{"id":22988,"date":"2022-05-23T14:30:59","date_gmt":"2022-05-23T09:00:59","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=22988"},"modified":"2023-11-10T10:26:57","modified_gmt":"2023-11-10T04:56:57","slug":"selina-concise-mathematics-class-7-icse-solutions-percent-and-percentage","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/selina-concise-mathematics-class-7-icse-solutions-percent-and-percentage\/","title":{"rendered":"Selina Concise Mathematics class 7 ICSE Solutions – Percent and Percentage"},"content":{"rendered":"
ICSE Solutions<\/a>Selina ICSE Solutions<\/a>ML Aggarwal Solutions<\/a><\/p>\n APlusTopper.com provides step by step solutions for Selina Concise ICSE Solutions for Class 7 Mathematics. You can download the Selina Concise Mathematics ICSE Solutions for Class 7 with Free PDF download option. Selina Publishers Concise Mathematics for Class 7 ICSE Solutions all questions are solved and explained by expert mathematic teachers as per ICSE board guidelines.<\/p>\n Selina Class 7 Maths ICSE Solutions<\/a>Physics<\/a>Chemistry<\/a>Biology<\/a>Geography<\/a>History & Civics<\/a><\/p>\n POINTS TO REMEMBER<\/strong><\/p>\n EXERCISE 8 (A)<\/strong><\/span><\/p>\n Question 1.<\/strong><\/span> Solution :<\/strong><\/span> Question 2.<\/strong><\/span> Solution :<\/strong><\/span> Question 3.<\/strong><\/span> Solution :<\/strong><\/span> Question 4.<\/strong><\/span> Solution :<\/strong><\/span> Question 5.<\/strong><\/span> Solution :<\/strong><\/span> Question 6.<\/strong><\/span> Solution :<\/strong><\/span> Question 7.<\/strong><\/span> Solution :<\/strong><\/span> Question 8.<\/strong><\/span> Solution :<\/strong><\/span> Question 9.<\/strong><\/span> Solution :<\/strong><\/span> Question 10.<\/strong><\/span> Solution :<\/strong><\/span> Question 11.<\/strong><\/span> Solution :<\/strong><\/span> Question 12.<\/strong><\/span> Solution :<\/strong><\/span> EXERCISE 8 (B)<\/strong><\/span><\/p>\n Question 1.<\/strong><\/span> Solution :<\/strong><\/span> Question 2.<\/strong><\/span> Solution :<\/strong><\/span> Question 3.<\/strong><\/span> Solution :<\/strong><\/span> Question 4.<\/strong><\/span> Solution :<\/strong><\/span> Question 5.<\/strong><\/span> Solution :<\/strong><\/span> Question 6.<\/strong><\/span> Solution :<\/strong><\/span> Question 7.<\/strong><\/span> Solution :<\/strong><\/span> Question 8.<\/strong><\/span> Solution :<\/strong><\/span> Question 9.<\/strong><\/span> Solution :<\/strong><\/span> Question 10.<\/strong><\/span> Solution :<\/strong><\/span> Question 11.<\/strong><\/span> Solution :<\/strong><\/span> EXERCISE 8 (C)<\/strong><\/span><\/p>\n Question 1.<\/strong><\/span> Solution :<\/strong><\/span> Question 2.<\/strong><\/span> Solution :<\/strong><\/span> Question 3.<\/strong><\/span> Solution :<\/strong><\/span> Question 4.<\/strong><\/span> Solution :<\/strong><\/span> Question 5.<\/strong><\/span> Solution :<\/strong><\/span> Question 6.<\/strong><\/span> Solution :<\/strong><\/span> Question 7.<\/strong><\/span>\n
\n(i) Express the given statement as a fraction.
\n(ii) Convert this fraction into an equivalent fraction with denominator 100.
\nTherefore to express a fraction or a decimal as percent, multiply it by 100.<\/li>\n
\n(i) If necessary, convert with the quantitities into the same units.
\n(ii) From the fraction with the number to be compared as numerator and the number with which it is to be compared as denominator.
\n(iii) Multiply the fraction obtained by 100 and at the same time write the percent sign (%).<\/li>\n<\/ol>\n
\nExpress each of the following as percent :<\/strong>
\n<\/p>\n
\n<\/p>\n
\nExpress the following percentages as fractions and as decimal numbers :<\/strong>
\n<\/p>\n
\n
\n<\/p>\n
\nWhat percent is :<\/strong>
\n (i) 16 hours of 2 days ?<\/strong>
\n (ii) 40 paisa of Rs. 2 ?<\/strong>
\n (iii) 25 cm of 4 metres<\/strong>
\n (iv) 600 gm of 5 kg ?<\/strong><\/p>\n
\n
\n<\/p>\n
\nFind the value of:<\/strong>
\n<\/p>\n
\n<\/p>\n
\nIn a class of 60 children, 30% are girls. How many boys are there ?<\/strong><\/p>\n
\nTotal children = 60,
\nGirls = 30%
\n\u2234Total girls = 30% of 60 = 60 x \\(\\frac { 30 }{ 100 }\\)= 18
\n\u2234 No. of boys = 60 – 18 = 42<\/p>\n
\nIn an election, two candidates A and B contested. A got 60% of the votes. The total votes polled were 8000. How many votes did each get ?<\/strong><\/p>\n
\nTotal number of votes polled = 8000
\nA got 60% of the votes
\nA got total votes = 60% of 8000 = 8000 x \\(\\frac { 60 }{ 100 }\\) = 4800
\n\u2234 B got total votes = 8000 – 4800 = 3200<\/p>\n
\nA person saves 12% of his salary every month. If his salary is \u20b92,500, find his expenditure.<\/strong><\/p>\n
\nTotal salary = \u20b92500
\nSaving = 12% of the salary
\n\u2234 Total savings = 12% of \u20b92500
\n= \u20b92500 x\\(\\frac { 12 }{ 100 }\\) = \u20b9300
\n\u2234Total expenditure = \u20b92500 – \u20b9300 = \u20b92200<\/p>\n
\nSeeta got 75% marks out of a total of 800. How many marks did she lose ?<\/strong><\/p>\n
\nTotal marks = 800
\nMarks Seeta got = 75% of total marks
\n\u2234 Total marks Seeta got = 75% of 800
\n= 800 x \\(\\frac { 75 }{ 100 }\\) = 600
\n\u2234 Marks Seeta lose = 800 – 600 = 200<\/p>\n
\nA shop worth \u20b925,000 was insured for 95% of its value. How much would the owner get in case of any mishappening ?<\/strong><\/p>\n
\nValue of shop =\u20b925,000
\nInsured amount = 95% of total value
\n=95% of \u20b925,000
\n= \u20b925,000 x \\(\\frac { 95 }{ 100 }\\)
\n= \u20b9 23,750<\/p>\n
\nA class has 30 boys and 25 girls. What is the percentage of boys in the class ?<\/strong><\/p>\n
\nNo. of boys = 30
\nNo. of girls = 25
\nTotal number of children = 30 + 25 = 55
\n\u2234Percentage of boys in the class
\n= \\(\\frac { 30 }{ 55 }\\) x 100
\n= \\(\\frac { 600 }{ 11 }\\)=54\\(\\frac { 6 }{ 11 }\\) %<\/p>\n
\nExpress :<\/strong>
\n (i) 3 \\(\\frac { 2 }{ 5 }\\) as a percent<\/strong>
\n (ii) 0.0075 as percent<\/strong>
\n (iii) 3 : 20 as percent<\/strong>
\n (iv) 60 cm as percent of 1 m 25 cm<\/strong>
\n (v) 9 hours as a percent of 4 days.<\/strong><\/p>\n
\n
\n<\/p>\n
\n(i) Find 2% of 2 hours 30 min.<\/strong>
\n (ii) What percent of 12 kg is 725 gm?<\/strong><\/p>\n
\n<\/p>\n
\nDeepak bought a basket of mangoes containing 250 mangoes 12% of these were found to be rotten. Of the remaining, 10% got crushed. How many mangoes were in good condition ?<\/strong><\/p>\n
\n<\/p>\n
\nIn a Maths Quiz of 60 questions, Chandra got 90% correct answers and Ram got 80% correct answers. How many correct answers did each give ?<\/strong>
\n What percent is Ram\u2019s correct answers to Chandra\u2019s correct answers ?<\/strong><\/p>\n
\n
\n<\/p>\n
\nIn an examination, the maximum marks are 900. A student gets 33% of the maximum marks and fails by 45 marks. What is the passing mark ? Also, find the pass percentage.<\/strong><\/p>\n
\n<\/p>\n
\nIn a train, 15% people travel in first class, 35% travel in second class. The balance travel in the A.C. class ? Calculate the percentage of A.C. class travellers ?<\/strong><\/p>\n
\n<\/p>\n
\nA boy eats 25% of the cake and gives away 35% of it to his friends. What percent of the cake is still left with him ?<\/strong><\/p>\n
\n<\/p>\n
\nWhat is the percentage of vowels in the English alphabet ?<\/strong><\/p>\n
\n<\/p>\n
\n<\/p>\n
\n<\/p>\n
\nThe money spent on the repairs of a house was 1% of its value. If the repair, costs Rs. 5,000, find the cost of the house.<\/strong><\/p>\n
\n<\/p>\n
\nIn a school out of300 students, 70% are girls and 30% are boys. If 30 girls leave and no new boy is admitted, what is the new percentage of girls in the school ?<\/strong><\/p>\n
\n<\/p>\n
\nKumar bought a transistor for Rs. 960. He paid 12 \\(\\frac { 1 }{ 2 }\\) % cash money. The rest he agreed to pay in 12 equal monthly instalments. How much will he pay each month ?<\/strong><\/p>\n
\n
\n<\/p>\n
\nAn ore contains 20% zinc. How many kg of ore will be required to get 45 kg of zinc ?<\/strong><\/p>\n
\n<\/p>\n
\nThe salary of a man is increased from Rs. 600 per month to Rs. 850 per month. Express the increase in salary as percent.<\/strong><\/p>\n
\n<\/p>\n
\nIncrease :<\/strong>
\n (i) 60 by 5%<\/strong>
\n (ii) 20 by 15%<\/strong>
\n (iii) 48 by 121 %<\/strong>
\n (iv) 80 by 140%<\/strong>
\n (v) 1000 by 3.5%<\/strong><\/p>\n
\n
\n<\/p>\n
\nDecrease :<\/strong>
\n (i)80 by 20%<\/strong>
\n (ii) 300 by 10%<\/strong>
\n (iii) 50 by 12.5%<\/strong><\/p>\n
\n<\/p>\n
\nWhat number :<\/strong>
\n (i) When increased by 10% becomes 88 ?<\/strong>
\n (ii) When increased by 15% becomes 230 ?<\/strong>
\n (iii) When decreased by 15% becomes 170 ?<\/strong>
\n (iv) When decreased by 40% becomes 480 ?<\/strong>
\n (v) When increased by 100% becomes 100 ?<\/strong>
\n (vi) When decreased by 50% becomes 50 ?<\/strong><\/p>\n
\n
\n
\n<\/p>\n
\nThe price of a car is lowered by 20% to Rs. 40,000. What was the original price ? Also, find the reduction in price.<\/strong><\/p>\n
\nLet original price of the car = Rs. 100
\nReduction = 20%’ = Rs. 20
\n\u2234 Reduced price = Rs. 100 – 20 = Rs. 80
\nIf reduced price is Rs. 80, then original price = Rs. 100
\nand if reduced price is Rs. 40,000 then original price = \\(\\frac { Rs.100 x 40000 }{ 80 }\\)
\n= Rs. 50,000
\nand reduction = Rs. 50000 – Rs. 40000
\n= Rs. 10,000<\/p>\n
\nIf the price of an article is increased by 25%, The increase is Rs. 10. Find the new price.<\/strong><\/p>\n
\nLet the price of an article = Rs. 100
\nIncrease = 25%
\n\u2234Increase = Rs. 25
\nIf an increased price = Rs. 100 + 25 = Rs. 125
\nIf increase is Rs. 25 then new price = Rs. 125
\nand if increase is Rs. 10, then new price = Rs. \\(\\frac { 125 x 10 }{ 25 }\\)
\n= Rs. 50<\/p>\n
\nIf the price of an article is reduced by 10%, the reduction is Rs. 40. What is the old price ?<\/strong><\/p>\n