{"id":29188,"date":"2018-07-18T06:12:57","date_gmt":"2018-07-18T06:12:57","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=29188"},"modified":"2020-12-01T11:35:02","modified_gmt":"2020-12-01T06:05:02","slug":"rs-aggarwal-solutions-class-9-chapter-7-areas","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/rs-aggarwal-solutions-class-9-chapter-7-areas\/","title":{"rendered":"RS Aggarwal Solutions Class 9 Chapter 7 Areas"},"content":{"rendered":"
RS Aggarwal Class 9 Solutions<\/a><\/p>\n Question 1:<\/strong><\/span> Question 2:<\/strong><\/span> Question 3:<\/strong><\/span> Question 4:<\/strong><\/span> Question 5:<\/strong><\/span> Question 6:<\/strong><\/span> Question 7:<\/strong><\/span> Question 8:<\/strong><\/span> Question 9:<\/strong><\/span> Question 10:<\/strong><\/span> Question 11:<\/strong><\/span> Question 12:<\/strong><\/span> Question 13:<\/strong><\/span> Question 14:<\/strong><\/span> Question 15:<\/strong><\/span> Question 16:<\/strong><\/span> Question 17:<\/strong><\/span> Question 18:<\/strong><\/span> Question 19:<\/strong><\/span> Question 20:<\/strong><\/span> Question 21:<\/strong><\/span> Question 22:<\/strong><\/span> Question 23:<\/strong><\/span> Question 24:<\/strong><\/span> RS Aggarwal Solutions Class 9 Chapter 7 Areas RS Aggarwal Class 9 Solutions Exercise 7A Question 1: Question 2: Question 3: Question 4: Question 5: Question 6: Question 7: Question 8: Question 9: Question 10: Question 11: Question 12: Question 13: Question 14: Question 15: (i) Area of an equilateral triangle =\u00a0 Where a is … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[6805],"tags":[],"yoast_head":"\nExercise 7A<\/span><\/strong><\/h3>\n
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\n(i) Area of an equilateral triangle =\u00a0\\(\\frac { \\sqrt { 3 } \u00a0}{ 4 } { a }^{ 2 } \u00a0\\)
\nWhere a is the side of the equilateral triangle
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