Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines (Including Parallel Lines)

Selina Publishers Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines (Including Parallel Lines)

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APlusTopper.com provides step by step solutions for Selina Concise ICSE Solutions for Class 6 Mathematics. You can download the Selina Concise Mathematics ICSE Solutions for Class 6 with Free PDF download option. Selina Publishers Concise Mathematics for Class 6 ICSE Solutions all questions are solved and explained by expert mathematic teachers as per ICSE board guidelines.

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IMPORTANT POINTS
1. Property : When two straight lines intersect:
(i) sum of each pair of adjacent angles is always 180°.
(ii) vertically opposite angles are always equal. .
2. Property : If the sum of two adjacent angles is 180°, their exterior arms are always in the same straight line.
Conversely, if the exterior arms of two adjacent angles are in the same straight line ; the sum of angles is always 180°
3. Parallel Lines : Two straight lines are said to be parallel, if they do not meet anywhere, no matter how much they are produced in either direction.
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4. Concepts of Transversal Lines : When a line cuts two or more lines (parallel or non-parallel); it is called a transversal line or simply, a transversal. In each of the following figures : PQ is a transversal line.
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5. Angles formed by two lines and their transversal line : When a transversal cuts two parallel or nonparallel lines; eight (8) angles are formed which are marked 1 to 8 in the adjoining diagram.
These angles can further he distinguished, as given below:
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(i) Exterior Angles : Angles marked 1, 2, 7 and 8 are exterior angles.
(ii) Interior Angles : Angles marked 3, 4, 5 and 6 are interior angles.
(iii) Exterior Alternates Angles : Two pairs of exterior alternate angles are marked as : 2 and 8 ; and, 1 and 7.
(iv) Interior Alternate Angles : Two pairs of interior alternate are marked as : 3 and 5 ; and 4 and 6. In general, interior alternate angles are simply called as alternate angles only.
(v) Corresponding Angles : Four pairs of corresponding angles are marked as : 1 and 5 ; 2 and 6 ; 3 and 7 ; and 4 and 8.
(vi) Co-interior or Conjoined or Allied Angles : Two pairs of co-interior or allied angles are marked as : 3 and 6 ; and 4 and 5.
(vii) Exterior Allied Angles : Two pairs of exterior allied angles are marked as : 2 and 7 ; and 1 and 8.

Properties of Angles and Lines Exercise 25A – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
Two straight lines AB and CD intersect each other at a point O and angle AOC = 50° ; find :
(i) angle BOD
(ii) ∠AOD
(iii) ∠BOC
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Solution:
(i)∠BOD = ∠AOC
(Vertically opposite angles are equal)
∴ ∠BOD =50°
(ii) ∠AOD
∠AOD + ∠BOD = 180°
∠AOD + 50° = 180° [From (i)]
∠AOD = 180°-50°
∠AOD = 130°
(iii) ∠BOC = ∠AOD
(Vertically opposite angles are equal)
∴ ∠BOC =130°

Question 2.
The adjoining figure, shows two straight lines AB and CD intersecting at point P. If ∠BPC = 4x – 5° and ∠APD = 3x + 15° ; find :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 5
(i) the value of x.
(ii) ∠APD
(iii) ∠BPD
(iv) ∠BPC
Solution:

Question 3.
The given diagram, shows two adjacent angles AOB and AOC, whose exterior sides are along the same straight line. Find the value of x.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 6
Solution:
Since, the exterior arms of the adjacent angles are in a straight line ; the adjacent angles are supplementary
∴ ∠AOB + ∠AOC = 180°
⇒ 68° + 3x – 20° = 180°
⇒ 3x = 180° + 20° – 68°
⇒ 3x = 200° – 68° ⇒ 3x =132°
x = \(\frac { 132 }{ 3 }\)° = 44°

Question 4.
Each figure given below shows a pair of adjacent angles AOB and BOC. Find whether or not the exterior arms OA and OC are in the same straight line.
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Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 8
Solution:
(i) ∠AOB + ∠COB = 180°
Since, the sum of adjacent angles AOB and COB = 180°
(90° -x) + (90°+ x) = 180°
⇒ 90°-x + 90° + x = 180°
⇒ 180° =180°
The exterior arms. OA and OC are in the same straight line.
(ii) ∠AOB + ∠BOC = 97° + 83° = 180°
⇒ The sum of adjacent angles AOB and BOC is 180°.
∴ The exterior arms OA and OC are in the same straight line.
(iii)∠COB + ∠AOB = 88° + 112° = 200° ; which is not 180°.
⇒ The exterior amis OA and OC are not in the same straight line.

Question 5.
A line segment AP stands at point P of a straight line BC such that ∠APB = 5x – 40° and ∠APC = .x+ 10°; find the value of x and angle APB.
Solution:
AP stands on BC at P and
∠APB = 5x – 40°, ∠APC = x + 10°
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 9
(i) ∵APE is a straight line
∠APB + ∠APC = 180°
⇒ 5x – 40° + x + 10° = 180°
⇒ 6x-30°= 180°
⇒6x= 180° + 30° = 210°
x = \(\frac { 210 }{ 6 }\)° = 35°
(ii) and ∠APB = 5x – 40° = 5 x 35° – 40°
= 175 ° – 140° = 135°

Properties of Angles and Lines Exercise 25B – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
Identify the pair of angles in each of the figure given below :
adjacent angles, vertically opposite angles, interior alternate angles, corresponding angles or exterior alternate angles.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 10
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 11
Solution:
(a) (i) Adjacent angles
(ii) Alternate exterior angles
(iii) Interior alternate angles
(iv) Corresponding angles
(v) Allied angles
(b) (i) Alternate interior angles
(ii) Corresponding angles
(iii) Alternate exterior angles
(iv) Corresponding angles
(v) Allied angles.
(c) (i) Corresponding
(ii) Alternate exterior
(iii) Alternate interior
(iv) Alternate interior
(v) Alternate exterior
(vi) Vertically opposite

Question 2.
Each figure given below shows a pair of parallel lines cut by a transversal For each case, find a and b, giving reasons.
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Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 13
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Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 16

Question 3.
If ∠1 = 120°, find the measures of : ∠2, ∠3, ∠4, ∠5, ∠6, ∠7 and ∠8. Give reasons.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 17
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 18

Question 4.
In the figure given below, find the measure of the angles denoted by x,y, z,p,q and r.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 19
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 20

Question 5.
Using the given figure, fill in the blanks.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 21
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 22

Question 6.
In the given figure, find the anlges shown by x,y, z and w. Give reasons.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 23
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 24

Question 7.
Find a, b, c and d in the figure given below :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 25
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 26

Question 8.
Find x, y and z in the figure given below :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 27
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 28

Properties of Angles and Lines Exercise 25C – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
In your note-book copy the following angles using ruler and a pair compass only.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 29
Solution:
(i) Steps of Construction :
1. At point Q, draw line QR = OB.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 30
2. With O as centre, draw an arc of any suitable radius, to cut the arms of the angle at C and D.
3. With Q as centre, draw the arc of the same size as drawn for C and D. Let this arc cuts line QR at point T.
4. In your compasses, take the distance equal to distance between C and D; and then with T as centre, draw an arc which cuts the earlier arc at S.
5. Join QS and produce upto a suitable point P. ∠PQR so obtained, is the angle equal to the given ∠AOB.
(ii) Steps of Construction :
1. A t point E, draw line EF.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 31
2. With E as centre, draw an arc of any suitable radius, to cut the amis of the angle at C and D.
3. With Q as centre, draw the arc of the same size as drawn for C and D. Let this arc cuts line QR at point T.
4. In your compasses, take the distance equal to distance between C and D ; and then with T as centre, draw an arc which cuts the earlier arc at S.
5. Join QS and produce upto a suitable point R ∠PQR, so obtained, is the angle equal to the given ∠DEE
(iii) Steps of Construction :
1. At point A draw line AB = QP
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 32
2. With Q as centre, draw an arc of any suitable radius, to cut the arms of the angle A + C and D.
3. With A as centre, draw the arc of the same size as drawn for C and D. Let this arc cuts line AB at D.
4. In your compasses, take the distance equal to distance between 7 and 5 ; and then with D as centre, draw an arc which cuts the earlier arc at E.
5. Join AE and produced upto a suitable point C. ∠BAC, so obtained is the angle equal to the given ∠PQR.

Question 2.
Construct the following angles, using ruler and a pair of compass only
(i) 60°
(ii) 90°
(iii) 45°
(iv) 30°
(v) 120°
(vi) 135°
(vii) 15°
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 33
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 34
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 35
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 36
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 37
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 38

Question 3.
Draw line AB = 6cm. Construct angle ABC = 60°. Then draw the bisector of angle ABC.
Solution:
Steps of Construction :
1. Draw a line segment AB = 6 cm.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 39
2. With the help of compass construct ∠CBA = 60°.
3. Bisect ∠CBA, with the help of compass, take any radius which meet line AB and BC at point E and F.
4. Now, with the help of compass take
radius more than \(\frac { 1 }{ 2 }\) of EF and draw two arcs from point E and F, which intersect both arcs at G, proceed BG toward D ∠DBA is bisector of ∠CBA.

Question 4.
Draw a line segment PQ = 8cm. Construct the perpendicular bisector of the line segment PQ. Let the perpendicular bisector drawn meet PQ at point R. Measure the lengths of PR and QR. Is PR = QR ?
Solution:
Steps of Construction :
1. With P and Q as centres, draw arcs on both sides of PQ with equal radii. The radius should be more than half the length of PQ.
2. Let these arcs cut each other at points R and RS
3. Join RS which cuts PQ at D.
Then RS = PQ Also ∠POR = 90°.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 40
Hence, the line segment RS is the perpendicular bisector of PQ as it bisects PQ at P and is also perpendicular to PQ. On measuring the lengths of PR = 4cm, QR = 4 cm
Since PR = QR, both are 4cm each
∴PR = QR.

Question 5.
Draw a line segment AB = 7cm. Mark a point Pon AB such that AP=3 cm. Draw perpendicular on to AB at point P.
Solution:
1. Draw a line segment AB = 7 cm.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 41
2. Out point from AB – AP =3cm
3. From point P, cut arc on out side of AB, E and F.
4. From pont E & F cut arcs on both side intersection each other at C & D.
5. Join point P, CD.
6. Which is the required perpendicular.

Question 6.
Draw a line segment AB = 6.5 cm. Locate a point P that is 5 cm from A and 4.6 cm from B. Through the point P, draw a perpendicular on to the line segment AB.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 42
Steps of Construction :
(i) Draw a line segment AB =6.5cm
(ii) With centre A and radius 5 cm, draw an arc and with centre B and radius 4.6 cm, draw another arc which intersects the first arc at P.
Then P is the required point.
(iii) With centre A and a suitable radius, draw an arc which intersect AB at E and F.
(iv) With centres E and F and radius greater than half of EF, draw the arcs which intersect each other at Q.
(v) Join PQ which intersect AB at D.
Then PD is perpendicular to AB.

Properties of Angles and Lines Exercise 25D – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
Draw a line segment OA = 5 cm. Use set-square to construct angle AOB = 60°, such that OB = 3 cm. Join A and B ; then measure the length ofAB.
Solution:
Measuring the length of AB = 4.4cm. (approximately)
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 43

Question 2.
Draw a line segment OP = 8cm. Use set-square to construct ∠POQ = 90°; such that OQ = 6 cm. Join P and Q; then measure the length of PQ.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 44

Question 3.
Draw ∠ABC = 120°. Bisect the angle using ruler and compasses. Measure each angle so obtained and check whether or not the new angles obtained on bisecting ∠ABC are equal.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 45

Question 4.
Draw ∠PQR = 75° by using set- squares. On PQ mark a point M such that MQ = 3 cm. On QR mark a point N such that QN = 4 cm. Join M and N. Measure the length of MN.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 46

Properties of Angles and Lines Revision Exercise – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
In the following figures, AB is parallel to CD; find the values of angles x, y and z :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 47
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 48
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 49
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 50

Question 2.
In each of the following figures, BA is parallel to CD. Find the angles a, b and c:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 51
Solution:

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 53

Question 3.
In each of the following figures, PQ is parallel to RS. Find the angles a, b and c:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 54
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 55
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 56
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 57
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 58

Question 4.
Two straight lines are cut by a transversal. Are the corresponding angles always equal?
Solution:
If a transversal cuts two straight lines, their the corresponding angles are not equal unless the lines are not parallel. One in case of parallel lines, the corresponding angles are equal.

Question 5.
Two straight lines are cut by a transversal so that the co-interior angles are supplementary. Are the straight lines parallel ?
Solution:
A transversal intersects two straight lines and co-interior angles are supplementary
∴ By deflations, the lines will be parallel.

Question 6.
Two straight lines are cut by a transversal so that the co-interior angles are equal. What must be the measure of each interior angle to make the straight lines parallel to each other ?
Solution:
A transveral intersects two straight lines and co-interior angles are equal to each other,
∵ The two straight lines are parallel Their sum of co-interior angles = 180°
But both angles are equal
∴ Each angle will be \(\frac { 180 }{ 2 }\)° = 90°

Question 7.
In each case given below, find the value of x so that POQ is straight line
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 59
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 60
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 61
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 62
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 63

Question 8.
in each case, given below, draw perpendicular to AB from an exterior point P
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 64
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 65
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 66
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 67

Question 9.
Draw a line segment BC = 8 cm. Using set-squares, draw ∠CBA = 60° and ∠BCA = 75°. Measure the angle BAC. Also measure the lengths of AB and AC.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 68

Question 10.
Draw a line AB = 9 cm. Mark a point P in AB such that AP=5 cm. Through P draw (using set-square) perpendicular PQ = 3 cm. Measure BQ.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 69

Question 11.
Draw a line segment AB = 6 cm. Without using set squares, draw angle OAB = 60° and angle OBA = 90°. Measure angle AOB and write this measurement.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 70

Question 12.
Without using set squares, construct angle ABC = 60° in which AB = BC = 5 cm. Join A and C and measure the length of AC.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 25 Properties of Angles and Lines image - 71

 

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles (With their Types)

Selina Publishers Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles (With their Types)

ICSE SolutionsSelina ICSE SolutionsML Aggarwal Solutions

APlusTopper.com provides step by step solutions for Selina Concise ICSE Solutions for Class 6 Mathematics. You can download the Selina Concise Mathematics ICSE Solutions for Class 6 with Free PDF download option. Selina Publishers Concise Mathematics for Class 6 ICSE Solutions all questions are solved and explained by expert mathematic teachers as per ICSE board guidelines.

Selina Class 6 Maths ICSE SolutionsPhysicsChemistryBiologyGeographyHistory & Civics

IMPORTANT POINTS
1. Ray. A ray is a half-line: It has one end point and other end is open. It can not be measured like a line. Here, OA is a ray.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 1
From appoint, infinite numbers of rays can be drawn.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 2
2. Angle: When two rays meet at a point, then an angle is formed. Angle is measured in degrees with the help of an instrument known as a protractor.
The point where the two rays meet is called an initial point or vertex of the angle and the two rays which form the angle, are called the sides of the angle e.g., two rays OA and OB meet at O.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 3
∴ Angle AOB is formed. Vertex is always kept between the ends points.
The anlgle can be denotes as ∠AOB, or ∠BOA, here sign ‘∠’ denotes the angle.
The angle is also denoted with letters A, B, C etc. or numbers 1, 2, 3 etc. also.

3. Parts of an angl: Angle has three parts : Interior, exterior and the angle itself.
4. Comparison of Angles: Two angles can be compared with respect to their magnitude. Any angle of greater measure is greater.

5. Kinds of Angles : 
(i) Zero angle: When two rotating rays (sides of angles) coincide each other, then ∠ero angle is formed.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 4
(ii) Right angle: An angle of 90° is called a right angle.
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(iii) Straight Angle: An angle of 180° is called a straight angle.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 6
(iv) Complete Angle: When a ray completes a revolution on rotating it, then a complete angle is formed.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 7
(v) Acute angle : An angle less than 90° is called an acute angle.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 8
(vi) Obtuse angle : An angle greater than 90° and less than 180° is called an obtuse angle.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 56
(vii) Reflex Angle: An angle greater than the 180° and less than 360°
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 10
Note:
1 ° = 60 minutes (60′)
1′ = 60 seconds (60″)

6. Pairs of angles :
(i) Adjacent Angles: Two angles with same vertex and one common arm and the other arms lying in opposite sides of it are called adjacent angles, ∠AOB and ∠BOC are adjacent angles.
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(ii) Linear Pair: A linear pair is a pair of adjacent angles whose sum is equal to 180°. ∠AOB and ∠BOC are a linear pair as ∠AOB + ∠BOC = 180°.
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(iii) Complementary Angle: Two angles whose sum is 90° are called complementary angles. ∠ABC and ∠PQR are complementary angles as ∠ABC + ∠PQR = 30° + 60° = 90°.
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(iv) Supplementary Angles: Two angles whose sum is 180°, are called supplementary angles. ∠ABC and ∠PQR are supplementary angles, because
∠ABC + ∠PQR = 130° + 50° = 180°.
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(v) Vertically Opposite Angles: When two lines intersect each other, then the pairs of opposite angles so formed are called vertically opposite angles.
∠1 and ∠2 are vertically opposite angles. Similarly, ∠3 and ∠4 are vertically opposite angles.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 15

Angles Exercise 24A – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
For each angle given below, write the name of the vertex, the names of the arms and the name of the angle.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 16
Solution:
(i) In figure (i) O is the vertex, OA, OB are its arms and name of the angle is ∠AOB or∠BOA or simply ∠O.
(ii) In figure (ii) Q is the vertex, QP and QR its arms and the name of the angle is ∠PQR or ∠RQP or simply ∠Q.
(iii) In figure (iii), M is the vertex, MN and ML and its anus, and name of the angle is ∠LMN or ∠NML or simply ∠M.

P .Q . Name the angles marked by letters a, b, c, x and y.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 17

Solution:
a = AOE, b = ∠AOB, c = ∠BOC d = ∠COD e= ∠DOE

Question 2.
Name the points :
(i) in the interior of the angle PQR,
(ii) in the exterior of the angle PQR.
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Solution:
(i) a, b and x
(ii) d, m, n, s, and t.

Question 3.
In the given figure, figure out the number of angles formed within the arms OA and OE.
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Solution:
∠AOE, ∠AOD, ∠AOC, ∠AOB, ∠BOC ∠BOD, ∠BOE, ∠COD, ∠COE and ∠DOE.

Question 4.
Add :
(i) 29° 16′ 23″ and 8° 27′ 12″
(ii) 9° 45’56” and 73° 8′ 15″
(m) 56° 38′ and 27° 42’30”
(iv) 47° and 61° 17’4″
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 20

Question 5.
In the figure, given below name :
(i) three pairs of adjacent angles.
(ii) two acute angles,
(iii) two obtuse angles
(iv) two reflex angles.
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Solution:
(i) Three pairs of adjacent angles are
∠AOB and ∠BOC;
∠BOC and ∠COD;
∠COD and ∠DOA.
(ii) Two acute angles are
∠AOB and ∠AOD.
(iii) Two obtuse angles are
∠BOC and ∠COD.
(iv) Two reflex angles are
∠AOB and ∠COD.

Question 6.
In the given figure ; PQR is a straight line. If :
(i) ∠SQR = 75° ; find ∠PQS.
(ii) ∠PQS = 110°; find ∠RQS
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 22
Solution:
(i) From figure,
∠PQS + ∠SQR = 180° [Linear pair of angles]
⇒∠PQS + 75° = 180°
⇒ ∠PQS = 180°-75°
⇒ ∠PQS = 105°
(ii) From figure again,
∠PQS + ∠RQS = 180°
⇒ 110° + ∠RQS = 180°
∠RQS = 180°- 110°
∠RQS = 70°

Question 7.
In the given figure ; AOC-is a straight line. If angle AOB = 50°, angle AOE = 90° and angle COD = 25° ; find the measure of :
(i) angle BOC
(ii) angle EOD
(iii) obtuse angle BOD
(iv) reflex angle BOD
(v) reflex angle COE.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 23
Solution:
(i) ∠AOB + ∠BOC = 180° (Linear pairs of angle)
⇒ 50° +∠BOC = 180°
⇒ ∠BOC = 180° – 50° = 130°
⇒ ∠BOC = 130°
(ii) ∠EOD + ∠COD = 90° (∵AOE = 90°)
⇒ ∠EOD + 25° = 90°
⇒ ∠EOD + 25° = 90°
⇒ ∠EOD = 90° – 25°
⇒ ∠EOD = 65°
(iii) ∠BOD = ∠BOC + COD
= 130° + 25° = 155°
(iv) Reflex ∠BOD = 360° – ∠BOD
= 360°- 155° = 205°
(v) Reflex ∠COE = 360° – ∠COE
= 360° (∠COD + ∠EOD)
= 360° – (25° + 65°)
= 360° – 90° = 270°

Question 8.
In the given figure if :
(i) a = 130° ; find b.
(ii) b = 200 ; find a.
(iii) a = 5/3 right angle, find b
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 24
Solution:
(i) From figure, a + b = 360°
⇒ 130° + 6 = 360
⇒ 6 = 360°-130°
⇒ b = 230°
(ii) From figure,
a + b = 360°
⇒ a + 200° = 360°
⇒ a = 360° – 200°
⇒ a = 160°
(iii) Here, a= \(\frac { 5 }{ 3 }\) right angle
= \(\frac { 5 }{ 3 }\) x90° = 150°
a = 150°
Here, a + b = 360°
⇒ 150° + b = 360° (∵a = 150°)
⇒ b = 360° -150°
b = 210°

Question 9.
In the given diagram, ABC is a straight line.
(i) If x = 53°, find y.
(ii) If y =1\(\frac { 1 }{ 2 }\) right angles ; find x.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 25
Solution:
(i) From the figure,
∠ABD + ∠DBC = 180° (Linear pair of angles)
⇒ x+y=180°
⇒ 53°+y = 180° (∵ x = 53”)
⇒ y = 180° – 53°
⇒ y = 127°
(ii) From figure again,
x+y= 180°
1 + \(\frac { 3 }{ 2 }\) x 90 = 180°
⇒ x+1\(\frac { 1 }{ 2 }\) right angles = 180°
⇒ x+\(\frac { 3 }{ 2 }\) x90=180°
⇒ x + 135°= 180°
⇒ x= 180° – 135°
⇒ x = 45°

Question 10.
In the given figure, AOB is a straight line. Find the value ofx and also answer each of the following :
(i) ∠AOP = ……..
(ii) ∠BOP = ……..
(iii) which angle is obtuse ?
(iv) which angle is acute ?
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 26
Solution:
∠AOP = x + 30°
∠BOP = x – 30°
But ∠AOP + ∠BOP = 180° (∵ ∠AOB is a straight angle)
⇒ x + 30°+x-30° = 180°
⇒ 2x = 180°
⇒ x = 90°
(i) ∠AOP = x + 30° = 90° + 30° = 120°
(ii) ∠BOP = x- 30° = 90° – 30° = 60°
(iii) ∠AOP is an obtuse angle
(iv) ∠BOP is an acute angle

Question 11.
In the given figure, PQR is a straight line. Find x. Then complete the following:
(i) ∠AQB = ……..
(ii) ∠BQP = ……..
(iii) ∠AQR = …….
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 27
Solution:
PQR is a straight line
∠AQP=x + 20°
∠AQB = 2x + 10°
∠BQR = x – 10°
But ∠AQP + ∠AQB + ∠BQR = 180°
⇒ x + 20° + 2x + 10° + x-10°= 180°
⇒ 4x + 20°= 180°
⇒4x= 180°-20°= 160°
⇒ x = \(\frac { 160 }{ 4 }\)° = 40°
(i) ∠AQB = 2x + 10° = 2 x 40° + 10° = 80° + 10° = 90°
∠AQP = x + 2(T = 40° + 20° = 60°
∠BQR = x – 10° = 40° – 10° = 30°
(ii) ∠BQP = ∠AQP + ∠AQB = 60° + 90° = 150°
(iii) ∠AQR = ∠AQB + ∠BQR = 90° + 30° = 120°

Question 12.
In the given figure, lines AB and CD intersect at point O.
(i) Find the value of ∠a.
(ii) Name all the pairs of vertically opposite angles.
(iii) Name all the pairs of adjacent angles.
(iv) Name all the reflex angles formed and write the measure of each.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 28
Solution:
Two lines AB and CD intersect each other at O
∠AOC = 68°
(i) ∵ AOB is a line
∠AOC + ∠BOC = 180°
⇒ 68° + a = 180°
⇒ a= 180°-68° = 112°
(ii) ∠AOC and ∠BOD and ∠BOC and ∠AOD are the two pairs of vertically opposite angles .
(iii) ∠AOC and ∠BOC; ∠BOC and ∠BOD; ∠BOD and ∠DOA;
∠DOA and AOC are the pairs of adjacent angles
(iv) ∠BOC and ∠DOA are reflex angles and also ∠AOC and ∠BOD are also reflex angles
Ref. ∠BOC = 180° + 68° = 248°
Ref. ∠DOA = 180° + 68° = 248°
Ref. ∠AOC = 180° + 112° = 292°
and ref. ∠BOD =180° + 112° = 292°

Question 13.
In the given figure :
(i) If ∠AOB = 45°, ∠BOC = 30° and ∠AOD= 110°;
find : angles COD and BOD.
(ii) If ∠BOC = ∠DOC = 34° and ∠AOD = 120° ;
find : angle AOB and angle AOC.
(iii) If ∠AOB = ∠BOC = ∠COD = 38°
find : reflex angle AOC and reflex angle AOD.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 29
Solution:
(i) ∠COD = ∠AOD – ∠AOC
= ∠AOD – (∠AOB + ∠BOC)
= 110°-(45°+ 30°)
= 110°-75° = 35°
∠BOD = ∠AOD -∠AOB
= 110° -45°
= 65°
(ii) ∠AOB = ∠AOD-∠BOD
= ∠AOD – (∠BOC + ∠COD)
= 120° – (34° + 34°)
= 120°-68°
= 52°
∠AOC = ∠AOB + ∠BOC
= 52° + 34°
= 86°
(iii) Reflex ∠AOC = 360°-∠AOC
= 360° – (∠AOB + ∠BOC)
= 360° – (38° + 38°)
= 360° – 76° = 284°
Reflex ∠AOD = 360° – ∠AOD
= 360° (∠AOB + ∠BOC + ∠COD)
= 360° – (38° + 38° + 38°)
= 360°- 114°
= 246°

Angles Exercise 24B – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
Write the complement angle of :
(i) 45°
(ii) x°
(iii) (x – 10)°
(iv) 20° + y°
Solution:
(i) Complement angle of 45°
= 90° – 45° = 45°
(ii) Complement angle of x°
= 90° – x° = (90 – x)°
(iii) Complement angle of (x – 10)° = 90° (x – 10°)
= 90°-x + 10° = 100°-x
(iv) Complement angle of 20° + y°
= 90°-(20°+y°)
= 90° – 20° -y° = 70° -y°

Question 2.
Write the supplement angle of :
(i) 49°
(ii) 111°
(iii) (x – 30)°
(iv) 20° + y°
Solution:
(i) Supplement angle of 49°
= 180°-49° = 131°
(ii) Supplement angle of 111°
= 180°- 1110 = 69°
(iii) Supplment of (x – 30)° = 180° – ( x° – 30°)
= 180o – x° + 30° – 210° – x°
(iv) Supplement of ∠20° + y° = 180° – (20° +y°)
= 180° -20°-y°
= 160° -y°

Question 3.
Write the complement angle of :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 30
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 31
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 32

Question 4.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 33
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 34
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 35

Question 5.
Find the angle :
(i) that is equal to its complement ?
(ii) that is equal to its supplement ?
Solution:
(i) 45° is equal to its complement.
(ii) 90° is equal to its supplement.

Question 6.
Two complementary angles are in the ratio 7 : 8. Find the angles.
Solution:
Let two complementary angles are lx and 8x
∴ 7x + 8x = 90°
⇒ 15x = 90°
⇒ x = \(\frac { 90 }{ 15 }\)°
⇒ x = 6°
∴Two complementary angles are
7x = 7 x 6° = 42°
8x = 8 x 6° = 48°

Question 7.
Two supplementary angles are in the ratio 7 : 11. Find the angles.
Solution:
Let two supplementary angles are 7x and 11x
∴ 7x+ 11x= 180°
⇒ 18x = 180°
⇒ x = \(\frac { 180 }{ 18 }\)
⇒ x = 10°
Two supplementary angles are
7x = 7 x 10° = 70°
11x= 11 x 10°= 110°

Question 8.
The measures of two complementary angles are (2x – 7)° and (x + 4)°. Find x.
Solution:
We know that, sum of two complementary angles = 90°
∴(2x – 7) + (x + 4) = 90°
2x-7 + x + 4 = 90°
⇒ 2x + x – 7 + 4 = 90°
⇒ 3x – 3 = 90°
⇒ 3x = 90 + 3
⇒ 3x = 93
⇒ x = \(\frac { 93 }{ 3 }\)
x = 31

Question 9.
The measures of two supplementary angles are (3x + 15)° and (2x + 5)°. Find x.
Solution:
We know that, sum of two supplementary angles = 180°
∴ (3x + 15)° + (2x + 5)° = 180° ‘
3x + 15 + 2x + 5 = 180°
⇒ 3x + 2x+15 + 5 = 180°
⇒ 5x°+ 20° = 180°
⇒ 5x = 180° – 20°
⇒ 5x= 160°
⇒ x = \(\frac { 160 }{ 5 }\)
⇒ x = 32°

Question 10.
For an angle x°, find :
(i) the complementary angle
(ii) the supplementary angle
(iii) the value of x° if its supplementary angle is three times its complementary angle.
Solution:
For an angle x,
(i) Complementary angle of x° = (90° – x)
(ii) Supplementary angle of x° = (180° – x)
(iii) ∵‘Supplementary angle = 3 (complementary anlge)
180°- x = 3 (90°-x)
⇒ 180°-x = 270°- 3x
⇒-x + 3x = 270°-180°
⇒ 2x = 90°
⇒x= \(\frac { 90 }{ 2 }\) = 45°
∴ x = 45°

Angles Revision Exercise – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
 Explain what do you understand by :
(i) Adjacent angles ?
(ii) Complementary angles ?
(iii) Supplementary angles ?
Solution:
(i) Adjacent Angles:  Two angles are called adjacent angles if (a) they have a common vertex (b) they have one common arm and (iii) the other two arms of the angles are on the opposite sides of the common arm.
(ii) Complementary Angles : Two angles whose sum is 90° are called complementary angles to each other.
(iii) Supplementary Angles : Two angles whose sum.is 180° are called supplementary angles to each other.

Question 2.
Find the value of ‘x’ for each of the following figures :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 36
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 37
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 38
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 39

Question 3.
Find the number of degrees in an angle that is (i) \(\frac { 3 }{ 5 }\) of a right angle (ii) 0.2 times of a straight line angle.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 40

Question 4.
In the given figure; AB, CD and EF are straight lines. Name the pair of angles forming :
(i) straight line angles.
(ii) vertically opposite angles.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 41
Solution:
In the given figure, AB, CD and EF are straight lines on intersecting, angles are formed a, b, c, d, l, m, n and p.
(i) In the figure pairs of straight line angles are ∠a, ∠b; ∠b, ∠c; ∠c, ∠d; ∠d, ∠a
∠l, ∠m; ∠m, ∠n;∠n, ∠p and ∠p, ∠l
(ii) Pairs of vertically angles are ∠a, ∠c; ∠b, ∠d; ∠l, ∠n; ∠m, ∠p

Question 5.
Find the complement of :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 42
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 43

Question 6.
Find the supplement of :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 44.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 45

Question 7.
Two complementary angles are in the ratio 8 : 7. Find the angles.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 46

Question 8.
Two supplementary angles are in the ratio 7 : 5. Find the angles.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 47

Question 9.
Two supplementary angles are (5x – 82°) and (4x + 73°). Find the value of x.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 48

Question 10.
Find the angle formed by the arms of a clock at:
(i) 3 O’clock
(ii) 6 O’clock
(iii) 9 O’clock
(iv) 12 O’clock
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 49
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 50

Question 11.
For an angle y°, find :
(i) its supplementary angle.
(ii) its complementary angle.
(iii) the value of y° if its supplement is four times its complement.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 51

Question 12.
Use the adjoining figure to find :
(i) ∠BOD
(ii) ∠AOC
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 52

Question 13.
Two adjacent angles forming a linear pair are in the ratio 7:5, find the angles.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 53

Question 14.
Find the angle that is three times its complementary angle.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 54

Question 15.
An angle is one-thirds of a straight line angle ; find :
(i) the angle
(ii) the complement and the supplement of the angle obtained above.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 24 Angles image - 55

 

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts

Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts

Selina Publishers Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts

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APlusTopper.com provides step by step solutions for Selina Concise ICSE Solutions for Class 6 Mathematics. You can download the Selina Concise Mathematics ICSE Solutions for Class 6 with Free PDF download option. Selina Publishers Concise Mathematics for Class 6 ICSE Solutions all questions are solved and explained by expert mathematic teachers as per ICSE board guidelines.

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IMPORTANT POINTS

1. Fundamental Concepts : Geometry is the study of position,, shape, size and other properties of different figures. The geometrical terms such as : point, line, plane, etc., contain the basic ideas for the development of geometry.
(i) Point : A point is a mark of position. It has neither length nor width nor. thickness and occupies no space.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 1
(ii) Line : A line has only length. It has neither width nor thickness.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 2(iii) Ray : It is a line (i.e. a straight line) that starts from a given fixed point and moves in the same direction.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 3
(iv) Line Segment: A line segmeftt is a part of a straight line. A line segment is a part of a line and also of a ray.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 4
(v) Surface : A surface has length and width, but no thickness.
(vi) Plane : It is a flat surface. A plane has length and width, but no thickness.
(vii) Parallel Lines : Two straight lines are said to be parallel to each other if they lie in the same plane and do not meet when produced on either side.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 5
(viii)Intersecting Lines : If two lines lie in the same plane and are not parallel to each other, they are called intersecting lines.
(xi) Collinearity of Points : If three of more points lie on the same straight line, then the points are called collinear points.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 6
(x) Concurrent Lines : If three or more straight lines pass through the same point, the lines are called concurrent lines.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 7Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 7

Fundamental Concepts Exercise 23A – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
State, true or false, if false, correct the statement.
(i) A dot has width but no length.
(ii) A ray has an infinite length only on one side of it.
(iii) A line segment PQ is written as \(\overleftrightarrow { PQ }\) .
(iv) \(\overleftrightarrow { PQ }\)  represents a straight line.
(v) Three points are said to be collinear, if they lie in the same plane.
(vi) Three or more points all lying in the same line, are called collinear points.
Solution:
(i) False : Because a dot has no length, no breadth.
(ii) True.
(iii) False : A line segment PQ is written as PQ.
(iv) True.
( v) False: Three points are called collinear points if they are in the same straight line.
(vi) True.

Question 2.
Write how many lines can be drawn through :
(i) a given point ?
(ii) two given fixed points ?
(iii) three collinear points ?
(iv) three non-collinear points ?
Solution:
(i) Infinite (unlimited) line can be drawn through a given point.
(ii) only one line can be drawn through two given point.
(iii) only one line can be drawn through three collinear points.
(iv) None (no) line can be drawn through three non-collinear points.

Question 3.
The shaded region of the given figure shows a plane :
(a) Name :
(i) three collinear points.
(ii) three non-collinear points.
(iii) a pair of intersecting lines.
(b) State whether true or false :
(i) Line DE is contained in the given plane P.
(ii) Lines AB and DE intersect at point C.
(iii) Points D, B and C are collinear.
(iv) Points D, B and E are collinear.
Solution:
(a) (i) A, B and C are three collinear points.
(ii) A, D and C are non-collinear points.
(iii) AC and DE are intersecting lines.
(b) (i) True
(ii) True
(iii) False
(iv) False
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 8

Question 4.
Correct the statement, if it is wrong:
(i) A A ray can be extended infinitely on either side.
(ii) A ray has a definite length.
(iii) A line segment has a definite length.
(iv) A line has two end-points.
(v) A ray has only one end point.
Solution:
(i) A ray can be extended infinitely on one side of it only.
(ii) A ray has infinite length.
(iii) Yes, a line segment has a definite length.
(iv) A line-segment has two end-points.
(v) Yes, a ray has only one end-point.

Question 5.
State true-er false, if false give the correct statement :
(i) A line has a countable number of points in it.
(ii) Only one line can pass through a given point.
(iii) The intersection of two planes is a straight line
Solution:
(i)  False, a line has length only.
(ii) False, any number of line can pass through a given point.
(iii) True.

Question 6.
State, whether the following pairs of lines or rays appear to be parallel or intersecting.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 9
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 10
Solution:
(i) intersecting
(ii) Parallel
(iii) Parallel
(iv) Intersecting

Question 7.
Give two examples, from your surroundings, for each of the following:
(i) points
(ii) line segments
(iii) plane surfaces
(iv) curved surfaces.
Solution:
(i) Tips of your pencil (Ball Pen) and Tip of paper pin.
(ii) Lines of Exercise Note-Books and edge of school desk.
(iii) Floor of the room and top of the table.
(iv) Surface of foot-ball and front glass of the car.

Question 8.
Under what condition will two straight
lines, in the same plane, have :
(i) no point in common.
(ii) only one point in common.
(iii) an infinite number of points in common.
(iv) If possible draw diagrams in support of your answer.
Solution:
(i) When lines are parallel to each others.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 11
(ii) When they intersect each other
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 12
Here, common point is E.
(iii) When line coincide with each other.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 13

Question 9.
Mark two points A and B on a page of your exercise book. Mark a third point P, such that :
(i) P lies between A and B ; and the three points A, P and B are collinear.
(ii) P does not lie between A and B yet the three points are collinear.
(iii) the three points do not lie in a line.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 14

Question 10.
Mark two points P and Q on a piece of paper. How many lines can you draw:
(i) passing through both the points P and Q?
(ii) passing through the point P ?
(iii) passing through the point Q ?
Solution:
(i) From above diagram it is clear only one line can be drawn.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 15
(ii) Infinite lines can pass through the point up
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 16
(iii) Infinite lines can pass through the point
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 17

Question 11.
The adjoining diagram shows a line AB. Draw diagram to represent:
(i) ray AB i.e. \(\xrightarrow { AB }\)
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 18
(ii) \(\xrightarrow { BA }\)
(iii) line segment AB.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 19

Question 12.
The adjoining diagram shows a ray AB. Draw diagrams to show :
(i) ray BA i.e. \(\xrightarrow { BA }\)
(ii) lineAB
(iii) line segment BA.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 20
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 21

Question 13.
The adjoining diagram shows a line segment AB. Draw diagrams to represent :
(i) ray AB i.e. \(\xrightarrow { AB }\)
(ii) line AB i.e. \(\overleftrightarrow { AB }\)
(iii) ray BA.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 22
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 23

Question 14.
Use a ruler and And whether following points are collinear or not:
(i) D, A and C
(ii) A, B and C
(iii) A, B and E
(iv) B, C and E
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 24
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 25

Question 15.
From the adjoining figure, write:
(i) all pairs f parallel lines
(ii) all the lines which intersect EF.
(iii) lines whose point of intersection is G.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 26
Solution:
(i) The pairs of parallel lines are EF || GH, EF || IJ and GH || IJ
(ii) The lines which intersect EF are AB and CD
(iii) AB and GH are the lines whose point of intersection is G.

Fundamental Concepts Exercise 23B – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
State, which of the following is a plane closed figure :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 27
Solution:
(i) , (iii) ,(iv),(vi)and (viii) are plane close figures.

Question 2.
Fill in the blanks :
(i) ….. is a three sided plane closed figure.
(ii) A square is a plane closed figure which is not bounded by …..
(iii) A rectangle is a …. sided plane ……
(iv) A rectangle has opposite sides ….. and adjacent sides ….. to each other.
(v) The sides of a square are ……. to each other and each angle is
(vi) For a line segment, a line making angle of ……… with it, is called perpendicular to it.
(vii) For a line segment, a line ……. it and making angle of ……. with it, is called ……. bisector of the line segment.
(viii) How many perpendiculars can be drawn to a line segment of length 6 cm ?
(ix) How many perpendicular bisectors can be drawn to a line segment of length 6 cm ?
(x) A perpendicular to a line segment will be its perpendicular bisector if it passes through the ……. of the given line segment.
Solution:
(i) Triangle
(ii) any curved line.
(iii) four, closed figure.
(iv) parallel, perpendicular.
(v) Equal, 90°
(vi) 90°
(vii) bisecting, 90°, perpendicular.
(viii) Infinite.
(ix) Only one.
(x) mid-point

Question 3.
State, which of the lines/line- segments are perpendicular to the line PQ :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 28
Solution:
CD and MN are perpendicular to the line PQ. forming angle to 90°

Question 4.
Which of the following figures show two mutually perpendicular lines :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 29
Solution:
figures (i) and (iii) show two mutually perpendiculars lines forming angles of 90°.

Question 5.
For each figure given below name the line segment that is perpendicular bisector of the other :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 30
Solution:
(i) AB of CD
(ii) AB to MN
(iii) PQ to RS and RS to PQ
(iv) None
(v) None.

Question 6.
Name three objects from your surroundings that contain perpendicular edges.
Solution:
(i) My Text-Book of Mathematics r
(ii) My Note-Book
(iii) My Scale or My school’s Black Board

Question 7.
Using the given figure, answer the following :
(i) Name the pairs of parallel lines.
(ii) Name the pairs of mutually perpendicular lines.
(iii) Is the line p parallel to the line l ?
(iv) Is the line q perpendicular to the line m ?
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 31
Solution:
(i) l || m and p || q
(ii) p and l, p and m, q and l, q and m.
(iii) No, p is perpendicular to line l.
(iv) Yes.

Question 8.
Place a scale (ruler) on a sheet of paper and hold it firmly with one hand. Now draw two line segments AB and CD along the longer edges of the scale. State whether segment AB is parallel to or perpendicular to segment CD.
Solution:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 32

Question 9.
Check your text book :
(i) How many pairs of its edges are parallel to each other ?
(ii) How many pairs of its edges are perpendicular to each other ?
Solution:
(i) 8
(ii) Three at each corner = 24

Question 10.
Give two examples from your surroundings for each of the following :
(i) intersecting lines
(ii) parallel lines
(iii) perpendicular lines.
Solution:
(i) Edges of my Text-Book and Note Book through any comer.
(ii) opp. edges of my Text-Book and Note Book.
(iii) Adjacent edges of my Text-Book and Black Board in my class-room.

Question 11.
State true or false; if false, give the correct statement :
(i) The maximum number of lines through three collinear points is three.
(ii) The maximum number of lines through three non-collinear points is three.
(iii) Two parallel lines always lie in the same plane.
(iv) Concurrent lines always meet at the same point.
(v) A surface can be plane or curved.
(vi) There are an infinite number of points in a line segment of length 10 cm.
(vii) There are an infinite number of points in a line.
(viii) A plane has an infinite number of lines.
(ix) A plane has an infinite number of points.
Solution:
(i) False: Because only one line passes through three collinear points.
(ii) False : No line passes through all the three non-collinear points.
(iii) True.
(iv) True.
(v) True.
(vi) True.
(vii) True.
(viii) True.
(ix) True.

Fundamental Concepts Revision Exercise – Selina Concise Mathematics Class 6 ICSE Solutions

Question 1.
Mark a point O on a piece of paper. Using a sharp pencil and a ruler, draw a line through the point O. Then draw one more line through the point O. How many lines can you draw through O?
Write a statement regarding your observations.
Solution:
We take a point O on a piece of paper. Using a sharp pencil, we draw a line OA through O

another line OB is drawn as shown in the figure.
We can draw an infinite number of lines from O as we know that an infinite number of lines can be drawn through a point in aplane,

Question 2.
Mark two points A and B on a plain sheet “ of paper. Using a sharp pencil and a ruler, draw a line through points A and B. Try to draw one more line through A and B. What do you observe ?
Write a statement regarding your observations.
Solution:
Two points A and B are marked On the plain sheet of paper. Using pencil, draw a line through there two points.

We cannot draw any other line joining them as only one line can be drawn passing through two fixed (given) points in a plane.

Question 3.
Draw two straight lines on a sheet of paper so that the lines drawn :
(i) intersect each other.
(ii) do not intersect.
(iii) appear to intersect when extended.
Solution:
Two straight lines are drawn on the sheet of a paper
(i) Intersecting each other:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 35
(ii) Not intersecting each other:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 36
(iii) Intersect each other when produced them:
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 37

Question 4.
Draw a figure to show that :
(i) points A, B and C arc collinear.
(ii) lines AB, CD and EF are concurrent.
Solution:
(i) We know that three or more points are collinear if they lie on the same straight line. Therefore the required figure (line) is given below on which three points A, B and C lie
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 38
(ii) If three or more lines pass through a common point, these are called concurrent lines. Below is given the figure, in which three lines AB, CD and EF are passing (or intersecting each other) at O.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 39

Question 5.
In your note-book, draw two rays with the same initial point O and going in opposite directions. Write the special name for the final figure obtained.
Solution:
Two rays OA and OB are drawn through O in opposite direction as given below.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 40
There two rays form a straight line \(\overleftrightarrow { AB }\)

Question 6.
In each figure, given below, write the number of line segments used :
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 41
Solution:
(i) In the given figure, there as Ten (10) line segments which are AB, BC, CD, DE, EF, FG, GH, HI, IJ and JA.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 42
(ii) In the given figure, there are 12 line segments which are AB, BC, CD, DE, EF, FG, GH, HI, IJ, JK, KL and LA.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 43
(iii) In the given figure, there are 13 line segments which are AB, BC, CD, DE, EF, FG, GH, HI, IJ, JK, KL, LM and MA.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 44
(iv) In the given figure, there are 7 line segments which are AB, BC, CD, DE, DA, DB, CE.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 45

Question 7.
In a circle, point P is its centre and PA = PB = radius of the circle. Where do points A and B lie ?
Solution:
A circle is given with centre P and PA = PB = radius of the circle.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 46
∵ The radii of a circle are equal there they lie on the circumference of the circle In other words, path of a point which is equidistant from a fixed point is the circumference of a circle. The fixed point is called the centre and equidistance is the radius.

Question 8.
Draw a four-sided closed figure, in which:
(i) all the sides are equal and each angle is 90°.
(ii) opposite sides are equal and each angle is 90°.
Write the special name of each figure drawn.
Solution:
(i) In this four sided closed figure all the sides are equal and each angle is 90°. This figure is called a square. In ABCD, AB = BC = CD = DA and ∠A = ∠B =∠C = ∠D = 90°
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 47
(ii) In this four sided closed figure opposite sides are equal and each angle is 90°. This figure is called a rectangle In rectangle ABCD, AB = CD and BC = AD
∠A = ∠B = ∠C = ∠D = 90°.
Selina Concise Mathematics Class 6 ICSE Solutions Chapter 23 Fundamental Concepts image - 48