RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9C & 9D

RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9C & 9D

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9C & 9D

Other Exercises

• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9A
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9B
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9C & 9D
• RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9E
• Mean, Median, Mode of Grouped Dat

Exercise 9C

Question 1:
As the class 50 – 60 has maximum frequency, so it is the modal class:

Hence, mode = 53.33

More Resources

• RS Aggarwal Solutions Class 10
• RD Sharma Class 10 Solutions
• NCERT Solutions

Question 2:
As the class 40 – 50 as maximum frequency, so it s modal class.

Hence, mode = 43.75 years

Read  More:

• Classmark and Discrete Frequency Distribution
• Cumulative Frequency in statistics

Question 3:
As the class 26 – 30 has maximum frequency so it is modal class

Hence, mode = 28.5
Question 4:
As the class 1500 – 2000 has maximum frequency, so it os modal class

Hence the average expenditure done by maximum number of workers = Rs. 1820
Question 5:
As the class 5000 – 10000 has maximum frequency, so it is modal class

Hence, mode = Rs. 7727.27
Question 6:
As the class 15 – 20 has maximum frequency so it is modal class.

Hence mode = 17.3 years
Question 7:
As the class 85 – 95 has the maximum frequency it is modal class

Hence, mode = 85.71
Question 8:
The given series is converted from inclusive to exclusive form and on preparing the frequency table, we get

As the class 20.5 – 25.5 has maximum frequency, so it is modal class

Hence, mode = 23.28

Exercise 9D

Question 1:
Let assumed mean be 35, h = 10, now we have

(i) Mean
= 

(ii) N = 100, \(\frac { N }{ 2 }   \)= 50
Cumulative frequency just after 50 is 63
Median class is 30 – 40
l = 30, h = 10, N = 100, c = 33, f = 30

(iii) Mode = 3 × median – 2 × mean
= 3 × 35.67 – 2 × 35.6 = 107.01 – 71.2
= 35.81
Thus, Mean = 35.6, Median = 35.67 and Mode = 35.81
Question 2:
Let assumed mean A be 8.5. Class interval h = 3

N = total frequency = 100
(i) Mean
= 

(ii) \(\frac { N }{ 2 }   \)= 50, Cumulative frequency just after 50 is 76
Median class is 7 – 10
l = 7, h = 3, N = 100, f = 40, c = 36

(iii) Mode = 3 × Median – 2 × Mean
= 3 × 8.05 – 2 × 8.32 = 24.15 – 16.64
= 7.51
Thus, mean = 8.32, Median = 8.05, Mode = 7.51
Question 3:
Let the assumed mean A be 145. Class interval h = 10.

(i) Mean
= 
= 145 + 4.8 = 149.8
(ii) N = 50, \(\frac { N }{ 2 }   \)= 25
Cumulative frequency just after 25 is 42
Corresponding median class is 150 – 160
Cumulative frequency before median class, c = 22
Median class frequency f = 20

(iii) Mode = 3 × median – 2 × mean
= 3 × 151.5 – 2 × 149.8 = 454.5 – 299.6
= 154.9
Thus, Mean = 149.8, Median = 151.5, Mode = 154.9
Question 4:
Let assumed mean A = 150 and h = 20

(i) Mean


(ii) N = 50, \(\frac { N }{ 2 }   \)= 25
Cumulative frequency just after 25 is 26
Corresponding frequency median class is 120 – 140
So, l = 120, f = 14, h = 20, c = 12

(iii) Mode = 3 × Median – 2 × Mode
= 3 × 138.6 – 2 × 145.2
= 415.8 – 190.4
= 125.4
Hence, Mean = 145.2, Median = 138.6 and Mode = 125.4
Question 5:
Let assumed mean = 225 and h = 50

(i) Mean
= 
(ii) N = 30, \(\frac { N }{ 2 }   \)= 15
Cumulative frequency just after 15 is 25
corresponding class interval is 200 – 250
Median class is 200 – 250
Cumulative frequency c just before this class = 13
So I=200, f=12, \(\frac { N }{ 2 }   \)= 15, h=50, c=13

Hence, Mean = 205 and Median = 208.33

Hope given RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9C & 9D are helpful to complete your math homework.

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