Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits

Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits

Mastering Physics Solutions

Chapter 21 Electric Current and Direct-Current Circuits Q.1CQ
What is the direction of the electric current produced by an electron that falls toward the ground?
Solution:
By convention, the direction of electric current is always in the opposite direction to the motion of negative charge. If the electron falls toward the ground. then the direction of current is in the upward direction

Chapter 21 Electric Current and Direct-Current Circuits Q.1P
How many coulombs of charge are in one ampere-hour?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits1ps

Chapter 21 Electric Current and Direct-Current Circuits Q.2CQ
Your body is composed of electric charges Does it follow, then, that you produce an electric current when you walk?
Solution:
No An electric current ¡s proc1ucei when a net charge mores Your body is electrically neutral, so no current is produced when you walk

Chapter 21 Electric Current and Direct-Current Circuits Q.2P
A flashlight bulb carries a current of 0.18 A for 78 s. How much charge flows through the bulb in this time? How many electrons?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits2ps

Chapter 21 Electric Current and Direct-Current Circuits Q.3CQ
Suppose you charge a comb by rubbing it through your hair Do you produce a current when you walk across the room carrying the comb?
Solution:
No.
By rubbing the comb through your hair you have transferred charge from your hair to the comb but the net charge of you and the comb together is still zero Therefore no current is produced when you walk across the room carrying the comb

Chapter 21 Electric Current and Direct-Current Circuits Q.3P
The picture tube in a particular television draws a current of 15 A. How many electrons strike the viewing screen every second?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits3ps

Chapter 21 Electric Current and Direct-Current Circuits Q.4CQ
Suppose you charge a comb by rubbing t through the fur on your dog’s back Do you produce a current when you walk across the room carrying the comb?
Solution:
Yes
There is a net charge separated and deposited on the comb surface and by moving the comb one place to another you have created an electric current

Chapter 21 Electric Current and Direct-Current Circuits Q.4P
IP A car battery does 260 J of work on the charge passing through it as it starts an engine,
(a) If the emf of the battery is 12 V, how much charge passes through the battery during the start?
(b) If the emf is doubled to 24 V, does the amoun,t of charge passing through the battery increase or decrease? By what factor?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits4ps

Chapter 21 Electric Current and Direct-Current Circuits Q.5CQ
An electron moving through a wire has an average drift speed that is very small Does this mean that its instantaneous velocity is also very small?
Solution:
No.
An electron may have a fairly large instant velocity at any given time But because its direction of motion keeps changing due to its collisions with atoms in the wire its average velocity in particular direction is almost very very small.

Chapter 21 Electric Current and Direct-Current Circuits Q.5P
Highly sensitive ammeters can measure currents as small as 10.0 fA. How many electrons per second flow through a wire with a 10.0-fA current?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits5ps

Chapter 21 Electric Current and Direct-Current Circuits Q.6CQ
Arc car headlights connected in series or parallel? Give an everyday observation that supports your answer
Solution:
Car head lights are wired in parallel as we can tell by the fact that some care has only one working head light.

Chapter 21 Electric Current and Direct-Current Circuits Q.6P
A television set connected to a 120-V outlet consumes 78 W of power, (a) How much current flows through the television? (b) How long does it take for 10 million electrons to pass through the TV?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits6ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits6ps

Chapter 21 Electric Current and Direct-Current Circuits Q.7CQ
Give an example of how four resistors of resistance R can be combined to produce an equivalent resistance of R.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits7cqs

Chapter 21 Electric Current and Direct-Current Circuits Q.7P
BIO Pacemaker Batteries Pacemakers designed for longterm use commonly employ a lithium-iodine battery capable of
supplying 0.42 A · h of charge,
(a) How many coulombs of charge can such a battery supply?
(b) If the average current produced by the pacemaker is 5.6 μ A, what is the expected lifetime of the device?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits7ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits7ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.8CQ
Is it possible to connect a group of resistors of value R in such a way that the equivalent resistance is less than R? If so, give a specific example.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits8cqs

Chapter 21 Electric Current and Direct-Current Circuits Q.8P
CE A conducting wire is quadrupled in length and tripled in diameter,
(a) Does its resistance increase, decrease, or stay the same? Explain,
(b) By what factor does its resistance change?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits8ps

Chapter 21 Electric Current and Direct-Current Circuits Q.9CQ
What physical quantity do resistors connected in series have in common?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits9cqs

Chapter 21 Electric Current and Direct-Current Circuits Q.9P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits9p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits9ps

Chapter 21 Electric Current and Direct-Current Circuits Q.10CQ
What physical quantity do resistors connected in parallel have in common?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits10cqs

Chapter 21 Electric Current and Direct-Current Circuits Q.10P
Current-versus-voltage plots for two materials, A and B, are shown in Figure 21-26.
(a) Is the resistance of material A greater than, less than, or equal to the resistance of material B at the voltage V1?
(b) Choose the best explanation from among the following:
I. Curve B is higher in value than curve A.
II. A larger slope means a larger value of I/V, and hcnce a smaller value of R.
III. Curve B has the larger slope at the voltage V1 and hence the larger resistance.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits10ps

Chapter 21 Electric Current and Direct-Current Circuits Q.11CQ
Explain how electrical devices can begin operating almost immediately after you throw a switch. even though individual electrons in the wire may take hours to reach the device
Solution:
Each electron in the wire affects its neighbors by means of electric field exerting a force on them causing them to move
Thus when electrons begin to move out of a battery their motion sets up a propagating influence that moves through the wire at nearly the speed of light causing electrons everywhere in the wire to begin moving.
In this way electrical device can begin operating almost immediately after we throw a switch even though individual electrons in the wire may take hours to reach the device

Chapter 21 Electric Current and Direct-Current Circuits Q.11P
Two cylindrical wires are made of the same material and have the same length. If wire B is to have nine times the resistance of wire A, what must be the ratio of their radii, rB/rA?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits11ps

Chapter 21 Electric Current and Direct-Current Circuits Q.12CQ
Explain the difference between resistivity and resistance.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits12cqs
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits12cqs1

Chapter 21 Electric Current and Direct-Current Circuits Q.12P
A silver wire is 5.9 m long and 0.49 mm in diameter. What is its resistance?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits12ps

Chapter 21 Electric Current and Direct-Current Circuits Q.13CQ
Explain why birds can roost on high-voltage wire without being electrocuted
Solution:
A number of factors come into play hera
—t First the bottom of a bird’s foot is tough and definitely not a good conductor of electricity.
—, Secondly the potential difference is required for the flow of current thru the bird’s body. contact with a high voltage wire isn’t enough to cause a problem. there need a contact with a lower voltage Source
But the bird is in contact with essentially the same high voltage in two different places (Where its two feet touch the wire) which doesn’t lead to a potential difference The only potential difference the bird experience is due to the very small voltage drop along the segment of wire between the bird’s two feet

Chapter 21 Electric Current and Direct-Current Circuits Q.13P
When a potential difference of 18 V is applied to a given wire, it conducts 0.35 A of current. What is the resistance of the wire?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits13ps

Chapter 21 Electric Current and Direct-Current Circuits Q.14CQ
List two electrical applications that would benefit from room-temperature superconductors. List two applications for which room-temperature superconductivity would not be beneficial.
Solution:
Magnetic resonance imaging (MRI) machines would definitely benefit from room temperature super conductivity
As it is. they must cool their magnets to law temperature Similarly.
Electric power transmission would benefit if the resistance of the wires could be eliminated On the other hand, a toaster or an electric oven requires resistance to do its job: super conductivity would not help

Chapter 21 Electric Current and Direct-Current Circuits Q.14P
The tungsten filament of a lightbulb has a resistance of 0.07 Ω. If the filament is 27 cm long, what is its diameter?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits14ps

Chapter 21 Electric Current and Direct-Current Circuits Q.15CQ
Oil what basic conservation laws are Kirchhoffs rules based?
Solution:
The junction rule is based on conservation of electric charge the loop rule is based on the conservation energy

Chapter 21 Electric Current and Direct-Current Circuits Q.15P
What is the resistance of 6.0 mi of copper wire with a diameter of 0.55 mm?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits15ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits15ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.16CQ
What physical quantity do capacitors connected in series have in common?
Solution:
Consider some capacitors connected in series with a battery The plate of the capacitor which is connected to the positive end of the battery will acquire positive charge and this will cause
same amount of negative charge to develop at the other negative plate of the capacitor The negative charge will then cause the capacitor next to it to develop same amount of charge- In this way all the capacitors in the series connection will get same amount of charga Hence, in a series connection, the physical quantity that the capacitors have in common is the electric charge

Chapter 21 Electric Current and Direct-Current Circuits Q.16P
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Solution:
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Chapter 21 Electric Current and Direct-Current Circuits Q.17CQ
What physical quantity do capacitors connected in parallel have in common?
Solution:
When the capacitors are connected in parallel then the potential difference is the common quantity on all the capacitors.

Chapter 21 Electric Current and Direct-Current Circuits Q.17P
IP A bird lands on a bare copper wire carrying a current of 32 A. The wire is 8 gauge, which means that its cross-sectional area is 0.13 cm2,
(a) Find the difference in potential between the bird’s feet, assuming they are separated by a distance of 6.0 cm.
(b) Will your answer to part (a) increase or decrease if the separation between the bird’s feet increases? Explain.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits17ps
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Chapter 21 Electric Current and Direct-Current Circuits Q.18CQ
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits18cq
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits18cqs

Chapter 21 Electric Current and Direct-Current Circuits Q.18P
A current of 0.96 A flows through a copper wire 0.44 mm in diameter when it is connected to a potential difference of 15 V. How long is the wire?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits18ps

Chapter 21 Electric Current and Direct-Current Circuits Q.19P
IP BIO Current Through a Cell Membrane A typical cell membrane is 8.0 nm thick and has an electrical resistivity of 1.3 × 107 Ω · m.
(a) If the potential difference between the inner and outer surfaces of a cell membrane is 75 mV, how much current flows through a square area of membrane 1.0 μ m on a side?
(b) Suppose the thickness of the membrane is doubled,
but the resistivity and potential difference remain the same. Does the current increase or decrease? By what factor?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits19ps

Chapter 21 Electric Current and Direct-Current Circuits Q.20P
When a potential difference of 12 V is applied to a wire 6.9 m long and 0.33 mm in diameter, the result is an electric current of 2.1 A. What is the resistivity of the wire?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits20ps

Chapter 21 Electric Current and Direct-Current Circuits Q.21P
IP
(a) What is the resistance per meter of an aluminum wire with a cross-sectional area of 2.4 × 10-7 m2.
(b) Would your answer to part (a) increase, decrease, or stay the same if the diameter of the wire were increased? Explain,
(c) Repeat part (a) for a wire with a cross-sectional area of 3.6 × 10−7 m2.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits21ps

Chapter 21 Electric Current and Direct-Current Circuits Q.22P
BIO Resistance and Current in the Human Finger The interior of the human body has an electrical resistivity of 0.15 Ω · m.
(a) Estimate the resistance for current flowing the length of your index finger. (For this calculation, ignore the much higher resistivity of your skin.)
(b) Your muscles will contract when they carry a current greater than 15 mA. What voltage is required to produce this current through your finger?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits22ps

Chapter 21 Electric Current and Direct-Current Circuits Q.23P
CE Light A has four times the power rating of light B when operated at the same voltage,
(a) Is the resistance of light A greater than, less than, or equal to the resistance of light B? Explain,
(b) What is the ratio of the resistance of light A to the resistance of light B?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits23p
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits23ps

Chapter 21 Electric Current and Direct-Current Circuits Q.24P
CE Light A has four times the power rating of light B when operated at the same voltage.
(a) Is the resistance of light A greater than, less than, or equal to the resistance of light B? Explain.
(b) What is the ratio of the resistance of light A to the resistance of light B?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits24ps

Chapter 21 Electric Current and Direct-Current Circuits Q.25P
CE Two lightbulbs operate on the same potential difference. Bulb Ahas four times the power output of bulb B.
(a) Which bulb has the greater current passing through it? Explain,
(b) What is the ratio of the current in bulb A to the current in bulb B?
Solution:
Given that,
Two light bulbs operate on the same potential difference. Bulb ‘A’ has 4 times the power output of bulb B.
(a) In terms of potential difference ‘V’ and current ‘I’, the power output of the bulbs can be written as
P = I V
It is given that ‘V’ is the same for both bulbs.
It follows, then, that the current in bulb ‘A’ is greater than the current in bulb ‘B’
(b) Since power is proportional to current, the current in bulb ‘A’ is four times greater than the current in bulb B.

Chapter 21 Electric Current and Direct-Current Circuits Q.26P
CE Two lightbulbs operate on the same current. Bulb A has four times the power output of bulb B.
(a) Is the potential difference across bulb A greater than or less than the potential difference across bulb B? Explain,
(b) What is the ratio of the potential difference across bulb A to that across bulb B?
Solution:
Given that,
Two light bulbs operate on the same current; Bulb ‘A’ has four times the power output of bulb ‘B’.
(a) In terms of potential difference ‘V’ and current ‘I’, the power output of the bulbs can be written as
P = I V
It is given that current ‘I’ is same for both bulbs.
It follows, that the potential difference in bulb ‘A’ is greater than the potential difference in bulb ‘B’.
(b) Since power is proportional to potential difference, the potential difference in bulb ‘A’ is four times greater than the potential difference in bulb ‘B’.
Chapter 21 Electric Current and Direct-Current Circuits Q.27P
A 75-V generator supplies 3.8 kW of power. How much current does the generator produce?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits27ps

Chapter 21 Electric Current and Direct-Current Circuits Q.28P
A portable CD player operates with a current of 22 mA at a potential difference of 4.1 V. What is the power usage of the player?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits28ps

Chapter 21 Electric Current and Direct-Current Circuits Q.29P
Find the power dissipated in a 25-Ω electric heater connected to a 120-V outlet.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits29ps

Chapter 21 Electric Current and Direct-Current Circuits Q.30P
The current in a 120-V reading lamp is 2.6 A. If the cost of electrical energy is $0.075 per kilowatt-hour, how much does it cost to operate the light for
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits30ps

Chapter 21 Electric Current and Direct-Current Circuits Q.31P
It costs 2.6 cents to charge a car battery at a voltage of 12 V and a current of 15 A for 120 minutes. What is the cost of electrical energy per kilowatt-hour at this location?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits31ps

Chapter 21 Electric Current and Direct-Current Circuits Q.32P
IP A 75-W lightbulb operates on a potential difference of 95 V. Find
(a) the current in the bulb and
(b) the resistance of the bulb,
(c) If this bulb is replaced with one whose resistance is half the value found in part
(b), is its power rating greater than or less than 75 W? By what factor?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits32ps
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Chapter 21 Electric Current and Direct-Current Circuits Q.33P
Rating Car Batteries Car batteries are rated by the following two numbers:
(1) cranking amps = current the battery can produce for 30.0 seconds while maintaining a terminal voltage of at least 7.2 V and
(2) reserve capacity = number of minutes the battery can produce a 25-A current while maintaining a terminal voltage of at least 10.5 V. One particular battery is advertised as having 905 cranking amps and a 155-minute reserve capacity. Which of these two ratings represents the greater amount of energy delivered by the battery?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits33ps

Chapter 21 Electric Current and Direct-Current Circuits Q.34P
CE Predict/Explain A dozen identical lightbulbs are connected to a given emf.
(a) Will the lights be brighter if they are connected in series or in parallel?
(b) Choose the best explanation from among the following:
I. When connected in parallel each bulb experiences the maximum emf and dissipates the maximum power.
II. Resistors in series have a larger equivalent resistance and dissipate more power.
III. Resistors in parallel have a smaller equivalent resistance and dissipate less power.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits34ps

Chapter 21 Electric Current and Direct-Current Circuits Q.35P
CE Predict/Explain A fuse is a device to protect a circuit from the effects of a large current. The fuse is a small strip of metal that burns through when the current in it exceeds a certain value, thus producing an open circuit,
(a) Should a fuse be connected in series or in parallel with the circuit it is intended to protect?
(b) Choose the best explanation from among the following:
I. Either connection is acceptable; the main tiling is to have a fuse in the circuit.
II. The fuse should be connected in parallel, otherwise it will interrupt the current in the circuit.
III. With the fuse connected in series, the current in the circuit drops to zero as soon as the fuse bruns through.
Solution:
(a) Fuse should be always connected in series.
If the fuse is connected in series, when the fuse is blown out it makes an open circuit and the appliances are protected from high current.
(b) If the fuse is connected in series and when the fuse is blown it becomes an open circuit and the current in the circuit becomes zero.
Hence best explanation is III

Chapter 21 Electric Current and Direct-Current Circuits Q.36P
CE A circuit consists of three resistors, R123, connected in series to a battery. Rank these resistors in order of increasing
(a) current through them and
(b) potential difference across them. Indicate ties where appropriate.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits36ps

Chapter 21 Electric Current and Direct-Current Circuits Q.37P
CE Predict/Explain Two resistors are connected in parallel,
(a) If a third resistor is now connected in parallel with the original two, does the equivalent resistance of the circuit increase, decrease, or remain the same?
(b) Choose the best explanation from among the following:
I. Adding a resistor generally tends to increase the resistance, but putting it in parallel tends to decrease the resistance; therefore the effects offset and the resistance stays the same.
II. Adding more resistance to the circuit will increase the equivalent resistance.
III. The third resistor gives yet another path for current to flow in the circuit, which means that the equivalent resistance is less.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits37ps

Chapter 21 Electric Current and Direct-Current Circuits Q.38P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits38p
Solution:
The equivalent resistance (R) of the resistors which are connected in series is equal to the sum of the resistance of the individual resistors.
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits38ps

Chapter 21 Electric Current and Direct-Current Circuits Q.39P
What is the minimum number of 65-Ω resistors that must be connected in parallel to produce an equivalent resistance of 11 Ω or less?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits39ps

Chapter 21 Electric Current and Direct-Current Circuits Q.40P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits40p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits40ps
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Chapter 21 Electric Current and Direct-Current Circuits Q.41P
Your toaster has a power cord with a resistance of 0.020 Ω connected in series with a 9.6-Ω nichrome heating element. If the potential difference between the terminals of the toaster is 120 V, how much power is dissipated in
(a) the power cord and
(b) the heating element?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits41ps

Chapter 21 Electric Current and Direct-Current Circuits Q.42P
A hobbyist building a radio needs a 150-Ω resistor in her circuit, but has only a 220-Ω, a 79-Ω, and a 92-Ω resistor available. How can she connect these resistors to produce the desired resistance?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits42ps

Chapter 21 Electric Current and Direct-Current Circuits Q.43P
A circuit consists of a 12.0-V battery connected to three resistors (42 Ω, 17 Ω, and 110 Ω) in series. Find
(a) the current that flows through the battery and
(b) the potential difference across each resistor.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits43ps

Chapter 21 Electric Current and Direct-Current Circuits Q.44P
IP Three resistors, 11 Ω, 53 Ω, and R, are connected in series with a 24.0-V battery. The total current flowing through the battery is 0.16 A.
(a) Find the value of resistance R.
(b) Find the potential difference across each resistor,
(c) If the voltage of the battery had been greater than 24.0 V, would your answer to part (a) have been larger or smaller? Explain.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits44ps
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Chapter 21 Electric Current and Direct-Current Circuits Q.45P
A circuit consists of a battery connected to three resistors (65 Ω, 25 Ω, and 170 Ω) in parallel. The total current through the resistors is 1.8 A. Find
(a) the emf of the battery and
(b) the current through each resistor.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits45ps
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Chapter 21 Electric Current and Direct-Current Circuits Q.46P
IP Three resistors, 22 Ω, 67 Ω, and R, are connected in parallel with a 12.0-V battery. The total current flowing through the battery is 0.88 A.
(a) Find the value of resistance R.
(b) Find the current through each resistor,
(c) If the total current in the battery had been greater than 0.88 A, would your answer to part (a) have been larger or smaller? Explain.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits46ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits46ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.47P
An 89-Ω resistor has a current of 0.72 A and is connected in series with a 130-Ω resistor. What is the emf of the battery to wliich the resistors are connected?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits47ps

Chapter 21 Electric Current and Direct-Current Circuits Q.48P
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Solution:
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Chapter 21 Electric Current and Direct-Current Circuits Q.49P
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Solution:
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Chapter 21 Electric Current and Direct-Current Circuits Q.50P
How many 65-W lightbulbs can be connected m parallel across a potential difference of 85 V before the total current in the circuit exceeds 2.1 A?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits50ps

Chapter 21 Electric Current and Direct-Current Circuits Q.51P
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Solution:
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Chapter 21 Electric Current and Direct-Current Circuits Q.52P
IP A 12-V battery is connected to terminals A and B in Figure 21-30.
(a) Given that R = 85 Ω, find the current in each resistor.
(b) Suppose the value of R is increased. For each resistor in turn, state whether the current flowing through it increases or decreases. Explain.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits52ps
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Chapter 21 Electric Current and Direct-Current Circuits Q.53P
IP The terminals A and B in Figure 21-31 are connected to a 9.0-V battery,
(a) Find the current flowing through each resistor,
(b) Is the potential difference across the 6.3-Ω resistor greater than, less than, or the same as the potential difference across the 1.5-Ω resistor? Explain.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits53ps
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Chapter 21 Electric Current and Direct-Current Circuits Q.54P
IP Suppose the battery in Figure 21-32 has an internal resistance r = 0.25 Ω
(a) How much current flows through the battery?
(b) What is the potential difference between the terminals of the battery? (c) If the 3.2-Ω resistor is increased in value, will the current in the battery increase or decrease? Explain.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits54ps
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Chapter 21 Electric Current and Direct-Current Circuits Q.55P
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Solution:
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Chapter 21 Electric Current and Direct-Current Circuits Q.56P
The current in the 13.8-Ω resistor in Figure 21- 0.795 A. Find the current in the other resistors in the circuit
Solution:
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Chapter 21 Electric Current and Direct-Current Circuits Q.57P
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Solution:
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Chapter 21 Electric Current and Direct-Current Circuits Q.58P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits58p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits58ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits58ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.59P
IP Suppose the polarity of the 11.5-V battery in Figure 21-35 is reversed,
(a) Do you expect this to increase or decrease the amount of current flowing in the circuit? Explain,
(b) Calculate the magnitude and direction (clockwise or counterclockwise) of the current in this case.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits59ps

Chapter 21 Electric Current and Direct-Current Circuits Q.60P
IP It is given that point A in Figure 21-35 is grounded (V = 0).
(a) Is the potential at point B greater than or less than zero? Explain,
(b) Is the potential at point C greater than or less than zero? Explain,
(c) Calculate the potential at point D.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits60ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits60ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.61P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits61p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits61ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits61ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits61ps2
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits61ps3
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits61ps4
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits61ps5
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits61ps6
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits61ps7
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits61ps8

Chapter 21 Electric Current and Direct-Current Circuits Q.62P
Suppose point A is grounded (V = 0) in Figure 21-36. Find the potential at points B and C.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits62ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits62ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits62ps2

Chapter 21 Electric Current and Direct-Current Circuits Q.63P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits63p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits63ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits63ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits63ps2

Chapter 21 Electric Current and Direct-Current Circuits Q.64P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits64p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits64ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits64ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits64ps2
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits64ps3

Chapter 21 Electric Current and Direct-Current Circuits Q.65P
CE Two capacitors, C1 = C and C2 = 2C, are connected to a battery,
(a) Which capacitor stores more energy when they are connected to the battery in series? Explain,
(b) Which capacitor stores more energy when they are connected in parallel? Explain.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits65ps

Chapter 21 Electric Current and Direct-Current Circuits Q.66P
CE Predict/Explain Two capacitors are connected in series,
(a) If a third capacitor is now connected in series with the original two, does the equivalent capacitance increase, decrease, or remain the same?
(b) Choose the best explanation from among the following:
I. Adding a capacitor generally tends to increase the capacitance, but putting it in series tends to decrease the capacitance; therefore, the net result is no change.
II. Adding a capacitor in series will increase the total amount of charge stored, and hence increase the equivalent capacitance.
III. Adding a capacitor in series decreases the equivalent capacitance since each capacitor now has less voltage across it, and hence stores less charge.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits66ps

Chapter 21 Electric Current and Direct-Current Circuits Q.67P
CE Predict/Explain Two capacitors are connected in parallel,
(a) If a third capacitor is now connected in parallel with the original two, does the equivalent capacitance increase, decrease, or remain the same?
(b) Choose the best explanation from among the following:
I. Adding a capacitor tends to increase the capacitance, but putting it in parallel tends to decrease the capacitance; therefore, the net result is no change.
II. Adding a capacitor in parallel will increase the total amount of charge stored, and hence increase the equivalent capacitance.
III. Adding a capacitor in parallel decreases the equivalent capacitance since each capacitor now has less voltage across it, and hence stores less charge.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits67ps

Chapter 21 Electric Current and Direct-Current Circuits Q.68P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits68p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits68ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits68ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.69P
A 12-V battery is connected to three capacitors in series. The capacitors have the following capacitances: 4.5 μ F, 12 μ F, and 32 μ F. Find the voltage across the 32- μ F capacitor.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits69ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits69ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.70P
CE You conduct a series of experiments in which you connect the capacitors C1 and C2 > C1 to a battery in various ways. The experiments are as follows:
A, C1 alone connected to the battery;
B, C2 alone connected to the battery;
C, C1 and C2 connected to the battery in series;
D, C1 and C2 connected to the battery in parallel. Rank these four experiments in order of increasing equivalent capacitance. Indicate ties where appropriate.
Solution:
The ranking is C<A<B<D
This follows because two capacitors in series have equivalent capacitances less than the smallest of the capacitor and two capacitor connected in parallel have an equivalent capacitance greater than the largest of the capacitors.

Chapter 21 Electric Current and Direct-Current Circuits Q.71P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits71p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits71ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits71ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits71ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits71ps2
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits71ps3

Chapter 21 Electric Current and Direct-Current Circuits Q.72P
Terminals A and B in Figure 21-39 are connected to a 9.0-V battery. Find the energy stored in each capacitor.
Solution:
Therefore, energy stored incapacitor is approximately.
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits72ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits72ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits72ps2
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits72ps3

Chapter 21 Electric Current and Direct-Current Circuits Q.73P
IP Two capacitors, one 7.5 μ F and the other 15 μ F, are connected in parallel across a 15-V battery,
(a) Find the equivalent capacitance of the two capacitors,
(b) Which capacitor stores more charge? Explain,
(c) Find the charge stored on each capacitor.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits73ps

Chapter 21 Electric Current and Direct-Current Circuits Q.74P
IP Two capacitors, one 7.5 μ F and the other 15 μ F, are connected in series across a 15-V battery,
(a) Find the equivalent capacitance of the two capacitors,
(b) Which capacitor stores more charge? Explain,
(c) Find the charge stored on each capacitor.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits74ps

Chapter 21 Electric Current and Direct-Current Circuits Q.75P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits75p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits75pss
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits75pss1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits75pss2
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits75pss3

Chapter 21 Electric Current and Direct-Current Circuits Q.76P
Two capacitors, C1 and C2, are connected in series and charged by a battery. Show that the energy stored in C1 plus the energy stored in C2 is equal to the energy stored in the equivalent capacitor, Ceq, when it is connected to the same battery.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits76ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits76ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.77P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits77p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits77ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits77ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits77ps2

Chapter 21 Electric Current and Direct-Current Circuits Q.78P
The switch on an RC circuit is closed at t = 0. Given that ε = 9.0 V, R = 150 Ω, and C = 23 μ F, how much charge is on the capacitor at time t = 4.2 ms?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits78ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits78ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.79P
ε The capacitor in an RC circuit (R = 120 Ω, C = 45 μ F) is initially uncharged. Find
(a) the charge on the capacitor and
(b) the current in the circuit one time constant (τ = RC) after the circuit is connected to a 9.0-V battery.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits79ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits79ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.80P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits80p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits80ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits80ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits80ps2
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits80ps3

Chapter 21 Electric Current and Direct-Current Circuits Q.81P
Consider an RC circuit with ε = 12.0 V, R = 175 Ω, and C = 55.7 μ F. Find
(a) the time constant for the circuit,
(b) the maximum charge on the capacitor, and
(c) the initial current in the circuit.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits81ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits81ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.82P
The resistor in an RC circuit has a resistance of 145 Ω.
(a) What capacitance must be used in this circuit if the time constant is to be 3.5 ms?
(b) Using the capacitance determined in part (a), calculate the current in the circuit 7.0 ms after the switch is closed. Assume that the capacitor is uncharged initially and that the emf of the battery is 9.0 V.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits82ps

Chapter 21 Electric Current and Direct-Current Circuits Q.83P
A flash unit for a camera has a capacitance of 1500 μ F. What resistance is needed in this RC circuit if the flash is to charge to 90% of its full charge in 21 s?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits83ps

Chapter 21 Electric Current and Direct-Current Circuits Q.84P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits84p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits84ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits84ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits84ps2

Chapter 21 Electric Current and Direct-Current Circuits Q.85P
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits85p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits85ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits85ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.86P
The capacitor in an RC circuit is initially uncharged. In terms of R and C, determine
(a) the time required for the charge on the capacitor to rise to 50% of its final value and
(b) the time required for the initial current to drop to 10% of its initial value.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits86ps

Chapter 21 Electric Current and Direct-Current Circuits Q.87GP
CE A given car battery is rated as 250 amp-hours. Is this rating a measure of energy, power, charge, voltage, or current? Explain.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits87ps

Chapter 21 Electric Current and Direct-Current Circuits Q.88GP
CE Predict/Explain The resistivity of tungsten increases with temperature,
(a) When a light containing a tungsten filament heats up, does its power consumption increase, decrease, or stay the same?
(b) Choose the best explanation from among the following:
I. The voltage is unchanged, and therefore an increase in resistance implies a reduced power, as we can see from P = V2/R.
II. Increasing the resistance increases the power, as is clear from P = I2R.
III. The power consumption is independent of resistance, as we can see from P = IV.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits88ps

Chapter 21 Electric Current and Direct-Current Circuits Q.89GP
CE A cylindrical wire is to be doubled in length, but it is desired that its resistance remain the same,
(a) Must its radius be increased or decreased? Explain,
(b) By what factor must the radius be changed?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits89ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits89ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.90GP
CE Predict/Explain An electric space heater has a power rating of 500 W when connected to a given voltage V.
(a) If two of these heaters are connected in series to the same voltage, is the power consiuned by the two heaters greater than, less than, or equal to 1000 W? (b) Choose the best explanation from among the following:
I. Each heater consumes 500 W; therefore two of them will consume 500 W + 500 W = 1000 W.
II. The voltage is the same, but the resistance is doubled by connecting the heaters in scries. Therefore, the power consumed (P = V2/R) is less than 1000 W.
III. Connecting two heaters in series doubles the resistance. Since power depends on the resistance squared, it follows that the power consumed is greater than 1000 W.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits90ps

Chapter 21 Electric Current and Direct-Current Circuits Q.91GP
CE Two resistors, R1 = R and R2 = 2R, are connected to a battery.
(a) Which resistor dissipates more power when they are connected to the battery in series? Explain,
(b) Which resistor dissipates more power when they aie connected in parallel? Explain.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits91ps

Chapter 21 Electric Current and Direct-Current Circuits Q.92GP
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits92p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits92ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits92ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.93GP
CE Predict/Explain
(a) Referring to Problem 92 arid the circuit in Figure 21-45, does the current supplied by the battery increase, decrease, or remain the same when the switch is closed?
(a) Choose the best explanation from among the following:
I. The current decreases because only two resistors can draw current from the battery when the switch is closed.
II. Closing the switch makes no difference to the current since the second resistor is still connected to the battery as before.
III. Closing the switch shorts out the second resistor, decreases the total resistance of the circuit, and increases the current.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits93ps

Chapter 21 Electric Current and Direct-Current Circuits Q.94GP
CE Predict/Explain
(a) Referring to Problem 92 and the circuit in Figure 21-45, does the total power dissipated in the circuit increase, decrease, or remain the same when the switch is closed?
(b) Choose the best explanation from among the following:
I. Closing the switch shorts out one of the resistors, which means that the power dissipated decreases.
II. The equivalent resistance of the circuit is reduced by closing the switch, but the voltage remains the same. Therefore, from P = V2/R we see that the power dissipated increases.
III. The power dissipated remains the same because power, P = IV, is independent of resistance.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits94ps

Chapter 21 Electric Current and Direct-Current Circuits Q.95GP
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits95p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits95ps

Chapter 21 Electric Current and Direct-Current Circuits Q.96GP
CE Predict/Explain
(a) When the switch is closed in the circuit shown in Figure 21-46, does the current supplied by the battery increase, decrease, or stay the same?
(b) Choose the best explanation from among the following:
I. The current increases because three resistors are drawing current from the battery when the switch is closed, rather than just two.
II. Closing the switch makes no difference to the current because the voltage is the same as before.
III. Closing the switch decreases the current because an additional resistor is added to the circuit.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits96ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits96ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.97GP
CE Predict/Explain
(a) When the switch is closed in the circuit shown in Figure 21-46, does the total power dissipated in the circuit increase, decrease, or stay the same?
(b) Choose the best explanation from among the following:
I. Closing the switch adds one more resistor to the circuit This makes it harder for the battery to supply current which decreases the power dissipated.
II. The equivalent resistance of the circuit is reduced by closing the switch, but the voltage remains the same. Therefore from P = V2/R we see that the power dissipated increases
III. The power dissipated remains the same because power P = IV, is independent of resistance.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits97ps

Chapter 21 Electric Current and Direct-Current Circuits Q.98GP
Suppose that points A and B in Figure 21-30 are connected to a 12-V battery. Find the power dissipated in each of the resistors assuming that R = 65 Ω.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits98ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits98ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits98ps2
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits98ps3

Chapter 21 Electric Current and Direct-Current Circuits Q.99GP
You are given resistors of 413 Ω, 521 Ω, and 146 Ω. Describe how these resistors must be connected to produce an equivalent resistance of 255 Ω.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits99ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits99ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.100GP
You arc given capacitors of 18 μF, 7.2 μF, and 9.0 μF. Describe how these capacitors must be connected to produce an equivalent capacitance of 22 μF.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits100ps

Chapter 21 Electric Current and Direct-Current Circuits Q.101GP
Suppose your car carries a chargc of 85 μC. What current does it produce as it travels from Dallas to Fort Worth (35 mi) in 0.75 h?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits101ps

Chapter 21 Electric Current and Direct-Current Circuits Q.102GP
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits102p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits102ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits102ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.103GP
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits103p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits103pss

Chapter 21 Electric Current and Direct-Current Circuits Q.104GP
It is desired to construct a 5.0-Ω resistor from a 1.2-m length of tungsten wire. What diameter is needed for this wire?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits104ps

Chapter 21 Electric Current and Direct-Current Circuits Q.105GP
Electrical Safety Codes For safety reasons, electrical codes have been established that limit the amount of current a wire of a given size can carry. For example, an 18-gauge (cross- sectional area = 1.17 mm2), rubber-insulated extension cord with copper wires can carry a maximum current of 5.0 A. Find the voltage drop in a 12-ft, 18-gauge extension cord carrying a current of 5.0 A. (Note: In an extension cord, the current must flow through two lengths—down and back.)
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits105ps

Chapter 21 Electric Current and Direct-Current Circuits Q.106GP
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits106p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits106ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits106ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.107GP
A portable CD player uses a current of 7.5 mA at a potential difference of 3.5 V.
(a) How much energy does the player use in 35 s?
(b) Suppose the player has a mass of 0.65 kg. For what length of time could the player operate on the energy required to lift it through a height of 1.0 m?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits107ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits107ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.108GP
An electrical heating coil is immersed in 4.6 kg of water at 22 °C. The coil, which has a resistance of 250 Ω, warms the water to 32 °C in 15 min. What is the potential difference at
which the coil operates?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits108ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits108ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.109GP
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits109p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits109ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits109ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits109ps2

Chapter 21 Electric Current and Direct-Current Circuits Q.110GP
A silver wire and a copper wire have the same volume and the same resistance. Find the ratio of their radii, r silver/r copper·
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits110ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits110ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.111GP
Two resistors are connected in series to a battery with an emf of 12 V. The voltage across the first resistor is 2.7 V and the current through the second resistor is 0.15 A. Find the resistance of the two resistors.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits111ps

Chapter 21 Electric Current and Direct-Current Circuits Q.112GP
BIOPacemaker Pulses A pacemaker sends a pulse to a patient’s heart every time the capacitor in the pacemaker charges to a voltage of 0.25 V. It is desired that the patient receive 75 pulses per minute. Given that the capacitance of the pacemaker is 110 μF and that the battery has a voltage of 9.0 V, what value should the resistance have?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits112ps

Chapter 21 Electric Current and Direct-Current Circuits Q.113GP
A long, thin wire has a resistance R. The wire is now cut into three segments of equal length, which are connected in parallel. In terms of R, what is the equivalent resistance of the three wire segments?
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits113ps

Chapter 21 Electric Current and Direct-Current Circuits Q.114GP
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits114p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits114ps

Chapter 21 Electric Current and Direct-Current Circuits Q.115GP
IP Suppose we connect a 12.0-V battery to terminals A and B in Figure 21-29.
(a) Is the current in the 45-Ω resistor greater than, less than, or the same as the current in the 35-Ω resistor? Explain,
(b) Calculate the current flowing through each of the three resistors in this circuit.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits115ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits115ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits115ps2
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits115ps3

Chapter 21 Electric Current and Direct-Current Circuits Q.116GP
IP Suppose the battery in Figure 21-50 has an internal resistance of 0.73 Ω.
(a) What is the potential difference across the terminals of the battery when the switch is open?
(b) When the switch is closed, does the potential difference of the battery increase or decrease? Explain,
(c) Find the potential difference across the battery after the switch has been closed a long time.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits116ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits116ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.117GP
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits117p
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits117ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits117ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits117ps2

Chapter 21 Electric Current and Direct-Current Circuits Q.118GP
IP 15.0-V battery is connected to terminals A and B in Figure 21-41.
(a) Given that C = 15.0 μF, find the charge on each of the capacitors,
(b) Find the total energy stored in this system,
(c) If the 7.22-μF capacitor is increased in value, will the total energy stored in the circuit increase or decrease? Explain.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits118ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits118ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits118ps2
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits118ps3
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits118ps4

Chapter 21 Electric Current and Direct-Current Circuits Q.119GP
IP The switch in the RC circuit shown in Figure 21-44 is closed at t = 0.
(a) How much power is dissipated in each resistor just after t = 0 and in the limit t → ∞?
(b) What is the charge on the capacitor at the time t = 0.35 ms?
(c) How much energy is stored in the capacitor in the limit t → ∞??
(d) If the voltage of the battery is doubled, by what factor does your answer to part (c) change? Explain.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits119ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits119ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits119ps2

Chapter 21 Electric Current and Direct-Current Circuits Q.120GP
Two resistors, R1 and R2, are connected in parallel and connected to a battery. Show that the power dissipated in R1 plus the power dissipated in R2 is equal to the power dissipated in the equivalent resistor, Req, when it is connected to the same battery.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits120ps

Chapter 21 Electric Current and Direct-Current Circuits Q.121GP
A battery has an emf ε and an internal resistance r. When the battery is connected to a 25-Ω resistor, the current through the battery is 0.65 A. When the battery is connected to a 55-Ω resistor, the current is 0.45 A. Find the battery’s emf and internal resistance.
Solution:
Calculate battery’s emf and internal resistance by applying Kirchhoff’s loop rule to the circuit.
Kirchhoff’s loop rule states that as one moves around a closed loop in a circuit, the algebraic sum of the potential difference must be zero.
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits121ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits121ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.122GP
When two resistors, R1 and R2, are connected in series across a 6.0-V battery, the potential difference across R1 is 4.0 V. When R1 and R2 are connccted in parallel to the same battery, the current through R2 is 0.45 A. Find the values of R1 and R2.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits122ps

Chapter 21 Electric Current and Direct-Current Circuits Q.123GP
Suppose the voltmeter measures a potential difference of 3.70 V across the resistor. What is the current that flows through the person’s body?
A. 3.70 × 10-6A
B. 5.00 × 10-5A
C. 0.0740 A
D. 3.70 A
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits123p
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits123ps

Chapter 21 Electric Current and Direct-Current Circuits Q.124PP
What is the resistance of the person and footwear when the voltmeter reads 3.70 V?
A. 1.25 × 107Ω
B. 1.35 × 107 Ω
C. 4.63 × 107 Ω
D. 1.71 × 108 Ω
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits124ps

Chapter 21 Electric Current and Direct-Current Circuits Q.125PP
The resistance of a given person and footwear is 4.00 × 107Ω What is the reading on the voltmeter when this person is tested?
A. 0.976 V
B. 1.22 V
C. 1.25 V
D. 50.0 V
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits125ps

Chapter 21 Electric Current and Direct-Current Circuits Q.126PP
The resistance of a given person and footwear is 4.00 × 107Ω What is the reading on the voltmeter when this person is tested?
A. 0.976 V
B. 1.22 V
C. 1.25 V
D. 50.0 V
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits126ps

Chapter 21 Electric Current and Direct-Current Circuits Q.127PP
Suppose that during one test a person’s shoes become wet when water spills onto the floor. When this happens, do you expect the reading on the voltmeter to increase, decrease, or stay the same?
Solution:
Given if the shoes become wet the resistance of the person foot wear will be decreased and the current flow will be increased. This results increase in the voltmeter reading.

Chapter 21 Electric Current and Direct-Current Circuits Q.128IP
Referring to Example 21-7 Suppose the three resistors in this circuit have the values R1 = 100.0 Ω, R2 = 200.0 Ω, and R3 = 300.0 Ω, and that the emf of the battery is 12.0 V. (The resistor numbers are given in the Interactive Figure.)
(a) Find the potential difference across each resistor,
(b) Find the current that flows through each resistor.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits128ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits128ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits128ps2

Chapter 21 Electric Current and Direct-Current Circuits Q.129IP
Referring to Example 21-7 Suppose R1 = R2 = 225 Ω and R3 = R. The emf of the battery is 12.0 V. (The resistor numbers are given in the Interactive Figure.)
(a) Find the value of R such that the current supplied by the battery is 0.0750 A. (b) Find the value of R that gives a potential difference of 2.65 V across resistor 2.
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits129ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits129ps1

Chapter 21 Electric Current and Direct-Current Circuits Q.130IP
IP Referring to Example 21-9 Suppose the resistance of the 126-Ω resistor is reduced by a factor of 2. The other resistor is 275 Ω, the capacitor is 182 μF, and the battery has an emf of 3.00 V.
(a) Does the filial value of the charge on the capacitor increase, decrease, or stay the same? Explain,
(b) Does the time for the capacitor to charge to 80.0% of its final value increase, decrease, or stay the same? Explain, (c) Find the time referred to in part (b).
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits130ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits130ps1
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits130ps2

Chapter 21 Electric Current and Direct-Current Circuits Q.131IP
IP Referring to Example 21-9 Suppose the capacitance of the 182-μF capacitor is reduced by a factor of 2. The two resistors are 126 Ω and 275 Ω, and the battery has an emf of 3.00 V.
(a) Find the final value of the charge on the capacitor,
(b) Does the time for the capacitor to charge to 80.0% of its final value increase, decrease, or stay the same? Explain,
(c) Find the time referred to in part (b).
Solution:
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits131ps
Mastering Physics Solutions Chapter 21 Electric Current and Direct-Current Circuits131ps1

Mastering Physics Solutions Chapter 20 Electric Potential and Electrical Potential Energy

Mastering Physics Solutions Chapter 20 Electric Potential and Electrical Potential Energy

Mastering Physics Solutions

Chapter 20 Electric Potential and Electrical Potential Energy Q.1CQ
In one region of space the electric potential has a positive constant value. In another region of space the potential has a negative constant value. What can be said about the electric field within each of these two regions of space?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy1cqs

Chapter 20 Electric Potential and Electrical Potential Energy Q.1P
CE An electron is released from rest in a region of space with nonzero electric field. As the electron moves, does it experience an increasing or decreasing electric potential? Explain.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy1ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.2CQ
Two like charges a distance r apart have a positive electric potential energy. Conversely, two unlike charges a distance r apart have a negative electric potential energy. Explain the physical significance of these observations.
Solution:
Electric potential energy is the energy required to carry a charge from a point towards another charge. If they are like charges then they repel to each other while if they are unlike charges then an attractive force acts between them by which they are attracted by each other.
If the charges are like then due to repulsive force between them an external energy is needed to carry the charge towards another charge, so potential energy is positive. Thus positive potential energy means requirement of external energy to carry one charge towards other.
On the other hand, for unlike charges the electric potential energy is negative which represents that there is no need of external energy to carry one charge towards other, one charge is attracted by attractive force, which acts between them.

Chapter 20 Electric Potential and Electrical Potential Energy Q.2P
A uniform electric field of magnitude 4.1 × 105 N/C points in the positive x direction. Find the change in electric potential energy of a 4.5-μC charge as it moves from the origin to the points (a) (0, 6.0 m); (b) (6.0 m, 0); and (c) (6.0 m, 6.0 m).
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy2ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.3CQ
If the electric field is zero in some region of space is the electric potential zero there as well? Explain.
Solution:
No, it need not necessary:
The electric field is a measure of change in position. So the electric field is zero in two cases.
I) When the electric potential is constant or
II) When the electric potential is zero.
So the electric potential need not necessarily be zero. If the electric field is zero. It may be positive or negative.

Chapter 20 Electric Potential and Electrical Potential Energy Q.3P
A uniform electric field of magnitude 6.8 × 105 N/C points in the positive x direction. Find the change in electric potential between the origin and the points (a) (0, 6.0 m); (b) (6.0 m, 0); and (c) (6.0 m, 6.0 m).
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy3ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy3ps1

Chapter 20 Electric Potential and Electrical Potential Energy Q.4CQ
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy4cq
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy4cqs

Chapter 20 Electric Potential and Electrical Potential Energy Q.4P
BIO Electric Potential Across a Cell Membrane In a typical living cell, the electric potential inside the cell is 0.070 V lower than the electric potential outside the cell. The thickness of the cell membrane is 0.10 μm. What are the magnitude and direction of the electric field within the cell membrane?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy4ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.5CQ
How much work is required to move a charge from one location on an equipotential to another point on the same equipo­ tential?Explain.
Solution:
Since the potential difference in the equipotential surface is zero, i.e. ΔV = 0
So, the work done for a moving charge in that surface W = q. ΔV
= q.0
= 0

Chapter 20 Electric Potential and Electrical Potential Energy Q.5P
A computer monitor accelerates electrons and directs them to the screen in order to create an image. If the accelerating plates are 1.05 cm apart, and have a potential difference of 25,500 V, what is the magnitude of the uniform electric field between them?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy5ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.6CQ
It is known that the electric potential is constant on a given two- dimensional surface. What can be said about the electric field on this surface?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy6cqs

Chapter 20 Electric Potential and Electrical Potential Energy Q.6P
Find the change in electric potential energy for an electron that moves from one accelerating plate to the other in the computer monitor described in the previous problem.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy6ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.7CQ
Explain why equipotenrials are always perpendicular to the electric field.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy7cqs

Chapter 20 Electric Potential and Electrical Potential Energy Q.7P
A parallel-plate capacitor has plates separated by 0.75 mm. If the electric field between the plates has a magnitude of (a) 1.2 × 105 V/m or (b) 2.4 × 104N/C, what is the potential difference between the plates?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy7ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.8CQ
Two charges are at locations that have the same value of the electric potential. Is the electric potential energy the same for these charges? Explain.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy8cqs

Chapter 20 Electric Potential and Electrical Potential Energy Q.8P
When an ion accelerates through a potential difference of 2140 V, its electric potential energy decreases by 1.37 × 10-15 J. What is the charge on the ion?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy8ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.9CQ
A capacitor is connected to a battery and fully charged. What becomes of the charge on the capacitor when it is disconnected from the battery? What becomes of the charge when the two terminals of the capacitor are connected to one another?
Solution:
The charge on the capacitor will remains same even after it is disconnected from the circuit.
When two terminals of the capacitor are connected to one another, the charge flow from plate to plate till the charge on both the plates becomes zero.

Chapter 20 Electric Potential and Electrical Potential Energy Q.9P
The Electric Potential of the Earth The Earth has a vertical electric field with a magnitude of approximately 100 V/m near its surface. What is the magnitude of the potential difference between a point on the ground and a point on the same level as the top of the Washington Monument (555 ft high)?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy9ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.10CQ
It would be unwise to unplug a television set, take off the back, and reach inside. The reason for the danger is that if you happen to touch the terminals of a high-voltage capacitor you could receive a large electrical shock—even though the set is unplugged. Why?
Solution:
Even after the television set is unplugged, the charge in the high voltage capacitor will remain there. So, when you come in contact with this capacitor you will receive a large electric shock.

Chapter 20 Electric Potential and Electrical Potential Energy Q.10P
A uni form electric field with a magnitude of 6350 N/C points in the positive x direction. Find the change in electric potential energy when a +12.5-μC charge is moved 5.50 cm in (a) the positive x direction, (b) the negative x direction, and (c) the positive y direction.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy10ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.11CQ
On which of the following quantities does the capacitance of a capacitor depend: (a) the charge on the plates; (b) the separation of the plates; (c) the voltage difference between the plates; (d) the electric field between the plates; or (e) the area of the plates?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy11cqs

Chapter 20 Electric Potential and Electrical Potential Energy Q.11P
IP A spark plug in a car has electrodes separated by a gap of 0.025 in. To create a spark and ignite the air-fuel mixture in the engine, an electric field of 3.0 × 106 V/m is required in the gap. (a) What potential difference must be applied to the spark plug to initiate a spark? (b) If the separation between electrodes is increased, docs the required potential difference increase, decrease, or stay the same? Explain, (c) Find the potential difference for a separation of 0.050 in.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy11ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.12CQ
We say that a capacitor stores charge, yet the total charge in a capacitor is zero; that is, Q + (−Q) = 0. In what sense does a capacitor store charge if the net charge within it is zero?
Solution:
Though the net charge of a capacitor is zero, charge of opposite signs is stored in two different locations. So we can say that a capacitor stores opposite charges separately and even has the energy needed to cause the separation.

Chapter 20 Electric Potential and Electrical Potential Energy Q.12P
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy12p
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy12ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy12ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy12ps2

Chapter 20 Electric Potential and Electrical Potential Energy Q.13CQ
The plates of a particular parallel-plate capacitor are uncharged. Is the capacitance of this capacitor zero? Explain.
Solution:
No.
The capacitance of this capacitor is not zero even if the plates of the parallel-plate capacitor are uncharged because the term CAPACITANCE defines the capacity of the capacitor which will not be zero.

Chapter 20 Electric Potential and Electrical Potential Energy Q.13P
A Charged Battery A typical 12-V car battery can deliver 7.5 × 105 C of charge. If the energy supplied by the battery could be converted entirely to kinetic energy, what speed would it give to a 1400-kg car that is initially at rest?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy13ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.14P
IP BIO The Sodium Pump Living cells actively “pump” positive sodium ions (Na+) from inside the cell to outside the cell. This process is referred to as pumping because work must be done on the ions to move them from the negatively charged inner surface of the membrane to the positively charged outer surface. Given that the electric potential is 0.070 V higher outside the cell than inside the cell, and that the cell membrane is 0.10 μm thick, (a) calculate the work that must be done (in joules) to move one sodium ion from inside the cell to outside. (b) If the thickness of the cell membrane is increased, does your answer to part (a) increase, decrease, or stay the same? Explain. (It is estimated that as much as 20% of the energy we consume in a resting state is used in operating this “sodium pump.”)
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy14ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.15P
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy15p
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy15ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy15ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy15ps2

Chapter 20 Electric Potential and Electrical Potential Energy Q.16P
Points A and B have electric potentials of 332 V and 149 V, respectively. When an electron released from rest at point A arrives at point C, its kinetic energy is KA. When the electron is released from rest at point B, however, its kinetic energy when it reaches point C is KB = 2KA. What are (a) the electric potential at point C and (b) the kinetic energy KA?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy16ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy16ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy16ps2

Chapter 20 Electric Potential and Electrical Potential Energy Q.17P
CE Predict/Explain An electron is released from rest in a region of space with a nonzero electric field, (a) As the electron
moves, does the electric potential energy of the system increase, decrease, or stay the same? (b) Choose the best explanation from among the following:
I. Because the electron has a negative charge its electric potential energy doesn’t decrease, as one might expect, but increases instead.
II. As the electron begins to move, its kinetic energy increases. The increase in kinetic energy is equal to the decrease in the electric potential energy of the system.
III. The electron will move perpendicular to the electric field, and hence its electric potential energy will remain the same.
Solution:
(a) The electron potential energy decrease This decrease in potential energy converted into the kinetic energy gained by the electron. This is due to the conservation of energy.
(b) So increase in kinetic energy of electron is equal to the decrease in potential energy of system. So best explanation is (II)

Chapter 20 Electric Potential and Electrical Potential Energy Q.18P
Calculate the speed of (a) a proton and (b) an electron after each particle accelerates from rest through a potential difference of 275 V.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy18ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy18ps1

Chapter 20 Electric Potential and Electrical Potential Energy Q.19P
The electrons in a TV picture tube are accelerated from rest through a potential difference of 25 kV. What is the speed of the electrons after they have been accelerated by this potential difference?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy19ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.20P
Find the potential difference required to accelerate protons from rest to 10% of the speed of light. (At this point, relativistic effects start to become significant.)
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy20ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy20ps1

Chapter 20 Electric Potential and Electrical Potential Energy Q.21P
IP A particle with a mass of 3.8 g and a charge of +0.045 μC is released from rest at point A in Figure 20-20. (a) In which di­rection will this charge move? (b) What speed will it have after moving through a distance of 5.0 cm? The electric field has a magnitude of 1200 N/C. (c) Suppose the particle continues moving for another 5.0 cm. Will its increase in speed for the second 5.0 cm be greater than, less than, or equal to its increase in speed in the first 5.0 cm? Explain.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy21ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy21ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy21ps2
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy21ps3

Chapter 20 Electric Potential and Electrical Potential Energy Q.22P
A proton has an initial speed of 4.0 × 105 m/s. (a) What potential difference is required to bring the proton to rest? (b) What potential difference is required to reduce the initial speed of the proton by a factor of 2? (c) What potential difference is required to reduce the initial kinetic energy of the proton by a factor of 2?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy22ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy22ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy22ps2
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy22ps3

Chapter 20 Electric Potential and Electrical Potential Energy Q.23P
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy23p
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy23ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy23ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy23ps2

Chapter 20 Electric Potential and Electrical Potential Energy Q.24P
CE The charge q1 in Figure 20-22 has the value +Q. (a) What value must q2 have if the electric potential at point B is to be zero? (b) With the value for q2 found in part (a), is the electric potential at point A positive, negative, or zero? Explain.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy24ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy24ps1

Chapter 20 Electric Potential and Electrical Potential Energy Q.25P
CE It is given that the electric potential is zero at the center of the square in Figure 20-22. (a) If q1 = +Q, what is the value of the charge q2? (b) Is the electric potential at point A positive, negative, or zero? Explain, (c) Is the electric potential at point B positive, negative, or zero? Explain.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy25ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy25ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy25ps2
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy25ps3
The above value shows the net electric potential at point B is negative. This is because the point B is closer to the negative charge as compare to positive charge. The electric potential is inversely proportional to distance of the point from the charge. The less distance from the negative charge implies that the potential due to negative charge is greater than the potential due to positive charge.
Hence, the net electric potential at point B is .negative

Chapter 20 Electric Potential and Electrical Potential Energy Q.26P
The electric potential 1.1 m from a point charge q is 2.8 × 104 V. What is the value of q?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy26ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.27P
A point charge of -7.2 μC is at the origin. What is the electric- potential at (a) (3.0 m, 0); (b) (−3.0 m, 0); and (c) (3.0 m,-3.0 m)
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy27ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy27ps1

Chapter 20 Electric Potential and Electrical Potential Energy Q.28P
The Bohr Atom The hydrogen atom consists of one electron and one proton, hi the Bohr model of the hydrogen atom the electron orbits the proton in a circular orbit of radius 0.529 × 10-10 m. What is the electric potential due to the proton at the electron’s orbit?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy28ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.29P
How far must the point charges q1 = +7.22 μC and q2 = −26.1 μC be separated for the electric potential energy of the system to be −126 J?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy29ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.30P
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy30p
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy30pss
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy30pss1

Chapter 20 Electric Potential and Electrical Potential Energy Q.31P
IP Point charges +4.1 μC and −2.2μC are placed on the x axis at (11 m, 0) and (−11 m, 0), respectively, (a) Sketch the electric potential on the x axis for this system, (b) Your sketch should show one point on the x axis between the two charges where the potential vanishes. Is this point closer to the +4.1-−μC charge or closer to the −2.2-μC charge? Explain, (c) Find the point referred to in part (b).
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy31ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy31ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy31ps2

Chapter 20 Electric Potential and Electrical Potential Energy Q.32P
IP (a) In the previous problem, find the point to the left of the negative charge where the electric potential vanishes, (b) Is the electric field at the point found in part (a) positive, negative, or zero? Explain.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy32ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy32ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy32ps2
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy32ps3

Chapter 20 Electric Potential and Electrical Potential Energy Q.33P
A dipole is formed by point charges +3.6 μC and −3.6 μC placed on the x axis at (0.25 m, 0) and (-0.25 m, 0), respectively. (a) Sketch the electric potential on the x axis for this system. (b) At what positions on the x axis does the potential have the value 7.5 × 105 V?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy33ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy33ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy33ps2
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy33ps3
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy33ps4

Chapter 20 Electric Potential and Electrical Potential Energy Q.34P
A charge of 3.05 μC is held fixed at the origin. A second charge of 3.05 μC is released from rest at the position (1.25 m, 0.570 m). (a) Tf the mass of the second charge is 2.16 g, what is its speed when it moves infinitely far from the origin? (b) At what distance from the origin does the second charge attain half the speed it will have at infinity?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy34ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy34ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy34ps2
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy34ps3
Therefore the second particle attains half of the speed at infinity at a distance of 1.84m from the origin.

Chapter 20 Electric Potential and Electrical Potential Energy Q.35P
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy35p
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy35ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy35ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy35ps2
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy35ps3

Chapter 20 Electric Potential and Electrical Potential Energy Q.36P
A charge of -2.205 μC is located at (3.055 m, 4.501 in), and a charge of 1.800 μC is located at (−2.533 m, 0). (a) Find the electric potential at tine origin, (b) There is one point on the line connecting these two charges where the potential is zero. Find this point.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy36ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy36ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy36ps2
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy36ps3

Chapter 20 Electric Potential and Electrical Potential Energy Q.37P
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy37p
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy37ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy37ps1
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy37ps2
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy37ps3

Chapter 20 Electric Potential and Electrical Potential Energy Q.38P
How much work must be done to move the three charges in Figure 20-24 infinitely far from one another?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy38ps
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy38ps1
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Chapter 20 Electric Potential and Electrical Potential Energy Q.39P
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Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.40P
A square of side a has a charge +Q at each corner. What is the electric potential energy of this system of charges?
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.41P
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Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.42P
CE Predict/Explain A positive charge is moved from one location on an equipotential to another point on the same equipotential. (a) Is the work done on the charge positive, negative, or zero? (b) Choose the best explanation from among the following: I. The electric field is perpendicular to an equipotential, therefore the work done in moving along an equipotential is zero.
I. Because the charge is positive the work done on it is also positive.
II. It takes negative work to keep the positive charge from accelerating as it moves along the equipotential.
Solution:
(a) Given,
A positive charge is moved from one location to another location in which both the locations are at same equipotential. Since the positive charge is moving in same equipotential there is no work done by the positive charge because of same equipotential. So work done in moving the positive charge from one place to another place is zero.
(b) The electric field is perpendicular to an equipotential therefore the work done in moving along equipotential is zero.
Therefore is the best explanation.

Chapter 20 Electric Potential and Electrical Potential Energy Q.43P
CE Predict/Explain (a) Is the electric potential at point 1 in Figure 20-19 greater than, less than, or equal to the electric potential at point 3? (b) Choose the best explanation from among the following:
I. The electric field lines point to the right, indicating that the electric potential is greater at point 3 than at point 1.
II. The value of the electric potential is large where the electric field lines are close together, and small where they are widely spaced. Therefore, the electric potential is the same at points 1 and 3.
III· The electric potential decreases as we move in the direction of the electric field, as shown in Figure 20-3. Therefore, the electric potential is greater at point 1 than at point 3.
Solution:
(a) The electric potential at point 1 is greater than the electric potential at point 3.
(b) We know that the direction of electric field is from high potential to low potential. Therefore the electric potential will decrease when we move in the field direction. In the figure the direction of electric field is from point 1 to point 3. So the electric potential at point 1 is greater than the electric potential at point 3.
Therefore option III is the best explanation.

Chapter 20 Electric Potential and Electrical Potential Energy Q.44P
CE Predict/Explain Imagine sketching a large number of equipotential surfaces in Figure 20-19, with a constant difference in electric potential between adjacent surfaces, (a) Would the equipotentials at point 2 be more closely spaced, be less closely spaced, or have the same spacing as equipotentials at point 1? (b) Choose the best explanation from among the following:
I. When electric field lines are close together, the corresponding equipotentials are far apart.
II. Equipotential surfaces, by definition, always have equal spacing between them.
III. The electric field is more intense at point 2 than at point 1, which means the equipotential surfaces are more closely spaced in that region.
Solution:
(a) When we draw large number of equipotential surfaces with constant potential difference between adjacent surfaces, the equipotentials at point 2 are more closely spaced as equipotentials at point1.
Comment
(b) From the figure it is clear that the electric field is more intense near point 2 than near point 1, because the field lines are packed more closely together near point 2. This means, in turn, that the electric potential changes more rapidly with position at point 2. As a result, the spacing between equipotential surfaces at point 2 is less than the spacing between equipotential surfaces at point 1.
Therefore option III is the best explanation.

Chapter 20 Electric Potential and Electrical Potential Energy Q.45P
Two point charges are on the x axis. Charge 1 is +q and is located at x = −1.0 m; charge 2 is −2q and is located at x = 1.0 m. Make sketches of the equipotential surfaces for this system (a) out to a distance of about 2.0 m from the origin and (b) far from the origin, In each case, indicate the direction in· which the potential increases.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy45ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.46P
Two point charges are on the x axis. Charge 1 is +q and is located at x = −1.0 m; charge 2 is +2q and is located at x − 1.0 m. Make sketches of the equipotential surfaces for this system (a) out to a distance of about 2.0 m from the origin and (b) far from the origin. In each case, indicate the direction in which the potential increases.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.47P
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Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.48P
IP Consider a region in space where a uniform electric field E = 6500 N/C points in the negative x direction, (a) What is the orientation of the equipotential surfaces? Explain, (b) If you
move in the positive x direction, does the clectric potential increase or decrease? Explain, (c) What is the distance between the +14-V and the +16-V equipotentials?
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.49P
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Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.50P
A 0.40−μF capacitor is connected to a 9.0-V battery. How much charge is on each plate of the capacitor?
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.51P
It is desired that 5.8 μC of charge be stored on each plate of a 3.2-μ F capacitor. What potential difference is required between the plates?
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.52P
To operate a given flash lamp requires a charge of 32 μC. What capacitance is needed to store this much charge in a capacitor with a potential difference between its plates of 9.0 V?
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.53P
A parallel-plate capacitor is made from two aluminum-foil sheets, each 6.3 cm wide and 5.4 m long. Between the sheets is a Teflon strip of the same width and length that is 0.035 mm thick. What is the capacitance of this capacitor? (The dielectric constant of Teflon is 2.1.)
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.54P
parallel-plate capacitor is constructed with circular plates of radius 0.056 m. The plates are separated by 0.25 mm, and the space between the plates is filled with a dielectric with dielectric constant κ. When the charge on the capacitor is 1.2 μC the potential difference between the plates is 750 V. Find the value of the dielectric constant, κ.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.55P
IP A parallel-plate capacitor has plates with an area of 0.012 m2 and a separation of 0.88 mm. The space between the plates is filled with a dielectric whose dielectric constant is 2.0. (a) What is the potential difference between the plates when the charge on the capacitor plates is 4.7 μC? (b) Will your answer to part (a) increase, decrease, or stay the same if the dielectric constant is increased? Explain, (c) Calculate the potential difference for the case where the dielectric constant is 4.0.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.56P
IP Consider a parallel-plate capacitor constructed from two circular metal plates of radius R. The plates arc separated by a distance of 1.5 mm. (a) What radius must the plates have if the capacitance of this capacitor is to be 1.0 μF? (b) If the separation between the plates is increased, should the radius of the plates be increased or decreased to maintain a capacitance of 1.0 μF? Explain, (c) Find the radius of the plates that gives a capacitance of 1.0 μF for a plate separation of 3.0 mm.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.57P
A parallel-plate capacitor has plates of area 3.45 × 10-4 m2. What plate separation is required if the capacitance is to be 1630 pF? Assume that the space between the plates is filled with (a) air or (b) paper.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.58P
IP A parallel-plate capacitor filled with air has plates of are 0.0066 m2 and a separation of 0.45 mm. (a) Find the magnitude of the charge on each plate when the capacitor is connected to a 12-V battery, (b) Will your answer to part (a) increase, decrease or stay the same if the separation between the plates is increased? Explain, (c) Calculate the magnitude of the charge on the plates if the separation is 0.90 mm.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.59P
Suppose that after walking across a carpeted floor you reach for a doorknob and just before you touch it a spark jumps 0.50 cm from your finger to the knob. Find the minimum voltage needed between your finger and the doorknob to generate this spark.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.60P
(a) What plate area is required if an air-filled, parallel-plate capacitor with a plate separation of 2.6 mm is to have a capacitance of 22 pF? (b) What is the maximum voltage that can be applied to this capacitor without causing dielectric breakdown?
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.61P
Lightning As a crude model for lightning, consider the ground to be one plate of a parallel-plate capacitor and a cloud at an altitude of 550 m to be the other plate. Assume the surface area of the cloud to be the same as the area of a square that is 0.50 km on a side, (a) What is the capacitance of this capacitor? (b) How much charge can the cloud hold before the dielectric strength of the air is exceeded and a spark (lightning) results?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy61ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.62P
A parallel-plate capacitor is made from two aluminum-foil sheets, each 3.00 cm wide and 10.0 m long. Between the sheets is a mica strip of the same width and length that is 0.0225 mm thick. What is the maximum charge that can be stored in this capacitor? (The dielectric constant of mica is 5.4, and its dielectric strength is 1.00 x 108V/m.)
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.63P
Calculate the work done by a 3.0-V battery as it charges a 7.8-μF capacitor in the flash unit of a camera
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.64P
BIO Defibrillator An automatic external defibrillator (AED) delivers 125 J of energy at a voltage of 1050 V. What is the capacitance of this device?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy64ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.65P
IP BIO Cell Membranes The membrane of a living cell can be approximated by a parallel-plate capacitor with plates of area 4.75 × 10-9 m2, a plate separation of 8.5 × 10-9 m, and a dielectric with a dielectric constant of 4.5. (a) What is the energy stored in such a cell membrane if the potential difference across it is 0.0725 V? (b) Would your answer to part (a) increase, de­crease, or stay the same if the thickness of the cell membrane is increased? Explain.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.66P
A 0.22-μF capacitor is charged by a 1.5-V battery. After being charged, the capacitor is connected to a small electric motor. Assuming 100% efficiency, (a) to what height can the motor lift a 5.0-g mass? (b) What initial voltage must the capacitor have if it is to lift a 5.0-g mass through a height of 1.0 cm?
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.67P
Find the electric energy density between the plates of a 225-μF parallel-plate capacitor. The potential difference between the plates is 345 V, and the plate separation is 0.223 mm.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.68P
What electric field strength would store 17.5 Jof energy in every 1.00 mm3 of space?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy68ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.69P
An electronic flash unit for a camera contains a capacitor with a capacitance of 890 μF. When the unit is fully charged and ready for operation, the potential difference between the capacitor plates is 330 V. (a) What is the magnitude of the charge on each plate of the fully charged capacitor? (b) Find the energy stored in the “charged-up” flash unit.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.70P
A parallel-plate capacitor has plates with an area of 405 cm2 and an air-filled gap between the plates that is 2.25 mm thick. The capacitor is charged by a battery to 575 V and then is dis- connected from the battery, (a) How much energy is stored in the capacitor? (b) The separation between the plates is now in- creased to 4.50 mm. How much energy is stored in the capacitor now? (c) How much work is required to increase the separation of the plates from 2.25 mm to 4.50 mm? Explain your reasoning.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.71GP
CE A proton is released from rest in a region of space with a nonzero electric field. As the proton moves, does it experience an increasing or decreasing electric potential? Explain.
Solution:
Apply the concept of electric field and the direction of electric field lines to discuss the motion of a charged particle in non-zero electric field.
In electrostatics, the positively charged region is treated as higher potential region and the negatively charged region is treated as lower potential region. The electric fields lines always points from the higher potential region to the lower potential region. Since the proton is a positively charged particle, the proton movement is in the line of direction of the electric field that is it travels towards the lower potential region. Therefore, the proton travels experience decreasing electric potential in the non-zero electric field region.

Chapter 20 Electric Potential and Electrical Potential Energy Q.72GP
CE Predict/Explain A proton is released from rest in a region of space with a nonzero electric field, (a) As the proton moves, does the electric potential energy of the system increase, decrease, or stay the same? (b) Choose the best explanation from among the following:
I. As the proton begins to move, its kinetic energy increases. The increase in kinetic energy is equal to the decrease in the electric potential energy of the system.
II. Because the proton has a positive charge, its electric potential energy will always increase.
III. The proton will move perpendicular to the electric field, and hence its electric potential energy will remain the same.
Solution:
(a)
If the proton released from rest in the region of space with non-zero electric field it gains kinetic energy.
From the conservation of energy, total energy (Sum of kinetic energy and electric potential energy) of the system is constant.
Then the electric potential energy of the proton must decrease to increase the kinetic energy of the proton.
(b)
As proton begins to move, its kinetic energy increases.
The increases in the kinetic energy are equal to the decrease in the electric potential energy of the system.
ANS: I

Chapter 20 Electric Potential and Electrical Potential Energy Q.73GP
CE In the Bohr model of the hydrogen atom, a proton and an electron are separated by a constant distance r. (a) Would the clectric potential energy of the system increase, decrease, or stay the same if the electron is replaced with a proton? Explain, (b) Suppose, instead, that the proton is replaced with an electron. Would the electric potential energy of the system increase, decrease, or stay the same? Explain.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.74GP
CE The plates of a parallel-plate capacitor have constant charges of +Q and-Q. Do the following quantities increase, decrease, or remain the same as the separation of the plates is increased? (a) The electric field between the plates; (b) the potentiell difference between the plates; (c) the capacitance; (d) the energy stored in the capacitor.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.75GP
CE A parallel-plate capacitor is connected to a battery that maintains a constant potential difference V between the plates. If the plates of the capacitor are pulled farther apart, do the following quantities increase, decrease, or remain the same? (a) The electric field between the plates; (b) the charge on the plates; (c) the capac- itance; (d) the energy stored in the capacitor.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.76GP
CE The plates of a parallel-plate capacitor have constant charges of +Q and −Q. Do the following quantities increase, decrease, or remain the same as a dielectric is inserted between the plates? (a) The electric field between the plates; (b) the po­tential difference between the plates; (c) the capacitance; (d) the energy stored in the capacitor.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.77GP
CE A parallel-plate capacitor is connected to a battery that maintains a constant potential difference V between the plates. If a dielectric is inserted between the plates of the capacitor, do the following quantities increase, decrease, or remain the same? (a) The electric field between,the plates; (b) the charge on the plates; (c) the capaci tance; (d) the energy stored in the capacitor.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy77ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.78GP
Find the difference in electric potential, ΔV = VB — VA between the points A and B for the following cases: (a) The electric field does 0.052 J of work as you move a +5.7-μC charge from A to B. (b) The electric field does -0.052 J of work as you move a −5.7-μC charge from A to B. (c) You perform 0.052 J of work as you slowly move a +5.7-μC charge from A to B.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.79GP
The separation between the plates of a parallel-plate capacitor is doubled and the area of the plates is halved. How is the capacitance affected?
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.80GP
A parallel-plate capacitor is connected to a battery that maintains a constant potential difference between the plates. If the spacing between the plates is doubled, how is the magnitude of charge on the plates affected?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy80ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.81GP
CE Two point charges arc placed on the x axis. The charge +2q is at x = 1.5 m, and the charge —q is at x = −1.5 m. (a) There is a point on the x axis between the two charges where the electric potential is zero. Where is this point? (b) The electric potential also vanishes at a point in one of the following regions: region 1, x between 1.5 m and 5.0 m; region 2, x between −1.5 m and −3.0 m; region 3, x between −3.5 m and −5.0 m. Identify the appropriate region, (c) Find the value of x referred to in part (b).
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.82GP
A charge of 24.5 μC is located at (4.40 m, 6.22 m), and a charge of −11.2 μC is located at (−4.50 m, 6.75 m). What charge must be located at (2.23 m, −3.31 m) if the electric potential is to be zero at the origin?
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.83GP
The Bohr Model In the Bohr model of the hydrogen atom (see Problem 28) what is the smallest amount of work that must be done on the electron to move it from its circular orbit, with a radius of 0.529 × 10−10 m, to an infinite distance from the proton? This value is referred to as the ionization energy of hydrogen.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy83ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.84GP
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy84p
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.85GP
Repeat Problem 84 for the case where both charges arc +1.2 μC.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.86GP
How much work is required to bring three protons, initially infinitely far apart, to a configuration where each proton is 1.5 × 10-15 m from the other two? (This is a typical separation for protons in a nucleus.) ·
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy86ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.87GP
A point charge Q = +87.1 μC is held fixed at the origin. A second point charge, with mass m = 0.0576 kg and charge q = −2.87 μC, is placed at the location (0.323 m, 0). (a) Find the clectric potential energy of this system of charges, (b) If the second charge is released from rest, what is its speed when it reaches the point (0.121 m, 0)?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy87ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.88GP
Electron Escape Speed An electron is at rest just above the surface of a sphere with a radius of 2.7 mm and a uniformly distributed positive charge of 1.8 × 10-15 C. Like a rocket blasting off from the Earth, the electron is given an initial speed vc radially
outward from the sphere. If the electron coasts to infinity, where its kinetic energy drops to zero, what is the escape speed, ve?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy88ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.89GP
Quark Model of the Neutron According to the quark model of fundamental particles, neutrons—the neutral particles in an atom’s nucleus—are composed of three quarks. Two of these quarks are “down” quarks, each with a charge of —e/3; the third quark is an “up” quark, with a charge of +2e/3. This gives the neutron a net charge of zero. What is the electric potential energy of these three quarks, assuming they are equidistant from one another, with a separation distance of 1.3 × 10-15 m? (Quarks are discussed in Chapter 32.)
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy89ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.90GP
A parallel-plate capacitor is charged to an electric potential of 325 V by moving 3.75 × 1016 electrons from one plate to the other. How much work is done in charging the capacitor?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy90ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.91GP
IP The three charges shown in Figure 20-25 are held in place as a fourth charge, q, is brought from infinity to the point P. The charge q starts at rest at infinity and is also at rest when it is placed at the point P. (a) If q is a positive charge, is the work required to bring it to the point P positive, negative, or zero? Explain. (b) Find the value of (/ if the work needed to bring it to point P is −1.3 × 10-11 J.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.92GP
(a) In Figure 20-28 we see that the electric potential increases by 10.0 V as one moves 4.00 cm in the positive x direction. Use this information to calculate the x component of the electric field. (Ignore the y direction for the moment.) (b) Apply the same reasoning as in part (a) to calcidate the y component of the electric field, (c) Combine the results from parts (a) and (b) to find the magnitude and direction of the electric field for this system.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy92ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.93GP
IP BIO Electric Catfish The electric catfish (Malapterurs electricus) is an aggressive fish, 1.0 m in length, found today in tropical Africa (and depicted in Egyptian hieroglyphics). The catfish is capable of generating jolts of electricity up to 350 V by producing a positively charged region of muscle near the head and a negatively charged region near the tail, (a) For the same amount of charge, can the catfish generate a higher voltage by separating the charge from one end of its body to the other, as it does, or from one side of the body to the other? Explain, (b) Estimate the charge generated at each end of a catfish as follows: Treat the catfish as a parallel-plate capacitor with plates of area 1.8 × 10-2 m2, separation 1.0 m, and filled with a dielectric with a dielectric constant K = 95.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy93ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.94GP
As a +6.2-μC charge moves along the x axis from x = 0 to x = 0.70 m, the electric potential it experiences is shown in Figure 20-21. Find the approximate location(s) of the charge when its electric potential energy is (a) 2.6 × 10—5 J and (b) 4.3 × 10—5 J.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy94ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.95GP
IP Computer Keyboards Many computer keyboards operate on the principle of capacitance. As shown in Figure 20-16, each key forms a small parallel-plate capacitor whose separation is reduced when the key is depressed, (a) Does depressing a key increase or decrease its capacitance? Explain, (b) Suppose the plates for each key have an area of 47.5 mm2,and an initial separation of 0.550 mm. In addition, let the dielectric have a dielectric constant of 3.75. If the circuitry of the computer can de­tect a change in capacitance of 0.425 pF, what is the minimum distance a key must be depressed to be detected?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy95ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.96GP
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy96p
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy96ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.97GP
BIO Cell Membranes and Dielectrics Many cells in the body have a cell membrane whose inner and outer surfaces carry opposite charges, just like the plates of a parallel-plate ca­pacitor. Suppose a typical cell membrane has a thickness of 8.1 × 10-9 m, and its inner and outer surfaces carry charge densities of −0.58 × 10 3 C/m2 and +0.58 × 10-3 C/m2, respectively. In addition, assume that the material in the cell membrane has a dielectric constant of 5.5. (a) Find the direction and magnitude of the electric field within the cell membrane, (b) Calculate the potential difference between the inner and outer walls of the membrane, and indicate which wall of the membrane has the higher potential.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy97ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.98GP
Long, long ago, on a planet far, far away, a physics experiment was carried out. First, a 0.250-kg ball with zero net charge was dropped from rest at a height of 1.00 m. The ball landed 0.552 s later. Next, the ball was given a net charge of 7.75 μC and dropped in the same way from the same height. This time the ball fell for 0.680 s before landing. What is the electric potential at a height of 1.00 m above the ground on this planet, given that the electric potential at ground level is zero? (Air resistance can be ignored.)
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy98ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.99GP
Rutherford’s Planetary Model of the Atom In 1911, Ernest Rutherford developed a planetary model of the atom, in which a small positively charged nucleus is orbited by electrons. The model was motivated by an experiment carried out by Rutherford and his graduate students, Geiger and Marsden. In tIn s experiment, they fired alpha particles with an initial speed of 1.75 × 107 m/s at a tIn n sheet of gold. (Alpha particles are obtained from certain radioactive decays. They have a charge of +2e and a mass of 6.64 × 10-27 kg.) Flow close can the alpha particles get to a gold nucleus (charge = +79e), assuming the nucleus remains stationary? (This calculation sets an upper limit on the size of the gold nucleus. See Chapter 31 for further details.)
Solution:
The work energy theorem states that the total work done of a system is equal to its change in kinetic energy.
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Chapter 20 Electric Potential and Electrical Potential Energy Q.100GP
IP (a) One of the — Q charges in Figure 20-26 is given an outward “kick” that sends it off with an initial speed V0 wIn le the other three charges are held at rest. If the moving charge has a mass m, what is its speed when it is infinitely far from the other charges? (b) Suppose the remaining — Q charge, wIn ch also has a mass m, is now given the same initial speed, V0. When it is infinitely far away from the two +Q charges, is its speed greater than, less than, or the same as the speed found in part (a)? Explain.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy100ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.101GP
Figure 20-30 shows a charge q = +6.77 μC with a mass m = 0.071 kg suspended by a thread of length L = 0.022 m between the plates of a capacitor, (a) Plot the electric potential energy of the system as a function of the angle θ the thread makes with the vertical. (The electric field between the plates has a magnitude E = 4.16 × 104 V/m.) (b) Repeat part (a) for
tine case of the gravitational potential energy of the system, (c) Show that the total potential energy of the system (electric plus gravitational) is a minimum when the angle θ satisfies the equilibrium condition for the charge, tan θ = qE/mg. TIn s relation implies that θ = 22°.
Solution:
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Chapter 20 Electric Potential and Electrical Potential Energy Q.102GP
The electric potential a distance r from a point charge q is 2.70 × 104 V. One meter farther away from the charge the potential is 6140 V. Find the charge q and the initial distance r.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy102ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.103GP
Referring to Problem 84, calculatc and plot the electric potential on the circle centered at (0.50 m, 0). Give your results in terms of the angle ×, defined as follows: θ is the angle measured counterclockwise from a vertex at the center of the circle, with θ = 0 at point C.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy103ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.104GP
When the potential difference between the plates of a capacitor is increased by 3.25 V, the magnitude of the charge on each plate increases by 13.5 μC. What is the capacitance of this capacitor?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy104ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.105PP
The electric potential a distance r from a point charge q is 155 V, and the magnitude of the elcctric field is 2240 N/C. Find the values of q and r.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy105ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.106PP
Electric eels produce an electric field witIn n their body. In which direction does the electric field point?
A. toward the head
B. toward the tail
C. upward
D. downward
Solution:
As the muscle cells called electro plaques producing each of 0.15V, these electro plaques are producing voltage in the body of eel together by producing the positive charge at head and negative charge at tail.
So electric field in the eel body is directed toward the tail.
So the correct option is (B)

Chapter 20 Electric Potential and Electrical Potential Energy Q.107PP
As a rough approximation, consider an electric eel to be a parallel-plate capacitor with plates of area 1.8 × 10-2 m2 separated by 2.0 m and filled with a dielectric whose dielectric constant is κ = 95. What is the capacitance of the eel in this model?
A. 8.0 × 10-14 F
B. 7.6 × 10-12 F
C. 1.5 ×10-11 F
D. 9.3 ×10-8 F
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy107ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.108PP
In terms of the parallel-plate model of the previous problem, how much charge does an electric eel generate at each end of its body when it produces a voltage of 650 V?
A. 1.2 ×10-14C
B. 5.2 ×10-11 C
C. 4.9×10-9 C
D. 6.1 ×10-5C
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy108ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.109PP
How much energy is stored by an electric eel when it is charged up to 650 V. Use the same parallel-plate model discussed in the previous two problems.
A. 1.8 ×10-17J
B. 1.7 ×10-8J
C. 1.6×10-6J
D. 2.0×10-2J
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy109ps

Chapter 20 Electric Potential and Electrical Potential Energy Q.110PP
IP Referring to Example 20-3 Suppose the charge -2q at x = 1.00 m is replaced with a charge -3q, where q = 4.11 ×10-9 C. The charge +q is at the origin, (a) Is the electric potential positive, negative, or zero at the point x = 0.333 m? Explain. (b) Find the point between x = 0 and x = 1.00 m where the electric potential vanishes, (c) Is there a point in the region x < 0 where the clectric potential passes through zero?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy110ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.111IP
Referring to Example 20-3 Suppose we can change the location of the charge −2q on the x axis. The charge +q (where q = 4.11 × 10-9C) is still at the origin, (a) Where should the charge −2q be placed to ensure that the electric potential vanishes at x = 0.500 m? (b) With the location of −2q found in part (a), where does the clectric potential pass through zero in the region x < 0?
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy111ps
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Chapter 20 Electric Potential and Electrical Potential Energy Q.112IP
IP Referring to Example 20-3 Suppose the charge +q at the origin is replaced with a charge +5q, where q = 4.11 × 10-9 C. The charge -2q is still at x = 1.00 m. (a) Is there a point in the region x<0 where the electric potential passes through zero? (b) Find the location between x = 0 and x = 1.00 m where the electric potential passes through zero, (c) Find the location in the region x > 1.00 m where the electric potential passes through zero.
Solution:
mastering-physics-solutions-chapter-20-electric-potential-and-electrical-potential-energy112ps
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Mastering Physics Solutions Chapter 19 Electric Charges, Forces, and Fields

Mastering Physics Solutions Chapter 19 Electric Charges, Forces, and Fields

Mastering Physics Solutions

Chapter 19 Electric Charges, Forces, and Fields Q.1CQ
When an object that was neutral becomes charged. does the total charge of the universechange? Explain
Solution:
No. charging of a neutral object does not change the total charge of the universe If a neutral object is charged with another charged object the transfer of charge takes place between them
and then the net charge remains constant Hence, the total charge in the universe remains same

Chapter 19 Electric Charges, Forces, and Fields Q.1P
CE PredictlExplain An electrically neutral object is given a positive charge. (a) In principle. does the object’s mass increase, decrease, or stay the same as a result of being charged? (b) Choose the best explanation from among the following:
I To give the object a positive charge we must remove some of its electrons: this will reduce its mass
ll Since electric charges have mass, giving the object a positive charge will increase its mass
llI Charge is conserved, and therefore the mass of the object will remain the sama
Solution:
(a) In order to give the positive charge to any body we should remove the electrons from the body. So some of the mass of the object will Idecreased
(b) As the removing of electrons leads to acquiring the positive charge this leads to decrease in mass of the object Hence best explanation is ( I).

Chapter 19 Electric Charges, Forces, and Fields Q.2CQ
The fact that the electron has a negative charge and the proton has a positive charge is due to a convention established by Benjamin Fran kIin Would there have been any significant consequences if Franklin had chosen the opposite convention? Is there any advantage to naming charges plus and minus as opposed to. say. A and B?
Solution:
No.
When the current existing convention for the charge in the physics for electron & proton is interchange then there would be no effect at all. because the net charge in the universe will be same.
If the + & – charge are replaced by A & B. then there would be a problem for the defining of O (zero) charge because O(zero) charge means, the object has equal number of positive & negative charge

Chapter 19 Electric Charges, Forces, and Fields Q.2P
CE PredictlExplain An electrically neutral object is given a negative charge. (a) In principle. does the objects mass increase, decrease, or stay the same as a result of being charged? (b) Choose the best explanation from among the following:
I To give the object a negative charge we must give it more electrons, and this will increase its mass
II A positive charge increases an object’s mass: a negative charge decreases its mass
IlI Charge is conserved, and therefore the mass of the object will remain the same
Solution:
(a)
An electrically neutral object acquires negative charge by addition of electrons These electrons will increase the mass of the object Hence, the total mass of the object will ¡n crease
(b)
Addition of more number of electrons results in acquiring negative charge by the object Therefore, the best explanation is

Chapter 19 Electric Charges, Forces, and Fields Q.3CQ
Explain why a comb that has been rubbed through your hair attracts small bits of paper. even though the paper is uncharged
Solution:
The plastic comb gets charged when it rubbed through our hair Here, the plastic comb gets negative charge and the hair gets positive charge. Like charges repel each other and the unlike charges attract each other.
When this negatively charged comb is placed near bits of paper then the electrons in each molecule of the bits of papers shill away from the combS As a result, the positive charge in the bit of paper comes close to the comb and charge separation takes place inside the bits of paper Hence, the bit of paper is polarized. Due to the electrostatic force between the negatively charged comb and the positive side of the paper they attracted by the comb

Chapter 19 Electric Charges, Forces, and Fields Q.3P
CE (a) Based on the materials listed in Table 19—1, is the charge of the rubber balloon shown on page 655 more likely to be positive or negative? Explain, (b) If the charge on the balloon is reversed, will the stream, of water deflect toward or away from the balloon? Explain
Solution:
(a)
From the table 19-1. one can infer that a rubber on rubbing acquires negative charge and readily accepts more number of electrons In the table specified, four minus signs were given
for the material rubber which means it is negatively charged. So. a balloon made up of rubber will also possesses the same charge Thus, the rubber balloon on rubbing acquires negative charge
(b)
Water is a polar molecule that does not possess net charge. as one end of the water molecule possesses partial positive charge and the other end possesses partial negative charge Assume that the charge on the balloon is reversed, that is. the charge on the balloon is positive If this positively charged balloon is brought near the stream of water, then the negative ends in the water molecule tend to align towards the positively charged balloon and positive ends in the water molecule move towards the opposite end As a result, the stream of water deflects towards the balloon In this case, the attractive
force between the negatively charged particles of water and positively charged balloon is greater when compared to the repulsive force between the positively charged particles of water and balloon.
Thus, whatever be the charge of the balloon, the water deflects towards the balloon because of its polarity nature.

Chapter 19 Electric Charges, Forces, and Fields Q.4CQ
Small bits of paper are attracted to an electrically charged comb, but as soon as they touch the comb they are strongly repelled Explain this behavior
Solution:
Bits of paper which are initially uncharged are attracted towards the electrically charged comb by polarization effect, but when they come in contact with the comb, the polarization effect will disappear & paper receives the same charge which shows the repulsion between them

Chapter 19 Electric Charges, Forces, and Fields Q.4P
CE This problem refers to the information given in Table 19—1 (a) If rabbit fur is rubbed against glass. what is the sign of the charge each acquires? Explain. (b) Repeat part (a) for the case of
glass and rubber. (C) Comparing the situations described in parts (a) and (b). in which case is the magnitude of the tribo— electric charge greater? Explain
Solution:
(a) Since the rabbit fur losses more electrons while the glass gains the electrons, so, when rabbit fur is rubbed against glass, the fur attains positive charge and the glass rod acquires negative charge
(b) Since the rubber has a tendency to gain the electrons so. when it rubbed against glass. the glass acquires + ve charge and rubber — ve charge
(c) Rabbit fur and glass are adjacent in the table where as glass and rubbers are widely separated So we can conclude that the magnitude of triboelectric charge is greater in the glass — rubber case than in rabbit fur — glass case

Chapter 19 Electric Charges, Forces, and Fields Q.5CQ
A charged rod is brought near a suspended object. which is repelled by the rod Can we conclude that the suspended object is charged? Explain
Solution:
Since the charged rod gets a repulsive force when it brought near a suspended object this observation clearly Indicates the object had the same Kind of charge on R Because the charges having lice signs are repel to each other

Chapter 19 Electric Charges, Forces, and Fields Q.5P
Find the net charge of a system consisting of 4.9 × 107 electrons.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields5ps

Chapter 19 Electric Charges, Forces, and Fields Q.6CQ
A charged rod is brought near a suspended object. which is attracted to the rod Can we conclude that the suspended object is charged? ExpIain
Solution:
May or may not have the charge
Since the charged rod gets an attractive force when it brought near a suspended object. this observation clearly indicates the object had either the opposite kind of charge or electrically neutral
Reason for first case: the charges having unlike signs are attracted to each other Reason for second case: the charges attracts because of the polarization effect

Chapter 19 Electric Charges, Forces, and Fields Q.6P
Find the net charge of a system consisting of (a) 6.15 × 10 electrons and 7.44 × 106 protons or (b) 212 electrons and 165 protons.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields6ps

Chapter 19 Electric Charges, Forces, and Fields Q.7CQ
Describe some of the similarities and differences between Coulombs law and Newton’s law of gravity.
Solution:
The Coulomb force is proportional to the product of charges and the force is inversely proportional to the square of the distance between the two charges. Here, k is the coulomb’s constant. It is coulomb’s law.
The gravitational force is proportional to the product of two different masses and inversely proportional to the square of the distance between the two masses. Here. G is the gravitational constant. It is Newton’s law of gravitation.
Similarities between ‘s law of gravity and Coulomb’s law:
1. Both the laws depend on the product of certain special properties of the objects.
Z Both the gravitational force and the electrostatic force are inversely proportional to the square of the distance between the objects
Dissimilarities:
1. In Newton’s law of gravity, mass is relevant, and in Coulomb’s law, the charge of the objects is irrelevant
2. Gravitational force is only attractive, whereas electrostatic force can be attractive or repulsive

Chapter 19 Electric Charges, Forces, and Fields Q.7P
How much negative electric charge is contained in 2 moles of carbon?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields7ps

Chapter 19 Electric Charges, Forces, and Fields Q.8CQ
A point charge +Q is fixed at a height H above the ground. Directly below this charge is a small ball with a charge −q and a mass m. When the ball is at a height h above the ground, the net force (gravitational plus electrical) acting on it is zero. Is this a stable equilibrium for the object? Explain.
Solution:
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Chapter 19 Electric Charges, Forces, and Fields Q.8P
Find the total electric charge of 1.5 kg of (a) electrons and (b) protons.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields8ps

Chapter 19 Electric Charges, Forces, and Fields Q.9CQ
Four identical point charges are placed at the corners of a square. A 111th point charge placed at the center of the square experiences zero net force. Is this a stable equilibrium for the fifth charge? Explain.
Solution:
An object is said to be in mechanical equilibrium, if the object is in a state of rest or balance under the action of two or more external forces. This essentially means that there is no unbalanced force or net force and net torque acting on the object And hence there is no acceleration of the object Consider equal charges q is placed at the tour corners of a square and consider the charge p be placed at the center of square Then, the charge p experiences 2 pairs of torces along the 2 diagonals of the square and the torces by each pairs of charges are equal and opposite in direction Thus, they cancel each other and experience no net torca This implies that the point charge in the center is not accelerating Hence, the point charge in the center is said to be in stable equilibrium Therefore, the this is a case of stable equilibrium for the fifth charge as the effect by all the charges on the fifth charge cancel

Chapter 19 Electric Charges, Forces, and Fields Q.9P
A container holds a gas consisting of 1.85 moles of oxygen molecules. One in a million of these molecules has lost a single electron. What is the net charge of the gas?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields9ps

Chapter 19 Electric Charges, Forces, and Fields Q.10CQ
A proton moves in a region of constant electric field. Does it follow that the proton’s velocity is parallel to the electric field? Does it follow that the proton’s acceleration is parallel to the electric field? Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields10cqs

Chapter 19 Electric Charges, Forces, and Fields Q.10P
The Charge on Adhesive Tape When adhesive tape is pulled from a dispenser, the detached tape acquires a positive charge and the remaining tape in the dispenser acquires a negative charge. If the tape pulled from the dispenser has 0.14 μC of charge per centimeter, what length of tape must be pulled to transfer 1.8 × 1013 electrons to the remaining tape?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields10ps

Chapter 19 Electric Charges, Forces, and Fields Q.11CQ
Describe some of the differences between charging by induction and charging by contact
Solution:
(i) Charging by induction does not involve any physical contact between the charging object and the object being charged Where as the charging by contact involves physical contact to transfer charge form one object to the other
(ii) When an object is charged by induction, the object acquires a charge opposite to that of the charging object. Charging by contact gives the object to be charged the same charge as that of the charging object

Chapter 19 Electric Charges, Forces, and Fields Q.11P
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields11p
Solution:
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Chapter 19 Electric Charges, Forces, and Fields Q.12CQ
A system consists of two charges of equal magnitude and opposite sign separated by a distance d Since the total electric charge of this system is zero, can we conclude that the electric field produced by the system is also zero? Does your answer depend on the separation if? Explain
Solution:
Consider two equal and opposite charges separated by a finite distance d The net charge of the system will be zero However it cannot be concluded that the net electric field produced by this system will be zero. For example. consider a point which is closer to the positive charge. Now, the electric field at this point will be the vector sum of electric fields due to both positive and negative charge Since the point is closer to positive charge than the negative charge. magnitude of electric field due to positive charge will be greater than magnitude of electric field due to negative charge. Therefore. after the vector sum, the effective electric field will be positive
However. if the separation becomes negligible (like the case when distance of point under consideration is much more than the separation distance d). the net electric field can be said to be zero as both the charge will have equal and opposite electric fields at the point under consideration

Chapter 19 Electric Charges, Forces, and Fields Q.12P
A system of 1525 particles, each of wliich is either an electron or a proton, has a net charge of −5.456 × 10−17 C. (a) How many electrons are in this system?(b) What is the mass of this system?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields12ps

Chapter 19 Electric Charges, Forces, and Fields Q.13CQ
The force experienced by charge 1 at point A is different in direction and magnitude from the force experienced by charge 2 at point B. Can we conclude that the electric fields at points A and B are different? Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields13cqs

Chapter 19 Electric Charges, Forces, and Fields Q.13P
CE A charge +q and a charge −q are placed at opposite corners of a square. Will a third point charge experience a greater force if it is placed at one of the empty corners of the square, or at the center of the square? Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields13ps

Chapter 19 Electric Charges, Forces, and Fields Q.14CQ
Can an electric tÏeId exist in a vacuum? Explain.
Solution:
Electromagnetic fields exist in solids. liquids, gases. and the vacuum In the vacuum, the electromagnetic held propagates this has a component of electric & magnetic held
Yes. the electric field exists in a vacuum.
Best example is sun. The sun is a giant ball of nuclear reactions which creates not just light but a large range of electromagnetic fields. Atmosphere absorbs some of this energy and the spinning of the earth’s gigantic core creates a huge magnetic field around the earthS This field points in the direction of one of the magnetic poles. At the poles of the earth, the magnetic field passes through the earth. Therefore, the field is smaller and causes the aurora borealis, the interaction of the sun’s electromagnetic energy with our atmosphere.

Chapter 19 Electric Charges, Forces, and Fields Q.14P
CE Repeat the previous question, this time with charges +q and +q at opposite corners of a square.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields14ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields14ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields14ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields14ps3

Chapter 19 Electric Charges, Forces, and Fields Q.15CQ
Explain why electric field lines never cross
Solution:
Electric field lines are imaginary lines to show the presence of the tield A tangent drawn at any point on the field line gives the direction of electric field at that point.
Consider two lines intersect at a point then in such case two tangents can be drawn at that point which indicates two directions of the electric field Now if a unit charge is placed at that point then force acting on the unit charge due to field, is in two direction accordingly which is not possible. Since the electric force could not act in two directions at a position. Therefore. electric field lines can never cross to each other

Chapter 19 Electric Charges, Forces, and Fields Q.15P
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields15p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields15ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields15ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields15ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields15ps3
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields15ps4

Chapter 19 Electric Charges, Forces, and Fields Q.16CQ
Charge ql is inside a closed Gaussian surface: charge q2 is just outside the surface Does the electric flux through the surface depend on ql?Does it depend on q2?Explain
Solution:
According to the Gauss Law, the electric flux through a surface depends on the charge that is enclosed by the surface So the electric flux through the Gaussian surface depends on q1
Since the charge q2 is outside the Gaussian surface so. it has no effect on the total electric flux through the surface

Chapter 19 Electric Charges, Forces, and Fields Q.16P
CE Predict!Explain Suppose the charged sphere in Active Example 19—2 is made from a conductor, rather than an insulator (a) Do you expect the magnitude of the force between the
point charge and the conducting sphere to be greater than, less than, or equal to the force between the point charge and an insulating sphere? (b) Choose the best explanation from among the following:
I The conducting sphere will allow the charges to move, resulting in a greater force.
II The charge of the sphere is the same whether it is conducting or insulating, and therefore the force is the same.
III The charge on a conducting sphere will move as far away as possible from the point charge. This results in a reduced force.
Solution:
(a)
The charge inside the conducting sphere comes on its surface. Hence, the resultant charge value on sphere remains sama Therefore, the magnitude of electrostatic force between the conducting sphere and point charge remains same as between an insulating sphere and point charge
There is no change in the value of charge on conducting and insulating sphere. Hence, the magnitude of electrostatic force also remains unchanged
Hence, option is the best explanation

Chapter 19 Electric Charges, Forces, and Fields Q.17CQ
In the previous question, does the electric field at a point on the Gaussian surface depend on q1?Does it depend on q2. Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields17cqs

Chapter 19 Electric Charges, Forces, and Fields Q.17P
At what separation is the electrostatic force between a +11.2-μC point charge and a +29.1-μCpoint charge equal in magnitude to 1.57 N?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields17ps

Chapter 19 Electric Charges, Forces, and Fields Q.18CQ
Gauss’s law can tell us how much charge ¡s contained within a Gaussian surface Can it tell us where inside the surface it is located? Explain
Solution:
No.
The electric flux through a surface depends on the total charge enclosed by the surface but it is completely independent of location of the enclosed charges Hence Gauss law cannot tell us where inside the surface the charge is located

Chapter 19 Electric Charges, Forces, and Fields Q.18P
The attractive electrostatic force between the point charges +8.44 × 10−6 C and Q has a magnitude of 0.975 N when the separation between the charges is 1.31 m. Find the sign and magnitude of the charge Q.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields18ps

Chapter 19 Electric Charges, Forces, and Fields Q.19CQ
Explain why Gauss’s law is not very useful in calculating the electric field of a charged disk.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields19cqs

Chapter 19 Electric Charges, Forces, and Fields Q.19P
If the speed of the electron in Example 19−1 were 73× 105 m/s, what would be the corresponding orbital radius?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields19ps

Chapter 19 Electric Charges, Forces, and Fields Q.20P
IP Two point charges, the first with a charge of +3.13 × 10−6C and the second with a charge of −4.47 × 10−6 C, are separated by 25.5 cm. (a) Find the magnitude of the electrostatic force experienced by the positive charge, (b) Is the magnitude of the force experienced by the negative charge greater than, less than, or the same as that experienced by the positive charge? Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields20ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields20ps1

Chapter 19 Electric Charges, Forces, and Fields Q.21P
When two identical ions are separated by a distance of 6.2 × 10−10 m, the electrostatic force each exerts on the other is 5.4 × 10−9 N. How many electrons are missing from each ion?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields21ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields21ps1

Chapter 19 Electric Charges, Forces, and Fields Q.22P
A sphere of radius 4.22 cm and uniform surface charge density +12.1 μC/m2 exerts an electrostatic force of magnitude 46.9 × 10−3 N on a point charge of +1.95 μC. Find the separation between the point charge and the center of the sphere.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields22ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields22ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields22ps2

Chapter 19 Electric Charges, Forces, and Fields Q.23P
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields23p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields23ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields23ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields23ps2

Chapter 19 Electric Charges, Forces, and Fields Q.24P
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields24p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields24ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields24ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields24ps2

Chapter 19 Electric Charges, Forces, and Fields Q.25P
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields25p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields25ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields25ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields25ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields25ps3
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields25ps4
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields25ps5

Chapter 19 Electric Charges, Forces, and Fields Q.26P
IP Given that q = +12 μCand d = 19 cm, (a) find the direction and magnitude of the net electrostatic force exerted on the point charge q2 in Figure 19−29. (b) How would your answers to part (a) change if the distance d were tripled?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields26ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields26ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields26ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields26ps3
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields26ps4

Chapter 19 Electric Charges, Forces, and Fields Q.27P
Suppose the charge q2 in Figure 19−29 can be moved left or right along the line connecting the charges q1 and q3. Given that q = +12 μC, find the distance from q1 where q2 experiences a net electrostatic force of zero. (The charges q1 and q3 are separated by a fixed distance of 32 cm.)
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields27ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields27ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields27ps2

Chapter 19 Electric Charges, Forces, and Fields Q.28P
Find the orbital radius for which the kinetic energy of the electron in Example 19−1 is 1.51 eV. (Note: 1 eV = 1 electron volt = 1.6 × 10−19J.)
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields28ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields28ps1

Chapter 19 Electric Charges, Forces, and Fields Q.29P
Apoint charge q = −0.35 nC is fixed at the origin. Where must a proton be placed in order for the electric force acting on it to be exactly opposite to its weight? (Let the y axis be vertical and the x axis be horizontal.)
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields29ps

Chapter 19 Electric Charges, Forces, and Fields Q.30P
A point charge q = −0.35 nC is fixed at the origin. Where must an electron be placed in order for the electric force acting on it to be exactly opposite to its weight? (Let the y axis be vertical and the x axis be horizontal.)
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields30ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields30ps1

Chapter 19 Electric Charges, Forces, and Fields Q.31P
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields31p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields31ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields31ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields31ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields31ps3
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields31ps4

Chapter 19 Electric Charges, Forces, and Fields Q.32P
IP(a) Find the direction and magnitude of the net electrostatic force exerted on the point charge q3 in Figure 19−32. Let q = +2.4 μC and d = 27 cm. (b) How would your answers to part (a) change if the distance d were doubled?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields32ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields32ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields32ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields32ps3
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields32ps4
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields32ps5
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields32ps6

Chapter 19 Electric Charges, Forces, and Fields Q.33P
IP Two point charges lie on the x axis. A charge of +9.9 μC is at the origin, and a charge of −5.1 μC is at x = 10.0 cm. (a) At what position x would a third charge q3 be in equilibrium? (b) Does your answer to part (a) depend on whether q3 is positive or negative? Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields33ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields33ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields33ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields33ps3

Chapter 19 Electric Charges, Forces, and Fields Q.34P
A system consists of two positive point charges, q1 and q2> q1. The total charge of the system is +62.0 μC, and each charge experiences an electrostatic force of magnitude 85.0 N when the separation between them is 0.270 m. Find q1 and q2
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields34ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields34ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields34ps2

Chapter 19 Electric Charges, Forces, and Fields Q.35P
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields35p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields35ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields35ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields35ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields35ps3
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields35ps4
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields35ps5

Chapter 19 Electric Charges, Forces, and Fields Q.36P
Referring to Problem 35, suppose that the magnitude of the net electrostatic force exerted on the point charge q2 in Figure 19−33 is 0.65 N. (a) Find the distance d. (b) What is the direction of the net force exerted on q2?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields36ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields36ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields36ps2

Chapter 19 Electric Charges, Forces, and Fields Q.37P
IP (a) If the nucleus in Example 19−1 had a charge of +2e (as would be the case for a nucleus of helium), would the speed of the electron be greater than, less than, or the same as that found in the Example? Explain. (Assume the radius of the electron’s orbit is the same.) (b) Find the speed of the electron for a nucleus of charge +2e.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields37ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields37ps1

Chapter 19 Electric Charges, Forces, and Fields Q.38P
Four point charges are located at the corners of a square with sides of length a. Two of the charges are +q, and two are −q, Find the magnitude and direction of the net electric force exerted on a charge +Q, located at the center of the square, for each of the following two arrangements of charge: (a) The charges alternate in sign (+q, −q, +q, −q) as you go around the square; (b) the two positive charges are on the top corners, and the two negative charges are on the bottom corners.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields38ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields38ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields38ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields38ps3
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields38ps4
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields38ps5
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields38ps6
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields38ps7

Chapter 19 Electric Charges, Forces, and Fields Q.39P
IP Two identical point charges in free space are connected by a string 7.6 cm long. The tension in the string is 0.21 N. (a) Find the magnitude of the charge on each of the point charges, (b) Using the information given in the problem statement, is it possible to determine the sign of the charges? Explain, (c) Find the tension in the string if +1.0 μC of charge is transferred from one point charge to the other. Compare with your result from part (a).
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields39ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields39ps1

Chapter 19 Electric Charges, Forces, and Fields Q.40P
Two spheres with uniform surface charge density, one with a radius of 7.2 cm and the other with a radius of 4.7 cm, are separated by a center−to−center distance of 33 cm. The spheres have a combined charge of +55 μCand repel one another with a force of 0.75 N. What is the surface charge density on each sphere?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields40ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields40ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields40ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields40ps3
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields40ps4
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields40ps5

Chapter 19 Electric Charges, Forces, and Fields Q.41P
Point charges, q1 and q2, are placed on the x axis, with q1 at x = 0 and q2 at x = d. Athird point charge, +Q, is placed at x = 3d/4. if the net electrostatic force experienced by the charge +Q is zero, how are q1 and q2 related?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields41ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields41ps1

Chapter 19 Electric Charges, Forces, and Fields Q.42P
CE Two electric charges are separated by a finite distance. Somewhere between the charges, on the line connecting them, the net electric field they produce is zero, (a) Do the charges have the same or opposite signs? Explain, (b) If the point of zero field is closer to charge 1, is the magnitude of charge 1 greater than or less than the magnitude of charge 2? Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields42ps

Chapter 19 Electric Charges, Forces, and Fields Q.43P
What is the magnitude of the el ectric field produced by a charge of magnitude 7.50 μCat a distance of (a) 1.00 m and (b) 2.00 m?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields43ps

Chapter 19 Electric Charges, Forces, and Fields Q.44P
A +5.0 μC charge experiences a 0.44−N force in the positive y direction. If this charge is replaced with a − 2.7μCcharge, what force will it experience?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields44ps

Chapter 19 Electric Charges, Forces, and Fields Q.45P
Two point charges he on the x axis. A charge of +6.2 μC is at the origin, and a charge of −9.5 μCis at x = 10.0 cm. What is the net electric field at (a) x = −4.0 cm and at (b) x = +4.0 cm?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields45ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields45ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields45ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields45ps3

Chapter 19 Electric Charges, Forces, and Fields Q.46P
CE The electric field on the dashed Une in Figure 19−28 vanishes at infinity, but also at two different points a finite distance from the charges. Identify the regions in which you can find E = 0 at a finite distance from the charges: region 1, to the left of point A; region 2, between points A and B; region 3, between points B and C; region 4, to the right of point C.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields46ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields46ps1

Chapter 19 Electric Charges, Forces, and Fields Q.47P
An object with a charge of −3.6 μC and a mass of 0.012 kg experiences an upward electric force, due to a uniform electric field, equal in magnitude to its weight, (a) Find the direction and magnitude of the electric field, (b) If the electric charge on the object is doubled while its mass remains the same, find the direction and magnitude of its acceleration.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields47ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields47ps1

Chapter 19 Electric Charges, Forces, and Fields Q.48P
IP Figure 19−33 shows a system consisting of three charges, q1 = +5.00 μC, q2 = +5.00 μC, and q3 = −5.00 μC, at the vertices of an equilateral triangle of side d = 2.95 cm. (a) Find the magnitude of the electric field at a point halfway between the charges q1 and q2. (b) Is the magnitude of the electric field halfway between the charges q2 and q3 greater than, less than, or the same as the electric field found in part (a)? Explain, (c) Find the magnitude of the electric field at the point specified in part (b).
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields48ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields48ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields48ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields48ps3
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields48ps4

Chapter 19 Electric Charges, Forces, and Fields Q.49P
Two point charges of equal magnitude are 7.5 cm apart. At the midpoint of the line connecting them, their combined electric field has a magnitude of 45 N/C. Find the magnitude of the charges.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields49ps

Chapter 19 Electric Charges, Forces, and Fields Q.50P
IP A point charge q1 = +4.7 μCis placed at each corner of an equilateral triangle with sides 0.21 m in length, (a) What is the magnitude of the electric field at the midpoint of any of the three sides of the triangle? (b) Is the magnitude of the electric field at the center of the triangle greater than, less than, or the same as the magnitude at the midpoint of a side? Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields50ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields50ps1

Chapter 19 Electric Charges, Forces, and Fields Q.51P
IP Four point charges, each of magnitude q, are located at the corners of a square wi th sides of length a. Two of the charges are +q, and two aie −q. The charges are arranged in one of the following two ways: (1) The charges alternate in sign (+q, −q, +q, −q) as you go around the square; (2) the top two comers of the square have positive charges (+q, +q), and the bottom two corners have negative charges (−q, −q). (a) In which case will the electric field at the center of the square have the greatest magnitude? Explain, (b) Calculate the electric field at the center of the square for each of these two cases.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields51ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields51ps1.
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields51ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields51ps3

Chapter 19 Electric Charges, Forces, and Fields Q.52P
The electric field at the point x = 5.00 cm and y = 0 points in the positive x direction with a magnitude of 10.0 N/C. At the point x = 10.0 cm and y = 0 the electric field points in the positive x direction with a magnitude of 15.0 N/C. Assuming this electric field is produced by a single point charge, find (a) its location and (b) the sign and magnitude of its charge.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields52ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields52ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields52ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields52ps3

Chapter 19 Electric Charges, Forces, and Fields Q.53P
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields53p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields53ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields53ps1

Chapter 19 Electric Charges, Forces, and Fields Q.54P
Make a qualitative sketch of the electric field lines produced by two equal positive charges, +q, separated by a distance d.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields54ps

Chapter 19 Electric Charges, Forces, and Fields Q.55P
Make a qualitative sketch of the electric field lines produced by two charges, +q and −q, separated by a distance d.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields55ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields55ps1

Chapter 19 Electric Charges, Forces, and Fields Q.56P
Referring to Figure 19-34, suppose q2 is not known. Instead, it is given that q1 + q2 = −2.5 μC. Find q1 q2, and q3.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields56ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields56ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields56ps2

Chapter 19 Electric Charges, Forces, and Fields Q.57P
Make a qualitative sketch of the electric field lines produced by the four charges, +q, −q, +q, and −q, arranged clockwise on the four corners of a square with sides of length d.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields57ps

Chapter 19 Electric Charges, Forces, and Fields Q.58P
Sketch the electric field lines for the system of charges shown in Figure 19-29.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields58ps

Chapter 19 Electric Charges, Forces, and Fields Q.59P
Sketch the electric field lines for the system of charges described in Problem 35.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields59ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields59ps1

Chapter 19 Electric Charges, Forces, and Fields Q.60P
Suppose the magnitude of the electric field between the plates in Example 19-6 is changed, and a new object with a charge of −2.05 μC is attached to the string. If the tension in the string is 0.450 N, and the angle it makes with the vertical is 16°, what are (a) the mass of the object and (b) the magnitude of the electric field?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields60ps

Chapter 19 Electric Charges, Forces, and Fields Q.61P
CE Predict/Explain Gaussian surface 1 has twice the area of Gaussian surface 2. Both surfaces enclose the same charge Q. (a) Ts the electric flux through surface 1 greater than, less than, or the same as the electric flux through surface 2? (b) Choose the best explanation from among the following:
I. Gaussian surface 2 is closer to the charge, since it has the smaller area. It follows that it has the greater electric flux.
II. The two surfaces enclose the same charge, and hence they have the same electric flux.
III. Electric flux is proportional to area. As a result, Gaussian surface 1 has the greater electric flux.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields61ps

Chapter 19 Electric Charges, Forces, and Fields Q.62P
CESuppose the conducting shell in Figure 19-25−which has a point charge +Q at its center−has a nonzero net charge. How much charge is on the inner and outer surface of the shell when the net charge of the shell is (a) −2Q, (b) −Q, and (c) +Q?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields62ps

Chapter 19 Electric Charges, Forces, and Fields Q.63P
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields63p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields63pss
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields63ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields63ps2

Chapter 19 Electric Charges, Forces, and Fields Q.64P
A uniform electric field of magnitude 25,000 N/C makes an angle of 37° with a plane surface of area 0.0153 m2, What is the electric flux through this surface?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields64ps

Chapter 19 Electric Charges, Forces, and Fields Q.65P
A surface encloses the charges q1 = 3.2 μC, q2 − 6.9 μC, and q3 = −4.1 μC. Find the electric flux through this surface.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields65ps

Chapter 19 Electric Charges, Forces, and Fields Q.66P
IPA uniform electric field of magnitude 6.00 × 103 N/C points upward. An empty, closed shoe box has a top and bottom that are 35.0 cm by 25.0 cm, vertical ends that are 25.0 cm by 20.0 cm, and vertical sides tha t are 20.0 cm by 35.0 cm. (a) Which side of the box has the greatest positive electric flux? Which side has the greatest negative electric flux? Which sides have zero electric flux? (b) Calculate the electric flux through each of the six sides of the box.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields66ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields66ps1

Chapter 19 Electric Charges, Forces, and Fields Q.67P
BIO Nerve Cells Nerve cells are long, thin cylinders along which electrical disturbances (nerve impulses) travel. The cell membrane of a typical nerve cell consists of an inner and an outer wall separated by a distance of 0.10 μ m. The electric field within the cell membrane is 7.0 × 105 N/C. Approximating the cell membrane as a parallel-plate capacitor, determine the magnitude of the charge density on the inner and outer cell walls.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields67ps

Chapter 19 Electric Charges, Forces, and Fields Q.68P
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields68p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields68ps

Chapter 19 Electric Charges, Forces, and Fields Q.69P
Consider a spherical Gaussian surface and three charges: q1 = 1.61 μC,q2 = −2.62 μC, and q3 = 3.91 μC. Find the electric flux through the Gaussian surface if it completely encloses (a) only charges q1 and q2, (b) only charges q2 and q3, and (c) all three charges, (d) Suppose a fourth charge, Q, is added to the situation described in part (c). Find the sign and magnitude of Q required to give zero electric flux through the surface.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields69ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields69ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields69ps2

Chapter 19 Electric Charges, Forces, and Fields Q.70P
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields70p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields70ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields70ps1

Chapter 19 Electric Charges, Forces, and Fields Q.71GP
CE Predict/Explain An electron and a proton are released from rest in space, far from any other objects. The particles move toward each other, due to their mutual electrical attraction. (a) When they meet, is the kinetic energy of the electron greater than, less than, or equal to the kinetic energy of the proton? (b) Choose the best explanation from among the following:
I. The proton has the greater mass. Since kinetic energy is proportional to mass, it follows that the proton will have the greater kinetic energy.
II. The two particles experience the same force, but the light electron moves farther than the massive proton. Therefore, the work done on the electron, and hence its kinetic energy, is greater.
III. The same force acts on the two particles. Therefore, they will have the same kinetic energy and energy will be conserved.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields71ps

Chapter 19 Electric Charges, Forces, and Fields Q.72GP
CE Predict/Explain In Conceptual Checkpoint 19−3, suppose the charge to be placed at cither point A or point B is +q rather than − q, (a) Is the magnitude of the net force experienced by the movable charge at point A greater than, less than, or equal to the magnitude of the net force at point B? (b) Choose the best explanation from among the following:
I. Point B is farther from the two fixed charges. As a result, the net force at point B is less than at point A. II. The net force at point A cancels, just as it does in Conceptual Checkpoint 19−3. Therefore, the nonzero net force at point B is greater in magnitude than the zero net force at point A.
III. The net force is greater in magnitude at point A because at that location the movable charge experiences a net repulsion from each of the fixed charges.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields72ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields72ps1

Chapter 19 Electric Charges, Forces, and Fields Q.73GP
CE An electron (charge = −e) orbits a helium nucleus (charge = +2e). Is the magnitude of the force exerted on the he− Hum nucleus by the electron greater than, less than, or the same as the magnitude of the force exerted on the electron by the helium nucleus? Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields73ps

Chapter 19 Electric Charges, Forces, and Fields Q.74GP
CE In the operating room, technicians and doctors must take care not to create an electric spark, since the presence of the oxygen gas used during an operation increases the risk of a deadly fire. Should the operating−room personnel wear shoes that are conducting or non-conducting? Explain.
Solution:
The operating room personnel should wear shoes that are conducting so that any charge they transform while walking, can flow into the ground.

Chapter 19 Electric Charges, Forces, and Fields Q.75GP
CE Under normal conditions, the electric field at the surface of the Earth points downward, into the ground. What is the sign of the electric charge on the ground?
Solution:
We know that electric field lines point in the direction of negative charges.So the charge on Earth must be negative

Chapter 19 Electric Charges, Forces, and Fields Q.76GP
CE Two identical spheres are made of conducting material. Initially, sphere 1 has a net charge of +35Q and sphere 2 has a net charge of −26Q. If the spheres are now brought into contact, what is the final charge on sphere 1? Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields76ps

Chapter 19 Electric Charges, Forces, and Fields Q.77GP
CE A Gaussian surface for the charges shown in Figure 19−35 has an electric flux equal to +3q/ε0. Which charges arc contained within this Gaussian surface?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields77ps

Chapter 19 Electric Charges, Forces, and Fields Q.78GP
A proton is released from rest in a uniform electric field of magnitude 1.08 × 105 N/C. Find the speed of the proton after it has traveled (a) 1.00 cm and (b) 10.0 cm.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields78ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields78ps1

Chapter 19 Electric Charges, Forces, and Fields Q.79GP
BIO Ventricular Fibrillation If a charge of 0.30 C passes through a person’s chest in 1.0 s, the heart can go into ventricular fibrillation−a nonrhythmic “fluttering” of the ventricles that results in little or no blood being pumped to the body. If this rate of charge transfer persists for 4.5 s, how many electrons pass through the chest?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields79ps

Chapter 19 Electric Charges, Forces, and Fields Q.80GP
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields80p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields80ps

Chapter 19 Electric Charges, Forces, and Fields Q.81GP
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields81p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields81ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields81ps1

Chapter 19 Electric Charges, Forces, and Fields Q.82GP
Find (a) the direction and (b) the magnitude of the net electric field at the center of the equilateral triangle in Figure 19−31. Give your answers in terms of the angle θ, as defined in Figure 19−31, and E, the magnitude of the electric field produced by any oneof the charges at the center of the triangle.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields82ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields82ps1

Chapter 19 Electric Charges, Forces, and Fields Q.83GP
At the moment, the number of electrons in your body is essentially the same as the number of protons, giving you a net charge of zero. Suppose, however, that this balance of charges is off by 1% in both you and your friend, who is 1 meter away. Estimate the magnitude of the electrostatic force each of you experiences, and compare it with your weight.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields83ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields83ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields83ps2

Chapter 19 Electric Charges, Forces, and Fields Q.84GP
A small object of mass 0.0150 kg and charge 3.1 μChangs from the ceiling by a thread. A second small object, with a charge of 4.2 μC, is placed 1.2 m vertically below the first charge. Find (a) the electric field at the position of the upper charge due to the lower charge and (b) the tension in the thread.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields84ps

Chapter 19 Electric Charges, Forces, and Fields Q.85GP
IP Consider a system of three point charges on the x axis. Charge 1 is at x = 0, charge 2 is at x = 0.20 m, and charge 3 is at x = 0.40 m. In addition, the charges have the following values: q1 = −19 μC, q2 = q3 = +19 μC(a)The electric field vanishes at some point on the x axis between x = 0.20 m and x = 0.40 m. Ts the point of zero field (i) at x = 0.30 m, (ii) to the left of x = 0.30 m, or (iii) to the right of x = 0.30 m? Explain, (b) find the point where E = 0 between x = 0.20 m and x = 0.40 m.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields85ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields85ps1

Chapter 19 Electric Charges, Forces, and Fields Q.86GP
IP Consider the system of three point charges described in the previous problem, (a) The electric field vanishes at two different points on the.x axis. One point is between x = 0.20 m and x = 0.40 m. Is the second point located to the left of charge 1 or to the right of charge 3? Explain, (b) Find the value of x at the second point where E = 0.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields86ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields86ps1

Chapter 19 Electric Charges, Forces, and Fields Q.87GP
The electric field at a radial distance of 47.7 cm from the thin charged wire shown in Figure 19−36 has a magnitude of 35,400 N/C. (a) Using the result given in Problem 70, what is the magnitude of. the charge per length on this wire? (b) At what distance from the wire is the magnitude of the electric field equal to ?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields87ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields87ps1

Chapter 19 Electric Charges, Forces, and Fields Q.88GP
A system consisting entirely of electrons and protons has a net charge of 1.84 × 10−15 C and a net mass of 4.56 × 10−23 kg. How many (a) electrons and (b) protons are in this system?
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields88ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields88ps1

Chapter 19 Electric Charges, Forces, and Fields Q.89GP
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields89p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields89ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields89ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields89ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields89ps3
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields89ps4
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields89ps5
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields89ps6
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields89ps7

Chapter 19 Electric Charges, Forces, and Fields Q.90GP
IP Consider the system of three charges described in the previous problem and shown in Figure 19−38. (a) Do you expect the net force acting on charge 1 to have a magnitude greater than, less than, or the same as the magnitude of the net force acting on charge 2? Explain, (b) Find the magnitude of the net force acting on charge 1. (c) Find the magnitude of the net force acting on charge 2.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields90ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields90ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields90ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields90ps3

Chapter 19 Electric Charges, Forces, and Fields Q.91GP
IP BIO Cell Membranes The cell membrane in a nerve cell has a thictcness of 0.12μ m. (a) Approximating the cell membrane as a parallel−plate capacitor with a surface charge density of 5.9 × 10−6 C/m2, find the electric field within the membrane, (b) If the thickness of the membrane were doubled, would your answer to part (a) increase, decrease, or stay the same? Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields91ps

Chapter 19 Electric Charges, Forces, and Fields Q.92GP
A square with sides of length L has a point charge at each of its four corners. Two corners that are diagonally opposite have charges equal to +2.25 μC; the other two diagonal comers have charges Q. Find the magnitude and sign of the charges Q such that each of the +2.25μC charges experiences zero net force.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields92ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields92ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields92ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields92ps3

Chapter 19 Electric Charges, Forces, and Fields Q.93GP
IP Suppose a charge +Q is placed on the Earth, and another charge +Q is placed on the Moon. (a) Find the value of Q needed to “balance” the gravitational attraction between the Earth and the Moon. (b) How would your answer to part (a) change if the distance between the Earth and the Moon were doubled? Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields93ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields93ps1

Chapter 19 Electric Charges, Forces, and Fields Q.94GP
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields94p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields94ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields94ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields94ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields94ps3

Chapter 19 Electric Charges, Forces, and Fields Q.95GP
A small sphere with a charge of +2.44 μCis attached to a relaxed horizontal spring whose force constant is 89.2 N/m. The spring extends along the x axis, and the sphere rests on a frictionless surface with its center at the origin. A point charge Q = −8.55 μCis now moved slowly from infinity to a point x = d > 0 on the x axis. This causes the small sphere to move to the position x = 0.124 m. Find d.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields95ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields95ps1

Chapter 19 Electric Charges, Forces, and Fields Q.96GP
Twelve identical point charges q are equally spaced around the circumference of a circle of radius R. The circle is centered al the origin. One of the twelve charges, which happens to be on the positive x axis, is now moved to the center of the circle. Find (a) the direction and (b) the magnitude of the net electric force exerted on this charge.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields96ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields96ps1

Chapter 19 Electric Charges, Forces, and Fields Q.97GP
BIO Nerve Impulses When a nerve impulse propagates along a nerve cell, the electric field within the cell membrane changes from 7.0 × 105 N/C inone direction to 3.0 × 105 N/C in the other direction. Approximating the cell membrane as a parallel−plate capacitor, find the magnitude of the change in charge density on the walls of the cell membrane.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields97ps

Chapter 19 Electric Charges, Forces, and Fields Q.98GP
IP The Electric Field of the Earth The Earth produces an approximately uniform electric field at ground level. This electric field has a magnitude of 110 N/C and points radially inward, toward the center of the Earth. (a) Find the surface charge density (sign and magnitude) on the surface of the Earth. (b) Given that the radius of the Earth is 6.38 × 106 m, find the total electric charge on the Earth. (c) If the Moon had the same amount of electric charge distributed uniformly over its surface, would its electric field at the surface be greater than, less than, or equal to 110 N/C? Explain.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields98ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields98ps1

Chapter 19 Electric Charges, Forces, and Fields Q.99GP
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields99p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields99ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields99ps1

Chapter 19 Electric Charges, Forces, and Fields Q.100GP
Four identical charges, +Q, occupy the corners of a square with sides of length a. A fifth charge, q, can be placed at any desired location. Find the location of the fifth charge, and the value of q, such that the net electric force acting on each of the original four charges, +Q, is zero.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields100ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields100ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields100ps2

Chapter 19 Electric Charges, Forces, and Fields Q.101GP
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields101p
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields101pss
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields101pss1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields101pss2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields101pss3

Chapter 19 Electric Charges, Forces, and Fields Q.102GP
Two identical conducting spheres are separated by a fixed center−to−center distance of 45 cm and have different charges. Initially, the spheres attract each other with a force of 0.095 N. The spheres are now connected by a thin conducting wire. After the wire is removed, the spheres are positively charged and repel one another with a force of 0.032 N. Find (a) the final and (b) the initial charges on the spheres.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields102ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields102ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields102ps2

Chapter 19 Electric Charges, Forces, and Fields Q.103PP
How many electrons must be transferredaway from a bee to produce a charge of +93.0 pC?
A. 1.72 × 10−9
B. 5.81 × 108
C. 1.02 × 1020
D. 1.49 × 1029
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields103ps

Chapter 19 Electric Charges, Forces, and Fields Q.104PP
Suppose two bees, each with a charge of 93.0 pC, are separated by a distance of 1.20 cm. Treatingthe bees as point charges, what is the magnitude of the electrostatic force experienced by the bees? (In comparison, the weight of a 0.140g bee is 1.37 × 10−3 N.)
A. 6.01 × 10−17 N
B. 6.48 × 10−9 N
C. 5.40 × 10−7N
D. 5.81 × 10−3N
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields104ps

Chapter 19 Electric Charges, Forces, and Fields Q.105PP
The force required to detach a grain of pollen from an avocado stigma is approximately 4.0 × 10−5 N. What is the maximum distance at which the electrostatic force between a bee and a grain of pollen is sufficient to detach the pollen? Treat the bee and pollen as point charges, and assume the pollen has a charge opposite in sign and equal in magnitude to the bee.
A. 4.7 × 10−7 m
B. 1.9 mm
C. 4.4 cm
D. 220 m
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields105ps

Chapter 19 Electric Charges, Forces, and Fields Q.106PP
The Earth produces an electric field of magnitude 110 N/C. What force does this electric field exert on a bee carrying a charge of 93.0 pC? (Again, for comparison, the weight of a bee is approximately 1.37 × 10−3 N.)
A. 1.76 × 10−17N
B. S.45 × 10−13 N
C. 1.02 × 10−8 N
D. 1.13 × 10−6 N
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields106ps

Chapter 19 Electric Charges, Forces, and Fields Q.107IP
IP Referring to Example 19−5 Suppose q1 = +2.90μC is no longer at the origin, but is now on the y axis between y = 0 and y = 0.500 m. Thecharge q2 = +2.90 μCis at x = 0 and y = 0.500 m, and point 3 is at x = y = 0.500 m. (a) Is the magnitude of the net electric field at point 3, which we call Enct, greater than, less than, or equal to its previous value? Explain. (b) Is the angle θ that Enct makes with the x axis greater than, less than, or equal to its previous value? Explain. Find the new values of (c) Enct and (d) θ if q1 is at y = 0.250 m.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields107ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields107ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields107ps2
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields107ps3

Chapter 19 Electric Charges, Forces, and Fields Q.108IP
IP Referring to Example 19−5 In this system, the charge q1 is at the origin, the charge q2 is at x = 0 and y = 0.500 m, and point 3 is at x = y = 0.500 m. Suppose that q1 = + 2.90 μC, but that q2 isincreased to a value greater than +2.90 μC. As a result, do (a) Enct and (b) θ increase, decrease, or stay the same? Explain. If Enct = 1.66 × 105 N/C, find (c) q2 and (d) θ.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields108ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields108ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields108ps2

Chapter 19 Electric Charges, Forces, and Fields Q.109IP
IP Referring to Example 19−6 The magnitude of the charge is changed until the angle the thread makes with the vertical is θ = 15.0°. The electric field is 1.46 × 104 N/C and the mass of the object is 0.0250 kg. (a) Is the new magnitude of q greater than or less than its previous value? Explain. (b) Find the new value of q.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields109ps
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields109ps1
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields109ps2

Chapter 19 Electric Charges, Forces, and Fields Q.110IP
Referring to Example 19−6 Suppose the magnitude of the electric field is adjusted to give a tension of 0.253 N in the thread. This will also change the angle the thread makes with the vertical. (a) Find the new value of E. (b) Find the new angle between the thread and the vertical.
Solution:
mastering-physics-solutions-chapter-19-electric-charges-forces-and-fields110ps

Mastering Physics Solutions Chapter 18 The Laws of Thermodynamics

Mastering Physics Solutions Chapter 18 The Laws of Thermodynamics

Mastering Physics Solutions

Chapter 18 The Laws of Thermodynamics Q.1CQ
If an engine has a reverse gear. does this make it reversible?
Solution:
If the engine is in reverse gear, is not reversible when it has friction.

Chapter 18 The Laws of Thermodynamics Q.1P
CE Give the change in internal energy of a system if (a) W = 50 J, Q = 50 J; (b) W = −50 J, Q = −50 J; or (c) W = 50 J, Q = −50 J.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics1ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics1ps1

Chapter 18 The Laws of Thermodynamics Q.2CQ
The temperature of a substance is held fixed. Is it possible for heat to flow (a) into or (b) out of this system? For each case, give an explanation if your answer is no. If your answer is yes, give a specific example.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics2cqs

Chapter 18 The Laws of Thermodynamics Q.2P
CE A gas expands, doing 100 J of work. How much heat must be added to this system for its internal energy to increase by 200 J?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics2ps

Chapter 18 The Laws of Thermodynamics Q.3CQ
A substance is thermally insulated, so that no heat can flow between it and its surroundings. Is it possible for the temperature of this substance to (a) increase or (b) decrease? For each case, give an explanation if your answer is no. If your answer is yes, give a specific example.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics3cqs

Chapter 18 The Laws of Thermodynamics Q.3P
A swimmer does 6.7 × 105 J of work and gives off 4.1 × 105 J of heat duringa workout. Determine ∆U, W,and Q for the swimmer.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics3ps

Chapter 18 The Laws of Thermodynamics Q.4CQ
Heat is added to a substance. Is it safe to conclude that the temperature of the substance will rise? Give an explanation if your answer is no. If your answer is yes, give a specific example.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics4cqs

Chapter 18 The Laws of Thermodynamics Q.4P
When 1210 Jof heat are added to one mole of an ideal monatomic gas, its temperature increases from 272 K to 276 K. Find the work done by the gas during this process.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics4ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics4ps1

Chapter 18 The Laws of Thermodynamics Q.5CQ
The temperature of a substance is increased. Is it safe to conclude that heat was added to the substance? Give an explanation if your answer is no. If your answer is yes, give a specific example.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics5cqs

Chapter 18 The Laws of Thermodynamics Q.5P
Three different processes act on a system. (a) In process A, 42 J of work are done on the system and 77 J of heat are added to the system. Find the change in the system’s internal energy. (b) In process B, the system does 42 J of work and 77 Jof heat are added to the system. What is the change in the system’s internal energy? (c) In process C, the system’s internal energy decreases by 120 J while the system performs 120 J of work on its surroundings. How much heat was added to the system?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics5ps

Chapter 18 The Laws of Thermodynamics Q.6CQ
Are there thermodynamic processes in which all the heat absorbed by an ideal gas goes completely into mechanical work? If so, give an example.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics6cqs

Chapter 18 The Laws of Thermodynamics Q.6P
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics6p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics6ps

Chapter 18 The Laws of Thermodynamics Q.7CQ
Is it possible to convert a given amount of mechanical work completely into heat? Explain.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics7cqs

Chapter 18 The Laws of Thermodynamics Q.7P
· · A basketball player does 2.43 × 105 J of work during her time in the game, and evaporates 0.110 kg of water. Assuming a latent heat of 2.26 × 106 J/kg for the perspiration (the same as for water), determine (a) the change in the player’s internal energy and (b) the number of nutritional calories the player has converted to work and heat.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics7ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics7ps1

Chapter 18 The Laws of Thermodynamics Q.8CQ
An ideal gas Is held in an insulated container at the temperature T. All the gas is initially in one-half of the container, with a partition separating the gas from the other half of the container, which is a vacuum. If the partition ruptures, and the gas expands to fill the entire container, what is its final temperature?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics8cqs

Chapter 18 The Laws of Thermodynamics Q.8P
IP One mole of an ideal monatomic gas is initially at a temperature of 263 K. (a) Find the final temperature of the gas if 3280 J of heat are added to it and it does 722 J of work. (b) Suppose the amount of gas is doubled to two moles. Does the final temperature found in part (a) increase, decrease, or stay the same? Explain.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics8ps

Chapter 18 The Laws of Thermodynamics Q.9CQ
Which of the following processes are approximately reversible? (a) Lighting a match. (b) Pushing a block up a frictionless inclined plane. (c) Frying an egg. (d) Swimming from one end of a pool to the other. (e) Stretching a spring by a small amount. (f) Writing a report for class.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics9cqs

Chapter 18 The Laws of Thermodynamics Q.9P
· · IP Energy from Gasoline Burning a gallon of gasoline releases 1.19 × 108 J of internal energy. If a certain car requires 5.20 × 1.05 J of work to drive one mile, (a) how much heat is given off to the atmosphere each mile, assuming the car gets 25.0 miles to the gallon? (b) If the miles per gallon of the car is increased, does the amount of heat released to the atmosphere increase, decrease, or stay the same? Explain.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics9ps

Chapter 18 The Laws of Thermodynamics Q.10CQ
Which law of thermodynamics would be violated if heat were to spontaneously flow between two objects of equal temperature?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics10cqs

Chapter 18 The Laws of Thermodynamics Q.10P
A cylinder contains 4.0 moles of a monatomic gas at an initial temperature of 27 °C. The gas is compressed by doing 560 J of work on it, and its temperature increases by 130 °C. How much heat flows into or out of the gas?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics10ps

Chapter 18 The Laws of Thermodynamics Q.11CQ
Heat engines always give off a certain amount of heat to a low-temperature reservoir. Would it be possible to use this “waste” heat as the heat input to a second heat engine, and then use the “waste” heat of the second engine to run a third engine, and so on?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics11cqs

Chapter 18 The Laws of Thermodynamics Q.11P
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics11p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics11ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics11ps1

Chapter 18 The Laws of Thermodynamics Q.12CQ
A heat pump uses 100 J of energy as it operates for a given time. Is it possible for the heat pump to deliver more than 100 J of heat to the inside of the house in this same time? Explain.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics12cqs

Chapter 18 The Laws of Thermodynamics Q.12P
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics12p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics12ps

Chapter 18 The Laws of Thermodynamics Q.13CQ
If you clean up a messy room, putting things back where they belong, you decrease the room’s entropy. Does this violate the second law of thermodynamics? Explain.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics13cqs

Chapter 18 The Laws of Thermodynamics Q.13P
A system consisting of an ideal gas at the constant pressure of 110 kPa gains 920 J of heat. Find the change in volume of the system if the internal energy of the gas increases by (a) 920 J or (b) 360 J.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics13ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics13ps1

Chapter 18 The Laws of Thermodynamics Q.14CQ
Which law of thermodynamics is most pertinent to the statement that “all the king’s horses and all the king’s men couldn’t put Humpty Dumpty back together again?”
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics14cqs

Chapter 18 The Laws of Thermodynamics Q.14P
An ideal gas is compressed at constant pressure to one-half its initial volume. If the pressure of the gas is 120 kPa, and 790 J of work is done on it, find the initial volume of the gas.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics14ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics14ps1

Chapter 18 The Laws of Thermodynamics Q.15CQ
Which has more entropy: (a) popcorn kernels, or the resulting popcorn; (b) two eggs in a carton, or an omelet made from the eggs; (c) a pile of bricks, or the resulting house; (d) a piece of paper, or the piece of paper after it has been burned?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics15cqs

Chapter 18 The Laws of Thermodynamics Q.15P
As an ideal gas expands at constant pressure from a volume of 0.74 m3 to a volume of 2.3 m3 it does 93 J of work. What is the gas pressure during this process?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics15ps

Chapter 18 The Laws of Thermodynamics Q.16P
The volume of a monatomic ideal gas doubles in an isother mal expansion. By what factor does its pressure change?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics16ps

Chapter 18 The Laws of Thermodynamics Q.17P
IP (a) If the internal energy of a system increases as the result of an adiabatic process, is work done on the system or b the system? (b) Calculate the work done on or by the system in part (a) if its internal energy increases by 670 J.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics17ps

Chapter 18 The Laws of Thermodynamics Q.18P
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics18p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics18ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics18ps1

Chapter 18 The Laws of Thermodynamics Q.19P
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics19p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics19ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics19ps1

Chapter 18 The Laws of Thermodynamics Q.20P
IP If 8.00 moles of a monatomic ideal gas at a temperature of 245 K are expanded isothennally from a volume of 1.12 L to a volume of 4.33 T, calculate (a) the work done and (b) the heat flow into or out of the gas. (c) If the number of moles is doubled, by what factors do your answers to parts (a) and (b) change? Explain.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics20ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics20ps1

Chapter 18 The Laws of Thermodynamics Q.21P
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics21p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics21ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics21ps1

Chapter 18 The Laws of Thermodynamics Q.22P
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics22p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics22ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics22ps1

Chapter 18 The Laws of Thermodynamics Q.23P
IP (a) A monatomic ideal gas expands at constant pressure. Is heat added to the system or taken from the system during this process? (b) Find the heat added to or taken from the gas in part (a) if it expands at a pressure of 130 kPa from a volume of 0.76 m3 to a volume of 0.93 m3.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics23ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics23ps1
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics23ps2

Chapter 18 The Laws of Thermodynamics Q.24P
During an adiabatic process, the temperature of 3.92 moles of a monatomic ideal gas drops from 485 °C to 205 °C. For this gas, find (a) the work it does, (b) the heat it exchanges with its surroundings, and (c) the change in its internal energy.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics24ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics24ps1

Chapter 18 The Laws of Thermodynamics Q.25P
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics25p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics25pss
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics25pss1
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics25pss2

Chapter 18 The Laws of Thermodynamics Q.26P
With the pressure held constant at 210 kPa, 49 mol of a monatomic ideal gas expands from an initial volume of 0.75 m3 to a final volume of 1.9 m3. (a) How much work was done by the gas during the expansion? (b) What were the initial and final temperatures of the gas? (c) What was the change in the internal energy of the gas? (d) How much heat was added to the gas?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics26ps

Chapter 18 The Laws of Thermodynamics Q.27P
IP Suppose 67.5 moles of an ideal monatomic gas undergo the series of processes shown in Figure 18–24. (a) Calculate the temperature at the points A, B, and C. (b) For each process, A → B, B →C, and C → A, state whether heat enters or leaves the system. Explain in each case. (c) Calculate the heat exchanged with the gas during each of the three processes.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics27ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics27ps1
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics27ps2
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics27ps3
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics27ps4

Chapter 18 The Laws of Thermodynamics Q.28P
A gas is contained in a cylinder with a pressure of 140 kPa and an initial volume of 0.66 m3. How much work is done by the gas as it (a) expands at constant pressure to twice its initial volume, or (b) is compressed to one-third its initial volume?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics28ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics28ps1

Chapter 18 The Laws of Thermodynamics Q.29P
A system expands by 0.75m3 at a constant pressure of 125 kPa. Find the heat that flows into or out of the system if its internal energy (a) increases by 65 J or (b) decreases by 1850 J. In each case, give the direction of heat flow.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics29ps

Chapter 18 The Laws of Thermodynamics Q.30P
IP An ideal monatomic gas is held in a perfectly insulated cylinder fitted with a movable piston. The initial pressure of the gas is 110 kPa, and its initial temperature is 280 K. By pushing down on the piston, you are able to increase the pressure to 140 kPa, (a) During this process, did the temperature of the gas increase, decrease, or stay the same? Explain. (b) Find the final temperature of the gas.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics30ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics30ps1

Chapter 18 The Laws of Thermodynamics Q.31P
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics31p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics31ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics31ps1

Chapter 18 The Laws of Thermodynamics Q.32P
An ideal gas doubles its volume in one of three different ways: (i) at constant pressure; (ii) at constant temperature; (iii) adiabatically. Explain your answers to each of the following questions: (a) In which expansion does the gas do the most work? (b) In which expansion does the gas do the least work? (c) Which expansion results in the highest final temperature? (d) Which expansion results in the lowest final temperature?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics32ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics32ps1

Chapter 18 The Laws of Thermodynamics Q.33P
CE Predict/Explain You plan to add a certain amount of heat to a gas in order to raise its temperature. (a) If you add the heat at constant volume, is the increase in temperature greater than, less than, or equal to the increase in temperature if you add the heat at constant pressure? (b) Choose the best explanation from among the following:
I. The same amount of heat increases the temperature by the same amount, regardless of whether the volume or the pressure is held constant.
II. All the heat goes into raising the temperature when added at constant volume;none goes into mechanical work.
III. Holding the pressure constant will cause a greater increase in temperature than simply having a fixed volume.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics33ps

Chapter 18 The Laws of Thermodynamics Q.34P
Find the amount of heat needed to increase the temperature of 3.5 mol of an ideal monatomic gas by 23 K if (a) the pressure or (b) the volume is held constant.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics34ps

Chapter 18 The Laws of Thermodynamics Q.35P
(a) If 535 J of heat are added to 45 moles of a monatomic gas at constant volume, how much does the temperature of the gas increase? (b) Repeat part (a), this time for a constant-pressure process.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics35ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics35ps1

Chapter 18 The Laws of Thermodynamics Q.36P
A system consists of 2.5 mol of an ideal monatomic gas at 325 K. How much heat must be added to the system to double its internal energy at (a) constant pressure or (b) constant volume?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics36ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics36ps1

Chapter 18 The Laws of Thermodynamics Q.37P
Find the change in temperature if 170 J of heat are added to 2.8 mol of an ideal monatomic gas at (a) constant pressure or (b) constant volume.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics37ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics37ps1

Chapter 18 The Laws of Thermodynamics Q.38P
IP A cylinder contains 18 moles of a monatomic ideal gas at a constant pressure of 160 kPa. (a) How much work does the gas do as it expands 3200 cm3, from 5400 cm3 to 8600 cm3? (b) If the gas expands by 3200 cm3 again, this time from 2200 cm3 to 5400 cm3, is the work it does greater than, less than, or equal to the work found in part (a)? Explain. (c) Calculate the work done as the gas expands from 2200 cm3 to 5400 cm3.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics38ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics38ps1

Chapter 18 The Laws of Thermodynamics Q.39P
· · IP The volume of a monatomic ideal gas doubles in an adiabatic expansion. By what factor do (a) the pressure and (b) the temperature of the gas change? (c) Verify your answers to parts (a) and (b) by considering 135 moles of gas with an initial pressure of 330 kPa and an initial volume of 1.2 m3. Find the pressure and temperature of the gas after it expands adiabatically to a volume of 2.4 m3.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics39ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics39ps1
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics39ps2

Chapter 18 The Laws of Thermodynamics Q.40P
A monatomic ideal gas is held in a thermally insulated container with a volume of 0.0750 m3. The pressure of the gas is 105 kPa, and its temperature is 317 K. (a) To what volume must the gas be compressed to increase its pressure to 145 kPa? (b) At what volume will the gas have a temperature of 295 K?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics40ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics40ps1

Chapter 18 The Laws of Thermodynamics Q.41P
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics41p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics41ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics41ps1
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics41ps2

Chapter 18 The Laws of Thermodynamics Q.42P
Referring to Problem 41, suppose the gas is expanded along processes 3 and 4 in Figure 18–26. On process 3 the gas expands at constant pressure from an initial volume of 1.00 m3 to a final volume of 3.00 m3. On process 4 the gas is heated at constant volume from an initial pressure of 106 kPa to a final pressure of 212 kPa. (a) How much heat is added to the gas during these two processes? (b) How much work does the gas do during this expansion? (c) What is the change in the internal energy of the gas?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics42ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics42ps1
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics42ps2

Chapter 18 The Laws of Thermodynamics Q.43P
CE A Carnot engine operates between a hot reservoir at the Kelvin temperature Th and a cold reservoir at the Kelvin temperature Tc.(a) If both temperatures are doubled, does the efficiency of the engine increase, decrease, or stay the same? Explain. (b) If both temperatures are increased by 50 K, does the efficiency of the engine increase, decrease, or stay the same? Explain.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics43ps

Chapter 18 The Laws of Thermodynamics Q.44P
· CE A Carnot engine can be operated with one of the following four sets of reservoir temperatures: A, 400 K and 800 K; B, 400 K and 600 K; C, 800 K and 1200 K; and D, 800 K and 1000 K. Rank these reservoir temperatures in order of increasing efficiency of the Carnot engine. Indicate ties where appropriate.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics44ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics44ps1

Chapter 18 The Laws of Thermodynamics Q.45P
What is the efficiency of an engine that exhausts 870 J of heat in the process of doing 340 J of work?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics45ps

Chapter 18 The Laws of Thermodynamics Q.46P
An engine receives 690 J of heat from a hot reservoir and gives off 430 J of heat to a cold reservoir. What arc (a) the work done and (b) the efficiency of this engine?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics46ps

Chapter 18 The Laws of Thermodynamics Q.47P
A Carnot engine operates between the temperatures 410 K and 290 K. (a) How much heat must be given to the engine to produce 2500 J of work? (b) How much heat is discarded to the cold reservoir as this work is done?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics47ps

Chapter 18 The Laws of Thermodynamics Q.48P
A nuclear power plant has a reactor that produces heat at the rate of 838 MW. This heat is used to produce 253 MW of mechanical power to drive an electrical generator. (a) At what rate is heat discarded to the environment by this power plant? (b) What is the thermal efficiency of the plant?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics48ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics48ps1
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics48ps2
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics48ps3

Chapter 18 The Laws of Thermodynamics Q.49P
At a coal-burning power plant a steam turbine is operated with a power output of 548 MW. The thermal efficiency of the power plant is 32.0%. (a) At what rate is heat discarded to the environment by this power plant? (b) At what rate must heat be supplied to the power plant by burning coal?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics49ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics49ps1

Chapter 18 The Laws of Thermodynamics Q.50P
IP If a heat engine does 2700 J of work with an efficiency of 0.18, find (a) the heat taken in from the hot reservoir and (b) the heat given off to the cold reservoir. (c) If the efficiency of the engine is increased, do your answers to parts (a) and (b) increase decrease, or stay the same? Explain.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics50ps

Chapter 18 The Laws of Thermodynamics Q.51P
IP The efficiency of a particular Carnot engine is 0.300. (a) If the high-temperature reservoir is at a temperature of 545 K, what is the temperature of the low-temperature reservoir? (b) To increase the efficiency of this engine to 40.0%, must the temperature of the low-temperature reservoir be increased or decreased? Explain. (c) Find the temperature of the low-temperature reservoir that gives an efficiency of 0.400.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics51ps

Chapter 18 The Laws of Thermodynamics Q.52P
During each cycle a reversible engine absorbs 2500 J of heat from a high-temperature reservoir and performs 2200 J of work. (a) What is the efficiency of this engine? (b) How much heat is exhausted to the low-temperature reservoir during each cycle? (c) What is the ratio, Th/Tc,of the two reservoir temperatures?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics52ps

Chapter 18 The Laws of Thermodynamics Q.53P
The operating temperatures for a Carnot engine are Tc and Th = Tc + 55 K. The efficiency of the engine is 11%. Find Tc and Th.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics53ps

Chapter 18 The Laws of Thermodynamics Q.54P
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics54p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics54ps

Chapter 18 The Laws of Thermodynamics Q.55P
CE Predict/Explain (a) If the temperature in the kitchen is decreased, is the cost (work needed) to freeze a dozen ice cubes greater than, less than, or equal to what it was before the kitchen was cooled? (b) Choose the best explanation from among the following:
I. The difference intemperature between the inside and the outside of the refrigerator is decreased, and hence less work is required to freeze the ice.
II. The same amount of ice is frozen in either case, which requires the same amount of heat to be removed and hence the same amount of work.
III. Cooling the kitchen means that the refrigerator must do more work, both to freeze the ice cubes and to warm the kitchen.
Solution:
ANSWER:
(a) If the temperature of the kitchen is decreased, then less energy is required to cool the
water. At a lower temperature, the heat extracted from the water can be expelled. Due to this reason, less work done is needed to freeze the a dozen ice cubes.
Therefore, if the temperature in the kitchen is decreased, then the work needed to freeze a dozen ice cubes less than before the kitchen is cooled.
(b) The difference in temperature between the inside and the outside of the refrigerator isdecreased, and hence less work is required to freeze the ice.Using the explanation given in the part (a), this is the correct explanation.
Hence, the best explanation from the given statements is.

Chapter 18 The Laws of Thermodynamics Q.56P
The refrigerator in your kitchen does 480 J of work to remove 110 J of heat from its interior. (a) How much heat does the refrigerator exhaust intothe kitchen? (b) What is the refrigerator’s coefficient of performance?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics56ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics56ps1
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Chapter 18 The Laws of Thermodynamics Q.57P
A refrigerator with a coefficient of performance of 1.75 absorbs 3.45 × 104 J of heat from the low-temperature reservoir during each cycle. (a) How much mechanical work is required to operate the refrigerator for a cycle? (b) How much heat does the refrigerator discard to the high-temperature reservoir during each cycle?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics57ps

Chapter 18 The Laws of Thermodynamics Q.58P
To keep a room at a comfortable 21.0 °C, a Carnot heat pump does 345 J of work and supplies it with 3240 J of heat. (a) How much heat is removed from the outside air by the heat pump? (b) What is the temperature of the outside air?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics58ps

Chapter 18 The Laws of Thermodynamics Q.59P
· · An air conditioner is used to keep the interior of a house at a temperature of 21 °C while the outside temperature is 32 °C. If heat leaks into the house at the rate of 11 kW, and the air conditioner has the efficiency of a Carnot engine, what is the mechanical power required to keep the house cool?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics59ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics59ps1

Chapter 18 The Laws of Thermodynamics Q.60P
A reversible refrigerator has a coefficient of performance equal to 10.0. What is its efficiency?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics60ps

Chapter 18 The Laws of Thermodynamics Q.61P
A freezer has a coefficient of performance equal to 4.0. How much electrical energy must this freezer use to produce 1.5 kg of ice at −5.0 °C from water at 15 °C?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics61ps

Chapter 18 The Laws of Thermodynamics Q.62P
If a Carnot engine has an efficiency of 0.23, what is its coefficient of performance if it is run backward as a heat pump?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics62ps

Chapter 18 The Laws of Thermodynamics Q.63P
CE Predict/Explain (a) If you rub your hands together, does the entropy of the universe increase, decrease, or stay the same? (b) Choose the best explanation from among the following:
I. Rubbing hands together draws heat from the surroundings, and therefore lowers the entropy.
II. No mechanicalwork is done by the rubbing, and hence the entropydoes not change.
III. The heat produced by rubbing raises the temperature of your hands and the air, which increases the entropy.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics63ps

Chapter 18 The Laws of Thermodynamics Q.64P
Predict/Explain (a) An ideal gas is expanded slowly and isothermally. Does its entropy increase, decrease, or stay the same? (b) Choose the best explanation from among the following:
I. Heat must be added to the gas to maintain a constant temperature, and this increases the entropy of the gas.
II. The temperature of the gas remains constant, which means its entropy also remains constant.
III. As the gas is expanded its temperature and entropy will decrease.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics64ps

Chapter 18 The Laws of Thermodynamics Q.65P
Predict/Explain (a) A gas isexpanded reversibly and adiabarically. Does its entropy increase, decrease, or stay the same? (b) Choose the best explanation from among the following:
I. The process is reversible, and no heat is added to the gas. Therefore, the entropy of the gas remains the same.
II. Expanding the gas gives it more volume to occupy, and this increases its entropy.
III. The gas is expanded with no heat added to it, and hence its temperature will decrease. This, in turn, will lower its entropy.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics65ps

Chapter 18 The Laws of Thermodynamics Q.66P
Find the change in entropy when 1.85 kg of water at 100 °C is boiled away to steam at 100 °C.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics66ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics66ps1

Chapter 18 The Laws of Thermodynamics Q.67P
Determine the change in entropy that occurs when 3.1 kg of water freezes at 0 °C.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics67ps

Chapter 18 The Laws of Thermodynamics Q.68P
· CEYou heat a pan of water on the stove. Rank the following temperature increases in order of increasing entropy change. Indicate ties where appropriate: A, 25 °C to 35 °C; B, 35 °C to 45 °C; C, 45 °C to 50 °C; and D, 50 °C to 55 °C.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics68ps

Chapter 18 The Laws of Thermodynamics Q.69P
On a cold winter’s day heat leaks slowly out of a house at the rate of 20.0 kW. If the inside temperature is 22 °C, and the outside temperature is −14.5 °C, find the rate of entropy increase.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics69ps

Chapter 18 The Laws of Thermodynamics Q.70P
· An 88-kg parachutist descends through a vertical height of 380 m with constant speed. Find the increase in entropy produced by the parachutist, assuming the air temperature is 21 °C.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics70ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics70ps1

Chapter 18 The Laws of Thermodynamics Q.71P
IP Consider the air-conditioning system described in Problem 59. (a) Does the entropy of the universe increase, decrease, or stay the same as the air conditioner keeps the imperfectly insulated house cool? Explain. (b) What is the rate at which the entropy of the universe changes during this process?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics71ps

Chapter 18 The Laws of Thermodynamics Q.72P
A heat engine operates between a high-temperature reservoir at 610 K and a low-temperaturereservoir at 320 K. In one cycle, the engine absorbs 6400 J of heat from the high-temperature reservoirand does 2200 J of work. What is the net change in entropy as a result of this cycle?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics72ps

Chapter 18 The Laws of Thermodynamics Q.73GP
CE An ideal gas is held in an insulated container at the temperature T. All the gas is initially in one-half of the container, with a partition separating the gas from the other half of the container, which is a vacuum. If the partition ruptures, and the gas expands to fill the entire container, is the final temperature greater than, less than, or equal to 77 Explain.
Solution:
The final temperature is unchanged as no work is done by the gas expanding into the vacuum. As the container is insulated, heat does not flow into or out of the system. Therefore, the internal energy and the temperatures of the system remain constant.

Chapter 18 The Laws of Thermodynamics Q.74GP
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics74p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics74ps

Chapter 18 The Laws of Thermodynamics Q.75GP
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics75p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics75pss
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Chapter 18 The Laws of Thermodynamics Q.76GP
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics76p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics76ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics76ps1

Chapter 18 The Laws of Thermodynamics Q.77GP
Heat is added to a 0.14-kg block of ice at 0 °C, increasing its entropy by 87 J/K. How much ice melts?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics77ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics77ps1

Chapter 18 The Laws of Thermodynamics Q.78GP
The heat that goes into a particular Carnot engine is 4.00 times greater than the work it performs. What is the engine’s efficiency?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics78ps

Chapter 18 The Laws of Thermodynamics Q.79GP
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics79p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics79ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics79ps1
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Chapter 18 The Laws of Thermodynamics Q.80GP
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics80p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics80pss
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics80pss1

Chapter 18 The Laws of Thermodynamics Q.81GP
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics81p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics81ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics81ps1
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics81ps2

Chapter 18 The Laws of Thermodynamics Q.82GP
IP Engine A has an efficiency of 66%. Engine B absorbs the same amount of heat from the hot reservoir and exhausts twice as much heat to the cold reservoir. (a) Which engine has the greater efficiency? Explain. (b) What is the efficiency of engine B?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics82ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics82ps1

Chapter 18 The Laws of Thermodynamics Q.83GP
A freezer with a coefficient of performance of 3.88 is used to convert 1.75 kg of water to ice in one hour. The water starts at a temperature of 20.0 °C, and the ice that is produced is cooled to a temperature of −5.00 °C. (a) How much heat must be removed from the water for this process to occur? (b) How much electrical energy does the freezer use during this hour of operation? (c) How much heat is discarded into the room that houses the freezer?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics83ps

Chapter 18 The Laws of Thermodynamics Q.84GP
Suppose 1800 J of heat are added to 3.6 mol of argon gas at a constant pressure of 120 kPa. Find the change in (a) internal energy and (b) temperature for this gas. (c) Calculate the change in volume of the gas. (Assume that the argon can be treated as an ideal monatomic gas.)
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics84ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics84ps1
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics84ps2

Chapter 18 The Laws of Thermodynamics Q.85GP
Entropy and the Sun The surface of the Sun has a temperature of 5500 °C and the temperature of deep space is 3.0 K. (a) Find the entropy increase produced by the Sun in one day, given that it radiates heat at the rate of 3.80 × 1026 W. (b) How much work could have been done if this heat had been used to run an ideal heat engine?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics85ps

Chapter 18 The Laws of Thermodynamics Q.86GP
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics86p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics86ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics86ps1

Chapter 18 The Laws of Thermodynamics Q.87GP
· · A cylinder with a movable piston holds 2.75 mol of argon at a constant temperature of 295 K. As the gas is compressed isothermally, its pressure increases from 101 kPa to 121 kPa. Find (a) the final volume of the gas, (b) the work done by the gas, and (c) the heat added to the gas.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics87ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics87ps1

Chapter 18 The Laws of Thermodynamics Q.88GP
An inventor claims a new cyclic engine that uses organic grape juice as its working material. According to the claims, the engine absorbs 1250 J of heat from a 1010-K reservoir and performs 1120 J of work each cycle. The waste heat is exhausted to the atmosphere at a temperature of 302 K. (a) What is the efficiency that is implied by these claims? (b) What is the efficiency of a reversible engine operating between the same high and low temperatures used by this engine? (Should you invest in this invention?)
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics88ps

Chapter 18 The Laws of Thermodynamics Q.89GP
A nonreversible heat engine operates between a high-temperature reservoir at Th = 810 K and a low-temperature reservoir at Tc = 320 K. During each cycle the engine absorbs 660 J of heat from the high-temperature reservoir and performs 250 I of work. (a) Calculate the total entropy change ∆Stot for one cycle. (b) How much work would a reversible heat engine perform in one cycle if it operated between the same two temperatures and absorbed the same amount of heat? (c) Show that the difference in work between the nonreversible engine and the reversible engine is equal to Tc∆Stot.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics89ps

Chapter 18 The Laws of Thermodynamics Q.90GP
IP A small dish containing 530 g of water is placed outside for the birds. During the night the outside temperature drops to −5.0 °C and stays at that value for several hours. (a) When the water in the dish freezes at 0 °C, does its entropy increase, decrease, or stay the same? Explain. (b) Calculate the change in entropy that occurs as the water freezes. (c) When the water freezes, is there an entropy change anywhere else in the universe? If so, specify where the change occurs.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics90ps

Chapter 18 The Laws of Thermodynamics Q.91GP
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics91p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics91ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics91ps1

Chapter 18 The Laws of Thermodynamics Q.92GP
Which would make the greater change in the efficiency of a Carnot heat engine: (a) raising the temperature of the high-temperature reservoir by ∆T, or (b) lowering the temperature of the Low-temperature reservoir by ∆T? Justify your answer by calculating the change in efficiency for each of these cases.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics92ps

Chapter 18 The Laws of Thermodynamics Q.93GP
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics93p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics93ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics93ps1
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics93ps2

Chapter 18 The Laws of Thermodynamics Q.94GP
When a heat Q is added to a monatomic ideal gas at constant pressure, the gas does a work W. Find the ratio, W/Q.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics94ps

Chapter 18 The Laws of Thermodynamics Q.95GP
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics95p
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics95ps
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mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics95ps5

Chapter 18 The Laws of Thermodynamics Q.96GP
A Carnot engine and a Carnot refrigerator operate between the same two temperatures. Show that the coefficient of performance, COP, for the refrigerator is related to the efficiency, e,of the engine by the following expression; COP = (1 – e)/e.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics96ps

Chapter 18 The Laws of Thermodynamics Q.97PP
Suppose an OTEC system operates with surface water at 22 °C and deep water at 4.0 °C. What is the maximum efficiency this system could have?
A. 6.10%
B. 8.20%
C. 9.40%
D. 18.0%
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics97ps

Chapter 18 The Laws of Thermodynamics Q.98PP
If 1500 kg of water at 22 °Cis cooled to 4.0 °C, how much energy is released? (For comparison, the energy released in burning a gallon of gasoline is 1.3 × 108 J.)
A. 2.5 × 107 J
B. 1.1 x 108 J
C. 1.4 × 108 J
D. 1.6 × 108 J
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics98ps

Chapter 18 The Laws of Thermodynamics Q.99PP
If we go deeper for colder water, where the temperature is only 2.0 °C, what is the maximum efficiency now?
A. 6.78%
B. 9.09%
C. 9.32%
D. 19.0%
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics99ps

Chapter 18 The Laws of Thermodynamics Q.100IP
· · IP Referring to Active Example 18–3 Suppose we lower the temperature of the cold reservoir to 295 K; the temperature of the hot reservoir is still 576 K. (a) Is the new efficiency of the engine greater than, less than, or equal to 0.470? Explain. (b) What is the new efficiency? (c) Find the work done by this engine when 1050 J of heat is drawn from the hot reservoir.
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics100ps

Chapter 18 The Laws of Thermodynamics Q.101IP
· · IP Referring to Active Example 18–3 Suppose the temperature of the hot reservoir is increased by 16 K, from 576 K to 592 K, and that the temperature of the cold reservoir is also increased by 16 K,from 305 K to 321 K. (a) Is the new efficiency greater than, less than, or equal to 0.470? Explain. (b) What is the new efficiency? (c) What is the change in entropy of the hot reservoir when 1050 J of heat is drawn from it? (d) What is the change in entropy of the cold reservoir?
Solution:
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics101ps
mastering-physics-solutions-chapter-18-the-laws-of-thermodynamics101ps1

Mastering Physics Solutions Chapter 17 Phases and Phase Changes

Mastering Physics Solutions Chapter 17 Phases and Phase Changes

 

Mastering Physics Solutions

Chapter 17 Phases and Phase Changes Q.1CQ
At the beginning of a typical airline flight you are instructed about the proper use of oxygen masks that will fall from the ceiling if the cabin pressure suddenly drops. You are advised that the oxygen masks are working properly, even if the bags do not fully inflate. In fact, the bags expand to their fullest if cabin pressure is lost at high altitude, but expand only partially if the plane is at low altitude. Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-changes1cqs

Chapter 17 Phases and Phase Changes Q.1P
(a) Is the number of molecules in one mole of N2 greater than, less than, or equal to the number of molecules in one mole of O2? (b) Is the mass of one mole of N2 greater than, less than, or equal to the mass of one mole of O2?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-changes1ps

Chapter 17 Phases and Phase Changes Q.2CQ
How is the air pressure in a tightly sealed house affected by operating the furnace? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-changes2cqs

Chapter 17 Phases and Phase Changes Q.2P
Is the number of atoms in one mole of helium greater than, less than, or equal to the number of atoms in one mole of oxygen? Helium consists of individual atoms. He. and oxygen is a diatomic gas. 02
Solution:
Helium is a monoatomic gas while oxygen is a diatomic gas Therefore, the total number of atoms in one mole of oxygen gas is equal to twice the number of atoms in one mole of helium Hence, the total number of atoms in one mole of helium gas is less than the total number of atoms in one mole of oxygen

Chapter 17 Phases and Phase Changes Q.3CQ
The average speed of air molecules in your room is on the order of the speed of sound. What is their average velocity?
Solution:
Since the velocity is accounts both it speed and direction of motion, so the average velocity of air molecules in the room will be Izerol as the molecules move randomly in all directions.

Chapter 17 Phases and Phase Changes Q.3P
If you put a helium-filled balloon in the refrigerator, (a) will its volume increase, decrease, or stay the same? (b) Choose the best explanation from among the following:
I. Lowering the temperature of an ideal gas at constant pressure results in a reduced volume.
II. The same amount of gas is in the balloon; therefore, its volume remains the same.
III. The balloon can expand more in the cool air of the refrigerator, giving an increased volume.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-changes3ps

Chapter 17 Phases and Phase Changes Q.4CQ
Is it possible to change both the pressure and thevolume of an ideal gas without changing the average kinetic energy of its molecules? If your answer is no, explain why not. If your answer is yes, give a specific example.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-changes4cqs

Chapter 17 Phases and Phase Changes Q.4P
Two containers hold ideal gases at the same temperature. Container A has twice the volume and half the number of molecules as container B. What is the ratio PA/PB where PA is the pressure in container A and PB is the pressure in container B?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-changes4ps

Chapter 17 Phases and Phase Changes Q.5CQ
Is it possible to change both the pressure and thevolume of an ideal gas without changing the average kinetic energy of its molecules? If your answer is no, explain why not. If your answer is yes, give a specific example.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-changes5cqs

Chapter 17 Phases and Phase Changes Q.5P
Standard temperature and pressure (STP) is defined as a temperature of 0°C and a pressure of 101.3 kPa. Whatis the volume occupied by one mole of an ideal gas at STP?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-changes5ps

Chapter 17 Phases and Phase Changes Q.6CQ
A camping stove just barely boils water on a mountaintop. When the stove is used at sea level, will it be able to boil water? Explain your answer.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-changes6cqs

Chapter 17 Phases and Phase Changes Q.6P
After emptying her lungs, a person inhales 4.1 L of air at 0.0 °C and holds her breath. How much does the volume of the air increase as it warms to her body temperature of 37 °C?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-changes6ps
mastering-physics-solutions-chapter-17-phases-and-phase-changes6ps1

Chapter 17 Phases and Phase Changes Q.7CQ
An autoclave is a device used to sterilize medical instruments. It is essentially a pressure cooker that heats the instruments in water under high pressure. This ensures that the sterilization process occurs at temperatures greater than the normal boiling point of water. Explain why the autoclave produces such high temperatures.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change7cqs

Chapter 17 Phases and Phase Changes Q.7P
In the morning, when the temperature is 286 K, a bicyclist finds that the absolute pressure in his tires is 501 kPa. That afternoon he finds that the pressure in the tires has increased to 554 kPa. Ignoring expansion of the tires, find the afternoon temperature.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change7ps

Chapter 17 Phases and Phase Changes Q.8CQ
As the temperature of ice is increased, it changes first tinto a liquid and then into a vapor. On the other hand, dry ice, which is solid carbon dioxide, changes directly from a solid to a vapor as its temperature is increased. How might one produce liquid carbon dioxide?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change8cqs

Chapter 17 Phases and Phase Changes Q.8P
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change8ps
mastering-physics-solutions-chapter-17-phases-and-phase-change8ps1

Chapter 17 Phases and Phase Changes Q.9CQ
Isopropyl alcohol is sometimes rubbed onto a patient’s arms and legs to lower their body temperature. Why is this effective?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change9cqs

Chapter 17 Phases and Phase Changes Q.9P
Amount of Helium in a Blimp The Goodyear blimp Spirit of Akron is 62.6 m long and contains 7023 m3 of helium. When the temperature of the helium is 285 K, its absolute pressure is 112 kPa. Find the mass of the helium in the blimp.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change9ps

Chapter 17 Phases and Phase Changes Q.10CQ
If you toss an ice cube into a swimming pool, is the water in the pool now at 0°C? Explain.
Solution:
The ice cube has an assured mass, which will engage a certain amount of heat from the water in the pool. The ice cube melt and water will come to a temperature equilibrium determined by the total mass of water and the total energy in the system.

Chapter 17 Phases and Phase Changes Q.10P
A compressed-air tank holds 0.500 m3 of air at a temperature of 285 K and a pressure of 880 kPa. What volume would the air occupy if it were released into the atmosphere, where the pressure is 101 kPa and the temperature is 303 K?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change10ps
mastering-physics-solutions-chapter-17-phases-and-phase-change10ps1

Chapter 17 Phases and Phase Changes Q.11CQ
A drop of water on a kitchen counter evaporates in a matter of minutes. However, only a relatively small fraction of the molecules in the drop move rapidly enough to escape through the drop’s surface. Why, then, does the entire drop evaporate rather than just a small fraction of it?
Solution:
Evaporation is the process of revolving from liquid into vapor. Evaporation of water from the kitchen’s surface, the relative fraction of the molecules drips quickly. They take energy from their surroundings (which have enough temperature) from the drop of water. Then, the next molecules come up, occupy the same level, and repeat the above process. In this way, all of the water evaporates in a matter of minutes from the surface of the kitchen. Hence, entire drop evaporates rather than just a small fraction of it.

Chapter 17 Phases and Phase Changes Q.11P
A typical region of interstellar space may contain 106 atoms per cubic meter (primarily hydrogen) at a temperature of 100 K. What is the pressure of this gas?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change11ps

Chapter 17 Phases and Phase Changes Q.12
CE Four ideal gases have the following pressures, P,volumes, V, and mole numbers, n: gas A, P = 100 kPa, V = 1 m3, n = 10 mol; gas B, P = 200 kPa, V = 2 m3, n = 20 mol; gas C, P = 50 kPa, V = 1 m3, n = 50 mol;gas D,P = 50 kPa, V = 4 m3 n = 5 mol. Rank these gases in order of increasing temperature. Indicate ties where appropriate.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change12ps

Chapter 17 Phases and Phase Changes Q.13P
A balloon contains 3.7 liters of nitrogen gas at a temperature of 87 K and a pressure of 101 kPa. If the temperature of the gas0 is allowed to increase to 24 °C and the pressure remains constant, what volume will the gas occupy?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change13ps

Chapter 17 Phases and Phase Changes Q.14P
A balloon is filled with helium at a pressure of 2.4 × 105 Pa. The balloon is at a temperature of 18 °C and has a radius of 0.25 m. (a) How many helium atoms are contained in the balloon? (b) Suppose we double the number of helium atoms in the balloon, keeping the pressure and the temperature fixed. By what factor does the radius of the balloon increase? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change14ps
mastering-physics-solutions-chapter-17-phases-and-phase-change14ps1

Chapter 17 Phases and Phase Changes Q.15P
A gas has a temperature of 310 K and a pressure of 101 kPa. (a) Find the volume occupied by 1.25 mol of this gas, assuming it is ideal, (b) Assuming the gas molecules can be approximated as small spheres of diameter 2.5 × 10−10 m, determine the fraction of the volume found in part (a) that is occupied by the molecules, (c) In determining the properties of an ideal gas, we assume that molecules are pointa of zero volume. Discuss the validity of this assumption for the case considered here.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change15ps

Chapter 17 Phases and Phase Changes Q.16P
A 15-cm3 flask contains 0.460 g of a gas at a pressure of 153 kPa and a temperature of 322 K. What is the molecular mass of this gas?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change16ps

Chapter 17 Phases and Phase Changes Q.17P
The Atmosphere of Mars On Mars, the average temperature is —64°F and the average atmospheric pressure is 0.92 kPa. (a) What is the number of molecules per volume in the Martian atmosphere? (b) Is the number of molecules per volume on the Earth greater than, less than, or equal to the number per volume on Mars? Explain your reasoning, (c) Estimate the number of molecules per volume in Earth’s atmosphere.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change17ps
mastering-physics-solutions-chapter-17-phases-and-phase-change17ps1

Chapter 17 Phases and Phase Changes Q.18P
The air inside a hot-air balloon has an average temperature of 79.2 °C. The outside air has a temperature of 20.3 °C. What is the ratio of the density of air in the balloon to the density of air in the surrounding atmosphere?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change18ps
mastering-physics-solutions-chapter-17-phases-and-phase-change18ps1

Chapter 17 Phases and Phase Changes Q.19P
mastering-physics-solutions-chapter-17-phases-and-phase-change19p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change19ps

Chapter 17 Phases and Phase Changes Q.20P
mastering-physics-solutions-chapter-17-phases-and-phase-change20p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change20ps

Chapter 17 Phases and Phase Changes Q.21P
One mole of a monatomic ideal gas has an initial pressure of 210 kPa, an initial volume of 1.2 × 10−3 m3, and an initial temperature of 350 K. The gas now undergoes three separate processes: (i) a constant-temperature expansion that triples its volume; (ii) a constant-pressure compression to its initial volume; and (iii) a constant-volume increase in pressure to its initial pressure. At the end of these three processes, the gas is back at its initial pressure, volume, and temperature. Plot these processes on a pressure-versus-volume graph, showing the values of P and V at the end points of each process.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change21ps
mastering-physics-solutions-chapter-17-phases-and-phase-change21ps1

Chapter 17 Phases and Phase Changes Q.22P
The air inyour room is composed mostly of oxygen (O2) and nitrogen (N2) molecules. The oxygen molecules are more massive than the nitrogen molecules, (a) Is the rms speed of the O2 molecules greater than, less than, or equal to the rms speed of the N2 molecules? (b) Choose the best explanation from among the following:
I. The more massive oxygen molecules have greater momentum and therefore greater speed.
II. Equal temperatures for the oxygen and nitrogen molecules imply they have equal rms speeds.
III. The temperature is the same for both molecules, and hence their average kinetic energies are equal. As a result, the more massive oxygen molecules have lower speeds.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change22ps
mastering-physics-solutions-chapter-17-phases-and-phase-change22ps1

Chapter 17 Phases and Phase Changes Q.23P
If the translational speed of molecules in an ideal gas is doubled, by what factor does the Kelvin temperature change? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change23ps

Chapter 17 Phases and Phase Changes Q.24P
A piston held at the temperature T contains a gas mixture with molecules of three different types; A, B, and C. The corresponding molecular masses are mc > m8 > mA Rank these molecular types in order of increasing (a) average kinetic energy and (b) rms speed. Indicate ties where appropriate.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change24ps

Chapter 17 Phases and Phase Changes Q.25P
The molecules in a tank of hydrogen have the same rms speed as the molecules in a tank of oxygen. State whether each of the following statements is true, false, or unknowable with the given information: (a) the pressures are the same; (b) the hydrogen is at the higher temperature; (c) the hydrogen has the higher pressure; (d) the temperatures are the same; (e) the oxygen is at the higher temperature.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change25ps
mastering-physics-solutions-chapter-17-phases-and-phase-change25ps1

Chapter 17 Phases and Phase Changes Q.26P
At what temperature is the rms speed of H2 equal to the rms speed that O2 has at 313 K?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change26ps
mastering-physics-solutions-chapter-17-phases-and-phase-change26ps1

Chapter 17 Phases and Phase Changes Q.27P
Suppose a planet has an atmosphere of pure ammonia at 0.0 °C. What is the rms speed of the ammonia molecules?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change27ps

Chapter 17 Phases and Phase Changes Q.28P
Three moles of oxygen gas (that is, 3.0 mol of O2) are placed in a portable container with a volume of 0.0035 m3.1f the temperature of the gas is 295 °C, find (a) the pressure of the gas and (b) the average kinetic energy of an oxygen molecule, (c) Suppose the volume of the gas is doubled, while the temperature and number of moles are held constant. By what factor do your answers to parts (a) and (b) change? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change28ps
mastering-physics-solutions-chapter-17-phases-and-phase-change28ps1

Chapter 17 Phases and Phase Changes Q.29P
The rms speed of O2 is 1550 m/s at a given temperature, (a) Is the rms speed of H2O at this temperature greater than, less than, or equal to 1550 m/s? Explain, (b) Find the rms speed of H2Oat this temperatiue.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change29ps
mastering-physics-solutions-chapter-17-phases-and-phase-change29ps1

Chapter 17 Phases and Phase Changes Q.30P
An ideal gas is kept in a container of constant volume. The pressure of the gas is also kept constant, (a) If the number
of molecules in the gas is doubled, does the rms speed increase, decrease, or stay the same? Explain, (b) If the initial rms speed is 1300 m/s, what is the final rms speed?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change30ps
mastering-physics-solutions-chapter-17-phases-and-phase-change30ps1
mastering-physics-solutions-chapter-17-phases-and-phase-change30ps2
mastering-physics-solutions-chapter-17-phases-and-phase-change30ps3

Chapter 17 Phases and Phase Changes Q.31P
What is the temperature of a gas of CO2 molecules whose rms speed is 329 m/s?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change31ps
mastering-physics-solutions-chapter-17-phases-and-phase-change31ps1

Chapter 17 Phases and Phase Changes Q.32P
The rms speed of a sample of gas is increased by 1 %. (a) What is the percent change in the temperature of the gas? (b) What is the percent change in the pressure of the gas, assuming its volume is held constant?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change32ps

Chapter 17 Phases and Phase Changes Q.33P
Enriching Uranium In naturally occurring uranium atoms, 99.3% are 238U (atomic mass = 238 u, where u = 1.6605 × 10−27 kg) and only 0.7% are 235U (atomic mass = 235 u). Uranium-fueled reactors require an enhanced proportion of 235U. Since both isotopes of uranium have identical chemical properties, they can be separated only by methods that depend on their differing masses. One such method is gaseous diffusion, in which uranium hexafluoride (UF6) gas diffuses through a series of porous barriers. The lighter 235UFfi molecules have a slightly higher rms speed at a given temperature than the heavier 238UF6 molecules, and this allows the two isotopes to be separated. Find the ratio of the rms speeds of the two isotopes at 230 °C.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change33ps

Chapter 17 Phases and Phase Changes Q.34P
A 350-mL spherical flask contains 0.075 mol of an ideal gas at a temperature of 293 K. What is the average force exerted on the walls of the flask by a single molecule?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change34ps
mastering-physics-solutions-chapter-17-phases-and-phase-change34ps1

Chapter 17 Phases and Phase Changes Q.35P
A brick has faces with the following dimensions: face 1 is 1 cm by 2 cm; face 2 is 2 cm by 3 cm; face 3 is 1 cm by 3 cm. On which face should the brick be placed if it is to have the smallest change in dimensions due to its own weight? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change35ps

Chapter 17 Phases and Phase Changes Q.36P
A hollow cylindrical rod (rod 1) and a solid cylindrical rod (rod 2) are made of the same material. The two rods have the same length and the same outer radius. If the same compressional force is applied to each rod, (a) is the change in length of rod 1 greater than, less than, or equal to the change in length of rod 2? (b) Choose the beat explanation from among the following:
I. The solid rod has the larger effective cross-sectional area, since the empty part of the hollow rod doesn’t resist compression. Therefore, the solid rod has the smaller change in length.
II. The rods have the same outer radius and hence the same cross-sectional area. As a result, their change in length is the same.
III. Tile walls of the hollow rod are hard and resist compression more than the uniform material in the solid rod. Therefore the hollow rod has the smaller change in length.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change36ps

Chapter 17 Phases and Phase Changes Q.37P
A rock climber hangs freely from a nylon rope that is 14 m long and has a diameter of 8.3 mm. If the rope stretches 4.6 cm, what is the mass of the climber?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change37ps
mastering-physics-solutions-chapter-17-phases-and-phase-change37ps1
mastering-physics-solutions-chapter-17-phases-and-phase-change37ps2
mastering-physics-solutions-chapter-17-phases-and-phase-change37ps3

Chapter 17 Phases and Phase Changes Q.38P
To stretch a relaxed biceps muscle 2.5 cm requires a force of 25 N. Find the Young’s modulus for the muscle tissue, assuming it to be a uniform cylinder of length 0.24 m and cross-sectional area 47 cm2.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change38ps

Chapter 17 Phases and Phase Changes Q.39P
mastering-physics-solutions-chapter-17-phases-and-phase-change39p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change39ps

Chapter 17 Phases and Phase Changes Q.40P
The Marianas Trench The deepest place in all the oceans is the Marianas Trench, where the depth is 10.9 Km and the pressure is 1.10 × 108 Pa. If acopper ball 15.0 cm in diameter is taken to the bottom of the trench, by how much does its volume decrease?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change40ps
mastering-physics-solutions-chapter-17-phases-and-phase-change40ps1

Chapter 17 Phases and Phase Changes Q.41P
mastering-physics-solutions-chapter-17-phases-and-phase-change41p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change41ps

Chapter 17 Phases and Phase Changes Q.42P
A steel wire 4.7 m long stretches0.11 cm when it is given a tension of 360 N. (a) What is the diameter of the wire? (b) If it is desired that the stretch be less than 0.11 cm, should its diameter be increased or decreased? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change42ps
mastering-physics-solutions-chapter-17-phases-and-phase-change42ps1

Chapter 17 Phases and Phase Changes Q.43P
Spiderweb An orb weaver spider with a mass of 0.26 g hangs vertically by one of its threads. The thread has a Young’s modulus of 4.7 × 109N/m2 and a radius of 9.8 × 10−6 m. (a) What is the fractional increase inthe thread’s length caused by the spider? (b) Suppose a 76-kg person hangs verticallyfrom a nylon rope. What radius must the rope haveif its fractional increase in length is to be the same as that of the spider’s thread?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change43ps
mastering-physics-solutions-chapter-17-phases-and-phase-change43ps1

Chapter 17 Phases and Phase Changes Q.44P
Two rods of equal length (0.55 m.) and diameter (1.7 cm) arc placed end to end. One rod is aluminum, the other is brass. If a compressive force of 8400 N is applied to the rods, (a) how much does their combined length decrease? (b) Which of the rods changes its length by the greatest amount? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change44ps
mastering-physics-solutions-chapter-17-phases-and-phase-change44ps1
mastering-physics-solutions-chapter-17-phases-and-phase-change44ps2

Chapter 17 Phases and Phase Changes Q.45P
A piano wire 0.82 m long and 0.93 mm in diameter is fixed on one end. The other end is wrapped around a timing peg 3.5 mm in diameter. Initially the* wire, whose Young’s modulus is 2.4 × 1010 N/m2, has a tension of 14 N. Find the tension in the wire after the tuning peg has been turned through one complete revolution.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change45ps
mastering-physics-solutions-chapter-17-phases-and-phase-change45ps1

Chapter 17 Phases and Phase Changes Q.46P
The formation of ice from water is accompanied by which of the following: (a) an absorption of heat by the water; (b) an increase in tempera ture; (c) a decrease in volume; (d) a removal of heat from the water; (e) a decrease in temperature?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change46ps

Chapter 17 Phases and Phase Changes Q.47P
mastering-physics-solutions-chapter-17-phases-and-phase-change47p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change47ps

Chapter 17 Phases and Phase Changes Q.48P
Using the vapor-pressure curve given m Figure 17-26, find the temperature at which water boils when the pressure is 1.5 kPa.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change48ps

Chapter 17 Phases and Phase Changes Q.49P
mastering-physics-solutions-chapter-17-phases-and-phase-change49p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change49ps

Chapter 17 Phases and Phase Changes Q.50P
mastering-physics-solutions-chapter-17-phases-and-phase-change50p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change50ps

Chapter 17 Phases and Phase Changes Q.51P
mastering-physics-solutions-chapter-17-phases-and-phase-change51p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change51ps

Chapter 17 Phases and Phase Changes Q.52P
mastering-physics-solutions-chapter-17-phases-and-phase-change52p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change52ps

Chapter 17 Phases and Phase Changes Q.53P
mastering-physics-solutions-chapter-17-phases-and-phase-change53p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change53ps

Chapter 17 Phases and Phase Changes Q.54P
mastering-physics-solutions-chapter-17-phases-and-phase-change54p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change54ps

Chapter 17 Phases and Phase Changes Q.55P
mastering-physics-solutions-chapter-17-phases-and-phase-change55p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change55pss

Chapter 17 Phases and Phase Changes Q.56P
CE Four liquids are at their freezing temperature. Heat is now removed from each of the liquids until it becomes completely solidified. The amount of heat that must be removed, Q, and the mass, m, of each of the liquids are as follows: liquid A, Q = 33,500 J, m = 0.100 kg; liquid B, Q = 166,000J, m = 0.500 kg; liquid Ç, Q = 31,500 J, m = 0.250 kg; liquid D, Q = 5400J, m = 0.0500 kg. Rank these liquids in order of increasing latent heat of fusion. Indicate ties where appropriate.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change56ps
mastering-physics-solutions-chapter-17-phases-and-phase-change56ps1

Chapter 17 Phases and Phase Changes Q.57P
How much heat must be removed from 0.96 kg of water at 0 °C to make ice cubes at 0 °C?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change57ps

Chapter 17 Phases and Phase Changes Q.58P
A heat transfer of 9.5 × 10s J is required to convert a block of ice at −15 °C to water at 15 °C. What was the mass of the block of ice?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change58ps
mastering-physics-solutions-chapter-17-phases-and-phase-change58ps1

Chapter 17 Phases and Phase Changes Q.59P
How much heat must be added to 1.75 kg of copper to change ‘ it from a solid at 1358 K to a liquid at 1358 K?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change59ps

Chapter 17 Phases and Phase Changes Q.60P
IP A 1.1-kg block of ice is initially at a temperature of −50 °C. (a) If 5.2 × 105 J of heat are added to the ice, what is the final temperature of the system? Find the amount of ice, if any, that remains, (b) Suppose the amount of heat added to the ice block is doubled. By what factor must the mass of the ice be increased if the system is to have the same final temperature? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change60ps
mastering-physics-solutions-chapter-17-phases-and-phase-change60ps1
mastering-physics-solutions-chapter-17-phases-and-phase-change60ps2

Chapter 17 Phases and Phase Changes Q.61P
Referring to the previous problem, suppose the amount ‘ of heat added to the block of ice is reduced by a factor of 2 to 2.6 × 105 J. Note that this amount of heat is still sufficient to melt at ieast some of the ice. (a) Do you expect the temperature increase in this case to be one-half that found in the previous problem? Explain, (b) What is the final temperature of the system in this case? Find the amount of ice, if any, that remains.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change61ps
mastering-physics-solutions-chapter-17-phases-and-phase-change61ps1

Chapter 17 Phases and Phase Changes Q.62P
Figure 17-21 shows a temperature-versus-heat plot for 1.000 kg of water, (a) Calculate the heat corresponding to the points A, B, C, and D. (b) Calculate the slope of the line from point B to point C. Show that this slope is equal to 1/c, where c is the specific heat of liquid water.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change62ps
mastering-physics-solutions-chapter-17-phases-and-phase-change62ps1
mastering-physics-solutions-chapter-17-phases-and-phase-change62ps2

Chapter 17 Phases and Phase Changes Q.63P
Suppose the 1.000 kg of water in Figure 17-21 starts at point A at time zero. Heat is added to this system at the rate of 12,250 J/s. How long does it take for the system to reach (a) point B, (b) point C, and (c) point D? (d) Describe the physical state of the system at time t = 63.00 s.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change63ps
mastering-physics-solutions-chapter-17-phases-and-phase-change63ps1
mastering-physics-solutions-chapter-17-phases-and-phase-change63ps2

Chapter 17 Phases and Phase Changes Q.64P
Figure 17-22 shows a temperature-versus-heat plot for 0.550 kg of water, (a) Calculate the slope of the line from point A to point B. Show that the slope is equal to “1/mc, where c is the specific heat of ice. (b) Calculate the slope of the line from point C to point D. Show that the slope is equal to 1/mc, where c is the specific heat of liquid water.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change64ps
mastering-physics-solutions-chapter-17-phases-and-phase-change64ps1

Chapter 17 Phases and Phase Changes Q.65P
In Conceptual Checkpoint 17-5 we pointed out that steam can cause more serious burns than water at the same temperature. Here we examine this effect quantitatively, noting that flesh becomes badly damaged when its temperature reaches 50.0 °C. (a) Calculate the heat released as 12.5 g of liquid water at 100 °C is cooled to 50.0 °C. (b) Calculate the heat released when 12.5 g of steam at 100 °C is condensed and cooled to 50.0 °C. (c) Find the mass of flesh that can be heated from 37,0 °C (normal body temperature) to 50.0 °C for the cases considered in parts (a) and (b). (The average specific heat of flesh is 3500J/kg · K.)
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change65ps
mastering-physics-solutions-chapter-17-phases-and-phase-change65ps1
mastering-physics-solutions-chapter-17-phases-and-phase-change65ps2

Chapter 17 Phases and Phase Changes Q.66P
When you go out to your car one cold whiter morning you discover a 0.58-cm-tliick layer of ice on the windshield, which has an area of 1.6 m2. Tf the temperature of the ice is −2.0 °C, and its density is 917 kg/m3 find the heat required to melt all the ice.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change66ps
mastering-physics-solutions-chapter-17-phases-and-phase-change66ps1
mastering-physics-solutions-chapter-17-phases-and-phase-change66ps2

Chapter 17 Phases and Phase Changes Q.67P
A large punch bowl holds 3.99 kg of lemonade (which is essentially water) at 20.5 °C. A 0.0550-kg ice cube at -10.2 °C is placed in the lemonade. What is the final tempera ture of the system, and the amount of ice (if any) remaining? Ignore any heat exchange with the bowl or the surroundings.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change67ps
mastering-physics-solutions-chapter-17-phases-and-phase-change67ps1

Chapter 17 Phases and Phase Changes Q.68P
A 155-g aluminum cylinder is removed from a liquid nitrogen bath, where it has been cooled to −196 °C. The cylinder is immediately placed in an insulated cup containing 80.0 g of water at 15.0 °C. What is the equilibrium temperature of this system? If your answer is 0 °C, determine the amount of water thathas frozen. The average specific heat of aluminum over this temperature range is 653 J/(kg · K).
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change68ps
mastering-physics-solutions-chapter-17-phases-and-phase-change68ps1

Chapter 17 Phases and Phase Changes Q.69P
An 825-g iron block is heated to 352 °C and placed in an insulated container (of negligible heat capacity) containing 40.0 g of water at 20.0 °C. What is the equilibrium tempera hare of this system? If your answer is 100 °C, determine the amount of water that has vaporized. The average specific heat of iron over this temperature range is 560 J/(kg · K).
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change69ps
mastering-physics-solutions-chapter-17-phases-and-phase-change69ps1
mastering-physics-solutions-chapter-17-phases-and-phase-change69ps2
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mastering-physics-solutions-chapter-17-phases-and-phase-change69ps4

Chapter 17 Phases and Phase Changes Q.70P
IP A 35-g ice cube at 0.0 °C is added to 110 g of water in a 62-g aluminum cup. The cup and the water have an initial temperature of 23 °C. (a) Find the equilibrium temperature of the cup and its contents, (b) Suppose the aluminum cup is replaced with one of equal mass made from silver. Is the equilibrium temperature with the silver cup greater than, less than, or the same as with the aluminum cup? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change70ps
mastering-physics-solutions-chapter-17-phases-and-phase-change70ps1

Chapter 17 Phases and Phase Changes Q.71P
A 48-g block of copper at-12 °C is added to 110 g of water in a 75-g aluminum cup. The cup and the water have an initial temperature of 4.1 °C. (a) Find the equilibrium temperature of the cup and its contents, (b) What mass of ice, if any, is present when the system reaches equilibrium?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change71ps
mastering-physics-solutions-chapter-17-phases-and-phase-change71ps1
mastering-physics-solutions-chapter-17-phases-and-phase-change71ps2

Chapter 17 Phases and Phase Changes Q.72P
A 0.075-kg ice cube at 0.0 °C is dropped into a Styrofoam cup holding 0.33 kg of water at 1.4 °C. (a) Find the final temperature of the system and the amount of ice (if any) remaining. Assume the cup and the surroundings can be ignored, (b) Find the initial temperature of the water that would be enough to jus/ barely melt all of the ice.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change72ps
mastering-physics-solutions-chapter-17-phases-and-phase-change72ps1

Chapter 17 Phases and Phase Changes Q.73P
To help keep her barn warm on cold days, a farmer stores 865 kg of warm water in the barn. How many hours would a 2.00-kilowatt electric heater have to operate to provide the same amount of heat as is given off by the water as it cools from 20.0 °C to 0 °C and then freezes at 0 °C?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change73ps
mastering-physics-solutions-chapter-17-phases-and-phase-change73ps1

Chapter 17 Phases and Phase Changes Q.74GP
Plastic bubble wrap is used as a protective packing material. Ts the bubble wrap more effective on a cold day or on a warm day? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change74ps

Chapter 17 Phases and Phase Changes Q.75GP
Two adjacent rooms in a hotel are equal in size and connected by an open door. Room 1 is warmer than room 2. Which room contains more air? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change75ps

Chapter 17 Phases and Phase Changes Q.76GP
As you go up in altitude, do you expect the ratio of oxygen to nitrogen in the atmosphere to increase, decrease; or stay the same? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change76ps

Chapter 17 Phases and Phase Changes Q.77GP
Suppose the Celsius temperature of an ideal gas is doubled from 100 °C to 200 °C. (a) Docs the average kinetic energy of the molecules in this gas increase by a factor-that is greater than, less than, or equal to 2? (b) Choose the best explanation from among the following:
I. Changing the temperature from 100 °C to 200 °C goes beyond the boiling point, which will increase the kinetic energy by more than a factor of 2.
II. The average kinetic energy is directly proportional to the temperature, so doubling the temperature doubles the kinetic energy.
III. Doubling the Celsius temperature from 100 °C to 200 °C changes the Kelvin temperature from 373.15 K to 473.15 K, which is an increase oF less than a factor of 2.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change77ps

Chapter 17 Phases and Phase Changes Q.78GP
Suppose the absolute temperature of an ideal gas is doubled from 100 K to 200 K. (a) Does the average speed of the molecules in this gas increase by a factor that is greater than, less than, or equal to 2? (b) Choose the beat explanation from among the following:
I. Doubling the Kelvin temperature doubles the average kinetic energy, but this implies an increase in the average speed by a factor of , which is less than 2.
II. The Kelvin temperature is the one we use in the ideal-gas law, and therefore doubling it also doubles the average speed of the molecules.
III. The change in average speed depends on the mass of the molecules in the gas, and hence doubling the Kelvin temperature generally results in an increase in speed that is greater than a factor of 2.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change78ps

Chapter 17 Phases and Phase Changes Q.79GP
Largest Raindrops Atmospheric scientists studying clouds in the Marshall Islands have observed what they believe to be the world’s largest raindrops, with a radius of 0.52 cm. Flow many molecules are in these monster drops?
Solution:
Mass of rain drop = m
mastering-physics-solutions-chapter-17-phases-and-phase-change79ps

Chapter 17 Phases and Phase Changes Q.80GP
Coolin: Computers Researchers arc developing “heat exchangers” for laptop computers that take heat from the laptop—to keep it from being damaged by overheating—and use it to vaporize methanol. Given that 5100 J of heat is removed from the laptop when 4.6 g of methanol is vaporized, what is the latent heat of vaporization for methanol?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change80ps

Chapter 17 Phases and Phase Changes Q.81GP
Scuba Tanks In scuba diving circles, “an 80” refers to a scuba tank tha t holds 80 cubic feet öf ah’, a standard amount for recreational diving. Given that a scuba tank is a cylinder 2 feet long and half a foot in diameter, determine (a) the volume of a tank arid (b) the pressure in a tank when 80 cubic feet of air is compressed into its relatively small volume, (c) What is the mass of air ina tank that holds 80 cubic feet of air. Assume the temperature is 21 “C and that the walls of the tank are of negligible thickness.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change81ps
mastering-physics-solutions-chapter-17-phases-and-phase-change81ps1

Chapter 17 Phases and Phase Changes Q.82GP
A reaction vessel contains 8.06 g of H; and 64.0 g of O2 at a temperature of 125 °C and a pressure of 101 kPa. (a) What is the volume of the vessel? (b) The hydrogen and oxygen are now ignited by a spark, initiating the reaction 2 H2 + O2 → 2 H2O. This reaction consumes all the hydrogenand oxygen in the vessel. What is the pressure of the resulting water vapor when i t returns to its initial temperature of 125 °C?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change82ps
mastering-physics-solutions-chapter-17-phases-and-phase-change82ps1

Chapter 17 Phases and Phase Changes Q.83GP
A bicycle tire with a radius of 0.68 m has a gauge pressure of 42 lb/in2. Treating the tire as a hollow hoop with a cross-sectional area of 0.0028 m2, find the number of air molecules in the tire when its temperature is 24 °C.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change83ps
mastering-physics-solutions-chapter-17-phases-and-phase-change83ps1

Chapter 17 Phases and Phase Changes Q.84GP
Peter catches a 4.8-kg striped bass on a fishing line 0.54 mm in diameter and begins to reel it in. He fishes from a pier well above the water, and his fish hangs vertically from the line out of the water. The fishing line has a Young’s modulus of 5.1 × 109 N/m2. (a) What is the fractional increase in length of the fishing line if the fish is at rest? (b) What is the fractional increase in the fishing line’s length when the fish is pulled upward with a constant speed of 1.5 m/s? (c) What is the fractional increase in the fishing line’s length when the fish is pulled upward with a constant acceleration of 1.5 m/s2?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change84ps
mastering-physics-solutions-chapter-17-phases-and-phase-change84ps1

Chapter 17 Phases and Phase Changes Q.85GP
You use a steel socket wrench 28 cm long to loosen a rusty bolt, applying a force F at the end of the handle. The handle undergoes a shear deformation of 0.11 mm. (a) If the crosssectional area of the handle is 2.3 cm2, what is the magnitude of the applied force F? (b) If the cross-sectional area of the handle is doubled, by what factor does the shear deformation change? Explain.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change85ps

Chapter 17 Phases and Phase Changes Q.86GP
A steel ball (density = 7860 kg/m3) with a diameter of 6.4 cm is lied to an aluminum wire 82 cm long and 2.5 mm in diameter The ball is whirled about in a vertical circle with a tangential speed of 7.8 m/s at the top of the circle and 9.3 m/s at the bottom of the circle. Find the amount of stretch in the wire (a) at the top and (b) at the bottom of the circle.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change86ps
mastering-physics-solutions-chapter-17-phases-and-phase-change86ps1
mastering-physics-solutions-chapter-17-phases-and-phase-change86ps2

Chapter 17 Phases and Phase Changes Q.87GP
mastering-physics-solutions-chapter-17-phases-and-phase-change87p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change87ps
mastering-physics-solutions-chapter-17-phases-and-phase-change87ps1

Chapter 17 Phases and Phase Changes Q.88GP
Five molecules have the following speeds: 221 m/s, 301 m/s, 412 m/s, 44.0 m/s, and 182 m/s. (a) Find vav for these molecules, (b) Do you expect (v)av to be greater than, less than, or equal to (vav)2? Explain, (c) Calculate (02)av and comment on your results, (d) Calculate Orms and compare with vav.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change88ps
mastering-physics-solutions-chapter-17-phases-and-phase-change88ps1

Chapter 17 Phases and Phase Changes Q.89GP
(a) Find the amount of heat that must be extracted from 1.5 kg of steam at 110 °C to convert it to ice at 0.0 “C. (b) What speed would this 1 -5-kg block of ice have if its translational kinetic energy were equal to the thermal energy calculated in part (a)?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change89ps
mastering-physics-solutions-chapter-17-phases-and-phase-change89ps1

Chapter 17 Phases and Phase Changes Q.90GP
When water freezes into ice it expands in volume by 9.05%. Suppose a volume of water is in a household water pipe or a cavity in a rock. If the water freezes, what pressure must be exerted on it to keep its volume from expanding? (If the pipe or rock cannot supply this pressure, the pipe will burst and the rock will split.)
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change90ps

Chapter 17 Phases and Phase Changes Q.91GP
Suppose the 0.550 kg of ice in Figure 17-22 starts at point A. How much ice is left in the system after (a) 5.00 × 104J, (b) 1.00 × 105T, and (c) 1.50 × 105J of heat are added to the system?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change91ps
mastering-physics-solutions-chapter-17-phases-and-phase-change91ps1

Chapter 17 Phases and Phase Changes Q.92GP
Students on a spring break picnic bring a cooler that contains 5.1 kg of ice at 0.0 aC. The cooler has walls that are 3.8 cm thick and are made of Styrofoam, which has a thermal conductivity of 0.030 W/(m · C°). The surface area of the cooler is 1.5 m2, and it rests in the shade where the air temperature is 21 °C. (a) Find the rate at which heat flows into the cooler, (b) How long does it take for the ice in the cooler to melt?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change92ps
mastering-physics-solutions-chapter-17-phases-and-phase-change92ps1

Chapter 17 Phases and Phase Changes Q.93GP
A 5.5-kg block of ice a t −1.5 “C slides on a horizontal surface with a coefficient of kinetic friction equal to 0.062. The initial speed of the block is 6.9 m/s and its final speed is 5.5 m/s. Assuming that all the energy dissipated by kinetic friction goes into melting a small mass m of the ice, and tha t the rest of the ice block remains at −1.5 °C, determine the value of m.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change93ps
mastering-physics-solutions-chapter-17-phases-and-phase-change93ps1

Chapter 17 Phases and Phase Changes Q.94GP
mastering-physics-solutions-chapter-17-phases-and-phase-change94p
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change94ps
mastering-physics-solutions-chapter-17-phases-and-phase-change94ps1

Chapter 17 Phases and Phase Changes Q.95PP
The American naturalist Charles William Beebe (1877-1962) set a world record in 1934 when he and Otis Barton (1899-1992) made a dive to a depth of 923 m below the surface of the ocean. The dive was made just 10 miles from Nonsuch Island, off the coast of Bermuda, in a device known as the bathysphere, designed and built by Barton. The bathysphere was basically a steel sphere 4.75 ft in diameter with three small ports made of fused quartz. Lowered in to the ocean on a steel cable whose radius was 1.85 cm, the bathysphere also carried bottles of oxygen, chemicals to absorb carbon dioxide, and a telephone line to the surface.
mastering-physics-solutions-chapter-17-phases-and-phase-change95p
Charles William Beebe (left) and Otis Barton with the bathysphere in 1934. Beebe was fascinated by the new forms of life he and Barton encountered on their numerous dives. At one point he saw a “creature, several feet long, dart toward the window, turn sideways and—explode. At the flash, which was so strong that it illumined my face … I saw the great red shrimp and the outpouring fluid of flame.” No wonder he considered the ocean depths to be “a world as strange as that of Mars.”
The dives were not without their risks, however. It was not uncommon, for example, to have the bathysphere return to the surface partially filled with water after a window seal failed. On one deep dive, water began to steamrapidly into the sphere. Beebe quickly called to the surface and asked—not to be raised quickly—but to be lowered more rapidly, in the hope that increasing water pressure would force the leaking window into its seals to stop the leak. It worked, showing that Beebe was not only an exceptional naturalist, but also a cool-headed scientist with a good knowledge of basic physics!
What pressure did the bathysphere experience at its record depth?
A. 9.37 atm
B. 89.6 atm
C. 91.9 atm
D. 92.9 atm
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change95ps
mastering-physics-solutions-chapter-17-phases-and-phase-change95ps1

Chapter 17 Phases and Phase Changes Q.96PP
The American naturalist Charles William Beebe (1877-1962) set a world record in 1934 when he and Otis Barton (1899-1992) made a dive to a depth of 923 m below the surface of the ocean. The dive was made just 10 miles from Nonsuch Island, off the coast of Bermuda, in a device known as the bathysphere, designed and built by Barton. The bathysphere was basically a steel sphere 4.75 ft in diameter with three small ports made of fused quartz. Lowered in to the ocean on a steel cable whose radius was 1.85 cm, the bathysphere also carried bottles of oxygen, chemicals to absorb carbon dioxide, and a telephone line to the surface.
mastering-physics-solutions-chapter-17-phases-and-phase-change96p
Charles William Beebe (left) and Otis Barton with the bathysphere in 1934.
Beebe was fascinated by the new forms of life he and Barton encountered on their numerous dives. At one point he saw a “creature, several feet long, dart toward the window, turn sideways and—explode. At the flash, which was so strong that it illumined my face … I saw the great red shrimp and the outpouring fluid of flame.” No wonder he considered the ocean depths to be “a world as strange as that of Mars.”
The dives were not without their risks, however. It was not uncommon, for example, to have the bathysphere return to the surface partially filled with water after a window seal failed. On one deep dive, water began to steamrapidly into the sphere. Beebe quickly called to the surface and asked—not to be raised quickly—but to be lowered more rapidly, in the hope that increasing water pressure would force the leaking window into its seals to stop the leak. It worked, showing that Beebe was not only an exceptional naturalist, but also a cool-headed scientist with a good knowledge of basic physics!
How much did the volume of the bathysphere decrease as it was lowered to its record depth? (For simplicity, treat the bathysphere as a solid metal sphere.)
A. 9.0 × 10−5 m3
B. 9.2 × 10”5 m3
C. 1.1 × 10−4 m3
D. 3.8 × 10−4 m3
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change96ps
mastering-physics-solutions-chapter-17-phases-and-phase-change96ps1

Chapter 17 Phases and Phase Changes Q.97PP
The American naturalist Charles William Beebe (1877-1962) set a world record in 1934 when he and Otis Barton (1899-1992) made a dive to a depth of 923 m below the surface of the ocean. The dive was made just 10 miles from Nonsuch Island, off the coast of Bermuda, in a device known as the bathysphere, designed and built by Barton. The bathysphere was basically a steel sphere 4.75 ft in diameter with three small ports made of fused quartz. Lowered in to the ocean on a steel cable whose radius was 1.85 cm, the bathysphere also carried bottles of oxygen, chemicals to absorb carbon dioxide, and a telephone line to the surface.
mastering-physics-solutions-chapter-17-phases-and-phase-change96p
Charles William Beebe (left) and Otis Barton with the bathysphere in 1934.
Beebe was fascinated by the new forms of life he and Barton encountered on their numerous dives. At one point he saw a “creature, several feet long, dart toward the window, turn sideways and—explode. At the flash, which was so strong that it illumined my face … I saw the great red shrimp and the outpouring fluid of flame.” No wonder he considered the ocean depths to be “a world as strange as that of Mars.”
The dives were not without their risks, however. It was not uncommon, for example, to have the bathysphere return to the surface partially filled with water after a window seal failed. On one deep dive, water began to steamrapidly into the sphere. Beebe quickly called to the surface and asked—not to be raised quickly—but to be lowered more rapidly, in the hope that increasing water pressure would force the leaking window into its seals to stop the leak. It worked, showing that Beebe was not only an exceptional naturalist, but also a cool-headed scientist with a good knowledge of basic physics!
How much did the volume of the bathysphere decrease as it was lowered to its record depth? (For simplicity, treat the bathysphere as a solid metal sphere.)
A. 9.0 × 10−5 m3
B. 9.2 × 10”5 m3
C. 1.1 × 10−4 m3
D. 3.8 × 10−4 m3
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change97ps
mastering-physics-solutions-chapter-17-phases-and-phase-change97ps1

Chapter 17 Phases and Phase Changes Q.98PP
The American naturalist Charles William Beebe (1877-1962) set a world record in 1934 when he and Otis Barton (1899-1992) made a dive to a depth of 923 m below the surface of the ocean. The dive was made just 10 miles from Nonsuch Island, off the coast of Bermuda, in a device known as the bathysphere, designed and built by Barton. The bathysphere was basically a steel sphere 4.75 ft in diameter with three small ports made of fused quartz. Lowered in to the ocean on a steel cable whose radius was 1.85 cm, the bathysphere also carried bottles of oxygen, chemicals to absorb carbon dioxide, and a telephone line to the surface.
mastering-physics-solutions-chapter-17-phases-and-phase-change96p
Charles William Beebe (left) and Otis Barton with the bathysphere in 1934. Beebe was fascinated by the new forms of life he and Barton encountered on their numerous dives. At one point he saw a “creature, several feet long, dart toward the window, turn sideways and—explode. At the flash, which was so strong that it illumined my face … I saw the great red shrimp and the outpouring fluid of flame.” No wonder he considered the ocean depths to be “a world as strange as that of Mars.”
The dives were not without their risks, however. It was not uncommon, for example, to have the bathysphere return to the surface partially filled with water after a window seal failed. On one deep dive, water began to steamrapidly into the sphere. Beebe quickly called to the surface and asked—not to be raised quickly—but to be lowered more rapidly, in the hope that increasing water pressure would force the leaking window into its seals to stop the leak. It worked, showing that Beebe was not only an exceptional naturalist, but also a cool-headed scientist with a good knowledge of basic physics!
Suppose the bathysphere and its occupants had a combined mass of 12,700 kg. How much did the cable stretch when the bathysphere was at a depth of 923 m? (Neglect the weight of the cable itself, but include the effects of the bathysphere’s buoyancy.)
A. 47 cm
B. 48 cm
C. 52 cm
D. 53 cm
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change98ps
mastering-physics-solutions-chapter-17-phases-and-phase-change98ps1
mastering-physics-solutions-chapter-17-phases-and-phase-change98ps2

Chapter 17 Phases and Phase Changes Q.99IP
(a) Find the final temperature of the system if two 0.0450-kg ice cubes are added to the warm lemonade. The temperature of the ice is 0 °C; the temperature and mass of the warm lemonade are 20.0 °C and 3.95 kg, respectively. (b) How many 0.0450-kg ice cubes at 0 °C must be added to the original warm lemonade if the final temperature of the system is to be at least as cold as 15.0 °C?
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change99ps

Chapter 17 Phases and Phase Changes Q.100IP
(a) Find the final temperature of the system if a single 0.045-kg ice cube at 0 °C is added to 2.00 kg of lemonade at 1.00 °C. (b) What initial temperature of the lemonade will be just high enough to melt all of the ice in a single ice cube and result in an equilibrium tempera ture of 0 °C? The mass of the lemonade is 2.00 kg and the temperature of the ice cube is 0 °C.
Solution:
mastering-physics-solutions-chapter-17-phases-and-phase-change100ps
mastering-physics-solutions-chapter-17-phases-and-phase-change100ps1