{"id":46934,"date":"2022-06-01T04:30:10","date_gmt":"2022-05-31T23:00:10","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=46934"},"modified":"2023-01-25T11:18:36","modified_gmt":"2023-01-25T05:48:36","slug":"ml-aggarwal-class-9-solutions-for-icse-maths-chapter-8-chapter-test","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/ml-aggarwal-class-9-solutions-for-icse-maths-chapter-8-chapter-test\/","title":{"rendered":"ML Aggarwal Class 9 Solutions for ICSE Maths Chapter 8 Indices Chapter Test"},"content":{"rendered":"
Question 1. Question 2. Question 3. Question 4. Question 5. Question 6. Question 7. Question 8. Question 9. ML Aggarwal Class 9 Solutions for ICSE Maths Chapter 8 Indices Chapter Test Question 1. If 2x . 3y. 5z = 2160 find the values of x, y and z. Hence compute the value of 3x. 2-y 5-z. Answer: 2x . 3y. 5z = 2160 => 2x . 3y. 5z = 2 \u00d7 2 \u00d7 … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[3034],"tags":[],"yoast_head":"\n
\nIf 2x<\/sup> . 3y<\/sup>. 5z<\/sup> = 2160 find the values of x, y and z. Hence compute the value of 3x<\/sup>. 2-y<\/sup> 5-z<\/sup>.
\nAnswer:
\n2x<\/sup> . 3y<\/sup>. 5z<\/sup> = 2160
\n=> 2x<\/sup> . 3y<\/sup>. 5z<\/sup> = 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 5
\n=> 2x<\/sup> . 3y<\/sup>. 5z<\/sup> = (2)4<\/sup>.(3)3<\/sup>\u00a0. (5)1<\/sup>
\nComparing powers of 2, 3 and 5, on both sides of above equation we get
\nx = 4, y = 3, z = 1
\nAlso 3x<\/sup>. 2-y<\/sup> 5-z<\/sup> = (3)4<\/sup> \u00d7 (2)-3<\/sup> \u00d7 (5)-1<\/sup>
\n<\/p>\n
\nIf x = 2 and y = -3, find the values of
\n(i) xx<\/sup> + yy<\/sup>
\n(ii) xy<\/sup> + yx<\/sup>.
\nAnswer:
\n(i) xx<\/sup> + yy<\/sup>, Given that x = 2 and y = 3
\n<\/p>\n
\nIf p = xm+n<\/sup> . yt<\/sup> , q = xn+l<\/sup>. ym<\/sup> and r = xl+m<\/sup> . yn<\/sup>. Prove that pm-n<\/sup>. qn-l<\/sup> . rl-n<\/sup> = 1
\nAnswer:
\nGiven that p = xm+n<\/sup>. yt<\/sup> ………(1)
\nq = xn+l<\/sup>. ym<\/sup> ….(2)
\nr = xl+m<\/sup> . yn<\/sup> ..(3)
\nL.H.S. = pm-n<\/sup> . qn-l<\/sup> . rl-m<\/sup> ……(4)
\nPutting the value of a, b, c from (1), (2), (3) respectively in (4), we get
\nL.H.S = (xm+n<\/sup>yt<\/sup> )m-n<\/sup> ,(xn+l<\/sup> ,ym<\/sup> )n-l<\/sup> .(xl+m<\/sup> yn<\/sup>)l-m<\/sup>
\n= (xm+n<\/sup>)m-n<\/sup> . yl(m-n)<\/sup> . (x)(n+l)(n-l)<\/sup> . ym(n-l)<\/sup>. (x)(l+m)(l-m)<\/sup> ym(l-m)<\/sup>
\n= (x(m+n)(m-n)<\/sup> ylm+ln<\/sup> . (x)(n+l)(n-l)<\/sup> . ymn-l<\/sup> . (x)(l+m)(l-m)<\/sup> . yln+nm<\/sup>
\n= (x)m2<\/sup>-n2<\/sup><\/sup> . ylm-ln<\/sup> . (x)n2<\/sup>-l2<\/sup><\/sup> . ymn-ml<\/sup> . (x) l2<\/sup>-m2<\/sup><\/sup> . y nl-nm<\/sup>
\n= (x)m2<\/sup> – n2<\/sup> + n2<\/sup> – l2<\/sup> + l2<\/sup> = m2<\/sup><\/sup> (y)lm-ln+mn-ml+nl-nm<\/sup>
\n= (x)o<\/sup>(y)o<\/sup> = 1 \u00d7 1 = 1
\nHence, Proved L.H.S = R.H.S.<\/p>\n
\nIf x = am+n<\/sup>, y = an+1<\/sup> and z = al+m<\/sup>, prove that xm<\/sup>.yn<\/sup>zl<\/sup> = xn<\/sup> yt<\/sup> zm<\/sup>
\nAnswer:
\nx = am+n<\/sup>,y = an+l<\/sup>, z = al+m<\/sup>
\nL.H.S. =xm<\/sup> yn<\/sup> zp<\/sup>
\n= am[m+n]<\/sup> . yx[n+l]<\/sup> . zl[l+m]<\/sup>
\n= am2<\/sup>+mn<\/sup> . yn2<\/sup>+nl<\/sup> . zl2<\/sup>+lm<\/sup>
\n= am2<\/sup>+mn+n2<\/sup>+nl+l2<\/sup>+lm<\/sup> = al2<\/sup>+m2<\/sup>+n2<\/sup>+lm+mn+np<\/sup>
\nR.H.S. = xn<\/sup> . yl<\/sup> . zm<\/sup>
\n= an(m+n)<\/sup> . al(n+p)<\/sup> . am(l+m)<\/sup>
\n= amn+n2<\/sup><\/sup>\u00a0. al(n+p)<\/sup> . am(l+m)<\/sup>
\n= amn+n2<\/sup><\/sup> . aln+l2<\/sup><\/sup> . alm+m2<\/sup><\/sup>
\n= amn+n2<\/sup>+ln+l2<\/sup>+lm+m2<\/sup><\/sup>
\n= al2<\/sup>+m2<\/sup>+n2<\/sup>+lm+mn+nl<\/sup>
\n\u2234 L.H.S. = R.H.S.<\/p>\n
\nShow that
\n
\nAnswer:
\n
\n
\nHence, L.H.S = R.H.S, Proved the result.<\/p>\n
\nIf x is a positive real number \u00bbnd exponents are rational numbers, then simplify the following :
\n
\nAnswer:
\n
\n
\n<\/p>\n
\nShow that:
\n
\nAnswer:
\nL.H.S =
\n
\n
\n<\/p>\n
\nIf 3x<\/sup> = 5y<\/sup> = (75)z<\/sup> show that z = \\(\\frac{x y}{2 x+y}\\).
\nAnswer:
\nLet 3x<\/sup> = 5y<\/sup> = (75)z<\/sup> = k
\n<\/p>\n
\nSolve the following equations:
\n
\nAnswer:
\n
\n
\n
\n
\n<\/p>\nML Aggarwal Class 9 Solutions for ICSE Maths<\/a><\/h4>\n","protected":false},"excerpt":{"rendered":"