ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 3 Integers Check Your Progress

ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 3 Integers Check Your Progress

Question 1.
Use the appropriate symbol < or > to fill in the following blanks:
(i) (-3 + ……… (-6) (-3) – (-6)
(ii) (-21) – (-10) ……. (-31)+ (-11)
(iii) 45 – (-11) ……….. (57) + (-4)
(iv) (-25) – (-42) …………. (-42) – (-25)
Solution:
(i) (-3 + (-6) < (-3) – (-6)
(ii) (-21) – (-10) > (-31) + (-11)
(iii) 45 – (-11) > (57) +(-4)
(iv) (-25 – (-42) > (-42) – (-25)

Question 2.
Find the value of:
(i) 12 + ( -3) + 5 – (-2)
(ii) 39 – 35 + 7-(-4) + 21
(iii) -15- (-2) – 71 – 8 + 6
Solution:
(i) 12 + (-3) + 5 – (-2)
= 12 – 3 + 5 + 2
= 9 + 7= 16

(ii) 39 – 35 + 7 – (-4) + 21
= 39 – 35 + 7 + 4 + 21
= 4 + 11 + 21
= 15 + 21 =36

(iii) -15 – (-2) – 71 – 8 + 6
= -15 + 2 – 71 – 8 + 6
= -13 – 79 + 6
= 92 + 6 = -86

Question 3.
Evaluate:
(i) |-13| – |-15|
(ii) |35 – 41| – |7-(-2)|
Solution:
(i) |-13| – |-15|
= +13 – 15 =-2

(ii) |35 – 41| – |7 – (-2)|
= 6 – 9 = -3

Question 4.
Arrange the following integers in ascending order:
-39, 35, -102, 0, -51, -5, -6, 7
Solution:
-102, -51, -39, -6, -5, 0, 7, 35

Question 5.
Find the successor and the predecessor of -199.
Solution:
Successor = -199 – 1 = -198
Predecessor = -199 – 1 = -200

Question 6.
Subtract the sum of -235 and 137 from -152.
Solution:
Sum of (-235 and 137)
= -235 + 137
= 137 – 235 = -98
Now, subtract the sum of (-235 and 137) from -152
= 152 – (-98)
= -152 + 98 = -54

Question 7.
What must be added to -176 to get -95?
Solution:
Let the number to be added = x
∴ -176 + x = -95
x = -95 + 176 = 81

Question 8.
What is the difference in height between a point 270 m above sea level and 80 m below sea level?
Solution:
Height above sea level = +270 m
Height below sea level = -80 m
Difference = +270 – (-80)
= 270 + 80 = 350 m

ML Aggarwal Class 6 Solutions for ICSE Maths

Leave a Comment