{"id":34689,"date":"2018-12-26T10:58:32","date_gmt":"2018-12-26T10:58:32","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=34689"},"modified":"2020-11-27T15:26:39","modified_gmt":"2020-11-27T09:56:39","slug":"ncert-solutions-for-class-10-maths-chapter-7-ex-7-2","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/ncert-solutions-for-class-10-maths-chapter-7-ex-7-2\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.2"},"content":{"rendered":"<p>NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.2 are part of NCERT Solutions for Class 10 Maths. Here are we have given Chapter 7 <strong>Coordinate Geometry\u00a0Class 10 NCERT Solutions Ex 7.2.<\/strong><\/p>\n<ul>\n<li><a title=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.1\" href=\"https:\/\/cbselibrary.com\/ncert-solutions-for-class-10-maths-chapter-7\/\" target=\"_blank\" rel=\"noopener\">Coordinate Geometry Class 10 Ex 7.1<\/a><\/li>\n<li><a title=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.3\" href=\"https:\/\/cbselibrary.com\/ncert-solutions-for-class-10-maths-chapter-7-ex-7-3\/\" target=\"_blank\" rel=\"noopener\">Coordinate Geometry Class 10 Ex 7.3<\/a><\/li>\n<li><a title=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.4\" href=\"https:\/\/cbselibrary.com\/ncert-solutions-for-class-10-maths-chapter-7-ex-7-4\/\" target=\"_blank\" rel=\"noopener\">Coordinate Geometry Class 10 Ex 7.4<\/a><\/li>\n<\/ul>\n<table style=\"table-layout: fixed; width: 650px;\" border=\"1\">\n<tbody>\n<tr>\n<td><strong>Board<\/strong><\/td>\n<td>CBSE<\/td>\n<\/tr>\n<tr>\n<td><strong>Textbook<\/strong><\/td>\n<td>NCERT<\/td>\n<\/tr>\n<tr>\n<td><strong>Class<\/strong><\/td>\n<td>Class 10<\/td>\n<\/tr>\n<tr>\n<td><strong>Subject<\/strong><\/td>\n<td>Maths<\/td>\n<\/tr>\n<tr>\n<td><strong>Chapter<\/strong><\/td>\n<td>Chapter 7<\/td>\n<\/tr>\n<tr>\n<td><strong>Chapter Name<\/strong><\/td>\n<td>Coordinate Geometry<\/td>\n<\/tr>\n<tr>\n<td><strong>Exercise<\/strong><\/td>\n<td>Ex 7.2<\/td>\n<\/tr>\n<tr>\n<td><strong>Number of Questions Solved<\/strong><\/td>\n<td>10<\/td>\n<\/tr>\n<tr>\n<td><strong>Category<\/strong><\/td>\n<td>NCERT Solutions<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h2>NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.2<\/h2>\n<p><a class=\"button-red\" href=\"https:\/\/cbselibrary.com\/ncert-solutions-for-class-10-maths\/\">NCERT Solutions for Class 10 Maths<\/a><\/p>\n<p><strong>Question 1.<\/strong> Find the coordinates of the point which divides the join of (- 1, 7) and (4, \u2013 3) in the ratio 2:3.<\/p>\n<p><strong>Solution:<br \/>\n<\/strong>Let P(x, y) be the required point. Using the section formula which says<br \/>\nCoordinates of points P, dividing the line segment joining A(x<sub>1<\/sub>, y<sub>1<\/sub>) &amp; B(x<sub>2<\/sub>,y<sub>2<\/sub>)<br \/>\ninternally in the ratio m:n<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-101017\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-14.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 14\" width=\"280\" height=\"157\" \/><br \/>\nConcept Insight: The key idea here is to identify m and n with point A &amp; n with point B<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-101018\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-15.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 15\" width=\"349\" height=\"81\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-15.png 349w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-15-300x70.png 300w\" sizes=\"(max-width: 349px) 100vw, 349px\" \/><\/p>\n<p><strong>Question 2.<\/strong> Find the coordinates of the points of trisection of the line segment joining (4, -1) and (-2, -3).<\/p>\n<p><strong>Solution:<\/strong><br \/>\nTrisection means division into three equal parts. So we need to find two points. such that they divide the line segment in three equal parts.<br \/>\nLet P (x<sub>1<\/sub>,y<sub>1<\/sub>) and Q (x<sub>2<\/sub>,y<sub>2<\/sub>) are the points of trisection of the line segment\u00a0joining the given points i.e. AP = PQ = QB<br \/>\nTherefore point P divides AB internally in ratio 1:2<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-101020\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-16.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 16\" width=\"333\" height=\"329\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-16.png 333w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-16-300x296.png 300w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-16-100x100.png 100w\" sizes=\"(max-width: 333px) 100vw, 333px\" \/><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-101021\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-17.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 17\" width=\"592\" height=\"152\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-17.png 592w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-17-300x77.png 300w\" sizes=\"(max-width: 592px) 100vw, 592px\" \/><\/p>\n<p><strong>Question 3.<\/strong> To conduct Sports Day activities, in your rectangular shaped school ground ABCD, lines have been drawn with chalk powder at a distance of 1 m each. 100 flower pots have been placed at a distance of 1 m from each other along AD, as shown in the following figure. Niharika runs 1\/4th the distance AD on the 2nd line and posts a green flag. Preet runs 1\/5th the distance AD on the eighth line and posts a red flag. What is the distance between both the flags? If Rashmi has to post a blue flag exactly halfway between the line segment joining the two flags, where should she post her flag?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-101022\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-18.gif\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 18\" width=\"315\" height=\"368\" \/><\/p>\n<p><strong>Solution:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-101023\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-19.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 19\" width=\"691\" height=\"378\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-19.png 691w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-19-300x164.png 300w\" sizes=\"(max-width: 691px) 100vw, 691px\" \/><br \/>\n<\/strong><\/p>\n<p><strong>Question 4.<\/strong> Find the ratio in which the line segment joining the points (-3, 10) and (6, \u2013 8) is divided by (-1, 6).<\/p>\n<p><strong>Solution:<br \/>\n<\/strong><\/p>\n<p>Let the ratio in which line segment joining (\u20143, 10) and (6, \u20148) is divided by<br \/>\npoint (\u20141, 6) is k: 1,<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-101025\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-20.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 20\" width=\"264\" height=\"148\" \/><\/p>\n<p>Concept Insight: Assume the ratio as k: 1 and not as m :n otherwise we will get one equation in two unknowns.<\/p>\n<p><strong>Question 5.<\/strong> Find the ratio in which the line segment joining A (1, \u2013 5) and B (- 4, 5) is divided by the x-axis. Also find the coordinates of the point of division.<\/p>\n<p><strong>Solution:<br \/>\n<\/strong>If the ratio in which P divides AB is k:1 , then the co-ordinates of the point P will be<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-101026\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-21.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 21\" width=\"600\" height=\"302\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-21.png 600w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-21-300x151.png 300w\" sizes=\"(max-width: 600px) 100vw, 600px\" \/><\/p>\n<p>Concept Insight: Assume the ratio as k: 1 and not as m :n otherwise we will get one equation in two unknowns.Use the fact that y coordinate is zero.<\/p>\n<p><strong>Question 6.<\/strong> If (1, 2), (4, <em>y<\/em>), (<em>x<\/em>, 6) and (3, 5) are the vertices of a parallelogram taken in order, find <em>x <\/em>and <em>y<\/em>.<\/p>\n<p><strong>Solution:<br \/>\n<\/strong><img loading=\"lazy\" class=\"alignnone size-full wp-image-101028\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-22.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 22\" width=\"506\" height=\"162\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-22.png 506w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-22-300x96.png 300w\" sizes=\"(max-width: 506px) 100vw, 506px\" \/><br \/>\nLet (1, 2), (4, y), (x, 6) and (3, 5) are the coordinates of A, B, C, D vertices of a parallelogram ABCD.<br \/>\nDiagonals of a parallelogram bisects each other so, O is midpoint of AC and BD<br \/>\nIf O is midpoint of AC, then coordinate and O are<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-101030\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-23.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 23\" width=\"369\" height=\"215\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-23.png 369w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-23-300x175.png 300w\" sizes=\"(max-width: 369px) 100vw, 369px\" \/><\/p>\n<p>Concept Insight: To prove that a quadrilateral with given vertices is a parallelogram using prove that the diagonals bisect each other.<\/p>\n<p><strong>Question 7.<\/strong> Find the coordinates of a point A, where AB is the diameter of circle whose centre is (2, \u2013 3) and B is (1, 4).<\/p>\n<p><strong>Solution:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-101031\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-24.gif\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 24\" width=\"415\" height=\"192\" \/><br \/>\n<\/strong><\/p>\n<p><strong>Question 8.<\/strong> If A and B are (\u20132, \u20132) and (2, \u20134), respectively, find the coordinates of P such that AP = 3\/7 AB and P lies on the line segment AB.<\/p>\n<p><strong>Solution:<br \/>\n<\/strong>Coordinates of the point P(x, y) which divides the line segment joining the points A(x<sub>1<\/sub>, y<sub>1<\/sub>) and B(x<sub>2<\/sub>,y<sub>2<\/sub>) intenally in the ratio m<sub>1<\/sub> : m<sub>2<\/sub>, are<br \/>\n\\(\\frac { { m }_{ 1 }{ x }_{ 2 }+{ m }_{ 2 }{ x }_{ 1 } }{ { m }_{ 1 }+{ m }_{ 2 } } ,\\frac { { m }_{ 1 }{ y }_{ 2 }+{ m }_{ 2 }{ y }_{ 1 } }{ { m }_{ 1 }+{ m }_{ 2 } } \\)<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-101032\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-25.gif\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 25\" width=\"543\" height=\"350\" \/><\/p>\n<p><strong>Question 9.<\/strong> Find the coordinates of the points which divide the line segment joining A (- 2, 2) and B (2, 8) into four equal parts.<\/p>\n<p><strong>Solution:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-101033\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-26.gif\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 26\" width=\"594\" height=\"464\" \/><br \/>\n<\/strong><\/p>\n<p class=\"ques\"><strong>Question 10.\u00a0<\/strong>Find the area of a rhombus if its vertices are (3, 0), (4, 5), (\u2014 1, 4) and (\u2014 2, \u20141) taken in order.<\/p>\n<div class=\"ttl\"><strong>Solution:<br \/>\n<\/strong><strong><img loading=\"lazy\" class=\"alignnone size-full wp-image-101035\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-27.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry 27\" width=\"539\" height=\"423\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-27.png 539w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2018\/12\/NCERT-Solutions-for-Class-10-Maths-Chapter-7-Coordinate-Geometry-27-300x235.png 300w\" sizes=\"(max-width: 539px) 100vw, 539px\" \/><\/strong><\/div>\n<div><\/div>\n<div class=\"ttl\">\n<p>Concept Insight: Use the result Area of a rhombus = 1\/2 (product of its diagonals) and diagonals are formed by joining opposite vertices.<\/p>\n<p>&nbsp;<\/p>\n<\/div>\n<p>We hope the NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.2 help you. If you have any query regarding NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.2, drop a comment below and we will get back to you at the earliest.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.2 are part of NCERT Solutions for Class 10 Maths. Here are we have given Chapter 7 Coordinate Geometry\u00a0Class 10 NCERT Solutions Ex 7.2. Coordinate Geometry Class 10 Ex 7.1 Coordinate Geometry Class 10 Ex 7.3 Coordinate Geometry Class 10 Ex 7.4 Board CBSE &#8230; <a title=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.2\" class=\"read-more\" href=\"https:\/\/cbselibrary.com\/ncert-solutions-for-class-10-maths-chapter-7-ex-7-2\/\" aria-label=\"More on NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.2\">Read more<\/a><\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[6805],"tags":[36685],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v17.8 (Yoast SEO v18.4.1) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.2 A Plus Topper.com<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.2 helpful to finish your Home Work. 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