ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 3 Integers Objective Type Questions

ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 3 Integers Objective Type Questions

Mental Maths

Question 1.
Fill in the blanks:
(i) The absolute value of 0 is ………
(ii) The sum of two negative integers is always a ……….. integer.
(iii) The smallest positive integer is ……………
(iv) The largest negative integer is ………….
(v) 17 + ………….. = 0
(vi) ……………. -15 = -10
(vii) The predecessor of -99 is …………
Solution:
(i) The absolute value of 0 is 0.
(ii) The sum of two negative integers is always a negative integer.
(iii) The smallest positive integer is 1.
(iv) The largest negative integer is -1.
(v) 17 + -17 = 0
(vi) 5 – 15 = -10
(vii) The predecessor of -99 is -100.

Question 2.
State whether the following statements are true (T) or false (F):
(i) The sum of a positive integer and a negative integer is always a negative integer.
(ii) Zero is an integer.
(iii) The sum of an integer and its negative is always zero.
(iv) The sum of three integers can never be zero.
(v) |-7| < |-3|.
(vi) -20 is to the left of -21 on the number line.
(vii) The successor of -29 is -30.
(viii) 0 is greater than every negative integer.
(ix) The difference of two integers is always an integer.
(x) Additive inverse of a negative integer is always a positive integer.
Solution:
(i) The sum of a positive integer and a negative integer is always a negative integer. False
(ii) Zero is an integer. True
(iii) The sum of an integer and its negative is always zero. True
(iv) The sum of three integers can never be zero. False
(v) |-7| < |—3|. False
(vi) -20 is to the left of -21 on the number line. False
(vii) The successor of -29 is -30. False
(viii)0 is greater than every negative integer. True
(ix) The difference of two integers is always an integer. True
(x) Additive inverse of a negative integer is always a positive integer. True

Question 3.
State whether the following statements are true or false. If a statement is false, write the corresponding correct statement.
(i) -8 is to the right of-10 on the number line.
(ii) -100 is to the right of -50 on the number line.
(iii) Smallest negative integer is -1.
(iv) -26 is greater than -25.
(v) -187 is the predecessor of-188.
Solution:
(i) -8 is to the right of-10 on the number line. True
(ii) -100 is to the right of -50 on the number line. False
Correct:
-100 is to the left of-50 on the number line.
(iii) Smallest negative integer is -1. False
Correct :
Greatest negative integer is -1.
(iv) -26 is greater than -25. False
Correct:
-26 is smaller than -25.
(v) -187 is the predecessor of-188. False
Correct:
-187 is the successor of -188.

Multiple Choice Questions

Choose the correct answer from the given four options (4 to 17):
Question 4.
The integer which is 5 more than -2 is
(a) -7
(b) -3
(c) 3
(d) 7
Solution:
3 (c)
ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 3 Integers Objective Type Questions 1
Integer 3 is 5 more than -2

Question 5.
The number of integers between -1 and 1 is
(a) 0
(b) 1
(c) 2
(d) 3
Solution:
‘0’ lies between -1 and 1
∴ -1, 0, 1 = 1 number (b)

Question 6.
The number of integers between -3 and 2 are
(a) 2
(b) 3
(c) 4
(d) 5
Solution:
-2, -1,0, 1 lies between -3 and 2
-3, -2, -1, 0, 1,2 = 4 numbers (c)

Question 7.
The number of whole numbers between -6 and 6 is
(a) 11
(b) 10
(c) 6
(d) 5
Solution:
Number -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5 lies between -6 and 6.
Among them 0, 1, 2, 3, 4, 5 are whole numbers.
∴ 6 whole numbers lies between -6 and 6 (c)

Question 8.
The greatest integer lying -10 and -15 is
(a) -10
(b) -11
(c) -14
(d) -15
Solution:
-11 (b)

Question 9.
The smallest integer lying between -10 and -15 is
(a)-10
(b) -11
(c) -14
(d) -15
Solution:
-14 (c)

Question 10.
Which of the following statement is true?
(a) |10 – 4| = |10| + |—4|
(b) Additive inverse of -5 is 5
(c) -1 lies on the right of 0 on the number line
(d) -7 is greater than -3
Solution:
Additive inverse of -5 is 5 (b)

Question 11.
Which of the following statement is false?
(a) -20 – (-5) = -15
(b) |-18| > |-13|
(c) 23 + (-31) = 8
(d) Every negative integer is less than 5
Solution:
23 + (-31) = 8
The correct answer will be
23 + (-31) = -8 (c)

Question 12.
Which of the following statements is false?
(a) (-3) + (-11) is an integer
(b) (-19)+ 13 = 13 +(-19)
(c) (-15) + 0 = -15 = 0 + (-15)
(d) Negative of-7 does not exist
Solution:
Negative of -7 does not exist, is false statement.
Negative of -7 is – (-7) = 7 (d)

Question 13.
If the sum of two integers is -17 and one of them is -9, then the other is
(a) 8
(b) -8
(c) 26
(d) -26
Solution:
-17 – (9)
= -17 + 9 = -8 (b)

Question 14.
On subtracting -7 from -4, we get
(a) 3.
(b) -3
(c) -11
(d) none of these
Solution:
-4 – (-7)
= -4 + 7 = 3 (a)

Question 15.
(-12) + 17 – (-10) is equal to
(a) -5
(b) 5
(c) 15
(d) -15
Solution:
(-12) + 17 – (-10)
= -12 + 27 = 15 (c)

Question 16.
Which of the following statements is true?
(a) -13 > – 8 – (-6)
(b) -5 – 4 > -12 + 2
(c) (-8) – 3 = (-3) – (-8)
(d) (-15) – (-22) < (-22) – (-15)
Solution:
-5 – 4 > -12 + 2
= -9 > -10
∴ -9 is always greater than -10 (b)

Question 17.
The statement “when an integer is added to itself, the sum is less than the integer” is
(a) always true
(b) never true
(c) true only when the integer is negative
(d) true when the integer is zero or positive
Solution:
true only when the integer is negative (c)

Higher Order Thinking Skills (HOTS)

Question 1.
Can the sum of successor and predecessor of an integer be an odd integer?
Solution:
No, the sum of successor and predecessor of an integer cannot be an odd integer.

Question 2.
What is the sum of all integers from -500 to 500?
Solution:
The sum of all integers from -500 to 500 = -500 + 500 = 0

Question 3.
Find two positive integers such that their product is 1,00,000 and none of them contains 0 as a digit.
Solution:
We shall find the factors of 1,00,000 to find the two positive integers such that their product is 1,00,000.
ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 3 Integers Objective Type Questions 2
The factors of 100000 = 2 × 2 × 2 × 2 × 2 × 5 × 5 × 5 × 5 × 5
∴ The positive integers which have the product 100000 are
(i) 2 × 2 × 2 × 2 × 2 = 32
(ii) and 5 × 5 × 5 × 5 × 5 = 3125

ML Aggarwal Class 6 Solutions for ICSE Maths

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