New Simplified Chemistry Class 10 ICSE Solutions – Nitric Acids

New Simplified Chemistry Class 10 ICSE Solutions -Study Of Compounds – Nitric Acids

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QUESTIONS
2000

Question 1.
What do you see when concentrated nitric acid is added to copper.
Answer:
A pungent smelling reddish brown coloured gas (NO2) is produced and the solution turns greenish blue.
Cu + 4HNO3 (cone.) → Cu (NO3)2 + 2H2O + 2NO2

2001

Question 1.
Name the gas produced in the reaction:
Action of concentrated nitric acid on copper.
Answer:
Nitrogen dioxide.

Question 2.
Choose the correct word from the brackets to complete the sentence. Sodium nitrate reacts with — (concentrated / dilute) sulphuric acid to produce nitric acid. Write equation for the same.
Answer:
Sodium nitrate reacts with concentrated sulphuric acid to produce nitric acid.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 1

Question 3.
Write the equations for the following reaction : Between copper and concentrated nitric acid.
Answer:
Cu + 4HNO3 (cone.) → Cu (NO3)2 + 2H2O+ 2NO2

Question 4.
From the formulae listed below, choose, one, corresponding to the salt having the given description:
AgCl, CuCO3, CuSO4. 5H2O, KNO3, NaCl, NaHSO,, Pb(NO3)2, ZnCO3, ZnSO4.7H2O.
This salt gives nitrogen dioxide on heating.
Answer:
Pb(NO3)2
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 2

2002

Question 1.
Give equations for the action of heat on –
(1) NH4Cl
(2) NH4NO3.
State whether each reaction is an example of thermal decomposition   or thermal dissociation.
(1) Dissociation
(2) decomposition
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 3

Question 2.
What compounds are required for the laboratory preparation of nitric acid.
Answer:
Potassium nitrate and cone, sulphuric acid.

Question 3.
State why pure nitric acid takes on a yellowish brown colour when exposed to light.
Answer:
In the presence of sunlight nitric acid decomposes even at room temperature to give nitrogen dioxide, water and oxygen.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 4

The NO2 so produced dissolves in cone. HNO3. The yellow colour of cone, nitric acid is due to NO2 dissolved in it.

Question 4.
Write an equation for the following reaction:
Copper and concentrated nitric acid.
Answer:
Cu + 4HNO3 (cone.) → Cu (NO3)2 + 2H2O + 2NO2.

Question 5.
The first step in the manufacture of HNO3 is the catalytic oxidation of NH3. Name the catalyst used.
Answer:
Platinum.

2003

Question 1.
Name a solution which gives nitrogen dioxide with copper.
Answer:
Concentrated nitric acid (HNO3).

Question 2.
When nitric acid is prepared by the action of concentrated sulphuric acid on potassium nitrate, what is the special feature of the apparatus used.
Answer:
All glass apparatus is used in the laboratory preparation of nitric acid.

Question 3.
Write the equation for the lab. preparation of H2NO3 from potassium nitrate and cone. H2SO4.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 5
Question 4.
Potassium nitrate prepared from KOH and nitric acid. State the type of reaction involved.
Answer:
Neutralization reaction.

Question 5.
State the cone, acid which will oxidise sulphur directly to H2SO4. Write the equation for the same.
Answer:
Hot and cone, nitric acid will oxidises sulphur directly to sulphuric acid.
S + 6HNO3 → H2SO4 + 2H2O + 6NO2

2004

Question 1.
X, Y and Z are three crystalline solids which are soluble in water and have a common anion. To help you
to identify X, Y and Z, you are provided with the following experimental observations. Copy and complete the corresponding inferences in.
A reddish-brown gas is obtained when X, Y and Z are separately warmed with concentrated sulphuric acid and copper turnings added to the mixture. The common anion is the ion.
Answer:
[NO] Nitrate

Question 2.
Write a balanced equation for the reaction of cone. HNO3 when added to copper turnings kept in a beaker.
Answer:
Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O

Question 3.
Write a balanced equation for the reaction of cone. HN03 when added to copper turnings kept in a beaker.
Answer:
Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O

              2005

Question 1.
Write a balanced equation for the reaction of – sulphur and hot concentrated nitric acid.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 6

Question 2.
Dilute nitric acid is generally considered a typical acid except for its reaction with metals. In what way is dilute nitric acid different from other acids when it reacts with metals.
Answer:
Metals, lying above hydrogen in the electro chemical series, give hydrogen from the acid. In case of nitric acid which is a strong oxidising agent, hydrogen produced in the nascent state reduces excess nitric acid and produces water and a reduction productof nitric acid. The reduction product depends on the dilution of the acid.

Question 3.
Write the equation for the reaction of dilute nitric acid with copper.
Answer:
3Cu + 8HNO3 → 3Cu(NO3)2 + 4H2O + 2NO

Question 4.
State why a yellow colour that appears in concentrated  nitric acid when it is left standing in an ordinary glass bottle.
Ans.
It turns yellow because cone. HNO3 decomposes by the action of sunlight to give brown coloured NO2
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 7
The brown coloured NO2 dissolves in cone. HNO3, to give it a yellow colour.

2006

Question 1.
From the substances – Ammonium sulphate, Lead carbonate, Chlorine, Copper nitrate, Ferrous sulphate — State:
A compound which releases a reddish brown gas on reaction with concentrated sulphuric acid and copper turnings.
Answer:
Copper Nitrate.

Question 2.
State what is observed when nitric acid is kept in a reagent bottle for a long time.
Answer:
Brown vapours are seen in the reagent bottle and nitric acid turns yellowish in colour.

Question 3.
Explain why only all-glass apparatus should be used for the preparation of nitric acid by heating concentrated sulphuric acid and potassium nitrate.
Answer:
Nitric acid is highly corrossive and a strong oxidising agent. It attacks rubber and wooden corks. Therefore, all glass apparatus should be used for the preparation of nitric acid in the laboratory.

2007

Question 1.
In the laboratory preparation of nitric acid: Name the reactants A (a liquid) and B (a solid) used.
Answer:
(A) Cone, sulphuric acid (B) Potassium nitrate (Nitre)

Question 2.
Write an equation to show how nitric acid undergoes decomposition.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 8

Question 3.
Write the equation for the reaction in which copper is oxidized by concentrated nitric acid.
Answer:
Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2

2008

Question 4.
Identify the following substances: a dilute acid B which does not normally give hydrogen when reacted with metals but does give a gas when it reacts with copper.
Answer:
HNO3 (Nitric acid)

Question 2.
Copy and complete the following table relating to an important industrial process. Output refers to the product of the process not the intermediate steps.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 9
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 10

Question 3.
What is the property of nitric acid which allows it to react with copper ?
Answer:
Nitric acid works as an oxidising agent.

Question 4.
Write the equations for the following reactions: Dilute nitric acid and copper.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 11

2009

Question 1.
Name the gas evolved (formula is not acceptable). The gas produced by the action of dilute nitric acid on copper.
Answer:
Nitric oxide (NO)

Question 2.
Match each substance A to E listed below with the appropriate description given below.|
(A) Sulphur

(B) Silver chloride
(C) Hydrogen chloride
(D) Copper (II) sulphate
(E) Graphite.
A non-metal which reacts with concentrated nitric acid to form its own acid as one of the product.

Question 3.
Correct the following statements.Copper reacts with nitric acid to produce nitrogen dioxide.
Answer:
Copper reacts with concentrated nitric acid to produce nitrogen dioxide.

2010

Question 1.
Select the correct answer from A, B, C D and E
(A) Nitroso Iron (II) sulphate
(B) Iron (III) chloride
(C) Chromium sulphate
(D) Lead (II) chloride
(E) Sodium chloride.
The compound which is responsible for the brown ring in the brown ring test for identify the nitrate ion.

Question 2.
A blue crystalline solid X on heating gave a reddish brown gas Y, a gas which re-lights a glowing splint and a residue is black Identify X, Y and write the equation for the action of heat on X.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 12
(1) X = Copper nitrate [Cu(NO3)2]
Y = Nitrogen gas (NO2)
(2) New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 13
(3) Cu(NO3)2 + H2S → CuS ↓+ 2HNO3

2011

Question 1.
Choose from the list substances – Acetylence gas, aqua fortis, coke, brass, barium chloride, bronze, platinum. A catalyst used in the manufacture of nitric acid by Ostwald’s process.
Answer:
Platinum

Question 2.
State your observation when copper is heated with concentrated nitric acid in a hard glass test tube.
Answer:
At once reddish brown fumes of nitrogen dioxide gas are evolved. Gradually the copper dissolves in dilute nitric acid to form greenish blue solution of copper (II) oxide.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 14

Question 3.
Choose the correct answer from the choices given – The brown ring test is used for detection of:
(A) C023
(B) NO-3
(c) SO23
(D) cl-

Question 4.
(1) State the special feature of the apparatus used in the laboratory preparation of nitric acid?
(2) State why the temperature of the reaction mixture of HNO3 is not allowed to rise above 200°C.
Answer:

  1. All glass apparatus is used because the vapours of nitric acid are corrosive and destroy materials like rubber and cork.
  2. The reaction mixture is not heated beyond 200 °C because at higher temperature:
    The nitric acid would decompose:
    4 HNO→4NO2 ↑+ 2H2O + O2
    The residue, sodium sulphate or potassium sulphate, forms a hard crust that sticks to the glass. Hence, its removal becomes difficult.

Question 5.
Write a balanced equation for – Ferric hydroxide reacts with nitric acid.
Ans.
Fe (OH)3 + 3HNO3→ Fe (NO3)3 + 3H2O

2012

Question 1.
Name the gas produced when copper reacts with concentrated nitric acid.
Answer:
Nitrogen dioxide.

Question 2.
State one observation for the following: Zinc nitrate crystals are strongly heated.
Answer:
Reddish brown gas is liberated residue is yellow when hot and white when cold.

Question 3.
Rewrite the correct statement with the missing word/s: Magnesium reacts with nitric acid to liberate hydrogen gas.
Answer:
With very dilute nitric acid.

Question 4.
Give reasons for the following: Iron is rendered passive with fuming nitric acid.
Answer:
Iron forms coating of its oxide and nitrate which stops further reaction.

Question 5.
Give a balanced equation for the reactions: Dilute nitric acid and Copper carbonate.
Answer:
CuCO3 + 2HNO3→ Cu (NO3)2 + H2O + CO2

2013

Question 1.
Identify the gas evolved when:

  1. Sulphur is treated with concentrated nitric acid.
  2. A few crystals of KNO3 are heated in a hard glass test tube.

Answer:

  1.  Nitrogen dioxide gas
  2. Oxygen gas

Question 2.
State two relevant observations for : Lead nitrate crys­tals are heated in a hard glass test tube.
Answer:

  1. Brown coloured pungent smelling gas – nitrogen dioxide (NO2) is produced.
  2. Buff coloured residue of PbO is obtained in the test tube.
  3. Oxygen produced relits a glowing splinter.

Question 3.
Give balanced equations for: Oxidation of carbon with concentrated nitric acid.
Answer:
C + 4HNO3 → 2H2O + 4NO2 + CO2

2014

1. Fill in the blank from the choices given in the bracket:

Question 1.
Cold, dil. nitric acid reacts with copper to form________(Hydrogen, nitrogen dioxide, nitric oxide).
Answer:
Cold, dilute nitric acid reacts with copper to form nitric oxide. }

Question 2.
Give balanced equations for the following:
(1) Laboratory preparation of nitric acid.
(2) Action of heat on a mixture of copper and concentrated nitric acid.
Answer:

  1. Laboratory preparation of nitric acid.
  2. Action of heat on a mixture of copper and concentrated nitric acid.
    Cu + 4HNO3  → Cu(NO3)2 + 2H2O + 2NO

2015

Question 1.
State one appropriate observation for — When crystals of copper nitrate are heated in a test tube.
Answer:
The greenish blue crystals of copper nitrate will change to black residue of copper oxide and give reddish brown gas i.e., nitrogen dioxide on heating.

Question 2.
Identify the acid — The acid which is prepared by cata­lytic oxidation of ammonia.
Answer:
Nitric acid

Question 3.
Explain the following:

  1. Dil. HN03 is generally considered a typical acid but not so in its reaction with metals.
  2. When it is left standing in a glass bottle, concentrated nitric add appears yellow.
  3. In the laboratory preparation of nitric acid, an all glass apparatus is used.

Answer:

  1. It is because it does not liberate hydrogen gas when treated with metals. Instead it liberates oxides of nitrogen, such as nitric oxide, nitrogen dioxide, etc., as it is very powerful oxidising agent.
  2. Cone. Nitric acid on exposure to sunlight, slowly decomposes to form nitrogen dioxide gas which is reddish brown in color/. Nitrogen dioxide gas redissolves in the nitric acid and imparts it yellow colour.
  3.  Nitric acid is a powerful oxidising agent and hence corrodes rubber or any other stoppers to avoid corrosion, we use all glass apparatus.

Question 4.
From the list of the following salts —
AgCl, MgCl2, NaHSO4, PbCO3, ZnCO3, KNO3, Ca(NO3)2 State the salt which on heating, evolves a brown coloured gas.
Answer:
On heating this salt, a brown-coloured gas is evolved is Ca(NO3)2

2016

Question 1.
Write balanced chemical equation for: Action of hot and concentrated nitric acid on copper.
Answer:
Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2  

Question 2.
Fill in the blanks using the appropriate words given in the bracket below:

(sulphur dioxide, nitrogen dioxide, nitric oxide, sulphuric acid)

  1. Cold, dilute, nitric acid reacts with copper to given nitric oxide.
  2.  Hot, concentrated nitric acid reacts with sulphur to form sulphuric acid.

2017

Question 1.
Write the balanced chemical equation for –

  1. Action of cold and dilute nitric acid on copper,
  2. Action of cone. nitric acid on sulphur.
  3. Laboratory preparation of ni- trie acid.

Answer:

  1. 3Cu + 8HNO3 (dil.) → 3Cu(NO3)2 + 2NO(g) + 4H2O
  2.  S + 6HNO3(conc.) → H2SO4 + 2H2O + 6NO2 (g)
  3. New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 15

 ADDITIONAL QUESTIONS

Question 1.
State  how atmospheric nitrogen converts itself to nitric acid.
Ans.

    1. During lightning discharge, nitrogen in the atmosphere reacts with oxygen to form nitric oxide and further to nitrogen dioxide.
    2. The nitrogen dioxide dissolves in atmospheric moisture forming nitric acid.
      New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 16
      2NO + O→2NO2
      4NO3+2HO + O2→ 4 HNO(acid Rain)

Question 2.
Give a word equation and balanced molecular equation for the laboratory preparation of nitric acid from (1) KN03 (2) NaNO3.
Answer:
(1)
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 17
(2)
Sodium Nitrate + Sulphuric acid (conc.)  Sodium Bisuiphate + Nitric acid
NaNO3 + H2S04 (conc.) NaHSO4 + HNO3

 Question 3.
In the laboratory preparation of nitric acid from – KNOor NaNO3 State

  1. The acid used
  2. The type of apparatus used
  3. The precautions to be taken during the preparation
  4. The method of collection of the acid
  5. The method of identification of the product i.e. acid formed.

Answer:

  1. Cone, sulphuric acid
  2. Glass retort
  3. Precautions are:

    • Use all glass apparatus with no wooden or rubber cork.
    • Control the temperature carefully at nearly 200 °C.
  4. Concentrated nitric acid vapours – condense and are collected in the water-cooled receiver.
  5. The vapours obtained in the receiver on heating alone or with copper turnings evolve – reddish brown fumes of nitrogen dioxide which turns acidified ferrous sulphate solution brown – proving that the vapours are of nitric acid.

Question 4.
Give reasons for the following – pertaining to the above laboratory preparation of nitric acid
Question 4(1).
concentrated hydrochloric acid is not used as a reactant in the laboratory preparation.
Answer:
Cone. HCl is not used as a reactant in the laboratory preparation of nitric acid. It is due to the following reasons:

  1. HCl is a volatile acid.
  2. HNO3, if formed, will oxidise HCl to Cl,. In the process, HNO3 will get reduced to NO or NO,. This very little yield, if any, of HNO, will be obtained and that too will be contaminated with HCl.

Question 4(2).
The complete apparatus in the laboratory preparation does not contain parts made of rubber or cork.
Answer:
The complete apparatus is made of glass only – since the vapours of nitric acid being highly corrosive and attack rubber, cork, etc.

Question 4(3).
The reaction temperature is maintained below 200°C
Answer:
The reaction temperature is maintained below 200°C. This is because at higher temperatures, HNO3 decomposes to give NO2. The brown coloured NO2 dissolves in HNO3 to give it a yellow colour. Thus, if the temperature is allowed to go beyond 200°C, the product (HNO3) obtained is not pure (colourless).

Question 4(3).
At high temperatures the sodium sulphate or phtassium sulphate formed, forms a crust and sticks to the glass apparatus.
Answer:
Formation of a hard residual crust of the corresponding sulphate [Na2SO4 or K2SO4] which being a -poor conductor of heat, sticks to the glass and cannot be easily removed from the apparatus.

Question 5.
State the colour of
(1) pure nitric acid
(2) nitric acid obtained in the laboratory
(3) nitric acid obtained in the laboratory after passage of air or addition of water to it.
Answer:

  1. Pure nitric acid is colourless.
  2. Nitric acid obtained in laboratory is pale yellow in colour.
  3. The pale yellow colour of nitric acid disappears and hence it becomes colourless.

Question 6.
State which reaction of ammonia forms the first step of Ostwald’s process.
Answer:
The first step of Ostwald’s process involves catalytic oxidation of ammonia to nitric oxide and water (steam).
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 18

Question 7.
Convert ammonia to nitric acid by the above process giving all conditions.
Answer:
Step I
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 19
Step II
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 20
Step III
 4NO2 + 2H2O → 4HNO3

Question 8.
State how —

  1. a higher ratio of the reactant air
  2. exothermicity of the catalytic reaction
  3. use of low temp, in the conversion of NO to NO2 – affects each related step in Ostwald’s process.

Answer:

  1. Excess of air carries the reactions in forward direction as oxygen is needed in all the three reactions, leading to the formation of nitric acid.
  2. The exothermicity of catalytic reaction helps in stopping external heating, there by saving on energy.
  3. Low temperature (less than 50°C)

Question 9.
State why  nitric acid

  1. Stains the skin
  2. Cannot be concentrated beyond 68% by boiling.

Answer:

  1. Nitric acid combines with protein of the skin forming a yellow compound Xanthoproteic acid, stains skin yellow.
  2. It is because at 68% concentration it forms a constant boiling mixture, i.e., if heated beyond this concentration then proportion of water vapour and nitric acid vapour, leaving the dilute acid does not change. Thus, it cannot be concentrated by boiling.

Question 10.
State two conditions which affect the decomposition of nitric acid.
Answer:
The conditions which affect the decomposition of nitric acid are:

  1. Presence of sunlight
  2. Higher temperature.

Question 11.
State the change in colour of pure concentrated nitric acid on initial and prolonged decomposition.
Answer:
Yellowish brown colour is changed to dark yellowish brown colour on prolonged decomposition.

Question 12.
State the cation responsible for turning moist neutral litmus red on reaction with dil. HNO3.
Answer:
Hydrogen |H+| ions and Nitrate ions.

Question 13.
State why nitric acid is a strong oxidising agent and yields varying products such as NO, NO2 on reaction with metals,non-metals etc.
Answer:
The oxidising property of nitric acid is based on the fact that when nitric acid undergoes decomposition, it yields nascent oxygen, which is very reactive.
2HNO3 (cone.) → H2O + 2NO2 + [O]
2HNO3 (dil.) → H2O + 2NO + 3[O]
This nascent oxygen oxidises metals, non-metals, organic and inorganic compounds. During the process, nitric acid itself gets reduced to various products (NO, NO2, N2O, NH3, etc.) depending upon the concentration of the acid, reaction temperature and activity of the metal with which it is reacting.

Question 14.
Give an equation for reaction of cone. HNO3 with
(1) carbon
(2) copper.
Answer:

  1. C + 4HNOs → CO2 + 2H2O + 4NO2
  2. 3Cu + 8HNO3 → 3Cu (NO3)2 + 4H2O + 2NO

Question 15.
Convert nitric acid to sulphuric acid using a non-metal.
Answer:
S + 6HNO3 → H2SO4 + 2H2O + 6NO2

Question 16.
State how you would obtain
(1) Hydrogen
(2) Nitric oxide
(3) Nascent chlorine – from nitric acid. State the concentration of nitric acid used in each case.
Ans.

  1. Hydrogen from nitric acid: Cold, very dilute (1%) nitric acid reacts with metals like Mg and Mn to give H2.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 21
  2. Nitric oxide from nitric acid: Dilute nitric acid reacts with metals like Cu, Ag to give nitric oxide (NO).
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 22
  3. Nascent chlorine from nitric oxide: A mixture of cone, nitric acid (I part) and cone, hydrochloric acid (III parts) (by volume) reacts with noble metals like gold and platinum. In this reaction, nascent chlorine is formed as an intermediate.
    HNO3 (cone.) + 3HCl (cone.) → 2H2O + NOCL + 2|Cl|

Question 17.
State why hydrogen is liberated when zinc reacts with dil.HCl but not with dil. HNO3.
Answer:
Zinc displace hydrogen from dil. HCl.
Zn + 2HCl(dil.) → ZnCl2 + H2
However, when zinc reacts with dil HNO3, no hydrogen is obtained. This is because nitric acid is a strong oxidising agent. Nitric acid oxidises the hydrogen produced to water and hence no hydrogen is liberated.

Question 18.
State a reason for the inactivity of iron and aluminium on reaction with fuming HNO3.
Answer:
Pure or fuming nitric acid renders metals like iron (Fe) and Al- passive i. e., inactive. This is due to the formation of a thin oxide coating on the surface of the metal which prevents further action.

Question 19.
State your observation when
(1) nitric acid is added to saw dust
(2) cone, nitric acid is heated
(a) in absence of copper
(b) in presence of copper.
Answer:

  1. Nitric acid being a strong oxidising agent decomposes to give nascent oxygen, which being very reactive, oxidises organic compounds to carbon dioxide and water. Saw dust is organic in nature. When hot cone. HNO3 is poured over saw dust, it burst into flames due to oxidation.
  2. (a)
    When cone. HNO, is heated, it decomposes to give brown coloured pungent smelling gas nitrogen dioxide (NO2).
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 23(b)
    (b) When. ”cone. HNO3 is heated in the presence of copper, brown coloured, pungent smelling NO2 is formed alongwith blue coloured copper nitrate.
    Cu + 4HNO(cone.)→ Cu(NO3)2 + 2H2O + 2NO2

Question 20.
State how addition of nitric acid to acidified FeSO, serves as a test for the former.
Answer:
Nitric acid oxidises iron(II) sulphate to iron (III) sulphate with the liberation of nitric oxide gas.
6FeSO4 +3H2SO4 + 2HNO3 (dil. ) → 3Fe2(SO4)3 + 4H2O +2NO
The nitric oxide so formed reacts wtih more of iron(II) sulphate to form nitrosoferrous sulphate, which appears in the form of brown ring at the junction of liquids.
FeSO4 + NO → FeSO4.NO

Question 21.
Name three chemical products manufactured from nitric acid. Give two general uses of HNO3.
Answer:

  1. Three chemical products manufactured from nitric acid. Explosives (T.N.T., picric acid, nitrocellulose etc.)
  2. Fertilizers (Ammonium nitrate, calcium ammonium nitrate or C.A.N.)
  3. Dyes (Picric acid and other nitro dyes)
    Two general uses of nitric acid

    1. For refinning of noble metals like gold, platinum etc.
    2. For etching on stainless steel.

UNIT TEST PAPER 7C — NITRIC ACID

Question 1.
Select the letters A, B, C, D or E, which form the gaseous products of the reactions from 1 to 5.
A: Nitrogen dioxide only
B: Nitric oxide only
C: Hydrogen
D: Nitrogen dioxide and oxygen
E: Nitrogen dioxide and carbon dioxide.

1. Reaction of manganese with cold very dil. nitric acid.
2. Reaction of sulphur with cone, nitric acid.
3. Reaction of zinc with dil. nitric acid.
4. Reaction of carbon with cone, nitric acid.
5. Heat on nitric acid.
Answer:

  1. (C) Hydrogen
  2. (A) Nitrogen dioxide only
  3. (B) Nitric oxide only
  4. (E) Nitrogen dioxide and carbon dioxide.
  5. (D) Nitrogen dioxide and oxygen.

Question 2.
Select the correct word from the list in bracket to complete each statement
.

  1. The oxidised product obtained on reaction of H2S ghs with dil. HNO3 is ……… (sulphur dioxide / sulphur / sulphuric acid).
    Ans. sulphur
  1. Aqua regia is a mixture of one part of…………… and three parts of……… (cone, hydrochloric acid/conc. nitric acid) in which nitric acid……….. (reduces/oxidises) hydrochloric acid to chlorine.
    Ans. cone, nitric acid, cone, hydrochloric acid, oxidises
  1. Pure cone, nitric acid or fuming nitric acid renders the metal…………. (zinc/copper/iron) passive or inactive.
    Ans. Iron
  1. A mineral acid obtained from cone, nitric acid on reaction with a non-metal is……….. (hydrochloric acid / sulphuric acid / carbonic acid).
    Ans. sulphuric acid
  1. The reaction of……….. (calcium carbonate / calcium oxide/ calcium sulphite) with dilute nitric acid is an example of a neutralization reaction.
    Ans. calcium oxide

Question 3.
Give balanced equations for the following conversions A to E.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 24
Answer:
1. A: Cu + 4HNO3→ Cu (NO3)2 + 2H2O + 2NO
B:New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 25
C : New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 26
2. D : S + 6HNO3→ H2SO4 + 2H2O + 6NO2
E : 3SO2 + 2H2O + 2HNO3 → 3H2SO4 + 2NO

Question 4.
Name the oxidised product when the following 1 to 5 react with nitric acid    

  1. Sulphur (with cone, acid)
  2. Zinc (with dil. acid)
  3. Aqueous soln. of SO2 (with dil. acid)
  4. Acidified iron (II) sulphate (with dil. acid)
  5. Carbon (with cone, acid)

Answer:
1. H2SO4
2. Zn(NO3)2
3. H2SO4
4.Fe2(SO4)3 CO2

Question 5.
Give reasons for the following:

  1. Nitric acid is not manufactured from atmospheric nitrogen.
    Ans. Direct conversion of atmospheric N2 into HNO3 is highly energy intensive process and hence very expensive.
  1. Nitric acid affects the skin if it accidently falls on it, staining the skin yellow.
    Ans. Nitric acid has an extremely corrosive action on the skin – and causes painful blisters. It combines with the protein of the skin forming a yellow compound xanthoproteic acid and hence stains the skin yellow.
  1. The yellow colour of nitric acid obtained in the laboratory is removed by babbling air through it.
    Ans. Yellow colour of the nitric acid is due to dissolved NO2. On bubbling air through it the NO2 is oxidised to HNO3 and the yellow colour of the acid disappears.
  1. Nitric acid finds application in the purification of gold.
    Ans. Nitric acid is used for purification of gold because it can dissolve away all impurities of baser metals (Ag, Cu, etc.), leaving behing pure gold.
  1. Nitric acid is a stronger oxidising agent in the cone, state of the acid than in the dilute state.
    Ans. Cone. HNOis a stronger oxidising agent than dil HNO3. It is due to the ease with which cone. HNO3 decomposes to give nascent oxygen, which acts as a powerful oxidising agent.

Question 6.
Answer the following questions pertaining to the brown ring test for nitric acid:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7C Study Of Compounds - Nitric Acids 27

  1. Name the chemical constituent of the brown ring ‘Y’.
    Ans. FeSO4.NO
  1. Which of the two solutions – iron (II) sulphate or cone, sulphuric acid, do ‘X’ and ‘Z’ represent.
    Ans. X-FeSO4                      Z-H2SO4
  2. State why the unstable brown ring decomposes completely on disturbing.
    Ans. When test tube is disturbed, cone. H2SO4 mixes with water (in Fe2SO4 solution). Dilution of cone. H2SO4 with water is an exothermic process. The heat so produced assists in the decomposition of unstable brown ring.
  1. Give a reason why the brown ring does not settle down at the bottom of the test tube.
    Ans. Cone. H2SO4), (density 1.98) is twice as heavy as water (density : 1). As such cone. H2SO4 settles down and iron(II) sulphate layer remains alone it resulting in the formation of brown ring at the junction.
  1. Name the gas evolved when acidified iron (II) sulphate reacts with dilute nitric acid in the brown ring test.
    Ans. Nitric oxide (NO)

SOMETHING MORE TO DO

Question 1.
Perform ring test in the laboratory in the presence of your teacher.
Answer:
Brown ring test: Procedure – Take a solution of – a nitrate or dilute nitric acid in a test tube.
Add to it – a freshly prepared saturated solution of iron [II] sulphate.
Add – cone, sulphuric acid carefully from the sides of the test tube.

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New Simplified Chemistry Class 10 ICSE Solutions – Study Of Compounds : Ammonia

New Simplified Chemistry Class 10 ICSE Solutions – Study Of Compounds: Ammonia

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Questions
2001

Question 1.
State what do you observe when :
Neutral litmus solution is added to an alkaline solution.
Answer:
The litmus solution turns to blue.

Question 2.
Name (formula is not acceptable) the gas produced in the following reaction :
Warming ammonium sulphate with sodium hydroxide solution.
Answer:
Ammonia gas.

Question 3.
Write the equation for the preparation of NH3 from ammonium chloride and calcium hydroxide.
Answer:
2NH4Cl + Ca(OH)2 → CaCl2 + 2NH3 + 2H2O

Question 4.
What are the products formed when ammonia is oxidized with copper oxide.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 1

2002

Question 1.
From the following gases – ammonia, chlorine, hydrogen chloride, sulphur dioxide, select the gas that turns moist red litmus paper blue.
Write the equation for the reaction – when the gas is passed over heated CuO.
Answer:
Ammonia gas.
3CuO + 2NH3 → 3Cu + N2 + 3H2O

2003

Question 1.
Name a gas whose solution in water is alkaline.
Answer:
Ammonia

Question 2.
How would you distinguish between Zn2+ and Pb2+ using ammonium hydroxide solution.
Answer:
Zinc salt gives white gelatinous ppt. and Pb2+ gives chalky white ppt. with ammonium hydroxide.

Question 3.
Write the equation for the formation of ammonia by the action of water on mangesium nitride.
Answer:
Mg3N2 + 6H2O → 2NH3 + 3Mg (OH)2

Question 4.
How is ammonia collected. Why is ammonia not collected over water.
Answer:
Ammonia gas is lighter than air and hence collected by the downward displacement of air.
Ammonia is not collected over water because it is highly soluble in water.

Question 5.
Which compound is normally used as a drying agent for ammonia.
Answer:
Quicklime(Calcium oxide CaO).

2004

Question 1.
From the gases ammonia, hydrogen chloride, hydrogen sulphide, sulphur dioxide – Select the following :

  1. When this gas is bubbled through copper sulphate soln., a deep blue coloured solution is formed.
  2. This gas burns in oxygen with a green flame.

Answer:

  1. ammonia
  2. ammonia

Question 2.
Write the equation for the reaction in the Haber’s process that forms ammonia.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 2

Question 3.
State the purpose of liquefying the ammonia produced in the process.
Answer:
By liquefying ammonia, it can be easily seperated from unreacted N2 and H2 gases.

Question 4.
Write an equation for the reaction of chlorine with excess of ammonia.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 3

2005

Question 1.
Name the ion other than ammonium ion formed when ammonia dissolves in water.
Answer:
Hydroxyl ion (NH3 + H2O → NH++ OH )

Question 2.
Write the equations for the following reactions which result in the formation of ammonia.

  1. A mixture of ammonium chloride and slaked lime is heated.
  2. Aluminium nitride and water.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 4

2006

Question 1.
Select the correct compound from the list given — Ammonia, Copper oxide, Copper sulphate, Hydrogen chloride, Hydrogen sulphide, Lead bromide — which matches the description given below :
The compound is not a metal hydroxide, its aqueous solution is alkaline in nature.
Answer:
Ammonia.

Question 2.
From the list of substances given — Ammonium sulphate, Lead carbonate, Chlorine, Copper nitrate, Ferrous sulphate — State :
A compound which on heating with sodium hydroxide produces a gas which forms dense white fumes with hydrogen chloride.
Answer:
Ammonium sulphate.

Question 3.
State what is observed when excess of ammonia is passed through an aq. solution of lead nitrate.
Answer:
Chalky white insoluble ppt. is formed.

Question 4.
Name the substance used for drying ammonia,
Answer:
Quick lime (CaO).

Question 5.
Write a balanced chemical equation to illustrate the reducing nature of ammonia.
Answer:
Reducing nature of ammonia.
2NH3 + 3CuO → 3Cu + 3H2 + N2 (g)

Question 6.
With reference to Haber’s process for the preparation of ammonia, write the equation and the conditions required.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 5
Conditions for maximum yield of ammonia

  1. High Pressure (700-900 atm)
  2. Optimum temperature (450-500°C)
  3. Use of a catalyst : Iron (Fe) and use of a promotor : Molybdenum (Mo)

2007

Question 1.
Write a balanced equation for the following reaction :
Ammonium sulphate from ammonia and dilute sulphuric acid.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 6

Question 2.
Give equation for – reaction in which NH3 is oxidized by :

  1. a metal oxide ;
  2. a gas which is not oxygen.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 7

Question 3.
You enter a laboratory after a class has completed the Fountain Experiment. How will you be able to tell whether the gas used in the experiment was hydrogen chloride or ammonia.
Answer:
If the colour of the litmus solution in the round bottomed flask is blue the gas used was ammonia and if the colour of the litmus solution in the round bottomed flask is red, the gas used was hydrogen chloride. This is because hydrogen chloride(aq) is acidic in nature and turns purple litmus solution red and ammonia (aq) is basic in nature and turns purple neutral litmus solution blue.

2008

Question 1.
Ammonia can be obtained by adding water to : [Select the correct word]
A Ammonium chloride
B Ammonium nitrite
C Magnesium nitride
D Magnesium nitrate
Answer:
C Magnesium nitride

Question 2.
Name : An alkaline gas A which gives dense white fumes with hydrogen chloride.
Answer:
NH3 (Ammonia)

Question 3.
Write the equation for the following reaction : Aluminium nitride and water.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 8

Question 4.
Complete the table relating to an important industrial processes. [Output refers to the product of the process].
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 9
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 10

2009

Question 1.
Name the gas – that burns in oxygen with a green flame.
Answer:
Ammonia (NH3)

Question 2.
Write a fully balanced equation for the following : Magnesium nitride is treated with warm water.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 11

Question 3.
Identity the substances ‘Q’ based on the information given :
The white crystalline solid Q is soluble in water, it liberates a pungent smelling gas when heated with sodium hydroxide solution.
Answer:
Q is Ammonium chloride and pungent smelling gas is ammonia.

2010

Question 1.
Complete the blanks (a) to (e) in the passage given, using the following words.
(Ammonium, reddish brown, hydroxyl, nitrogen dioxide, ammonia, dirty green, alkaline, acidic) in the presence of a catalyst, nitrogen and hydrogen combine
to give (a) _____ gas. When the same gas is passed through water, it forms a solution which will be _____ (b) in nature, and will contain the ions (c) _____ and (d) _____ (e) _____ coloured precipitate of iron [II] hydroxide is formed when the above solution is added to iron [II] sulphate solution, sssssss
Answer:

(a) Ammonia
(b) Alkaline
(c) Ammonium
(d) Hydroxyl
(e) Dirty green

Question 2.
State your observation when – in the absence of a catalyst ammonia gas is burnt in an atmosphere of oxygen.
Answer:
Greenish yellow flame is observed.

Question 3.
Give the equation for the reaction : ammonium chloride is heated with sodium hydroxide.
Answer:
NH4Cl + NaOH → NaCl + NH3 + H2O

Question 4.
In the manufacture of ammonia.

  1. Name the process.
  2. State the ratio must the reactants taken ?
  3. State the catalyst used.
  4. Give the equation for the manufacture of the gas ammonia.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 12

Question 5.
Write a relevant equation, to show that ammonia can act as a reducing agent
Answer:
2NH3 + 3Cl2 → N2 + 6HCl

Question 6.
Name two gases you have which can be used to study the fountain experiment.
State the common property demonstrated by the fountain experiment ?
Answer:
Two gases which are used to study the fountain experiment are Hydrogen chloride gas (HCl) and Ammonia (NH3)
The common property of these two gases demonstrated by the fountain experiment is the solubility of gases

2011

Question 1.
State what is observed when – Ammonium hydroxide is first added in a small quantity and then in excess to a solution of copper sulphate.
Answer:
On adding ammonium hydroxide in small amount, pale blue precipitates will appear. On adding ammonium hydroxide in excess, blue precipitates will dissolve forming deep blue solution.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 13

Question 2.
The diagram shows set up for the laboratory preparation of a pungent alkaline gas.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 14

  1. Name the gas collected in the jar.
  2. Write the balanced equation for the above preparation
  3. State how the gas is collected?
  4. Name the drying agent used.
  5. State how you will find out that the jar is full of pungent gas?

Answer:

  1. Ammonia (NH3)
  2. NH4 Cl + Ca (OH)2 → CaCl2 + 2H2O + 2NH3
  3. Downward displacement of air
  4. Quicklime (CaO)
  5. Bring a rod dipped in HCl near it. Dense white fumes of ammonium chloride will be formed.

Question 3.
Write a balanced chemical equation – Chlorine reacts with excess of ammonia.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 15

Question 4.
State your observation when – Water is added to the product formed, when aluminium is burnt in a jar of nitrogen gas.
Answer:
Pungent smelling and alkaline gas (NH3) is evolved.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 16

2012

Question 1.
Name the gas produced when excess ammonia reacts with chlorine.
Answer:
Nitrogen.

Question 2.
Rewrite the correct statement with the missing word/s Magnesium nitride reacts with water to liberate ammonia.
Answer:
Magnesium nitride reacts with warm water to liberate ammonia along with magnesium hydroxide.

Question 3.
Give balanced equation for the reaction : Ammonia and Oxygen in the presence of a catalyst.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 17

Question 4.
The following questions are based on the preparation of ammonia gas in the laboratory:

  1. Explain why ammonium nitrate is not used in the preparation of ammonia.
  2. Name the compound normally used as a drying agent during the process.
  3. How is ammonia gas collected ? Explain why it is not collected over water.

Answer:

  1. Ammonium nitrate does not undergo a reversible sublimation reaction, it melts and then decompses into nitrogen oxide gas and water vapour. Thus it is not used in the preparation of ammonia.
    NH4NO3 → N2O + 2H2O
  2. Calcium oxide
  3. Ammonia is collected in an inverted dry gas jar by downward displacement of air.
    It is highly soluble in water and hence cannot be collected by downward displacement of water.

2013

Question 1.
State one appropriate observation for :
Excess of chlorine gas is reacted with ammonia gas.
Answer:
A yellow explosive liquid (Nitrogen trichloride) is formed.

Question 2.
Nitrogen gas can be obtained by heating :

(a) Ammonium nitrate
(b) Ammonium nitrite
(c) Magnesium nitric
(d) Ammonium chloride

Answer:

(b) Ammonium nitrite

Question 3.
State two relevant observations for :
Ammonium hydroxide solution is added to zinc nitrate solution in minimum quantities and then in excess.
Answer:
A white gelatin like precipitate of zinc hydroxide is formed which dissolves in excess of ammonium hydroxide.

Question 4.
Give balanced equations for :
Reduction of hot Copper (II) oxide to copper using ammonia gas.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 18

Question 5.
Copy and complete the following table relating to im¬portant industrial process :
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 19
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 20

Question 6.
Identify : An alkaline gas which produces dense white fumes when reacted with HCl gas.
Answer:
Ammonia gas.

2014

Question 1.
Fill in the blank from the choices given in bracket : Ammonia gas is collected by _____ (upward displacement of air, a downward displacement of water, a downward displacement of air)
Answer:
Ammonia gas is collected by a downward displacement of air.

Question 2.
Write balanced equation for : Action of warm water on magnesium nitride.
Answer:
Action of warm water on magnesium nitride.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 21

Question 3.
Distinguish between the following pairs of compounds using the test given within bracket :

  1. Iron(II)sulphate and iron (III) sulphate (using ammonium hydroxide)
  2. A lead salt and a zinc salt (using excess ammonium hydroxide)

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 22
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 23

Question 4.
State your observation : Calcium hydroxide is heated with ammonium chloride crystals.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 24
ammonia gas is evolved which fumes strongly in moist air.

Question 5.
Name the other ion formed when ammonia dissolves in water. Give one test that can be used to detect the presence of the ion produced.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 25

Question 6.
State the conditions required for : Catalytic oxidation of ammonia to nitric oxide.
Answer:
Catalytic oxidation of ammonia to nitric oxide.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 26
Conditions for catalytic oxidation of ammonia to nitric oxide : Platinum catalyst and 800°C temperature.

2015

Question 1.
From the list the gases — Ammonia, ethane, hydrogen chloride, hydrogen sulphide, ethyne
Select the gas which is used as a reducing agent in reducing copper oxide to copper.
Answer:
Hydrogen

Question 2.
State one relevant observation — Ammonia gas is burnt in an atmosphere of excess oxygen.
Answer:
Ammonia gas bums to form nitrogen gas and steamy fumes of water.

Question 3.
A metal ‘X’ has valency 2 and a non-metal ‘Y’ has a valency 3.
If ‘Y ’ is a diatomic gas, write an equation for the direct combination of X and Y to from a compound.
Answer:
The equation for the direct combination of X and Y to form a compound is
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 27

Question 4.
Give balanced chemical equations —

  1. Lab. preparation of ammonia using an ammonium salt.
  2. Reaction of ammonia with excess chlorine.
  3. Reaction of ammonia with sulphuric acid.

Answer:

  1. Ammonia is prepared in the laboratory by using ammonium chloride.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 28
  2. When ammonia reacts with excess of chlorine, it forms nitrogen trichloride and HCl
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 29
  3. Ammonia reacts with sulphuric acid to form ammonium sulphate.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 30

2016

Question 1.
Write balanced equations for :

  1. Action of warm water on AIN.
  2. Excess of ammonia is treated with chlorine.
  3. An equation to illustrate the reducing nature of ammonia.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 31

Question 2.
Name the gas evolved when the following mixtures are heated :

  1. Calcium hydroxide and Ammonium chloride.
  2. Sodium nitrite and Ammonium chloride.

Answer:

  1. Ammonia gas
  2. Nitrogen gas

2017

Question 1.
Write the balanced chemical equation for each of the following –

  1. Reaction of ammonia with heated copper oxide.
  2. Laboratory preparation of ammonia from ammonium chloride.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 32

Question 2.
State one relevant observation for the following reaction – Burning of ammonia in air.
Answer:
Ammonia bums with a yellowish green flame.

Question 3.
Certain blanks spaces are left in the following tables as C, D & E. Identify each of them.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 33
Answer:

C : Reactants are Magnesium nitride(Mg3N2) and water(H2O).
D : Drying agent is anhydrous calcium oxide (Quick lime).
E : NH3 gas is collected by the downward displacement of air.

Question 4.
Give a balanced chemical equation for each of the following –

  1. Catalytic oxidation of ammonia.
  2. Reaction of ammonia with nitric acid.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 34

Additional Questions

Question 1.
State why nitrogenous matter produces ammonia. State a liquid source of ammonia.
Answer:
When nitrogenous matter (such as animal and vegetable protiens) decays in the absence of air, the putrefying bacteria on the organic matter in the soil or ammonifying bacteria in organic matter produces ammonia.
The liquid souce of ammonia is decaying urine of animals.

Question 2.
Give the word equation and balanced molecular equation for the laboratory preparation of ammonia from NH4Cl and calcium hydroxide.
Answer:
Ammonium Chloride + Calcium Hydroxide → Calcium Chloride + Water + Ammonia
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 35

Question 3.
Convert ammonium sulphate to ammonia using two different alkalis.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 36

Question 4.
State why ammonia is not obtained in the laboratory from NH4NO3 and NaOH.
Answer:
Ammonium nitrate on heating decomposes explosively with the formation of nitrous oxide and water.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 37

Question 5.
State the method used with reasons for drying and collecting ammonia gas.
Answer:
Calcium oxide (quick lime) is used for drying ammonia. It is because, calcium oxide being basic in nature does not react chemically with ammonia.
CaO + H2O → Ca(OH)2
Chemicals such as CaCl2 (anhydrous), P2O5 and cone H2SO4 are not used for drying ammonia, because they react chemically with it as shown in the equation below :
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 38
Ammonia is collected by downward displacement of air. Ammonia gas is highly soluble in water, as such it cannot be collected over water. Further, ammonia is lighter than air. As such ammonia is collected by downward displacement of air.

Question 6.
State how you would convert (i) Mg (ii) Ca (iii) Al – to ammonia.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 39
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 40

Question 7.
Give a balanced equation with all conditions to obtain NH3 from N2 and H2.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 41
Conditions for maximum yield of ammonia :

  • Pressure : 200-900°C (High pressure)
  • Temperature : 450-500°C (Optimum temperature)
  • Catalyst : Finely divided iron, Fe
  • Promotor : Molybdenum, Mo

Question 8.
State two physical properties of NH3 which enable separation of NH3 from a mixture of NH3, N2 and H2.
Answer:

  1. Ammonia liquifies at a pressure 8 atmosphere at -33°C, but not hydrogen and nitrogen.
  2. Ammonia is extremely soluble in water, but not hydrogen and nitrogen.

Question 9.
Compare the density of ammonia with that of air. Name two gases lighter than ammonia.
Answer:
The vapour density of ammonia is 8.5 and that of air is 14.4. The two gases lighter than ammonia are

  1. hydrogen
  2. helium.

Question 10.
‘Ammonia is highly soluble in water’. Name two other gases showing similar solubility.
Answer:
The other highly soluble gases in water are :

  1. Hydrogen chloride
  2. Sulphur trioxide.

Question 11.
Name the experiment and state its procedure to demonstrate the high solubility of ammonia.
Answer:
Highly solubility of ammonia can be shown by Fountain Experiment.
To demonstrate the high solubility of ammonia gas in water.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 42
Apparatus :

  1. Round bottomed flask filled with ammonia gas.
  2. Mouth of the flask with a rubber stopper with two holes, one for jet tube and other for dropper containing water.
  3. Trough below contains red litmus solution.

Procedure :

  1. The dropper containing water is squeezed and few drops of water enters the flask.
  2. Ammonia gas present in the flask gets dissolved in water due to its high solubility, which creates a partial vacuum in the flask.
  3. Since outside pressure is higher, so red litmus solution rush up the jet tube and emerge as a fountain. (Ammonia gas being basic changed red litmus blue.)
    Ammonia gas is lighter than air, hence it is collected by downward displacement of air.
  4. Easily liquified at low temperatures.
  5. Liquid ammonia boils at – 33.5°C
  6. Solid ammonia melts at – 77.5°C

Question 12.
Give an equation for the burning of ammonia in oxygen. State the observation seen.
Answer:
Ammonia bums in the atmosphere of oxygen with a pale blue flame, forming nitrogen gas and water vapour.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 43

Question 13.
Convert ammonia to nitric oxide by catalytic oxidation of ammonia. State all conditions.
Answer:
When a mixture of 2 (vols.) of oxygen and l(vols.) of ammonia is passed over platinum gauze maintained at 800°C, it reacts to form nitric oxide and water vapour.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 44

  • Conditions for the reaction : Ostwald’s process
  • Temperature : 800°C
  • Catalyst : Platinum (Pt)

Question 14.
Draw a simple diagram for the catalytic oxidation of ammonia in the laboratory.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 45

Question 15.
Give reasons for the observation seen during catalytic oxidation of ammonia.
Answer:
The colourless nitric oxide formed undergoes further oxidation to give reddish brown vapours of nitrogen oxide.
The platinum(catalyst) continues to emit a reddish glow even after the heating is discontinued since the catalytic oxidation of ammonia is an exothermic reaction.

Question 16.
Name an industrial process which involves ammonia, oxygen and a catalyst as its starting reactants.
Answer:
The industrial process is called Ostwald’s process for preparing nitric acid.

Question 17.
State what an aqueous solution of NH3 is called. State how it is prepared giving reasons.
Answer:
The aqueous solution of ammonia is chemically ammonium hydroxide(NH4OH) (Liquor Ammonia).
It is prepared by connecting the delivery tube of the apparatus generating ammonia with an inverted funnel whose rim is just dipping in water contained in beaker.
This arrangement provides

  1. large surface area for the absorption of ammonia and
  2. prevents back suction
    NH3 + H2O → NH4 OH

Question 18.
State why an aq. soln. of NH3

  1. turns red litmus blue
  2. is a weak base and a weak electrolyte.

Answer:

  1. Ammonia on dissolving in water furnishes ammonium (NH4+) ions and hydroxyl (OH) ions.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 46
    The presence of OH turns the red litmus blue.
  2. When ammonia dissolves in water, it forms ammonium hydroxide. The ammonium hydroxide dissociates to NH4+ ions and OH ions.
    However, the degree of dissociation of ammonium hydroxide molecules is very low. Thus, due to the presence of few OH- ions it is a weak base, as well as weak electrolyte.

Question 19.
State two different methods of preparing NH4Cl using hydrochloric acid.
Answer:

  1. When ammonium hydroxide is treated with hydrochloric acid, neutrilisation reaction takes place with formation of Ammonium chloride
    NH4OH + HCl (dil.) → NH4Cl + H2O
  2. When ammounium carbonate is treated with hydrochloric acid, it forms ammonium chloride, carbon dioxide and water.
    (NH4)2 CO3 + 2HCl (dil.) → 2NH4Cl + CO2 + H2O

Question 20.
Convert (i) ammonia (ii) ammonium hydroxide to an ammonium salt using (a) HNO3 (b) H2SO4.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 47

Question 21.
State a reason why reaction of liquor ammonia with nitric acid is a neutralization reaction.
Answer:
Liquor ammonia is a saturated solution of ammonia in water. Ammonia, NH3 dissolves in water to give ammonium hydroxide which dissociates partially to give NH4+ and OH ions. Due to presence of OH ions, ammonium hydroxide acts as an alkali.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 48
The reaction between an acid (nitric acid) and an alkali or base is a neutralisation reaction.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 49
Hence, the reaction between liquor ammonia and nitric acid is a neutralisation reaction.

Question 22.
State why an aqueous solution of ammonia (NH4OH) is used for identifying cations.
Answer:
Because of its colour and solubility in excess NH4OH.

Question 23.
State how NH4OH is used for identify :

  1. Fe2+
  2. Fe3+
  3. pb2+
  4. Zn2+
  5. Cu2+ cations.

Give also a balanced equation in each case for a known example.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 50
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 51
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 52

Question 24.
State why the blue ppt. formed on addition of NH4OH to CuSO4 soln. dissolves to give a deep blue solution with excess of NH4OH. Give an equation for the reaction. State why Zn(OH)2 is soluble in excess of NH4OH.
Answer:
CuSO4 when reacts with excess of ammonia it produces needle shape crystals of tetraammine copper(II) sulphate complex which possess a beautiful deep blue colour.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 53

Question 25.
Give balanced equations for the reducing reactions of ammonia with
(i) copper (II) oxide, (ii) lead (II) oxide, (iii) chlorine using, (a) excess NH3(b) excess Cl2.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 54
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 55
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 56

Question 26.
State five tests for ammonia where a colour change is involved.
Answer:
Tests for ammonia :

  1. Ammonia turns red (or purple) litmus solution to blue.
  2. Ammonia turns methyl orange solution to yellow.
  3. Ammonia turns phenolphthalein (colourless) solution to pink.
  4. Ammonia turns Nesseler’ reagent (colourless) solution to pale brown.
  5. Ammonia (when in excess) gives a deep blue coloured solution with CuSO4 (aq.)

Question 27.
State (i) a light neutral gas (ii) an acid (iii) an explosive (iv) a fertilizer — obtained from ammonia.
Answer:

  1. Hydrogen
  2. Nitric acid
  3. NH4NO3
  4. Ammonium sulphate.

Question 28.
Name an ammonium salt which is a constituent of (a) smelling salts (b) dry cells.
Give reasons for the use of the named ammonium salt for the same.
Answer:

(a) Smelling salts : Ammonium carbonate, (NH4)2CO3 is used as smelling salt. It is an unstable white solid decomposes to give pungent smellingNH3 gas.
(NH4)2CO3 → 2NH3 + CO2 + H2O
The pungent smelling NH3 gas revives a fainted person. (NH4)2CO3 is always kept in a tightly closed container to prevent it from decomposition.
(b) Dry cells : Ammonium chloride(NH4Cl) is used in dry cells. It oxidises Zn to Zn2+ ions. The electrons so produced constitute the electric current.

Question 29.
Give one use with reason of

  1. an aqueous solution of NH3
  2. liquefied NH3.

Answer:
(i) Use of an Aqueous solution of Ammonia (NH3) : An aqueous solution of NH3 is called liquor ammonia. Being a base, it can easily emulsify oils and fats. Therefore, it is used for removing oil and fat stains from clothes carpets, upholstery etc. It is also used for cleaning window panes, porcelain articles etc.
(ii) Use of Liqueified Ammonia (NH3) : Liquid ammonia is used as refrigerant i.e. for producing low temperature. This is due to the following reasons:

(a) It is highly volatile.
(b) It can be easily liquefied under high pressure and low temperature.
(c) It’s latent heat of evaporation is very high.

Question 30.
State what are chlorofluorocarbons and give their use. Give a reason why they are ozone depleting. State a suitable alternative to chlorofluorocarbons which are non-ozone depleting.
Answer:
Chlorofluorocarbons (CFC’s) are compounds of carbon with chlorine or fluorine.
CFC are chemicals which like liquefied ammonia gas are used in refrigeration gas. They are also used as coolants in refrigeration and A/c Plants and aerosol sprays and cleansing agents.
These CFC’s deplete ozone layer and also contribute to global warming. Thus these CFC’s are harmful to life. The CFC’s are decomposed by ultraviolet rays coming from sun to produce highly reactive chlorine atoms i.e. free Cl radicals.
Suitable alternatives to chloroflurocarbons which are not depleting ozone are :
HCFC – Hydrochloroflurocarbons; and HFC – 125 Hydrochloroflurocarbons ; which act as a substitute for CFCs, which are non-ozone depleting.

Unit Test Paper 7b —Ammonia

Q.1. Choose the letter corresponding to the correct answer from — A : NO2, B : NO, C : N2, D : N2O.
The gas obtained when –
1. Dry ammonia and dry oxygen gas are ignited together.
2. Ammonia is passed over heated litharge.
3. A greenish yellow gas reacts with excess ammonia.
4. (a) Dry NH3 and O2 are passed over heated Pt.
(b) The gaseous product obtained is further oxidised.
5. Ammonium nitrite undergoes thermal decomposition.
Answer:

  1. C(N2)
  2. C(N2)
  3. C(N2)
  4. (a) B(NO),(b) A(NO2)
  5. D(N2O)

Q.2. State the colour of :

Question 1.
Phenolphthalein solution after passage of ammonia through it.
Answer:
Colourless phenolphthalein changes to pink colour.

Question 2.
Copper (II) hydroxide solution after-addition of ammonium hydroxide in excess to it.
Answer:
The pale blue precipitate turns into a deep blue coloured solution.

Question 3.
The flame obtained on burning dry ammonia in oxygen.
Answer:
Greenish yellow flame.

Question 4.
The solution obtained on addition of excess ammonium hydroxide to zinc sulphate solution.
Answer:
White gelantinous precipitate dissolves.

Question 5.
The vapours obtained when ammonia-oxygen gas mixture is passed over heated Pt.
Answer:
The colourless NO gas first produced is further oxidises to brown coloured NO2.

Q.3. Give balanced equations for the following conversions — A, B, C, D and E.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 57
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 58

Q.4. Give reasons for the following.

  1. An aqueous solution of ammonia acts as a weak base.
  2. A mixture of ammonium nitrate and slaked lime are not used in the lab. preparation of ammonia gas.
  3. Finely divided iron catalyst does not affect the percentage yield of ammonia in Haber’s process.
  4. Ammonium salts are formed when ammonia reacts with dilute acids in the gaseous or aq. medium.
  5. Aqueous solution of lead and zinc nitrate can be distinguished using an aqueous solution of ammonia.

Answer:

  1. Ammonia molecule contains a lone pair of electrons on N- atom, which accepts a proton from water, and forms ammonium ion and hydroxide ion, this makes ammonia solution alkaline and thus, it acts as a base.
    NH3+ H2O → NH4+ + OH
    However, as the concentration of the hydroxyl ions that are furnished is less, therefore aqueous solution of ammonia acts as a weak base.
  2. Because ammonium nitrate is explosive and decomposes itself.
  3. Formation of NH3 from N2 and H2 in haber’s process is a reversible reaction. In a reversible reaction, a catalyst does not increase the yield of the product. It only helps in attaining the equilibrium in a shorter time.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 59
  4. Ammonia in gaseous form neutralises acids to form salts.
  5. Zinc nitrate forms white gelatinous ppt. while lead nitrate forms chalky white ppt.

Q.5. Complete the statements by selecting the correct word from the words in brackets.

  1. The salt solution which does not give an insoluble precipitate on addition of ammonium hydroxide in small amount is _____ (Mg(NO3)2 / NaNO3/Cu(NO3)2]
  2. The alkaline behaviour of liquor ammonia is due to the presence of _____ ions, (ammonium / hydronium / hydroxyl)
  3. Ammonia in the liquefied form is _____ (acidic / basic / neutral)
  4. Ammonia reduces chlorine to _____ (nitrogen / hydrogen chloride / ammonium chloride)
  5. The chemical not responsible for ozone depletion is _____ [methyl chloride / ammonia / chloroflourocarbons]

Answer:

  1. NaNO3
  2. Hydroxyl
  3. basic
  4. Ammonium chloride .
  5. Ammonia

Q.6. Select the most probable substance from A, B, C, D and E which need to be added to distinguish :
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 60
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 61
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7B Study Of Compounds - Ammonia 62

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New Simplified Chemistry Class 10 ICSE Solutions – Study Of Compounds : Hydrogen Chloride

New Simplified Chemistry Class 10 ICSE Solutions – Study Of Compounds: Hydrogen Chloride

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Questions
2005

Question 1.
Write balanced equations for the following reactions :

  1. Copper oxide and dilute Hydrochloric acid.
  2. Manganese (IV) oxide and concentrated Hydrochloric acid.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 1
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 2

Question 2.

  1. Name the experiment illustrated aside.
  2. Which property of hydrogeii chloride is demonstrated by this experiment.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 3
  3. State the colour of the water that has entered the round-bottomed flask.

Answer:

  1. Fountain experiment.
  2. Hydrogen chloride is soluble in water.
  3. Red.

2006

Question 1.
From the list — Ammonia, Copper oxide, Copper sulphate, Hydrogen chloride, Hydrogen sulphide, Lead bromide — select the compound which can be oxidized to chlorine.
Answer:
Hydrogen chloride

Question 2.
Write balanced chemical equation for the reaction of zinc and dilute hydrochloric acid.
Answer:
Zn + 2HCl → ZnCl2 + H2

Question 3.
State what is observed when hydrochloric acid is added to silver nitrate solution.
Answer:
A white ppt. of silver chloride is formed.

Question 4.
Write a balanced chemical equation for the reaction of calcium bicarbonate and dil. hydrochloric acid.
Answer:
Ca(HCO3)2 + 2HCl → CaCl2 + 2CO2 + 2H2O.

2007

Question 1.
Write a balanced equation for the following reaction :
Sodium chloride from sodium carbonate solution and dilute hydrochloric acid.
Answer:
Na2CO3 + 2HCl → 2NaCl + H2O + CO2

Question 2.
Of the two gases, NH3 and HCl, which is more dense.
Name the method of collection of this gas.
Answer:
Hydrogen chloride gas ; by upward displacement of air.

Question 3.
Give one example of a reaction between the above two gases which produces a solid.
Answer:
NH3 (g) + HCl (g) → NH4 Cl (s-solid)

Question 4.
Write equations for the reaction of dil. HCl with each of the following :

  1. iron
  2. sodium hydrogen carbonate
  3. iron [II] sulphide
  4. sodium sulphite

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 4

2008

Question 1.
What property of hydrogen chloride is demonstrated when it is collected by downward delivery (upward displacement)? Why is hydrogen chloride not collected over water.
Answer:
Hydrogen chloride is heavier than air.
Hydrogen chloride cannot be collected over water because hydrogen chloride is highly soluble in water.

Question 2.
Write the equations for the following reactions :

  1. dil. HCl and sodium thiosulphate.
  2. dil. HCl and lead nitrate solution.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 5
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 6

2009

Question 1.
Name the gas evolved (formula is not acceptable). The gas produced by the action of concentrated sulphuric acid on sodium chloride.
Answer:
Hydrogen chloride (HCl)

Question 2.
Match each substance A to E listed below with the appropriate description given below :
(A) Sulphur
(B) Silver chloride
(C) Hydrogen chloride
(D) Copper (II) sulphate
(E) Graphite.
(i) A Covalent compound which behaves like an ionic compound in aqueous solution.
(ii) A compound which is insoluble in cold water but soluble in excess of ammonia solution.
Answer:

  1. (C) Hydrogen chloride
  2. (B) Silver chloride

Question 3.
Write a fully balanced equation for each of the following :

  1. Red lead is warmed with concentrated hydrochloric acid.
  2. Magnesium metal is treated with dilute hydrochloric acid.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 7

Question 4.
Correct the following statements.
HCl is prepared in the laboratory by passing hydrogen chloride directly through water.
Answer:
Hydrochloric acid is prepared in the laboratory by passing hydrogen chloride gas through inverted funnel arrangement in water.

2010

Question 1.
Select the correct answer from A, B, C and D.
(i) Aqua regia is a mixture of :
A : Dilute hydrochloric and cone, nitric acid
B : Cone, hydrochloric acid and dilute nitric acid
C : One part of cone, hydrochloric acid 3 parts of cone, nitric acid.
D : 3 parts of Cone, hydrochloric acid and 1 part of cone, nitric acid
Answer:
D : 3 parts of Cone, hydrochloric acid and 1 part of cone, nitric acid

Question 2.
State your observation when :
A glass rod dipped in NH4OH soln. is brought near an open bottle containing cone. HCl
Answer:
Dense white fumes of – ammonium chloride are formed.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 8

Question 3.

  1. State the salt and the acid, used in the laboratory preparation of hydrogen chloride.
  2. Give the equation for the preparation.
  3. State a method to prove that the gas jar used for collection of HC1 gas is filled with hydrogen chloride?
  4. Observing the method of collection of the gas, state what you can tell about the density of hydrogen chloride ?

Answer:

  1. Sodium chloride and Sulphuric acid
  2. New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 9
  3. In order to know that the jar is filled with the gas, bring a glass rod dipped in ammonium hydroxide solution near its mouth. If dense white fumes of ammonium chloride are produced, it indicates that the gas jar is full of HCl gas.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 10
  4. The method used to collect HCl is “Upward displacement of air”. This clearly indicates that HCl gas is heavier than air.

Question 4.
How would you distinguish between dilute HCl and dilute HNO3, by addition of only one solution.
Answer:
HCl (dilute)
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 11

Question 5.
Name two gases which can be used in the study of the fountain experiment.
State the common property demonstrated by the fountain experiment ?
Answer:

  1. Hydrogen chloride gas (HCl)
  2. Ammonia (NH3)
    Solubility of gases is the common property demonstrated by the fountain experiment.

2011

Question 1.
Choose the correct answer from the choices given :
Hydrogen chloride gas being highly soluble in water is dried by :
(A) Anhydrous calcium chloride
(B) Phosphorous pentaoxide
(C) Quick lime
(D) Concentrated sulphuric acid.
Answer:
(D) Concentrated sulphuric acid.

Question 2.
Write balanced equations of dil. HCl with – Calcium bicarbonate.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 12

Question 3.
In the laboratory preparation of hydrochloric acid, Hydrogen chloride gas is dissolved in water.
(i) Draw a diagram to show the arrangement used for the absorption of HCl in water.
(ii) State why such an arrangement is necessary? Give two reasons for the same.
(iii) Write balanced chemical equations for the laboratory preparation of HCl gas when the reactants are :

(A) below 200°C
(B) above 200° C

Answer:
(i) Refer to page 335 of this book.
(ii) Two reasons for the use of funnel arrangement are :

(A) Prevents back suction of water into the flask.
(B) Provides a large surface area for the absorption of the gas (HCl).

New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 13

2012

Question 1.
Rewrite the correct statement with the missing word/s :
Aqua regia contains one part by volume of nitric acid and three parts by volume of hydrochloric acid.
Answer:
Aqua regia contains one part by volume of cone, nitric acid and three parts by volume of cone, hydrochloric acid.

Question 2.
Give reasons : Hydrogen chloride gas cannot be dried over quick lime.
Answer:
Hydrogen chloride is acidic while quick lime is basic, so they react.

Question 3.
Concentrated hydrochloric acid and Potassium permanganate solution.
Answer:

Question 4.
Give balanced equations with conditions, if any, for the following conversions A to D.
A : Sodium Chloride → Hydrogen Chloride
B : Hydrogen Chloride → Iron (II) chloride
C : Hydrogen Chloride → Ammonium chloride
D : Hydrogen Chloride → Lead chloride.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 14

2013

Question 1.
Identify the gas evolved when :

  1. Potassium sulphite is treated with dilute hydrochloric acid.
  2. concentrated hydrochloric acid is made to react with manganese dioxide.

Answer:

  1. Sulphur dioxide gas
  2. Chlorine gas

Question 2.
State one appropriate observation for

  1. Copper sulphide is treated with dilute hydrochloric acid.
  2. A few drops of dil. HCl are added to AgNO3 soln, followed by addition of NH4OH soln.

Answer:

  1. A colourless gas with a smell of rotten eggs is given off and a green coloured solution is formed.
  2. White ppt is formed which dissolves in ammonium hydroxide.

2014

Question 1.
Fill in the blanks from the choices in the bracket : Quicklime is not used to dry HCl gas because _____ (CaO is alkaline, CaO is acidic, CaO is neutral)
Answer:
Quicklime is not used to dry HCl gas because CaO is alkaline.

Question 2.
Write the balanced equation for : Action of dilute hydrochloric acid on sodium sulphide.
Answer:
Action of dilute hydrochloric acid on sodium sulphide.
Na2S + 2HCl → 2NaCl + H2S

Question 3.
State your observation : Dilute HC1 is added to sodium carbonate crystals.
Answer:
Na2CO3 + 2HCl → 2NaCl + H2O + CO2
effervescence of CO2 seen which turns lime water milky

Question 4.
Study the figure given below and answer the questions that follow :
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 15

  1. Identify the gas Y.
  2. What property of gas Y does this experiment demonstrate?
  3. Name another gas which has the same property and can be demonstrated through this experiment.

Answer:

  1. Identify the gas Y — It is HCl (Hydrogen chloride)
  2. Property of Y —Highly solubility in water
  3. The another gas has same property — NH3 (Ammonia)

2015

Question 1.
Select from the gases — ammonia, ethane, hydrogen chloride, hydrogen sulphide, ethyne — The gas which produces dense white fumes with ammonia gas.
Answer:
Hydrogen chloride

Question 2.
Identify the acid which on mixing with silver nitrate solution produces a white precipitate which is soluble in excess ammonium hydroxide.
Answer:
Dilute hydrochloric acid

Question 3.
The following questions are pertaining to the laboratory preparation of hydrogen chloride gas:

  1. Write the equation for its preparation mentioning the condition required.
  2. Name the drying agent used in the above preparation and give a reason for the choice.
  3. State a safety precaution you would take during the preparation of hydrochloric acid.

Answer:

  1. The equation for the laboratory preparation of hydrogen chloride gas :
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 16
    Although it is a reversible reaction, it goes to completion as hydrogen chloride continuously escapes as a gas.
    The reaction can occur up to the stage of the formation of sodium sulphate on heating above 200°C.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 17
  2. The drying agent used in the laboratory preparation of hydrochloric acid is conc.sulphuric acid.
    The other drying agents such as phosphorus pentoxide (P2O5) and quick lime
    (CaO) cannot be used because they react with hydrogen chloride.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 18
  3. A safety precaution which should be taken during the preparation of hydrochloric acid :
    Always wear chemical splash goggles, chemical-resistant gloves and a chemical resistant apron in the laboratory during the preparation of hydrochloric acid.

2016

Question 1.
Select the correct answer from A, B, C and D : The aim of the Fountain experiment is to prove that :
(A) HCl turns blue litmus red
(B) HCl is denser than air
(C) HCl is highly soluble in water
(D) HCl fumes in moist air.
Answer:
(C) HCl is highly soluble in water

Question 2.
Fill in the blank : _____ (AgCl / PbCl2), a white precipitate is soluble in excess NH4OH.
Answer:
AgCl (because of formation of diammine silver chloride), a white precipitate is soluble in excess NH4OH.

Question 3.
Write balanced chemical equation for : Action of hydrochloric acid on sodium bicarbonate.
Answer:
NaHCO3 + HCl → NaCl + H2O + CO2

Question 4.
State your observations when dilute hydrochloric acid is added to :

  1. Lead nitrate soln. and the mixture is heated.
  2. Copper carbonate.
  3. Sodium thiosulphate.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 19
When dilute hydrochloric acid is added to lead nitrate white precipitates of lead chloride is formed.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 20
When dilute hydrochloric acid is added to copper carbonate brisk effervescence due to the liberation of carbon dioxide is observed.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 21
When dilute hydrochloric acid is added to sodium thiosulphate pale yellow residue (due to formation of sulphur) is formed and a gas with choking odour is formed.

Question 5.
Identify the gas evolved and give the chemical test in when dilute hydrochloric acid reacts with :

  1. Sodium sulphite.
  2. Iron (II) sulphide.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 22

2017

Question 1.
Fill in the blanks from the choices given – Potassium sulphite on reacting with hydrochloric acid, releases gas. _____ [Cl2, SO2, H2S]
Answer:
Potassium sulphite on reacting with hydrochloric acid, releases SO2 gas.

Question 2.
Identify the substance underlined – A solid formed by the reaction of two gases, one of which is acidic and the other basic in nature.
Answer:
Ammonium chloride.

Question 3.
State one relevant observation – Action of dilute hydrochloric acid on iron [II] sulphide.
Answer:
A foul smelling gas like rotten eggs is given off.

Question 4.
Certain blanks spaces are left in the following tables as A & 8. Identify each of them.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 23
Answer:
A : The products are sodium hydrogen sulphate (NaHSO4) and HCl gas.
B : HCl gas as collected by the upward displacement of air.

Q. Complete the statements given below pertaining to hydrogen chloride gas or hydrochloric acid.

  1. Hydrogen chloride gas is not dried using _____ (cone.H2SO4, CaO).
  2. Hydrogen chloride gas on heating above 500°C gives hydrogen and chlorine.
    The reaction is an example of _____ (thermal decomposition, thermal dissociation).
  3. Iron reacts with hydrogen chloride gas forming [iron (II) chloride, iron (III) chloride) and hydrogen. The reaction is an example of _____ (double decomposition, synthesis, simple displacement).
  4. Hydrogen chloride and water are examples of (polar covalent compounds, non-polar covalent compounds) and a solution of hydrogen chloride in water _____ (contains, does not contain) free ions.
  5. Addition of _____ (sodium nitrate, zinc nitrate, silver nitrate) to hydrochloric acid, gives an insoluble precipitate of the respective chloride. This precipitate is _____ (soluble,insoluble) in ammonium hydroxide and _____ (soluble, insoluble) in dilute taitric add.
  6. Addition of _____ [iron (III) sulphide, iron (II) sulphide, iron pyrites] to dilute hydrochloric acid results in liberation of hydrogen sulphide gas.
  7. Aqua regia is a mixture of _____ (one, two, three) part/s of concentrated nitric acid and )_____ (one, two, three) part/s of concentrated hydrochloric acid by _____ (weight, volume). In aqua regia, nitric acid _____ (oxidises, reduces) hydrochloric acid to chlorine.
  8. Hydrochloric acid can be converted into chlorine by heating with _____ [calcium oxide, lead (H) oxide, lead (IV) oxide] which acts as a / an _____ (oxidising, reducing) agent.

Answer:

  1. CaO
  2. Thermal dissociation
  3. Iron (II) chloride ; simple displacement
  4. polar covalent compounds ; contains
  5. silver nitrate ; soluble ; insoluble
  6. iron (II) sulphide
  7. one, three, volume, oxidises
  8. Lead (II) oxide ; oxidisirig.

Additional Questions

Question 1.
Give a reason why
(a) gastric juices of luammals are acidic
(b) HCl is considered a polar covalent compound.
Answer:
(a) HCI gas occurs in free state in gastric juices of mammals.
(b) Due to difference in electronegativities of H and Cl ; The bond in HCl is a polar covalent.

Question 2.
Give the equation for preparation of HCI gas by Synthesis. State two conditions involved in the synthesis.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 24

Question 3.
Give a balanced equation for preparation of HCl gas in the laboratory from sodium chloride.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 25

Question 4.
In the laboratory preparation of HCl frem sodium chloride, state why the following are preferred –

  1. Cone. H2SO4 as a reactant
  2. Temp, below 200°C
  3. Cone. H2SO4 as a drying agent.

Answer:

  1. Since it is non-volatile and has a high boiling point.
  2. The glass apparatus does not crack, no hard crust is formed, fuel is not wasted.
  3. It only removes moisture content of the gas but not react with it.

Question 5.
State with reasons the method of collection of HCl gas in the laboratory.
Answer:
HCl gas is collected by upward displacement of air because it is 1.28 times heavier than air. It is not collected in water because it is highly soluble in water.

Question 6.
Compare the density of HCl gas with air and state the solubility of HCl gas in water.
Answer:
V.D of HCl = 18.25, V.D of air = 14.4. It is highly soluble in water.

Question 7.
State why HCl gas forms a mist of droplets of HCl acid in moist air.
Answer:
Due to high solubility, HCl gas fumes in moist air and forms a mist of droplets of HCl acid.

Question 8.
State what the fountain experiment demonstrates with reference to HCl gas.
Answer:
Fountain experiment demonstrates the solubility of HCI gas in water and its acidic nature.

Question 9.
State the colour change in three different indicators in presence of HCl gas.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 26

Question 10.
Give a balanced equation for the thermal dissociation of

  1. a gas
  2. a solid (both containing the chloride ion).

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 27

Question 11.
Give the equation and state the observation seen when HCl gas reacts with ammonia.
Answer:
When a gas jar containing hydrogen chloride gas is inverted over ajar full of ammonia gas, dense white fumes are formed.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 28

Question 12.
Convert iron to iron (II) chloride using HCl gas.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 29

Question 13.
Explain the arrangement (i) not used (ii) used – for converting HCl gas into HCl acid.
Answer:
Hydrochloric acid is prepared by dissolving hydrogen chloride gas in water usi ig a special funnel arrangement.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 30
1. Direct absorption of HCl gas in water using a delivery tube i.e., arrangement (i) causes back suction.
Hydrogen chloride gas is extremely soluble in water. If a delivery tube through which HCl gas is passed is directly immersed in water, the rate of absorption of HCl gas is high and hence a partial vacuum is created in the tube. The pressure outside being higher causes the water to be pushed up into the delivery tube and damages the apparatus. This is called back-suction.
2. Special funnel arrangement, i.e., arrangement (ii) is used for avoiding back suction.
The funnel arrangement :

(a) Prevents or minimizes back-suction of water.
(b) Provides a large surface area for absorption of HCl gas.

The rim of the funnel is placed so that it just touches the trough containing water. If back-suction occurs, the water rises up the funnel and the level outside the funnel falls, thus creating an air gap between the rim of the funnel and the surface of water. The pressure outside and inside equalize and the water which had risen in the funnel falls down again. This process continues till the water in the trough is saturated with hydrogen chloride gas resulting information of hydrochloric acid.
Hence hydrochloric acid is not prepared in the laboratory by passing hydrogen chloride gas directly through water, but prepared using a special funnel arrangement.

Question 14.
Explain the term ‘constant boiling mixture’.
Answer:
A solution of HCl in water forms a constant boiling mixture with water.

Question 15.
State why dilute HCl cannot be concentrated beyond a certain concentration by boiling.
Answer:
On boiling the mixture evolves out the vapours of both acid and water in the same proportion as in the liquid. Hence dil HCl cannot be concentrated beyond a certain concentration.

Question 16.
Name the ions obtained when HCl dissociates in aqueous solution.
Answer:
Hydronium ions.

Question 17.
Name the ion responsible for acidic nature of HCl acid.
Answer:
The presence of hydrogen ions |H+| imparts acidic nature to HCl.

Question 18.
State which of two – a solution of HCl in water or in toluene is an electrolyte, giving reasons.
Answer:
A solution of hydrogen chloride in water; water being a covalent solvent ionizes aqueous solution of HCl shows acidic properties and is an electrolyte, whereas toluene is not; being not a polar solvent.

Question 19.
Give four different word equations relating to acidic properties of an aq. soln. of HCl gas.
Answer:
Zinc + Hydrochloric acid → Zinc chloride + Hydrogen
Sodium hydroxide + Hydrochloric acid → Sodium chloride + Water
Sodium carbonate + Hydrochloric acid → Sodium chloride + Carbon dioxide + Water
Calcium oxide + Hydrochloric acid → Calcium chloride + Water

Question 20.
Give balanced equations to obtain

  1. H2
  2. CO2
  3. SO2
  4. H2S from dil. HCl.

Answer:

  1. Zn + 2HCl → ZnCl2 + H2
  2. Na2CO2 + 2HCl → 2NaCl + H2O + CO2
  3. Na2SO3 + 2HCl → 2NaCl + H20 + SO2
  4. FeS + 2HCl → FeCl2 + H2S

Question 21.
Convert two soluble metallic nitrates to insoluble metallic chlorides using dil. HCl.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 31

Question 22.
State how you would prove that HCl contains

  1. hydrogen – using an active metal below magnesium
  2. chlorine – using an oxidising agent not containing lead.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 32

Question 23.
State the composition of aqua regia. State which component is the oxidising agent in aqua regia.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 33

Question 24.
Convert hydrochloric acid to nascent chlorine.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 34

Question 25.
State why aqua regia dissolves gold, which is insoluble in all other acids.
Answer:
In aqua regia (a mixture of 1 part cone. HNO3 and 3 parts cone. HCl by volume), nitric acid oxidises hydrochloric acid to give nascent chlorine. This nascent chlorine is very reactive. It reacts with gold to give gold (III) chloride, which is soluble in water.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 35

Question 26.
Give three tests for hydrochloric acid. Convert silver nitrate to a soluble salt of silver using hydrochloric acid and an alkali.
Answer:

  1. If glass rod dipped in ammonia soln. (NH4OH) brought near vapours of hydrochloric acid.
    Dense white fumes of – ammonium chloride are formed.
  2. Addition of silver nitrate soln. to dil. HCl (acidified with dil. HNO3)
    Curdly white precipitate – of silver chloride obtained.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 36
  3. Action of heat on a mixture of manganes dioxide and cone. HCl Greenish yellow gas (chlorine).

Question 27.
State two industrial products manufactured from hydrochloric acid, which are also manufactured from nitric and sulphuric acid. Give two general uses of hydrochloric acid.
Answer:
Industrial products manufactured from HCl acid are : Dyes, paints, drugs.
General uses of hydrochloric acid are :

  1. Hydrochloric acid dissolves the calcium phosphate present in bones.
  2. Hydrochloric acid dissolves the metallic oxides coating on the surface of metals. Thereby cleans the metallic surface.

Unit Test Paper 7A — Hydrogen Chloride

Q.1. Give balanced equations for the conversions A, B, C, D and E given below :
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 37
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 7A Study Of Compounds - Hydrogen Chloride 38

Q.2. Give reasons for the following :

Question 1.
In the laboratory preparation of HCl acid from NaCl and cone. H2SO4, the residual salt formed at temperatures above 200°C forms a hard crust and sticks
to the glass.
Answer:
When sodium chloride and cone, sulphuric acid is heated above 200°C ; sodium sulphate forms a hard crust, sticks to the glass and is difficult to remove.

Question 2.
Dense white fumes are obtained when a jar of HCl gas is inverted over a jar of ammonia gas.
Answer:
When a gas jar containing hydrogen chloride gas is inverted over of jar full of ammonia gas dense white fumes are formed. These fumes consists of particles of solid ammonium chloride suspended in air.

Question 3.
In the fountain experiment to demonstrated the high solubility of HCl gas in water, dry HCl gas is filled in the round bottom flask.
Answer:
HCl gas present in the flask dissolves in water due to high solubility, creating a partial vacuum in the flask. The outside pressure being higher pushes the water up the jet tube which emerges as fountain.

Question 4.
Iron sheets are cleaned with hydrochloric acid before dipping into molten zinc for galvanizing.
Answer:
Hydrochloric acid dissolves the metallic oxide coating on the surface of the metal, thereby cleans the metallic surface.

Question 5.
Hydrogen chloride gas fumes in moist air but hydrogen sulphide gas does not.
Answer:
HCl gas fumes in moist air due to its high solubility and forms a mist of droplets of HCl acid while H2S does not.

Q.3. Complete the statements given below using the correct word/s

  1. An aqueous solution of HCl gas is named _____ (aqua fortis/muriatic acid/oil of vitriol)
  2. The salt obtained when rock salt reacts with cone. H2SO4 at temperatures below 200°C is a/an _____ (acid/normal) salt.
  3. In the preparation of HCl acid from HCl gas, a funnel arrangement provides _____ (less/more) surface area for absorption of the gas.
  4. The ions which impart acidic properties to an aqueous solution of hydrogen chloride are _____ (chloride/hydrogen/hydronium)
  5. The indicator which does not change colour on passage of hydrogen chloride gas is _____ (moist blue litmus/phenolphthalein/methyl orange)

Answer:

  1. mutriatic acid
  2. normal
  3. more
  4. hydrogen
  5. phenolphthalein

Q.4. Choose from the letters A, B, C, D and E, to match the descriptions 1 to 5 given below.
A : NH4 Cl
B : AgCl
C : PbCl2
D : FeCl2
E : Ag(NH3)2 Cl

  1. A solubl salt obtained on reaction of a metallic chloride with liquor ammonia.
  2. A salt which is insoluble in dilute nitric acid but soluble in ammonium hydroxide.
  3. A salt obtained on reaction of an active metal with hydrogen chloride gas.
  4. A salt obtained when a basic gas reacts with hydrogen chloride gas.
  5. A salt soluble in hot water but not in cold, obtained on heating an oxidising agent with cone. HCl.

Answer:

  1. E [Ag (NH3)2 Cl]
  2. B (AgCl)
  3. D (FeCl2)
  4. A (NH4Cl)
  5. C (PbCl2)

Q.5. Select the correct word or formula from the same given in bracket :

  1. The substance reacted with cone. HCl and heated to prove that cone. HCl contains Cl2. (PbCl2/PbO2/Pb0)
  2. The metal reacted with dil. HCl to prove that dil. HCl contains hydrogen. (Cu/Fe/Ag/Pb)
  3. The gas/es which is / are heavier than air and highly soluble in water. (NH3 / HCl/CO2/H2S)
  4. The acid which is not an oxidising agent. (Cone. HNO3/ Cone. HCl/Conc. H2SO4)
  5. The acid which is not a monobasic acid. (Acetic/ Sulphurous/Hydrochloric/Nitric/Formic acid)

Answer:
1. PbO2
2. Fe
3. HCl(g)
4. Cone. HNO3
5. Sulphurous acid

Q.6. Select the correct words from the list given below to complete the following word equations :
Metallic oxide, active metal, metallic carbonate, metallic bisulphite, active metal, metallic hydroxide, metallic bicarbonate, metallic sulphate, metallic sulphide.

  1. _____ + hydrochloric acid (dil) → salt + hydrogen
  2. _____ + hydrochloric acid (dil) → salt + water
  3. _____ + hydrochloric acid (dil) → salt + water + carbon dioxide
  4. _____ + hydrochloric acid (dil) → salt + water + sulphur dioxide
  5. _____ + hydrochloric acid (dil) → salt + hydrogen sulphide

Answer:

  1. active metal
  2. metallic hydroxide
  3. metallic carbonate / bicarbonate
  4. metallic sulphite
  5. metallic sulphide


For More Resources

New Simplified Chemistry Class 10 ICSE Solutions – Metallurgy

New Simplified Chemistry Class 10 ICSE Solutions – Metallurgy

ICSE SolutionsSelina ICSE SolutionsML Aggarwal Solutions

Viraf J Dalal Chemistry Class 10 Solutions and Answers

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For Objective and ICSE Board Type Questions Questions (Solved)

2002

Question 1.
Match the metals/alloys – brass, with its correct use.
Uses : (a) steel making (b) aeroplane wings (c) galvanizing (d) radiation shield (e) electrical fittings
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 1

Question 2.
In order to obtain aluminium, the following inputs are required : Bauxite, sodium hydroxide and graphite. The aluminium compound in bauxite is aluminium oxide and the main impurity is iron (III) oxide. Aluminium is obtained by the electrolysis of aluminium oxide dissolved in cryolite,

  1. When bauxite is treated with sodium hydroxide solution what happens to the : (a) aluminium oxide (b) iron (c) oxide.
  2. Name the process used for the purification of bauxite.
  3. Write the equation for the action of heat on aluminium hydroxide
  4. Write the formula of cryolite.

Answer:
(i) (a) Aluminium oxide reacts with NaOH (aq.) at 150-200°C to give sodium aluminate which is soluble in water.
(b) Iron (II) oxide remains unaffected.
(ii) Baeyer’s method is used for removal of impurities.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 2
Aluminium hydroxide write below Al2O3
(iv) Formula of cryolite – (Na3 Al F6)

Question 3.
Write down the word which correctly completes the following sentence : “By dissolving aluminium oxide in cryolite a __ [conducting / non-conducting] solution is produced.
State why is so much graphite is requires for this electrolytic process.
Write the equation for the reaction which takes place at the cathode.
Answer:
“By dissolving aluminium oxide in cryolite a conducting solution is produced.
The graphite anodes are periodically replaced during electrolysis process of fused alumina.
At cathode : 2Al3+ + 6e → 2Al

Question 4.
In construction work, state why the alloy duralumin is used rather than pure aluminium.
Answer:
Duralumin is light, strong and corrosion resistant.

2003

Question 1.
Name an alloy of copper and zinc.
Answer:
Brass

2004

Question 1.
Element X is a metal with a valency 2. Element Y is a nonmetal with a valency 3.
Write equations to show how X and Y form ions.
Answer:
Y + 3e → Y3 (cations formed)

Question 2.
Cations are formed by _____ (loss / gain) of electrons and anions are formed by _____ (loss / gain) of electrons.
Answer:
Cations are formed by loss of electrons and anions are formed by gain of electrons.

Question 3.
(i) Write three balanced equations for the purification of bauxite by Hall’s process in extraction of Al.
(ii) Name a chemical used for dissolving Al2O3. In which state of subdivision is the chemical used.
(iii) Write an equation for the reaction at the anode during the extraction of aluminium by the electrolytic process.
(iv) Mention one reason for the use of aluminium in thermite welding.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 3

2005

Question 1.
A to F below relate to the source and extraction of either Zinc or Aluminium. A : Bauxite, B : Coke, C : Cryolite, D : Froth floatation, E : Sodium hydroxide solution, F : Zinc blende.

  1. Write down the three letters each from the above list which are relevant to – Aluminium.
  2. Fill in the blanks using the most appropriate words from A to F : (a) The ore from which aluminium is extracted must first be treated with so that pure Aluminium oxide can be obtained. (b) Pure Aluminium oxide is dissolved in to make a conducting solution
  3. Write the formula of Cryolite.

Answer:

  1. Aluminium: Bauxite (A), Cryolite (C), Sodium hydroxide solution (F).
  2. (a) Sodium Hydroxide Solution (b) Cryolite
  3. Na3AlF6

Question 2.
Calcium, Copper, Lead, Aluminium, Zinc, Chromium, Magnesium, Iron.
Choose the major metals from the list given above to make the following alloys :

  1. Stainless steel
  2. Brass.

Answer:

  1. Iron, Chromium
  2. Copper, Zinc

2006

Question 1.
Name the following :

  1. A metal which is liquid at room temperature.
  2. A compound added to lower the fusion temp, of the electrolytic bath in the extraction of Al.
  3. The process of heating an ore to a high temperature in the presence of air.

Answer:

  1. Mercury or Gallium
  2. Cryolite [Na3 (AlF6)]
  3. Roasting

Question 2.
A strip of copper is placed in four different colourless salt solutions. They are KNO3, AgNO3, Zn(NO3)2, Ca(NO3)2.
Which one of the solutions will finaky turn blue.
Answer:
Silver Nitrate (AgNO3)

Question 3.
When a metal atom becomes an ion
A : it loses electrons and is oxidized
B : it gains electrons and is reduced
C : it gains electrons and is oxidized
D : it loses electrons and is reduced
(Choose the correct answer from the choices A, B, C and D)
Answer:
A : it loses electrons and is oxidized

2007

Question 1.
In the extraction of aluminium :

  1. Which soln. is used to react with bauxite as a first step in obtaining pure aluminium oxide.
  2. The aluminium oxide for the electrolytic extraction of aluminium is obtained by heating aluminium hydroxide. Write the equation for this reaction.
  3. Name the element which serves as the anode and cathode in the extraction of aluminium.
  4. Write the equation for the reaction that occurs at the cathode during the extraction of aluminium by electrolysis.
  5. Give the equation for the reaction at the anode when aluminium is purified by electrolysis.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 4

2008

Question 1.
Brass is an alloy of :
A. Copper and tin
B. Copper and zinc
C. Zinc and lead
D. Lead and tin
Answer:
B. Copper and zinc

Question 2.
The following is a sketch of an electrolytic cell used in the extraction of aluminium :

  1. What is the substance of which the electrodes A and B are made?
  2. At which electrode (A or B) is the aluminium formed ?
  3. What are the two aluminium compounds in the electrolyte C ?
  4. Why is it necessary for electrode B to be continuously replaced ?

New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 5

Answer:

  1. Electrodes A and B are made of graphite. Electrode B is carbon (graphite) lining while, electrode A is thick rods of graphite.
  2. Aluminium is formed at cathode in the molten state which can be taken out through a tapping hole.
  3. The two aluminium compounds in the electrolyte C are Alumina (Al2O3) and Cryolite (Na3AlF6).
  4. This is because electrode (B i.e. anode) is oxidised by the oxygen produced to carbon monoxide.

2009

Question 1.
The metal oxide which can react with acid as well as alkali is :
A. Silver oxide
B. Copper (II) oxide
C. Aluminium oxide
D. Calcium oxide
Answer:
C. Aluminium oxide

Question 2.
Correct the following statements. — Haematite is the chief ore of aluminium.
Answer:
Haematite is the chief ore of iron.
Or
Bauxite is the chief ore of aluminium.

Question 3.
The sketch below illustrates the refining of aluminium by Hoope’s process.

  1. Which of A and B is the cathode and which one is the anode ?
  2. What is the electrolyte in the tank?
  3. What material is used for the cathode ?

New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 6

Answer:

  1. A are graphite rods and they act as cathode, B act as anode.
  2. Molten Fluorides.
  3. Graphite rods dipped in pure molten aluminium.

Question 4.
State the property of the metal being utilized in the following :

  1. Zinc in Galvanization
  2. Aluminium in Thermite welding

Answer:
Use of metal :

(a) Zinc in Galvanization
(b) Aluminium in Thermite welding

Property :

(a) Zinc forms a protective layer of zinc oxide which prevents rusting of iron.
(b) Strong affinity for oxygen.

2010

Question 1.
State the main constituent metal in each alloy :

  1. Duralumin
  2. Brass
  3. Stainless steel

Answer:

  1. Aluminium
  2. Copper
  3. Iron

Question 2.
Select the correct answer from A, B, C and D – The property which is true for metals.
A : Metals are good conductors of electricity
B : Metals are malleable and ductile
C : Non-polar covalent compounds are formed from metals.
D : Metals have 1, 2 or 3 valence electrons.
Answer:
C : Non-polar covalent compounds are formed from metals.

2011

Question 1.
Choose from the following list of the substances, Acetylence gas, aqua fortis, coke, brass, barium chloride, bronze, platinum.
The substance which is an alloy of zinc, copper and tin.
Answer:
Bronze

Question 2.

(i) Name a metal which is found abundantly in the earth’s crust.
Answer:
Aluminium

(ii) Difference between calcination and roasting?
Answer:
Roasting :

  1. Ore is heated in the presence of air.
  2. Used generally for sulphide ores. SO2 gas is given off.
    2ZnS+ 3O2 → 2ZnO + 2SO2
  3. Volatile impurities are removed as oxides.

Calcination :

  1. Ore is heated in the absence of air.
  2. Hence Used generally for carbonate ores.
    Hence, CO2 gas is given off. ZnCO3 → ZnO + CO2.
  3. Moisture, organic impurities and volatile impurities are removed.

(iii) Name the process used for the enrichment of sulphide ore.
Answer:
Froth floatation process

(iv) Write the chemical formulae of one main ore – of iron and aluminium.
Answer:

  • Iron : Haematite → Fe2O3
  • Aluminium : Bauxite → Al2,O3.2H2O

(v) Write the constituents of electrolyte for – the extraction of aluminium.
Answer:

  1. Fused Alumina (Al2O3) 1 part by weight.
  2. Cryolite fused (Na3 AlF6) 3 part by weight.
  3. Fluorspar (CaF2) 1 part by weight.

2012

Question 1.
Choose the correct answer from the options given below

(i) An alkaline earth metal.
(A) Potassium
(B) Calcium
(C) Lead
(D) Copper
Answer:
(B) Calcium

(ii) Which of the following metallic oxides cannot be reduced by normal reducing agents ?
(A) Magnesium oxide
(B) Copper(II) oxide
(C) Zinc oxide
(D) Iron(III) oxide
Answer:
(A) Magnesium oxide

Question 2.
Match the properties and uses of alloys in List 1 with the appropriate answer from List 2.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 7
Answer:

  1. (B) Brass
  2. (A) Duralumin
  3. (D) Stainless stell
  4. (E) Solder
  5. (C) Bronze

Question 3.
Name the following metals :

  1. A metal present in cryolite other than sodium.
  2. A metal which is unaffected by dilute or concentrated acids.

Answer:

  1. Aluminium
  2. Platinum

Question 4.
The following questions are relevant to the extraction of Aluminium :

  1. State the reason for addition of caustic alkali to bauxite ore during purification of bauxite.
  2. Give a balanced chemical equation for the above reaction.
  3. Along with cryolite and alumina, another substance is added to the electrolyte mixture. Name the substance and give one reason for the addition.

Answer:

  1. The caustic alkali dissolves aluminium oxide to form sodium aluminate.
  2. New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 8
  3. Fluorspar is added. It helps in increasing the conductivity of the mixtures.

2013

Question 1.
The amphoteric metallic oxide is
(A) Calcium oxide
(B) Barium oxide
(C) Zinc oxide
(D) Copper (II) oxide
Answer:
(C) Zinc oxide is an amphoteric oxide

Question 2.
The metals zinc and tin are present in the alloy :
(A) Solder
(B) Brass
(C) Bronze
(D) Duralumin.
Answer:
(C) Bronze

Question 3.
Using the information below about X and Y – complete the following questions :

New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 9

  1. ____ is the metallic element.
  2. Metal atoms tend to have a maximum of _____ electrons in the outermost energy level.
  3. Non-metallic elements tend to form _____ oxides while metals tend to form _____ oxides.
  4. Non-metallic elements tend to be _____ conductors of beat and electricity.
  5. Metals tend to _____ electrons and act as _____ agents in their reactions with elements and compounds,

Answer:

  1. Y is the metallic element.
  2. Metal atoms tend to have a maximum of three electrons in the outermost energy level.
  3. Non-metallic elements tend to form acidic oxides while metals tend to form basic oxides.
  4. Non-metallic elements tend to be bad conductors of heat and electricity.
  5. Metals tend to lose electrons and act as reducing agents in their reactions with elements and compounds.

Question 4.
The following questions relate to the extraction of aluminium by electrolysis :

(i) Name the other aluminium containing compound added to alumina and state its significance,
Answer:
The compound is cryolite [Na3AlF6]
The addition of cryolite lowers the melting point of alumina from 2050°C to 660 °C.
Furthermore, it increases the electrical conductivity of the molten alumina.

(ii) Give the equation for the reaction that takes place at the cathode.
Answer:
Al3+ + 3e → Al

(iii) Explain why is it necessary to renew the anode periodically.
Answer:
The anode (which is made of carbon) is attacked by nascent oxygen formed due to the discharge of O2- ions and changes to carbon dioxide. As the anode is gradually consumed, it is periodically renewed.

2014

Question 1.
Choose the correct answer from the choices :

(i) Heating an ore in a limited supply of air or in the absence of air at a temperature just below its melting point is known as :
(A) smelting
(B) ore dressing
(C) calcination
(D) bessemerisation
Answer:
(C) calcination

(ii) Aluminium powder is used in thermite welding because,
(A) it is a strong reducing agent
(B) it is a strong oxidising agent
(C) it is corrosion resistant
(D) it is a good conductor of heat.
Answer:
(A) it is a strong reducing agent

(iii) The main ore used for the extraction of iron is :
(A) Haematite
(B) Calamine
(C) Bauxite
(D) Cryolite
Answer:
(A) Haematite

Question 2.
State the main components of the following alloys :

  1. Brass
  2. Duralumin
  3. Bronze.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 10

Question 3.
Name the following :

  1. The property possessed by metals by which they can be beaten into sheets.
  2. A compound added to lower the fusion temperature of electrolytic bath in the extraction of aluminium.
  3. The ore of zinc containing its sulphide.

Answer:

  1. Melleability
  2. Cryolite (Na3AlF6)
  3. The ore of zinc containing sulphide ZnS (Zinc Blende).

2015

Question 1.
Select which is not an alloy of copper :
(A) Brass
(B) Bronze
(C) Solder
(D) Duralumin.
Answer:
(C) Solder
Solder is an alloy of lead and tin.

Question 2.
Give scientific reasons for : Zinc oxide can be reduced to zinc by using carbon monoxide, but aluminium oxide can – not be reduced by a reducing agent.
Answer:
Zinc ion is lower in electrochemical series. Thus, carbon monoxide provides enough energy and hence reduces zinc oxide to zinc. Aluminium ion is higher in electrochemical series. The carbon monoxide does not produce enough energy and hence aluminium oxide is not reduced to aluminium.

Question 3.
From the list of oxides — SO2, SiO2, Al2O3, MgO, CO, Na2O — Select

  1. A basic oxide
  2. An amphoteric oxide.

Answer:

  1. Na2O
  2. Al2O3

Question 4.
A metal ‘X’ has a valency 2 and a non-metal ‘Y’ has a valency 3. Write an equation to show how ‘Y’ forms an ion.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 11

Question 5.
(i) Describe the role played in the extraction of aluminium by each of the substances listed.

(a) Cryolite
(b) Sodium hydroxide
(c) Graphite

(ii) Explain why :

(a) In the electrolysis of alumina using the Hall Heroult’s Process the electrolyte is covered with powdered coke.
(b) During galvanization, iron sheets are coated with zinc during galvanization.

Answer:
(i)

(a) Cryolite lowers the melting point of alumina from 2050° to 950°C. This in turn increases the conductivity of electrolyte and saves on electricity, which is the main source of energy in the reduction of alumina.
(b) Sodium hydroxide dissolves the alumina (Al2O3), but not the impurities to form sodium aluminate. The impurities are filtered out and the sodium aluminate is treated with carbon dioxide to form pure aluminium hydroxide. Alumina is recovered from sodium hydroxide by strong heating.
(c) Graphite is used as cathode as it is a good conductor of electricity and is not attacked by the chemicals.

(ii)

(a) It prevents burning of carbon anodes and prevents heat loss from the molten electrolyte.
(b) Zinc forms a protecting coating on the surface of iron and hence prevents it from rusting. Zinc by itself form a protective layer of zinc oxide and hence does not tarnish.

Question 6.
Select from the following salts — AgCl, MgCl2, NaHSO4, PbCO3, ZnCO3, KNO3, Ca(NO3)2 — the salt which on heating gives a yellow residue when hot and white when cold.
Answer:
On heating, this salt gives a yellow residue when hot and a white residue when cold is ZnCO3

2016

Question 1.
Fill in the blanks from the choices given :
Metals are good _____ (oxidizing agents/reducing agents)
because they are electron _____ (acceptors / donors).
Answer:
Metals are good reducing agents because they are electron donors.

Question 2.
Select the correct answer from A, B, C and D :kThe two main metals in Bronze are :
(A) Copper and zinc
(B) Copper and lead
(C) Copper and nickel
(D) Copper and tin
Answer:
(D) Copper and tin

Question 3.
Identify the term in the following :
“The method used to separate ore from gangue by preferential wetting.”
Answer:
Froth flotation process

Question 4.

  1. Name the solution used to react with Bauxite-as a first step in obtaining pure aluminium oxide, in the Baeyer’s process.
  2. Write the equation for the reaction where the – aluminum oxide for the electrolytic extraction of aluminum is obtained by heating aluminum hydroxide.
  3. Name the compound added to – pure alumina to lower the fusion temperature during the electrolytic reduction of alumina.
  4. Write the equation for – the reaction that occurs at the cathode during the extraction of aluminium by electrolysis.
  5. Explain why – it is preferable to use a number of graphite electrodes as anode instead of a single electrode, during the abvoe electrolysis.

Answer:

  1. Sodium hydroxide.
  2. New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 12
  3. Cryolite (Na3Al F6) acts as a solvent and lower the fusion temperature from 2050°C to 950°C.
  4. Cathode : (rich in electron)
    AL3 + 3e → Al
  5. It is preferable to use a number of graphite electrodes as anode because anode gets oxidised by the oxygen evolved.
    Hence, if large number of electrodes are used it will keep the process continuous for a longer time.

2017

Question 1.
From the list of terms given, choose the most appropriate term to match the given description: [calcination, roasting, pulverisation, smelting]

  1. Crushing of the ore into a fine powder.
  2. Heating of the ore in the absence of air to a high temperature.

Answer:

  1. Pulverisation
  2. Calcination

Question 2.
Name the following :

  1. An alloy of lead and tin that is used in electrical circuits.
  2. An ore of zinc containing its sulphide.
  3. A metal oxide that can be reduced by hydrogen.

Answer:

  1. Fusible alloy
  2. Zincite (ZnS)
  3. Copper oxide (CuO)

Question 3.
Answer the following questions with respect to the electrolytic process – in the extraction of aluminium.

  1. Identify the components of the electrolyte other than pure alumina and the role played by each.
  2. Explain why powdered coke is sprinkled over the electrolytic mixture.

Answer:

  1. Cryolite (Na3AlF4) : It increases the conductivity of mixture and lowers the m.p. of electrolyte from 2050°C to 950°C.
  2. Fluorspar (CaF2) : It increases mobility of ions in the mixture as it acts as solvent for alumina and cryolite.
    Powdered coke prevents (a) heat loss from the electrolyte (b) burning of electrodes projecting out of electrolyte.

Question 4.
Complete the following by selecting the correct option from the choices given –

  1. The metal whose oxide, which is amphoteric, is reduced to metal by carbon reduction _____ [Fe / Mg / Pb / Al]
  2. The divalent metal whose oxide is reduced to metal by electrolysis of its fused salt is _____ [Al / Na / Mg / K]

Answer:

  1. The metal whose oxide, which is amphoteric, is reduced to metal by carbon reduction Pb (Lead).
  2. The divalent metal whose oxide is reduced to metal by electrolysis of its fused salt is Mg (Magnesium).

Additional Questions

Question 1.
State how the physical and chemical property differences between metals and non-metals are related to their basic atomic structure.
Define a metal with particular emphasis on (i) ionization (ii) valency (iii) formation of oxides.
State the position [group] in the periodic table to which the following metals belong (i) Na – alkali metal (ii) Mg – alkaline earth metal (iii) Fe and Zn transition elements (iv) inner transition elements (metals) (v) Al – post transition element.
Answer:
Atoms of Metallic elements, in general, have relatively larger atomic size. Hence, their valence electrons are held less tightly by the nucleus. As such, the valence electrons are mobile, leading to good electrical and thermal conductivity in case of metals. Further, with 1,2 or 3 valence electrons, metals can easily lose electrons to form cations. Thus, metal are electropositive in nature and are strong reducing agents.
On the other hand, non-metallic elements, in general, have relatively smaller atomic size. Hence their valence electrons are held tightly by the nucleus. As such their valence electrons are not mobile, thus making non-metals bad conductor of heat and electricity. Further, non-metals have 5, 6 or 7 valence electrons. As such, non-metals tend to gain electrons to form anions. Thus non-metals are electronegative in nature and strong oxidising agents.
Thus, we find that the physical and chemical properties of metals and non-metals are related to their basic atomic structure.
Defination of Metals :

  1. Atoms of metals with 1, 2 or 3 electrons in their valence shell can easily lose their valence electrons to form cations e.g.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 13
  2. As metals can easily lose electrons to form cations, metals are electropositive in nature.
  3. Metals on reacting with non-metals form ionic or electrovalent compounds, e.g.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 14
  4. As metals tend to form cations, metals show a positive valency of 1,2 or 3.

Position of Metals in the periodic table :

  1. Na – alkali metal – Group I (IA)
  2. Mg – alkaline earth metal – Group 2 (IIA)
  3. Fe and Zn transition elements – Group 9 (VIII), Group 12 (IIB)
  4. Inner transition elements : zero group.
  5. Al-post transition element: Group 13 (III A)

Question 2.
Metals occur in the free state and in the combined state, name two metals which occur in the free or native state. In the combined state metals occur in the form of compounds. Name two different metallic compounds in each case which occur as

  1. halides
  2. oxides
  3. sulphides.

Answer:
Gold and Platinum are the two metals that occur in the free or native state.
The metallic compounds which occur in :

  1. Halides – Cryolite[Na3AlF6], Flurospar[CaF2], Rock Salt[NaCl]
  2. Oxides – Bauxite[Al2O3.2H2O], Zincite[ZnO], Cuprite[Cu2O]
  3. Sulphides – Iron Pyrite[FeS2], Zinc blende[ZnS], Gdlena[PbS]

Question 3.
Differentiate between

  1. mineral & ore
  2. matrix & flux.

Answer:
Differentiate between mineral & ore
Mineral :

  • The compounds of various metal found in nature associated with their earthly impurities are called minerals.

Ore :

  • The naturally occurring minerals from which metals can be extracted profitably and conveniently are called ores,

Differentiate between matrix & flux

  1. Matrix : The rocky impurities including silica [SiO2], mud etc. associated with the ore is called matrix or gangue.
  2. Flux : The substance added to the ore to get rid of the matrix resulting in the formation of a fusible compound slag.

Question 4.
Give the (i) common (ii) chemical nadie (iii) formula of two common ores each of aluminium, zinc and iron.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 15

Question 5.
In the stages involved in the extraction of metals in general – give reasons for the following.

(i) Dressing of the ore is an essential process in the extraction of metal from its ore.
Answer:
The ores are found mixed with earthy impurities like sand, clay, lime stone etc. These unwanted impurities in the ore are called gangue or matrix.
The process of removal of gangue from powdered ore is called concentration or ore dressing.
Hence, it is the essential process in the extraction of metal from its ore because it convert’s the impure ore to pure concentrated ore

(ii) An electromagnetic wheel is used in the magnetic separation process of ore from gangue.
Answer:
An electromagnetic wheel is used in the magnetic separation process of ore from gangue as it seperate’s the magnetic particles from the non-magnetic particles. The magnetic particles get attracted to the magnetic wheel and thus get seperated from the gangue.

(iii) In the froth floatation process, the ore floats on the top & the gangue settles down.
Answer:
The impurities get wetted by water and remain behind in the tank. Since, the ore is lighter, it comes on the surface with the froth and the impurities(gatlgue) are left behind.

(iv) Magnetic separation is not used during the dressing of bauxite ore in the extraction of aluminium.
Answer:
Bauxite is concentrated by Leaching (Baeyer’s process). The impure bauxite is treated with concentrated NaOH, Al2O3 and SiO2 dissolve, but Fe2O3 and other basic materials remain insoluble and are removed by filtration.
Aluminium is highly reactive metal, belonging to the III A group of the periodic table. In nature, aluminium is found in the form of its oxide in its ore.
Hence, Magnetic separation is not used during the dressing of bauxite ore in the extraction of aluminium.

(v) Conversion of concentrated ore to its oxide is an essential step in the extraction of metals from the ore, even then the step is not necessary in the metallurgy of aluminium.
Answer:
Conversion of concentrated ore to its oxide is an essential step in the extraction of metals from the ore, even then the step is not necessary in the metallurgy of aluminium because in metallurgy of aluminium, the ore is already an oxide.

(vi) Roasting of the concentrated ore is carried out in the presence of excess air, while calcination of the concentrated ore in the absence or limited supply of air.
Answer:
Roasting is a process of converting an ore into its oxide by heating strongly in presence of excess air, so that oxygen gets added to form the corresponding oxide. It is done on sulphide ores in order to remove sulphur as sulphur gets escape in the form of gas.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 16
Whereas in carbonates ores, one needs to drive out carbonate and moisture impurities. So, ore is heated to a high temperature in absence of air. This process is called calcination.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 17

(vii) Roasting the ore generally results in evolution of sulphur dioxide gas, while calcination of the ore evolves carbon dioxide gas.
Answer:
Generally, sulphide ores are roasted, so SO2 is given off.
While carbonate and hydrated ores are calcined, so CO2 or water vapours are given off.

(viii) Reduction of metallic oxides to metal in the extraction of metals from the ores- is based on the position of the metal in the activity series.
Answer:
The method used to extract a metal from its ore depends on the position of the metal in the reactivity series.

(a) Metals higher up in the series need to be extracted using electricity.
(b) Metals lower in the series can be extracted by reduction with carbon.

(ix) Oxides or halides of highly electropositive metals e.g. K, Na, Ca, Al are reduced to metals by electrolysis and not by reduction with coke.
Answer:
Oxides are highly active metals like potassium, sodium, calcium, magnesium and aluminium have great affinity towards oxygen and so cannot be reduced by coke.

(x) Coke is not preferred as a reducing agent in the reduction of the oxide of mercury to its metal, but is preferred in the reduction of the oxide of zinc to its metal.
Answer:
Coke is not preferred as a reducing agent in the reduction of the oxide of mercury to its metal because metals low in the activity series are very reactive and the oxides of the metals can be reduced to metals by heating in air.
The reducing nature of carbon plays an important role in metallurgy and helps extract metals from their ores.
For example :
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 18

Question 6.
In the extraction of aluminium from bauxite, the first step is the dressing of the ore by Baeyer’s process. Give balanced equations for the conversion of impure bauxite to pure alumina using a concentrated solution of NaOH.
Answer:
Bauxite (red) contains Fe2O3. and SiO2 as the main impurities. It is crushed to a powder and is treated with a cone, solution of NaOH at 150-200°C (under pressure) when Al2O3 dissolves.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 19

Question 7.
In the electrolytic reduction of pure alumina to pure aluminium – by Hall Herault’s process, give the electrolytic reactions involved in the same, resulting in formation of aluminium at the cathode.
Answer:
Aluminium is obtained from alumina (Al2O3) by electrolytic reduction. The electrolytic both consists of a mixture of cryolite (Na3AlF6) and fluorspar (CaF2) and alumina (Al2O3)
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 20

Question 8.
State the function of

  1. NaOH
  2. cryolite
  3. fluorspar in the metallurgy of aluminium.

Answer:
Functions of :
(i) NaOH : Crushed and powdered bauxite is heated with a cone, solution of NaOH at 150-200°C for 2 hours under pressure. The main impurities present in bauxite (Fe2O3 and SiO2) remain unaffected with cone. NaOH since these are not amphoteric. Bauxite, being amphoteric reacts with the base to form sodium aluminate, which is soluble in water. Thus NaOH helps in the purification of the ore.
(ii) Cryolite :

(a) To increase the mobility of the fused mixture.
(b) To lower the fusion point of the mixture.
(c) To increase the electrical conductivity of the mixture.

(iii) Fluorspar :

(a) To increase the mobility of the fused mixture.
(b) To lower the fusion point of the mixture.

Question 9.
Give reasons for the following – pertaining to Hall Herault’s process.

  1. The fusion temperature of the electrolyte has to be lowered before conducting the electrolytic reduction.
  2. The constituents of the electrolyte in addition to one part of fused alumina contains three parts of cryolite and one part of fluorspar.
  3. A layer of powdered coke sprinkled over the electrolytic mixture, protects the carbon electrodes.
  4. It is preferred to use a number of graphite electrodes as anode, instead of a single graphite electrode.

Answer:
(i) The liberated A1 metal [m.p. 660°C] may also tend to volatize out and get wasted. Hence the fusion temperature of the electrolytic mixture has to be – lowered.
(ii) The reasons for addition of mainly cryolite [in a higher ratio] and fluorspar to the electrolytic mixture are :

(a) They lowers the fusion point of the mixture i. e. the mixture fuses [melts] around 950°C instead of 2050°C.
(b) They enhances the mobility of the fused mixture by acting as a solvent for the electrolytic mixture.
Thus cryolite in the molten state of subdivision dissolves aluminium oxide.
(c) Addition of cryolite enhances the conductivity of the mixture.
Since pure alumina is almost a non-conductor of electricity

(iii) The layer of powdered coke is sprinkled over the electrolytic mixture because :

(a) It prevents burning of carbon electrodes in air at the emergence point from the bath.
(b) It minimizes or prevents heat loss by radiation.

(iv) The graphite[carbon] anodes are continously replaced during the electrolysis because :

(a) The oxygen evolved at the anode escapes as a gas or reacts with the carbon anode.
(b) The carbon anode is thus oxidised to carbon monoxide which either bums giving carbon dioxide or escapes out through an outlet.
2C + O2 → 2CO [2CO + O2 → 2CO2]
(c) The carbon anode is hence consumed and renewed periodically after a certain period of usage,

Question 10.
Define — (a) alloy, (b) amalgam
Answer:

  • Alloy : An alloy is a homogenous mixture of two or more metals and non-metals, out of which at least one is a metal.
    For example, brass (Zn + Cu), bronze (Cu + Sn), solder (Sn +Pb), stainless steel (Fe + Cr + Ni + C) etc.
  • Amalgam : An alloy in which mercury is an essential constituent is called an amalgam.
    For example, Dental amalgam (Hg + Ag + Sn), it is used for filling dental cavities.

Question 11.
State (i) composition (ii) reason for alloying (iii) one use of each of the following alloys.

  1. Brass
  2. Bronze
  3. Duralumin
  4. Solder [fuse metal]
  5. Stainless steel

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 21

Unit Test Paper 6 — Metallurgy

Q.1. Loss of electrons from an element ‘X’ is represented by : X – 3e– → X3+ (X → X3+ + 3e)

1. X is a _____ (metal/non-metal) and will form _____ (electrovalent/covalent) compounds only.
Ans. X is a metal and will form electrovalent compounds only.

2. X3+ formed is a _____ (cation / anion) and element ‘X’ has a valency of _____ [+2 /+3 / -3].
Ans. X3+ formed is a cation and element ‘X’ has a valency of +3.

3. If X3+ combines with oxygen the formula of the product is _____ (X2O3 / XO / X3O2),
Ans. If X3+ combines with oxygen the formula of the product is X2O3.

4. If the above product in the _____ (solid/molten) state is electrolysed the ion X3+ will get discharged at the _____ (anode / cathode).
Ans. If the above product in the molten state is electrolysed the ion X3+ will get discharged at the cathode.

5. The ion X3+ _____ (accepts / loses) electrons and gets _____ (oxidised / reduced) to neutral _____ (ions / atoms / molecules).
Ans. The ion X3+ loses electrons and gets reduced to neutral atoms.

Q.2. Select the correct answer from the list A, B, C and D given in each statement.

1. The oxide of the metal which reacts with both acids and alkalis- to give salt & water.
A : MgO
B : CuO
C : Al2O3
D : K2O

2. The common name of the ore of iron – whose chemical formula is Fe3 O4.
A : Iron pyrites
B : Magnetite
C : Haematite
D : Spathic iron ore

3. The chemical name – of the main ore of aluminium.
A : Aluminium flouride
B : Aluminium oxide
C : Sodium aluminium flouride
D : Hydrated aluminium oxide

4. The process of dressing of the ore which involves separation of ore & gangue – due to preferential wetting.
A : Magnetic separation
B : Hydrolytic method
C : Froth flotation method
D : Chemical method

5. The metallic oxide reduced to metal generally by – thermal decomposition.
A : ZnO
B : MgO
C : HgO
D : Al2O3
Answer:

  1. C : Al2O3
  2. B : Magnetite
  3. D : Hydrated aluminium oxide
  4. C : Froth flotation method
  5. C : HgO

Q.3. Name the substance A to E, reacted with each reactant below to give the respective product/s.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 22
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 23

Q.4. Name the following :

  1. A metallic ore converted to its oxide – iron [II] oxide on heating the concentrated ore.
  2. A black metallic oxide reduced to metal on heating with coke.
  3. The compound which on ignition at elevated temperatures gives pure alumina.
  4. The non-metal which forms the anode during electrolytic reduction of fused alumina in Hall Heroult’s process.
  5. A metal other than manganese, present in duralumin but not in magnalium.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 24

Q.5. Match the properties & uses of alloys in List 1 – with the correct answer from List 2.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 25
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 6 Metallurgy 26

For More Resources

New Simplified Chemistry Class 10 ICSE Solutions – Electrolysis

New Simplified Chemistry Class 10 ICSE Solutions – Electrolysis

ICSE SolutionsSelina ICSE SolutionsML Aggarwal Solutions

Viraf J Dalal Chemistry Class 10 Solutions and Answers

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QUESTIONS

2004

Question 1.
Write two applications of electrolysis in which the anode diminishes in mass.
Answer:

  1. Used in electroplating.
  2. Purification of metals.

Question 2.
If the compound formed between X (a metal with a valency 2) and Y (a non-metal with a valency 3) is melted and an electric current passed through the molten compound, the element X will be obtained at the……….. and Y at the……… of the electrolytic cell. (Provide the missing words.)
Answer:
Cathode, Anode.

Question 3.
What kind of particles will be found in a liquid compound which is a non-electrolyte.
Answer:
Only molecules.

Question 4.
If HX is a weak acid, what particles will be present in its dilute solution apart from those of water.
Answer:
Non-ionized molecules, H+ and X”.

Question 5.
What ions must be present in a solution used for electroplating a particular metal.
Answer:
Cations of that particular metal to be deposited.

Question 6.
Explain how electrolysis is an example of redox reaction.
Answer:
Redox Reaction: “A chemical reaction in which loss of electrons and the gain of electrons takes place simultaneously is called REDOX reaction.”
Example: Electrolysis of Potassium chloride
2K – 2e1-→ 2K+
Cl2 + 2e1-→  2Cl-
2K + Cl2→ 2K+Cl or 2KCl

The potassium atoms lose one electron each from their valence shells to form potassium ions. As loss of electrons takes place therefore, potassium metal is oxidised to Potassium ions [K+].
Chlorine atoms gain one electron each in their valence shells to form chloride ions. As gain of electrons take place, therefore, chlorine atoms are reduced to chloride ions (Cl ). Since reduction and oxidation takes place simultaneously, therefore, electrolysis is a Redox reaction.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 1

2005

Question 1.
Explain why copper, though a good conductor of electricity, is a non-electrolyte.
Answer:
Copper metal – is a good conductor of electricity – but is a non-electrolyte, since-
It does not undergo chemical decomposition due to flow of electric current through it.

Question 2.
Name the gas released at the cathode when acidulated water is electrolysed.
Answer:
Hydrogen gas.

Question 3.
Explain why solid sodium chloride does not allow electricity to pass through.
Answer:
Sodium chloride (an ionic solid) does not conduct electricity in its solid state. It is because the anions (chloride – Cl ) and cations (sodium -Na+), remain in fact occupying fixed position in the crystal lattice due to strong electrostatic attractive forces among them. The ions, therefore are unable to move to any large extent when electric field is affected. Hence no current.

Question 4.
Fill in the blanks:

  1. As we descend the electro chemical series containing cations, the tendency of the cations to get  reduced at the cathode increases.
  2. The higher the concentration of an ion in a solution, the greater is the probability of its being discharged at its appropriate electrode.

Question 5.
State the term used for:
A liquid or solution, which conducts electricity with accompanying chemical change.
Answer:
Electrolyte.

Question 6.
Electrons are getting added to an element Y. Which electrode will Y migrate to during electrolysis.
Answer:
Cathode.

2006

Question 1.
Select from the list: —Ammonia, Copper oxide, Copper sulphate, Hydrogen chloride, Hydrogen sulphide, Lead bromide.

  1. A solution of this compound is used as the electrolyte when copper is purified.
  2. When this compound is electrolysed in the molten state, lead is obtained at the cathode.

Answer:

  1. Copper sulphate
  2. Lead Bromide.

Question 2.
State what is observed when copper sulphate solution is electrolysed using a platinum anode.
Answer:
Blue colour of the solution disappears.

Question 3.
An electrode ‘A’ is connected to the positive terminal of a battery and electrode ‘B’ to the negative terminal.

  1. Give the names of the electrodes A and B.
  2. Which electrode is the oxidizing electrode.

Answer:

  1. Anode, Cathode
  2.  Anode.

Question 4.
Write the equations at the cathode and anode when acidified water is electrolysed.
Answer:
Reaction at Cathode –
4H1+ + 4e → H x 4                          
2H + 2H → 2H2
Reaction at Anode:
40H1- + 4e → OH x 4
4OH → 2H2O + O2

Question 5.
A soln. of AgNOis a good electrolyte but it is not used for electroplating an article with silver. Why.
Answer:
Migration of Ag1+ ion from the complex salt solution silver cyanide is slow as compared to silver nitrate. That is why silver nitrate solution is not used.

2007

Question 1.
From — A: non-electrolyte, B: strong electrolyte, C: weak electrolyte, D: metallic conductor — Match:

  1. Molten ionic compound
  2. CCl4
  3. An aluminium wire
  4. A soln. containing solvent molecules, solute molecules and ions formed by the dissociation of solute molecules.
  5. A sugar soln. with sugar molecules and water molecules.

Answer:
Description

  1. (B) Strong electrolyte.
  2. (A) Non-electrolyte.
  3. (D) Metallic conductor
  4. (C) Weak electrolyte
  5. (A) Non-electrolyte

2008

Question 1.
During the electrolysis of molten lead bromide, which of the following takes place ?
A.  Bromine is released at the cathode
B.  Lead is deposited at the anode
C.  Bromine ions gain electrons
D.  Lead is deposited at the cathode

Question 2(1).
Here is an electrode reaction:
Cu → Cu2+ + 2e. [i.e. Cu – 2e → Cu2+]
At which electrode (anode or cathode) would such a reaction take place ? Is this an example of oxidation or reduction ?
Answer:
Cu → Cu2+ + 2e
This reaction takes place at anode.
This is an example of oxidation

Question 2(2).
A soln. contains Mg2+ ions, Fe2+ ions and Cu2+ ions. On passing an electric current through this soln. which ions will be the first to be discharged at the cathode ? Write the equation for the cathode reaction/
Answer:
Cu2+ (Copper ions will get discharged at cathode)

2009

Question 1.
State which from A to E fits the description —‘A pink metal is deposited at the cathode during the electrolysis of the soln. of this salt.
(A) Sulphur
(B) Silver chloride
(C) Hydrogen chloride
(D) Copper [II] sulphate
(E) Graphite.

Question 2.
Select the correct answer — The aqueous solution of the compounds which contains both ions and molecules is:
(A) Sulphuric acid
(B) Hydrochloric acid
(C) Nitric acid
(D) Acetic acid

Question 3.
Correct the following statements conducts electricity.
Answer:
Molten lead bromide conducts electricity.

Question 4.
A metal article is to be electroplated with silver. The electrolyte selected is sodium argentocyanide.

  1. What kind of salt is sodium argentocyanide.
  2. Why is it preferred to silver nitrate as an electrolyte?
  3. State one condition to ensure that the deposit is smooth, firm and long lasting.
  4. Write the reaction taking place at the cathode.
  5. Write the reaction taking place at the anode.

Answer:

  1. It is a complex salt.
  2. Silver nitrate is not used as an electrolyte since deposition of silver is rapid and the coating is not uniform. Hence sodium argentocyanide is used.
  3. A direct current of smaller magnitude should be applied for a longer time.
    Dissociation reaction:
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 2
    Both Na+ and Ag+ will migrate towards cathode but Ag+ ions will be discharged.
  4. Reaction at cathode
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 3
  5. Reaction at anode
    The silver atoms from the anode lose electrons and other into the solution as silver ions
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 4

Question 5.
Aqueous solution of Nickel sulphate contains Ni2+ and SO42+ ions

    1. Which ions moves towards the cathode ?
    2. What is the product at the anode ?

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 5

  1. Nickel ions moves towards the cathode
  2. Reaction At anode: (with nickel electrodes)
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 6

Hence nickel dissolves from the anode by forming nickel ions.
(if electrodes used of platinum).

Then being an aqueous solution hydrolysis of water will also take place
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 7
At Anode:  4OH – 4e → 4OH
4OH → 2H2O + O2 ↑
Hence oxygen gas will be released if electrodes used are of platinum.

2010

Question 1.
Select the correct answer — A compound which liberates reddish brown gas around the anode during electrolysis in its molten state is :
(A) Sodium chloride
(B) Copper (II) oxide
(C) Copper (II) sulphate
(D) Lead (II) bromide

Question 2.
During electroplating of an article with nickel –
(1) Name

  1. The electrolyte
  2. The cathode

(2) Give the reaction of the electrolysis at

  1. The cathode .
  2. The anode

Answer:
(1)
(a) Nickel sulphate
(b) Article
(c) Pure nickel plate / rod
(2)
(a) At Cathode: Ni2+ + 2e→ Ni(s)
(b) At Anode: Ni(s) – 2e→ Ni2+

Question 3.
A, B and C are three electrolytic cells, connected in different circuits. Cell ‘A’ contains NaCl soln., and the bulb in the circuit glows brightly, when the circuit is completed. Cell ‘B’ contains acetic acid and the bulb glows dimly. Cell ‘C’ contains sugar soln., and the bulb not glow. Give reasons for each observation.
Answer:
Electrolytic cell A has completely ionised sodium chloride solution. Thus, the ions can easily migrate to oppositely charged poles and hence bulb glows brightly. To conclude sodium chloride solution is a strong electrolyte.
Electrolytic cell B has a weak electrolyte as only 5% of the acetic acid molecules ionise. Thus, a weak current flows through it and hence the bulb glows dimly.
Electrolytic cell C has a non-electrolyte. Sugar molecules do not ionise and hence no current flows through. Thus, the bulb does not glow.

2011

Question 1.
Give reasons – The electrolysis of acidulated water is considered to be an example of catalysis.
Answer:
The amount of acid in the water does not change. Furthermore, it does not take part in electrochemical reaction, but makes the water a good conductor of electricity.

Question 2.
During electrolysis of CuSO4 using platinum [cathode] and carbon [anode]:

  1. State what you observe at the cathode and anode.
  2. State the change noticed in the electrolyte
  3. Write the reactions at the cathode and anode.

Answer:

  1. Cathode: Reddish brown deposition of copper occurs at cathode.
    Anode: Colourless gas is evolved at anode.
  2. On prolonged electrolysis, the blue electrolyte turns colourless.                                          .
  3. Cathode: Cu2+ + 2e → Cu
    Anode: OH— le → OH
    4OH → 2H2O + O2

Question 3.
Differentiate between electrical conductivity of – copper sulphate solution and of copper metal.
Answer:

Electrical conductivity of copper sulphate solutionsElectrical conductivity of copper metal
1. Flow of electricity takes place the molten or dissolved state.

2. Flow of electricity is due to the movement of ions.

3. There is chemical decompos­ition of the copper sulphate sol.

4. The electrical conductivity increases with the increase in temperature.

1. Flow of in electricity place in the solid state.

2. Flow of electricity is due to the movement of electrons.

3. There is no chemical decomposition.

4. The electrical conductivity with increase in temperature, decreases

2012


Question 1.
Rewrite the correct statement with the missing word/s: Cations migrate during electrolysis.
Answer:
Cation migrates to cathode during electrolysis.

Question 2.
Identify the weak electrolyte from the following:
(A) Sodium Chloride solution
(B) Dilute Hydrochloric acid
(C) Dilute Sulphuric acid
(D) Aqueous acetic acid.

Question 3.
Match the following in column A with the correct answer from the choices given in column B.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 8
Answer:
                 Column A                                             Column B
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 9

Question 4.
Give reasons: An aqueous solution of sodium chloride conducts electricity.
Answer:
Aqueous solution of sodium chloride contains very large number of sodium ions (Na+) and chloride ions (Cl ). On the passage of electric current these ions migrate to the oppositely charged electric poles and the conduction of electricity takes place.

Question 5.
Select the correct answer from the list in brackets:

  1. An aqueous electrolyte consists of the ions .mentioned in the list, the ion which could be
    discharged most readily during electrolysis. [Fe2+, Cu2+, Pb2+, H+].
  2. The metallic electrode which does not take part in an electrolytic reaction. [Cu, Ag, Pt, Ni].
  3. The ion which is discharged at the anode during the electrolysis of copper sulphate solutions using copper electrodes as anode and cathode. [Cu2+, OH, SO42--, H+].
  4. When dilute sodium chloride is electrolysed using graphite electrodes, the cation is discharged at the cathode most readily. [Na+, OH, H+, Cl].
  5. During silver plating of an article using potassium argentocyanide as an electrolyte, the anode material should be [Cu, Ag, Pt, Fe].

Answer:
(1) Cu2+ (2) Pt (3) Cu2+ (4) H1+ (5) Ag

2013

Question 1.
State one appropriate observation for : Electricity is passed through molten lead bromide.
Answer:
The molten lead bromide breaks into lead metal which dis­charges at cathode and bromine gas which discharged at an­ode.

Question 2.
State which of these will act as non-electrolyte ?
(A) Liquid carbon tetrachloride
(B) Acetic acid
(C) Sodium hydroxide aqueous solution acid.
(D) Potassium chloride aqu. solution.
Answer:
(A) Liquid carbon tetrachloride is non-electrolyte

Question 3.
Copper sulphate soln. is electrolysed using copper elec­trodes as seen in diagram
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 10

  1. Which electrode to your left or right is known as the oxidising electrode and why?
    Ans. The electrode on left hand side donates electrons and hence is oxidising electrode.
  2. Write the equation representing the reaction that oc­curs.
    Ans. Cu – 2e→ Cu2+
  3. State two appropriate observations for the above elec­trolysis reaction.
    Ans. The size of anode gradually decreases and that of cathode gradually increases. However, there is no change in the colour of copper sulphate solution.
  4. Name: A gas which in the liquid state does not conduct electricity but conducts when dissolved in water.
    Ans. Hydrogen chloride gas.

2014

Question 1.
The observation seen when fused lead bromide is electrolysed is:
A: a silver grey deposit at anode and a reddish brown deposit at cathode.
B: a silver grey deposit at cathode and a reddish brown deposit at anode.
C: a silver grey deposit at cathode and reddish brown fumes at anode.
D: silver grey fumes at anode and reddish brown fumes at cathode

Question 2.
During electroplating an article with silver, the electrolyte used is: 
A: silver ifitrate solution
B: silver cyanide solution
C: sodium argentocyanide solution
D: nickel sulphate solution

Question 3.
Give one word or phrase for: Electrolytic deposition of a superior metal on a baser metal.
Answer:
Electrolytic deposition of a superior metal on a baser metal→ Electroplating.

Question 4.
State your observation:
At the cathode when acidified aq. CuSO4 spin. is electrolyzed with copper electrodes.
Answer:
Pure copper will deposit at cathode.

Question 5.
State which electrode: anode or cathode is the oxidising electrode. Give a reason for the same.
Answer:
Anode is the oxidising electrode.

Question 6.
Name the kind of particles present in:

  1. Sodium Hydroxide soln.
  2. Carbonic acid.
  3. Sugar sol.n.

Answer:

  1. Particles present in sodium hydroxide a strong alkali solution:
    Sodium (Na+) ions and hydroxide (OH ) ions.
  2. Particles present in carbonic acid (a weak acid) solution:
    Ions (H+, HCO3, CO32- ) and molecules (H2CO3)
  3. Particles present in sugar (a non-electrolyte) solution:
    Molecules of sugar (C12 H22O11)

Question 7.
M2O is the oxide of a metal ‘M’ which is the above hydrogen in the activity series. M2O when dissolved in water forms the corresponding hydroxide which-is a good conductor of electricity.

  1. State the reaction taking place at the cathode.
  2. Name the product at the anode.

Answer:

  1. Reaction of cathode: M+ + e → M
  2. Product at anode: O2 + O2-→ O2 (Oxygen)

2015

Question 1.
State one observation for. ‘At the Anode when aqueous copper sulphate solution is electrolysed using copper electrodes’.
Answer:
Blue Cu2+ ions formed.

Question 2.
Give scientific reasons:

  1. During electrolysis of molten lead bromide graphite anode is preferred to other electrodes.
  2. Electrical conductivity of acetic acid is less in comparison to the of dil. H2SO4 – at a given concentration
  3. Electrolysis is of molten lead bromide is considered to be a redox reaction.

Answer:

  1. During the electrolysis of molten lead bromide, a graphite anode is preferred because graphite remains unaffected by the reactive bromine vapours which are released at the anode.
  2. Sulphuric acid is a strong acid compared to acetic acid. A strong acid has more ions than a weak one, and so, its solution will be a better electrical conductor than a weak acid. So, electrical conductivity of acetic acid is less in comparison of electric conductivity of sulphuric acid.
  3. In the electrolysis of molten lead bromide, the following reactions take place:
    At the cathode: Pb2+ (l) + 2e → Pb(l)
    At the anode: 2Br (l) → Br2 (g) + 2e
    Lead (II) ions (Pb2+) are attracted to the negative electrode, and the Pb2+ ions are forced to accept two electrons. Pb2+ ions are reduced. Bromide ions (Br ) are attracted to the positive electrode and the bromide ions are forced to give away their extra electron to form bromine atoms. Thus, bromide ions are oxidised. So, electrolysis of molten lead bromide is a redox reaction.

Question 3.
Differentiate between the terms strong electrolyte and weak electrolyte, (stating any two differences)
Answer:

Strong Electrolytes

Weak Electrolytes

(1)  Electrolytes which allow a large amount of electricity to flow through them.

(2) The solution of a strong electrolyte contains only free mobile ions.

(1)  Electrolytes which allow a small amount of electricity to flow through them.

(2)  The solution of a weak electrolyte contains ions and molecules.

Question 4.
During purification of copper – State:

  1. The anode used
  2. The electrolyte used.

Write the equation taking place at the anode in the above.
Answer:
(1)
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 34
(2) Equation at the anode:
Cu – 2e → Cu2+ (Anode)

2016

Question 1.
The particles present in strong electrolytes are:
Select the correct answer from A, B, C and D:
A: only molecules
B: mainly ions
C: ions and molecules
D: only atoms

Question 2.
Write equations for the reactions taking place at the two electrodes during the electrolysis of:

  1. Acidified CuSO4 with copper electrodes.
  2. Molten PbBr2 with inert electrodes. (mention clearly the name of the electrode in each case)

Answer:
(1) Dissociation reaction:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 11
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 12
At cathode (negative terminal of battery)
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 13
At anode (positive terminal of battery)
Cu → Cu2++2e

(2) Dissociation reaction:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 14

At cathode (negative terminal of battery)
Pb2+ + 2e → Pb
Lead metal is obtained in molten state At anode (positive terminal of battery)
Br – e → Br
Br + Br → Br2
Reddish brown vapours of bromine are formed

Question 3.
Name:

  1. the product formed at the anode – during electrolysis of acidified water using platinum electrodes.
  2. the metallic ions that should be present – in the electrolyte when an article made of copper is to be electroplated with silver.

Answer:

  1. Oxygen
  2. Silver ions

Question 4.
Give reasons why:

  1. Sodium Chloride will conduct electricity only in fused or aq. soln. state.
  2. In the electroplating of an article with silver, the electrolyte sodium argentocyanide soln. is preferred over silver nitrate solution.
  3. Although copper is a good conductor of electricity,it is a non-electrolyte.                                  ‘

Answer:

  1. Sodium chloride is a solid, ionic compound, it has strong electrostatic forces of attraction. Only in the fused or aqueous solution, it forms ions which are capable of conducting electricity.
  2. It is preferred over silver nitrate because the dissociation of AgN03 will be very fast and deposit will not be smooth and uniform.
  3. Because it does not form ions.

2017

Question 1.
Identify the substance underlined, in each of the following-

  1. The elctrolvte used for electroplating an article with silver.
  2. The particles present in a liquid such as kerosene, that is a non-electrolyte.

Answer:

  1. Sodium argentocyanide or Potassium argentocyanide solution.
  2. Molecules

Question 2.
State the observations at the anode & at the cathode during the electrolysis of –

  1. Fused lead bromide using graphite electrodes.
  2. Copper sulphate solution using copper electrodes.

Answer:

  1. At cathode silvery droplets of molten lead appear.
    At anode reddish vapours of bromine are given out.
  2. Brown metal copper is deposited at cathode.
    Cu2+ ion is liberated at anode.
    Colour of CuSO4 solution (blue colour) does not fade.

Question 3.
Select the ion in each case, that would get selectively discharged from the aqueous mixture of the ions listed below:
(1) S042-, NO3 and OH ;
(2) Pb2-, Ag+ and Cu2+.
Answer:

  1. OH ion will get discharged in preference to SO42- or NO3 ions.
  2. Ag+ ions will get discharged in preference to Pb2+ or Cu2+ ions.

ADDITIONAL QUESTIONS

Question 1.
Define:

  1. Electrolysis
  2. Electrodes
  3. Ions
  4. Electrolytic dissociation.

Answer:
(1) Electrolysis: “The process of decomposition of a chemical compound in aqueous solution or in molten state accompanied by chemical change.”
(2) Electrodes: Electrodes allow the electric current to enter or leave the electrolyte solution.
(3) Ions: They are atoms which carry a positive or negative charge and become free and mobile when an electric current is passed through an aqueous solution of a chemical compound.
(4) Electrolytic dissociation: The process due to which an ionic compound in the fused or in aqueous solution dissociates into ions by passage of electric current through it is called electrolytic dissociation.

Question 2.
Differentiate between

  1. Electrolytes and Non-electrolytes
  2. Strong and Weak electrolytes
  3. Anode and Cathode
  4. Electrolytic dissociation and Ionisation with suitable examples.

Answer:

Question 2(1).
Electrolytes and Non-electrolytes

Electrolytes:

Chemical compound – which conduct electricity in the fused or in aq. solution state and -undergo chemical decomposition due to the flow of current through it.
Electrolytes – are ionic compounds
Particles in Electrolytes – ions only or Ions and molecules only
Examples:
Acids – dil. HCl, HNO2 H2SO4 Alkalis – KOH, NaOH solutions Ionic salts – PbBr2 [molten],
CuSO4 [aq.]

Non-electrolytes:

Chemical compound – which do not conduct electricity in the fused or aq. soln. state and – do not undergo chemical decom­position due to the flow of current through it.
Non-electrolytes – are covalent compounds
Particles in non-electrolytes – Molecules only
Example:
Pure or distilled water, Alcohol, Kerosene, Carbon disulphide, carbon tetrachloride, sucrose, glucose, sugar solution.

Question 2(2).
Strong and Weak electrolytes:

Strong electrolytes:

  1. The compounds which in their aqueous solution or in fused state are almost completely ionised are called strong electrolytes.
  2. They allow a large amount of electricity to flow through them and hence are good conductors of electricity.
  3. In aqueous solution or molten state, only ions are present.
    Examples:
    Strong acids:
    HCl, H2SO4,HNO3
    Strong bases: NaOH, KOH
    Salts: NaCl, NaNO3, K2S04

Weak electrolytes:

  1. The compound which in their aqueous solution or in fused state are partially ionised are called weak electrolytes.
  2. They allow small amount of electricity to flow through them and hence are poor conductors of electricity.The compound which in their aqueous solution or in fused state are partially ionised are called weak electrolytes.
    In aqueous solution or molten state ions as well as unionised molecules are present.
    Examples:
    Weak acids: CH3COOH, H2CO3
    Weak bases: NH4OH, Ca(OH)2
    Salts: CH3COONH4

Question 2(3).
Anode and Cathode:

Anode:

  1. It is the electrode connected to the positive terminal of the battery
  2. Anions migrate to anode.
  3. The anions donate excess electrons to the anode and they are oxidised to neutral atoms.

Cathode:

  1. It is the electrode connected to the negative terminal of the battery.
  2. Cations migrate to cathode.
  3. The cations gain excess electrons from the cathode and they are reduced to neutral atoms.

Question 2(4).
Electrolytic dissociation and ionisation with suitable examples.

Dissociation:

  1. Separation of ions which are already present in an ionic compounds.
  2. Electrovalent compounds show dissociation e.g. potassium chloride, lead bromide.
    KCl → K+ + Cl

Ionisation

  1. Formation of positively or negatively charged ions from molecules which are not intially in the ionic state.
  2. Polar covalent compounds show ionisation.
    e.g. HCl, H4CO3 , NH4OH
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 15

Question 3.
Compare the flow of electricity through a nickel wire and nickel sulphate solution.
Answer:
Flow of electricity through nickel wire

  1. It is due to the flow of electrons.
  2. It is a physical change.
  3. It can take place in solid state.
  4. Electrical conductivity is more.

low of electricity through nickel sulphate solution

  1. It is due to the flow of ions.
  2. It is a chemical change.
  3. It cannot take place in solid state.
  4. Electrical conductivity is less.

Question 4.
Name three organic compounds and one neutral liquid which are non-electrolytes.
Answer:
Organic compounds which are non-electrolyte:
Sugar, glucose, naphthalene
Neutral liquid which are non-electrolytes:
Carbon tetrachloride, carbon disulphide

Question 5.
State which of the following solutions are weak electrolytes – dil. HCI ; carbonic acid ; NH4OH ; dil. H2SO4 ; AgNO3 ; Na2CO3 ; PbBr2 ; KOH ; HI ; oxalic acid, NaHCO3 ; sodium acetate ; Na2SO4 ; NaOH.
Answer:
Weak Electrolytes: Carbonic acid, NH4OH, Na2CO3 oxalic acid.

Question 6.
State which of the following solutions contain (1) molecules only (2) ions only (3) both molecules and ions – CS2 ; CH3COOH ; NH4OH ; NaOH ; dil. HNO3 ; Na2CO3 ; CuCl2 ; oxalic acid ; pure H2O,
kerosene ; HI.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 16

Question 7.
State giving reasons, in which state or medium does
(1) NaCl, (2) HCI gas (3) NH3 gas conduct electricity.
Answer:

  1. NaCl will conduct electricity only molten state or when dissolved in water. This is because the Na+ and Cl ions present in solid NaCl are too big to move under the influence of applied electric field.
  2. HCI gas is a polar covalent compound when dissolved in water, it will ionise to give H+ and CP ions. Under the influence of applied electric field these ions can easily move in an aqueous solution and thus conduct electricity.
    Thus HCI (g) when dissolved in water conducts electricity.
  3. NH3(g) will dissolved in water to give NH4OH.
    NH3(g) + H2O (l) → NH4OH (aq)
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 17
    NH4OH will ionise to give NH4+ and OH ions. Under the influence of applied electric field these ions can migrate in an aqueous solution and hence conduct electricity. Thus NH3 (g) when dissolved in water conduct electricity.

Question 8.
State on what basis are acids, bases and salts classified as strong and weak electrolytes.
Answer:
Strong electrolytes – Compound which in the fused or in the aqueous solution state are almost completely dissociated and are good conductors of electricity are called.

Weak Electrolytes – Compound which in the fused or in the aqueous solution state are feebly or partially dissociated and are poor conductors of electricity are called – weak electrolytes.

Question 9.
Explain the terms 

  1. metal activity or electro chemical series
  2. selective discharge of ions.

Answer:

  1. Depending on the ease with the metals lose their electrons and form ions – they are arranged in a series known as – metal activity series or electro chemical series.
    The arrangement is so done that the elements that – ionize most readily [discharged with great difficulty]- are placed at the top of the series and other elements in the descending order.
  2. Selective discharge of ions: The preferential discharge of ions present in an electrolyte at the respective electrodes is known as selective discharge of ions.

It depends upon the following factors:

  • Relative position of the ion in the electo chemical series: Lower the position of the ion in the series, easier to discharge.
  • Concentration of the ion: More the concentration of the ion, easier to discharge.
  • Nature of the electrode: Inert electrodes (graphite, platinum) do not take part in the electrolytic reaction.
    Active electrodes (Cu electrodes for electrolysis of aq. CuSO4, Ag electrodes for electrolysis of aq. AgNO3 etc.) take part in electrolytic reactions.

Question 10.
From the ions –

  1. SO42- and OH1-
  2. Cu2+ and H1+
  3. Ag1+ and H1+ state giving reasons which ion is discharged at the respective electrode in each case.

Answer:

  1. Out of SO42- and OH ions, OH ions will be discharged at anode forming O2 gas.
  2. Out of Cu2+ and H+, Cu2+ ions will be discharged because Cu is lower in the electro chemical series than H.
  3. Out of Ag+ and H+, Ag+ will be discharged because Ag is lower in the electro chemical
    series than H.

Question 11.
With reference to nature of electrodes — name three inert and three active electrodes.
Answer:
Inert electrodes

  • Platinum
  • Iron
  • Graphite

Active electrodes

  • Copper
  • Nickel
  • Silver

Question 12.
State the reason for difference in product formed at the anode during electrolysis of aq. CuSO4 using

  1. active electrode – copper anode
  2. inert electrode – platinum anode.

Answer:

  1. Electrolysis of aq. CuS04 using copper anode:
    As copper can easily lose electron, copper from anode will dissolve as Cu2+ ions.
    Cu (s) – 2e→ Cu2+ (aq)
  2. Electrolysis of aq. CuS04 using inert platinum anode: Due to very low tendency of platinum to lose electron platinum anode does not take part in electrolytic reaction. Further tendency of SO42- to lose electron is much less than that of OH(from feebly ionised water). Thus OH ions get oxidised in preference to SO42- ions to  give O2
    4OH – 4e → 4OH
    40H→ 2H2O + O2↑

Question 13.
Give the electrode reactions for formation of

  1. Lead metal and bromine vapours from molten PbBr2 using inert electrodes
  2. H2 and O2 gas (2:1) from acidified water using inert Pt electrodes.

Answer:

  1. Electrolysis of molten PbBr2 using inert electrodes.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 18
    At cathode: Pb2+ (l) + 2e →Pb (s)
    At anode: 2Br (l) – 2e→ 2Br
    Br + Br→ Br2 (g)
  2. Electrolysis of acidified water using Pt electrodes.
    At cathode:
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 19
    4H+ (aq) + 4e → 4H
    2H + 2H→ 2H2
    At anode:
    4OH+ (aq) – 4e → 4OH
    4OH→ 2H2O (l) + O2 (g)

Question 14.
Starting from aq. copper (II) sulphate solution, give equations for the reactions at the cathode and anode during electrolysis of aq. CuSO4 using active copper electrodes.
Answer:
Electrode reaction:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 20
Reaction at Cathode:
Cu2+ + 2e → Cu
Cu2+ and H1+ ions migrate to the cathode.
Reaction at anode: Cu – 2e → Cu2+
S042- and OH1- ions migrate to anode but not discharged.

Question 15.
Give reasons for the following changes –

(1) pure water a non-electrolyte – becomes an electrolyte on addition of dil. H2SO4
(2) Blue colour of aq. CuSO4 – turns almost colourless on its electrolysis using Pt electrodes.
Answer:

  1. Pure water is a non electrolyte. It consists of entirely of molecules. It can be electrically decomposed by Addition of traces of dil. Sulphuric acid. Which dissociates into H1+ and sulphate (S042-) ions.
  2. If platinum anode is used the blue colour of CuS04 solution fades since the blue Cu2+ ions which are discharged at the cathode are not replaced or added at the anode.

Question 16.
‘Iron is electroplated with silver’ –

  1. define the term in italics
  2. state two reasons for electroplating
  3. state why the iron is not placed at the anode and silver at the cathode during electroplating.

Answer:

  1. Electroplating: The electrolytic process of deposition of a superior metal on the surface of a baser metal or article is called electroplating.
  2. Reasons for electroplating:

    • Prevents corrosion or rusting.
    • Makes the article attractive and gives it an expensive appearance.
  3. The article to be electroplated is always placed at the cathode because during electrolytic reaction the metal is always deposited at the cathode by gain of electrons.

Question 17.
Draw a diagram for –
(1) electroplating an article with silver;
(2) electrorefining or purification of copper.

Answer:
(1)
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 21
(2)
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 22

Question 18.
State the

  1. electrolyte
  2. cathode used
  3. anode used
  4. electrode reaction at cathode
  5. electrode reaction at anode
  6. product at cathode and anode – during
    (a) electroplating an article with nickel
    (b) electroplating a spoon with silver
    (c) purification of impure copper.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 23

Electrolytic reaction at cathode
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 24

Electrode reaction at anode
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 25
Products at cathode
(a) Ni (ions)
(b) Silver
(c) Copper
Products at anode
(a) SO42– and OH1--(ions)
(b) CN and OH1- (ions)
(c) SO42- and OH1- (ions)

Question 19.
Give a reason why metals –
copper, silver and lead are electrorefined but K, Na and Ca are not.
Answer:
Extraction of K, Na and Ca are done by electrolysis and are extracted in their fused state. Their oxides are highly stable and the metal has a strong affinity for oxygen. They do not decompose on thermal decomposition. .

Question 20.
Explain the term ‘electrometallurgy’. At what electrode is the extracted metal always deposited ?
Answer:
Electrometallurgy – is the process of extraction of metals by electrolysis. Metals comparatively higher in the electrochemical series are extracted by electrolysis. During this process, the extracted metal is always deposited on cathode.

Question 21.
State how activity series of metals plays a role in extraction of metals from oxides.
Answer:
In activity series, metals are placed in decreasing order of reactivity with most reactive metal at the top and least reactive metal at the bottom. Depending upon the reactivity of metals, different methods are used for their extraction from respective ores.
For example:

  1. Extraction by electrolysis: Metals at the top of the activity series are extracted from their ores by electrolysis. Being highly reactive, they cannot be reduced by common reducing agent (C, CO, H2) For example: K, Na, Ca, Mg,Al.
  2. Extraction by common reducing agents: Metals at the middle of the activity series, being less reactive, can be extracted from their ores by reduction with common reducing agents like C, CO, H2
    For example: Zn, Fe, Pb, Cu.
  3. Extraction by thermal decomposition: Metals near the bottom of the activity series, due to their very low reactivity, can be extracted from their ores, by heating only.
    For example: Hg, Ag.
  4. Metal at the bottom of the activity series exist in native state (Au, Pt).
  5. State the electrode reaction at the respective electrodes during extraction of Al from Al2 O3.

Question 22.
State the electrode reaction at the respective electrodes during extraction of Al from Al2 O3.
Answer:
At cathod:   2Al3+ + 6e–  → 2Al
At anode:    3O2- – 6e → 3|0|
3|0|+3|0|→3O2

UNIT TEST PAPER 5 – ELECTROLYSIS

Question 1.
Match the statements 1 to 5 with their answers selected from A to J.
A: Cathode, B: Sucrose soln., C: Cl”, D : Formic acid, E: Electro metallurgy, F: Ammonia, G: Mg2+, H: Electro refining, I: Sulphur dioxide, J: Anode.

  1. A compound containing molecules only.
    Ans. Sucrose soln.
  1. A compound which ionizes in soln. state but not in gaseous state.
    Ans. Ammonia
  1. The ion which accepts electrons from the cathode and gets reduced to neutral atoms.
    Ans. Mg2+
  1. The electrode to which the cyanide ions of aq. Na[(Ag(CN)2] migrate during electrolysis.
    Ans. Anode
  1. An application of electrolysis in which the anode does not generally diminish in size.
    Ans. Electro metallurgy.

Question 2.
Complete the table given below:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 26
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 27

Question 3.
Select the correct word from the words in bracket to complete the sentence:

  1. The electrode at which anions donate excess electrons and are oxidized to neutral atoms is the…………….. (anode / cathode).
    Ans. Anode
  1. On electrolysis, Ag1+ and H1+ ions migrate to the…………..(cathode / anode) and………… (Ag1+ / H,+) are discharged.
    Ans. Cathode ; AgI+
  1. Electrolysis is a / an………. (oxidation / reduction / redox) reaction in which reduction reaction takes place at the……………. (cathode / anode)
    Ans. redox, cathode
  1. According to Arrhenius’s theory the amount of electricity conducted by the electrolyte depends on the ………………… (nature / concentration) of the ions in solution.
    Ans. Concentration
  1. Salts ionize in aq. soln. on passage of electric current to give……….. (negative / positive) ions other than H+ ions.
    Ans. positive.

Question 4.
Give balanced equations for the electrode reactions involved in the following conversions at the respective electrodes:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 28
Answer:

  1. Electrolysis of molten Al203:
    202- – 4e→ 2 [O]
    [O] + [O]→ O2 (g)    (At Anode)
    Electrolysis of copper (II) sulphate
    4OH- (aq) + 4e→ 4 [OH]
    4 [OH] → 2H2O (l) + O2 (g)    (At Anode)
  2. Cu (s) – 2e→ Cu2+ (aq)   (At Anode)
    Cu2+ (aq) + 2e→ Cu (s)   (At Cathod)
  3. Electrolysis of molten PbCl2
    2Cl (l) – 2e→ 2 [Cl]
    2 [Cl] → Cl2(g) (At Anode)
    Electrolysis of HCl (aq)
    2Cl- (aq) – 2e → 2 [Cl]
    2 [Cl] → Cl2 (g)
  4. Electrolysis of acidified water
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 29
    4OH – 4e→ 4 [OH]
    4 [OH] → 2H20 (l) + O2 (g)  (At Anode)
  5. Electrolysis of molten KBr
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 30
    2Br (l) – 2e→ 2 [Br]
    2[Br]→ Br2 (g) (At Anode)
    Electrolysis of molten PbBr2

    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 31
    2Br (l) — 2e → 2 [Br]
    2 [Br] ) Br2 (g) (At anode)

Question 5.
Select the correct answer from the list in bracket:

  1. The cation discharged at the cathode most readily.[Fe2+, Cu2+, Pb2+, H1+]
    Ans. Cu2+
  2. The anion discharged at the anode with most difficulty.[SO2-4, Br1-, N03‘-OH1]
    Ans. OH1
  3. The metallic electrode which does not take part in an electrolytic reaction. [Cu, Ag, Fe, Ni]
    Ans. Fe
  4. The ion/s which is / are discharged during electrolysis of aq. CuSO4 using Cu electrode.
    [Cu2+, S042-, H1+, OH1-]
    Ans. Cu2+
  5. A covalent compound which in aqueous state conducts electricity.    [CCl4, CS2, NH3, C2H4]
    Ans. NH3

Question 6.
Give reasons for the following:

Question 1.
Electrolysis of molten lead bromide is considered a redox reaction.
Answer:
Electrolysis of molten PbBr2 takes place as follows:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 32
Pb2+ + 2e → Pb (at cathode)

New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 33
2 [Br]→ Br
Thus reduction takes place at cathode while oxidation takes place at anode. Therefore, electrolysis of molten PbBr2 is a redox reaction.

Question 2.
Lead bromide undergoes electrolytic dissociation in the molten state but is a non-electrolyte in the solid state.
Answer:
The ions present in PbBr2 in solid state are held by strong electrostatic forces of attraction and hence cannot move under the influence of applied electric field.

OR

In solid state only tiny electrons can move under the influence of applied electric field (e.g., in metals). Ions are too big to move in solid state.

Question 3.
The blue colour of aq. copper sulphate does not change when it is electrolysed using copper electrodes.
Answer:
For every copper ion (Cu2+) discharged at the cathode as neutral copper atom (Cu), a copper ion (Cu2+) is released or added to the solution at the anode and hence the total number of Cu2+ ions remains the same. Therefore the blue colour of CuSO does not fade in electrolytic reaction.

Question 4.
During electrolytic dissociation of sodium chloride, the sodium ions are discharged at the cathode.
Answer:
Sodium ions (Na+) being positively charged migrate to negative electrode, i.e., cathode. This is due to electrostatic forces of attraction between oppositely charged ions.

Question 5.
In the electrolysis of acidified water, dilute sulphuric acid is preferred to dilute nitric acid.
Answer:
Since nitric acid is a volatile acid, may decompose and nitrate radical (N03) may tend to interfere with the electrolytic reaction.

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