{"id":42688,"date":"2022-05-25T17:30:20","date_gmt":"2022-05-25T12:00:20","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=42688"},"modified":"2023-11-10T09:51:36","modified_gmt":"2023-11-10T04:21:36","slug":"ml-aggarwal-class-7-solutions-for-icse-maths-chapter-8-check-your-progress","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/ml-aggarwal-class-7-solutions-for-icse-maths-chapter-8-check-your-progress\/","title":{"rendered":"ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 8 Algebraic Expressions Check Your Progress"},"content":{"rendered":"

ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 8 Algebraic Expressions Check Your Progress<\/h2>\n

Question 1.
\nConsider the expression \\(\\frac { 3 }{ 2 }\\) x2<\/sup>y – \\(\\frac { 1 }{ 2 }\\) xy2<\/sup> + 6x2<\/sup>y2<\/sup>.
\n(i) How many terms are there? What do you call such an expression?
\n(ii) List out the terms.
\n(iii) In the term \\(\\frac { -1 }{ 2 }\\) xy2<\/sup>, write down the numerical coefficient and the literal coefficient.
\n(iv) In the term \\(\\frac { -1 }{ 2 }\\) xy2<\/sup>, what is the coefficient of x?
\nSolution:
\n\\(\\frac { 3 }{ 2 }\\) x2<\/sup>y – \\(\\frac { 1 }{ 2 }\\) xy2<\/sup> + 6x2<\/sup>y2<\/sup>
\n(i) It has 3 terms : Trinomial
\n(ii) \\(\\frac { 3 }{ 2 }\\) x2<\/sup>y, \\(\\frac { -1 }{ 2 }\\) xy2<\/sup>, 6x2<\/sup>y2<\/sup>
\n(iii) In \\(\\frac { -1 }{ 2 }\\) xy2<\/sup>,
\nnumerical coefficient = \\(\\frac { -1 }{ 2 }\\)
\nLiteral coefficient = xy2<\/sup>
\n(iv) In the term \\(\\frac { -1 }{ 2 }\\) xy2<\/sup>
\ncoefficient of x = \\(\\frac { -1 }{ 2 }\\) y2<\/sup><\/p>\n

Question 2.
\nWrite the Degree of the following polynomials:
\n(i) \\(\\frac { 2 }{ 5 }\\) x3<\/sup> – 7x2<\/sup> – \\(\\frac { 1 }{ 2 }\\) x + 3
\n(ii) \\(\\frac { 2 }{ 3 }\\) xy2<\/sup> – 5xy + \\(\\frac { 3 }{ 5 }\\) y2<\/sup>x2<\/sup> + 2x
\nSolution:
\n\"ML<\/p>\n

Question 3.
\nIdentify monomials, binomials and trinomials from the following algebraic expressions:
\n(i) 5x \u00d7 y
\n(ii) 3 – 5x
\n(iii) \\(\\frac { 1 }{ 2 }\\) (7x – 3y + 5z)
\n(iv) 3x2<\/sup> – 1.2xy
\n(v) -3x3<\/sup>y4<\/sup>z5<\/sup>
\n(vi) 5x(2x – 3y) + 7x2<\/sup>
\nSolution:
\n\"ML<\/p>\n

Question 4.
\nUsing horizontal method:
\n(i) Add x2<\/sup> + y2<\/sup> – 2xy, -2x2<\/sup> – y2<\/sup> – 2xy and 3x2<\/sup> + y2<\/sup> + xy
\n(ii) Subtract -x2<\/sup> + y2<\/sup> + 2xy from 2x2<\/sup> – 3y2<\/sup>.
\nSolution:
\n(i) x2<\/sup> + y2<\/sup> – 2xy – 2x2<\/sup> – y2<\/sup> – 2xy + 3x2<\/sup> + y2<\/sup> + xy
\n= x2<\/sup> – 2x2<\/sup> + 3x2<\/sup> + y2<\/sup> – y2<\/sup> + y2<\/sup> – 2xy – 2xy + xy
\n= 2x2<\/sup> + y2<\/sup> – 3xy
\n(ii) (2x2<\/sup> – 3y2<\/sup>) – (-x2<\/sup> + y2<\/sup> + 2xy)
\n= 2x2<\/sup> – 3y2<\/sup> + x2<\/sup> – y2<\/sup> – 2xy
\n= 3x2<\/sup> – 4y2<\/sup> – 2xy<\/p>\n

Question 5.
\nUsing column method, add ab + 2bc – ca and 2ab – bc – ca and subtract 4ab + 5bc – 3ca.
\nSolution:
\n\"ML<\/p>\n

Question 6.
\nThe sides fo a triangle are 5a – 3b, 3a + 2b and 5b – 2a, find its perimeter.
\nSolution:
\nSides of a triangle are 5a – 3b, 3a + 2b and 5b – 2a
\nPerimeter = 5a – 3b + 3a + 2b + 5b – 2a
\n= 8a – 2a + 4b
\n= 6a + 4b<\/p>\n

Question 7.
\nIf two adjacent sides of a rectangle are 4x +7y and 3y – x, find its perimeter.
\nSolution:
\nTwo adjacent sides of a rectangle are 4x + 7y and 3y – x
\nPerimeter = 2(4x + 7y + 3y – x) = 2(3x + 10y) = 6x + 20y<\/p>\n

Question 8.
\nSubtract the sum of 3x2<\/sup> + 2xy – 2y2<\/sup> and 5y2<\/sup> – 7xy from 5x2<\/sup> + 2y2<\/sup> – 3xy.
\nSolution:
\nSum of 3x2<\/sup> + 2xy – 2y2<\/sup> and 5y2<\/sup> – 7xy
\n= 3x2<\/sup> + 2xy – 2y2<\/sup> + 5y2<\/sup> – 7xy
\n= 3x2<\/sup> – 5xy + 3y2<\/sup>
\nNow,
\n\"ML<\/p>\n

Question 9.
\nWhat must be added to 5x3<\/sup> – 2x2<\/sup> + 3x + 7 to get 7x3<\/sup> + 7x – 5?
\nSolution:
\nRequired expression
\n= 7x3<\/sup> + 7x – 5 – (5x3<\/sup> – 2x2<\/sup> + 3x + 7)
\n= 7x3<\/sup> + 7x – 5 – 5x3<\/sup> + 2x2<\/sup> – 3x – 7
\n= 2x3<\/sup> + 2x2<\/sup> + 4x – 12<\/p>\n

Question 10.
\nHow much is 3p – 4q + r less than 4p + 3q – 5r?
\nSolution:
\nRequired expression
\n= (4p + 3q – 5r) – (3p – 4q + r)
\n= 4p + 3q – 5r – 3p + 4q – r
\n= p + 7q – 6r<\/p>\n

Question 11.
\nHow much is 3a2<\/sup> – 5ab + 7b2<\/sup> + 3 greater than 2a2<\/sup> + 2ab + 5?
\nSolution:
\nRequired expression
\n\"ML<\/p>\n

Question 12.
\nHow much should 5x3<\/sup> + 3x2<\/sup> – 2x + 1 be increased to get 6x2<\/sup> + 7?
\nSolution:
\nRequired expression
\n= 6x2<\/sup> + 7 – (5x3<\/sup> + 3x2<\/sup> – 2x + 1)
\n= 6x2<\/sup> + 7 – 5x3<\/sup> – 3x2<\/sup> + 2x – 1
\n= -5x3<\/sup> + 3x2<\/sup> + 2x + 6<\/p>\n

Question 13.
\nSubtract the sum of 12ab – 10b2<\/sup> – 18a2<\/sup> and 9ab + 12b2<\/sup> + 14a2<\/sup> from the sum of ab + 2b2<\/sup> and 3b2<\/sup> – a2<\/sup>.
\nSolution:
\nSum of 12ab – 10b2<\/sup> – 18a2<\/sup>
\nand 9ab + 12b2<\/sup> + 14a2<\/sup>
\n\"ML<\/p>\n

Question 14.
\nwhen a = 3, b = 0, c = -2, find the values of:
\n(i) ab + 2bc + 3ca + 4abc
\n(ii) a3<\/sup> + b3<\/sup> + c3<\/sup> – 3abc
\nSolution:
\na = 3, b = 0, c = -2
\n(i) ab + 2bc + 3ca + 4abc
\n= 3 \u00d7 0 + 2 \u00d7 0 \u00d7 (-2) + 3(-2)(3) + 4(3)(0)(-2)
\n= 0 + 0 – 18 + 0
\n= -18
\n(ii) a3<\/sup> + b3<\/sup> + c3<\/sup> – 3abc
\n= (3)3<\/sup> + (0)3<\/sup> + (-2)3<\/sup> – 3 \u00d7 3 \u00d7 0 \u00d7 (-2)
\n= 27 + 0 – 8 – 0
\n= 19<\/p>\n

Question 15.
\nWrite the algebraic expression for the nth term of the number pattern 13, 23, 33, 43, ………..
\nSolution:
\n13, 23, 33, 43
\n13 = 10 \u00d7 1 + 3
\n23 = 10 \u00d7 2 + 3
\n33 = 10 \u00d7 3 + 3
\n43 = 10 \u00d7 4 + 3
\n10 \u00d7 n + 3 = 10n + 3
\nWhere n is a natural number.<\/p>\n

ML Aggarwal Class 7 Solutions for ICSE Maths<\/a><\/h4>\n","protected":false},"excerpt":{"rendered":"

ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 8 Algebraic Expressions Check Your Progress Question 1. Consider the expression x2y – xy2 + 6x2y2. (i) How many terms are there? What do you call such an expression? (ii) List out the terms. (iii) In the term xy2, write down the numerical coefficient and the … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[3034],"tags":[],"yoast_head":"\nML Aggarwal Class 7 Solutions for ICSE Maths Chapter 8 Algebraic Expressions Check Your Progress - CBSE Library<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/cbselibrary.com\/ml-aggarwal-class-7-solutions-for-icse-maths-chapter-8-check-your-progress\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 8 Algebraic Expressions Check Your Progress\" \/>\n<meta property=\"og:description\" content=\"ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 8 Algebraic Expressions Check Your Progress Question 1. 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Consider the expression x2y – xy2 + 6x2y2. (i) How many terms are there? What do you call such an expression? (ii) List out the terms. (iii) In the term xy2, write down the numerical coefficient and the ... 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