{"id":15821,"date":"2022-05-26T16:00:34","date_gmt":"2022-05-26T10:30:34","guid":{"rendered":"https:\/\/cbselibrary.com\/?p=15821"},"modified":"2023-11-10T09:40:18","modified_gmt":"2023-11-10T04:10:18","slug":"selina-icse-solutions-class-10-maths-section-mid-point-formula","status":"publish","type":"post","link":"https:\/\/cbselibrary.com\/selina-icse-solutions-class-10-maths-section-mid-point-formula\/","title":{"rendered":"Selina Concise Mathematics Class 10 ICSE Solutions Section and Mid-Point Formula"},"content":{"rendered":"
Selina Publishers Concise Mathematics Class 10 ICSE Solutions Chapter 13\u00a0Section and Mid-Point Formula<\/strong><\/p>\n Question 1.<\/strong><\/span> Question 2.<\/strong><\/span> Question 3.<\/strong><\/span> Question 4.<\/strong><\/span> Question 5.<\/strong><\/span> Question 6.<\/strong><\/span> Question 7.<\/strong><\/span> Question 8.<\/strong><\/span> Question 9.<\/strong><\/span> Question 10.<\/strong><\/span> Question 11.<\/strong><\/span> Question 12.<\/strong><\/span> Question 13.<\/strong><\/span> Question 14.<\/strong><\/span> Question 15.<\/strong><\/span> Question 16.<\/strong><\/span> Question 17.<\/strong><\/span> Question 18.<\/strong><\/span> Question 19.<\/strong><\/span> Question 20.<\/strong><\/span> Question 21.<\/strong><\/span> Question 22.<\/strong><\/span> Question 23.<\/strong><\/span> Question 24.<\/strong><\/span> Question 25.<\/strong><\/span> Question 26. Question 1.<\/strong><\/span> Question 2.<\/strong><\/span> Question 3.<\/strong><\/span> Question 4.<\/strong><\/span> Question 5.<\/strong><\/span> Question 6.<\/strong><\/span> Question 7.<\/strong><\/span> Question 8.<\/strong><\/span> Question 9.<\/strong><\/span> Question 10.<\/strong><\/span> Question 11.<\/strong><\/span> Question 12.<\/strong><\/span> Question 13.<\/strong><\/span> Question 14.<\/strong><\/span> Question 15.<\/strong><\/span> Question 16.<\/strong><\/span> Question 17.<\/strong><\/span> Question 18.<\/strong><\/span> Question 1.<\/strong><\/span> Question 2.<\/strong><\/span> Question 3.<\/strong><\/span> Question 4.<\/strong><\/span> Question 5.<\/strong><\/span>Section and Mid-Point Formula Exercise 13A – Selina Concise Mathematics Class 10 ICSE Solutions<\/h3>\n
\nCalculate the co-ordinates of the point P which divides the line segment joining:
\n(i) A (1, 3) and B (5, 9) in the ratio 1: 2.
\n(ii) A (-4, 6) and B (3, -5) in the ratio 3: 2.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nIn what ratio is the line joining (2, -3) and (5, 6) divided by the x-axis.
\nSolution:<\/strong><\/span>
\nLet the line joining points A (2, -3) and B (5, 6) be divided by point P (x, 0) in the ratio k: 1.
\n
\nThus, the required ratio is 1: 2.<\/p>\n
\nIn what ratio is the line joining (2, -4) and (-3, 6) divided by the y-axis.
\nSolution:<\/strong><\/span>
\nLet the line joining points A (2, -4) and B (-3, 6) be divided by point P (0, y) in the ratio k: 1.
\n
\nThus, the required ratio is 2: 3.<\/p>\n
\nIn what ratio does the point (1, a) divided the join of (-1, 4) and (4, -1)? Also, find the value of a.
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\nIn what ratio does the point (a, 6) divide the join of (-4, 3) and (2, 8)? Also, find the value of a.
\nSolution:<\/strong><\/span>
\nLet the point P (a, 6) divides the line segment joining A (-4, 3) and B (2, 8) in the ratio k: 1.
\nUsing section formula, we have:
\n<\/p>\n
\nIn what ratio is the join of (4, 3) and (2, -6) divided by the x-axis. Also, find the co-ordinates of the point of intersection.
\nSolution:<\/strong><\/span>
\nLet the point P (x, 0) on x-axis divides the line segment joining A (4, 3) and B (2, -6) in the ratio k: 1.
\nUsing section formula, we have:
\n<\/p>\n
\nFind the ratio in which the join of (-4, 7) and (3, 0) is divided by the y-axis. Also, find the coordinates of the point of intersection.
\nSolution:<\/strong><\/span>
\nLet S (0, y) be the point on y-axis which divides the line segment PQ in the ratio k: 1.
\nUsing section formula, we have:
\n
\n<\/p>\n
\nPoints A, B, C and D divide the line segment joining the point (5, -10) and the origin in five equal parts. Find the co-ordinates of A, B, C and D.
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\nThe line joining the points A (-3, -10) and B (-2, 6) is divided by the point P such that \\(\\frac { PB }{ AB } =\\frac { 1 }{ 5 }\\) Find the co-ordinates of P.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nP is a point on the line joining A (4, 3) and B (-2, 6) such that 5AP = 2BP. Find the co-ordinates of P.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nCalculate the ratio in which the line joining the points (-3, -1) and (5, 7) is divided by the line x = 2. Also, find the co-ordinates of the point of intersection.
\nSolution:<\/strong><\/span>
\nThe co-ordinates of every point on the line x = 2 will be of the type (2, y).
\nUsing section formula, we have:
\n
\nThus, the required co-ordinates of the point of intersection are (2, 4).<\/p>\n
\nCalculate the ratio in which the line joining A (6, 5) and B (4, -3) is divided by the line y = 2.
\nSolution:<\/strong><\/span>
\nThe co-ordinates of every point on the line y = 2 will be of the type (x, 2).
\nUsing section formula, we have:
\n<\/p>\n
\nThe point P (5, -4) divides the line segment AB, as shown in the figure, in the ratio 2: 5. Find the co-ordinates of points A and B.
\n
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nFind the co-ordinates of the points of trisection of the line joining the points (-3, 0) and (6, 6).
\nSolution:<\/strong><\/span>
\nLet P and Q be the point of trisection of the line segment joining the points A (-3, 0) and B (6, 6).
\nSo, AP = PQ = QB
\n<\/p>\n
\nShow that the line segment joining the points (-5, 8) and (10, -4) is trisected by the co-ordinate axes.
\nSolution:<\/strong><\/span>
\nLet P and Q be the point of trisection of the line segment joining the points A (-5, 8) and B (10, -4).
\nSo, AP = PQ = QB
\n
\nSo, point Q lies on the x-axis.
\nHence, the line segment joining the given points A and B is trisected by the co-ordinate axes.<\/p>\n
\nShow that A (3, -2) is a point of trisection of the line-segment joining the points (2, 1) and (5, -8). Also, find the co-ordinates of the other point of trisection.
\nSolution:<\/strong><\/span>
\nLet A and B be the point of trisection of the line segment joining the points P (2, 1) and Q (5, -8).
\nSo, PA = AB = BQ
\n<\/p>\n
\nIf A = (-4, 3) and B = (8, -6)
\n(i) Find the length of AB.
\n(ii) In what ratio is the line joining A and B, divided by the x-axis?
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nThe line segment joining the points M (5, 7) and N (-3, 2) is intersected by the y-axis at point L. Write down the abscissa of L. Hence, find the ratio in which L divides MN. Also, find the co-ordinates of L.
\nSolution:<\/strong><\/span>
\nSince, point L lies on y-axis, its abscissa is 0.
\nLet the co-ordinates of point L be (0, y). Let L divides MN in the ratio k: 1.
\n<\/p>\n
\nA (2, 5), B (-1, 2) and C (5, 8) are the co-ordinates of the vertices of the triangle ABC. Points P and Q lie on AB and AC respectively, such that AP: PB = AQ: QC = 1: 2.
\n(i) Calculate the co-ordinates of P and Q.
\n(ii) Show that PQ = 1\/3 BC.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nA (-3, 4), B (3, -1) and C (-2, 4) are the vertices of a triangle ABC. Find the length of line segment AP, where point P lies inside BC, such that BP: PC = 2: 3.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nThe line segment joining A (2, 3) and B (6, -5) is intercepted by x-axis at the point K. Write down the ordinate of the point K. Hence, find the ratio in which K divides AB. Also, find the co-ordinates of the point K.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nThe line segment joining A (4, 7) and B (-6, -2) is intercepted by the y-axis at the point K. Write down the abscissa of the point K. Hence, find the ratio in which K divides AB. Also, find the co-ordinates of the point K.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nThe line joining P (-4, 5) and Q (3, 2) intersects the y-axis at point R. PM and QN are perpendiculars from P and Q on the x-axis. Find:
\n(i) the ratio PR: RQ.
\n(ii) the co-ordinates of R.
\n(iii) the area of the quadrilateral PMNQ.
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\nIn the given figure, line APB meets the x-axis at point A and y-axis at point B. P is the point (-4, 2) and AP: PB = 1: 2. Find the co-ordinates of A and B.
\n
\nSolution:<\/strong><\/span>
\nGiven, A lies on x-axis and B lies on y-axis.
\nLet the co-ordinates of A and B be (x, 0) and (0, y) respectively.
\nGiven, P is the point (-4, 2) and AP: PB = 1: 2.
\nUsing section formula, we have:
\n
\nThus, the co-ordinates of points A and B are (-6, 0) and (0, 6) respectively.<\/p>\n
\nGiven a line segment AB joining the points A(-4, 6) and B(8, -3). Find:
\n(i) the ratio in which AB is divided by the y-axis
\n(ii) find the coordinates of the point of intersection
\n(iii) the length of AB
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\n<\/strong><\/span>If P(-b, 9a – 2) divides the line segment joining the points A(-3, 3a + 1) and B(5, 8a) in the ratio 3: 1, find the values of a and b.
\nSolution:<\/strong><\/span>
\n<\/b>Take (x1<\/sub>\u00a0, y1<\/sub>) =\u00a0(-3, 3a + 1) ;\u00a0(x2<\/sub>\u00a0, y2<\/sub>) =\u00a0B(5, 8a) and
\n<\/b>(x, y) = (-b, 9a – 2)
\nHere m1<\/sub>\u00a0= 3 and m2<\/sub>\u00a0=1
\n<\/p>\nSection and Mid-Point Formula Exercise 13B – Selina Concise Mathematics Class 10 ICSE Solutions<\/h3>\n
\nFind the mid-point of the line segment joining the points:
\n(i) (-6, 7) and (3, 5)
\n(ii) (5, -3) and (-1, 7)
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nPoints A and B have co-ordinates (3, 5) and (x, y) respectively. The mid-point of AB is (2, 3). Find the values of x and y.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nA (5, 3), B (-1, 1) and C (7, -3) are the vertices of triangle ABC. If L is the mid-point of AB and M is the mid-point of AC, show that LM = 1\/2 BC.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nGiven M is the mid-point of AB, find the co-ordinates of:
\n(i) A; if M = (1, 7) and B = (-5, 10)
\n(ii) B; if A = (3, -1) and M = (-1, 3).
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nP (-3, 2) is the mid-point of line segment AB as shown in the given figure. Find the co-ordinates of points A and B.
\n
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nIn the given figure, P (4, 2) is mid-point of line segment AB. Find the co-ordinates of A and B.
\n
\nSolution:<\/strong><\/span>
\n<\/p>\n
\n(-5, 2), (3, -6) and (7, 4) are the vertices of a triangle. Find the lengths of its median through the vertex (3, -6)
\nSolution:<\/strong><\/span>
\nLet A (-5, 2), B (3, -6) and C (7, 4) be the vertices of the given triangle.
\nLet AD be the median through A, BE be the median through B and CF be the median through C.
\n
\nWe know that median of a triangle bisects the opposite side.
\n<\/p>\n
\nGiven a line ABCD in which AB = BC = CD, B = (0, 3) and C = (1, 8). Find the co-ordinates of A and D.
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\nOne end of the diameter of a circle is (-2, 5). Find the co-ordinates of the other end of it, if the centre of the circle is (2, -1).
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nA (2, 5), B (1, 0), C (-4, 3) and D (-3, 8) are the vertices of a quadrilateral ABCD. Find the co-ordinates of the mid-points of AC and BD.
\nGive a special name to the quadrilateral.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nP (4, 2) and Q (-1, 5) are the vertices of a parallelogram PQRS and (-3, 2) are the co-ordinates of the points of intersection of its diagonals. Find the coordinates of R and S.
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\nA (-1, 0), B (1, 3) and D (3, 5) are the vertices of a parallelogram ABCD. Find the co-ordinates of vertex C.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nThe points (2, -1), (-1, 4) and (-2, 2) are mid-points of the sides of a triangle. Find its vertices.
\nSolution:<\/strong><\/span>
\n
\n
\n<\/p>\n
\nPoints A (-5, x), B (y, 7) and C (1, -3) are collinear (i.e., lie on the same straight line) such that AB = BC. Calculates the values of x and y.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nPoints P (a, -4), Q (-2, b) and R (0, 2) are collinear. If Q lies between P and R, such that PR = 2QR, calculate the values of a and b.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nCalculate the co-ordinates of the centroid of a triangle ABC, if A = (7, -2), B = (0, 1) and C = (-1, 4).
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nThe co-ordinates of the centroid of a PQR are (2, -5). If Q = (-6, 5) and R = (11, 8); calculate the co-ordinates of vertex P.
\nSolution:<\/strong><\/span>
\nLet G be the centroid of DPQR whose coordinates are (2, -5) and let (x,y) be the coordinates of vertex P.
\n<\/p>\n
\nA (5, x), B (-4, 3) and C (y, -2) are the vertices of the triangle ABC whose centroid is the origin. Calculate the values of x and y.
\nSolution:<\/strong><\/span>
\n<\/p>\nSection and Mid-Point Formula Exercise 13C – Selina Concise Mathematics Class 10 ICSE Solutions<\/h3>\n
\nGiven a triangle ABC in which A = (4, -4), B = (0, 5) and C = (5, 10). A point P lies on BC such that BP: PC = 3: 2. Find the length of line segment AP.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nA (20, 0) and B (10, -20) are two fixed points. Find the co-ordinates of a point P in AB such that: 3PB = AB. Also, find the co-ordinates of some other point Q in AB such that AB = 6AQ.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nA (-8, 0), B (0, 16) and C (0, 0) are the vertices of a triangle ABC. Point P lies on AB and Q lies on AC such that AP: PB = 3: 5 and AQ: QC = 3: 5. Show that: PQ = 3\/8 BC.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nFind the co-ordinates of points of trisection of the line segment joining the point (6, -9) and the origin.
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nA line segment joining A(-1, 5\/3) and B (a, 5) is divided in the ratio 1: 3 at P, point where the line segment AB intersects the y-axis.
\n(i) Calculate the value of ‘a’.
\n(ii) Calculate the co-ordinates of ‘P’.
\nSolution:<\/strong><\/span>