ICSE Solutions for Class 10 Chemistry – Electrolysis

ICSE Solutions for Class 10 Chemistry – Electrolysis

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APlusTopper.com provides ICSE Solutions for Class 10 Chemistry Chapter 6 Electrolysis for ICSE Board Examinations. We provide step by step Solutions for ICSE Chemistry Class 10 Solutions Pdf. You can download the Class 10 Chemistry ICSE Textbook Solutions with Free PDF download option.

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Short Questions

Question 1: Classify following substances under three headings:
Strong electrolytes, Weak electrolytes, Non-electrolytes.
Acetic acid, ammonium chloride, ammonium hydroxide, carbon tetrachloride, dilute hydrochloric acid, sodium acetate, dilute sulphuric acid.
Answer: Strong electrolytes —Ammonium chloride, dilute hydrochloric acid, dilute sulphuric acid.
Weak electrolytes — Ammonium hydroxide, acetic acid, sodium acetates.
Non-electrolyte — Carbon tetra chloride.

Question 2: How will you distinguish between metallic conductions and electrical conductions ?
Answer:

Metallic Conduction Electrical Conduction
(i) By the Movement of electrons. By the Movement of ions.
(ii) Does not involve the transfer of matter. It involves the transfer of matter as ions.
(iii) No change in chemical properties of the conductor. It involve the decomposition of electrolyte as a result of chemical reactions.
(iv) Increase in resistance with, die rise of temperature. Decrease in resistance with the rise of temperature.

Question 3: Differentiate between an Electrolytic cell and Electrochemical cell.
Answer:

Electrolytic cell Electrochemical cell
It is a device (vessel) in which chemical changes are brought about with the help of electric energy. It is a device in which electric energy is generated as a result of chemical change.

Question 4: Differentiate between electrical conductivity of copper sulphate solution and copper metal.
Answer: Differences between electrical conductivity of copper sulphate solution and copper metal:

Copper sulphate solution Copper metal
Electric current is by flow of ions. Electric current is by flow of electrons.
It is aqueous solution of ionic compound. It is a metal in solid state.
Copper sulphate undergoes a chemical change. Copper metal remains unchanged chemically.

Question 5: Choose A, B, C or D to match the descriptions (i) to (v) below. Some alphabets may be repeated.
A. non-electrolyte
B. strong electrolyte
C. Weak electrolyte
D. metallic conductor
(i) Molten ionic compound
(ii) Carbon tetrachloride
(iii) An aluminium wire
(iv) A solution containing solvent molcules, solute molecules and ions formed by the dissociation of solute molecules.
(v) A sugar solution with sugar molecules and water molecules.
Answer: (i) B, (ii) A, (iii) D, (iv) C, (v) A.

Question 6: Give three differences between sodium atom and sodium ion.
Answer: (i) Sodium atom is neutral in nature, while sodium ion is a positively charged particle.
(ii) Sodium atom vigorously reacts with water to liberate hydrogen gas, while sodium ion does not react with water.
(iii) Sodium atom tends to lose an electron to form sodium ion with a complete octet in the outermost shell.

Question 7: Explain how electrolysis is an example of redox reaction.
Answer: Redox reactions are called simultaneous oxidation-reduction reactions. In electrode reactions, the positively charged ions (cations) accept electrons from cathode to form neutral atoms, i.e., at cathode reduction’takes place. At anode, the negatively charged ions (anions) lose electrons to form neutral atoms, i.e., at anode oxidation takes place. So, electrode reactions also signify oxidation-reduction reactions. Hence, they are also called Redox reactions.

Question 8: (i) Write equations to show the electrolytic dissociation of:
(a) Two acids (b) Two bases.
(ii) When fused sodium chloride is electrolysed, explain exactly what happens at the electrodes and explain how the electricity is conducted ?
Answer: (i) (a) Acids:
H2SO4   ⇌   2H+ + SO42-
HNO  ⇌   H+ + NO3
(b) Bases:
NaOH    ⇌    Na+ + OH
KOH    ⇌    K+ + OH
(ii) When electricity is passed through fused sodium chloride, the electrolysis starts as follows :
NaCl    ⇌    Na+ + Cl
Na+ + e–   ⟶   Na (At cathode)
Cl – e  ⟶   Cl
Cl + Cl   ⟶  Cl2 (At anode)
Sodium metal is deposited at cathode, while chlorine gas is liberated at anode. Electricity is conducted with the help of free sodium and chloride ions, which are present in fused sodium chloride.

Question 9: How is it possible to discharge Na+ ions in preference to H+ ions in electrolysis of NaCl solution ?
Answer: By using cathode made of moving mercury, Na+ ions are discharged in preference to H+ ions because of the nature of electrode. Mercury has strong tendency to form an amalgam with : sodium
Na+ + e–   ⟶   Na
Na + Hg   ⟶  Na/Hg
When the sodium amalgam dissolves in water, the reaction is
2Na/Hg + 2H20   ⟶  2NaOH + H2 + Hg

Question 10: A certain metal, say M, does not liberate hydrogen from dilute sulphuric acid, but displaces copper from aqueous copper (II) sulphate. State the most likely place for the metal in electrochemical series.
Answer: The activity series is obtained, when we examine replacement of one metal ion from its solution by another metal. The metal (M) which displaces copper from aqueous copper (II) sulphate is placed at higher position as compared to copper in activity series.

Question 11: M is a metal above hydrogen in the activity series and its oxide has the formula M2O. This oxide when dissolved in water forms the corresponding hydroxide which is a good conductor of electricity. In the above context answer the following:
(i) What kind of combination exists between M and O ?
(ii) How many electrons are there in the outermost shell of M ?
(iii) Name the group to which M belongs.
(iv) State the reaction taking place at the cathode.
(v) Name the product at the anode.
Answer: (i) Electrovalent bond exists between M and O.
(ii) One electron is there in the outermost shell.
(iii) M belongs to First group.
(iv) M+ + e  ⟶   M (at cathode).
M + M   ⟶  M2
(v) Oxygen gas is liberated at anode.

Question 12: How will you electrolyse the molten solution of lead bromide?
Answer: Molten lead bromide (PbBr2) forms and Br ions. The positive lead ions (Pb2) move to the cathode, and gain two electrons and change into lead atom.
Pb2+ + 2e–   ⟶   Pb (Lead)
Lead is deposited at the cathode. The negative bromide ion migrates to the anode. It loses an electron and becomes a bromide atom. The two bromine atoms join bromine molecule. It is liberated as bromine gas.
Br – e   ⟶   Br
Br+Br   ⟶   Br2

Question 13: (i) What are the particles present in a non-electrolyte?
(ii) What is conductivity of metals due to?
(iii) What should be the physical state of lead bromide, if it is to conduct electricity?
(iv) What particles are present in pure lead bromide?
Answer: (i) Molecules are present in a non-electrolyte.
(ii) The conductivity of metals is due to movement of electrons.
(iii) Lead bromide should be in molten state, if it is to conduct electricity.
(iv) Lead ions and bromide ions are present in pure lead bromide in molten state.

Question 14: (i) When the electrolysis of acidified water is carried out:
(a) What is the ratio of the volume of hydrogen produced to the volume of oxygen?
(b) Give the equation for the discharge of ions at the cathode.
(ii) To carry out the so-called “electrolysis of water”, sulphuric acid is added to water. How does the addition of sulphuric acid produce a conducting solution?
Answer: (i) (a) The ratio is 2 : 1
(b) H+ + e   ⟶   H; 2H + 2H   ⟶   2H2
(ii) Addition of sulphuric acid causes dissociation of water molecules into [H+] and [OH] ions.

Question 15: What would happen if in the electrolysis of acidified water, copper electrodes were used instead of platinum ones ?
Answer: At anode : OH and S032- would migrate to anode but neither would be discharged, instead copper atoms would get oxidised to Cu2+ and enter solution
Cu   ⟶   Cu2+ + 2e
The electrolytic solution would become blue in colour. Anode would dissolve.
At cathode : H+ ions would migrate to the cathode and get reduced. Thus, H2 gas would be discharged at cathode
2H+ + 2e   ⟶   2H   ⟶   H2
Later, as the solution turns blue due to formation of Cu++ ions, the Cu++ ions will get discharged to 2Hions as they are less electropositive
Cu2+ + 2e   ⟶   Cu↓

Question 16: During the electrolysis of aqueous copper sulphate, between copper electrodes, the sulphate and hydroxyl ions remain as spectator ions.
Answer: During electrolysis of aqueous copper sulphate using copper electrodes, the two anions OH.and S042- migrate to the anode, but none of them get discharged because the copper of the anode dissolves in the solution producing copper ions and electrons. Hence, OH and S042- ions remain as spectator ions.

Question 17: The following questions refer to the electrolysis of copper sulphate solution with copper electrodes.
(i) Compare the change in mass of the cathode with the change in mass of the anode.
(ii) What happens, when electrolysis of aqueous copper sulphate between platinum electrode, occurs.
(iii) What is the practical application of the electrolysis of copper sulphate solution ? Briefly describe one such application.
Answer: (i) Mass of Cathode increases where as that of anode decreases due to deposition of pure copper on cathode.
(ii) The blue colour of copper sulphate is due to the presence of cupric ions (Cu++). Cu++ ions are discharged at the cathode and deposited as Pinkish copper metal, but OH ions are discharged at anode. The electrolyte consists of hydrogen and sulphate ions which associate to form colourless sulphuric acid.
(iii) The electrolysis of copper sulphate solution is used in the purification of copper using pure copper plate as cathode and impure copper plate as anode.

Question 18: During the electrolysis of copper (II) sulphate solution using platinum as cathode and carbon as anode:
(i) What do you observe at the cathode and at the anode ?
(ii) What change is noticed in the electrolyte ?
(iii) Write the reactions at the cathode and at the anode.
Answer: (i) At cathode red shiny metal deposits.
At anode bubbles of a colourless odourless gas are seen coming out.
(ii) Colour of electrolyte gradually fades from blue to colourless.
(iii) Reaction at cathode:
Cu2+ + 2e   ⟶   Cu
Reaction at anode:
OH – 1e  ⟶   OH
4OH   ⟶    2H2O + O2

Question 19: Explain, how the blue colour of electrolyte fades during electrolysis of CuSO4 solution ?
Answer: The blue colour of electrolyte is due to the presence of copper ions in it. As the electrolysis is . carried out, the copper ions discharge at the cathode.
Cu2+ + 2e   ⟶   Cu
However, no copper ions enters in the electrolyte from anode. Thus concentration of copper ions goes on decreasing. This result in fading of blue colour. When copper ions completely finish the electrolyte becomes colourless.
Reaction of cathode:
H+ + e   ⟶   H
H + H   ⟶   H2
Reaction of anode :
OH – 1e  ⟶   OH
4OH   ⟶    2H2O + O2(g)

Question 20: Explain, how blue colour of electrolyte remains unchanged during electrolysis of aqueous copper sulphate ?
Answer: The decrease in the weight of copper anode is equal to the increase in weight of copper cathode.
ICSE Solutions for Class 10 Chemistry - Electrolysis 1
From the above equations it can be deduced that for every Cu2+ discharging at cathode a copper atom ionises from anode to form Cu2+ ion.
Thus concentration of copper ions in electrolyte remain unchanged. As the blue colour of electrolyte is due to the presence of Cu++ ions, therefore it does not change.
ICSE Solutions for Class 10 Chemistry - Electrolysis 2

Question 21: Mention the type of ions present, the products obtained and the electrode reactions that occur, when the following are electrolysed :
(i) Molten lead bromide between steel cathode and graphite anode.
(ii) Water acidified with sulphuric acid between platinum electrodes.
(iii) Aqueous copper sulphate between copper electrodes.
(iv) Aqueous copper sulphate between copper cathode and platinum anode.
Answer:
ICSE Solutions for Class 10 Chemistry - Electrolysis 3

Question 22: With reference to electroplating answer the following :
(i) Why are articles electroplated ?
(ii) Why a small current passed for a longer period is preferred over high current for a shorter period ?
(iii) Why the article to be electroplated is made a cathode ?
(iv) Why a direct current is used ?
Answer: (i) Articles are electroplated for the following reasons:
(a) To prevent it from corrosion.
(b) To improve the appearance of the metal articles.
(ii) To get a uniform and smooth coating of superior metal, a small current should be used -for a longer time.
(iii) The article to be electroplated is always placed at cathode because the metal is always deposited at cathode.
(iv) Direct current is used to get smooth coating and the phase of the current is same at all instance of time.

Question 23: How a spoon is electroplated with silver ?
Answer: Silver nitrate solution is taken in a beaker. Silver wire and a spoon, which is to be plated with silver, are dipped in the solution. Silver wire is connected with the positive terminal of the battery which acts as anode and spoon is connected with the negative terminal of the battery which acts as cathode.
When electric current is passed through silver nitrate solution, electrolysis takes place and silver is deposited as a fine thin film at the surface of spoon. The spoon is coated with silver and looks as a silver spoon.

Question 24: Element X is a metal with a valency 2.
Element Y is a non-metal with a valency 3.
(i) Write equations to show how X and Y form ions.
(ii) If Y is a diatomic gas, write the equation for the direct combination of X and Y to form a compound.
(iii) Write two applications of electrolysis in which the anode diminishes in mass.
(iv) If the compound formed between X and Y is melted and an electric current passed through the molten compound, the element X will be obtained at the … and Y at the … of the electrolytic cell.
(Provide the missing words.)
Answer: (i) X – 2e   ⟶   X2+
Y + 3e   ⟶   Y3-
(ii) 3X+2 + 2Y-3   ⟶   X3Y2
(iii) (1) Electroplating of Metals.
(2) Electro-refining of Metals.
(iv) If the compound formed between X and Y and an electric current passed through the molten compound, the element X will be obtained at the cathode and Y at the anode of the electrolytic cell.

Question 25: Mr. Ramu wants to electroplate his key chain with nickel to prevent rusting. For this electroplating :
(i) Name the electrolyte
(ii) Name the cathode
(iii) Name the anode
(iv) Give the reaction at the cathode
(v) Give the reaction at the anode.
Answer: (i) Nickel sulphate (ii) Key chain
(iii) Pure nickel plate
(iv) Ni2+ + 2e  ⟶   Ni
(v) Ni – 2e   ⟶   Ni2+.

Question 26: Three different electrolytic cells A, B and C are connected in separate circuits. Electrolytic cell A contains sodium chloride solution. When the circuit is completed a bulb in the circuit glows brightly. Electrolytic cell B contains acetic acid solution and in this case the bulb in the circuit glows dimly. The electrolytic cell C contains sugar solution and the bulb does not glow. Give a reason for each of these observations.
Answer: In Cell A: Sodium chloride being strong electrolyte dissociates completely and therefore current flows better.
In Cell B: Acetic acid being weak electrolyte ionises only partially and therefore, only a weak current flows.
In Cell C: Sugar being a covalent compound does not ionise at all and therefore, no current flows.

Figure/Table Based Questions

Question 1:
ICSE Solutions for Class 10 Chemistry - Electrolysis 4
(i) Name the cathode and anode used during electroplating of silver.
(ii) Name the electrolyte used in this processes.
(iii) Give the dissodation reactions taking place.
(iv) Give the reactions occuring at cathode and anode.
(y) The overall strength of silver ions remain constant in the reaction. Why?
Answer: (i) Cathode: Highly cleaned article such as copper cup.
Anode : A plate or rod of silver.
(ii) Sodium argento cyanide (Na[Ag(CN)2]) and hydrocyaruc acid (HCN).
ICSE Solutions for Class 10 Chemistry - Electrolysis 5
(v) Overall strength of silver ions does not change in the electrolyte as the number of Ag+ ions entering the electrolyte is equal to the number of Ag+ ions discharged at cathode.

Question 2: Copper sulphate solution is electrolysed using copper electrodes. Study the diagram given below and answer the question that follows:

ICSE Solutions for Class 10 Chemistry - Electrolysis 6
(i) Which electrode to your left or right is known as the oxidising electrode and why ?
(ii) Write the equation representing the reaction that occurs.
(iii) State two appropriate observations for the above electrolysis reaction.
Answer: (i) Electrode on the left side is the oxidising electrode because copper atoms lose electrons at this electrode.
(ii) Cu – 2e–  ⟶  Cu2+
(iii) Reddish brown copper metal is deposited at cathode and blue colour of aqueous copper (II) Sulphate solution remains unchanged.

Question 3: (i) Study the diagram given below and answer the questions that follows :
ICSE Solutions for Class 10 Chemistry - Electrolysis 7
(a) Give the names of the electrodes A and B.
(b) Which electrode is the oxidizing electrode ?
(ii) A strip of copper is placed in four different colourless salt solutions. They are KNO3, AgNO3, Zn(NO3)2, Ca(NO3)2. Which one of the solutions will finally turn blue ?
(iii) Write the equations of the reactions which take place at the cathode and anode when acidified water is electrolysed.
Answer: (i) (a) A—Anode
B—Cathode
(b) A
(ii) AgNO3 solution
ICSE Solutions for Class 10 Chemistry - Electrolysis 8

Question 4: Study the given figure and answer the question that follow :
ICSE Solutions for Class 10 Chemistry - Electrolysis 9
(i) Why silica crucible is used in this type of electrolysis ?
(ii) Which anode is preferred and why ?
(iii) Why crucible is heated from outside ?
(iv) Write the equations of the reaction which take place at the cathode and anode.
Answer: (i) Silica is non-reactive. It can withstand at high temperature and is almost a non-conductor of electricity.
(ii) The graphite anode is preferred because it is unaffected by the reactive bromine vapours.
(iii) The crucible is heated from outside to keep lead bromide in the molten sate. So that the ions become free.
ICSE Solutions for Class 10 Chemistry - Electrolysis 10

Question 5: An electrolytic all is an set up using two platinum electrodes and an aqueous solution of copper (II) sulphate.
(i) Draw a labelled diagram of the electrolytic cell.
(ii) Name the ions present in the cell.
(iii) Name the ions migrating towards the anode.
(iv) Name the ios migrating towards the cathode.
(v) Name the ions which will not be discharged at electrodes during electrolysis.
(vi) Write the reaction at the cathode.
(vii) Write the reaction at the anode.
(viii) Name the spectator ions in the solution.
(ix) Why the electrolytic solution acidified.
Answer: (i)
ICSE Solutions for Class 10 Chemistry - Electrolysis 11
(ii) The ions present in the cell are Cu2+ + H+, SO42- and OH.
(iii) The ions migrating towards the anode are SO42- and OH.
(iv) The ions migrating towards the cathode is Cu2+.
(v) The ions will not be discharged at electrode during electrolysis are H+ and OH.
ICSE Solutions for Class 10 Chemistry - Electrolysis 12
(viii) The separator ions present in the solution are – SO42- and OH.
(ix) To increase the electrical conductivity of electrolyte.

Question 6: A saturated aqueous copper (II) chloride is electrolysed using graphite anode and copper cathode as illustrated in diagram given below:
ICSE Solutions for Class 10 Chemistry - Electrolysis 13
(i) Name the ions which will migrate to cathode.
(ii) Nametheions which will migrate to anode.
(iii) Which ion is likely to discharge at cathode and why?
(iv) Write ionic equation fòr reaction taking place atcathode.
(v) Which ion is likely to discharge at anode and why ?
(vi) Write ionic equation for reaction taking place at anode.
(vii) If electric current is passed for a very long time, state colour change taking place in electrolyte. State one reason for the change.
(viii) Give one reason for using graphite anode, rather than copper anode.
(ix) Name the gas liberated at cathode after the colour changes in electrolyte.
Answer: (i) Copper ions (Cu2+) and hydrogen ions H+ migrate to cathode.
(ii) Chloride ions (Cl) and hydroxyl ions OH migrate to anode.
(iii) Copper ions (Cu2+) are likely to discharge at cathode, because their position is lower than hydrogen ions H+ in electrochemical series.
(iv) Cu2+ + 2e–  ⟶  Cu
(v) Hydroxyl ions (OH) are likely to discharge at anode, because their position is lower than chloride ion (Cl) in electrochemical series.
(vi) 4OH – 4e  ⟶   2H2O + O2 (g)
(vii) The electrolyte gets decolourised. It is because, the blue colour of electrolyte is due to the presence of Cu2+ ions. As Cu2+ ions discharge at cathode, therefore their concentration in electrolyte decreases. Thus, gradually blue colour fades away.
(viii) In such a situation the copper atoms on copper anode ionise and enter into electrolyte. Thus, size of copper anode gradually decreases. This is not possible in case of graphite anode.
(ix) Hydrogen gas is liberated at cathode.

Reasoning Based Questions

Question 1: Why are adds, bases and salts classified as electrolytes?
Answer: Acids, bases and salts are classified as electrolytes because these compounds dissociate into ions, conduct electricity and undergo chemical decomposition at the same time.

Question 2: Metals like potassium, calcium, sodium, etc., can be extracted only by electrolysis.
Answer: Metals like K, Ca, Na, etc., can be extracted only by electrolysis because conventional reducing agents such as coke, carbon monoxide, hydrogen do not supply sufficient energy to break ionic bonds between the active metals and their chlorides or oxides.

Question 3: Dilute acids are strong electrolytes. Why?
Answer: Dilute acids produce a large number of hydronium ions, so they behave like strong electrolytes.

Question 4: Sea water is a strong electrolyte. Why?
Answer: Sea water is a strong electrolyte because sodium chloride dissolved in it dissociates completely into free mobile ions.
Na+Cl-  ⇌  Na+ + Cl

Question 5: Copper is a good conductor of electricity, but it is a non-electrolyte. Why?
Answer: During metallic conduction, the chemical properties of copper are intact as it does not undergo chemical decomposition. Since, the flow of electricity only produces heat and energy and no new products are formed copper metal is thus a good conductor of electricity but is a non electrolyte.

Question 6: A solution of ionic compound is an electrolyte, while that of covalent compound is non electrolyte?
Answer: The solution of ionic compound has free ions, which can migrate to cathode and anode and discharge. Thus, solution of ionic compound is good conductor of electricity and hence is electrolyte.
However, a solution of covalent compound, consists of only molecules and does not have any free ions, which could migrate to cathode or anode. Hence, it is non-electrolyte.

Question 7: Explain, why hydrochloric acid is a conductor of electricity?
Answer: Hydrochloric acid dissociates into ions in aqueous solution as follows:
HCl   ⇌  H+ + Cl
When a current is passed through in aqueous solution of HCl, the ions move towards their respective electrodes. Thus, the hydrochloric acid is a conductor of electricity.

Question 8: Does wax conduct electricity ? Give reason to justify your answer.
Answer: No, wax does not conduct electricity because wax, being a covalent compound, does not have positively or negatively charged ions which could not be weakened by heating or in aqueous solution. Therefore due to absence of free ions, wax does not conduct electricity.

Question 9: Mercury is a liquid and allows the flow of electricity, though it is not an electrolyte.
Answer: An electrolyte is a substance which on dissolving in water breaks up into positively and negatively charged ions. But mercury is a metal, so on dissolving in water, it can’t break up into cations and anions, When electric current passes through mercury it doesn’t undergo any decomposition and no new substance is formed. Electric current passes through mercury due to the presence of free electrons in its penultimate shell and not due to the formation of ions.
Hence, mercury is a metallic conductor and not an electrolyte.

Question 10: A solution of cane sugar does not conduct electricity, but a solution of sodium chloride is a good conductor.
Answer: The sugar cane solution is a covalent compound. When it is dissolved in water, does not dissociate to give free ions which could migrate to cathode or anode. Hence, sugar solution is bad conductor of electricity. The sodium chloride solution mainly consists of free sodium and chloride ions which could migrate to positively charged electrodes. Hence, solution of sodium chloride is good conductor of electricity.

Question 11: Why does blue colour of CuSO4 solution slowly disappear when iron rod is dipped in it ?
Answer: When an iron rod is dipped in CuSO4 solution, iron displaces copper from CuSO4 to form FeSO4 which is light green in colour.
ICSE Solutions for Class 10 Chemistry - Electrolysis 14

Question 12: During electrolysis high voltage is not favoured. Why ?
Answer: During electrolysis high voltage is not favoured because the electrolytic conduction increases with rise in temperature, i.e., decrease in resistance. Increase in resistance can only be obtained by applying low voltage during electrolysis.
Thus, only electricity is suitable as reducing agent which provides unlimited amount of energy to break ionic bonds easily.

Question 13: While electrolysing concentrated sulphuric acid, the bulb glows very dimly but when diluted, the bulb glows brightly. Why ?
Answer: Concentrated (99%) sulphuric acid behaves like a weak electrolyte as it has very little hydronium ions in it. But when added to water, it becomes diluted and produces a large, number of hydronium ions. Now, it behaves like a stronger electrolyte and hence the bulb glows brightly.

Question 14: Why electrolysis of acidulated water is considered example of electrolysis ?
Answer: It is because the amount of sulphuric acid does not change when water is electrolysed. The sulphuric acid just helps in increasing the conductivity of water.

Question 15: Why should water be acidified before proceeding with the electrolysis of water ?
Answer: It is done because water is a non-electrolyte, so it can be electrolytically decomposed by removing the H+ and OH ions continuously because the negligible ionization of water yields H+ and OH ions which recombine to form a water molecule, then another molecule will ionize. Sulphuric acid is used to remove these ions.
ICSE Solutions for Class 10 Chemistry - Electrolysis 15

Question 16: Hydroxyl (OH) ion is lower in the activity series, than chloride ion. Yet when a concentrated solution of hydrochloric acid is subjected to electrolysis, the hydroxyl ion does not get discharged.
Answer: If an electrolyte has a much higher concentration of ions that are higher in the electrochemical series than those that are lower, then the higher gets discharged in preference to the lower one. Concentrated hydrochloric acid being strong electrolyte gets fully dissociated furnishing H+ and Cl ion. Water is less dissociated into H+ and OH ion. Thus, concentration of chloride ion is more as compared to OH ion and hence, chloride ion are discharged in preference to the OH ion.

Balancing/Writing the Chemical Equations

Question 1: Write equations for the reactions taking place at cathode and at anode during the electrolysis of :
1. Acidified nickel sulphate solution with nickel electrode.
2. Acidified copper sulphate solution with copper electrode.
3. Acidified copper sulphate solution with platinum electrode.
4. Acidulated water with inert electrode.
5. Molten lead bromide with inert electrodes.
6. Electroplating a spoon with silver.
Answer:
ICSE Solutions for Class 10 Chemistry - Electrolysis 16
Question 2: Complete and balance the following equations :
ICSE Solutions for Class 10 Chemistry - Electrolysis 17
Answer:
ICSE Solutions for Class 10 Chemistry - Electrolysis 18

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Selina Concise Chemistry Class 10 ICSE Solutions Electrolysis

Selina Concise Chemistry Class 10 ICSE Solutions Electrolysis

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Selina ICSE Solutions for Class 10 Chemistry Chapter 6 Electrolysis

Exercise Intext 1

Solution 1.

(a) Powdered sodium chloride (common salt) does not conduct an electric current, but it does so when dissolved in water or when melted.

(b) Molten lead bromide conducts electricity .It is called an electrolyte. It is composed of lead ions and bromide ions. The lead ions are positivelycharged and are called cations. The bromide ions are negatively charged and are called anions.

(c) Substances which conduct electricity in the solid state are generally metals.

(d) The electron releasing tendency of zinc is more than that of copper.

(e) A solution of HCl gas in water conducts electricity because it ionizes, but a solution of HCl gas in toluene does not conduct an electric current because it does not ionize in toluene.

Solution 2.

(a) Electrolysis: It is the process of decomposition of a chemical compound in aqueous solutions or in molten state accompanied by a chemical change using direct electric current.

(b) Non-electrolyte: It is a compound which neither in solution nor in the molten state allows an electric current to pass through it.

(c) Cation and anion: Atoms which carry positive charge are called cations.
Atoms which carry negative charge are called anions.

(d) Weak electrolyte: Electrolytes which allow small amount of electricity to flow through them and are partially dissociated in fused or aqueous solution are called weak electrolyte.

Solution 3.

(a) Difference between Modern explanation and Arrhenius explanation for the theory of electrolysis:
Arrhenius considered that water ionizes electrolytes but Modern theory explained that electrolytes are ionic even in solid state and their ions are held by strong electrostatic forces which make them immobile. Water renders these ions mobility by breaking the electrostatic forces.

(b) Difference between electrolytic dissociation and ionization :

Ionisation Dissociation
1. Formation of positively or negatively charged ions from molecules which are not initially in the ionic state. 1. Separation of ions which are already present in an ionic compound.
2. Polar covalent compounds show ionization. e.g. HCl, H2CO3, NH4OH etc. 1. Electrovalent compounds show dissociation. e.g. Potassium chloride , lead bromide, etc.

(c) A cation and anion:

Cation Anion
1. Are positively charged ions. Are negatively charged ions.
2. Migrate to cathode during electrolysis. Migrate to anode during electrolysis.
3. Gain electron from the cathode and get reduced to become a neutral atom. Lose electrons to the anode and get oxidized to become a neutral atom.

(d) Electrolytic dissociation and thermal dissociation:
Electrolytic dissociation is the dissociation of an electrovalent compound into ions in the fused state or in aqueous solution state.

Thermal dissociation: Reversible breakdown of a chemical compound into simpler substances by heating it. The splitting of ammonium chloride into ammonia and hydrogen chloride is an example. On cooling, they recombine to form the salt.

Solution 4.

(a) Sodium carbonate
(b) NH4OH
(c) An inert electrode: graphite and Active electrode: silver
(d) H+
(e) Electrode is cathode
(f) Graphite

Solution 5.

Electrolysis is a redox process. The reaction at the cathode involves reduction of cations as they gain of electrons while the reaction at anode involves oxidation of anions as they loss of electrons to become neutral.
Example: Dissociation of sodium chloride during electrolysis.

Cathode : Na+ + e → Na (reduction)
Cl – e– → Cl (oxidation)
Cl + Cl → Cl2
Overall reaction: 2NaCl → 2Na + Cl2

Exercise Intext 2

Solution 1.

(a) Glucose, Kerosene
(b) NaCl and NaOH
(c) CH3COOH and NH4OH

Solution 2.

(a) Cane sugar is a compound which does not have ions even in solution and contains only molecules. Hence, it does not conduct electricity. On the other hand, sodium chloride solution contains free mobile ions and allows electric current to pass through it. This makes it a good conductor of electricity.

(b) Hydrochloric acid is a strong electrolyte and dissociates completely in aqueous solution. The solution contains free mobile ions which allow electric current to pass through it. Hence, hydrochloric acid is a good conductor of electricity.

(c) Hydrogen is placed lower in the electrochemical series and sodium is placed at a higher position. This is because H+ ions are discharged more easily at the cathode than Naduring electrolysis and gains electrons more easily.
Therefore, H+ ion is reduced at the cathode and not Na+ ion.

Solution 3.

(a) Zn occurs readily as ion whereas Cu occurs more readily as metal in nature.

(b) Copper is above silver in the electrochemical series and is thus more reactive than silver. So, copper displaces silver from silver nitrate. Hence, we cannot store AgNO3 solution in copper vessel.
Cu +AgNO3 → Cu(NO3)2 + 2Ag

(c) Copper is more active than Ag.

Solution 4.

(a) By treating its salt with a more reactive metal.
(b) By supplying two electrons to Cu+2
Cu+2 + 2e– → Cu

Solution 5.

In the aqueous state, the slightly negatively charged oxygen atoms of the polar water molecule exerts a pull on the positively charged sodium ions. A similar pull is exerted by the slightly charged hydrogen atoms of the water on the negatively charged chloride ions. Thus the ions become free in solution. These free ions conduct electricity.
In the molten state, the high temperatures required to melt the solid weakens the bond between the particles and the ions are set free.

Solution 6.

(a) Two anions are and OH.

(b) OH is discharged at anode and the main product of the discharge of OH is O2
Reaction is :
OH– → OH + e
4OH → 2H2O + O2

(c) The product formed at cathode is hydrogen. The reaction is :
H+ + e → H
H + H → H2

(d) No change in colour is observed.

(e) Dilute sulphuric acid catalyse the dissociation of water molecules into ions, hence electrolysis of acidified water is considered as an example of catalysis.

Solution 7.

(a) Labelled diagram of electrolytic cell is:

(b) The ions present in the cell are Cu2+, H+, SO42- , OH.
(c) SO42- and OH ions both migrate towards anode.
(d) Both Cu2+ and H+ ions migrate towards cathode.
(e) SO42- and H+ will not discharge at electrodes.
(f) Reaction at cathode:
Cu+2 +2e → Cu
(g) Reaction at anode:
OH – e → OH
2OH + 2OH → 2H2O + O2
(h) Sulphate ions are the spectator ions because they do not change in the reaction.

Solution 8.

(a) Reaction at anode during the electrolysis ofvery dilute sulphuric acid:
OH → OH + e
4OH → 2H2O + O2

(b) Reaction at anode during the electrolysis of aqueous copper sulphate solution
4OH → 4OH + 4e
4OH → 2H2O + O2

(c) Reaction at anode during the electrolysis of sodium chloride solution
2Cl → Cl2 + 2e

(d) Reaction at anode during the electrolysis of fused lead bromide
Br – e– → Br
Br + Br → Br2

(e) Reaction at anode during the electrolysis of magnesium chloride (molten)
2Cl → Cl2 +2e

(f) Concentrated HCl,
HCl in the pure liquid state is unionised and hence does not conduct electricity.

(g) Very dilute HCl,
Cl – e → Cl
Cl  + Cl  → Cl2

Solution 9.

(a) Electrolyte
(b) Nickel
(c) Cathode
(d) Anode
(e) Cations

Exercise 1

Solution 1.

(a) During electrolysis of lead bromide, there is loss of electrons at anode by bromine and gain of electrons at cathode by lead. Thus oxidation and reduction go side by side. Therefore, it is a redox reaction.
PbBr2 → Pb+2 + 2Br

(b) The blue colour of copper ions fades due to decrease in Cu+2 ions and finally the solution becomes colourless as soon as Cu+2 ions are finished.

(c) Lead bromide dissociate into ions in the molten state whereas it does not dissociate in solid state. The ions become free when lead bromide is in molten state but in the solid state the ions are not free since they are packed tightly together due to electrostatic force between them. Therefore, lead bromide undergoes electrolytic dissociation in the molten state.

(d) Aluminium has great affinity towards oxygen, so it is not reduced by reducing agent. Therefore it is extracted from its oxide by electrolytic reduction.

(e) As per electrolytic reactions, 4H+1 are needed at cathode and 4OH at the anode and two molecules of water are produced at the anode. Hence for every two molecules of water, two molecules of hydrogen and one molecule of oxygen are liberated at the cathode and anode respectively.

(f) This is because HNO3 is volatile.

(g) Ammonia is a covalent compound. Therefore, it is unionized in the gaseous state but in the aqueous solution it gives NH4OH which is a weak electrolyte and dissociates into ions.

(h) Graphite is unaffected by the bromine vapours.

(i) Silver nitrate is not used as electrolyte for electroplating with silver because the deposition of silver will be very fast and hence not very smooth and uniform.

(j) Carbon tetrachloride is a liquid and does not conduct electricity because it is a covalent compound and there are no free ions present and contain only molecules.

Solution 2.

(a) Strong electrolyte : Dilute hydrochloric acid, dilute sulphuric acid, ammonium chloride, sodium acetate
(b) Weak electrolyte: Acetic acid, ammonium hydroxide
(c) Non-electrolyte: Carbon tetrachloride

Solution 3.

(a) Molecules
(b) Will not

Solution 4.

Water is a non-conductor of electricity and consists entirely of molecules. It can be electrolytically decomposed by addition of traces of dilutesulphuric acid which dissociate as H+ and SO42- ions and help in dissociating water into H+ and OH, water being a polar solvent.

Solution 5.

Anode Electrolyte Cathode
Silver plating of spoon Plate of pure clean silver Solution of potassiumargentocyanide Article to be electroplated
Purification of copper Impure copper Solution of coppersulphate and dilutesulphuric acid Thin strip of pure copper

Solution 6.

Electricity, Chemical

Solution 7.

(b) CuSO4 is preferred as an electrolyte.

(c) The copper anode continuously dissolves as ions in solution and is replaced periodically. The electrolyte dissociates into Cu+2 ions which migrate towards the iron object taken as the cathode and are deposited as neutral copper atoms on the cathode.
Electrolyte: Aqueous solution of nickel sulphate
Dissociation: CuSO4 → Cu2+ + SO42-
H2O → H+ + OH
Electrodes:
Cathode: Article to be electroplated
Anode: Block of pure copper
Electrode reactions:
Reaction at cathode: Cu2+ + 2e→ Cu (deposited)
Reaction at anode: Cu – 2e→ Cu2+

Solution 1 (2004).

(a) X → X2+ + 2e , Y + 3e→ Y3-
(b) Y2 + 3X → X3Y2
(c) (i) It is used for the electroplating of metals.
(ii) It is also used in purification of metals.
(d) Cathode, Anode

Solution 1 (2005).

(a) Because Copper is an electronic conductor as it is a metal.
(b) In solid sodium chloride, Na+ and Cl – ions are not free due to strong electrostatic forces of attraction among them. The ions, therefore are unable to move to any large extent when electric field is affected. Hence no current.

Solution 1 (2006).

(a) (i) The name of electrode A is Platinum anode and that of electrode B is platinum or copper cathode.
(ii) Anode act as oxidizing electrode.
(b) AgNOsolution will turn blue.

Solution 1 (2007).

(i) Molten ionic compound: Strong electrolytes
(ii) Carbon tetrachloride: Non-electrolyte
(iii) An aluminium wire: Metallic conductor
(iv) A solution containing solvent molecules, solute molecules and ions formed by dissociation of solute molecules: Weak electrolyte
(v) A sugar solution with sugar molecules and water molecules: Non- electrolyte

Solution 1 (2008).

(a) The reaction takes place at anode. This is an example of oxidation.
(b) Cu+2 will discharge easily at cathode.
Reaction at cathode:
Cu+2 +2e → Cu
(c) Carbon tetrachloride is a non-electrolyte because it is a covalent compound. It does not ionize and hence do not conduct electricity.

Solution 2 (2004).

(a) Non-electrolyte contains molecules.
(b) Molecules of HX and H+ and X ions.
(c) Loss
(d) The electrolyte used for the purpose must contain the ions of metal which is to be electroplated on the article.
(e) The reaction at the cathode involves reduction of cations as they gain electrons to become neutral atoms while that at anode involves oxidation of anions as they lose electrons to become neutral.
Example: Dissociation of sodium chloride during electrolysis.
NaCl → Na+ + Cl
At cathode: Na+ + e Na (Reduction)
At anode: Cl – e → Cl(oxidation)
Cl + Cl → Cl2
Overall reaction: 2NaCl → 2Na + Cl2

Solution 2 (2005).

Hydrogen gas is released at cathode when acidulated water is electrolyzed.

Solution 2 (2008).

During the electrolysis of molten lead bromide. Lead is deposited at cathode.

More Resources for Selina Concise Class 10 ICSE Solutions

What is the Process of Electrolysis

What is the Process of Electrolysis

Electrolysis

The production of a chemical reaction by passing an electric current through an electrolyte is called electrolysis.

We know that an electrolyte contains ions, which are charged. The positively charged ions are called cations, because they are attracted to the cathode, and the negatively charged ones are called anions, because they are attracted to the anode. We know that unlike charges attract and like charges repel. Cations, being positively charged, get attracted to the negatively charged cathode and move towards it. Anions, being negatively charged, get attracted to the positively charged anode and move towards it. This explains how ions move in an electrolytic cell, and thus ‘conduct’ an electric current.

What is the Process of Electrolysis 1

A chemical reaction takes place at the anode and the cathode. This can be observed as formation of bubbles (due to production of gases) or deposition of metal on the electrodes or as a change in the colour of the electrolyte. The reaction varies depending on the metals used for the electrodes and the electrolyte chosen. Electrolysis of a solution of sodium chloride (NaCl) produces hydrogen gas (H2), chlorine gas (Cl2), and sodium hydroxide (NaOFI).

What is the Process of Electrolysis 2

Activity

Aim: To show that gases are produced when electric current is passed through a solution of common salt.
Materials needed: A 9-volt cell, two electrical wires (about 10 cm each), a beaker/glass tumbler (if a glass tumbler is used it should be discarded after the experiment), insulation tape, a blade, tap water, and table salt.
Method:
1. Take the two wires and remove the jacket from each end using a blade.
2. Connect one end each of the two wires to the positive and negative terminals of the cell.
3. Fill the tumbler with tap water and dissolve common salt in it.
4. Dip the two free ends of the wires into the water, taking care that they do not touch each other.
Observation: You will observe tiny bubbles at the wire connected to the negative terminal (cathode) of the cell. These bubbles are formed due the formation of hydrogen gas. Chlorine gas is produced at the wire connected to the positive terminal (anode), but the reaction is much slower and cannot be observed easily. To test that the bubbles are indeed formed on passing electric current through the solution, remove the anode wire from the salt solution. You will observe that no bubbles are now formed at the cathode. Dip the wire back into the solution and the bubbling will start again.
Conclusion: Gases are produced when electric current is passed through a solution of common salt.

Note: Adult supervision required.

New Simplified Chemistry Class 10 ICSE Solutions – Electrolysis

New Simplified Chemistry Class 10 ICSE Solutions – Electrolysis

ICSE SolutionsSelina ICSE SolutionsML Aggarwal Solutions

Viraf J Dalal Chemistry Class 10 Solutions and Answers

Simplified ChemistryEnglishMathsPhysicsChemistryBiology

QUESTIONS

2004

Question 1.
Write two applications of electrolysis in which the anode diminishes in mass.
Answer:

  1. Used in electroplating.
  2. Purification of metals.

Question 2.
If the compound formed between X (a metal with a valency 2) and Y (a non-metal with a valency 3) is melted and an electric current passed through the molten compound, the element X will be obtained at the……….. and Y at the……… of the electrolytic cell. (Provide the missing words.)
Answer:
Cathode, Anode.

Question 3.
What kind of particles will be found in a liquid compound which is a non-electrolyte.
Answer:
Only molecules.

Question 4.
If HX is a weak acid, what particles will be present in its dilute solution apart from those of water.
Answer:
Non-ionized molecules, H+ and X”.

Question 5.
What ions must be present in a solution used for electroplating a particular metal.
Answer:
Cations of that particular metal to be deposited.

Question 6.
Explain how electrolysis is an example of redox reaction.
Answer:
Redox Reaction: “A chemical reaction in which loss of electrons and the gain of electrons takes place simultaneously is called REDOX reaction.”
Example: Electrolysis of Potassium chloride
2K – 2e1-→ 2K+
Cl2 + 2e1-→  2Cl-
2K + Cl2→ 2K+Cl or 2KCl

The potassium atoms lose one electron each from their valence shells to form potassium ions. As loss of electrons takes place therefore, potassium metal is oxidised to Potassium ions [K+].
Chlorine atoms gain one electron each in their valence shells to form chloride ions. As gain of electrons take place, therefore, chlorine atoms are reduced to chloride ions (Cl ). Since reduction and oxidation takes place simultaneously, therefore, electrolysis is a Redox reaction.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 1

2005

Question 1.
Explain why copper, though a good conductor of electricity, is a non-electrolyte.
Answer:
Copper metal – is a good conductor of electricity – but is a non-electrolyte, since-
It does not undergo chemical decomposition due to flow of electric current through it.

Question 2.
Name the gas released at the cathode when acidulated water is electrolysed.
Answer:
Hydrogen gas.

Question 3.
Explain why solid sodium chloride does not allow electricity to pass through.
Answer:
Sodium chloride (an ionic solid) does not conduct electricity in its solid state. It is because the anions (chloride – Cl ) and cations (sodium -Na+), remain in fact occupying fixed position in the crystal lattice due to strong electrostatic attractive forces among them. The ions, therefore are unable to move to any large extent when electric field is affected. Hence no current.

Question 4.
Fill in the blanks:

  1. As we descend the electro chemical series containing cations, the tendency of the cations to get  reduced at the cathode increases.
  2. The higher the concentration of an ion in a solution, the greater is the probability of its being discharged at its appropriate electrode.

Question 5.
State the term used for:
A liquid or solution, which conducts electricity with accompanying chemical change.
Answer:
Electrolyte.

Question 6.
Electrons are getting added to an element Y. Which electrode will Y migrate to during electrolysis.
Answer:
Cathode.

2006

Question 1.
Select from the list: —Ammonia, Copper oxide, Copper sulphate, Hydrogen chloride, Hydrogen sulphide, Lead bromide.

  1. A solution of this compound is used as the electrolyte when copper is purified.
  2. When this compound is electrolysed in the molten state, lead is obtained at the cathode.

Answer:

  1. Copper sulphate
  2. Lead Bromide.

Question 2.
State what is observed when copper sulphate solution is electrolysed using a platinum anode.
Answer:
Blue colour of the solution disappears.

Question 3.
An electrode ‘A’ is connected to the positive terminal of a battery and electrode ‘B’ to the negative terminal.

  1. Give the names of the electrodes A and B.
  2. Which electrode is the oxidizing electrode.

Answer:

  1. Anode, Cathode
  2.  Anode.

Question 4.
Write the equations at the cathode and anode when acidified water is electrolysed.
Answer:
Reaction at Cathode –
4H1+ + 4e → H x 4                          
2H + 2H → 2H2
Reaction at Anode:
40H1- + 4e → OH x 4
4OH → 2H2O + O2

Question 5.
A soln. of AgNOis a good electrolyte but it is not used for electroplating an article with silver. Why.
Answer:
Migration of Ag1+ ion from the complex salt solution silver cyanide is slow as compared to silver nitrate. That is why silver nitrate solution is not used.

2007

Question 1.
From — A: non-electrolyte, B: strong electrolyte, C: weak electrolyte, D: metallic conductor — Match:

  1. Molten ionic compound
  2. CCl4
  3. An aluminium wire
  4. A soln. containing solvent molecules, solute molecules and ions formed by the dissociation of solute molecules.
  5. A sugar soln. with sugar molecules and water molecules.

Answer:
Description

  1. (B) Strong electrolyte.
  2. (A) Non-electrolyte.
  3. (D) Metallic conductor
  4. (C) Weak electrolyte
  5. (A) Non-electrolyte

2008

Question 1.
During the electrolysis of molten lead bromide, which of the following takes place ?
A.  Bromine is released at the cathode
B.  Lead is deposited at the anode
C.  Bromine ions gain electrons
D.  Lead is deposited at the cathode

Question 2(1).
Here is an electrode reaction:
Cu → Cu2+ + 2e. [i.e. Cu – 2e → Cu2+]
At which electrode (anode or cathode) would such a reaction take place ? Is this an example of oxidation or reduction ?
Answer:
Cu → Cu2+ + 2e
This reaction takes place at anode.
This is an example of oxidation

Question 2(2).
A soln. contains Mg2+ ions, Fe2+ ions and Cu2+ ions. On passing an electric current through this soln. which ions will be the first to be discharged at the cathode ? Write the equation for the cathode reaction/
Answer:
Cu2+ (Copper ions will get discharged at cathode)

2009

Question 1.
State which from A to E fits the description —‘A pink metal is deposited at the cathode during the electrolysis of the soln. of this salt.
(A) Sulphur
(B) Silver chloride
(C) Hydrogen chloride
(D) Copper [II] sulphate
(E) Graphite.

Question 2.
Select the correct answer — The aqueous solution of the compounds which contains both ions and molecules is:
(A) Sulphuric acid
(B) Hydrochloric acid
(C) Nitric acid
(D) Acetic acid

Question 3.
Correct the following statements conducts electricity.
Answer:
Molten lead bromide conducts electricity.

Question 4.
A metal article is to be electroplated with silver. The electrolyte selected is sodium argentocyanide.

  1. What kind of salt is sodium argentocyanide.
  2. Why is it preferred to silver nitrate as an electrolyte?
  3. State one condition to ensure that the deposit is smooth, firm and long lasting.
  4. Write the reaction taking place at the cathode.
  5. Write the reaction taking place at the anode.

Answer:

  1. It is a complex salt.
  2. Silver nitrate is not used as an electrolyte since deposition of silver is rapid and the coating is not uniform. Hence sodium argentocyanide is used.
  3. A direct current of smaller magnitude should be applied for a longer time.
    Dissociation reaction:
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 2
    Both Na+ and Ag+ will migrate towards cathode but Ag+ ions will be discharged.
  4. Reaction at cathode
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 3
  5. Reaction at anode
    The silver atoms from the anode lose electrons and other into the solution as silver ions
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 4

Question 5.
Aqueous solution of Nickel sulphate contains Ni2+ and SO42+ ions

    1. Which ions moves towards the cathode ?
    2. What is the product at the anode ?

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 5

  1. Nickel ions moves towards the cathode
  2. Reaction At anode: (with nickel electrodes)
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 6

Hence nickel dissolves from the anode by forming nickel ions.
(if electrodes used of platinum).

Then being an aqueous solution hydrolysis of water will also take place
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 7
At Anode:  4OH – 4e → 4OH
4OH → 2H2O + O2 ↑
Hence oxygen gas will be released if electrodes used are of platinum.

2010

Question 1.
Select the correct answer — A compound which liberates reddish brown gas around the anode during electrolysis in its molten state is :
(A) Sodium chloride
(B) Copper (II) oxide
(C) Copper (II) sulphate
(D) Lead (II) bromide

Question 2.
During electroplating of an article with nickel –
(1) Name

  1. The electrolyte
  2. The cathode

(2) Give the reaction of the electrolysis at

  1. The cathode .
  2. The anode

Answer:
(1)
(a) Nickel sulphate
(b) Article
(c) Pure nickel plate / rod
(2)
(a) At Cathode: Ni2+ + 2e→ Ni(s)
(b) At Anode: Ni(s) – 2e→ Ni2+

Question 3.
A, B and C are three electrolytic cells, connected in different circuits. Cell ‘A’ contains NaCl soln., and the bulb in the circuit glows brightly, when the circuit is completed. Cell ‘B’ contains acetic acid and the bulb glows dimly. Cell ‘C’ contains sugar soln., and the bulb not glow. Give reasons for each observation.
Answer:
Electrolytic cell A has completely ionised sodium chloride solution. Thus, the ions can easily migrate to oppositely charged poles and hence bulb glows brightly. To conclude sodium chloride solution is a strong electrolyte.
Electrolytic cell B has a weak electrolyte as only 5% of the acetic acid molecules ionise. Thus, a weak current flows through it and hence the bulb glows dimly.
Electrolytic cell C has a non-electrolyte. Sugar molecules do not ionise and hence no current flows through. Thus, the bulb does not glow.

2011

Question 1.
Give reasons – The electrolysis of acidulated water is considered to be an example of catalysis.
Answer:
The amount of acid in the water does not change. Furthermore, it does not take part in electrochemical reaction, but makes the water a good conductor of electricity.

Question 2.
During electrolysis of CuSO4 using platinum [cathode] and carbon [anode]:

  1. State what you observe at the cathode and anode.
  2. State the change noticed in the electrolyte
  3. Write the reactions at the cathode and anode.

Answer:

  1. Cathode: Reddish brown deposition of copper occurs at cathode.
    Anode: Colourless gas is evolved at anode.
  2. On prolonged electrolysis, the blue electrolyte turns colourless.                                          .
  3. Cathode: Cu2+ + 2e → Cu
    Anode: OH— le → OH
    4OH → 2H2O + O2

Question 3.
Differentiate between electrical conductivity of – copper sulphate solution and of copper metal.
Answer:

Electrical conductivity of copper sulphate solutions Electrical conductivity of copper metal
1. Flow of electricity takes place the molten or dissolved state.

2. Flow of electricity is due to the movement of ions.

3. There is chemical decompos­ition of the copper sulphate sol.

4. The electrical conductivity increases with the increase in temperature.

1. Flow of in electricity place in the solid state.

2. Flow of electricity is due to the movement of electrons.

3. There is no chemical decomposition.

4. The electrical conductivity with increase in temperature, decreases

2012


Question 1.
Rewrite the correct statement with the missing word/s: Cations migrate during electrolysis.
Answer:
Cation migrates to cathode during electrolysis.

Question 2.
Identify the weak electrolyte from the following:
(A) Sodium Chloride solution
(B) Dilute Hydrochloric acid
(C) Dilute Sulphuric acid
(D) Aqueous acetic acid.

Question 3.
Match the following in column A with the correct answer from the choices given in column B.
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 8
Answer:
                 Column A                                             Column B
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 9

Question 4.
Give reasons: An aqueous solution of sodium chloride conducts electricity.
Answer:
Aqueous solution of sodium chloride contains very large number of sodium ions (Na+) and chloride ions (Cl ). On the passage of electric current these ions migrate to the oppositely charged electric poles and the conduction of electricity takes place.

Question 5.
Select the correct answer from the list in brackets:

  1. An aqueous electrolyte consists of the ions .mentioned in the list, the ion which could be
    discharged most readily during electrolysis. [Fe2+, Cu2+, Pb2+, H+].
  2. The metallic electrode which does not take part in an electrolytic reaction. [Cu, Ag, Pt, Ni].
  3. The ion which is discharged at the anode during the electrolysis of copper sulphate solutions using copper electrodes as anode and cathode. [Cu2+, OH, SO42--, H+].
  4. When dilute sodium chloride is electrolysed using graphite electrodes, the cation is discharged at the cathode most readily. [Na+, OH, H+, Cl].
  5. During silver plating of an article using potassium argentocyanide as an electrolyte, the anode material should be [Cu, Ag, Pt, Fe].

Answer:
(1) Cu2+ (2) Pt (3) Cu2+ (4) H1+ (5) Ag

2013

Question 1.
State one appropriate observation for : Electricity is passed through molten lead bromide.
Answer:
The molten lead bromide breaks into lead metal which dis­charges at cathode and bromine gas which discharged at an­ode.

Question 2.
State which of these will act as non-electrolyte ?
(A) Liquid carbon tetrachloride
(B) Acetic acid
(C) Sodium hydroxide aqueous solution acid.
(D) Potassium chloride aqu. solution.
Answer:
(A) Liquid carbon tetrachloride is non-electrolyte

Question 3.
Copper sulphate soln. is electrolysed using copper elec­trodes as seen in diagram
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 10

  1. Which electrode to your left or right is known as the oxidising electrode and why?
    Ans. The electrode on left hand side donates electrons and hence is oxidising electrode.
  2. Write the equation representing the reaction that oc­curs.
    Ans. Cu – 2e→ Cu2+
  3. State two appropriate observations for the above elec­trolysis reaction.
    Ans. The size of anode gradually decreases and that of cathode gradually increases. However, there is no change in the colour of copper sulphate solution.
  4. Name: A gas which in the liquid state does not conduct electricity but conducts when dissolved in water.
    Ans. Hydrogen chloride gas.

2014

Question 1.
The observation seen when fused lead bromide is electrolysed is:
A: a silver grey deposit at anode and a reddish brown deposit at cathode.
B: a silver grey deposit at cathode and a reddish brown deposit at anode.
C: a silver grey deposit at cathode and reddish brown fumes at anode.
D: silver grey fumes at anode and reddish brown fumes at cathode

Question 2.
During electroplating an article with silver, the electrolyte used is: 
A: silver ifitrate solution
B: silver cyanide solution
C: sodium argentocyanide solution
D: nickel sulphate solution

Question 3.
Give one word or phrase for: Electrolytic deposition of a superior metal on a baser metal.
Answer:
Electrolytic deposition of a superior metal on a baser metal→ Electroplating.

Question 4.
State your observation:
At the cathode when acidified aq. CuSO4 spin. is electrolyzed with copper electrodes.
Answer:
Pure copper will deposit at cathode.

Question 5.
State which electrode: anode or cathode is the oxidising electrode. Give a reason for the same.
Answer:
Anode is the oxidising electrode.

Question 6.
Name the kind of particles present in:

  1. Sodium Hydroxide soln.
  2. Carbonic acid.
  3. Sugar sol.n.

Answer:

  1. Particles present in sodium hydroxide a strong alkali solution:
    Sodium (Na+) ions and hydroxide (OH ) ions.
  2. Particles present in carbonic acid (a weak acid) solution:
    Ions (H+, HCO3, CO32- ) and molecules (H2CO3)
  3. Particles present in sugar (a non-electrolyte) solution:
    Molecules of sugar (C12 H22O11)

Question 7.
M2O is the oxide of a metal ‘M’ which is the above hydrogen in the activity series. M2O when dissolved in water forms the corresponding hydroxide which-is a good conductor of electricity.

  1. State the reaction taking place at the cathode.
  2. Name the product at the anode.

Answer:

  1. Reaction of cathode: M+ + e → M
  2. Product at anode: O2 + O2-→ O2 (Oxygen)

2015

Question 1.
State one observation for. ‘At the Anode when aqueous copper sulphate solution is electrolysed using copper electrodes’.
Answer:
Blue Cu2+ ions formed.

Question 2.
Give scientific reasons:

  1. During electrolysis of molten lead bromide graphite anode is preferred to other electrodes.
  2. Electrical conductivity of acetic acid is less in comparison to the of dil. H2SO4 – at a given concentration
  3. Electrolysis is of molten lead bromide is considered to be a redox reaction.

Answer:

  1. During the electrolysis of molten lead bromide, a graphite anode is preferred because graphite remains unaffected by the reactive bromine vapours which are released at the anode.
  2. Sulphuric acid is a strong acid compared to acetic acid. A strong acid has more ions than a weak one, and so, its solution will be a better electrical conductor than a weak acid. So, electrical conductivity of acetic acid is less in comparison of electric conductivity of sulphuric acid.
  3. In the electrolysis of molten lead bromide, the following reactions take place:
    At the cathode: Pb2+ (l) + 2e → Pb(l)
    At the anode: 2Br (l) → Br2 (g) + 2e
    Lead (II) ions (Pb2+) are attracted to the negative electrode, and the Pb2+ ions are forced to accept two electrons. Pb2+ ions are reduced. Bromide ions (Br ) are attracted to the positive electrode and the bromide ions are forced to give away their extra electron to form bromine atoms. Thus, bromide ions are oxidised. So, electrolysis of molten lead bromide is a redox reaction.

Question 3.
Differentiate between the terms strong electrolyte and weak electrolyte, (stating any two differences)
Answer:

Strong Electrolytes

Weak Electrolytes

(1)  Electrolytes which allow a large amount of electricity to flow through them.

(2) The solution of a strong electrolyte contains only free mobile ions.

(1)  Electrolytes which allow a small amount of electricity to flow through them.

(2)  The solution of a weak electrolyte contains ions and molecules.

Question 4.
During purification of copper – State:

  1. The anode used
  2. The electrolyte used.

Write the equation taking place at the anode in the above.
Answer:
(1)
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 34
(2) Equation at the anode:
Cu – 2e → Cu2+ (Anode)

2016

Question 1.
The particles present in strong electrolytes are:
Select the correct answer from A, B, C and D:
A: only molecules
B: mainly ions
C: ions and molecules
D: only atoms

Question 2.
Write equations for the reactions taking place at the two electrodes during the electrolysis of:

  1. Acidified CuSO4 with copper electrodes.
  2. Molten PbBr2 with inert electrodes. (mention clearly the name of the electrode in each case)

Answer:
(1) Dissociation reaction:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 11
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 12
At cathode (negative terminal of battery)
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 13
At anode (positive terminal of battery)
Cu → Cu2++2e

(2) Dissociation reaction:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 14

At cathode (negative terminal of battery)
Pb2+ + 2e → Pb
Lead metal is obtained in molten state At anode (positive terminal of battery)
Br – e → Br
Br + Br → Br2
Reddish brown vapours of bromine are formed

Question 3.
Name:

  1. the product formed at the anode – during electrolysis of acidified water using platinum electrodes.
  2. the metallic ions that should be present – in the electrolyte when an article made of copper is to be electroplated with silver.

Answer:

  1. Oxygen
  2. Silver ions

Question 4.
Give reasons why:

  1. Sodium Chloride will conduct electricity only in fused or aq. soln. state.
  2. In the electroplating of an article with silver, the electrolyte sodium argentocyanide soln. is preferred over silver nitrate solution.
  3. Although copper is a good conductor of electricity,it is a non-electrolyte.                                  ‘

Answer:

  1. Sodium chloride is a solid, ionic compound, it has strong electrostatic forces of attraction. Only in the fused or aqueous solution, it forms ions which are capable of conducting electricity.
  2. It is preferred over silver nitrate because the dissociation of AgN03 will be very fast and deposit will not be smooth and uniform.
  3. Because it does not form ions.

2017

Question 1.
Identify the substance underlined, in each of the following-

  1. The elctrolvte used for electroplating an article with silver.
  2. The particles present in a liquid such as kerosene, that is a non-electrolyte.

Answer:

  1. Sodium argentocyanide or Potassium argentocyanide solution.
  2. Molecules

Question 2.
State the observations at the anode & at the cathode during the electrolysis of –

  1. Fused lead bromide using graphite electrodes.
  2. Copper sulphate solution using copper electrodes.

Answer:

  1. At cathode silvery droplets of molten lead appear.
    At anode reddish vapours of bromine are given out.
  2. Brown metal copper is deposited at cathode.
    Cu2+ ion is liberated at anode.
    Colour of CuSO4 solution (blue colour) does not fade.

Question 3.
Select the ion in each case, that would get selectively discharged from the aqueous mixture of the ions listed below:
(1) S042-, NO3 and OH ;
(2) Pb2-, Ag+ and Cu2+.
Answer:

  1. OH ion will get discharged in preference to SO42- or NO3 ions.
  2. Ag+ ions will get discharged in preference to Pb2+ or Cu2+ ions.

ADDITIONAL QUESTIONS

Question 1.
Define:

  1. Electrolysis
  2. Electrodes
  3. Ions
  4. Electrolytic dissociation.

Answer:
(1) Electrolysis: “The process of decomposition of a chemical compound in aqueous solution or in molten state accompanied by chemical change.”
(2) Electrodes: Electrodes allow the electric current to enter or leave the electrolyte solution.
(3) Ions: They are atoms which carry a positive or negative charge and become free and mobile when an electric current is passed through an aqueous solution of a chemical compound.
(4) Electrolytic dissociation: The process due to which an ionic compound in the fused or in aqueous solution dissociates into ions by passage of electric current through it is called electrolytic dissociation.

Question 2.
Differentiate between

  1. Electrolytes and Non-electrolytes
  2. Strong and Weak electrolytes
  3. Anode and Cathode
  4. Electrolytic dissociation and Ionisation with suitable examples.

Answer:

Question 2(1).
Electrolytes and Non-electrolytes

Electrolytes:

Chemical compound – which conduct electricity in the fused or in aq. solution state and -undergo chemical decomposition due to the flow of current through it.
Electrolytes – are ionic compounds
Particles in Electrolytes – ions only or Ions and molecules only
Examples:
Acids – dil. HCl, HNO2 H2SO4 Alkalis – KOH, NaOH solutions Ionic salts – PbBr2 [molten],
CuSO4 [aq.]

Non-electrolytes:

Chemical compound – which do not conduct electricity in the fused or aq. soln. state and – do not undergo chemical decom­position due to the flow of current through it.
Non-electrolytes – are covalent compounds
Particles in non-electrolytes – Molecules only
Example:
Pure or distilled water, Alcohol, Kerosene, Carbon disulphide, carbon tetrachloride, sucrose, glucose, sugar solution.

Question 2(2).
Strong and Weak electrolytes:

Strong electrolytes:

  1. The compounds which in their aqueous solution or in fused state are almost completely ionised are called strong electrolytes.
  2. They allow a large amount of electricity to flow through them and hence are good conductors of electricity.
  3. In aqueous solution or molten state, only ions are present.
    Examples:
    Strong acids:
    HCl, H2SO4,HNO3
    Strong bases: NaOH, KOH
    Salts: NaCl, NaNO3, K2S04

Weak electrolytes:

  1. The compound which in their aqueous solution or in fused state are partially ionised are called weak electrolytes.
  2. They allow small amount of electricity to flow through them and hence are poor conductors of electricity.The compound which in their aqueous solution or in fused state are partially ionised are called weak electrolytes.
    In aqueous solution or molten state ions as well as unionised molecules are present.
    Examples:
    Weak acids: CH3COOH, H2CO3
    Weak bases: NH4OH, Ca(OH)2
    Salts: CH3COONH4

Question 2(3).
Anode and Cathode:

Anode:

  1. It is the electrode connected to the positive terminal of the battery
  2. Anions migrate to anode.
  3. The anions donate excess electrons to the anode and they are oxidised to neutral atoms.

Cathode:

  1. It is the electrode connected to the negative terminal of the battery.
  2. Cations migrate to cathode.
  3. The cations gain excess electrons from the cathode and they are reduced to neutral atoms.

Question 2(4).
Electrolytic dissociation and ionisation with suitable examples.

Dissociation:

  1. Separation of ions which are already present in an ionic compounds.
  2. Electrovalent compounds show dissociation e.g. potassium chloride, lead bromide.
    KCl → K+ + Cl

Ionisation

  1. Formation of positively or negatively charged ions from molecules which are not intially in the ionic state.
  2. Polar covalent compounds show ionisation.
    e.g. HCl, H4CO3 , NH4OH
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 15

Question 3.
Compare the flow of electricity through a nickel wire and nickel sulphate solution.
Answer:
Flow of electricity through nickel wire

  1. It is due to the flow of electrons.
  2. It is a physical change.
  3. It can take place in solid state.
  4. Electrical conductivity is more.

low of electricity through nickel sulphate solution

  1. It is due to the flow of ions.
  2. It is a chemical change.
  3. It cannot take place in solid state.
  4. Electrical conductivity is less.

Question 4.
Name three organic compounds and one neutral liquid which are non-electrolytes.
Answer:
Organic compounds which are non-electrolyte:
Sugar, glucose, naphthalene
Neutral liquid which are non-electrolytes:
Carbon tetrachloride, carbon disulphide

Question 5.
State which of the following solutions are weak electrolytes – dil. HCI ; carbonic acid ; NH4OH ; dil. H2SO4 ; AgNO3 ; Na2CO3 ; PbBr2 ; KOH ; HI ; oxalic acid, NaHCO3 ; sodium acetate ; Na2SO4 ; NaOH.
Answer:
Weak Electrolytes: Carbonic acid, NH4OH, Na2CO3 oxalic acid.

Question 6.
State which of the following solutions contain (1) molecules only (2) ions only (3) both molecules and ions – CS2 ; CH3COOH ; NH4OH ; NaOH ; dil. HNO3 ; Na2CO3 ; CuCl2 ; oxalic acid ; pure H2O,
kerosene ; HI.
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 16

Question 7.
State giving reasons, in which state or medium does
(1) NaCl, (2) HCI gas (3) NH3 gas conduct electricity.
Answer:

  1. NaCl will conduct electricity only molten state or when dissolved in water. This is because the Na+ and Cl ions present in solid NaCl are too big to move under the influence of applied electric field.
  2. HCI gas is a polar covalent compound when dissolved in water, it will ionise to give H+ and CP ions. Under the influence of applied electric field these ions can easily move in an aqueous solution and thus conduct electricity.
    Thus HCI (g) when dissolved in water conducts electricity.
  3. NH3(g) will dissolved in water to give NH4OH.
    NH3(g) + H2O (l) → NH4OH (aq)
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 17
    NH4OH will ionise to give NH4+ and OH ions. Under the influence of applied electric field these ions can migrate in an aqueous solution and hence conduct electricity. Thus NH3 (g) when dissolved in water conduct electricity.

Question 8.
State on what basis are acids, bases and salts classified as strong and weak electrolytes.
Answer:
Strong electrolytes – Compound which in the fused or in the aqueous solution state are almost completely dissociated and are good conductors of electricity are called.

Weak Electrolytes – Compound which in the fused or in the aqueous solution state are feebly or partially dissociated and are poor conductors of electricity are called – weak electrolytes.

Question 9.
Explain the terms 

  1. metal activity or electro chemical series
  2. selective discharge of ions.

Answer:

  1. Depending on the ease with the metals lose their electrons and form ions – they are arranged in a series known as – metal activity series or electro chemical series.
    The arrangement is so done that the elements that – ionize most readily [discharged with great difficulty]- are placed at the top of the series and other elements in the descending order.
  2. Selective discharge of ions: The preferential discharge of ions present in an electrolyte at the respective electrodes is known as selective discharge of ions.

It depends upon the following factors:

  • Relative position of the ion in the electo chemical series: Lower the position of the ion in the series, easier to discharge.
  • Concentration of the ion: More the concentration of the ion, easier to discharge.
  • Nature of the electrode: Inert electrodes (graphite, platinum) do not take part in the electrolytic reaction.
    Active electrodes (Cu electrodes for electrolysis of aq. CuSO4, Ag electrodes for electrolysis of aq. AgNO3 etc.) take part in electrolytic reactions.

Question 10.
From the ions –

  1. SO42- and OH1-
  2. Cu2+ and H1+
  3. Ag1+ and H1+ state giving reasons which ion is discharged at the respective electrode in each case.

Answer:

  1. Out of SO42- and OH ions, OH ions will be discharged at anode forming O2 gas.
  2. Out of Cu2+ and H+, Cu2+ ions will be discharged because Cu is lower in the electro chemical series than H.
  3. Out of Ag+ and H+, Ag+ will be discharged because Ag is lower in the electro chemical
    series than H.

Question 11.
With reference to nature of electrodes — name three inert and three active electrodes.
Answer:
Inert electrodes

  • Platinum
  • Iron
  • Graphite

Active electrodes

  • Copper
  • Nickel
  • Silver

Question 12.
State the reason for difference in product formed at the anode during electrolysis of aq. CuSO4 using

  1. active electrode – copper anode
  2. inert electrode – platinum anode.

Answer:

  1. Electrolysis of aq. CuS04 using copper anode:
    As copper can easily lose electron, copper from anode will dissolve as Cu2+ ions.
    Cu (s) – 2e→ Cu2+ (aq)
  2. Electrolysis of aq. CuS04 using inert platinum anode: Due to very low tendency of platinum to lose electron platinum anode does not take part in electrolytic reaction. Further tendency of SO42- to lose electron is much less than that of OH(from feebly ionised water). Thus OH ions get oxidised in preference to SO42- ions to  give O2
    4OH – 4e → 4OH
    40H→ 2H2O + O2↑

Question 13.
Give the electrode reactions for formation of

  1. Lead metal and bromine vapours from molten PbBr2 using inert electrodes
  2. H2 and O2 gas (2:1) from acidified water using inert Pt electrodes.

Answer:

  1. Electrolysis of molten PbBr2 using inert electrodes.
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 18
    At cathode: Pb2+ (l) + 2e →Pb (s)
    At anode: 2Br (l) – 2e→ 2Br
    Br + Br→ Br2 (g)
  2. Electrolysis of acidified water using Pt electrodes.
    At cathode:
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 19
    4H+ (aq) + 4e → 4H
    2H + 2H→ 2H2
    At anode:
    4OH+ (aq) – 4e → 4OH
    4OH→ 2H2O (l) + O2 (g)

Question 14.
Starting from aq. copper (II) sulphate solution, give equations for the reactions at the cathode and anode during electrolysis of aq. CuSO4 using active copper electrodes.
Answer:
Electrode reaction:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 20
Reaction at Cathode:
Cu2+ + 2e → Cu
Cu2+ and H1+ ions migrate to the cathode.
Reaction at anode: Cu – 2e → Cu2+
S042- and OH1- ions migrate to anode but not discharged.

Question 15.
Give reasons for the following changes –

(1) pure water a non-electrolyte – becomes an electrolyte on addition of dil. H2SO4
(2) Blue colour of aq. CuSO4 – turns almost colourless on its electrolysis using Pt electrodes.
Answer:

  1. Pure water is a non electrolyte. It consists of entirely of molecules. It can be electrically decomposed by Addition of traces of dil. Sulphuric acid. Which dissociates into H1+ and sulphate (S042-) ions.
  2. If platinum anode is used the blue colour of CuS04 solution fades since the blue Cu2+ ions which are discharged at the cathode are not replaced or added at the anode.

Question 16.
‘Iron is electroplated with silver’ –

  1. define the term in italics
  2. state two reasons for electroplating
  3. state why the iron is not placed at the anode and silver at the cathode during electroplating.

Answer:

  1. Electroplating: The electrolytic process of deposition of a superior metal on the surface of a baser metal or article is called electroplating.
  2. Reasons for electroplating:

    • Prevents corrosion or rusting.
    • Makes the article attractive and gives it an expensive appearance.
  3. The article to be electroplated is always placed at the cathode because during electrolytic reaction the metal is always deposited at the cathode by gain of electrons.

Question 17.
Draw a diagram for –
(1) electroplating an article with silver;
(2) electrorefining or purification of copper.

Answer:
(1)
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 21
(2)
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 22

Question 18.
State the

  1. electrolyte
  2. cathode used
  3. anode used
  4. electrode reaction at cathode
  5. electrode reaction at anode
  6. product at cathode and anode – during
    (a) electroplating an article with nickel
    (b) electroplating a spoon with silver
    (c) purification of impure copper.

Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 23

Electrolytic reaction at cathode
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 24

Electrode reaction at anode
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 25
Products at cathode
(a) Ni (ions)
(b) Silver
(c) Copper
Products at anode
(a) SO42– and OH1--(ions)
(b) CN and OH1- (ions)
(c) SO42- and OH1- (ions)

Question 19.
Give a reason why metals –
copper, silver and lead are electrorefined but K, Na and Ca are not.
Answer:
Extraction of K, Na and Ca are done by electrolysis and are extracted in their fused state. Their oxides are highly stable and the metal has a strong affinity for oxygen. They do not decompose on thermal decomposition. .

Question 20.
Explain the term ‘electrometallurgy’. At what electrode is the extracted metal always deposited ?
Answer:
Electrometallurgy – is the process of extraction of metals by electrolysis. Metals comparatively higher in the electrochemical series are extracted by electrolysis. During this process, the extracted metal is always deposited on cathode.

Question 21.
State how activity series of metals plays a role in extraction of metals from oxides.
Answer:
In activity series, metals are placed in decreasing order of reactivity with most reactive metal at the top and least reactive metal at the bottom. Depending upon the reactivity of metals, different methods are used for their extraction from respective ores.
For example:

  1. Extraction by electrolysis: Metals at the top of the activity series are extracted from their ores by electrolysis. Being highly reactive, they cannot be reduced by common reducing agent (C, CO, H2) For example: K, Na, Ca, Mg,Al.
  2. Extraction by common reducing agents: Metals at the middle of the activity series, being less reactive, can be extracted from their ores by reduction with common reducing agents like C, CO, H2
    For example: Zn, Fe, Pb, Cu.
  3. Extraction by thermal decomposition: Metals near the bottom of the activity series, due to their very low reactivity, can be extracted from their ores, by heating only.
    For example: Hg, Ag.
  4. Metal at the bottom of the activity series exist in native state (Au, Pt).
  5. State the electrode reaction at the respective electrodes during extraction of Al from Al2 O3.

Question 22.
State the electrode reaction at the respective electrodes during extraction of Al from Al2 O3.
Answer:
At cathod:   2Al3+ + 6e–  → 2Al
At anode:    3O2- – 6e → 3|0|
3|0|+3|0|→3O2

UNIT TEST PAPER 5 – ELECTROLYSIS

Question 1.
Match the statements 1 to 5 with their answers selected from A to J.
A: Cathode, B: Sucrose soln., C: Cl”, D : Formic acid, E: Electro metallurgy, F: Ammonia, G: Mg2+, H: Electro refining, I: Sulphur dioxide, J: Anode.

  1. A compound containing molecules only.
    Ans. Sucrose soln.
  1. A compound which ionizes in soln. state but not in gaseous state.
    Ans. Ammonia
  1. The ion which accepts electrons from the cathode and gets reduced to neutral atoms.
    Ans. Mg2+
  1. The electrode to which the cyanide ions of aq. Na[(Ag(CN)2] migrate during electrolysis.
    Ans. Anode
  1. An application of electrolysis in which the anode does not generally diminish in size.
    Ans. Electro metallurgy.

Question 2.
Complete the table given below:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 26
Answer:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 27

Question 3.
Select the correct word from the words in bracket to complete the sentence:

  1. The electrode at which anions donate excess electrons and are oxidized to neutral atoms is the…………….. (anode / cathode).
    Ans. Anode
  1. On electrolysis, Ag1+ and H1+ ions migrate to the…………..(cathode / anode) and………… (Ag1+ / H,+) are discharged.
    Ans. Cathode ; AgI+
  1. Electrolysis is a / an………. (oxidation / reduction / redox) reaction in which reduction reaction takes place at the……………. (cathode / anode)
    Ans. redox, cathode
  1. According to Arrhenius’s theory the amount of electricity conducted by the electrolyte depends on the ………………… (nature / concentration) of the ions in solution.
    Ans. Concentration
  1. Salts ionize in aq. soln. on passage of electric current to give……….. (negative / positive) ions other than H+ ions.
    Ans. positive.

Question 4.
Give balanced equations for the electrode reactions involved in the following conversions at the respective electrodes:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 28
Answer:

  1. Electrolysis of molten Al203:
    202- – 4e→ 2 [O]
    [O] + [O]→ O2 (g)    (At Anode)
    Electrolysis of copper (II) sulphate
    4OH- (aq) + 4e→ 4 [OH]
    4 [OH] → 2H2O (l) + O2 (g)    (At Anode)
  2. Cu (s) – 2e→ Cu2+ (aq)   (At Anode)
    Cu2+ (aq) + 2e→ Cu (s)   (At Cathod)
  3. Electrolysis of molten PbCl2
    2Cl (l) – 2e→ 2 [Cl]
    2 [Cl] → Cl2(g) (At Anode)
    Electrolysis of HCl (aq)
    2Cl- (aq) – 2e → 2 [Cl]
    2 [Cl] → Cl2 (g)
  4. Electrolysis of acidified water
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 29
    4OH – 4e→ 4 [OH]
    4 [OH] → 2H20 (l) + O2 (g)  (At Anode)
  5. Electrolysis of molten KBr
    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 30
    2Br (l) – 2e→ 2 [Br]
    2[Br]→ Br2 (g) (At Anode)
    Electrolysis of molten PbBr2

    New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 31
    2Br (l) — 2e → 2 [Br]
    2 [Br] ) Br2 (g) (At anode)

Question 5.
Select the correct answer from the list in bracket:

  1. The cation discharged at the cathode most readily.[Fe2+, Cu2+, Pb2+, H1+]
    Ans. Cu2+
  2. The anion discharged at the anode with most difficulty.[SO2-4, Br1-, N03‘-OH1]
    Ans. OH1
  3. The metallic electrode which does not take part in an electrolytic reaction. [Cu, Ag, Fe, Ni]
    Ans. Fe
  4. The ion/s which is / are discharged during electrolysis of aq. CuSO4 using Cu electrode.
    [Cu2+, S042-, H1+, OH1-]
    Ans. Cu2+
  5. A covalent compound which in aqueous state conducts electricity.    [CCl4, CS2, NH3, C2H4]
    Ans. NH3

Question 6.
Give reasons for the following:

Question 1.
Electrolysis of molten lead bromide is considered a redox reaction.
Answer:
Electrolysis of molten PbBr2 takes place as follows:
New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 32
Pb2+ + 2e → Pb (at cathode)

New Simplified Chemistry Class 10 ICSE Solutions Chapter 5 Electrolysis 33
2 [Br]→ Br
Thus reduction takes place at cathode while oxidation takes place at anode. Therefore, electrolysis of molten PbBr2 is a redox reaction.

Question 2.
Lead bromide undergoes electrolytic dissociation in the molten state but is a non-electrolyte in the solid state.
Answer:
The ions present in PbBr2 in solid state are held by strong electrostatic forces of attraction and hence cannot move under the influence of applied electric field.

OR

In solid state only tiny electrons can move under the influence of applied electric field (e.g., in metals). Ions are too big to move in solid state.

Question 3.
The blue colour of aq. copper sulphate does not change when it is electrolysed using copper electrodes.
Answer:
For every copper ion (Cu2+) discharged at the cathode as neutral copper atom (Cu), a copper ion (Cu2+) is released or added to the solution at the anode and hence the total number of Cu2+ ions remains the same. Therefore the blue colour of CuSO does not fade in electrolytic reaction.

Question 4.
During electrolytic dissociation of sodium chloride, the sodium ions are discharged at the cathode.
Answer:
Sodium ions (Na+) being positively charged migrate to negative electrode, i.e., cathode. This is due to electrostatic forces of attraction between oppositely charged ions.

Question 5.
In the electrolysis of acidified water, dilute sulphuric acid is preferred to dilute nitric acid.
Answer:
Since nitric acid is a volatile acid, may decompose and nitrate radical (N03) may tend to interfere with the electrolytic reaction.

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