{"id":42172,"date":"2022-05-24T22:00:51","date_gmt":"2022-05-24T16:30:51","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=42172"},"modified":"2023-11-10T10:03:24","modified_gmt":"2023-11-10T04:33:24","slug":"ml-aggarwal-class-7-solutions-for-icse-maths-chapter-1-ex-1-4","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/ml-aggarwal-class-7-solutions-for-icse-maths-chapter-1-ex-1-4\/","title":{"rendered":"ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 1 Integers Ex 1.4"},"content":{"rendered":"

ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 1 Integers Ex 1.4<\/h2>\n

Question 1.
\nEvaluate the following:
\n(i) (-36) \u00f7 (-9)
\n(ii) 150 \u00f7 (-25)
\n(iii) (-270) \u00f7 27
\n(iv) (-59) \u00f7 59
\n(v) 0 \u00f7 (-17)
\n(vi) (-784) \u00f7 (-56)
\nSolution:
\n(i) (-36) \u00f7 (-9) = \\(\\frac { -36 }{ -9 }\\) = +4
\n(ii) 150 \u00f7 (-25) = \\(\\frac { 150 }{ -25 }\\) = -6
\n(iii) (-270) \u00f7 27 = \\(\\frac { -270 }{ 27 }\\) = -10
\n(iv) (-59) \u00f7 59 = \\(\\frac { -59 }{ 59 }\\) = -1
\n(v) 0 \u00f7 (-17) = \\(\\frac { 0 }{ -17 }\\) = 0
\n(vi) (-784) \u00f7 (-56) = \\(\\frac { -784 }{ -56 }\\) = 14
\n\"ML<\/p>\n

Question 2.
\nEvaluate the following:
\n(i) 13 \u00f7 [(-2) + 1]
\n(ii) (-47) \u00f7 [(-45) + (-2)]
\n(iii) [(-6) + 5] \u00f7 [(-2) + 1]
\n(iv) [(-48) \u00f7 (-6)] \u00f7 (-2)
\nSolution:
\n(i) 13 \u00f7 [(-2) + 1]
\n= 13 \u00f7 [-2 + 1]
\n= 13 \u00f7 (-1)
\n= -13<\/p>\n

(ii) (-47) \u00f7 [(-45) + (-2)]
\n= (-47) \u00f7 (-47)
\n= 1<\/p>\n

(iii) [(-6) + 5] \u00f7 [(-2) + 1]
\n= [-6 + 5] + [-2 + 1]
\n= (-1) \u00f7 (-1)
\n= 1<\/p>\n

(iv) [(-48) \u00f7 (-6)] \u00f7 (-2)
\n= \\(\\frac { -48 }{ -6 }\\) \u00f7 (-2)
\n= 8 \u00f7 (-2)
\n= -4<\/p>\n

Question 3.
\nVerify that (a \u00f7 b) \u00f7 c \u2260 a \u00f7 (b \u00f7 c) for a = -225, b = 15 and c = -3.
\nSolution:
\n\"ML
\n\"ML<\/p>\n

Question 4.
\nVerify that a \u00f7 (b \u00f7 c) \u2260 (a \u00f7 b) \u00f7 (a \u00f7 c) for
\n(i) a = -10, b = 1 and c = 1
\n(ii) a = 12, b = 1 and c = -2
\nSolution:
\na \u00f7 (b \u00f7 c) \u2260 (a \u00f7 b) \u00f7 (a \u00f7 c)
\n\"ML
\n= (12 \u00f7 1) + [12 \u00f7 (-2))
\n= 12 – 6
\n= 6
\nLHS \u2260 RHS<\/p>\n

Question 5.
\nFill in the blanks to make the following statements true:
\n(i) 239 \u00f7 …….. = 1
\n(ii) (-85) \u00f7 …….. = -1
\n(iii) (-213) \u00f7 ….. = 1
\n(iv) (-43) \u00f7 …… = 43
\n(v) …….. \u00f7 (-21) = 4
\n(vi) (-66) \u00f7 ……. = -3
\nSolution:
\n\"ML<\/p>\n

Question 6.
\nWrite five pairs of integers (a, b) such that a \u00f7 b = -3 one such pair is (-6, 2).
\nSolution:
\nHere, a \u00f7 b = -3
\n\u21d2 a = -3b
\nPutting some different values to b, we get corresponding values of a such as
\n(i) b = 1, then
\na = -3b = -3 \u00d7 1 = -3
\n(-3, 1)
\n(ii) b = 3, then
\na = -3 \u00d7 3 = -9
\n(-9, 3) is a pair.
\n(iii) b = 4, then a = -3 \u00d7 4 = -12
\nPair is (-12, 4)
\n(iv) b = 5, then a = -3 \u00d7 5 = -15
\nPair is (-15, 5)
\n(v) b = 6, then a = -3 \u00d7 6 = -18
\nPair is (-18, 6)<\/p>\n

Question 7.
\nIn a competition 3 marks are given for every correct answer and (-2) marks are given for every incorrect answer and no marks for not attempting any question.
\n(i) Sachin scored 24 marks. If he got 14 correct answers, how many questions has he attempted incorrectly?
\n(ii) Nalini scores (-7) marks in this competition, though she has got 9 correct answers. How many questions she has attempted
\nincorrectly?
\nSolution:
\nIn a competition,
\n3 marks for every correct answer and (-2) marks for every incorrect answer.
\nNo marks for non-attempting the question.
\n(i) Sachin got 14 correct answers, and got 24 marks
\nHe attempted 14 correct answer
\nHe would have got 14 \u00d7 3 = 42 marks
\nBut to get 24 marks 42 – 24 = 18 marks were deducted due to incorrect answer.
\nHe attempted \\(\\frac { 18 }{ 2 }\\) = 9 questions incorrect.
\n(ii) Nalini scored (-7) marks, she got 9 correct answers, so she would have 9 \u00d7 3 = 27 marks
\nBut she got (-7) marks
\nSo, 27 + 7 = 34 marks were deducted due to incorrect answers.
\nNumber of incorrect answers = \\(\\frac { 34 }{ 2 }\\) = 17 questions<\/p>\n

Question 8.
\nAn elevator descends into a mine shaft at the rate of 6 m\/min. If the descend starts from 10 m above the ground level, how long will it take to reach the shaft 350 m below the ground level?
\nSolution:
\nRate of elevator = 6 m\/min
\nand it was started 10 m above the ground level
\nDepth below ground level = 350 m
\nTotal depth = 350 + 10 = 360
\nTime taken = \\(\\frac { 360 }{ 6 }\\) minutes = 60 minutes = 1 hour<\/p>\n

ML Aggarwal Class 7 Solutions for ICSE Maths<\/a><\/h4>\n","protected":false},"excerpt":{"rendered":"

ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 1 Integers Ex 1.4 Question 1. Evaluate the following: (i) (-36) \u00f7 (-9) (ii) 150 \u00f7 (-25) (iii) (-270) \u00f7 27 (iv) (-59) \u00f7 59 (v) 0 \u00f7 (-17) (vi) (-784) \u00f7 (-56) Solution: (i) (-36) \u00f7 (-9) = = +4 (ii) 150 \u00f7 (-25) = … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[3034],"tags":[],"yoast_head":"\nML Aggarwal Class 7 Solutions for ICSE Maths Chapter 1 Integers Ex 1.4 - CBSE Library<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/cbselibrary.com\/ml-aggarwal-class-7-solutions-for-icse-maths-chapter-1-ex-1-4\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 1 Integers Ex 1.4\" \/>\n<meta property=\"og:description\" content=\"ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 1 Integers Ex 1.4 Question 1. Evaluate the following: (i) (-36) \u00f7 (-9) (ii) 150 \u00f7 (-25) (iii) (-270) \u00f7 27 (iv) (-59) \u00f7 59 (v) 0 \u00f7 (-17) (vi) (-784) \u00f7 (-56) Solution: (i) (-36) \u00f7 (-9) = = +4 (ii) 150 \u00f7 (-25) = ... Read more\" \/>\n<meta property=\"og:url\" content=\"https:\/\/cbselibrary.com\/ml-aggarwal-class-7-solutions-for-icse-maths-chapter-1-ex-1-4\/\" \/>\n<meta property=\"og:site_name\" content=\"CBSE Library\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/aplustopper\/\" \/>\n<meta property=\"article:published_time\" content=\"2022-05-24T16:30:51+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2023-11-10T04:33:24+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2019\/06\/ML-Aggarwal-Class-7-Solutions-for-ICSE-Maths-Chapter-1-Integers-Ex-1.4-1.1.png\" \/>\n<meta name=\"twitter:card\" content=\"summary\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Prasanna\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"3 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Organization\",\"@id\":\"https:\/\/cbselibrary.com\/#organization\",\"name\":\"Aplus Topper\",\"url\":\"https:\/\/cbselibrary.com\/\",\"sameAs\":[\"https:\/\/www.facebook.com\/aplustopper\/\"],\"logo\":{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/cbselibrary.com\/#logo\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/Aplus_380x90-logo.jpg\",\"contentUrl\":\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/Aplus_380x90-logo.jpg\",\"width\":1585,\"height\":375,\"caption\":\"Aplus Topper\"},\"image\":{\"@id\":\"https:\/\/cbselibrary.com\/#logo\"}},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/cbselibrary.com\/#website\",\"url\":\"https:\/\/cbselibrary.com\/\",\"name\":\"CBSE Library\",\"description\":\"Improve your Grades\",\"publisher\":{\"@id\":\"https:\/\/cbselibrary.com\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/cbselibrary.com\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/cbselibrary.com\/ml-aggarwal-class-7-solutions-for-icse-maths-chapter-1-ex-1-4\/#primaryimage\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2019\/06\/ML-Aggarwal-Class-7-Solutions-for-ICSE-Maths-Chapter-1-Integers-Ex-1.4-1.1.png\",\"contentUrl\":\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2019\/06\/ML-Aggarwal-Class-7-Solutions-for-ICSE-Maths-Chapter-1-Integers-Ex-1.4-1.1.png\",\"width\":95,\"height\":110,\"caption\":\"ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 1 Integers Ex 1.4 1.1\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/cbselibrary.com\/ml-aggarwal-class-7-solutions-for-icse-maths-chapter-1-ex-1-4\/#webpage\",\"url\":\"https:\/\/cbselibrary.com\/ml-aggarwal-class-7-solutions-for-icse-maths-chapter-1-ex-1-4\/\",\"name\":\"ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 1 Integers Ex 1.4 - 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