## Linear Equations In One Variable

A statement of equality of two algebraic expressions, which involve one or more unknown quantities is known as an equation.
A linear equation is an equation which involves linear polynomials.
A value of the variable which makes the two sides of the equation equal is called the solution of the equation.
Same quantity can be added/subtracted to/from both the sides of an equation without changing the equality.
Both the sides of an equation can be multiplied/divided by the same non-zero number without changing the equality.

GENERAL FORM OF LINEAR EQUATION IN TWO VARIABLES

ax + by + c = 0, a ≠ 0, b ≠ 0 or any one from a & b can zero.

## General Form Of Linear Equation In Two Variables Example Problems With Solutions

### Example 1:    Express the following linear equations in general form and identify coefficients of x, y and constant term.Solution:Make linear equation by the following statements:

Example 2:     The cost of 2kg of apples and 1 kg of grapes on a day was found to be 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is 300. Represent the situation algebraically.
Solution:    Let cost of per kg apples & grapes are x & y respectively then by Ist condition:
2x + y = 160       ……(i)
& by IInd condition: 4x + 2y = 300         …..(ii)

Example 3:    The coach of a cricket team buys 3 bats and 6 balls for 3900. Later, she buys another bat and 3 more balls of the same kind for 1300. Represent this situation algebraically.
Solution:    Let cost of a bat and a ball are x & y respectively. According to questions
3x + 6y = 3900        …..(i)
& x + 3y = 1300       …..(ii)

Example 4:    10 students of class IX took part in a Mathematics quiz. If the number of girls is 4 more than the number of boys.
Solution:    Let no. of boys and girls are x & y then according to question
x + y = 10          ……(i)
& y = x + 4         ……(ii)

Example 5:    Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is
36 m.
Solution:     Let length & breadth are x m and y m.
∴ according to question 1/2 perimeter = 36
1/2 [2(l + b)] = 36
⇒ x + y = 36        …..(i)
also length = 4 + breadth
x = 4 + y         ..…(ii)

Example 6:     The difference between two numbers is 26 and one number is three times the other.
Solution:    Let the numbers are x and y & x > y
∴ x – y = 26       ……(i)
and  x = 3y ……(ii)

Example 7:    The larger of two supplementary angles exceeds the smaller by 18 degrees.
Solution:    Sol. Let the two supplementary angles are x and y & x > y
Then x + y = 180°    ……(i)
and   x = y + 18°       ……(ii)

Example 8:    A fraction becomes 9/11, if 2 is added to both the numerator and the denominator. If, 3 is added to both the numerator and the denominator it becomes 5/6.
Solution:    Let fraction is x/y
Now according to question    $$\frac{x+2}{y+2}=\frac{9}{11}$$
⇒ 11x + 22 = 9y + 18
⇒ 11x – 9y = – 4          …..(i)
and
$$\frac{x+3}{y+3}=\frac{5}{6}$$
⇒ 6x + 18 = 5y + 15
⇒ 6x – 5y = –3           ….(ii)

Example 9:    Five years hence, the age of Sachin will be three times that of his son. Five years ago, Sachin’s age was seven times that of his son.
Solution:    Let present ages of Sachin & his son are
x years and y years.
Five years hence,
age of Sachin = (x + 5) years & his son’s age = (y + 5) years
according to question (x + 5) = 3(y + 5)
⇒ x + 5 = 3y + 15
⇒ x – 3y = 10          ……(i)
and 5 years ago age of both were (x – 5) years and (y – 5) years respectively
according to question (x – 5) = 7(y – 5)
⇒ x – 5 = 7y – 35
⇒ x – 7y = –30      .…(ii)

## Glencoe Algebra 1 Solutions Chapter 3 Solving Linear Equations Exercise 3.9

Glencoe Algebra 1 Solutions Chapter 3 Solving Linear Equations Exercise 3.9

## Glencoe Algebra 1 Solutions Chapter 3 Solving Linear Equations Exercise 3.8

Glencoe Algebra 1 Solutions Chapter 3 Solving Linear Equations Exercise 3.8

## Glencoe Algebra 1 Solutions Chapter 3 Solving Linear Equations Exercise 3.6

Glencoe Algebra 1 Solutions Chapter 3 Solving Linear Equations Exercise 3.6

## Glencoe Algebra 1 Solutions Chapter 3 Solving Linear Equations Exercise 3.7

Glencoe Algebra 1 Solutions Chapter 3 Solving Linear Equations Exercise 3.7

.