principles.
Solution:
It is always safer to ride in a heavy car, because if a heavy car and a light one collide, the lighter car will move with greater acceleration than the heavier car after impact.
Force F = mass acceleration. When the heavy car collides with a light car, both the cars exert equal and opposite forces on each other. As the mass of the lighter car is less, it moves with greater acceleration, making it less safe for the rider.

Chapter 9 Linear Momentum And Collisions Q.7P
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions7p
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions7ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions7ps1
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions7ps2

Chapter 9 Linear Momentum And Collisions Q.8CQ
(a) As you approach a stoplight, youapply the brakes and bring your car to rest. What happened to your car’s initial momentum? (b) When the light turns green, you accelerate until you reach cruising speed. What force was responsible for increasing your car’s momentum?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions8cqs

Chapter 9 Linear Momentum And Collisions Q.8P
CE Your car rolls slowly in a parking lot and bangs into the metal base of a light pole. In terms of safety, is it better for your collision with the light pole to be elastic, inelastic, or is the safety risk the same for either case? Explain.
Solution:
It is better for you if the car has an inelastic collision because the impulse from the pole in an inelastic collision would be just enough to stop the car. In an elastic collision, however, the impulse from the car would be greater and would act on it for a shorter period, causing injury to the rider.

Chapter 9 Linear Momentum And Collisions Q.9CQ
An object at rest on a frictionless surface is struck by a second object. Is it possible for both objects to be at rest after the collision? Explain.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions9cqs

Chapter 9 Linear Momentum And Collisions Q.9P
CE Predict/Explain A net force of 200 N acts on a 100-kg boulder, and a force of the same magnitude acts on a 100-g pebble, (a) Is the change of the boulder’s momentum in one second greater than, less than, or equal to the change of the pebble’s momentum in the same time period? (b) Choose the best explanation from among the following:
I. The large mass of the boulder gives it the greater momentum.
II. The force causes a much greater speed in the 100-g pebble, resulting in more momentum.
III. Equal force means equal change in momentum for a given time.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions9ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions9ps1

Chapter 9 Linear Momentum And Collisions Q.10CQ
In the previous question, is it possible for one of the two objects to be at rest after the collision? Explain.
Solution:
Yes; for example, in a one-dimensional elastic collision of objects of equal mass, the objects “swap” speeds. Therefore, if one object is at rest before the collision, it is also possible for one object to be at rest after the collision.

Chapter 9 Linear Momentum And Collisions Q.10P
CE Predict/Explain Referring to the previous question, (a) is the change in the boulder’s speed in one second greater than, less than, or equal to the change in speed of the pebble in the same time period? (b) Choose the best explanation from among the following:
I. The large mass of the boulder results in a small acceleration.
II. The same force results in the same change in speed for a given time.
III. Once the boulder gets moving it is harder to stop than the pebble.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions10ps

Chapter 9 Linear Momentum And Collisions Q.11CQ
(a) Can two objects on a horizontal frictionless surface have a collision in which all the initial kinetic energy of the system is lost? Explain, and give a specific example if your answer is yes. (b) Can two such objects have a collision in which all the initial momentum of the system is lost? Explain, and give a specific example if your answer is yes.
Solution:
(a) Yes. If two objects with momentum of equal magnitude collide head-on in an inelastic collision, the two objects come to rest. The initial kinetic energy of the system is converted into internal energy and other forms of energy.
In an inelastic collision, the momentum is conserved, but the kinetic energy is not conserved. This is assuming that the external forces on the system sum to zero, or that the differences are negligible.
(b) No. The initial momentum is not lost unless an external force acts on the system.
No force is mentioned here, so we assume that there is no external force acting on the system, and the momentum of the system is conserved in all collisions.

Chapter 9 Linear Momentum And Collisions Q.11P
CE Predict/Explain A friend tosses a ball of mass m to you with a speed v. When you catch the ball, you feel a noticeable sting in your hand, due to the force required to stop the ball. (a) If you now catch a second ball, with a mass 2m and speed v/2,is the sting you feel greater than, less than, or equal to the sting you felt when you caught the first ball? The time required to stop the two balls is the same. (b) Choose the best explanation from among the following:
I. The second ball has less kinetic energy, since kinetic energy depends on v2, and hence it produces less sting.
II. The two balls have the same momentum, and hence they produce the same sting.
III. The second ball has more mass, and hence it produces the greater sting.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions11ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions11ps1

Chapter 9 Linear Momentum And Collisions Q.12CQ
Two cars collide at an intersection. If the cars do not stick together, can we conclude that their collision was elastic? Explain.
Solution:
The collision between the two cars does not need to be elastic, even if the cars do not stick together.
This is because when the two cars collide, a certain amount of energy is dissipated in the form of sound, heat, and also in deforming the cars by forming dents. So the kinetic energy of the system is not conserved and the collision is not elastic.

Chapter 9 Linear Momentum And Collisions Q.12
CE Force A has a magnitude F and acts for the time △t, force B has a magnitude 2F and acts for the time △t/3, force C has a magnitude 5F and acts for the time △t/10,and force D has a magnitude l0F and acts for the time △t/100. Rank these forces in order of increasing impulse. Indicate ties where appropriate.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions12ps

Chapter 9 Linear Momentum And Collisions Q.13CQ
At the instant a bullet is fired from a gun, the bullet and the gun have equal and opposite momenta. Whichobject−the bullet or
the gun−has the greater kinetic energy? Explain. How does your answer apply to the observation that it is safe to hold a gun while it is fired, whereas the bullet is deadly?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions13cqs

Chapter 9 Linear Momentum And Collisions Q.13P
Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1250 N. Assume that the player’s foot is in contact with the ball for 5.95 ×10−3 s.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions13ps

Chapter 9 Linear Momentum And Collisions Q.14CQ
An hourglass is turned over, and the sand is allowed to pour from the upper half of the glass to the lower half. If the hourglass is resting on a scale, and the total mass of the hourglass and sand is M, describe the reading on the scale as the sand runs to the bottom.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions14cqs

Chapter 9 Linear Momentum And Collisions Q.14P
In a typical golf swing, the club is in contact with the ball for about 0.0010 a. If the 45-g ball acquires a speed of 67 m/s, estimate the magnitude of the force exerted by the club on the ball.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions14ps

Chapter 9 Linear Momentum And Collisions Q.15CQ
In the classic movie The Spirit of St. Louis, Jimmy Stewart portrays Charles Lindbergh on his history-making transatlantic flight. Lindbergh is concerned about the weight of his fuel-laden airplane. As he flies over Newfoundland he notices a fly on the dashboard. Speaking to the fly, he wonders aloud, “Does the plane weigh less if you fly inside it as it’s flying? Now that’s an interesting question.” What do you think?
Solution:
The weight of the plane is the same whether the fly is on the dashboard or inside the cockpit. This is because the fly exerts the same downward force (F=mg), regardless of whether it is on the dashboard or inside. This force acts downward on the plane. Thus, the effect is the same whether the fly is standing on the outside or the inside of the plane.

Chapter 9 Linear Momentum And Collisions Q.15P
A 0.50-kg croquet ball is initially at rest on the grass. When the ball is struck by a mallet, the average force exerted on it is 230 N. If the ball’s speed after being struck is 3.2 m/s, how long was the mallet in contact with the ball?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions15ps

Chapter 9 Linear Momentum And Collisions Q.16CQ
A tall, slender drinking glass with a thin base is initially empt. (a) Where is the center of mass of the glass? (b) Suppose the glass is now filled slowly with water until it is completely full. Describe the position and motion of the center of mass during the filling process.
Solution:
The center of mass of an object is the point where the entire mass of the object seems to be concentrated.
(a) If the base of the glass is very thin, the center of mass of the glass will be at its geometric center.
(b) When the glass is being filled with water, initially the center of mass for the system is below the center of mass for the glass. When the glass is completely filled with water, the center of mass will again be at the geometric center of the glass.

Chapter 9 Linear Momentum And Collisions Q.16P
(a) Can two objects on a horizontal frictionless surface have a collision in which all the initial kinetic energy of the system is lost? Explain, and give a specific example if your answer is yes.
(b) Can two such objects have a collision in which all the initial momentum of the system is lost? Explain, and give a specific example if your answer is yes
Solution:
(a) Yes If two objects with momentum of equal magnitude collide head-on in an linelastic collision the two objects come to restS The initial kinetic energy of the system is converted into internal energy and other forms of energy In an inelastic collision, the momentum is conserved, but the kinetic energy is not conserved This is assuming that the external forces on the system sum to zero, or that the differences are negligible
(b) No The initial momentum is not lost unless an external force acts on the system No force is mentioned here, so we assume that there is no external force acting on the system. and the momentum of the system is conserved in all collisions

Chapter 9 Linear Momentum And Collisions Q.17CQ
Lifting one foot into the air, you balance on the other foot. Wha t can you say about the location of yourcenter of mass?
Solution:
When you stand on one foot lifting the other one in air the entire body weight will be concentrated between ground and the foot which is in contact with the ground.
So your center of mass is somewhere directly above the area of contact between your foot and the ground.

Chapter 9 Linear Momentum And Collisions Q.17P
IP A 15.0-g marble is dropped from rest onto the floor 1.44 m below, (a) If the marble bounces straight upward to a height of 0.640 m, what are the magni tude and d irection of the impulse delivered to the marble by the floor? (b) If the marble had bounced to a greater height, would the impulse delivered to it have been greater or less than the impulse found in part (a)? Explain.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions17ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions17ps1
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Chapter 9 Linear Momentum And Collisions Q.18CQ
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions18cq
Solution:
As this jumper clears the bar, a significant portion of the body extends below the bar because of the extreme arching of his back. Just as the center of mass of a donut can lie outside the donut, the center of mass of the jumper can be outside his body. In extreme cases, the center of mass can even be below the bar at all times during the jump.

Chapter 9 Linear Momentum And Collisions Q.18P
To make a bounce pass, a player throws a 0.60-kg basketball toward the floor. The ball hits the floor with a speed of 5.4 m/s at an angle of 65° to the vertical. If the ball rebounds with the same speed and angle, what was the impulse delivered to it by the floor?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions18ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions18ps1

Chapter 9 Linear Momentum And Collisions Q.19P
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions19p
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions19ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions19ps1
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions19ps2

Chapter 9 Linear Momentum And Collisions Q.20P
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions20ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions20ps1

Chapter 9 Linear Momentum And Collisions Q.21P
In a situation similar to Example 9-3, suppose the speeds of the two canoes after they are pushed apart are 0.58 m/s for canoe 1 and 0.42 m/s for canoe 2. If the mass of canoe 1 is 320 kg, what is the mass of canoe 2?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions21ps

Chapter 9 Linear Momentum And Collisions Q.22P
Two ice skaters stand at rest in the center of an ice rink. When they push off against one another the 45-kg skater acquires a speed of 0.62 m/s. If the speed of the other skater is 0.89 m/s, what is this skater’s mass?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions22ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions22ps1

Chapter 9 Linear Momentum And Collisions Q.23P
Suppose the bee in Active Example 9-2 has a mass of 0.175 g. If the bee walks with a speed of 1.41 cm/s relative to the still water, what is the speed of the 4.75-g stick relative to.the water?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions23ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions23ps1

Chapter 9 Linear Momentum And Collisions Q.24P
An object initially at rest breaks into two pieces as the result of an explosion One piece has twice the kinetic energy of the other piece What is the ratio of the masses of the two pieces? Which piece has the larger mass?

An object initially at rest breaks into two pieces as the result of an explosion. One piece has twice the kinetic energy of the other piece. What is the ratio of the masses of the two pieces? Which piece has the larger mass?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions24ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions24ps1

Chapter 9 Linear Momentum And Collisions Q.25P
A 92-kg astronaut and a 1200-kg satellite are at rest relative to the space shuttle. The astronaut pushes on the sa tellite, giving it a speed of 0.14 m/s directly away from the shuttle. Seven and a half seconds later the astronaut comes into contact with the shuttle. What was the initial distance from the shuttle to the astronaut?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions25ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions25ps1

Chapter 9 Linear Momentum And Collisions Q.26P
IP An 85-kg lumberjack stands at one end of a 380-kg floating log, as shown in Figure 9-15. Both the log and the lumberjack are at rest initially. (a) If the lumberjack now trots toward the other end of the log with a speed of 2.7 m/s relative to the log, what is the lumberjack’s speed relative to the shore? Ignore friction between the log and the water. (b) If the mass of the log had been greater, would the lumberjack’s speed relative to the shore be greater than, less than, or the same as in part (a)? Explain, (c) Check your answer to part (b) by calculating the lumberjack’s speed relative to the shore for the case of a 450-kg log.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions26ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions26ps1
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Chapter 9 Linear Momentum And Collisions Q.27P
A plate drops onto a smooth floor and shatters into three nieces of equal mass. Two of the pieces go off with equal speeds v at right angles to one another. Find the speed and direction of the third piece.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions27ps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions27ps1

Chapter 9 Linear Momentum And Collisions Q.28P
A cart of mass m moves with a speed v on a frictionless air track and collides with an identical cart that is stationary. If the two carts stick together after the collision, what is the final kinetic energy of the system?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions28ps
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Chapter 9 Linear Momentum And Collisions Q.29P
Suppose the car in Example 9-6 has an initial speed of 20.0 m/s and that the direction of the wreckage after the collision is 40.0° above the x axis. Find the initial speed of the minivan and the final speed of the wreckage.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.30P
Two 72.0-kg hockey players skating at 5.45 m/s collide and stick together. If the angle between their initial directions was 115°, what is their speed after the collision?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.31P
IP (a) Referring to Exercise 9-2, is the final kinetic energy of the car and truck together greater than, less than, or equal to the sum of the initial kinetic energies of the car and truck separately? Explain. (b) Verify your answer to part (a) by calculating the initial and final kinetic energies of the system.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.32P
IP A bullet with a mass of 4.0 g and a speed of 650 m/s is fired at a block of wood with a mass of 0.095 kg. The block rests on a frictionless surface, and is thin enough that the bullet passes completely through it. Immediately after the bullet exits the block, the speed of the block is 23 m/s. (a) What is the speed of the bullet when it exits the block? (b) Is the final kinetic energy of this system equal to, less than, or greater than the initial kinetic energy? Explain. (c) Verify your answer to part (b) by calculating the initial and final kinetic energies of the system.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.33P
IP A 0,420-kg block of wood hangs from the ceiling by a string, and a 0.0750-kg wad of putty is thrown straight upward, striking the bottom of the block with a speed of 5.74 m/s. The wad of putty sticks to the block. (a) Is the mechanical energy of this system conserved? (b) How high does the putty-block system rise above the original position of the block?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.34P
A 0.430-kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 20.0 N/m. The block rests on a fi-ictionless surface. A 0.0500-kg wad of putty is thrown horizontally at the block, hitting it with a speed of 2.30 m/s and sticking. How far does the putty-block system compress the spring?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.35P
Two objects moving with a speed v travel in opposite directions in a straight line. The objects stick together when they collide, and move with a speed of v/4after the collision, (a) What is the ratio of the final kinetic energy of the system to the initial kinetic energy? (b) What is the ratio of the mass of the more massive object to the mass of the less massive object?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.36P
The collision between a hammer and a nail can be considered to be approximately elastic, Calculate the kinetic energy acquired by a 12-g nail when it is struck by a 550-g hammer moving with an initial speed of 4.5 m/s.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions36ps

Chapter 9 Linear Momentum And Collisions Q.37P
A 732-kg car stopped at an intersection is rear-ended by a 1720-kg truck moving with a speed of 15.5 m/s. lf the car was in neutral and its brakes were off, so that the collision is approximately elastic, find the final speed of both vehicles after the collision.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.38P
CE Suppose you throw a rubber ball at an elephant that is charging directly at you (not a good idea). When the ball bounces back toward you, is its speed greater than, less than, or equal to the speed with which you threw it? Explain.
Solution:
The speed of the ball after bouncing off the elephant will be greate than the speed that it had brfore collision. As the elephant is a heavier object and the ball is a lighter object, when the ball bounces back of the elephant its speed will be nearly twice the speed with which it is thrown.

Chapter 9 Linear Momentum And Collisions Q.39P
IP A charging bull elephant with a mass of 5240 kg comes directly toward you with a speed of 4.55 m/s. You toss a 0.150-kg rubber ball at the elephant with a speed of 7.81 m/s. (a) When the ball bounces back toward you, what is its speed? (b) How do you account for the fact that the ball’s kinetic energy has increased?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.40P
Moderating a Neutron In a nuclear reactor, neutrons released by nuclear fission must be slowed down before they can trigger additional reactions in other nuclei. To see what sort of material is most effective in slowing (or moderating) a neutron, calculate the ratio of a neutron’s final kinetic energy to its initial kinetic energy, Kf/Ki, for a head-on elastic collision with each of the following stationary target particles. (Note: The mass of a neutron is m = 1.009 u, where the atomic mass unit, u, is defined as follows: 1 u = 1.66 × 10−27 kg.) (a) An electron (M = 5.49 × 10−4 u). (b) A proton (M = 1.007 u). (c) The nucleus of a lead atom (M = 207.2 u).
Solution:
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Chapter 9 Linear Momentum And Collisions Q.41P
In the apple-orange collision in Example 9-7, suppose the final velocity of the orange is 1.03 m/s in the negative y direction. What are the final speed and direction of the apple in this case?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.42P
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.43P
In this problem we show that when one ball is pulled to the left in the photo on page 275, only a single ball recoils to the right−under ideal elastic-collision conditions. To begin, suppose that each ball has a mass m, · and that the ball coming in from the left strikes the other balls with a speed v0. Now, consider the hypothetical case of two balls recoiling to the right. Determinethe speed the two recoiling balls must have in order to satisfy (a) momentum conservation and (b) energy conservation. Since these speeds are not the same, it follows that momentum and energy cannot be conserved simultaneously with a recoil of two balls.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.44P
CE Predict/Explain A stalactite in a cave has drops of water falling from it to the cave floor below. The drops are equally
spaced in time and come in rapid succession, so that at any given moment there are many drops in midair. (a) Is the center of mass of the midair drops higher than, lower than, or equal to the halfway distance between the tip of the stalactite and the cave floor? (b) Choose the best explanation from among the following:
I. The drops bunch up as they near the floor of the cave.
II. The drops are equally spaced as they fall, since they are released at equal times.
III. Though equally spaced in time, the drops are closer together higher up.
Solution:
a) The center of mass is higher than the half way distance between the tip of the stalactite and the cave cover.
b) The reason is as the drops fall, their separations increases. With the drops more closely spaced on the upper half of their falls, the center of mass is shifted above the halfway mark.
So option III is correct.

Chapter 9 Linear Momentum And Collisions Q.45P
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions45p
Solution:
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Chapter 9 Linear Momentum And Collisions Q.46P
You are holding a shopping basket at the grocery store with two 0.56-kg cartons of cereal at the left end of the basket. The basket is 0.71 m long. Where should you place a 1.8-kg half gallon of milk, relative to the left end of the basket, so that the center of mass of your groceries is at the center of the basket?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions46ps

Chapter 9 Linear Momentum And Collisions Q.47P
Earth-Moon Center of Mass The Earth has a mass of 5.98 × 1024 kg, the Moon has a mass of 7.35 × 1022 kg, and their center-to-center distance is 3.85 × 108 m. How far from the center of the Earth is the Earth-Moon center of mass? Is the Earth-Moon center of mass above or below the surface of the Earth? By what distance? (As the Earth and Moon orbit one another, their centers orbit about their common center of mass.)
Solution:
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Chapter 9 Linear Momentum And Collisions Q.48P
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions48p
Solution:
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Chapter 9 Linear Momentum And Collisions Q.49P
CE A pencil standing upright on its eraser end falls over and lands on a table. As the pencil falls, its eraser does not slip. The following questions refer to the contact force exerted on the pencil by the tablethe positive x direction be in the direction the pencil with the positive y direction be vertically
upward. (a) During the pencil’s fall, is the x component of the contact force positive, negative, or zero? Explain. (b) Is the y component of the contact force greater than, less than, or equal to the weight of the pencil? Explain.
Solution:
Let the direction of the pencil in an upright position be in a positive y-direction.
Let the direction of the pencil, when it falls, be in the positive x-direction.
(a) As the direction of the fall of the pencil is in the positive x-direction, the x-component of the force is also in the same direction because when the pencil falls to the ground, its center of mass accelerates in the positive x-direction only. So the contact force has a positive horizontal component.
(b) We know that the acceleration of the center of mass of the pencil is non-zero, and is directed downwards. As the pencil is in contact with the table, the table exerts a force on the pencil, which is less than the weight of the pencil.

Chapter 9 Linear Momentum And Collisions Q.50P
A cardboard box is in the shape of a cube with each side of length L. If the top of the box is missing, where is the center of mass of the open box? Give your answer relative to the geometric center of the box.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions50ps
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Chapter 9 Linear Momentum And Collisions Q.51P
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.52P
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.53P
· · IP Three uniform metersticks, each of mass m, are placed on the floor as follows: stick 1 lies along the y/axis from y = 0 to y = 1.0 m, stick 2 lies along the x axis from x = 0 to x = 1.0 m, stick 3 lies along the x axis from x = 1.0 m to x = 2.0 m. (a) Find the location of the center of mass of the metersticks. (b) How would the location of the center of mass be affected if the mass of the metersticks were doubled?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions53ps

Chapter 9 Linear Momentum And Collisions Q.54P
A 0.726-kg rope 2.00 meters long lies on a floor. You grasp one end of the rope and begin lifting it upward with a constant speed of 0.710 m/s. Eind the position and velocity of the rope’s center of mass from the time you begin lifting the rope to the time the last piece of rope lifts off the floor. Plot your results. (Assume the rope occupies negligible volume directly below the point where it is being lifted.)
Solution:

Chapter 9 Linear Momentum And Collisions Q.55P
Repeat the previous problem, this time lowering the rope onto a floor instead of lifting it.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.56P
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.57P
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.58P
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.59P
Rocks for a Rocket Engine A child sits in a wagon with a pile of 0.65-kg rocks. If she can throw each rock with a speed of 11 m/s relative to the ground, causing the wagon to move, how many rocks must she throw per minute to maintain a constant average speed against a 3.4-N force of friction?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions59ps

Chapter 9 Linear Momentum And Collisions Q.60P
A 57.8-kg person holding two 0.880-kg bricks stands on a 2.10-kg skateboard. Initially, the skateboard and the person are at rest. The person now throws the two bricks at the same time so that their speed relative to the person is 17.0 m/s, What is the recoil speed of the person and the skateboard relative to the ground, assuming the skateboard moves without friction?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.61P
In the previous problem, calculate the final speed of the person and the skateboard relative to the ground if the person throws the bricks one at a time. Assume that each brick is thrown with a speed of 17.0 m/s relative to the person.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.62P
A 0.540-kg bucket rests on a scale. Into this bucket you pour sand at the constant rate of 56.0 g/s. If the sand lands in the bucket with a speed of 3.20 m/s, (a) what is the reading of the scale when there is 0.750 kg of sand in the bucket? (b) What is the weight of the bucket and the 0.750 kg of sand?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions62ps

Chapter 9 Linear Momentum And Collisions Q.63P
IP Holding a long rope by its upper end, you lower it onto a scale. The rope has a mass of 0.13 kg per meter of length, and is lowered onto the scale at the constant rate of 1.4 m/s. (a) Calculate the thrust exerted by the rope as it lands on the scale. (b) At the instant when the amount of rope at rest on the scale has a weight of 2.5 N, does the scale read 2.5 N, more than 2.5 N, or less than 2.5 N? Explain. (c) Check y oui’ answer to part (b) by calculating the reading on the scale at this time.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions63ps

Chapter 9 Linear Momentum And Collisions Q.64GP
CE Object A has a mass m, object B has a mass 2m, and object C has a mass m/2. Rank these objects in order of increasing kinetic energy, given that they all have the same momentum. Indicate ties where appropriate.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.65GP
·CE Object A has a mass m,object B has a mass 4m, and object C has a mass m/4. Rank these objects in order of increasing momentum, given that they all have the same kinetic energy. Indicate ties where appropriate.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.66GP
CE Predict/Explain A block of wood is struck by a bullet. (a) Is the block more likely to be knocked over if the bullet is metal and embeds itself in the wood, or if the bullet is rubber and bounces off the wood? (b) Choose the best explanation from among the following;
I. The change in momentum when a bullet rebounds is larger than when it is brought to rest.
II. The metal bullet does more damage to the block.
III. Since the rubber bullet bounces off, it has little effect.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions66ps

Chapter 9 Linear Momentum And Collisions Q.67GP
CE A juggler performs a series of tricks with three bowling balls while standing on a bathroom scale. Is the average reading of the scale greater than, less than, or equal to the weight of the juggler plus the weight of the three balls? Explain.
Solution:
The scale supports the juggler and the three balls for an extended period of time. Therefore, the average reading of the scale is equal to the weight of the juggler, plus the weight of the three balls.

Chapter 9 Linear Momentum And Collisions Q.68GP
A72.5-kg tourist climbs the stairs to the top of the Washington Monument, which is 555 ft high, How far does the Earth move in the opposite direction as the tourist climbs?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.69GP
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.70GP
A car moving with an initial speed v collides with a second stationary car that is one-half as massive. After the collision the first car moves in the same direction as before with a speed v/3. (a) Find the final speed of the second car. (b) Is this collision clastic or inelastic?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions70gps

Chapter 9 Linear Momentum And Collisions Q.71GP
A 1.35-kg block of wood sits at the edge of a table, 0.782 m above the floor. A 0.0105-kg bullet moving horizontally with a speed of 715 m/s embeds itself within the block. What horizontal distance does the block cover before hitting the ground?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.72GP
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.73GP
The Force of a Storm During a severe storm in Palm Beach, FL, on January 2, 1999, 31 inches of rain fell in a period of nine hours. Assuming that the raindrops hit the ground with a speed of 10 m/s, estimate the average upward force exerted by one square meter of ground to stop the falling raindrops during the storm. (Note: One cubic meter of water has a mass of 1000 kg.)
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions73gps

Chapter 9 Linear Momentum And Collisions Q.74GP
An apple that weighs 2.7 N falls vertically downward from rest for 1.4 s. (a) What is the change in the apple’s momentum per second? (b) What is the total change in its momentum during the 1.4-second fall?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.75GP
To balance a 35.5-kg automobile tire and wheel, a mechanic must place a 50.2-g lead weight 25.0 cm from the center of the wheel. When the wheel is balanced, its center of mass is exactly fat the center of the wheel. How far from the center of the wheel was its center of mass before the lead weight was added?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.76GP
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.77GP
IP A 63-kg canoeist stands in the middle of her 22-kg canoe. The canoe is 3.0 m long, and the end that is closest to land is 2.5 m from the shore. The canoeist now walks toward the shore until she contes to the end of the canoe. (a) When the canoeist stops at the end of her canoe, is her distance from the shore equal to, greater than, or less than 2.5 m? Explain. (b) Verify your answer to part (a) by calculating the distance from the canoeist to shore.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.78GP
In the previous problem, suppose the canoeist is 3.4 m from shore when she reaches the end of her canoe. What is the canoe’s mass?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.79GP
· · Referring to Problem 56, find the reading on the scale (a) before and (b) after the string breaks, assuming the ball falls through the liquid with an acceleration equal to 0.250g.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.80GP
A younghockey player stands at rest on the ice holding a 1.3-kg helmet. The player tosses the helmet with a speed of 6.5 m/s in a direction 11° above the horizontal, and recoils with a speed of 0.25 m/s. Find the mass of the hockey player.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.81GP
Suppose the air carts in Example 9-9 are both moving to the right initially. The cart to the left has a mass m and an initial speed v0; the cart to the right has an initial speed v0/2. If the center of mass of this system moves to the right with a speed 2v0/3,what is the mass of the cart on the right?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.82GP
A long, uniform rope with a mass of 0.135 kg per meter lies on the ground. You grab one end of the rope and lift it at the constant rate of 1.13 m/s. Calculate the upward force you must exert at the moment when the top end of the rope is 0.525 m above the ground.
Solution:
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Chapter 9 Linear Momentum And Collisions Q.83GP
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.84GP
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.85GP
IP A fireworks rocket is launched vertically into the night sky with an initial speed of 44.2 m/s. The rocket coasts after being launched, then explodes and breaks into two pieces of equal mass 2.50 s later. (a) If each piece follows a trajectory that is initially at 45.0° to the vertical, what was their speed immediately a fter the explosion? (b) Wha t is the velocity of the rocket’s center of mass before and after the explosion? (c) What is the acceleration of the rocket’s center of mass before and after the explosion?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.86GP
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.87GP
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.88GP
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.89GP
Two air carts of mass m1 = 0.84 kg and m2 = 0.42 kg are placed on a frictionless track. Cart 1 is at rest initially, arid has a spring bumper with a force constant of 690 N/m. Cart 2 has a flat metal surface for a bumper, and moves toward the bumper of the stationary cart with an initial speed v = 0.68 m/s. (a) What is the speed of the two carts at the moment when their speeds are equal? (b) How much energy is stored in the spring bumper when the carts have the same speed? (c) What is the final speed of the carts after the collision?
Solution:
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Chapter 9 Linear Momentum And Collisions Q.90GP
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Solution:
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Chapter 9 Linear Momentum And Collisions Q.91GP
Two objects with masses m1 and m2 and initial velocities v1 and v2,i move along a straight line and collide elastically. Assuming that the objects move along the same straight line after the collision, show that their relative velocities are unchanged; that is, show that v1 − v2/ i = v2,f − v1,f(You can use the results given in Problem 88.)
Solution:
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Chapter 9 Linear Momentum And Collisions Q.92GP
Amplified Rebound Height Two small rubber balls are dropped from rest at a height h above a hard floor. When the balls are released, the lighter ball (with mass m)is directly above the heavier ball (with mass M). Assume the heavier ball reaches the floor first and bounces elastically; thus, when the balls collide, the ball of mass M is moving upwardwith a speed v and the ball of mass m is moving downward with essentially the same speed. In terms of h, find the height to which the ball of mass m rises after the collision. (Use the results given in Problem 88, and assume the balls collide at ground level.)
Solution:
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Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions92gps2

Chapter 9 Linear Momentum And Collisions Q.93GP
On a cold winter morning, a child sits on a sled resting on smooth ice. When the 9.75-kg sled is pulled with a horizontal force of 40.0 N, it begins to move with an acceleration of 2.32 m/s2. The 21.0-kg child accelerates too, hut with a smaller acceleration than that of the sled. Thus, the child moves forward relative to the ice, but slides backward relative to the sled. Find the acceleration of the child relative to the ice.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions93gps

Chapter 9 Linear Momentum And Collisions Q.94GP
An object of mass m undergoes an elastic collision with an identical object that is at rest. The collision is not head-on. Show that the angle between the velocities of the two objects after the collision is 90°.
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions94gps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions94gps1
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions94gps2

Chapter 9 Linear Momentum And Collisions Q.95GP
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions95gp
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions95gps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions95gps1
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions95gps2
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions95gps3

Chapter 9 Linear Momentum And Collisions Q.96GP
IP A uniform rope of length L and mass M rests on a table, (a) if you lift one end of the rope upward with a constant speed, v, show that the rope’s center of mass moves upward with constant acceleration. (b) Next, suppose you hold the rope suspended in air, with its lower end just touching the table. If you now lower the rope with a constant speed, v, onto the table, is the acceleration of the rope’s center of mass upward or downward? Explain your answer. (c) Find the magnitude and direction of the acceleration of the rope’s center of mass far the case described in part (b). Compare with part (a).
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions96gps
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions96gps1

Chapter 9 Linear Momentum And Collisions Q.97PP
From the perspective of an observer on the planet, what is the spacecraft’s speed of approach?
A. v1+u
B. v1− u
C. u − vi
D. vf −u
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions97pps

Chapter 9 Linear Momentum And Collisions Q.98PP
From the perspective of an observer on the planet, what is the spacecraft’s speed of departure?
A. v1+u
B. vf− u
C. u − vf
D. vi − u
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions98pps

Chapter 9 Linear Momentum And Collisions Q.99PP
Set the speed of departure from Problem 98 equal to the speed of approach from Problem 97. Solving this relation for the final speed, vf, yields:
A. vf = v + u
B. vf = vi− u
C. vf = vi + 2u
D. vf = vi − 2u
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions99pps

Chapter 9 Linear Momentum And Collisions Q.100PP
Consider the special case in which vi = u. By what factor does the kinetic energy of the spacecraft increase as a result of the encounter?
A. 4
B. 8
C. 9
D. 16
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions100pps

Chapter 9 Linear Momentum And Collisions Q.101IP
Referring to Example 9-5 Suppose a bullet of mass m = 6.75 g is fired into a ballistic pendulum whose bob has a mass of M = 0.675 kg. (a) If the bob rises to a height of 0.128 m, what was the initial speed of the bullet? (b) What was the speed of the bullet-bob combination immediately after the collision takes place?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions101ips
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Chapter 9 Linear Momentum And Collisions Q.102IP
Referring to Example 9-5 A bullet with a mass m = 8.10 g and an initial speed v0 = 320 m/s is fired into aballistic pendulum. Wha t mass must the bob have if the bullet-bob combination is to rise to a maximum height of 0.125 m after the collision?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions102ips
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions102ips1

Chapter 9 Linear Momentum And Collisions Q.103IP
Referring to Example 9-9 Suppose that cart 1 has a mass of 3.00 kg and an initial speed of 0.250 m/s. Cart 2 has a mass of 1.00 kg and is at rest initially. (a) What is the final speed of the carts? (b) How much kinetic energy is lost as a result of the collision?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions103ips

Chapter 9 Linear Momentum And Collisions Q.104IP
Referring to Example 9-9 Suppose the two carts have equal masses and are both moving to the Light before the collision. The initial speed of cart 1 (on the left) is v0 and the initial speed of cart 2 (on the right) is v0/2.(a) What is the speed of the center of mass of this system? (b) What percentage of the initial kinetic energy is lost as a result of the collision? (c) Suppose the collision is elastic. What are the final speeds of the two carts in this case?
Solution:
Mastering Physics Solutions Chapter 9 Linear Momentum And Collisions104ips
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