{"id":39463,"date":"2019-04-09T06:32:50","date_gmt":"2019-04-09T06:32:50","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=39463"},"modified":"2020-11-23T18:57:17","modified_gmt":"2020-11-23T13:27:17","slug":"plus-two-chemistry-chapter-wise-questions-answers-chapter-14","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/plus-two-chemistry-chapter-wise-questions-answers-chapter-14\/","title":{"rendered":"Plus Two Chemistry Chapter Wise Questions and Answers Chapter 14 Biomolecules"},"content":{"rendered":"
Plus Two Chemistry Chapter Wise Questions and Answers Chapter 14 Biomolecules is part of Plus Two Chemistry Chapter Wise Questions and Answers<\/a>. Here we have given Plus Two Chemistry Chapter Wise Questions and Answers Chapter 14 Biomolecules.<\/p>\n Question 1. Question 2. Question 3. Question 4. Question 5. Question 6. Question 7. Question 8. Question 9. Question 10. Question 11. Question 12. Question 13. Question 1. Question 2. Question 3. Question 4. Question 5. Question 6. Question 7. Question 8. Question 9. Question 10. Question 1. Answer:<\/p>\n 1. They are known as anomers. Question 2. Question 3. Answer:<\/p>\n 1. Sugar that is present in DNA and RNA:<\/p>\n 2.<\/p>\n Question 4. Answer:<\/p>\n Question 5. Answer:<\/p>\n Question 6. Amylopectin is a branched chain polymer of \u03b1-D-glucose units in which chain is formed by C1 – C4 glycosidic linkage whereas branching occurs by C1 – C6 glycosidic linkage. Cellulose is a straight chain polysaccharide composed of only \u03b2-D-glucose units joined by C1 – C4 glycosidic linkage.<\/p>\n Question 1. Answer:<\/p>\n Question 2. Answer: Question 3. Question 4.<\/p>\n Answer: Question 5. Answer:<\/p>\n Question 6.<\/p>\n Answer: 2. The repeating structural units of nucleic acids are called nucleotides.<\/p>\n Question 7.<\/p>\n Answer:<\/p>\n 1. The pH at which the Zwitter ions do not migrate neither towards cathode nor towards anode is known as isoelectric point of the amino acids.<\/p>\n 2. Amino acids possess both acidic and basic group, they generally exist as dipolar ions called Zwitter ions. Question 1. Question 2. Question 3. Cellulose is only a linear polymer of D-glucose units joined through \u03b2 -glycosidic linkage between C1 of one glucose with C4 of next glucose unit.<\/p>\n Question 4. Question 5. We hope the Kerala Plus Two Chemistry Chapter Wise Questions and Answers Chapter 14 Biomolecules help you. If you have any query regarding Kerala Plus Two Chemistry Chapter Wise Questions and Answers Chapter 14 Biomolecules, drop a comment below and we will get back to you at the earliest.<\/p>\n","protected":false},"excerpt":{"rendered":" Plus Two Chemistry Chapter Wise Questions and Answers Chapter 14 Biomolecules is part of Plus Two Chemistry Chapter Wise Questions and Answers. Here we have given Plus Two Chemistry Chapter Wise Questions and Answers Chapter 14 Biomolecules. Kerala Plus Two Chemistry Chapter Wise Questions and Answers Chapter 14 Biomolecules Plus Two Chemistry Biomolecules One Mark … Read more<\/a><\/p>\n","protected":false},"author":8,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[42728],"tags":[],"yoast_head":"\nKerala Plus Two Chemistry Chapter Wise Questions and Answers Chapter 14 Biomolecules<\/h2>\n
Plus Two Chemistry Biomolecules One Mark Questions and Answers<\/h3>\n
\nWhich of the following is an example of globular protein?
\n(a) Myosin
\n(b) Collagen
\n(c) Insulin
\n(d) Keratin
\nAnswer:
\n(c) Insulin<\/p>\n
\nThe vitamin essential for blood clotting is
\nAnswer:
\nVitamin K<\/p>\n
\nWhich base is present in RNA but not in DNA?
\n(a) Uracil
\n(b) Thymine
\n(c) Guanine
\n(d) ytosine
\nAnswer:
\n(a) Uracil<\/p>\n
\nSay TRUE or FALSE:
\nThe coagulation of egg white on boiling is an example of protein denaturation.
\nAnswer:
\nTrue<\/p>\n
\nThe linkage that holds monosaccharide units together in a polysaccharide is called …………………….
\nAnswer:
\nGlycosidic linkage<\/p>\n
\nProteins are essential for growth in animals. They are build up of amino acid molecules. How are different amino acid molecules linked in a proteins?
\nAnswer:
\nBy peptide linkage.<\/p>\n
\nWhat are the different types of RNA found in the cell?
\nAnswer:
\nm-RNA, t-RNA, r-RNA<\/p>\n
\nLactose is made of ………………….
\nAnswer:
\n\u03b2 -D galactose and \u03b2 -D glucose<\/p>\n
\nGlucose does not react with ………………..
\na) Br2<\/sub>\/H2<\/sub>O
\nb) NH2<\/sub>OH
\nc) HI
\nd) NaHSO3<\/sub>
\ne) CH3<\/sub>-CO-O-CO-CH3<\/sub>
\nAnswer:
\n(d) NaHSO3<\/sub><\/p>\n
\nAnaemia is caused by the deficiency of vitamin ………………………
\nAnswer:
\nB12<\/sub><\/p>\n
\nThe number of chiral C atoms on glucose and fructose are
\nAnswer:
\n4 in glucose and 3 in fructose<\/p>\n
\nGlucose on oxidation with bromine water give …………………………
\nAnswer:
\nGluconic acid<\/p>\n
\nName the vitamin responsible for the coagulation of blood.
\nAnswer:
\nVitamin K.<\/p>\nPlus Two Chemistry Biomolecules Two Mark Questions and Answers<\/h3>\n
\nExplain the denaturation of protein.
\nAnswer:
\nWhen a protein is treated with acid, alkali or heated or subjected to change in pH, the secondary and primary structure of protein gets ruptured. Denaturation does not change the primary structure of proteins.<\/p>\n
\nWhy cannot vitamin C be stored in our body?
\nAnswer:
\nVitamin \u2018C\u2019 is a water soluble vitamin and they are readily excreted in urine and cannot be stored in our body.<\/p>\n
\nClassify the following into monosaccharides and disaccharides.
\nRibose, 2-deoxyribose, maltose, galactose, fructose and lactose.
\nAnswer:<\/p>\n\n
\nWhat do you understand by the term glycosidic linkage?
\nAnswer:
\nThe two monosaccharide units are linked together by an oxide or either linkage formed by the loss of water molecules. Such a linkage called glycosidic linkage.<\/p>\n
\nDistinguish between essential and non-essential amino acids. Give examples.
\nAnswer:<\/p>\n\n
\nWhat is \u2018peptide linkage\u2019 as related to proteins?
\nAnswer:
\nThe linkage, – CO – NH – which unites various amino acid units in a peptide molecule is called peptide linkage.<\/p>\n
\nAmino acids show amphoteric behavior. Why?
\nAnswer:
\nAmino acids contain both NH2<\/sub> & -COOH group and hence they exhibit amphoteric character.
\nNH3<\/sub>+<\/sup> – CH2<\/sub> – COO–<\/sup><\/p>\n
\nWhat are reducing sugars? Give one example.
\nAnswer:
\nSugar units which are having free – CHO groups are reducing sugars, eg. Maltose.<\/p>\n
\nWhat is primary structure of proteins?
\nAnswer:
\nThe primary structure gives an idea regarding the sequence in which amino acids are arranged.<\/p>\n
\nDifferentiate between fibrous & globular proteins.
\nAnswer:
\nFibrous proteins have threads lying side by side to form a fiber-like structure, e.g. Keratin. Globular proteins have molecules which are folded into compact units that often approach spherical shape.<\/p>\nPlus Two Chemistry Biomolecules Three Mark Questions and Answers<\/h3>\n
\nD-glucose is obtained in two different forms, \u03b1- D- glucose, and \u03b2-D-glucose.<\/p>\n\n
\n2. Anomers are a pair of stereo isomeric ring forms of a sugar which differ in configuration only around first carbon atom.
\n<\/p>\n
\nComplete the following table:
\n
\nAnswer:<\/p>\n\n
\nThere are two types of nucleic acids, DNA and RNA.<\/p>\n\n
\n
\n\n
\n DNA<\/td>\n RNA<\/td>\n<\/tr>\n \n 1) Double helix structure<\/td>\n 1) Single helix<\/td>\n<\/tr>\n \n 2) Sugar-deoxyribose<\/td>\n 2) Sugar-Ribose<\/td>\n<\/tr>\n \n 3) Bases – A, G, C, T<\/td>\n 3) Bases A, G, C, U<\/td>\n<\/tr>\n \n 4) Transmits Traits<\/td>\n 4) Responsible for protein synthesis<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
\nClassify the given vitamins as fat soluble and water soluble.<\/p>\n\n
\n
\nWrite the products obtained when glucose is treated with the following reagents?<\/p>\n\n
\n
\nWhat is the basic structural difference between starch and cellulose?
\nAnswer:
\nStarch has 2 components namely amylose and amylopectin. Amylose is a long unbranched chain made of \u03b1-D-(+)-glucose units held by C1 – C4 glycosidic linkage.<\/p>\nPlus Two Chemistry Biomolecules Four Mark Questions and Answers<\/h3>\n
\nAmino substituted carboxylic acids are called amino acids.<\/p>\n\n
\n
\nThose amino acids which can not be synthesized in our body and must be obtained through diet are known as essential amino acids. eg. valine, Lysine<\/li>\n
\nStarch on enzymatic hydrolysis by diastase gives a reducing disaccharide \u2018A\u2019 which undergoes hydrolysis by enzyme maltase to form \u2018B\u2019 which is also a reducing sugar.<\/p>\n\n
\n1. Compound A-Maltose
\nCompound B – Glucose
\n
\nb) All those carbohydrates which contain free aldehydic or ketonic group to reduce Tollens reagent and Fehling\u2019s solution and are called reducing sugars, e.g. Glucose, Fructose.<\/p>\n
\nIn the following table, the names of Vitamins, their sources, and deficiency diseases are tabulated in the wrong order. Match them in the correct order.
\n
\nAnswer:
\n<\/p>\n\n
\n1.
\n
\n2.
\n<\/p>\n
\nWhen egg is boiled its physical structure changes.<\/p>\n\n
\n
\n
\n1. Intermolecular hydrogen bonding between -NH group of each amino acid and carbonyl group of an adjacent turn of the helix.<\/p>\n\n
\n
\ne.g. glycine H3<\/sub>N(+)<\/sup> – CH2<\/sub> – COO(-)<\/sup><\/p>\nPlus Two Chemistry Biomolecules NCERT Questions and Answers<\/h3>\n
\nClassify the following into monosaccharides and disaccharides.
\nRibose, 2-deoxyribose, maltose, galactose, fructose and lactose.
\nAnswer:<\/p>\n\n
\nWhat do you understand by the term glycosidic linkage?
\nAnswer:
\nIn oligosaccharides and polysaccharides, the two monosaccharide units are linked together by an oxide or ether linkage formed by the loss of water molecules. Such a linkage between two monosaccharide units through oxygen atom is called glycosidic linkage.<\/p>\n
\nWhat is the basic structural difference between starch and cellulose?
\nAnswer:
\nBoth starch and cellulose contain a large number of \u03b1 -D(+)-glucose units. Starch consists of two components:<\/p>\n\n
\nEnumerate the reactions of D-glucose which cannot obe explained by its open chain structure.
\nAnswer:<\/p>\n\n
\nWhat is the difference between a nucleoside and a nucleotide?
\nAnswer:
\nNucleoside is formd by condensation of a purine or pyrimidine base with pentose sugar at position 1. When nucloeside is linked to phosphoric acid at 5 position of sugar moeity, we get a nucleotide. So a nucleoside has two units: pentose sugar and a base while a nucleotide has three units: phosphate group, pentose sugar and a base.
\n<\/p>\n