Get the comprehensive Chapter 8 Ex 8.2 Class 10 Maths NCERT Solutions from here and score good marks in CBSE Class 10 Board Examinations

NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.2 are part of NCERT Solutions for Class 10 Maths. Here are we have given Chapter 8 **Introduction to Trigonometry Class 10 NCERT Solutions Ex 8.2.**

- Introduction to Trigonometry Class 10 Ex 8.1
- Introduction to Trigonometry Class 10 Ex 8.3
- Introduction to Trigonometry Class 10 Ex 8.4

Board | CBSE |

Textbook | NCERT |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 8 |

Chapter Name | Introduction to Trigonometry |

Exercise | Ex 8.2 |

Number of Questions Solved | 4 |

Category | NCERT Solutions |

## NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.2

NCERT Solutions for Class 10 Maths

Page No: 187

**Question 1.** Evaluate the following :

(i) sin 60° cos 30° + sin 30° cos 60°

(ii) 2 tan^{2}45° + cos^{2}30° – sin^{2}60°

(iii) \(\frac { cos45^{ 0 } }{ sec{ 30 }^{ 0 }+cosec{ 30 }^{ 0 } } \)

(iv) \(\frac { sin{ 30 }^{ 0 }+tan45^{ 0 }-cosec{ 60 }^{ 0 } }{ sec{ 30 }^{ 0 }+cosec{ 60^{ 0 } }+cot{ 45 }^{ 0 } } \)

(v) \(\frac { 5cos^{ 2 }{ 60 }^{ 0 }+4sec^{ 2 }{ 30 }^{ 0 }-tan^{ 2 }{ 45 }^{ 0 } }{ sin^{ 2 }{ 30 }^{ 0 }+cos^{ 2 }{ 30 }^{ 0 } } \)

**Solution: **

**Question 2.** Choose the correct option and justify your choice :

(i) \(\frac { 2tan{ 30 }^{ 0 } }{ 1+tan^{ 2 }{ 30 }^{ 0 } } =\)

(A) sin 60° (B) cos 60° (C) tan 60° (D) sin 30°

(ii) \(\frac { 1-tan{ ^{ 2 }45 }^{ 0 } }{ 1+tan{ ^{ 2 }45 }^{ 0 } } =\)

(A) tan 90° (B) 1 (C) sin 45° (D) 0

(iii) sin 2A = 2 sin A is true when A =

(A) 0° (B) 30° (C) 45° (D) 60°

(iv) \(\frac { 2tan{ 30 }^{ 0 } }{ 1-tan{ ^{ 2 }30 }^{ 0 } } =\)

(A) cos 60° (B) sin 60° (C) tan 60° (D) sin 30°

**Solution: **

**Question 3.** If tan (A + B) = √3 and tan (A – B) = 1/√3; 0° < A + B ≤ 90°; A > B, find A and B.

**Solution: **

**Question 4.** State whether the following are true or false. Justify your answer.

(i) sin (A + B) = sin A + sin B.

(ii) The value of sin θ increases as θ increases.

(iii) The value of cos θ increases as θ increases.

(iv) sin θ = cos θ for all values of θ.

(v) cot A is not defined for A = 0°.

**Solution: **

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