{"id":18781,"date":"2018-01-18T09:10:55","date_gmt":"2018-01-18T09:10:55","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=18781"},"modified":"2020-11-26T12:01:16","modified_gmt":"2020-11-26T06:31:16","slug":"math-labs-activity-pythagoras-theorem-method-2","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/math-labs-activity-pythagoras-theorem-method-2\/","title":{"rendered":"Math Labs with Activity – Pythagoras’ theorem (Method 2)"},"content":{"rendered":"
OBJECTIVE<\/strong><\/span><\/p>\n To verify Pythagoras’ theorem (Method 2)<\/p>\n Materials Required<\/strong><\/span><\/p>\n Theory<\/strong> <\/span> Procedure<\/strong> <\/span> Observations and Calculations<\/strong><\/span> Result<\/strong> <\/span> Remarks:<\/strong> Math Labs with Activity<\/a>Math Labs<\/a>Science Practical Skills<\/a>Science Labs<\/a><\/p>\n","protected":false},"excerpt":{"rendered":" Math Labs with Activity – Pythagoras theorem (Method 2) OBJECTIVE To verify Pythagoras’ theorem (Method 2) Materials Required A piece of cardboard Two sheets of white paper A pair of scissors A geometry box A tube of glue Theory Pythagoras’ theorem: In a right-angled triangle, the square of the hypotenuse is equal to the sum … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[6805],"tags":[],"yoast_head":"\n\n
\nPythagoras’ theorem:<\/strong> In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.<\/p>\n
\nStep 1:<\/strong>\u00a0Paste a sheet of white paper on the cardboard.
\n” On this paper, draw a right-angled triangle ABC, right angled at C. Let the lengths of the sides AB, BC and CA be c, a and b units respectively (see Figure 10.1).
\n
\nStep 2:<\/strong> Make four exact copies of the right-angled \u0394ABC on the other sheet of paper. Also, construct a square with each side measuring c units.
\nStep 3:<\/strong> Cut these four triangles and the square, arid arrange them as shown in Figure 10.2.
\n<\/p>\n
\nWe observe that by the combination of the square and the four triangles, a new square is formed which clearly has each side equal to (a+b) units. Then,
\narea of the large square formed = area of the square with side c + 4 (area of \u0394ABC)
\ni.e., (a+b)\u00b2 =c\u00b2 +4 (\u00bd x a x b)\u00a0 \u00a0 \u00a0[\u2234<\/strong>\u00a0area of \u0394ABC =\u00a0\u00bd (a x b)]
\n=> (a\u00b2 + b\u00b2 + 2ab) =c\u00b2 + 2ab
\n=> a\u00b2 + b\u00b2 =c\u00b2.
\nSo, the square of the hypotenuse of right-angled \u0394ABC is equal to the sum of the squares of the other two sides.<\/p>\n
\nPythagoras’ theorem is verified.<\/p>\n
\nThis method is just a process of verification of Pythagoras’ theorem and cannot be used as a proof for the theorem.<\/p>\n