{"id":42688,"date":"2022-05-25T17:30:20","date_gmt":"2022-05-25T12:00:20","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=42688"},"modified":"2023-11-10T09:51:36","modified_gmt":"2023-11-10T04:21:36","slug":"ml-aggarwal-class-7-solutions-for-icse-maths-chapter-8-check-your-progress","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/ml-aggarwal-class-7-solutions-for-icse-maths-chapter-8-check-your-progress\/","title":{"rendered":"ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 8 Algebraic Expressions Check Your Progress"},"content":{"rendered":"
Question 1. Question 2. Question 3. Question 4. Question 5. Question 6. Question 7. Question 8. Question 9. Question 10. Question 11. Question 12. Question 13. Question 14. Question 15. ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 8 Algebraic Expressions Check Your Progress Question 1. Consider the expression x2y – xy2 + 6x2y2. (i) How many terms are there? What do you call such an expression? (ii) List out the terms. (iii) In the term xy2, write down the numerical coefficient and the … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[3034],"tags":[],"yoast_head":"\n
\nConsider the expression \\(\\frac { 3 }{ 2 }\\) x2<\/sup>y – \\(\\frac { 1 }{ 2 }\\) xy2<\/sup> + 6x2<\/sup>y2<\/sup>.
\n(i) How many terms are there? What do you call such an expression?
\n(ii) List out the terms.
\n(iii) In the term \\(\\frac { -1 }{ 2 }\\) xy2<\/sup>, write down the numerical coefficient and the literal coefficient.
\n(iv) In the term \\(\\frac { -1 }{ 2 }\\) xy2<\/sup>, what is the coefficient of x?
\nSolution:
\n\\(\\frac { 3 }{ 2 }\\) x2<\/sup>y – \\(\\frac { 1 }{ 2 }\\) xy2<\/sup> + 6x2<\/sup>y2<\/sup>
\n(i) It has 3 terms : Trinomial
\n(ii) \\(\\frac { 3 }{ 2 }\\) x2<\/sup>y, \\(\\frac { -1 }{ 2 }\\) xy2<\/sup>, 6x2<\/sup>y2<\/sup>
\n(iii) In \\(\\frac { -1 }{ 2 }\\) xy2<\/sup>,
\nnumerical coefficient = \\(\\frac { -1 }{ 2 }\\)
\nLiteral coefficient = xy2<\/sup>
\n(iv) In the term \\(\\frac { -1 }{ 2 }\\) xy2<\/sup>
\ncoefficient of x = \\(\\frac { -1 }{ 2 }\\) y2<\/sup><\/p>\n
\nWrite the Degree of the following polynomials:
\n(i) \\(\\frac { 2 }{ 5 }\\) x3<\/sup> – 7x2<\/sup> – \\(\\frac { 1 }{ 2 }\\) x + 3
\n(ii) \\(\\frac { 2 }{ 3 }\\) xy2<\/sup> – 5xy + \\(\\frac { 3 }{ 5 }\\) y2<\/sup>x2<\/sup> + 2x
\nSolution:
\n<\/p>\n
\nIdentify monomials, binomials and trinomials from the following algebraic expressions:
\n(i) 5x \u00d7 y
\n(ii) 3 – 5x
\n(iii) \\(\\frac { 1 }{ 2 }\\) (7x – 3y + 5z)
\n(iv) 3x2<\/sup> – 1.2xy
\n(v) -3x3<\/sup>y4<\/sup>z5<\/sup>
\n(vi) 5x(2x – 3y) + 7x2<\/sup>
\nSolution:
\n<\/p>\n
\nUsing horizontal method:
\n(i) Add x2<\/sup> + y2<\/sup> – 2xy, -2x2<\/sup> – y2<\/sup> – 2xy and 3x2<\/sup> + y2<\/sup> + xy
\n(ii) Subtract -x2<\/sup> + y2<\/sup> + 2xy from 2x2<\/sup> – 3y2<\/sup>.
\nSolution:
\n(i) x2<\/sup> + y2<\/sup> – 2xy – 2x2<\/sup> – y2<\/sup> – 2xy + 3x2<\/sup> + y2<\/sup> + xy
\n= x2<\/sup> – 2x2<\/sup> + 3x2<\/sup> + y2<\/sup> – y2<\/sup> + y2<\/sup> – 2xy – 2xy + xy
\n= 2x2<\/sup> + y2<\/sup> – 3xy
\n(ii) (2x2<\/sup> – 3y2<\/sup>) – (-x2<\/sup> + y2<\/sup> + 2xy)
\n= 2x2<\/sup> – 3y2<\/sup> + x2<\/sup> – y2<\/sup> – 2xy
\n= 3x2<\/sup> – 4y2<\/sup> – 2xy<\/p>\n
\nUsing column method, add ab + 2bc – ca and 2ab – bc – ca and subtract 4ab + 5bc – 3ca.
\nSolution:
\n<\/p>\n
\nThe sides fo a triangle are 5a – 3b, 3a + 2b and 5b – 2a, find its perimeter.
\nSolution:
\nSides of a triangle are 5a – 3b, 3a + 2b and 5b – 2a
\nPerimeter = 5a – 3b + 3a + 2b + 5b – 2a
\n= 8a – 2a + 4b
\n= 6a + 4b<\/p>\n
\nIf two adjacent sides of a rectangle are 4x +7y and 3y – x, find its perimeter.
\nSolution:
\nTwo adjacent sides of a rectangle are 4x + 7y and 3y – x
\nPerimeter = 2(4x + 7y + 3y – x) = 2(3x + 10y) = 6x + 20y<\/p>\n
\nSubtract the sum of 3x2<\/sup> + 2xy – 2y2<\/sup> and 5y2<\/sup> – 7xy from 5x2<\/sup> + 2y2<\/sup> – 3xy.
\nSolution:
\nSum of 3x2<\/sup> + 2xy – 2y2<\/sup> and 5y2<\/sup> – 7xy
\n= 3x2<\/sup> + 2xy – 2y2<\/sup> + 5y2<\/sup> – 7xy
\n= 3x2<\/sup> – 5xy + 3y2<\/sup>
\nNow,
\n<\/p>\n
\nWhat must be added to 5x3<\/sup> – 2x2<\/sup> + 3x + 7 to get 7x3<\/sup> + 7x – 5?
\nSolution:
\nRequired expression
\n= 7x3<\/sup> + 7x – 5 – (5x3<\/sup> – 2x2<\/sup> + 3x + 7)
\n= 7x3<\/sup> + 7x – 5 – 5x3<\/sup> + 2x2<\/sup> – 3x – 7
\n= 2x3<\/sup> + 2x2<\/sup> + 4x – 12<\/p>\n
\nHow much is 3p – 4q + r less than 4p + 3q – 5r?
\nSolution:
\nRequired expression
\n= (4p + 3q – 5r) – (3p – 4q + r)
\n= 4p + 3q – 5r – 3p + 4q – r
\n= p + 7q – 6r<\/p>\n
\nHow much is 3a2<\/sup> – 5ab + 7b2<\/sup> + 3 greater than 2a2<\/sup> + 2ab + 5?
\nSolution:
\nRequired expression
\n<\/p>\n
\nHow much should 5x3<\/sup> + 3x2<\/sup> – 2x + 1 be increased to get 6x2<\/sup> + 7?
\nSolution:
\nRequired expression
\n= 6x2<\/sup> + 7 – (5x3<\/sup> + 3x2<\/sup> – 2x + 1)
\n= 6x2<\/sup> + 7 – 5x3<\/sup> – 3x2<\/sup> + 2x – 1
\n= -5x3<\/sup> + 3x2<\/sup> + 2x + 6<\/p>\n
\nSubtract the sum of 12ab – 10b2<\/sup> – 18a2<\/sup> and 9ab + 12b2<\/sup> + 14a2<\/sup> from the sum of ab + 2b2<\/sup> and 3b2<\/sup> – a2<\/sup>.
\nSolution:
\nSum of 12ab – 10b2<\/sup> – 18a2<\/sup>
\nand 9ab + 12b2<\/sup> + 14a2<\/sup>
\n<\/p>\n
\nwhen a = 3, b = 0, c = -2, find the values of:
\n(i) ab + 2bc + 3ca + 4abc
\n(ii) a3<\/sup> + b3<\/sup> + c3<\/sup> – 3abc
\nSolution:
\na = 3, b = 0, c = -2
\n(i) ab + 2bc + 3ca + 4abc
\n= 3 \u00d7 0 + 2 \u00d7 0 \u00d7 (-2) + 3(-2)(3) + 4(3)(0)(-2)
\n= 0 + 0 – 18 + 0
\n= -18
\n(ii) a3<\/sup> + b3<\/sup> + c3<\/sup> – 3abc
\n= (3)3<\/sup> + (0)3<\/sup> + (-2)3<\/sup> – 3 \u00d7 3 \u00d7 0 \u00d7 (-2)
\n= 27 + 0 – 8 – 0
\n= 19<\/p>\n
\nWrite the algebraic expression for the nth term of the number pattern 13, 23, 33, 43, ………..
\nSolution:
\n13, 23, 33, 43
\n13 = 10 \u00d7 1 + 3
\n23 = 10 \u00d7 2 + 3
\n33 = 10 \u00d7 3 + 3
\n43 = 10 \u00d7 4 + 3
\n10 \u00d7 n + 3 = 10n + 3
\nWhere n is a natural number.<\/p>\nML Aggarwal Class 7 Solutions for ICSE Maths<\/a><\/h4>\n","protected":false},"excerpt":{"rendered":"