{"id":15857,"date":"2022-05-14T01:30:20","date_gmt":"2022-05-13T20:00:20","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=15857"},"modified":"2023-11-10T12:07:42","modified_gmt":"2023-11-10T06:37:42","slug":"selina-icse-solutions-class-10-biology-transpiration","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/selina-icse-solutions-class-10-biology-transpiration\/","title":{"rendered":"Selina Concise Biology Class 10 ICSE Solutions Transpiration"},"content":{"rendered":"

Selina Concise Biology Class 10 ICSE Solutions Transpiration<\/span><\/h2>\n

APlusTopper.com provides step by step solutions for Selina Concise ICSE Solutions for Class 10 Biology Chapter 5 Transpiration. You can download the Selina Concise Biology ICSE Solutions for Class 10 with Free PDF download option. Selina Publishers Concise Biology for Class 10 ICSE Solutions all questions are solved and explained by expert teachers as per ICSE board guidelines.<\/p>\n

Download Formulae Handbook For ICSE Class 9 and 10<\/a><\/p>\n

ICSE Solutions<\/a>Selina ICSE Solutions<\/a><\/p>\n

Selina ICSE Solutions for Class 10 Biology Chapter 5 Transpiration<\/strong><\/p>\n

Exercise 2<\/strong><\/span><\/p>\n

Solution A.1.<\/strong><\/span>
\n(a) Open stomata, dry atmosphere and moist soil<\/p>\n

Solution A.2.<\/strong><\/span>
\n(a) increase<\/p>\n

Solution A.3.<\/strong><\/span>
\n(b) temperature is high<\/p>\n

Solution A.4.<\/strong><\/span>
\n(c) sunken stomata<\/p>\n

Solution A.5.<\/strong><\/span>
\n(d) hydathodes<\/p>\n

Solution A.6.<\/strong><\/span>
\n(d) transpiration<\/p>\n

Solution A.7.<\/strong><\/span>
\n(d) hot, dry and windy<\/p>\n

Solution A.8.<\/strong><\/span>
\n(b) Lenticels<\/p>\n

Solution A.9.<\/strong><\/span>
\n(b) evaporation of water from the aerial surfaces of a plant<\/p>\n

Solution B.1.<\/strong><\/span>
\n(a) Lenticels
\n(b) Guttation
\n(c) Potometer
\n(d) Nerium
\n(e) Ganong’s photometer
\n(f) Stomata and cuticle
\n(g) Hydathodes
\n(h) Guttation<\/p>\n

Solution B.2.<\/strong><\/span>
\n(a) vapour, aerial
\n(b) stomata, transpiration
\n(c) suction, water (heat)<\/p>\n

Solution C.1.<\/strong><\/span>
\n(a) guttation
\n(b) protection and reduced transpiration
\n(c) transpiration
\n(d) reduced transpiration<\/p>\n

Solution C.2.<\/strong><\/span>
\n(i) False
\n(ii) True
\n(iii) True
\n(iv) False
\n(v) Most transpiration occurs at mid-day.
\n(vi) Potometer is an instrument used for measuring the rate of transpiration in green plants.<\/p>\n

Solution C.3.<\/strong><\/span>
\n(a) Transpiration increases with the velocity of wind. If the wind blows faster, the water vapours released during transpiration are removed faster and the area surrounding the transpiring leaf does not get saturated with water vapour.<\/p>\n

(b) When the rate of transpiration far exceeds the rate of absorption of water by roots, the cells lose their turgidity. Hence, excessive transpiration results in wilting of the leaves.<\/p>\n

(c) Plants absorb water continuously through their roots, which is then conducted upwards to all the aerial parts of the plant, including the leaves. Only a small quantity of this water i.e. about 0.02% is used for the photosynthesis and other activities. The rest of the water is transpired as water vapour. Hence water transpired is the water absorbed.<\/p>\n

(d) There are more stomatal openings on the lower surface of a dorsiventral leaf. More the number of stomata, higher is the rate of transpiration. Hence more transpiration occurs from the lower surface.<\/p>\n

(e) Cork and Bark of trees are tissues of old woody stems. Bark is thick with outermost layer made of dead cells and the cork is hydrophobic in nature. These properties make them water-proof and hence they prevent transpiration.<\/p>\n

(f) In both perspiration and transpiration, water is lost by evapouration from the body of the organism as water vapour. This evaporation reduces the temperature of the body surface and brings about cooling in the body of the organism.<\/p>\n

(g) On a bright sunny day, the rate of transpiration is much higher than any other days. The leaves of certain plants roll up on a bright sunny day to reduce the exposed surface and thus reduce the rate of transpiration.<\/p>\n

Solution C.4.<\/strong><\/span>
\n(a) False
\nReason: Potometer is used to measure the rate of transpiration in a plant. Demonstration of transpiration occurring from the lower surface of a leaf is done by analyzing the changes in colour of pieces of dry cobalt chloride paper attached (and held in place) to the two surfaces of a leaf.<\/p>\n

(b) True
\nReason: Transpiration carried out by the large number of trees in a forest. This increases the moisture in the atmosphere and brings rain.<\/p>\n

(c) False
\nReason: Hydathodes are special pores present on the ends of leaf veins through which guttation occurs and water droplets are given out. Their openings cannot be regulated. Stomata on the other hand are minute openings in the epidermal layer of leaves through which exchange of gases as well as transpiration occurs. Water is given out as water vapour. Stomatal opening is regulated by guard cells.<\/p>\n

(d) False
\nReason: Transpiration is reduced during high atmospheric humidity. High humidity in the air reduces the rate of outward diffusion of the internal water vapour across stomata, thereby reducing the rate of transpiration.<\/p>\n

(e) True
\nReason: Desert plants need to reduce transpiration as much as possible so as to survive in the hot and dry environment. Hence some of them have sunken stomata as an adaptation to curtail transpiration.<\/p>\n

(f) True
\nReason: During the day, the stomata are open to facilitate the inward diffusion of carbon dioxide for photosynthesis. During mid-day, the outside temperature is higher, due to which there is more evaporation of water from the leaves. Therefore more transpiration occurs during mid-day.<\/p>\n

Solution C.5.<\/strong><\/span><\/p>\n\n\n\n\n\n
Guttation<\/strong><\/td>\nBleeding<\/strong><\/td>\n<\/tr>\n
It is the removal of excess of water from the plants because of excess water buildup in the plant.<\/td>\nIt is the removal of water from the plant because of injury.<\/td>\n<\/tr>\n
Water escapes from\u00a0specialisedstructures called\u00a0hydathodes.<\/td>\nWater escapes in the form of sap from the injured part of the plant.<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Solution D.1.<\/strong><\/span>
\nWilting refers to the loss of cellular turgidity in plants which results in the drooping of leaves or plant as a whole because of lack of water.
\nDuring noon the rate of transpiration exceeds the rate of absorption of water by roots. Due to the excessive transpiration, the cells of leaves lose their turgidity and wilt.<\/p>\n

Solution D.2.<\/strong><\/span>
\nThe lower surface of leaf is sheltered from direct sunlight. If more stomata are on the upper surface of a leaf, then excessive transpiration would occur, resulting in quick wilting of the plant. Hence most plants have more numerous stomata on the lower surface of a leaf to control the rate of transpiration.<\/p>\n

Solution D.3.<\/strong><\/span>
\nTake the small potted rose plant and cover it with a transparent polythene bag. Tie its mouth around the base of the stem. Leave the plant in sunlight for an hour or two.
\n\"Selina
\nDrops of water will soon appear on the inner side of the bag due to the saturation of water vapour given out by the leaves. A similar empty polythene bag with its mouth tied and kept in sunlight will show no drops of water. This is the control to show that plants transpire water in the form of water. If tested with dry cobalt chloride paper, the drops will be confirmed as water only.<\/p>\n

Solution D.4.<\/strong><\/span>
\n\"Selina
\nPotometer is a device that measures the rate of water intake by a plant. This water intake is almost equal to the water lost through transpiration. Potometers do not measure the water lost due to transpiration but measure the water uptake by the shoot.<\/p>\n

Solution D.5.<\/strong><\/span><\/p>\n