{"id":2541,"date":"2016-09-09T04:30:14","date_gmt":"2016-09-09T04:30:14","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=2541"},"modified":"2018-06-12T06:24:15","modified_gmt":"2018-06-12T06:24:15","slug":"types-of-factorization","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/types-of-factorization\/","title":{"rendered":"What Are The Types Of Factorization"},"content":{"rendered":"
Type I: Factorization by taking out the common factors.\u00a0 <\/strong><\/p>\n Example 1: \u00a0 \u00a0<\/strong>Factorize the following expression Type II: Factorization by grouping the terms.\u00a0\u00a0\u00a0 <\/strong><\/p>\n Example 2: \u00a0 \u00a0<\/strong>Factorize the following expression Type III: Factorization by making a perfect square.\u00a0\u00a0 <\/strong><\/p>\n Example 3: \u00a0 \u00a0<\/strong>Factorize of the following expression Example 4: \u00a0 \u00a0<\/strong>Factorize of the following expression Example 5: \u00a0 \u00a0<\/strong>Factorize of the following expression People also ask:<\/strong><\/p>\n Type IV: Factorizing by difference of two squares.<\/strong><\/p>\n Example 6: <\/strong>\u00a0 \u00a0Factorize\u00a0the following expressions Example 7: \u00a0 \u00a0<\/strong>Factorize 4x2<\/sup> + 12 xy + 9 y2<\/sup> Example 8: \u00a0 \u00a0<\/strong>Factorize each of the following expressions Example 9: \u00a0 \u00a0<\/strong>Factorize each of the following expressions Example 10: \u00a0 \u00a0<\/strong>Factorize the following algebraic expression Example 11: \u00a0 \u00a0<\/strong>Factorize the following expression Example 12: \u00a0 \u00a0<\/strong>Factorize the following expression Type V: Factorizing the sum and difference of cubes of two quantities.<\/strong> Example 13: \u00a0 \u00a0<\/strong>Factorize the following expression Example 14: \u00a0 \u00a0<\/strong>Simplify : (x+ y)3<\/sup> \u2013 (x \u2013y)3<\/sup>\u00a0\u2013 6y(x2<\/sup> \u2013 y2<\/sup>) Types Of Factorization Example Problems With Solutions Type I: Factorization by taking out the common factors.\u00a0 Example 1: \u00a0 \u00a0Factorize the following expression 2x2y + 6xy2\u00a0+ 10x2y2 Solution: \u00a0 \u00a02x2y + 6xy2\u00a0+ 10x2y2 =2xy(x + 3y + 5xy) Type II: Factorization by grouping the terms.\u00a0\u00a0\u00a0 Example 2: \u00a0 \u00a0Factorize the following expression a2 \u2013 b … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[5],"tags":[1088,1102,24,1101,1103],"yoast_head":"\n
\n2x2<\/sup>y + 6xy2<\/sup>\u00a0+ 10x2<\/sup>y2<\/sup>
\nSolution: \u00a0 \u00a0<\/strong>2x2<\/sup>y + 6xy2<\/sup>\u00a0+ 10x2<\/sup>y2<\/sup>
\n=2xy(x + 3y + 5xy)<\/p>\n
\na2<\/sup> \u2013 b + ab \u2013 a
\nSolution: \u00a0 \u00a0<\/strong>a2<\/sup> \u2013 b + ab \u2013 a
\n= a2<\/sup> + ab \u2013 b \u2013 a = (a2<\/sup> + ab) \u2013 (b + a)
\n= a (a + b) \u2013 (a + b) = (a + b) (a \u2013 1)<\/p>\n
\n9x2<\/sup> + 12xy + 4y2<\/sup>
\nSolution: \u00a0 \u00a0<\/strong>9x2<\/sup> + 12xy + 4y2<\/sup>
\n= (3x)2<\/sup> + 2 \u00d7 (3x) \u00d7 (2y) + (2y)2<\/sup>
\n= (3x + 2y)2<\/sup><\/p>\n
\n\\(\\frac{{{x}^{2}}}{{{y}^{2}}}+2+\\frac{{{y}^{2}}}{{{x}^{2\\prime }}},x\\ne 0,y\\ne 0\\)
\nSolution: \u00a0 \u00a0<\/strong>
\n<\/p>\n
\n\\({{\\left( 5x-\\frac{1}{x} \\right)}^{2}}+4\\left( 5x-\\frac{1}{x} \\right)+4,x\\ne 0\\)
\nSolution:<\/strong>
\n<\/p>\n\n
\n(a) 2x2<\/sup>y + 6 xy2<\/sup> + 10 x2<\/sup>y2<\/sup>
\n(b) 2x4<\/sup> + 2x3<\/sup>y + 3xy2<\/sup> + 3y3<\/sup>
\nSolution:<\/strong>
\n<\/p>\n
\nSolution:<\/strong>
\n<\/p>\n
\n(i) 9x2<\/sup> \u2013 4y2<\/sup>
\n(ii) x3<\/sup>\u00a0\u2013 x
\nSolution:<\/strong>
\n<\/p>\n
\n(i) 36x2<\/sup> \u2013 12x + 1 \u2013 25y2<\/sup>
\n\\(\\text{(ii) }{{a}^{2}}-\\frac{9}{{{a}^{2}}},a\\ne 0\\)
\nSolution:<\/strong>
\n<\/p>\n
\nx4<\/sup>\u00a0\u2013 81y4<\/sup>
\nSolution:<\/strong>
\n<\/p>\n
\nx(x+z) \u2013 y (y+z)
\nSolution: \u00a0 \u00a0<\/strong>x(x+z) \u2013 y (y+z) = (x2<\/sup> \u2013 y2<\/sup>) + (xz\u2013yz)
\n= (x\u2013y) (x+y) + z (x\u2013y)
\n= (x\u2013y) {(x+y) + z}
\n= (x\u2013y) (x+ y + z)<\/p>\n
\nx4<\/sup>\u00a0+ x2<\/sup>\u00a0+ 1
\nSolution: \u00a0 \u00a0<\/strong>x4<\/sup> + x2<\/sup> + 1 = (x4<\/sup> + 2x2<\/sup> +1) \u2013 x2<\/sup>
\n= (x2<\/sup> +1)2<\/sup> \u2013 x2<\/sup> = (x2<\/sup> + 1 \u2013 x) (x2<\/sup> + 1+x)
\n= (x2<\/sup>\u2013x + 1) (x2<\/sup> + x + 1)<\/p>\n
\n(i) (a3<\/sup> + b3<\/sup>) = (a + b) (a2<\/sup> \u2013 ab + b2<\/sup>)
\n(ii) (a3<\/sup> \u2013 b3<\/sup>) = (a \u2013 b) (a2<\/sup> + ab + b2<\/sup>)<\/p>\n
\na3<\/sup> + 27
\nSolution: \u00a0 <\/strong>a3<\/sup>\u00a0 + 27 = a3<\/sup>\u00a0 + 33<\/sup>\u00a0= (a + 3) (a2<\/sup>\u00a0\u20133a +9)<\/p>\n
\nSolution: \u00a0 \u00a0<\/strong>
\n<\/p>\n","protected":false},"excerpt":{"rendered":"