{"id":29206,"date":"2018-07-18T06:12:12","date_gmt":"2018-07-18T06:12:12","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=29206"},"modified":"2020-12-02T10:04:55","modified_gmt":"2020-12-02T04:34:55","slug":"rs-aggarwal-solutions-class-10-chapter-9-mean-median-mode-of-grouped-data-ex-9e","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/rs-aggarwal-solutions-class-10-chapter-9-mean-median-mode-of-grouped-data-ex-9e\/","title":{"rendered":"RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E"},"content":{"rendered":"<h2>RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E<\/h2>\n<p>These Solutions are part of <a href=\"https:\/\/cbselibrary.com\/rs-aggarwal-class-10-solutions\/\">RS Aggarwal Solutions Class 10<\/a>. Here we have given RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E<\/p>\n<p><strong>Other Exercises<\/strong><\/p>\n<ul>\n<li><a href=\"https:\/\/cbselibrary.com\/rs-aggarwal-solutions-class-10-chapter-9-mean-median-mode-of-grouped-data-ex-9a\/\">RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9A<\/a><\/li>\n<li><a href=\"https:\/\/cbselibrary.com\/rs-aggarwal-solutions-class-10-chapter-9-mean-median-mode-of-grouped-data-ex-9b\/\">RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9B<\/a><\/li>\n<li><a href=\"https:\/\/cbselibrary.com\/rs-aggarwal-solutions-class-10-chapter-9-mean-median-mode-of-grouped-data-ex-9c-9d\/\">RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9C &amp; 9D<\/a><\/li>\n<li><a href=\"https:\/\/cbselibrary.com\/rs-aggarwal-solutions-class-10-chapter-9-mean-median-mode-of-grouped-data-ex-9e\/\">RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E<\/a><\/li>\n<li><a href=\"https:\/\/cbselibrary.com\/mean-advantages-disadvantages\/\">Mean<\/a>, <a href=\"https:\/\/cbselibrary.com\/calculate-median-grouped-frequency-distribution\/\">Median<\/a>, <a href=\"https:\/\/cbselibrary.com\/mode-statistics\/\">Mode of Grouped Dat<\/a><\/li>\n<\/ul>\n<h3 style=\"text-align: center;\"><span style=\"color: #0000ff;\"><strong>Exercise 9E<\/strong><\/span><\/h3>\n<p><span style=\"color: #993366;\"><strong>Question 1:<\/strong><\/span><br \/>\nFrom the given table, we may prepare the cumulative frequency table as shown below:<\/p>\n<table style=\"height: 210px;\" border=\"2\" width=\"291\">\n<tbody>\n<tr>\n<td style=\"text-align: center;\" width=\"213\"><strong>Class interval<\/strong><\/td>\n<td style=\"text-align: center;\" width=\"213\"><strong>C.F<\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">Less than 220<\/td>\n<td style=\"text-align: center;\" width=\"213\">7<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">Less than 240<\/td>\n<td style=\"text-align: center;\" width=\"213\">10<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">Less than260<\/td>\n<td style=\"text-align: center;\" width=\"213\">16<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">Less than 280<\/td>\n<td style=\"text-align: center;\" width=\"213\">24<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">Less than 300<\/td>\n<td style=\"text-align: center;\" width=\"213\">26<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">Less than 320<\/td>\n<td style=\"text-align: center;\" width=\"213\">30<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>On a graph paper, we plot the point (220, 7), (240, 10), (260, 16), (280, 24), (300, 26), (320, 30)<br \/>\nWe join these points successively with a freehand to get the cumulative frequency curve or an ogive<br \/>\nHere\u00a0N = 30, \\(\\frac { N }{ 2 } \u00a0 \\)=\u00a015<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-117097\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-1.1.jpg\" alt=\"RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E 1.1\" width=\"483\" height=\"291\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-1.1.jpg 483w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-1.1-300x181.jpg 300w\" sizes=\"(max-width: 483px) 100vw, 483px\" \/><br \/>\nTake point (0, 15) on the y-axis and draw AP || x-axis meeting the curve at P. Draw PM \u22a5 \u00a0x -axis intersecting the x-axis at M. Then OM = 258 and hence median = 258.<\/p>\n<p><strong>Read \u00a0More:<\/strong><\/p>\n<ul>\n<li><a href=\"https:\/\/cbselibrary.com\/classmark-prepare-discrete-frequency-distribution\/\">Classmark and Discrete Frequency Distribution<\/a><\/li>\n<li><a href=\"https:\/\/cbselibrary.com\/cumulative-frequency-statistics\/\">Cumulative Frequency in statistics<\/a><\/li>\n<\/ul>\n<p><span style=\"color: #993366;\"><strong>Question 2:<\/strong><\/span><br \/>\nCumulative frequency table is as follows:<\/p>\n<table style=\"height: 210px;\" border=\"2\" width=\"291\">\n<tbody>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">Marks<\/td>\n<td style=\"text-align: center;\" width=\"213\"><strong>C.F<\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">Marks less than 10<\/td>\n<td style=\"text-align: center;\" width=\"213\">3<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">Marks less than 20<\/td>\n<td style=\"text-align: center;\" width=\"213\">11<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">Marks less than 30<\/td>\n<td style=\"text-align: center;\" width=\"213\">28<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">Marks less than 40<\/td>\n<td style=\"text-align: center;\" width=\"213\">48<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">Marks less than 50<\/td>\n<td style=\"text-align: center;\" width=\"213\">70<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Scale :<br \/>\nHorizontal: 1 small div = 10 marks<br \/>\nVertical : 1 small div = 10 students<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-117100\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-2.1.jpg\" alt=\"RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E 2.1\" width=\"483\" height=\"291\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-2.1.jpg 483w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-2.1-300x181.jpg 300w\" sizes=\"(max-width: 483px) 100vw, 483px\" \/><br \/>\nThe points (10, 3), (20, 11), (30, 28), (40, 48), (50, 70) are plotted and joined as shown above. This is required cumulative curve.<br \/>\nN = 70, \\(\\frac { N }{ 2 } \u00a0 \\)= 35<br \/>\nOb vertical line OY, take OA = 35<br \/>\nThrough A, a horizontal line AP is drawn meeting the graph at P<br \/>\nThrough P, a vertical line PM is drawn.<br \/>\nNow, OM = 34, therefore Median = 34<\/p>\n<p><strong>More Resources<\/strong><\/p>\n<ul>\n<li><a title=\"RS Aggarwal Class 10 Solutions\" href=\"https:\/\/cbselibrary.com\/course\/rs-aggarwal-class-10-solutions\/\">RS Aggarwal Solutions Class 10<\/a><\/li>\n<li><a title=\"RD Sharma Class 10 Solutions\" href=\"http:\/\/www.learncbse.in\/rd-sharma-class-10-solutions\/\">RD Sharma Class 10 Solutions<\/a><\/li>\n<li><a title=\"NCERT Solutions Home Page\" href=\"http:\/\/www.learncbse.in\/ncert-solutions-2\/\">NCERT Solutions<\/a><\/li>\n<\/ul>\n<p><span style=\"color: #993366;\"><strong>Question 3:<\/strong><\/span><br \/>\nThe following table gives height in metre of 360 tress:<\/p>\n<table style=\"height: 341px;\" border=\"2\" width=\"264\">\n<tbody>\n<tr>\n<td width=\"133\">\n<p style=\"text-align: center;\"><strong>Height in m<\/strong><\/p>\n<\/td>\n<td style=\"text-align: center;\" width=\"133\"><strong>Number of trees<\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"133\">Less than 7<\/p>\n<p>Less than 14<\/p>\n<p>Less than 21<\/p>\n<p>Less than 28<\/p>\n<p>Less than 35<\/p>\n<p>Less than 42<\/p>\n<p>Less than 49<\/p>\n<p>Less than 56<\/td>\n<td width=\"133\">\n<p style=\"text-align: center;\">25<\/p>\n<p style=\"text-align: center;\">45<\/p>\n<p style=\"text-align: center;\">95<\/p>\n<p style=\"text-align: center;\">140<\/p>\n<p style=\"text-align: center;\">235<\/p>\n<p style=\"text-align: center;\">275<\/p>\n<p style=\"text-align: center;\">320<\/p>\n<p style=\"text-align: center;\">360<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>The points (7, 25), (14, 45), 21, 95), (28, 140), (35, 235), (42, 275), (49, 320), (56, 360) are plotted and joined one by one as shown in the figure.<br \/>\nThis is the required cumulative curve<br \/>\nN = 360, \\(\\frac { N }{ 2 } \u00a0 \\)=\u00a0180<br \/>\nAt y = 180, affix A.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-117102\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-3.1.jpg\" alt=\"RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E 3.1\" width=\"483\" height=\"291\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-3.1.jpg 483w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-3.1-300x181.jpg 300w\" sizes=\"(max-width: 483px) 100vw, 483px\" \/><br \/>\nThrough A, draw a horizontal line meeting the curve at P.<br \/>\nThrough P, a vertical line is drawn which meets OX at M.<br \/>\nOM = 31.<br \/>\nHence median = 31<br \/>\n<span style=\"color: #993366;\"><strong>Question 4:<\/strong><\/span><br \/>\nLess than series<\/p>\n<table style=\"height: 486px;\" border=\"2\" width=\"346\">\n<tbody>\n<tr>\n<td width=\"146\">\n<p style=\"text-align: center;\"><strong>Less than<\/strong><\/p>\n<p style=\"text-align: center;\"><strong>Capital<\/strong><\/p>\n<p style=\"text-align: center;\"><strong>(in lakh of Rs)<\/strong><\/p>\n<\/td>\n<td style=\"text-align: center;\" width=\"146\">\n<p style=\"text-align: center;\"><strong>No. of Companies<\/strong><\/p>\n<p style=\"text-align: center;\"><strong>(C.F.)<\/strong><\/p>\n<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"146\">Less than 10<\/p>\n<p>Less than 20<\/p>\n<p>Less than 30<\/p>\n<p>Less than 40<\/p>\n<p>Less than 50<\/p>\n<p>Less than 60<\/p>\n<p>Less than 70<\/p>\n<p>Less than 80<\/td>\n<td width=\"146\">\n<p style=\"text-align: center;\">2<\/p>\n<p style=\"text-align: center;\">5<\/p>\n<p style=\"text-align: center;\">12<\/p>\n<p style=\"text-align: center;\">23<\/p>\n<p style=\"text-align: center;\">38<\/p>\n<p style=\"text-align: center;\">45<\/p>\n<p style=\"text-align: center;\">47<\/p>\n<p style=\"text-align: center;\">50<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Scale: Horizontal : 1 small div = capital of 1 lakh of Rs<br \/>\nVertical: 1 small div. = 1 company.<br \/>\nPlot the points (10, 2), (20, 5), (30, 12), (40, 23), (50, 38), (60, 45), (70, 47) and (80, 50).<br \/>\nThrough A(0, 25), AP is drawn parallel to OX and PM\u00a0 OX, OM = 41. Hence median = 41.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-117104\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-4.1.jpg\" alt=\"RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E 4.1\" width=\"483\" height=\"291\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-4.1.jpg 483w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-4.1-300x181.jpg 300w\" sizes=\"(max-width: 483px) 100vw, 483px\" \/><br \/>\n<span style=\"color: #993366;\"><strong>Question 5:<\/strong><\/span><br \/>\nMore than series<\/p>\n<table style=\"height: 210px;\" border=\"2\" width=\"291\">\n<tbody>\n<tr>\n<td style=\"text-align: center;\" width=\"213\"><strong>Score<\/strong><\/td>\n<td style=\"text-align: center;\" width=\"213\"><strong>No of Candidates<\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">More than\u00a0400<\/td>\n<td style=\"text-align: center;\" width=\"213\">230<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">More than\u00a0450<\/td>\n<td style=\"text-align: center;\" width=\"213\">210<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">More than 500<\/td>\n<td style=\"text-align: center;\" width=\"213\">175<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">More than 550<\/td>\n<td style=\"text-align: center;\" width=\"213\">135<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">More than 600<\/td>\n<td style=\"text-align: center;\" width=\"213\">103<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">More than 600<\/td>\n<td style=\"text-align: center;\" width=\"213\">79<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">More than 700<\/td>\n<td style=\"text-align: center;\" width=\"213\">52<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"213\">More than 750<\/td>\n<td style=\"text-align: center;\" width=\"213\">34<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>We plot the points (400, 230), (450, 210), (500, 175), (550, 135), (600, 103), (650, 79), (700, 52), (750, 34)<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-117106\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-5.1.jpg\" alt=\"RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E 5.1\" width=\"486\" height=\"284\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-5.1.jpg 486w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-5.1-300x175.jpg 300w\" sizes=\"(max-width: 486px) 100vw, 486px\" \/><br \/>\nHence,\u00a0N = 230, \\(\\frac { N }{ 2 } \u00a0 \\)= 115<br \/>\nTake a point A(0, 115) on the y-axis and draw AP||x-axis meeting the curve at P, Draw PM x-axis intersecting x-axis at M<br \/>\nThen, OM = 590<br \/>\nHence median = 590<br \/>\n<span style=\"color: #993366;\"><strong>Question 6:<\/strong><\/span><br \/>\n(i) Less than series:<\/p>\n<table style=\"height: 341px;\" border=\"2\" width=\"264\">\n<tbody>\n<tr>\n<td width=\"133\">\n<p style=\"text-align: center;\"><strong>Marks<\/strong><\/p>\n<\/td>\n<td style=\"text-align: center;\" width=\"133\"><strong>Number of Students<\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"133\">Less than 5<\/p>\n<p>Less than 10<\/p>\n<p>Less than 15<\/p>\n<p>Less than 20<\/p>\n<p>Less than 25<\/p>\n<p>Less than 30<\/p>\n<p>Less than 35<\/p>\n<p>Less than 40<\/p>\n<p>Less than 45<\/p>\n<p>Less than 50<\/td>\n<td width=\"133\">\n<p style=\"text-align: center;\">2<\/p>\n<p style=\"text-align: center;\">7<\/p>\n<p style=\"text-align: center;\">13<\/p>\n<p style=\"text-align: center;\">21<\/p>\n<p style=\"text-align: center;\">31<\/p>\n<p style=\"text-align: center;\">56<\/p>\n<p style=\"text-align: center;\">76<\/p>\n<p style=\"text-align: center;\">94<\/p>\n<p style=\"text-align: center;\">98<\/p>\n<p style=\"text-align: center;\">100<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Plot the points (5, 2), (10, 7), (15, 13), (20, 21), (25, 31), (30, 56), (35, 76), (40, 94), (45, 98) and (50, 100)<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-117108\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-6.1.jpg\" alt=\"RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E 6.1\" width=\"483\" height=\"393\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-6.1.jpg 483w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-6.1-300x244.jpg 300w\" sizes=\"(max-width: 483px) 100vw, 483px\" \/><br \/>\nJoin these points free hand to get the curve representing &#8220;less than&#8221; cumulative curve.<br \/>\n(ii) From the given table we may prepare the &#8216;more than&#8217; series as shown below<\/p>\n<table style=\"height: 341px;\" border=\"2\" width=\"264\">\n<tbody>\n<tr>\n<td width=\"133\">\n<p style=\"text-align: center;\"><strong>Marks<\/strong><\/p>\n<\/td>\n<td style=\"text-align: center;\" width=\"133\"><strong>Number of Students<\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"133\">More than 45<\/p>\n<p>More than 40<\/p>\n<p>More than 35<\/p>\n<p>More than 30<\/p>\n<p>More than 25<\/p>\n<p>More than 20<\/p>\n<p>More than 15<\/p>\n<p>More than 10<\/p>\n<p>More than 5<\/p>\n<p>More than 0<\/td>\n<td width=\"133\">\n<p style=\"text-align: center;\">2<\/p>\n<p style=\"text-align: center;\">6<\/p>\n<p style=\"text-align: center;\">24<\/p>\n<p style=\"text-align: center;\">44<\/p>\n<p style=\"text-align: center;\">69<\/p>\n<p style=\"text-align: center;\">79<\/p>\n<p style=\"text-align: center;\">87<\/p>\n<p style=\"text-align: center;\">93<\/p>\n<p style=\"text-align: center;\">98<\/p>\n<p style=\"text-align: center;\">100<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Now, on the same graph paper as above, we plot the point (0, 100), (5, 98), (10, 93), (15, 87), (20, 79), (25, 69), (30, 44), (35, 24) and (40, 6) and (45, 2)Plot the points (5, 2), (10, 7), (15, 13), (20, 21), (25, 31), (30, 56), (35, 76), (40, 94), (45, 98) and (50, 100)<br \/>\nJoin these points free hand to get required curve<br \/>\nHere\u00a0N = 100, \\(\\frac { N }{ 2 } \u00a0 \\)=\u00a050<br \/>\nTwo curves intersect at point P(28, 50)<br \/>\nHence, the median = 28<br \/>\n<span style=\"color: #993366;\"><strong>Question 7:<\/strong><\/span><br \/>\nWe may prepare less than series and more than series<br \/>\n(i) Less than series<\/p>\n<table style=\"height: 341px;\" border=\"2\" width=\"264\">\n<tbody>\n<tr>\n<td width=\"133\">\n<p style=\"text-align: center;\"><strong>Height in (cm)<\/strong><\/p>\n<\/td>\n<td style=\"text-align: center;\" width=\"133\"><strong>Frequency<\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"133\">Less than 140<\/p>\n<p>Less than 144<\/p>\n<p>Less than 148<\/p>\n<p>Less than 152<\/p>\n<p>Less than 156<\/p>\n<p>Less than 160<\/p>\n<p>Less than 164<\/p>\n<p>Less than 168<\/p>\n<p>Less than 172<\/p>\n<p>Less than 176<\/p>\n<p>Less than 180<\/td>\n<td width=\"133\">\n<p style=\"text-align: center;\">0<\/p>\n<p style=\"text-align: center;\">3<\/p>\n<p style=\"text-align: center;\">12<\/p>\n<p style=\"text-align: center;\">36<\/p>\n<p style=\"text-align: center;\">67<\/p>\n<p style=\"text-align: center;\">109<\/p>\n<p style=\"text-align: center;\">173<\/p>\n<p style=\"text-align: center;\">248<\/p>\n<p style=\"text-align: center;\">330<\/p>\n<p style=\"text-align: center;\">416<\/p>\n<p style=\"text-align: center;\">450<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Now on graph paper plot the points (140, 0), (144, 3), (148, 12), (152, 36), (156, 67), (160, 109), (164, 173), (168, 248), (172, 330), (176, 416), (180, 450)<br \/>\n(ii) More than series<\/p>\n<table style=\"height: 341px;\" border=\"2\" width=\"264\">\n<tbody>\n<tr>\n<td width=\"133\">\n<p style=\"text-align: center;\"><strong>Height in (cm)<\/strong><\/p>\n<\/td>\n<td style=\"text-align: center;\" width=\"133\"><strong>C.F.<\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"133\">More than 140<\/p>\n<p>More than 144<\/p>\n<p>More than 148<\/p>\n<p>More than 152<\/p>\n<p>More than 156<\/p>\n<p>More than 160<\/p>\n<p>More than 164<\/p>\n<p>More than 168<\/p>\n<p>More than 172<\/p>\n<p>More than 176<\/p>\n<p>More than 180<\/td>\n<td width=\"133\">\n<p style=\"text-align: center;\">450<\/p>\n<p style=\"text-align: center;\">447<\/p>\n<p style=\"text-align: center;\">438<\/p>\n<p style=\"text-align: center;\">414<\/p>\n<p style=\"text-align: center;\">383<\/p>\n<p style=\"text-align: center;\">341<\/p>\n<p style=\"text-align: center;\">277<\/p>\n<p style=\"text-align: center;\">202<\/p>\n<p style=\"text-align: center;\">120<\/p>\n<p style=\"text-align: center;\">34<\/p>\n<p style=\"text-align: center;\">0<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Now on the same graph plot the points (140, 450), (144, 447), (148, 438), (152, 414), (156, 383), (160, 341), (164, 277), (168, 202), (172, 120), (176, 34), (180, 0)<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-117111\" src=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-7.1.jpg\" alt=\"RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E 7.1\" width=\"491\" height=\"404\" srcset=\"https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-7.1.jpg 491w, https:\/\/cbselibrary.com\/wp-content\/uploads\/2020\/12\/RS-Aggarwal-Solutions-Class-10-Chapter-9-Mean-Median-Mode-of-Grouped-Data-Ex-9E-7.1-300x247.jpg 300w\" sizes=\"(max-width: 491px) 100vw, 491px\" \/><br \/>\nThe curves intersect at (167, 225).<br \/>\nHence, 167 is the median.<\/p>\n<p>Hope given <a href=\"https:\/\/cbselibrary.com\/rs-aggarwal-solutions-class-10-chapter-9-mean-median-mode-of-grouped-data-ex-9e\/\">RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E<\/a>\u00a0are helpful to complete your math homework.<\/p>\n<p>If you have any doubts, please comment below. <a href=\"https:\/\/cbselibrary.com\">A Plus Topper<\/a> try to provide online math tutoring for you.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E Other Exercises RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, &#8230; <a title=\"RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E\" class=\"read-more\" href=\"https:\/\/cbselibrary.com\/rs-aggarwal-solutions-class-10-chapter-9-mean-median-mode-of-grouped-data-ex-9e\/\" aria-label=\"More on RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E\">Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[6805],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v17.8 (Yoast SEO v18.4.1) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E - CBSE Library<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/cbselibrary.com\/rs-aggarwal-solutions-class-10-chapter-9-mean-median-mode-of-grouped-data-ex-9e\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E\" \/>\n<meta property=\"og:description\" content=\"RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E These Solutions are part of RS Aggarwal Solutions Class 10. 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